The number of electrons must be removed the charge on the sphere is 0, is [tex]4 \times 10^{12}[/tex]. Option c is correct choice.
A coulomb (C) is the standard unit of electric charge in the International System of Units (SI). It is the amount of electricity that a 1-ampere (A) current carries in one second (s). A quantity of 1 C is equal to the electrical charge of approximately 6.24 x 1018 electrons or protons.
Total charge on a electron is, [tex]-1.9 \times 10^{-19}[/tex] Coulombs.
The charge on Sphere is, [tex]-6.40 \times 10^{-7}[/tex] Coulombs.
The number of electrons required to be removed from sphere is, [tex]\dfrac{-6.40 \times 10^{-7}}{-1.9 \times 10^{-19}}[/tex],
[tex]4 \times 10^{12}[/tex].
Option c is correct.
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for a marble launched at an angle above the horizontal, should the calculated position of the cup be moved closer or further away from the ramp?
The cup should be placed farther from the ramp in order to accommodate marbles launched at angles above horizontal.
A marble is a tiny, spherical ball or toy made of stone, glass, or ceramic. Marbles are frequently used in games and recreational activities like marbles, where participants shoot or roll the marbles towards a target with their fingers. Marbles come in a variety of shapes, hues, and patterns, and they could be adorned with swirls or other patterns. In the past, marbles have been used for a variety of activities in numerous cultures and civilizations, such as religious rites, art, and commerce items. Today, marbles are mostly used recreationally and may keep individuals of all ages entertained for hours.
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1.in an rc series circuit, the source voltage is vs, the voltage across the resistor is vr, and the voltage across the capacitor is vc. according to kirchoff's loop rule, what is the relationship between these voltages?
The relationship between these voltages vs = vr + vc. In an RC series circuit, the total voltage across all components in the circuit must equal the source voltage, according to Kirchhoff's loop rule.
In an RC series circuit, the total voltage across all components in the circuit must equal the source voltage, according to Kirchhoff's loop rule. Therefore, the relationship between the source voltage (vs), the voltage across the resistor (vr), and the voltage across the capacitor (vc) can be expressed as follows:
vs = vr + vc
This equation states that the sum of the voltages across the resistor and the capacitor must equal the source voltage in order to satisfy the law of conservation of energy in the circuit. The relationship between these voltages vs = vr + vc. In an RC series circuit, the total voltage across all components in the circuit must equal the source voltage, according to Kirchhoff's loop rule.
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why did aristarchus believe in the radical notion that the sun was at the center of the universe and that earth moved around it in an orbit
Aristarchus believed that the sun was the center of the universe because he had found that the sun was larger than the earth and other planets and made the conclusion that other planets revolved around the sun.
Definition of Aristarchus TheoryAristarchus' hypothesis was that the sun and stars did not move, that the earth revolved around the sun, while the sun remained stationary in the center of the earth's orbit.
In testing his hypothesis, Aristarchus constructed a kind of "sundial" which he probably used to measure the height of the sun and the position of the stars, as well as measure the angles and diameters of the moon as accurately as possible.
As a result, apart from the theory of the sun as the center of the solar system, Aristarchus also discovered that the earth is one of several planets revolving around the sun. Aristarchus used the theory of lunar eclipses to estimate the size of the solar system according to the radius of the earth
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every month, the moon passes between earth and the sun (new moon) and on the opposite side of earth from the sun (full moon). why do not we see eclipses every month?
Because the moon's orbit is tilted, we do not see eclipses every month.
Total solar eclipses happen when the moon crosses between the sun and Earth and casts its shadow onto our planet, but Earth doesn't experience a total solar eclipse every month.
Exploratorium Senior Scientist Paul Doherty explains why not—the orbit of the moon is tilted relative to the orbit of the Earth around the sun, so the moon often passes below or above Earth.
At those times, it does not cross the line between the sun and the Earth, and therefore does not create a solar eclipse. There are just two times a year in the Earth's orbit when there is a possibility of a total solar eclipse.
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what happens when a falling object reaches terminal velocity?(1 point) responses it hits the ground and stops. it hits the ground and stops. it speeds up. it speeds up. it slows down. it slows down. it stops accelerating. it stops accelerating.
When a falling object reaches terminal velocity, it stops accelerating.
option D.
What happens when a falling object reaches terminal velocity?
When a falling object reaches terminal velocity, it means it has reached the maximum speed it can attain while falling due to the drag force (air resistance) acting upon it, which is equal in magnitude to the gravitational force acting upon it.
At terminal velocity, the net force on the object is zero, so its velocity remains constant and it falls at a constant rate. The terminal velocity of an object depends on its mass, size, shape, and the density of the fluid it is falling through.
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17. A microwave has a wavelength of 3 cm and a speed of 3 x 108 m/s. Calculate the frequency.
Important Formulas:
[tex]v=\lambda f[/tex]
velocity(measured in m/s) = wavelength(measured in meters) * frequency(measured in hertz)
__________________________________________________________
Given:
[tex]\lambda=0.03m[/tex] (cm to m)
[tex]v=300,000,000m/s[/tex] (speed of light)
[tex]f=?[/tex]
__________________________________________________________
Rearranging formula for velocity to make frequency the subject:
[tex]v=\lambda f[/tex]
[tex]\dfrac{v}{\lambda} =\dfrac{\lambda f}{\lambda}[/tex]
[tex]f=\dfrac{v}{\lambda}[/tex]
__________________________________________________________
Finding frequency:
[tex]f=\dfrac{v}{\lambda}[/tex]
[tex]f=\dfrac{300,000,000}{0.03}[/tex]
__________________________________________________________
Answer:
[tex]\boxed{f = 1\times10^{10} Hertz}[/tex]
an electron traveling north enters a region where the electric field is uniform and points north. the electron:
When an electron traveling north reaches an area with a consistent electric field facing north, the electron's speed and direction of motion are altered.
What is an electron?A negatively charged subatomic particle known as an electron can either be free or attached to an atom. In the electron cloud, which is located outside of the atomic nucleus, exist electrons.
An electric field that is oriented northward will exert a force on an electron moving northward through it. The electron will accelerate in the field's direction as a result of this force. The strength of the electric field and the charge of the electron will determine how much the acceleration is.
The electron will continue to receive a constant force and move in a straight line with a constant acceleration in a uniform electric field since the electric field's direction is constant. As the electron passes through the electric field, both its velocity and kinetic energy will increase.
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a person sings musical note which has a frequency of 256 Hz , how many times do the person's vocal chords vibrate each second ?
Answer: no question is wron
Explanation:
What is the frequency of a planet around a star in orbit at a mean distance of R, if it is twice the mean distance of a planet orbiting the same star with a frequency of 2.10 × 10^-5 rev/s?
A) 1.4 × 10^-5 rev/s
B) 7.4 × 10^-6 rev/s
C) 1.7 × 10^-7 rev/s
D) 6.8 × 10^-7 rev/s
E) 2.4 × 10^-8 rev/s
Pls show work so I can learn how you got to that answer. Thank you!
Answer:
A) 1.4 × 10^-5 rev/s
Explanation:
We can use Kepler's Third Law of Planetary Motion to solve this problem. Kepler's Third Law states that the square of the period of a planet's orbit is proportional to the cube of its average distance from the star.
T^2 = k * R^3
where T is the period of the orbit and R is the mean distance of the planet from the star. k is a constant of proportionality that depends on the mass of the star.
Let's assume that the frequency of the first planet is f1 and its mean distance from the star is R1. The frequency of the second planet is 2.10 × 10^-5 rev/s and its mean distance from the star is 2R1. We can relate the frequency of the orbit to the period of the orbit as follows:
f = 1/T
Using the first equation, we can find the period of the first planet:
T1^2 = k * R1^3
And the period of the second planet:
T2^2 = k * (2R1)^3
Now, we can substitute these equations into the equation for frequency:
f1 = 1/T1 = 1/sqrt(k * R1^3)
f2 = 1/T2 = 1/sqrt(k * (2R1)^3)
Finally, we can set f1 = 2f2 and solve for f1:
2f2 = 1/sqrt(k * R1^3)
f1 = 1/sqrt(k * R1^3) / 2
So, f1 = 1.4 × 10^-5 rev/s, which is the answer (A).
which statements are true regarding a conductor in electrostatic equilibrium? a: all unbalanced charges must lie on the surfaces of the conductors. b: the electric field immediately outside a conductor must be perpendicular to the conductor. c: the electric field is zero inside the conductor.
All the statements are true regarding a conductor in electrostatic equilibrium.
The correct answer: A, B and C.
All unbalanced charges must lie on the surfaces of the conductors. The electric field immediately outside a conductor must be perpendicular to the conductor. The electric field is zero inside the conductor.In addition to the three statements that are true regarding a conductor in electrostatic equilibrium, there are a few other important facts to consider when dealing with electric fields. In an electrostatic field, the electric field lines are always perpendicular to the surface of the conductor. This means that any unbalanced charge on a conductor's surface must produce an electric field that is also perpendicular to the surface.
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fuses and circuit breakers are intended to protect conductors and equipment from the effects of potentially harmful ? .
Yes, conductors and equipment are protected from the impacts of potentially damaging by fuses and circuit breakers.
A circuit breaker is a type of electrical safety device used to guard against overcurrent damage to electrical circuits. Its primary purpose is to stop the flow of current in order to safeguard machinery and lower the likelihood of a fire. A circuit breaker can be reset to continue normal operation, in contrast to a fuse, which can only be used once before needing to be replaced.
There are many different sizes of circuit breakers, from tiny devices that protect low-current circuits or specific home appliances to massive switchgear built to safeguard high voltage circuits supplying an entire city.
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a sinusoidal transverse wave is propagating to the right. what direction is the velocity of a particle on this wave when it is at a peak (maximum displacement from the zero axis)?
Along a string, a sinusoidal axial wave is moving in the opposite direction of the x-axis.
A wave is what?A wave is an energetic perturbation in a material that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic strength, an electric potential, or a change in temperature are a few examples. a disruption or variation that causes energy to be transferred gradually from one point to another in a medium; it can be a different from place to place or a change in pressure, external electromagnetic strength, electrostatic force, or temperature.
How does pressure work?The pressure of soil against a wall; the application of force to a surface by an item, liquid, or., in contact with it. Physics. power.
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when temperature inversions work to trap pollution ?
The warmer air rises and acts as a lid, trapping the colder air near the ground. The air layer closest to the ground becomes more and more polluted as a result of pollution, including that from traffic, being trapped. This continues until the current meteorological conditions change.
What is temperature ?
Temperature is a unit used to represent how hot or cold something is. It can be stated using the Celsius or Fahrenheit scales, among others. Temperature shows which way heat energy will naturally flow, i.e., from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature).
What is pollution ?
The release of dangerous substances into the environment is referred to as pollution. Pollutants are these dangerous materials. Natural substances like volcanic ash are examples of pollutants. They may also be the result of human activity, such as the production of factory runoff or waste.
In a temperature inversion, the warmer air serves as a lid, keeping pollutants close to the ground and preventing them from dispersing until the weather changes. The chemicals consequently pose a significant threat to human health by reacting with one another to create other pollutants like ground-level ozone.
Therefore, Temperature inversions work to trap pollution is mentioned above.
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you toss a ball straight up in the air, it goes up, comes down, and you catch it. if it took 4 s from when you threw it to when you caught it, how high did it go?
So, the height to which the ball was thrown is approximately 29.4 meters. To find the height to which the ball was thrown, we need to use the equation for motion under constant acceleration, which is given by:
h = vi * t + (1/2) * a * t^2
where h is the height, vi is the initial velocity (which is the upward velocity with which the ball was thrown), t is the time it took for the ball to reach its highest point, and a is the acceleration due to gravity (-9.8 m/s^2).
Since the ball was thrown upward and then came back down, it reached its highest point after half of the total time, which is 2 seconds. So, we can use 2 seconds for the value of t in the equation.
Next, we can solve for vi using the time it took for the ball to reach its highest point and the acceleration due to gravity:
vi = h / (2 * t) - (1/2) * a * t
Substituting the known values into the equation:
vi = h / (2 * 2) - (1/2) * (-9.8 m/s^2) * 2^2
vi = h / 4 + 9.8 m/s
Now, we can use the value of vi to find the height h:
h = vi * 2 - (1/2) * (-9.8 m/s^2) * 2^2
h = 2 * (h / 4 + 9.8 m/s) - (1/2) * (-9.8 m/s^2) * 2^2
h = 2 * (h / 4 + 9.8 m/s) + 9.8 m
h = (h / 2 + 19.6 m) + 9.8 m
h = h / 2 + 29.4 m
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the total number of stars in the observable universe is roughly equivalent to group of answer choices the number of grains of dry sand on all the beaches on earth the number of grains of dry sand on miami beach infinity the number of stars in the milky way galaxy
The star in the observable cosmos is about equal to: A) The amount of sand grains on all of Earth's beaches
What sort of things are stars?
A star is formed in an enormous gas cloud. The sky's temperature is too moderate for the creation of molecules. The Delta haze groups in the Orion galaxy are stars in this stage of development. 2. Protostar When gas particles hit in the solar nebula, heat energy is produced.
The Sun is a star, but why?
The energy and light provided by the sun, which is actually a star, are essential in maintaining all life on earth. Nuclear fusion events that take place inside stars are what give them their light. A byproduct of this process, which turns hydrogen into helium, is energy. This energy is what manifests as light for humans.
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at what temperature would the average velocity of helium atoms equal the escape velocity from (a) the earth
At 23700K would the average velocity of helium atoms equal the escape velocity from (a) the earth.
The mass of a helium atom is
m=6.64×10−27 kg m = 6.64 × 10 − 27 k g.
Given let the average speed of helium atoms equal the escape speed from the Earth.
Thus we have at 23700K the average speed of helium atoms equal the escape speed from the Earth.
What is helium?
Its melting point at ordinary pressure is zero, and its boiling point is the lowest of all the elements.After hydrogen, it is the second-lightest and second-most prevalent element in the observable universe.More than 12 times the mass of all the heavier elements put together, it makes up around 24% of the total mass of the elements.Due to helium-4's extremely high nuclear binding energy (per nucleon), compared to other elements, its abundance is similar to this in both the Sun and Jupiter.To know more about the helium, click the link given below:
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write a 200 to 300 word conclusion discussing your results and the relationships between positions velocity and acceleration and how calculus can allow us to find position from velocity
The relationships between positions velocity and acceleration is velocity function and that the indefinite integral of the velocity represents the distance function when studying the relationship between the derivative and the indefinite integral as inverse operations.
In situations requiring distance, velocity, and acceleration—each of which is a function of time—the indefinite integral is frequently used. The derivative of a distance function represents immediate velocity, while the derivative of a velocity function represents instantaneous acceleration at a specific moment, as noted in the discussion of derivative applications. Remember that the indefinite integral of the acceleration function represents the velocity function and that the indefinite integral of the velocity represents the distance function when studying the relationship between the derivative and the indefinite integral as inverse operations.
A measure of how velocity varies is acceleration. It should come as no surprise that we can determine acceleration by taking the derivative of the velocity function as velocity is a measure of how position changes. Since we can determine velocity by taking the derivative of the position function.
A curved position graph will have a changing slope, which also indicates a changing velocity. Acceleration implies a change in velocity. Therefore, a graph's curvature indicates that an object is accelerating and changing velocity or slope.
The velocity-time graph displays how quickly you moved, while the position-time graph displays how far you've come. The points on the velocity-time graph are determined by the rate of change of the position-time graph.
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The School Security Committee has complained that there are some intruders who hide behind the gate and break into the school in the evening As Physica students, you have been asked to design a device which the ratekeeper will use to see the intruders who hide behind the gate. You will present to the head teacher and staff.
In order to locate intruders hiding behind the gate, we propose a device that employs infrared sensors and an alert system.
Design:The camera that will be attached to our device will be on a long telescopic pole. The camera will be facing the area behind the school gate, so the pole will be placed close to the gate.
The gatekeeper will be able to clearly see any intruders who might be hiding behind the gate because the camera will be connected to a television or monitor. To ensure maximum safety, the camera will also have night vision and motion detection capabilities.
The camera will be connected to a remote control so that the gatekeeper can tilt and pan the camera to get a better view of the area behind the gate. This will make the device easy to use. The gatekeeper will be able to zoom in on any suspects using the zoom feature on the remote control.
Additionally, the device will have an alarm system that will sound if there is any movement in the area behind the gate. A light will also be connected to the alarm system, and when the alarm goes off, it will flash brightly to let the gatekeeper know there are intruders there.
In conclusion, the school will get a comprehensive security system from our device that will help find intruders who hide behind the gate. The device is simple to operate and will give the gatekeeper clear, in-depth pictures of any intruders who might be hiding behind the gate.
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(A) A small mass of 0.60 kg is rotated at the end of a string in a horizontal circle of radius 1.20 m. The string will break if the tension exceeds 60 N. What is the GREATEST frequency of revolution that is possible? (B) the same mass of 0.60 kg is now rotated at the end of another string at a constant speed, v, in a vertical circle of radius 1.20 m. the minimum tension in the string is 2.1N (I) state and explain where the tension in the string is maximum and minimum (ii) find the speed of the mass
(a) The maximum frequency of revolution is 4.0 rad/s.
b (i) The tension in the string is maximum when the object is at the top of its path and minimum when it is at the bottom of its path.
b (ii) The speed of the mass can be found using the minimum tension in the string is 2 m/s.
What is the maximum frequency of revolution?
The maximum frequency of revolution is given by the maximum tension in the string, which is 60 N.
T = mv² / r
where;
m is the mass of the object (0.60 kg), v is its linear speed, r is the radius of the circle (1.20 m).The linear speed is given by:
v = 2πrf
where;
f is the frequency of revolutionf = √T / (mr²))
f = √(60 / (0.60 x 1.20²))
f = 4.0 rad/s
(i) The tension in the string is maximum when the object is at the top of its path and minimum when it is at the bottom of its path. This is because the tension provides the centripetal force that keeps the object moving in a circular path.
(ii) The speed of the mass can be found using the minimum tension in the string, which is 2.1 N:
T = mv² / r = 2.1 N
Rearranging and solving for v, we get:
v = √(Tr / m)
v = √(2.1 x 1.20 / 0.60)
v = 2.0 m/s
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determine the horsepower developed by a passenger car traveling at a speed of 50-mi/h on an upgrade of 5% with a smooth pavement. the weight of the car is 4,500-lb and the cross-sectional area of the vehicle is 50 square-feet.
Passenger car requires 21.23 horsepower to travel at a speed of 50-mi/h on an upgrade of 5% with a smooth pavement, given its weight of 4,500-lb and cross-sectional area of 50 square-feet.
The horsepower developed by the passenger car, we need to calculate the force required to overcome the resistance of the car on the upgrade, and then use that force to calculate the power required in horsepower.
[tex]Force = Weight * Grade + Drag[/tex]
First, we calculate the force required to overcome the resistance of the car on the upgrade:
where:
Weight = 4,500 lb
Grade = 5% = 0.05
Drag = 0.5 * Air Density * Velocity^2 * Coefficient of Drag * Cross-Sectional Area
[tex]Drag = 0.5 * Air Density * Velocity^2 * Coefficient of Drag * Cross-Sectional Area[/tex]
[tex]Air Density =[/tex][tex]0.075 lb/ft^3[/tex]
[tex]Velocity = 50 mph[/tex]
[tex]Coefficient of Drag = 0.35[/tex]
[tex]Drag =[/tex][tex]0.5 * 0.075 * (50/3600)^2 * 0.35 * 50 = 8.53 lb[/tex]
[tex]Force = 4,500 * 0.05 + 8.53 = 233.53 lb[/tex]
Next, we calculate the power required in horsepower:
[tex]Power (HP) = Force * Velocity / 550[/tex]
[tex]Velocity = 50 mph[/tex]
[tex]Power (HP) = 233.53 * 50 / 550 = 21.23 HP[/tex]
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a tree house is 8 m above the ground. if peter does 360 j of work while pulling a box from the ground up to his tree house with a rope, what is the mass of a box?
To find the mass of the box, we can use the equation for work done by gravity, which is: Work = Force x Distance is 4.64 kg
where Force is the force required to lift the box, and Distance is the distance the box is lifted.
The force required to lift an object is given by the equation:
Force = Mass x Gravity
where Mass is the mass of the object and Gravity is the acceleration due to gravity (9.8 m/s^2 on the surface of the Earth).
So, we can substitute the Force equation into the Work equation to get:
Work = Mass x Gravity x Distance
Rearranging this equation, we get:
Mass = Work / (Gravity x Distance)
Now, we can substitute the known values into this equation:
Mass = 360 J / (9.8 m/s^2 x 8 m)
Mass = 360 J / 77.6 J/kg
Mass = 4.64 kg
So, the mass of the box is approximately 4.64 kg.
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what is the downward force exerted by the atmosphere on a football field whose dimensions are 110 m by 49 m ?
The downward force exerted by the atmosphere on a football field whose dimensions are 110 m by 49 m is 546×10⁶ N.
The atmospheric pressure or air pressure is the force exerted on a surface by the air above it as gravity pulls it to Earth. Atmospheric pressure is commonly measured with a barometer. The force of buoyancy exerted by the atmosphere on a balloon is B in the upward direction and remains constant. The force of air resistance on the balloon acts opposite to the direction of velocity and is proportional to it. The total downward force exerted by the atmosphere on a football field is found using the atmospheric pressure. So, P atm. A=F. Where A is the area of the football field, A=a⋅b=110 m⋅49m. Finally F=101.3 kPa. 110.49 m² = 546×10⁶ N.
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systems tend to change until they reach equilibrium. based on this fact, what will happen when cold air and warm are added to the same container?
When cold air and warm are added to the same container then the warm air will get colder and cold air will get warmer.
The warm air molecules have more kinetic energy than the cold air molecules when the two air masses are blended. As a result, the warm air molecules attack the cold air molecules and transmit some of their kinetic energy. Up until balance is established, the warm air will get colder and the cold air will get warmer.
Two systems are considered to be in thermal equilibrium with one another when they are in contact with one another and there is no energy movement between them. Thermal equilibrium, said simply, denotes that both systems are at the same temperature. Our daily lives are so reliant on the idea of thermal homeostasis.
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it is possible to view the moon in first-quarter phase the day after a total lunar eclipse. group of answer choices true false
It is untrue that the day following a total lunar eclipse, one can see the moon in its first quarter phase.
Can you observe a lunar eclipse every full moon?Only a night with a full moon can have a lunar eclipse. However, because Planet's orbit around the sun and the moon's orbit around the earth are not in the same plane, they do not occur every full moon night. Only when the sun, the earth, and the moon align in a straight line can an eclipse occur.
What phase of the Moon must be present for a lunar eclipse to occur?Only under a full moon and when the Moon travels entirely or partially through Earth's shadow can there be a lunar eclipse.
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two parallel plates, separated by 0.20 m, are connected to a 12-v battery. an electron released from rest at a location 0.10 m from the negative plate. when the electron arrives at a distance 0.050m from the positive plate, how much kinetic energy does the electron gain?
The electron gains 4.8 x 10^-17 J of kinetic energy when it arrives at a distance of 0.050 m from the positive plate.
The potential difference (V) between the two plates is equal to the voltage of the battery, so V = 12 V. The electric field (E) between the two plates is given by E = V/d, where d is the separation distance between the plates. So, the electric field between the plates is E = 12 V / 0.20 m = 60 N/C.
The change in potential energy of the electron as it moves from 0.10 m to 0.050 m from the negative plate can be calculated as ΔU = qΔV, where q is the charge of the electron and ΔV is the change in potential. The change in potential can be calculated as ΔV = Ed, where d is the change in the distance between the electron and the plate. So,[tex]ΔU = qE(0.10 m - 0.050 m) = qE(0.05 m).[/tex]
The change in potential energy is equal to the change in kinetic energy, so ΔK = ΔU. The final kinetic energy (Kf) of the electron can be calculated as [tex]Kf = ΔK = ΔU = qE(0.05 m) = (1.6 x 10^-19 C)(60 N/C)(0.05 m) = 4.8 x 10^-17 J[/tex].
Therefore, the electron gains [tex]4.8 x 10^-17 J[/tex] of kinetic energy when it arrives at a distance of 0.050 m from the positive plate.
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for the point charges arragement shown in the figure find the net electrostatic force exerted on Q by q1 and q2
The net electrostatic force exerted on Q by q1 and q2 is
F=9.99 *10^-2
What are point charges?Generally, Point charges are hypothetical charges concentrated at a single point in space. They are used in physics and electrical engineering to simplify the analysis of electrical fields and their interactions.
Point charges are considered to be dimensionless, that is, they have zero size, and they have a magnitude that is either positive or negative, depending on whether the charge is a proton or an electron, respectively. In reality, point charges do not exist, as all charges are distributed over a finite volume, but they are a useful abstraction for certain calculations and simulations.
[tex]& K=\frac{1}{4 \bar{R} \varepsilon} \\\\& =\frac{1}{4 \times 3.142 \times 8-854 \times 10^{-12}} \\\\& =\frac{1}{1-112626454 \times 10^{-10}} \\[/tex]
=8.79 *10^9
[tex]f=\frac{k /q1 / /q2/}{r^2}[/tex]
r=0.30 +0.30
r=0.6
[tex]F=\frac{8.17 \times 10^7 \times\left(2 \times 10^{-6}\right) \times\left(2 \times 10^{-6}\right)}{0.6^2} \\[/tex]
[tex]F=\frac{(8-11 \times 2 \times 2) \times\left(101 \times 10^{-6} \times 10^{-6}\right)}{0.36} \\[/tex]
[tex]& F=\frac{35.96 \times 10^{-3}}{0.36} \\[/tex]
F=9.99 *10^-2
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ohm's law states that the potential difference across a metallic conductor is directly proportional to the current in the conductor at constant temperature. would you say the resistor used in this lab was ohmic (obeys ohm's law)? explain.
The potential difference across the resistor was found to be directly proportional to the current flowing through it at a constant temperature, then the resistor would be considered ohmic and would obey Ohm's law.
If the potential difference and current were found to have a non-linear relationship, then the resistor would be non-ohmic and would not obey Ohm's law. If the graph is a straight line passing through the origin, then the resistor is ohmic and obeys Ohm's law. If the graph is not a straight line passing through the origin, then the resistor is non-ohmic and does not obey Ohm's law.
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a spring has a natural length of 15 cm. it takes 50 joules of work to stretch it to 35 cm. how much work is needed to stretch it from a length of 35 cm to 85 cm?
In the first phase, you are conflating force and labour. Your supplied quantity is work since work is defined in joules. Given that you are 0.5 meters away from equilibrium,
The joule (unit J) is what?
What is a Joule (unit J) - Definition of an Energy Unit One energy unit. Energy is often thought of as the capacity to produce heat or work. 2 Joules of energy. Joule (unit: J) (unit: J). A derived energy unit is the joule. Three examples of 1 joule of energy. The energy is converted into kinetic of a 1 kilogram object traveling at a speed of 2 m/s
What does one joule of energy mean?
A derivative unit of energy is the joule. It is the amount of energy transmitted to an item when a one newton force is applied to it in the plane of its motion across a one meter distance. 0.239 calories make up 1 joule. 9.48 × 10-4 BTU equals 1 joule. A joule equals 2.778 x 10-7 kWh. Examples of 1 Joule of Energy
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for a two-dimensional collision (vertical separation of centers is not zero), how does increasing the mass of the yellow stone impact the final velocity of the red stone? the final velocity of the yellow stone?
On increasing the mass of the yellow stone,in vertical direction balls center move away from each other and collision probability between the two balls will decrease and final velocity of yellow ball will also decrease.
A Collision happens when a strong power strikes on at least two bodies in a generally brief timeframe. Collision is a one-time event. Because of the crash, the elaborate particles' energy and force change. The crash might happen because of real actual contact between the taking part bodies, like an impact between two billiard balls or a ball and bat. There might be impacts where there is no immediate actual touch, for example, an alpha molecule slamming into a core.
Two dimensional collision(vertical collision)
The accompanying cases might emerge in the event of versatile crash between two bodies :
(1) Two-layered Versatile Crash in Research center Reference Casing
(2) Versatile crash with boundless masses in two aspects
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through a piece of copper wire 20 cm long and with a cross-sectional area of \u200b\u200b0.6 mm ^ 2 a charge of 4 cells is passed in 0.1 s. determine the voltage at the ends of the wire
Using Ohm's Law, the voltage at the ends of the wire can then be calculated as [tex]V = I*R = (4 cells)*(0.672 Ohms) = 2.688 Volts.[/tex]
What is Ohm's Law ?Ohm's Law states that the current through a conductor between two points is directly proportional to the potential difference or voltage across the two points, and inversely proportional to the resistance between them. In other words, the voltage across a resistor is proportional to the current flowing through it. This relationship is expressed mathematically as V=IR, where V represents the voltage, I is the current, and R is the resistance.
The voltage at the ends of the wire can be calculated using Ohm's Law, which states that voltage (V) is equal to current (I) multiplied by resistance (R). In this case, the resistance of the copper wire is determined using the formula R = (resistivity of the material)*(length of the wire)/(cross-sectional area of the wire). The resistivity of copper is [tex]1.68 x 10^-8 Ohm-meters[/tex], so the resistance is equal to [tex](1.68 x 10^-8)*(20 cm)/(0.6 x 10^-3 m^2) = 0.672 Ohms.[/tex]
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