Answer:
False, it is a fuse.
Explanation:
In electronics and electrical engineering, a fuse is an electrical safety device that operates to provide overcurrent protection of an electrical circuit. Its essential component is a metal wire or strip that melts when too much current flows through it, thereby stopping or interrupting the current. It is a sacrificial device; once a fuse has operated it is an open circuit, and must be replaced or rewired, depending on its type.
Fuses have been used as essential safety devices from the early days of electrical engineering. Today there are thousands of different fuse designs which have specific current and voltage ratings, breaking capacity and response times, depending on the application. The time and current operating characteristics of fuses are chosen to provide adequate protection without needless interruption. Wiring regulations usually define a maximum fuse current rating for particular circuits. Short circuits, overloading, mismatched loads, or device failure are the prime or some of the reasons for fuse operation.
A fuse is an automatic means of removing power from a faulty system; often abbreviated to ADS (Automatic Disconnection of Supply). Circuit breakers can be used as an alternative to fuses, but have significantly different characteristics.
Source: https://en.wikipedia.org/wiki/Fuse_(electrical)
A fuse is a small glass or plastic tube that contains a piece of wire. That wire is carefully calibrated so that it will only allow a certain level of current to pass through it. Any more, and the wire will melt from the heat, breaking the circuit. This means that if a power surge comes into your home, a circuit will be broken before it causes damage to your appliances.
A circuit breaker achieves the same thing, but by a different method. A circuit breaker also disconnects the circuits in your home if the current gets too large but does it using electromagnets. If the current gets high enough, then the electromagnet will become powerful enough to attract a contact and break the circuit that way.
Both circuit breakers and fuses can be used to help with another situation. If you have an appliance with a metal case and that appliance comes in contact with a live wire, it can cause you to electrocute yourself. But if that metal case is connected to a ground wire (the third pin in some plugs), then the electricity will flow through the ground wire, through the circuit breaker or fuse box, and break the circuit, stopping you from potentially getting electrocuted.
Source: https://study.com/academy/lesson/the-differences-between-fuses-circuit-breakers.html
At what efficiency is a photovoltaic array running if insolation on the collector is 650 W/m2, the total collector area is 10 m2, the voltage across the array is 50 V, and the current being delivered is 15 A
Answer: 11.53 %
Explanation:
Given
area [tex]A=10\ m^2[/tex]
Voltage V=50 V
current I=15 A
Array running at [tex]650\ W/m^2[/tex]
Power [tex]P=VI=50\times 15=750\ W[/tex]
Efficiency [tex]\eta=\frac{750}{650\times 10}\times 100=11.53\%[/tex]
Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 l
Answer:
585lb
Explanation:
Given the following
F1 = 235lb
F2 = 350lb
The resultant is expressed as;
FR = F1+F2
Substitute the given values
FR = 235+350
FR = 585lb
Hence the magnitude of the resultant is 585lb
Question 7 of 10
What is the period of a wave with a frequency of 3 Hz and an amplitude of
0.01 m?
A. 0.0033 s
B. 300 s
C. 0.33 s
D. 0.030 S
Answer:
0.33s
Explanation:
hope this is the correct ans
Consider the standing wave on a guitar string and the sound wave generated by the string as a result of this vibration. What do these two waves have in common
Answer:
As the string vibrates, it "moves" the particles in the air, generating what we know as a soundwave.
Because this soundwave is generated by the wave-like motion of the string, makes sense that the soundwave will have some characteristics in common with the standing wave on the guitar string. This means that both waves will have the same normal modes. (So if the principal mode of the vibrating string has a frequency of 440hz, to soundwave also will have that main frequency, and we will hear an A). You can hear almost all the normal modes when you pluck a guitar string, particularly in music, these are called "overtones" or "harmonics"
A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the person is 67.0 kg, the mass of the skateboard is 4.10 kg, and the mass of the brick is 2.50 kg. If the person throws the brick forward (in the direction they are facing) with a speed of 23.0 m/s relative to the skateboard and we ignore friction, determine the recoil speed of the person and the skateboard, relative to the ground.
Answer:
v₁ = -0.8087 m / s
Explanation:
To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved
Initial instant. When they are united
p₀ = 0
Final moment. After throwing the brick
[tex]p_{f}[/tex] = (m_man + m_skate) v1 + m_brick v2
the moment is preserved
p₀ = p_{f}
0 = (m_man + m_skate) v₁ + m_brick v₂
v₁ = - [tex]\frac{ m_{brick} }{m_{man} + m_{skate} } v_{2}[/tex]
the negative sign indicates that the two speeds are in the opposite direction
let's calculate
v₁ = - [tex]\frac{2.5}{67 + 4.10} 23.0[/tex]
v₁ = -0.8087 m / s
Question 1 of 10
What is the electric force acting between two charges of -0.0085 C and
-0.0025 C that are 0.0020 m apart?
Use F.- and k - 900-10° N m.cº.
kq,92
A. -4.8 - 1010N
B. -9.6x 107N
C. 9.6 x 10°N
D. 4.8 - 1010 N
Answer:
D
Explanation:
1. Define "compressibility." Give an example from your daily life
A 7.03 nC charge is located 1.75 m from a 4.26 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.
Given that,
Charge, q₁ = 7.03 nC
Charge, q₂ = 4.26 nC
Distance, r = 1.75 m
To find,
The magnitude of the electrostatic force that one charge exerts on the other.
Solution,
The force between two charges at a distance is given by the formula as formula :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 7.03\times 10^{-9}\times 4.26\times 10^{-9}}{(1.75)^2}\\\\=8.8\times 10^{-8}\ N[/tex]
So, the required force is [tex]8.8\times 10^{-8}\ N[/tex].
You walk into the living room and find your family watching a nature documentary on PBS. Which lens does this network fall under
Answer:
Natural Sciences
Explanation:
This network would fall under the lens of Natural Sciences. This is based on what the family is currently watching. Nature documentaries focus on our Planet as well as all the wildlife in it. In these documentaries, they talk about how and why certain things in nature occur. All of this would be considered educational information on the subjects of Earth Science and Biology which are main subcategories under the lens of Natural Sciences.
A ball of clay with a mass of 55 g and a speed of 1.5 m/s collides with a 55 g ball of clay that is at rest. By what percent has the kinetic energy decreased after the inelastic collision?
Answer:
The kinetic energy decreased 50 % after the inelastic collision.
Explanation:
Since both ball collide and experiments an inelastic collision, the final velocity of the system is found by means of the Principle of Linear Momentum:
[tex]m_{A}\cdot v_{A} + m_{B}\cdot v_{B} = (m_{A}+m_{B})\cdot v[/tex] (1)
Where:
[tex]m_{A}[/tex], [tex]m_{B}[/tex] - Masses of the balls of clay, measured in kilograms.
[tex]v_{A}[/tex], [tex]v_{B}[/tex] - Speeds of the balls of clay before collision, measured in meters per second.
[tex]v[/tex] - Speed of the system after collision, measured in meters per second.
If we know that [tex]m_{A} = m_{B} = 0.055\,kg[/tex], [tex]v_{A} = 1.5\,\frac{m}{s}[/tex] and [tex]v_{B} = 0\, \frac{m}{s}[/tex], then the speed of the system after collision is:
[tex]v = \frac{m_{A}\cdot v_{A}+m_{B}\cdot v_{B}}{m_{A}+m_{B}}[/tex]
[tex]v = \frac{(0.055\,kg)\cdot \left(1.5\,\frac{m}{s} \right)+(0.055\,kg)\cdot \left(0\,\frac{m}{s} \right)}{0.110\,kg}[/tex]
[tex]v = 0.75\,\frac{m}{s}[/tex]
The initial ([tex]E_{o}[/tex]) and final kinetic energies of the system ([tex]E_{f}[/tex]), measured in joules, are now described by the following equations:
[tex]E_{o} = \frac{1}{2}\cdot (m_{A}\cdot v_{A}^{2}+m_{B}\cdot v_{B}^{2})[/tex] (2)
[tex]E_{f} = \frac{1}{2}\cdot (m_{A}+m_{B})\cdot v^{2}[/tex] (3)
And the percentage of lost energy due to inelastic collision is:
[tex]\%e = \left(1-\frac{E_{f}}{E_{o}} \right)\times 100\,\%[/tex] (4)
If we know that [tex]m_{A} = m_{B} = 0.055\,kg[/tex], [tex]v_{A} = 1.5\,\frac{m}{s}[/tex], [tex]v_{B} = 0\, \frac{m}{s}[/tex] and [tex]v = 0.75\,\frac{m}{s}[/tex], then the percentage of lost energy due to inelastic collision is:
[tex]E_{o} = \frac{1}{2}\cdot \left[(0.055\,kg)\cdot \left(1.5\,\frac{m}{s} \right)^{2}+(0.055\,kg)\cdot \left(0\,\frac{m}{s} \right)^{2}\right][/tex]
[tex]E_{o} = 0.062\,J[/tex]
[tex]E_{f} = \frac{1}{2}\cdot (0.110\,kg)\cdot \left(0.75\,\frac{m}{s} \right)^{2}[/tex]
[tex]E_{f} = 0.031\,J[/tex]
[tex]\%e = \left(1-\frac{0.031\,J}{0.062\,J} \right)\times 100\,\%[/tex]
[tex]\%e = 50\,\%[/tex]
The kinetic energy decreased 50 % after the inelastic collision.
The two charges are then brought closer together so that the force between them increases by a factor of 25. By what factor was their separation decreased
Answer:
Explanation:
The forces between two charges is inversely proportional to the square of distance.
[tex]F = k q_1 q_2 / r^{2}[/tex]
So if the distance is half then the force increases by a factor of 4 . if force between the charges increases by a factor of 25 then separation between them is decreased by a factor of 5 i.e distance between them is 1/5.
help mmmemememeeee I'M BEING TIMED
Answer:
it's c. or A. not b.
Explanation:
.................
Which statement describes the vector plotted below?
A. The vector goes from (1, -2) to (-3,1).
B. The vector goes from (-3,-1) to (-3,-1).
c. The vector goes from (1, 2) to (-3,1).
D. The vector goes from (-3,-1) to (1,2).
Answer: the vector goes from (1,2) to (-3,1)
Explanation:
Describe reflection using the terms incident ray and reflected ray.
Answer:
Explanation:
The ray of light that hits the polished surface is called the incident ray. The ray that gets reflected away is called the reflected ray. The point at which the light hits the surface is called the point of incidence. If a line is drawn perpendicular to that point, it is called the normal.
A block weighing 9.3 N requires a force of 3.7 N to push it along at constant velocity. What is the coefficient of friction for the surface
Answer:
0.398
Explanation:
According to friction, the frictional force is directly proportional to the normal reaction
Ff = nR
Ff is the frictional force
n is the coefficient of friction
R is the reaction
Reaction is equal to the weight
R= W = 9.3N
Fm = Ff = 3.7N
Fm is the moving force
Get the coefficient of friction
n = Ff/R
n = 3.7/9.3
n = 0.398
Hence the coefficient of friction for the surface is 0.398
When you graph displacement vs. time, velocity is represented by
A. the x-intercept of the graph
B. the y-intercept of the graph
C. the slope of the graph
D. the curve of the graph
if a tomato is considered a fruit... then is ketchup considered a smoothie?
Answer:
depends... do you add suger to your ketchup?
Explanation:
A horizontal spring on a frictionless surface has a spring constant of 10 N/m with a mass of 2kg attached to the end of the spring. If the spring is stretched 2m passed its point of equilibrium and released, how many times does the mass pass through equilibrium per second
Answer:
0.356 times the mass pass through equilibrium per second.
Explanation:
Given that,
Spring constant = 10 N/m
Mass = 2 kg
Stretched spring = 2m
We need to calculate the frequency
Using formula of frequency
[tex]f=\dfrac{1}{2pi}\sqrt{\dfrac{k}{m}}[/tex]
Where, m = mass
k = spring constant
Put the value into the formula
[tex]f=\dfrac{1}{2\pi}\sqrt{\dfrac{10}{2}}[/tex]
[tex]f=0.356\ Hz[/tex]
We know that,
Hertz = cycle per second
Hence, 0.356 times the mass pass through equilibrium per second.
How fast, in rpm, would a 5.6 kg, 25-cm-diameter bowling ball have to spin to have an angular momentum of 0.26 kgm2/s
Answer:
71 rpm
Explanation:
Given that:
Angular momentum (L) = 0.26
Diameter = 25cm = 0.25 cm
Radius, r = (d/2) = 0.125m
Mass = 5.6 kg
Moment of inertia (I) = 2mr² / 5
I = (2 * 5.6 * 0.125^2) / 5
= 0.175
= 0.175 / 5
= 0.035 kgm²
Angular speed (w) ;
w = L / I
w = 0.26 / 0.035
= 7.4285714
= 7.429 rad/s
w = (7.429 * 60/2π)
w = 445.74 / 2π rpm
w = 70.941724
Angular speed = 70.94 rpm
= 71 rpm
Suggest why natural gas from different countries has a different percentage to hydrocarbons
Answer:
See the answer below
Explanation:
Natural gas from different countries has a different percentage of hydrocarbons because they are formed from different biomass of organisms.
Natural gas is formed from decomposed organic matter that has been deposited millions of years ago. Layers of decomposing plants and animal matters buried deep in the ground experience intense heat and pressure and are eventually transformed after millions of years.
Different countries have different diversity of organisms. Hence, the organic matter that eventually transforms into natural gas for each country also differ. The implication is that the natural gas that would be formed in each country would be different. This is why natural gas from different countries may have different percentages of hydrocarbons.
What is the difference between the number of electrons in an atom of Iodine (I) and the number of electrons in an atom of Aluminum (Al)?
Answer:
Iodine is element number 53. Iodine has 53 protons and 53 electrons (because it has no charge the number of protons equals the number of electrons). Iodine-131 has 131 protons and neutrons.
Explanation:
A rope 6m long is fixed at one end; the other end is attached to a light string so that it is free to move. The speed of waves on the rope is 18 m/s. The frequency of the second harmonic is
Given :
A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.
The speed of waves on the rope is 18 m/s.
To Find :
The frequency of the second harmonic.
Solution :
We know, for second harmonic wave :
Wavelength = Length of rope
[tex]\lambda = L\\\\\lambda = 6 \ m[/tex]
Now, we know frequency is given by :
[tex]Frequency = \dfrac{Speed}{Wavelenght}\\\\f = \dfrac{18 \ m/s}{6\ m}\\\\f = 3 \ s^{-1}[/tex]
Therefore, the frequency of the second harmonic is 3 s⁻¹.
A 9.0 kg test rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1905 J by the time the rocket engine burns all of the fuel. What additional height will the rocket rise
Answer:
21.6m
Explanation:
Since the rocket engine burns all the fuel hence the kinetic energy will be converted to potential energy
Potential Energy = mass × acceleration due to gravity × height
Given
PE = 1905J
Mass = 9.0kg
Acceleration due to gravity =9.8m/s²
Required
Height h
Substitute into the formula
1905 = 9(9.8)h
1905 = 88.2h
h =1905/88.3
h = 21.6m
Hence the required height is 21.6m
A 146N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor. Find the coefficient of friction.
Answer:
F = force
f = friction
u = coefficient of friction
R = normal reaction force
a = Acceleration
m = mass of block
g = gravity
f = uR
F = Ma
Say the block is moving to the right.
The 146N force thus acts to the right, and the friction force to the left, since it resists movement.
The 146N force acts to the right, but the horizontal component of it is 146 cos 50 = 93.84: So this is the force to the right.
Since F = uR and we're trying to find u, we need both F and R. R is easy to get since it is just m x g. This is in fact already given as the weight 350N. So R = 350.
The block is moving at a constant speed, so the force to the right must = the force to the left.
F = ma, so 93.84 - f = (350/g) x 0
This means f must be 93.84 also.
so we have f = uR,
93.84 = u x 350
so u = 0.268 or
0.27 to 2dp.
Hope you understand this.
Explanation:
The coefficient of friction is 0.26 if the 46N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N). Mathematically it is defined as the product of the coefficient of friction and normal reaction.
We know:
f = uR
Where f is the friction force and u is the coefficient of friction, R is the normal reaction force.
The horizontal component of 146N is:
F' = 146cos50°
F' = 93.84 N
Since F = mass×acceleration
Because the block is traveling at a constant speed, the right-hand force must equal the left-hand force.
F' = f = 93.84 N
93.84 = u x 350 (R = 350N)
u = 0.26
Thus, the coefficient of friction is 0.26 if the 46N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor.
Learn more about the friction force here:
https://brainly.com/question/1714663
#SPJ2
distance formula and unit
Answer:
distance = speed × time
Explanation:
the unit of distance is meter(m)
but the formula differs according to the given
A person walks first at a constant speed of 5.40 m/s along a straight line from point to point and then back along the line from to at a constant speed of 3.10 m/s. (a) What is her average speed over the entire trip
Answer: The average speed over the entire trip is 3.94 m/s
Explanation:
As we know : [tex]speed=\frac{distance}{time}[/tex]
Let the distance of straight line from point to point be = d
Total distance covered = 2d
Time taken to cover the forward journey = [tex]\frac{d}{5.40}[/tex]
Time taken to cover the backward journey = [tex]\frac{d}{3.10}[/tex]
Total time for the journey = Time taken to cover the forward journey + Time taken to cover the backward journey = [tex]\frac{d}{5.40}+\frac{d}{3.10}[/tex]
Average speed = [tex]\frac{\text {total distance}}{\text {total time}}=\frac{2d}{\frac{d}{5.40}+\frac{d}{3.10}}=3.94m/s[/tex]
Thus average speed over the entire trip is 3.94 m/s
4.
What is the BEST example you can offer to explain a folkway?
A. It is against your religious beliefs to commit adultery.
B. Your workplace decreases your pay if you arrive late.
C. When you answer your phone, you say hello.
D. All people are kind to one another.
Help please!!
During transcription, the DNA strand being transcribed has the following nucleotides: CTT CAG.
What would be the matching nucleotides on the mRNA?
Select one
1. GAA GUC
2.GUU GTC
3. AUU ATC
4. ACC AUC
Answer:
l think the correct answer is 1.GAA GUC
One wave of 1 m amplitude meets another wave of 2 m amplitude. If they are exactly out of phase, what is the magnitude of the new amplitude
Answer:
1 m
Explanation:
Assuming both waves have the same frequency, and speed, this means that they have the same wavelength.If they are exacty out of phase, one will be at its maximum positive amplitude (crest), while the other will be at its maximum negative amplitude (trough), which means that the magnitude of the new amplitude will be the difference between both amplitudes, i.e., 1 m.If both waves had the same amplitude, the new amplitude would be just zero.Find the magnitude of the velocity of the of the chain when 5.58 m of the chain is hanging vertically. Answer in units of m/s.
Answer:
10.46m/s
Explanation:
Given
Distance = 5.58m
Required
magnitude of the velocity'
Using the equation of motion expressed as
v² = u² + 2gS
v² = 0 +2(9.8)(5.58)
v² = 109.368
v= √109.368
v = 10.46m/s
Hence the magnitude of the velocity of the of the chain is 10.46m/s