Answer:
torque to raise the load = 16.411 Nm
torque to lower the load = 8.40 Nm
overall efficiency = 0.24
Explanation:
Given:
max load on vertical direction of the screw = Force = F = 5kN
frictional diameter of the collar = 45 mm
Diameter = 25 mm
length of pitch = 5 mm
coefficient of friction for thread µ = 0.09
coefficient of friction for collar µ[tex]_{c}[/tex] = 0.06
To find:
torque to "raise" the load
torque to and "lower"
overall efficiency
Solution:
Compute torque to raise the load:
[tex]T_{R} = \frac{ Fd_{m}}{2} (\frac{L+(\pi ud_{m}) }{\pi d_{m}-uL }) +\frac{Fu_{c} d_{c} }{2}[/tex]
where
[tex]T_{R}[/tex] is the torque
F is the load
[tex]d_{m}[/tex] is diameter of thread
[tex]d_{c}[/tex] is diameter of collar
L is the thread pitch distance
µ is coefficient of friction for thread
µ[tex]_{c}[/tex] is coefficient of friction for collar
Putting the values in above formula:
[tex]T_{R}[/tex] = 5(25) / 2 [5+ (π(0.09)(25) / π(25)-0.09(5)] + 5(0.06)(45) / 2
= 125/2 [5 + (3.14)(0.09)(25)/ 3.14(25)-0.45] + 13.5/2
= 62.5 [(5 + 7.065) / 78.5 - 0.45] + 6.75
= 62.5 [12.065 / 78.05 ] + 6.75
= 62.5 (0.15458) + 6.75
= 9.66125 + 6.75
= 16.41125
[tex]T_{R}[/tex] = 16.411 Nm
Compute torque to lower the load:
[tex]T_{L} = \frac{ Fd_{m}}{2} (\frac{(\pi ud_{m}) - L }{\pi d_{m}-uL }) +\frac{Fu_{c} d_{c} }{2}[/tex]
= 5(25) / 2 [ (π(0.09)(25) - L / π(25)-0.09(5) ] + 5(0.06)(45) / 2
= 125/2 [ ((3.14)(0.09)(25) - 5) / 3.14(25)-0.45 ] + 13.5/2
= 62.5 [ (7.065 - 5) / 78.5 - 0.45 ] + 6.75
= 62.5 [ 2.065 / 78.05 ] + 6.75
= 62.5 (0.026457) + 6.75
= 1.6535625 + 6.75
= 8.40 Nm
Since the torque required to lower the the load is positive indicating that an effort is applied to lower the load, Hence the thread is self locking.
Compute overall efficiency:
overall efficiency = F(L) / 2π [tex]T_{R}[/tex]
= 5(5) / 2(3.14)( 16.411)
= 25/ 103.06108
overall efficiency = 0.24
A homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time. Determine the average cost per kWh for the month using the following residential rate schedule: Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.
Answer:
16.2 cents
Explanation:
Given that a homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time.
Where Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.
For the first 100 kWh:
16 cent × 100 = 1600 cents = 16 dollars
Since 1 dollar = 100 cents
For the remaining energy:
260 - 100 = 160 kwh
10 cents × 160 = 1600 cents = 16 dollars
The total cost = 10 + 16 + 16 = 42 dollars
Note that the base monthly of 10 dollars is added.
The cost of 260 kWh of energy consumption in July is 42 dollars
To determine the average cost per kWh for the month of July, divide the total cost by the total energy consumed.
That is, 42 / 260 = 0.1615 dollars
Convert it to cents by multiplying the result by 100.
0.1615 × 100 = 16.15 cents
Approximately 16.2 cents
A wedge with a base (x) of 2 ft, height (h2) of 5 ft, and width into the page of 7 ft is holding back water 7ft deep (h1). Determine the weight of the block necessary to prevent the gate from opening.
Answer:
hello your question lacks the required diagram attached below is he missing diagram and solution
answer : 17480.618 Ib
Explanation:
To calculate the weight of block neccessary to prevent the gate from opening , we will first calculate the force of water from the hinge
next we will calculate moments about the force of water and the force about the hinge of the gate
attached below is the complete solution and free hand sketch
from the sketch : h1 = 7 ft, x = 2ft, h2 = 5ft,
Why is it nearly impossible to obtain satisfactory performance from a shunt motor connected to an ac power source
Answer:
Because the shunt winding consist of a large number of turns,
Explanation:
It is nearly impossible to obtain satisfactory performance from a shunt motor connected to an ac power source because the shunt winding consist of a large number of turns, due to the high number of turns that the DC shunt motor has it develops a high impedance when connected to an ac power source. and due to this high impedance the amount of current that flows through the field will be very low making it nearly impossible for the shunt motor to operate properly
An air-conditioning system operates at a total pressure of 1 atm and consists of a heating section and a humidifier that supplies wet steam (saturated water vapor) at 1008C. Air enters the heating section at 108C and 70 percent relative humidity at a rate of 35 m3/min, and it leaves the humidifying section at 208C and 60 percent relative humidity. Determine (a) the temperature and relative humidity of air when it leaves the heating section, (b) the rate of heat transfer in the heating section, and (c) the rate at which water is added to the air in the humidifying section.
Correct question is;
An air-conditioning system operates at a total pressure of 1 atm and consists of a heating section and a humidifier that supplies wet steam (saturated water vapor) at 100°C. Air enters the heating section at 10°C and 70 percent relative humidity at a rate of 35 m3/min, and it leaves the humidifying section at 20°C and 60 percent relative humidity. Determine (a) the temperature and relative humidity of air when it leaves the heating section, (b) the rate of heat transfer in the heating section, and (c) the rate at which water is added to the air in the humidifying section.
Answer:
A) Temperature at state 2: T2 = 19.5°C and Relative Humidity at state 2: Φ2 = 37.8%
B) Q' = 420.01 KJ/min
C) m'w = 0.1472 Kg/min
Explanation:
This question depicts a steady state process and as such the mass flow rate of dry air will remain constant during the entire process.
A) Now, from the psychometric chart attached, at temperatures of T1 = 10°C & T3 = 20°C, Relative humidities; Φ2 = 70% & Φ2 = 60% and at pressure of 1 atm, we have;
Enthalpy at state 1;h1 = 23.5 Kj/kg dry air
Absolute humidity at state 1;ω1 = ω2 = 0.0053 kg of water per kg dry air
Enthalpy at state 3;h3 = 42.3 KJ/Kg dry air
Absolute humidity at state 3; ω3 = 0.0087 kg of water per Kg dry air
Specific volume at state 1;υ1 = 0.809 m³/kg
The formula for energy balance for the humidifying is given as;
h3 = h2 + hg(ω3 - ω2)
Where hg is the enthalpy of wet steam.
From second table attached, hg at 100°C is 2675.6 KJ/kg
Thus;
Making h2 the subject, we have;
h2 = h3 + hg(ω2 - ω3)
Plugging in the relevant values we have;
h2 = 42.3 + 2675.6(0.0053 - 0.0087)
h2 = 33.2 KJ/kg
Still using the psychrometric chart attached at ω2 = 0.0053 and h2 = 33.2 KJ/kg, we have;
Temperature at state 2: T2 = 19.5°C and Relative Humidity at state 2: Φ2 = 37.8%
B) to determine the rate of heat transfer, let's first find the mass flow rate first;
m' = V1'/υ1
Thus, m' = 35/0.809
m' = 43.3 kg/min
Thus, rate of heat transfer is given by;
Q' = m'(h2 - h1)
Plugging in the relevant values, gives;
Q' = 43.3(33.2 - 23.5)
Q' = 420.01 KJ/min
C) the rate at which water is added to the air in the humidifying section is given by;
m'w = m'( ω3 - ω2)
m'w = 43.3(0.0087 - 0.0053)
m'w = 0.1472 Kg/min
Answer:
T₂ = 19.5 °C
∅₂ = 37.8%
Q = 420.01 kJ/min
m[tex]_{w}[/tex] = 0.015 kg/min
Explanation:
Given:
total pressure = p = 1 atm
Temperatures:
T₁ = 10°C
T₃ = 20°C
Relative Humidity:
∅₁ = 70%
∅₃ = 60%
Volume = V₁ = 35 m³/min
Solution:
a) Use psychometric chart to determine the enthalpies by using the given values of temperatures and relative humidity:
h₁ = 23.5 kJ/kg
w₁ = 0.0053
w₁ = w₂
h₃ = 42.3 kJ/kg
w₃ = 0.0087
v₁ = 0.809 m³/kg
When the airs flows through the heating section, the amount of moisture in it remains constant. So
w₁ = w₂
When the airs flows through the humidifying section, the amount of moisture in it increases. So
w₃ > w₂
Compute enthalpy h₂
h₂ = h₃ - ( w₃ - w₂) hs
where hs is the enthalpy of wet steam at 100°C from steam table
hs = 2676 kJ/kg
h₂ = 42.3 - ( 0.0087 - 0.0053 ) 2676
= 42.3 - (0.0034) 2676
= 42.3 - 9.0984
= 33.2016
h₂ = 33.2 kJ/kg
Compute T₂ and ∅₂
Using h₂ = 33.2 kJ/kg and w₂ = 0.0053 and psychometric chart:
T₂ = 19.5 °C
∅₂ = 37.8%
Compute mass flow rate:
mass flow rate = m = V₁ /v₁
= 35/0.809
= 43.26 kg/min
m = 43.3 kg/min
b) Compute heat transfer in the heating section:
Q = m x (h₂ - h₁)
= 43.3 kg/min ( 33.2 kJ/kg - 23.5 kJ/kg )
= 43.3 ( 9.7 )
Q = 420.01 kJ/min
c) Compute rate at which water is added to the air in the humidifying section
Let m[tex]_{w}[/tex] be the mass flow rate equation of water in humidifying section is:
m[tex]_{w}[/tex] = m(w₃ - w₂)
= 43.3 ( 0.0087 - 0.0053 )
= 43.3(0.0034)
= 0.14722
= 0.147 kg/min
m[tex]_{w}[/tex] = 0.015 kg/min
A mixture of 1080g of gravel with effective absorption of 0.9% and 720g of sand with surface moisture of 2.51% was added to concrete mix. Determine the adjustments that must be made to the added water to maintain a constant water cement ratio.
Answer:
the amount of water required to be added to concrete should reduced by 8.352gm
Explanation:
Given that;
amount of gravel = 1080 gm
absorption in gravel = 0.90 %
Now
Amount of water absorbed by gravel
= (0.90 / 100) x 1080 gm = 9.72 gm
we were also told that the amount of sand = 720 gm
and surface moisture = 2.51%
This means , sand will provide some water due to its moisture, therefore adding some water in concrete .Hence, we need to apply correction to maintain constant water cement ratio .
Since, sand is providing water, correction is negative
Amount of water provided by sand = - (2.51/100) x 720 = - 18.072 gm
Overall correction = 9.72 gm - 18.072 gm = - 8.352 gm
Negative sign indicate that the amount of water required to be added to concrete should reduced by 8.352gm
Select the correct answer.
Which of these scenarios depicts unethical workplace practice by an employee?
A.
monitoring employee movement during working hours
B. monitoring use of workplace resources
C. restricting Internet use
D. revealing confidential data
Reset
Next
Answer:
D
Explanation:
Confidential data is not supposed to be shared amongst others.
Answer:
D.
Explanation:
Revealing confidential data is illegal first of all. And second business isn't allowed to share info due to the confidentiality law. All the others aren't unethical, they are just precautions for the safety of other employees.
You are stopped at a red traffic light and are first in line at the intersection. When the traffic light changes to green, you should
Accelerate quickly up to the speed limit.
Go, regardless of other traffic. You have the right-of-way.
Go, but only if the intersection is clear. Yield to pedestrians and vehicles still in the intersection.
Answer:
Go, but only if the intersection is clear.
Explanation:
Traffic at intersection can be complicated at times. If the green light comes on after a red light, you have the right of way to go, but you should be careful to only go when the intersection is clear to avoid an accident. Once using the road, a good driver should be conscious of the other road users, as accidents might happen from you claiming your-right of-way
If the operating control on a commercial water heater fails, the gas valve will be de-energized by?
Answer:
Do not operate water heater if exposed to flooding or water damage. ... de-energize the 24-volt gas valve and end the current heating cycle. The control system
Explanation:
A 10 mm diameter jet of water is deflected by a homogeneous rectangular block (15 mm by 200 mm by 100 mm) that weighs 6 N. Determine the minimum volume flowrate needed to tip the block.
Answer:
The minimum flow rate is [tex]2.66*10^-^4 m^3/s[/tex]Explanation:
The question is in complete without the diagram. please see attached the diagram
From the free body diagram of the block when it is ready to tip
∑M₀= 0.
kindly find attached the diagram of the rectangular block,
the free body diagram, and a detail solving for your reference
. A storm sewer is carrying snow melt containing 1.200 g/L of sodium chloride into a small stream. The stream has a naturally occurring sodium chloride concentration of 20 mg/L. If the storm sewer flow rate is 2,000 L/min and the stream flow rate is 2.0 m3 /s, what is the concentration of salt in the stream after the discharge point? Assume that the sewer flow and the stream flow are completely mixed, that the salt is a conservative substance (it does not react), and that the system is at steady state.
Answer:
Explanation:
In the steady state total volume going out will be equal to total volume coming in , and
total salt coming in = total salt going out
Total volume coming in per minute = 2000 + 2 x 10³ x 60
= 122000 L .
Total salt coming in per minute = 1200 x 2000 + 20 x 2 x 10³ x 60
= 2400000 + 2400000 mg
= 4800000 mg
volume of water going out per minute = 122000 L
Total salt going out per minute = 4800000 mg
concentration of water going out = 4800000 / 122000
= 39.344 mg / L
In a certain voltage-divider biased npn transistor, VB is 2.95 V. The dc emitter voltage is approximately
Answer:
2.25V
Explanation:
In the above question, we are given an npn transistor.
It's VB = Biased voltage = 2.95V
We are asked to calculate the DC emitter voltage.
DC emitter voltage = VB - VBE
Where:
VBE = Voltage between the base and emitter of a bipolar junction transistor
VBE has a set standard voltage of 0.7V
Hence,
DC emitter voltage = 2.95V - 0.7V
= 2.25V
In this exercise we have to use the knowledge of voltage to calculate the difference, like this:
[tex]2.25V[/tex]
Knowing that the initial voltage is given by 2.95V and we want to find the voltage difference we have:
[tex]DC = VB - VBE[/tex]
Where, VBE = Voltage between the base and emitter of a bipolar junction transistor is equal to 0.7 V, this way:
[tex]DC = 2.95V - 0.7V = 2.25V[/tex]
See more about voltage at brainly.com/question/2364325
What is the primary water source for a water cooled recovery unit's condensing coll?
A
Chilled water from the evaporator
B
Condenser water
C
Local municipal water supply
D
De ionized water
The primary water source for a water-cooled recovery unit's condensing coll would be ''Local municipal water supply.'' Hence, option C is true.
Given that,
Ask about the primary water source for a water-cooled recovery unit's condensing coll.
We know that,
A water-cooled recovery unit is generally used to recover large amounts of refrigerant in comparatively less time.
So, The primary water source most often used for cooling the condenser of a water-cooled recovery unit is the local municipal water supply.
Therefore, option C is true.
To learn more about primary water visit:
https://brainly.com/question/1313076
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Determine ten different beam loading values that will be used in lab to end load a cantilever beam using weights. Load values should increase by 100 gram intervals with an initial load of approximately 200 grams
Answer:
1st value = 1.828 * 10 ^9 gm/m^2 ------- 10th value = 7.312 * 10^9 gm/m^2
Explanation:
initial load ( Wp) = 200 g
W1 ( value by which load values increase ) = 100 g
Ten different beam loading values :
Wp + w1 = 300g ----- p1
Wp + 2W1 = 400g ---- p2
Wp + 3W1 = 500g ----- p3 ----------------- Wp + 10W1 = 1200g ---- p10
x = 10.25" = 0.26 m
b = 1.0" = 0.0254 m
t = 0.125" = 3.175 * 10^-3 m
using the following value to determine the load values at different beam loading values
attached below is the remaining part fo the solution
Find the power and the rms value of the following signal square: x(t) = 10 sin(10t) sin(15t)
1. Px =
2. xrmx =
Answer:
[tex]\mathbf{P_x =25 \ watts}[/tex]
[tex]\mathbf{x_{rmx} = 5 \ unit}[/tex]
Explanation:
Given that:
x(t) = 10 sin(10t) . sin (15t)
the objective is to find the power and the rms value of the following signal square.
Recall that:
sin (A + B) + sin(A - B) = 2 sin A.cos B
x(t) = 10 sin(15t) . cos (10t)
x(t) = 5(2 sin (15t). cos (10t))
x(t) = 5 × ( sin (15t + 10t) + sin (15t-10t)
x(t) = 5sin(25 t) + 5 sin (5t)
From the knowledge of sinusoidial signal Asin (ωt), Power can be expressed as:
[tex]P= \dfrac{A^2}{2}[/tex]
For the number of sinosoidial signals;
Power can be expressed as:
[tex]P = \dfrac{A_1^2}{2}+ \dfrac{A_2^2}{2}+ \dfrac{A_3^2}{2}+ ...[/tex]
As such,
For x(t), Power [tex]P_x = \dfrac{5^2}{2}+ \dfrac{5^2}{2}[/tex]
[tex]P_x = \dfrac{25}{2}+ \dfrac{25}{2}[/tex]
[tex]P_x = \dfrac{50}{2}[/tex]
[tex]\mathbf{P_x =25 \ watts}[/tex]
For the number of sinosoidial signals;
[tex]RMS = \sqrt{(\dfrac{A_1}{\sqrt{2}})^2+(\dfrac{A_2}{\sqrt{2}})^2+(\dfrac{A_3}{\sqrt{2}})^2+...[/tex]
For x(t), the RMS value is as follows:
[tex]x_{rmx} =\sqrt{(\dfrac{5}{\sqrt{2}} )^2 +(\dfrac{5}{\sqrt{2}} )^2 }[/tex]
[tex]x_{rmx }=\sqrt{(\dfrac{25}{2} ) +(\dfrac{25}{2} ) }[/tex]
[tex]x_{rmx }=\sqrt{(\dfrac{50}{2} )}[/tex]
[tex]x_{rmx} =\sqrt{25}[/tex]
[tex]\mathbf{x_{rmx} = 5 \ unit}[/tex]
How do you prevent a process B, that was forked from parent process A, from becoming a zombie? Choose one of the following:
1) By having the parent process A wait() for process B
2) By having the child process B wait() for the parent process A
3) By forking process A again, creating another child C
Answer:
3) By forking process A again, creating another child C
Explanation:
To prevent a process B, forked from a parent process A from becoming a Zombie, you have to make sure that the parent process A calls wait for every child process that terminates. We can also fork the process A again, and have the immediate child process B exited immediately.
The direction of rotation of a dc series motor or a universal motor connected to a dc power source A) depends on the polarities of the armature and field currents. B) depends exclusively on the polarity of the armature current. C) depends exclusively on the polarity of the field current. D) depends on the connection of the compensating winding.
Answer:
A) depends on the polarities of the armature and field currents.
Explanation:
In the DC series motor, or a universal motor, the field and armature winding are connected in series. This means that if the polarity of the input DC voltage is changed, the direction of the field & armature will also change, resulting in the change of direction of rotation of the motor. This means that the direction of rotation of a DC series motor, or a universal motor connected to a DC power source can be reversed by changing the polarity of the field current, or the armature current.
As the impurity concentration in solid solution of a metal is increased, the tensile strength:________.a) decreasesb) increasesc) remains unchanged
Answer:
Increases
Explanation:
By inhibiting the motion of dislocations by impurities in a solid solutions, is a strengthening mechanism. In solid solutions it is atomic level strengthening resulting from resistance to dislocation motion. Hence, the strength of the alloys can differ with respect to the precipitate's property. Example, the precipitate is stronger (ability to an obstacle to the dislocation motion) than the matrix and it shows an improvement of strength.
B1) 20 pts. The thickness of each of the two sheets to be resistance spot welded is 3.5 mm. It is desired to form a weld nugget that is 5.5 mm in diameter and 5.0 mm thick after 0.3 sec welding time. The unit melting energy for a certain sheet metal is 9.5 J/mm3 . The electrical resistance between the surfaces is 140 micro ohms, and only one third of the electrical energy generated will be used to form the weld nugget (the rest being dissipated), determine the minimum current level required.
Answer:
I = 8975.95 A
Explanation:
Given :
Diameter of the nugget, D = 5.5 mm
Length of the nugget, l = 5.0 mm
Therefore, volume of the nugget,
[tex]$ V = \frac{\pi}{4}D^2l$[/tex]
= [tex]$\frac{\pi}{4}(5.5)^25 = 118.73\ mm^3[/tex]
Now, required melting energy, (M.E.) = 9.5 x V
= 9.5 x 118.73
= 1127.95 J
Given efficiency of the heat used from electric energy, η = 1/3
Then actual required energy = ME/η
= 1127.95 / (1/3) = 3383.84 J
We know that, electric energy (EE) = [tex]$I^2Rt$[/tex]
where, I is current, R is resistance and t is time in seconds.
3383.75 = [tex]$I^2 \times 140 \times 10^{-6} \times 0.3$[/tex]
I = 8975.95 A
In a three-phase squirrel-cage induction motor, the rotating magnetic field is produced by:__________
a. two electromagnets placed at right angle from each other and two sine wave currents phase shifted of 90° from one another.
b. three electromagnets placed at 90° from each other and three sine wave currents phase shifted of 120° from one another.
c. three electromagnets placed at 120° from each other and three sine wave currents phase shifted of 120° from one another.
d. three electromagnets placed at 120° from each other and three sine wave currents phase shifted of 90° from one another.
Answer: Option C -- three electromagnets placed at 120° from each other and three sine wave currents phase shifted of 120° from one another.
Explanation:
In a three-phase squirrel-cage induction motor, the rotating magnetic field is produced by three electromagnets placed at 120° from each other and three sine wave currents phase shifted of 120° from one another
Water flows at 8.4 m3/s in a trapezoidal channel with a bottom width of 2 m and side slopes of 2:1 (H:V). Over a distance of 100 m, the bottom width expands to 2.5 m, with the side slopes remaining constant at 2:1. If the depth of flow at both of these sections is 1 m and the channel slope is 0.001, calculate the head loss between the sections. What is the power in kilowatts that is dissipated
Answer:
the head loss between the sections is 0.147m
The power in kilowatts that is dissipated 12.1 kW
Explanation:
First we find the area of the trapezoidal channel at section 1 A₁ using the expression
A₁ = b₁y₁ + m₁y₁²
where b₁ is width of channel at section 1 (2m), y₁ is depth of flow at section 1 (1m), m₁ is side slope of the channel at section 1 (2).
so we substitute in the expression
A₁ = ( 2 × 1 ) + ( 2 × 1²) = 4m²
next we find the area of the trapezoidal channel at section 1 A₂ using the expression.
A₂ = b₂y₂ + m₂y₂²
where b₂ is width of channel at section 2 (2.5m), y₂ is depth of flow at section 2 (1m), m₂ is side slope of the channel at section 2 (2).
so we substitute in the expression
A₂ = ( 2.5 × 1 ) + ( 2 × 1²) = 4.5m²
Next we determine the velocity at section 1 ( V₁) using the expression
V₁= Q/A₁
where Q is the flow rate of the channel (8.4m³/s)
so we substitute
V₁ = 8.4 / 4 = 2.10 m/s
the velocity at section 2 ( V₂) using the expression
V₂= Q/A₂
where Q is the flow rate of the channel (8.4m³/s)
we substitute
V₂ = 8.4 / 4.5 = 1.87 m/s
Now we find the friction head loss per unit length ( Sf) using this expression;
y₁ + v₁²/2g - y₂ - v₂²/2g = L ( Sf - S₀ )
where g is acceleration due to gravity ( 9.81 m/s), L is distance between the inflow and outflow sections of the control volume ( 100m), S₀ is the longitudinal slope of the section( 0.001)
now we substitute
1 + (2.10²/(2×9.81)) - 1 - (1.87²/(2×9.81)) = 100( Sf - 0.001 )
100Sf - 0.1 = 0.0465
100Sf = 0.1465
Sf = 0.00147
Now to calculate the head loss between the sections hL, we say
hL = L × Sf
remember oue L = 100m and Sf = 0.00147
so we substitute
hL = 100 × 0.00147
hL = 0.147m
∴ the head loss between the sections is 0.147m
To find the power in kilowatts that is dissipated we say;
P = YωQhL
where Yω is the specific weight of water ( at 20°C = 9.79kN/m³
so P = 9.79 × 8.4 × 0.147
P = 12.0887 ≈ 12.1 kW
∴ The power in kilowatts that is dissipated 12.1 kW
Stone has been used as a building material since ancient times because of its compressive strength, which is the __________.
Complete Question:
Stone has been used as a building material since ancient times because of its compressive strength, which is the?
Group of answer choices
A. ability to support pressure without breaking.
B. ability to press down and become solidly fixed in the ground.
C. relative weight of a block of stone to its size.
D. force a block exerts on the blocks around it.
Answer:
A. ability to support pressure without breaking.
Explanation:
Stone has been used as a building material since ancient times because of its compressive strength, which is the ability to support pressure without breaking.
Compressive strength can be defined as the ability of a structural element or particular material to withstand an applied, which is aimed at reducing the size of the structural element.
Simply stated, it is the ability of a structural element or material to withstand an applied load without deflections, fracture or having any crack.
In this context, a stone possesses the ability to resist or withstand compression loads.
Some examples of other materials or structural elements having good compressive strength are steel, bones, concrete etc. The standard unit of measurement of the compressive strength of a material is Mega Pascal (MPa) or pound-force per square inch (psi) in the United States of America.
An air-conditioning system operates at a total pressure of 1 atm and consists of a heating section and a humidifier that supplies wet steam (saturated water vapor) at 1008C. Air enters the heating section at 108C and 70 percent relative humidity at a rate of 35 m3/min, and it leaves the humidifying section at 208C and 60 percent relative humidity. Determine (a) the temperature and relative humidity of air when it leaves the heating section, (b) the rate of heat transfer in the heating section, and (c) the rate at which water is added to the air in the humidifying section.
Correct question is;
An air-conditioning system operates at a total pressure of 1 atm and consists of a heating section and a humidifier that supplies wet steam (saturated water vapor) at 100°C. Air enters the heating section at 10°C and 70 percent relative humidity at a rate of 35 m3/min, and it leaves the humidifying section at 20°C and 60 percent relative humidity. Determine (a) the temperature and relative humidity of air when it leaves the heating section, (b) the rate of heat transfer in the heating section, and (c) the rate at which water is added to the air in the humidifying section.
Answer:
A) Temperature at state 2: T2 = 19.5°C and Relative Humidity at state 2: Φ2 = 37.8%
B) Q' = 420.01 KJ/min
C) m'w = 0.1472 Kg/min
Explanation:
This question depicts a steady state process and as such the mass flow rate of dry air will remain constant during the entire process.
A) Now, from the psychometric chart attached, at temperatures of T1 = 10°C & T3 = 20°C, Relative humidities; Φ2 = 70% & Φ2 = 60% and at pressure of 1 atm, we have;
Enthalpy at state 1;h1 = 23.5 Kj/kg dry air
Absolute humidity at state 1;ω1 = ω2 = 0.0053 kg of water per kg dry air
Enthalpy at state 3;h3 = 42.3 KJ/Kg dry air
Absolute humidity at state 3; ω3 = 0.0087 kg of water per Kg dry air
Specific volume at state 1;υ1 = 0.809 m³/kg
The formula for energy balance for the humidifying is given as;
h3 = h2 + hg(ω3 - ω2)
Where hg is the enthalpy of wet steam.
From second table attached, hg at 100°C is 2675.6 KJ/kg
Thus;
Making h2 the subject, we have;
h2 = h3 + hg(ω2 - ω3)
Plugging in the relevant values we have;
h2 = 42.3 + 2675.6(0.0053 - 0.0087)
h2 = 33.2 KJ/kg
Still using the psychrometric chart attached at ω2 = 0.0053 and h2 = 33.2 KJ/kg, we have;
Temperature at state 2: T2 = 19.5°C and Relative Humidity at state 2: Φ2 = 37.8%
B) to determine the rate of heat transfer, let's first find the mass flow rate first;
m' = V1'/υ1
Thus, m' = 35/0.809
m' = 43.3 kg/min
Thus, rate of heat transfer is given by;
Q' = m'(h2 - h1)
Plugging in the relevant values, gives;
Q' = 43.3(33.2 - 23.5)
Q' = 420.01 KJ/min
C) the rate at which water is added to the air in the humidifying section is given by;
m'w = m'( ω3 - ω2)
m'w = 43.3(0.0087 - 0.0053)
m'w = 0.1472 Kg/min
The u velocity component of a steady, two-dimensional, incompressible flow field is u = 3 ax 2 - 2 bxy, where a and b are constants. Velocity component v is unknown. Generate an expression for u as a function of x and y.
Answer:
The velocity component v is [tex]-6axy+2by^2+f(x)[/tex]
Explanation:
Given that,
The velocity component of a steady, two-dimensional
[tex]u=3ax^2-2bxy[/tex]
We need to calculate the function of x
Using given equation
[tex]u=3ax^2-2bxy[/tex]
Where, a and b is constant
On differential
[tex]\dfrac{du}{dx}=6ax-2by[/tex]
We need to calculate the velocity component v
Using equation of velocity
[tex]\dfrac{dv}{dy}=-\dfrac{du}{dx}-\dfrac{dw}{dz}[/tex]
Put the value into the formula
[tex]\dfrac{dv}{dy}=-6ax+2by-0[/tex]
Now, on integration w.r.t y
[tex]v=-6axy+2by^2+f(x)[/tex]
Hence, The velocity component v is [tex]-6axy+2by^2+f(x)[/tex]
The first attempt to strengthen concrete flexural elements by externally bonded steel plates was attempted in?
Answer:
Explanation:
The first reported attempts to strengthen concrete flexural elements by externally bonded steel plates were attempted in France around 1964-65 and practical applications date back to 1966-67 in France and South Africa then followed by Japan and Russia.
Human settlement has 5 elements. How do you observe those 5 elements around you. Give examples.
Answer:
5 elements that human settlement required are discussed below in complete details.
Explanation:
Nature: The climate and the biosphere that give the basic requirements to survive.Society: Agglomeration of characters that builds communication and connection administered by social artifacts such as political, social, cultural, and spiritual.Man: makes a choice on what to do with the sources around them.Networks: these are ways through which people, power, and knowledge flow.Shells: Contain human movements and provide protection.An array of eight 2024 T6 aluminum alloy rectangular fins each 3 mm wide x 0.4 mm thick and 40 mm long is used to cool a transistor. When the base is 340 K and the ambient air is 300 K, how much power does the array dissipate? Take the combined convection and radiation heat transfer coefficient to be 8.0 W/m^2 K.
Answer: total heat dissipated from the array is 0.60 Watt
Explanation:
No. of fins 8
Given that:
Wdth (b) = 3 mm = 0.003 m
thickness (t) = 0.4 mm = 0.0004 m
length (L) = 40 mm
combined convection and radiation heat transfer coefficient to be = 8.0 W/m² K.
Tb = 340 K, Tw = 300 K
First we compute for area of fins A = 0.003 m × 0.00004 = 1.2 × 10⁻⁶ m²
Perimeter of Fin P = 2( 0.003 m + 0.00004 m ) = 0.0068 = 6.8 × 10⁻³
for 2024 T6 aluminium alloy K = 151 W/m-k from table
Now
m = √ ( hp/ka) = √[( 8 × 6.8 × 10⁻³ ) / (151 × 1.2 × 10⁻⁶ m²)] = 17.327
Lc = L + t/2 = 40 + 0.4/2 = 40.2 mm = 40.2 × 10⁻³
Now heat transfer from on fin :
Q = √( hpKA) × (Tb-Tw) × Tanh(mLc)
= √( 8×6.8 × 10⁻³×151×1.2 × 10⁻⁶) × (340-300) × tanh (0.6965)
= 3.13963 × 40 × 0.602144
= 0.075620 Watt
So total heat dissipated from array of 8 fins = 8 ×0.075620 = 0.60 Watt
Which BEST identifies a contrast in these two passages? A) The actions taken by the bird in the poem cause injuries, but the actions taken by Sojourner Truth in the account do not cause any injuries. B) The actions taken by the bird in the poem cause no injuries, but the actions taken by Sojourner Truth in the account cause her great injuries. C) The actions taken by the bird in the poem are effective, but the actions taken by Ms. Truth, Ms. Griffling, and Ms. Haviland in the account have no impact. D) The actions taken by the bird in the poem are ineffective, but the actions taken by Ms. Truth, Ms. Griffling, and Ms. Haviland in the account have a great impact.
The option that BEST identifies a contrast in these two passages is option D) The actions taken by the bird in the poem are ineffective, but the actions taken by Ms. Truth, Ms. Griffling, and Ms. Haviland in the account have a great impact.
What do you mean by contrast?The term contrast is known to be a word that tends to show some noticeable differences between two things.
Note that it is liken to a cause and its effect. The option that BEST identifies a contrast in these two passages is option D) The actions taken by the bird in the poem are ineffective, but the actions taken by Ms. Truth, Ms. Griffling, and Ms. Haviland in the account have a great impact.
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A rigid container is partly filled with a liquid at 1520 kPa. The volume of the liquid is 1.232 litres. At a pressure
of 3039 kPa, the volume of the liquid is 1.231 litres.
a. Calculate the average bulk modulus of elasticity of the liquid
Answer:
Bulk modulus: ß = - ∆p/(∆V/V)
∆p = (3039 - 1520)x10³ = 1519 kPa
∆V = 1231 - 1232 = -1 m³
V = 1232 m³
ß = - 1519/(-1/1232) = 1.87x10^6 kPa = 1.87 GPa
Explanation:
a.The average bulk modulus of elasticity of the liquid is 1.87 GPa
b. Coefficient of compressibility 0.5437 GPa-¹
c Velocity of sound 1.87 x 10^9P
a. Bulk modulus of elasticity
ß = - ∆p/(∆V/V)
First step is to determine ∆p
∆p = (3039 kpa - 1520 kpa)x10³
∆p = 1519 kPa
Second step is to determine ∆V
∆V = 1231 litres - 1232 litres
∆V = -1 m³
Now let determine the Bulk modulus of elasticity
Bulk modulus of elasticity= - 1519/(-1/1232)
Bulk modulus of elasticity= 1.87x10^6 kPa
Bulk modulus of elasticity= 1.87 GPa
b. The coefficient of compressibility
Coefficient of compressibility=β =1/K
Coefficient of compressibility=β =1/1.87
β =0.5437 GPa-¹
C. Velocity of sounds in the medium with a density of 1593 kg/m3
V=√K/ρ
V=√1.87×10^9/ 1593
V=1083m/s
V = 1.87 x 10^9P
Inconclusion:
a.The average bulk modulus of elasticity of the liquid is 1.87 GPa
b. Coefficient of compressibility 0.5437 GPa-¹
c Velocity of sound 1.87 x 10^9P
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You have just been hired as the Security Manager of a medium- sized Financial Services company employing 250 people in New Hampshire, and have been asked to write two new security policies for this company. The first one is an e-mail policy for employees concentrating on personal use of company resources. The second policy is that of WIFI and Internet use within the company.
There are many resources available on the web so researching these topics and policies should be easy. The most difficult part of this exercise will be determining how strict or how lenient you want to make these policies for this particular company.
Project Plan
You are asked to create two separate policies on use of EMAIL and a WIFI/INTERNET USE within the company. Be specific in your terms and conditions of use. Consider these items to be included in your policies (as applicable).
1. Overview
2. Purpose
3. Scope
4. Policy
5. Policy Compliance
6. Related Standards, Policies and Processes
7. Definitions and Terms
Answer:
Explanation:
Let us Begin with the first Policy;
Email Policy
Outline/Overview - At present, email is truly outstanding, simple, and well known correspondence medium which interfaces workers, clients, and different partners of the organization. Because of the improvement of the innovation, the aggressors are attempting to utilize email for doing assaults which are driving security dangers inside the organization. Henceforth, it is significant for all representatives to comprehend the best possible utilization of email. Reason/Purpose - The motivation behind the email strategy is to affirm the correct utilization of email address of the organization by the representatives. Scope - The arrangement is covering the utilization of any email which is sent from an organization email address. It additionally applies to all related representatives, clients, and different partners who are working in the interest of the organization. PolicyThe email address of the organization ought to be utilized by workers just for business reason. Representatives are restricted to unlawfully utilize the organization email address. The utilization of the email office must be steady with other security approaches of the organization. It gives the guarantee of the moral conduct inside the organization. The "Information Protection Standards" must be utilized to make sure about the substance of the messages. The organization must need to hold just clear email and keep up a record which stores the substance of the necessary messages. The representatives ought to need to take care during opening any sort of dubious email which originates from unlawful location. They should need to answer to the security chief on the off chance that they got any sort of such email.It isn't permitted to advance email to any outsider utilizing the organization email address. The representatives are not permitted to utilize the organization email address for individual works and correspondence. Policy Compliance - The security group of the organization will confirm the consistence of the approach utilizing suitable strategies, for example, stroll through, inward and outside reviews, business instrument reports, video checking, and input. The security group must need to educate and support any sort of special case to the arrangement ahead of time. Related Standards, Policies, and Processes - Data assurance guidelines Definitions and Terms - NoneThe Second Policy;
WIFI and Internet usage policy
Overview - The expanding utilization of web associations is bringing different sorts of security dangers for the organization. It turns into a significant asset of assault. A WIFI and Internet utilization strategy will control the unlawful and dishonest use of web assets inside the organization. Purpose - The motivation behind WIFI and Internet use strategy is to affirm the best possible utilization of WIFI and Internet by the representatives inside the organization. Scope - The arrangement applies to each web client including full-time representatives, low maintenance workers, colleagues, and so on of the organization. PolicyAsset utilization – Employees will get consent and endorsement to get to WIFI and Internet if sensible business needs are found. As per the present place of employment obligations, the WIFI and Internet administrations will be conceded to the workers. Permitted utilization – WIFI and Internet use is conceded to representatives just for supporting the business capacities and finishing some other important works. All web clients must need to follow the business standard during the utilization of assets.Individual use – Employees can by and by utilize the WIFI and Internet assets by taking consent from the IT office. They should need to take care during individual use as the organization consistently screens their web use exercises. Denied utilization – The representatives are not permitted to abuse the accessible database of the organization or unlawful web surfing through organization web assets. Policy Compliance - The security group of the organization will confirm the consistence of the arrangement utilizing proper techniques, for example, stroll through, interior and outer reviews, business apparatus reports, video checking, and input. Related Standards, Policies, and Processes - The organization must need to utilize "Web utilization inclusion affirmation structure" for taking the affirmation from every representative in the wake of perusing the arrangement. The affirmation structure guarantees that each representative appropriately read the arrangement and get it.Affirmation
I peruse and comprehend the approach. I am concurred with the arrangement.
Worker name and signature________________________
IT administrator name and signature_______________________
Date_____________________
. Definitions and Term - NoneA stone-filled pit used for waste disposal is commonly referred to as a
Answer:
The answer is =Soak pit / Soakage pit