A simple pendulum is constructed by hanging a 3 kg mass on the end of a 0.8 m long string. The pendulum is pulled back to a height of 0.2 m and released. At what time will the mass first reach its maximum velocity

Answers

Answer 1

Answer:

The time when the mass will reach its first maximum velocity  is 1.8 s.

Explanation:

Given;

mass of the pendulum, m = 3 kg

length of the pendulum, l = 0.8 m

height in which the pendulum is raised to, h = 0.2 m

the mass will reach its first maximum velocity when it returns to its initial position, i.e at the middle (x = 0).

the distance between the initial position of the pendulum and the height in which it is raised is the maximum displacement (A).

If we form a right angle triangle with respect to the height in which the pendulum is raised;

the height of the right triangle, H = L - 0.2 = 0.8 - 0.2 = 0.6 m

the hypotenuse side, = L = 0.8 m

the base of the triangle (opposite side) = A

A² = L² - H²

A² = (0.8)² - (0.6)²

A² = 0.28

A = √0.28

A = 0.529 m

The maximum velocity of the pendulum is calculated as;

[tex]V_{max} = A \omega\\\\V_{max} = A \sqrt{\frac{g}{l} } \\\\V_{max} = (0.529)\sqrt{\frac{9.8}{0.8} }\\\\V_{max} = 1.852 \ m/s[/tex]

The period is calculated as;

[tex]V_{max} = A\omega\\\\V_{max} = A (\frac{2\pi}{T} )\\\\T = \frac{2\pi A }{V_{max}}\\\\T = \frac{2\pi \ \times \ 0.529}{1.852} \\\\T = 1.8 \ s[/tex]

Therefore, the time when the mass will reach its first maximum velocity  is 1.8 s.


Related Questions

Which statement describes the vector plotted below?
A. The vector goes from (1, -2) to (-3,1).
B. The vector goes from (-3,-1) to (-3,-1).
c. The vector goes from (1, 2) to (-3,1).
D. The vector goes from (-3,-1) to (1,2).

Answers

Answer: the vector goes from (1,2) to (-3,1)

Explanation:

A 60.0 kg woman runs up a staircase 15 m high (vertically) in 20. s. (a) How much power does she expend

Answers

Given that,

Mass of a woman, m = 60 kg

She runs up a staircase 15 m high in 20 s.

To find,

Power expanded.

Solution,

Power = rate of doing work

[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{60\times 9.8\times 15}{20}\\\\=441\ W[/tex]

So, the required power is 441 W.

honey solidifies from the bottom whereas water from the top. Why?

Answers

Answer:

it is due to anamolous expansion of water as water cools from 4dg.c to 0dg.c. it expand making ice lighter than water to float

help mmmemememeeee I'M BEING TIMED

Answers

Answer:

it's c. or A. not b.

Explanation:

.................

Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 l

Answers

Answer:

585lb

Explanation:

Given the following

F1 = 235lb

F2 = 350lb

The resultant is expressed as;

FR = F1+F2

Substitute the given values

FR = 235+350

FR = 585lb

Hence the magnitude of the resultant is 585lb

4.
What is the BEST example you can offer to explain a folkway?

A. It is against your religious beliefs to commit adultery.

B. Your workplace decreases your pay if you arrive late.

C. When you answer your phone, you say hello.

D. All people are kind to one another.

Answers

The answer is A. A folkway is a closely held belief by a specific group of people.
ITS A!!! UEHHSBSHHWBEBSNIWJWBSBENSJAHWVVSBSISEE

Consider the standing wave on a guitar string and the sound wave generated by the string as a result of this vibration. What do these two waves have in common

Answers

Answer:

As the string vibrates, it "moves" the particles in the air, generating what we know as a soundwave.

Because this soundwave is generated by the wave-like motion of the string, makes sense that the soundwave will have some characteristics in common with the standing wave on the guitar string. This means that both waves will have the same normal modes. (So if the principal mode of the vibrating string has a frequency of 440hz, to soundwave also will have that main frequency, and we will hear an A). You can hear almost all the normal modes when you pluck a guitar string, particularly in music, these are called "overtones" or "harmonics"

A 200 kg motorcycle speeds at 90 mph (40 m/s) off of a highway overpass and lands on top of a 18,000 kg semi truck, which is traveling in the same direction at 65 mph (30 m/s). Assume both vehicles stick together are coasting without friction after the collision. What will be the final speed of the semi truck after the collision

Answers

Answer:

The final speed of the semi truck is 30.11 m/s.

Explanation:

Given;

mass of the motorcycle, m₁ = 200 kg

initial speed of the motorcycle, u₁ = 40 m/s

mass of the semi truck , m₂ = 18,000 kg

initial speed of the semi truck, u₂ = 30 m/s (same direction as u₁)

If the two vehicles stick together after collision, the final speed of the motorcycle will be equal to final speed of the semi truck = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(200 x 40) + (18,000 x 30) = v(200 + 18,000)

8000 + 540,000 = v(18,200)

548,000 = v(18,200)

[tex]v = \frac{548,000}{18,200} \\\\v = 30.11 \ m/s[/tex]

Therefore, the final speed of the semi truck is 30.11 m/s.

If a 15kg mass weighs 372 N on Jupiter, what is Jupiter's gravitational acceleration?

Answers

Answer:

The mass of Jupiter is 1.9 x 1027 kg. It is hard to fully understand a number that large, so here are a few comparisons to help. It would take 318 times Earth's mass to equal Jupiter's.

Explanation:

The two charges are then brought closer together so that the force between them increases by a factor of 25. By what factor was their separation decreased

Answers

Answer:

Explanation:

The forces between two charges is inversely proportional to the square of distance.

 [tex]F = k q_1 q_2 / r^{2}[/tex]

So  if the distance is half  then the force increases by a factor of 4 . if force between the charges increases by a factor of 25 then separation between them is decreased by a factor of  5 i.e distance between them is 1/5.    

A 146N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor. Find the coefficient of friction.

Answers

Answer:

F = force

f = friction

u = coefficient of friction

R = normal reaction force

a = Acceleration

m = mass of block

g = gravity

f = uR

F = Ma

Say the block is moving to the right.

The 146N force thus acts to the right, and the friction force to the left, since it resists movement.  

The 146N force acts to the right, but the horizontal component of it is 146 cos 50  = 93.84: So this is the force to the right.

Since F = uR and we're trying to find u, we need both F and R. R is easy to get since it is just m x g. This is in fact already given as the weight 350N. So R = 350.

The block is moving at a constant speed, so the force to the right must = the force to the left.

F = ma, so 93.84 - f = (350/g) x 0

This means f must be 93.84 also.  

so  we have f = uR,  

      93.84 = u x 350

so u = 0.268 or  

0.27 to 2dp.  

Hope you understand this.

Explanation:

The coefficient of friction is 0.26 if the 46N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N). Mathematically it is defined as the product of the coefficient of friction and normal reaction.

We know:

f = uR

Where f is the friction force and u is the coefficient of friction, R is the normal reaction force.

The horizontal component of 146N is:

F' = 146cos50°

F' = 93.84 N

Since F  = mass×acceleration

Because the block is traveling at a constant speed, the right-hand force must equal the left-hand force.

F' = f = 93.84 N

93.84 = u x 350   (R = 350N)

u = 0.26

Thus, the coefficient of friction is 0.26 if the 46N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor.

Learn more about the friction force here:

https://brainly.com/question/1714663

#SPJ2

At what efficiency is a photovoltaic array running if insolation on the collector is 650 W/m2, the total collector area is 10 m2, the voltage across the array is 50 V, and the current being delivered is 15 A

Answers

Answer: 11.53 %

Explanation:

Given

area [tex]A=10\ m^2[/tex]

Voltage V=50 V

current I=15 A

Array running at [tex]650\ W/m^2[/tex]

Power  [tex]P=VI=50\times 15=750\ W[/tex]

Efficiency [tex]\eta=\frac{750}{650\times 10}\times 100=11.53\%[/tex]

What is the difference between the number of electrons in an atom of Iodine (I) and the number of electrons in an atom of Aluminum (Al)?

Answers

Answer:

Iodine is element number 53. Iodine has 53 protons and 53 electrons (because it has no charge the number of protons equals the number of electrons). Iodine-131 has 131 protons and neutrons.

Explanation:

You walk into the living room and find your family watching a nature documentary on PBS. Which lens does this network fall under

Answers

Answer:

Natural Sciences

Explanation:

This network would fall under the lens of Natural Sciences. This is based on what the family is currently watching. Nature documentaries focus on our Planet as well as all the wildlife in it. In these documentaries, they talk about how and why certain things in nature occur. All of this would be considered educational information on the subjects of Earth Science and Biology which are main subcategories under the lens of Natural Sciences.

if a tomato is considered a fruit... then is ketchup considered a smoothie?

Answers

Answer:

depends... do you add suger to your ketchup?

Explanation:

distance formula and unit

Answers

Answer:

distance = speed × time

Explanation:

the unit of distance is meter(m)

but the formula differs according to the given

When you graph displacement vs. time, velocity is represented by
A. the x-intercept of the graph
B. the y-intercept of the graph
C. the slope of the graph
D. the curve of the graph

Answers

C. The slope of the graph

A rope 6m long is fixed at one end; the other end is attached to a light string so that it is free to move. The speed of waves on the rope is 18 m/s. The frequency of the second harmonic is

Answers

Given :

A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.

The speed of waves on the rope is 18 m/s.

To Find :

The frequency of the second harmonic.

Solution :

We know, for second harmonic wave :

Wavelength = Length of rope

[tex]\lambda = L\\\\\lambda = 6 \ m[/tex]

Now, we know frequency is given by :

[tex]Frequency = \dfrac{Speed}{Wavelenght}\\\\f = \dfrac{18 \ m/s}{6\ m}\\\\f = 3 \ s^{-1}[/tex]

Therefore, the frequency of the second harmonic is 3 s⁻¹.

A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the person is 67.0 kg, the mass of the skateboard is 4.10 kg, and the mass of the brick is 2.50 kg. If the person throws the brick forward (in the direction they are facing) with a speed of 23.0 m/s relative to the skateboard and we ignore friction, determine the recoil speed of the person and the skateboard, relative to the ground.

Answers

Answer:

    v₁ = -0.8087 m / s

Explanation:

To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved

Initial instant. When they are united

        p₀ = 0

Final moment. After throwing the brick

        [tex]p_{f}[/tex] = (m_man + m_skate) v1 + m_brick v2

the moment is preserved

        p₀ = p_{f}

        0 = (m_man + m_skate) v₁ + m_brick v₂

        v₁ = -  [tex]\frac{ m_{brick} }{m_{man} + m_{skate} } v_{2}[/tex]

the negative sign indicates that the two speeds are in the opposite direction

let's calculate

        v₁ = - [tex]\frac{2.5}{67 + 4.10} 23.0[/tex]

        v₁ = -0.8087 m / s

where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.02 ohms per second. When the resistance is 100 ohms and the current is 0.02 amperes, at what rate is the current changing

Answers

Answer:

[tex]\frac{dI}{dt} =-3.04*10^-^4amps/sec[/tex]

Explanation:

From the question we are told that

Voltage change [tex]\frac{dv}{dt}=-0.03volts/sec[/tex]

Resistance change [tex]\frac{dR}{dt}=0.02ohms/sec[/tex]

Resistance [tex]R=100[/tex]

Current [tex]I=0.02[/tex]

Generally the equation for ohms law is mathematically represented as

[tex]V=IR[/tex]

Therefore

[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

Resolving the Rate of current changing [tex]\frac{dI}{dt}[/tex] as subject of formula

[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

[tex]R\frac{dI}{dt} =\frac{dv}{dt} -I\frac{dR}{dt}[/tex]

[tex]\frac{dI}{dt} =\frac{1}{R} (\frac{dv}{dt} -I\frac{dR}{dt})[/tex]

Therefore

[tex]\frac{dI}{dt} =\frac{(-0.03) -(0.02)(0.02)}{100}[/tex]

[tex]\frac{dI}{dt} =-3.04*10^-^4amps/sec[/tex]

Therefore the current decreases at a rate

[tex]\frac{dI}{dt} =3.04*10^-^4amps/sec[/tex]

A block weighing 9.3 N requires a force of 3.7 N to push it along at constant velocity. What is the coefficient of friction for the surface

Answers

Answer:

0.398

Explanation:

According to friction, the frictional force is directly proportional to the normal reaction

Ff = nR

Ff is the frictional force

n is the coefficient of friction

R is the reaction

Reaction is equal to the weight

R= W = 9.3N

Fm = Ff = 3.7N

Fm is the moving force

Get the coefficient of friction

n = Ff/R

n = 3.7/9.3

n = 0.398

Hence the coefficient of friction for the surface is 0.398

A concave mirror creates a real, inverted image 16.0 cm from its surface. If the image is 3.5 times larger, how far away is the object? Use the GUESS method to solve the problem and show all your work. Record you final answer using the correct number of significant digits

Answers

Answer:

3.6, make sure you study

Question 7 of 10
What is the period of a wave with a frequency of 3 Hz and an amplitude of
0.01 m?
A. 0.0033 s
B. 300 s
C. 0.33 s
D. 0.030 S

Answers

Answer:

0.33s

Explanation:

hope this is the correct ans

Help please!!

During transcription, the DNA strand being transcribed has the following nucleotides: CTT CAG.


What would be the matching nucleotides on the mRNA?


Select one
1. GAA GUC
2.GUU GTC
3. AUU ATC
4. ACC AUC

Answers

Answer:

l think the correct answer is 1.GAA GUC

One wave of 1 m amplitude meets another wave of 2 m amplitude. If they are exactly out of phase, what is the magnitude of the new amplitude

Answers

Answer:

1 m

Explanation:

Assuming both waves have the same frequency, and speed, this means that they have the same wavelength.If they are exacty out of phase, one will be at its maximum positive amplitude (crest), while the other will be at its maximum negative amplitude (trough), which means that the magnitude of the new amplitude will be the difference between both amplitudes, i.e., 1 m.If both waves had the same amplitude, the new amplitude would be just zero.


1. Define "compressibility." Give an example from your daily life

Answers

the capacity of something to be flattened or reduced in size by pressure.

A 7.03 nC charge is located 1.75 m from a 4.26 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.

Answers

Given that,

Charge, q₁ = 7.03 nC

Charge, q₂ = 4.26 nC

Distance, r = 1.75 m

To find,

The magnitude of the electrostatic force that one charge exerts on the other.

Solution,

The force between two charges at a distance is given by the formula as formula :

[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 7.03\times 10^{-9}\times 4.26\times 10^{-9}}{(1.75)^2}\\\\=8.8\times 10^{-8}\ N[/tex]

So, the required force is [tex]8.8\times 10^{-8}\ N[/tex].

A 9.0 kg test rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1905 J by the time the rocket engine burns all of the fuel. What additional height will the rocket rise

Answers

Answer:

21.6m

Explanation:

Since the rocket engine burns all the fuel hence the kinetic energy will be converted to potential energy

Potential Energy = mass × acceleration due to gravity × height

Given

PE = 1905J

Mass = 9.0kg

Acceleration due to gravity =9.8m/s²

Required

Height h

Substitute into the formula

1905 = 9(9.8)h

1905 = 88.2h

h =1905/88.3

h = 21.6m

Hence the required height is 21.6m

Describe reflection using the terms incident ray and reflected ray.

Answers

Answer:

Explanation:

The ray of light that hits the polished surface is called the incident ray. The ray that gets reflected away is called the reflected ray. The point at which the light hits the surface is called the point of incidence. If a line is drawn perpendicular to that point, it is called the normal.

Find the magnitude of the velocity of the of the chain when 5.58 m of the chain is hanging vertically. Answer in units of m/s.

Answers

Answer:

10.46m/s

Explanation:

Given

Distance = 5.58m

Required

magnitude of the velocity'

Using the equation of motion expressed as

v² = u² + 2gS

v² = 0  +2(9.8)(5.58)

v² = 109.368

v= √109.368

v = 10.46m/s

Hence the magnitude of the velocity of the of the chain is 10.46m/s

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