The probability that exactly 90 defective washers are found is (400 choose 90) * (1100 choose 110) / (1500 choose 200). and the probability that at least 2 defective items are found is (400 choose 1) * (1100 choose 199) / (1500 choose 200).
Let X be the number of defective washers in a sample of 200 washers.
We can model X as a hypergeometric distribution with parameters N = 1500 (total number of washers), K = 400 (total number of defective washers), and n = 200 (sample size).
a) The probability of finding exactly 90 defective washers is:
P(X = 90) = (400 choose 90) * (1100 choose 110) / (1500 choose 200)
This is because we need to choose 90 defective washers from the 400 defective washers, and 110 non-defective washers from the 1100 non-defective washers, out of the total of 200 washers chosen.
b) The probability of finding at least 2 defective items can be calculated as the complement of the probability of finding 0 or 1 defective item in the sample:
P(X >= 2) = 1 - P(X = 0) - P(X = 1)
To compute P(X = 0), we need to choose 0 defective washers from the 400 defective washers, and 200 non-defective washers from the 1100 non-defective washers, out of the total of 1500 washers:
P(X = 0) = (400 choose 0) * (1100 choose 200) / (1500 choose 200)
To compute P(X = 1), we need to choose 1 defective washer from the 400 defective washers, and 199 non-defective washers from the 1100 non-defective washers, out of the total of 1500 washers:
P(X = 1) = (400 choose 1) * (1100 choose 199) / (1500 choose 200)
Once we have computed P(X = 0) and P(X = 1), we can substitute these values into the expression for P(X >= 2) to obtain the desired probability.
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get it right ok PLS!!!!!!!!!!!!!!!!!!!!!!!
Answer:
The number in standard form is 304.014.
Answer:
The Standard form of the number is 44,410.
What is Multiplication?
To multiply means to add a number to itself a particular number of times.
Multiplication can be viewed as a process of repeated addition.
Here, given number(3 X 100) + (1 X 110) + (4 X 11000)(300) + (110) + (44000)300 + 110 + 44000410 + 4400044410
Thus, the Standard form of the number is 44,410.
In calculus, we define a function f with domain R to be strictly increasing provided that for all real numbers x and y, f (x) < f (y) whenever x < y. Complete each of the following sentences using the appropriate symbols for quantifiers: (a). A function f with domain R is strictly increasing provided that ____ (b). A function f with domain R is not strictly increasing provided that ____
Complete the following sentence in English without using symbols for quan- tifiers: (c). A function f with domain R is not strictly increasing provided that ____
A function f with domain R is strictly increasing provided that - f(x) < f(y).
A function f with domain R is not strictly increasing provided that - f(x) >= f(y).
A function f with domain R is not strictly increasing provided that - x < y, but f(x) >= f(y)
(a) A function f with domain R is strictly increasing provided that for all real numbers x and y, if x < y, then f(x) < f(y).
(b) A function f with domain R is not strictly increasing provided that there exist real numbers x and y such that x < y, but f(x) >= f(y).
(c) A function f with domain R is not strictly increasing provided that there exist two real numbers x and y such that x < y, but f(x) >= f(y), i.e., the function does not strictly increase between x and y.
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For each linear operator T on the vector space V, find an ordered basis for the T-cyclic subspace generated by the vector z. (a) V=R^4, T(a,b,c,d) = (a I b,b - c,a + c,a + d), and z = e1.(b) V=P3(R), T(F(x)) = f'(x), and z = x^3 (c) V=M2x2(R), T(A) = A^t, and z = (0 1 1 0) (d) V=M2x2(R), T(A) =(1 2 2 2) A, and z =( 0 1 1 0)
The ordered bases for the T-cyclic subspaces generated by z in (a), (b), (c), and (d) are[tex]B={e1, Te1, T^2e1, T^3e1}, B={x^3, 3x^2, 6x, 6}, B={(0 1 1 0), (1 0 0 1), (0 1 -1 0), (-1 0 0 -1)}[/tex] and [tex]B={(0 1 1 0), (1 2 2 2), (2 3 3 3), (3 4 4 4)}[/tex], respectively.
a)The T-cyclic subspace generated by z = e1 = (1,0,0,0) is spanned by the vectors e1, [tex]Te1=(1,b,-c,a+d), T^2e1=(b,-c,a+c,2a+d)[/tex] and [tex]T^3e1=(-c,a+c,2a+d,3a+2d)[/tex]. So the ordered basis for the T-cyclic subspace generated by e1 is [tex]B={e1, Te1, T^2e1, T^3e1}[/tex].
b)The T-cyclic subspace generated by [tex]z=x^3[/tex] is spanned by the vectors [tex]x^3, Tx^3=3x^2, T^2x^3=6x, T^3x^3=6[/tex]. So the ordered basis for the T-cyclic subspace generated by x^3 is [tex]B={x^3, 3x^2, 6x, 6}[/tex].
c)The T-cyclic subspace generated by z=(0 1 1 0) is spanned by the vectors (0 1 1 0), [tex]T(0 1 1 0)=(1 0 0 1), T^2(0 1 1 0)=(0 1 -1 0), T^3(0 1 1 0)=(-1 0 0 -1)[/tex]. So the ordered basis for the T-cyclic subspace generated by (0 1 1 0) is [tex]B={(0 1 1 0), (1 0 0 1), (0 1 -1 0), (-1 0 0 -1)}[/tex].
d)The T-cyclic subspace generated by z=(0 1 1 0) is spanned by the vectors (0 1 1 0). So the ordered basis for the T-cyclic subspace generated by (0 1 1 0) is [tex]B={(0 1 1 0), (1 2 2 2), (2 3 3 3), (3 4 4 4)}[/tex].
The ordered bases for the T-cyclic subspaces generated by z in (a), (b), (c), and (d) are [tex]B={e1, Te1, T^2e1, T^3e1}, B={x^3, 3x^2, 6x, 6}, B={(0 1 1 0), (1 0 0 1), (0 1 -1 0), (-1 0 0 -1)}[/tex], and [tex]B={(0 1 1 0), (1 2 2 2), (2 3 3 3), (3 4 4 4)}[/tex], respectively.
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Y=x+13
xy = 30
What is x?
which statement is true about angle ABC
Answer:
It has letters
Step-by-step explanation:
Let f(x) = x^4-3x^2 + 2 and g(x) = 2x^4 - 6x^2 + 2x -1. Let a be a constant. What is the largest smallest degree of f(x) + a * g(x)
The largest and smallest degree of f(x) + a * g(x) if a be a constant is 4 and 1 respectively.
According to the question f(x) = x^4-3x^2 + 2 and g(x) = 2x^4 - 6x^2 + 2x -1
f(x) + a * g(x) = x^4-3x^2 + 2 + a( 2x^4 - 6x^2 + 2x -1)
= x^4(1 + 2a)x^4 +(-3-6a)x^2 +2 + 2ax -a
The term with the largest exponent is (1 +2a)x^4, which has degree 4. This term will be non-zero for a ≠ -1/2.
The largest possible degree of f + ag is 4
When a = -1/2, the first two terms disappear and the sum becomes
f + ag = -x +1/2
The smallest possible degree of f + ag is 1.
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from your sketch, what is the equation of the solution to the differential equation that passes through (-1,0)? (verify that your solution is correct
The equation of the solution passing through (-1,0) is y = x + eˣ.
A slope field is a graphical representation of the solutions to a differential equation at different points in the xy-plane.
In this problem, we are given the equation y = -x + y and asked to sketch the solutions that pass through three different points: (0,0), (-3,1), and (-1,0). To do this, we first plot each of these points on the slope field and draw a short line segment with the same slope as the slope at that point. By repeating this process for several points, we can obtain a rough sketch of the solution curve passing through each point.
Once we have sketched the solution curves, we can try to find the equation of the solution passing through (-1,0). To do this, we need to integrate the differential equation y = -x + y with respect to x, which involves finding the antiderivative of -x + y. In this case, we can use the method of separation of variables to write the differential equation as:
dy/dx = y - x
Dividing both sides by y - x, we get:
dy / (y - x) = dx
Integrating both sides, we obtain:
ln|y - x| = x + C
where C is the constant of integration. Exponentiating both sides and simplifying, we get:
y - x = Ceˣ
where C is the constant of integration. To find the value of C, we can use the initial condition that the solution passes through (-1,0), which means that:
0 - (-1) = Ce⁻¹
Simplifying, we get:
C = e
Substituting this value of C into the equation for the solution, we get:
y - x = eˣ
which is the equation of the solution passing through (-1,0). We can verify that this solution is correct by checking that it satisfies the original differential equation:
dy/dx = y - x
Substituting y = x + eˣ, we get:
d/dx(x + eˣ) = (x + eˣ) - x
Simplifying, we get:
eˣ = eˣ
which is true.
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Complete Question:
The slope field for the equation y = -x + y is shown below EN On a print out of this slope field, sketch the solutions that pass through the points (1) (0,0); (ii) (-3,1); and (iii) (-1,0). From your sketch, what is the equation of the solution to the differential equation that passes through (-1,0)? (Verify that your solution is correct by substituting it into the differential equation.)
Evaluate x ÷ 4 x 5y if x = 16 and y = 2
f(x) =3x - 5 por f(-3)=
Answer:
Step-by-step explanation:To evaluate F(x) at a specific value, we simply replace x with that value in the expression for F(x). In this case, we want to find F(-3), so we substitute -3 for x in the expression for F(x):
F(-3) = 3(-3) - 5
Simplifying the right-hand side:
F(-3) = -9 - 5
F(-3) = -14
Therefore, F(-3) = -14.
Help if you know how to do it
First we multiply 9 and 15, which is 135cm. 100cm = 1m so the plant will grow 1.35m, so the plant is now 9.35m
1, 2, 3, 4, 5? (b) If one of the children is randomly chosen, what is the probability that child comes from a family having i children, i = 1, 2, 3, 4, 5?
The probability of having i children, i = 1,2,3,4,5 is 0.2, 0.4, 0.25, 0.1, 0.05 respectively. The probability that a randomly chosen child comes from a family with i children are 0.0741, 0,2963, 0.2773, 0.1481, 0.0926.
The probability that a randomly chosen family has i children is given by the ratio of the number of families with i children to the total number of families. Therefore:
P(1 child) = 4/20 = 0.2
P(2 children) = 8/20 = 0.4
P(3 children) = 5/20 = 0.25
P(4 children) = 2/20 = 0.1
P(5 children) = 1/20 = 0.05
(b) To calculate the probability that a randomly chosen child comes from a family with i children, we need to take into account the different numbers of children in each family. There are a total of 4+8x2+5x3+2x4+1x5=54 children in the community organization. Therefore, the probabilities are:
P(child from 1-child family) = 4/54 ≈ 0.0741
P(child from 2-child family) = 2x8/54 ≈ 0.2963
P(child from 3-child family) = 3x5/54 ≈ 0.2778
P(child from 4-child family) = 4x2/54 ≈ 0.1481
P(child from 5-child family) = 5/54 ≈ 0.0926
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____The given question is incomplete, the complete question is given below:
A small community organization consists of 20 families, of which 4 have one child, 8 have two children, 5 have three children,2 have four children, and 1 has five children.
(a) If one of these families is chosen at random, what is the probability it has i children, i = 1,2,3,4,5?
(b) If one of the children is randomly chosen, what is the probability this child comes from a family having i children, i =1,2,3,4,5?
Mariene and her parents are baking a large batch of cookies for a fundraiser. There are 150 cookies and 62% of cookie and 62% of the cookies are chocolate chips.How many chocolate chip cookies did they make?
93 chocolate chip cookies
A recent survey found that 80% of IRSC students plan to go on a vacation after graduation. Suppose 5 IRSC
students are randomly selected and let z be the number of students that plan to go on a vacation after
graduation, out of the sample of 5. Use the binomial probability formula or the binomial probability table
to construct the probability distribution of x. Ao, use the binomial probability formula or the binomial
probability table to construct the cumulative probability distribution of .
The binomial distribution is solved as
a) The probability that no more than 2 students out of the random 5 plan to go out on vacation is P ( X ≤ 2 ) = 0.0579
b) The probability that more than 2 students out of the random 5 plan to go out on vacation is P ( X > 2 ) = 0.9421
What is a Binomial Distribution?The binomial distribution is a type of probability distribution that predicts the likelihood of obtaining one of two outcomes given a set of inputs. It summarizes the number of tries where each trial has the equal chance of producing the same result.
The formula for Binomial Distribution is given by
P ( x ) = [ n! / ( n - x )! x! ] pˣqⁿ⁻ˣ
where
n = number of trials
x = number of successes
p = probability of getting a success in one trial
q = probability of getting a failure in one trial
q = 1 - p
Given data ,
Let the probability be represented as P
Now , the total number of trials = 5
The number of students going for vacation be represented as n
Now , the probability of success p = 0.8
So , the value of q = 0.2
a)
The probability that no more than 2 students out of the random 5 plan to go out on vacation is P ( X ≤ 2 ) = P ( x ) = [ n! / ( n - x )! x! ] pˣqⁿ⁻ˣ
Substituting the values , we get
The probability that no more than 2 students out of the random 5 plan to go out on vacation is P ( X ≤ 2 ) = 0.0579
The probability that no more than 2 students out of the random 5 plan to go out on vacation is P ( X ≤ 2 ) = 5.79 %
b)
The probability that more than 2 students out of the random 5 plan to go out on vacation is P ( X > 2 ) = P ( x ) = [ n! / ( n - x )! x! ] pˣqⁿ⁻ˣ
Substituting the values , we get
The probability that more than 2 students out of the random 5 plan to go out on vacation is P ( X > 2 ) = 0.9421
The probability that more than 2 students out of the random 5 plan to go out on vacation is P ( X > 2 ) = 94.21 %
Hence , the binomial distribution is solved
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15
A house cleaning company charges $25 to come to a
customer's home. Then the company charges $50 per
hour for the time the employee spends cleaning.
Graph a line that best represents the relationship
between x, the number of hours the employee works,
and y, the amount the company charges in dollars.
Answer:
The amount the company charges in dollars can be represented as a linear function of the number of hours the employee works. We can use the slope-intercept form of a linear equation to graph this relationship:
y = mx + b
where y is the amount charged in dollars, x is the number of hours worked, m is the hourly rate charged by the company, and b is the initial charge for coming to the customer's home.
In this case, we have:
m = $50/hour (hourly rate)
b = $25 (initial charge)
Substituting these values into the equation, we get:
y = 50x + 25
This is the equation of a line with a slope of 50 and a y-intercept of 25. To graph this line, we can plot the y-intercept at (0, 25) and then use the slope to find other points on the line. For example, if the employee works for 1 hour, the company will charge:
y = 50(1) + 25 = $75
So we can plot the point (1, 75) on the graph. Similarly, if the employee works for 2 hours, the company will charge:
y = 50(2) + 25 = $125
So we can plot the point (2, 125) on the graph.
By connecting these points with a straight line, we get the graph of the linear function that represents the relationship between the number of hours worked and the amount charged by the company:
Step-by-step explanation:
define a rational number
What was the difference between the highest guess and the lowest guess?
Write your answer as a fraction, mixed number, or whole number.
The difference between the highest guess and the lowest guess, in the whole number, is 120.
What is subtraction?Mathematical operations include subtraction. It is employed in order to exclude phrases or objects from the expression.
Given:
A table that shows the relationship between the guessed amount and the number of weeks.
Week Amount
1 120
2 140
3 160
4 240
Here, the highest guess is 240.
And the lowest guess is 120.
The difference between the highest guess and the lowest guess,
= 240 - 120
= 120
120 is a whole number.
Therefore, 120 is the required number.
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The complete question:
A table that shows the relationship between the guessed amount and the number of weeks.
Week Amount
1 120
2 140
3 160
4 240
What was the difference between the highest guess and the lowest guess? Write your answer as a fraction, mixed number, or whole number
The velocity function, in feet per second, is given for a particle moving along a straight line.
v(t) = t3 − 11t2 + 34t − 24, 1 ≤ t ≤ 7
(a) Find the displacement.
(b) Find the total distance that the particle travels over the given interval.
If you can please explain.
Please report this so a moderator can delete this answer. I was not finished with my answer and accidentally posted it. I will not have enough time to add it before the editing timer is up.
I need help!!!!!!!!!!!!!!!!!!!
Answer:
Its not A!!!!!!!!!!!!!!!!!!!!!!!!
Step-by-step explanation:
Its not!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
problem 1.7 each of the four vertical links has an 8x36 mm uniform rectangular cross section and eash of the four pins has a 16mm diameter. determine the maximum calue of the average normal stress in the links connecting (a) points b and d, (b) points c and e.
The average normal stress in the links connecting:
(a) points B and D is:
|σ_max| = 13.7 MPa
(b) points C and E is:
|σ_max| = 13.0 MPa
The value of the average normal stressTo determine the maximum value of the average normal stress in the links connecting points B and D, we need to calculate the bending moment and the axial force in the link. Assuming the links are in pure bending, we can use the bending stress formula to calculate the maximum normal stress:
σ_max = Mc / I
where M is the bending moment, c is the distance from the neutral axis to the outer fiber, and I is the moment of inertia of the cross-sectional area.
The bending moment in the link BD can be calculated as the sum of the moments due to the applied loads and the reactions at the pins. The axial force can be calculated as the sum of the forces in the link due to the applied loads.
Assuming a sign convention where clockwise moments are positive and upward forces are positive, we have:M = 4kN * 80mm - 8kN * 120mm = -640 Nm
F = 4kN - 8kN = -4kN
The distance c for a rectangular cross section is half the height, so c = 4 mm. The moment of inertia can be calculated as:I = bh³ / 12
where b is the width and h is the height of the cross section. Therefore:I = (8mm) * (36mm)³ / 12 = 186624 mm⁴
Substituting these values into the bending stress formula, we get:σ_max = (-640 Nm) * (4mm) / 186624 mm⁴ = -13.7 MPa
Since the stress is negative, the maximum tensile stress occurs on the upper part of the link (above the neutral axis). Therefore, the maximum value of the average normal stress in the link connecting points B and D is:|σ_max| = 13.7 MPa
For the link connecting points C and E, the calculation is similar. The bending moment can be calculated as:M = 4kN * 40mm + 8kN * 80mm = 800 Nm
The axial force is:F = 4kN + 8kN = 12kN
The distance c is still 4 mm, but the moment of inertia is different due to the orientation of the cross section. The moment of inertia for a rectangular cross section rotated 90 degrees is:I = bh³ / 12 = (36mm) * (8mm)³ / 12 = 24576 mm⁴
Substituting these values into the bending stress formula, we get:σ_max = (800 Nm) * (4mm) / 24576 mm⁴ = 13.0 MPa
Since the stress is positive, the maximum compressive stress occurs on the lower part of the link (below the neutral axis). Therefore, the maximum value of the average normal stress in the link connecting points C and E is:|σ_max| = 13.0 MPa
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the school band has 80 students and 35% play woodwind instruments. fill in the missing information and determine how many students play a woodwind instrument in the band.
By using the unitary method, 28 students in the school band play woodwind instruments.
Unitary method, which involves finding the value of a single unit and then using that value to find the value of multiple units. In this case, the single unit represents the percentage of students who play woodwind instruments.
Here we need to find the value of a single unit
To find the value of a single unit, we need to divide the given percentage by 100. So, 35% can be written as 0.35.
Therefore, the value of a single unit is 0.35.
Now use the unitary method to find the number of students who play woodwind instruments
Now, we can use the value of a single unit to find the number of students who play woodwind instruments. To do this, we multiply the value of a single unit by the total number of students in the band.
So, the number of students who play woodwind instruments is:
0.35 x 80 = 28
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Let T: n rightarrow m be a linear transformation, with A its standard matrix. Complete the following statement to make it true: "T maps n onto m if and only if A has pivot columns." Find some theorems that explain why the statement is true. T maps n into m if and only if A has Let S : p rightarrow n and T : n rightarrow m be linear transformations. Show that the mapping x T(S(x)) is a Unear transformation (from to m). (Hint: Compute T(S(cu + dv)) for u, v in p and scalars c and d. Justify each step of the computation, and explain why this computation gives the desired conclusion.! [M]
So x → T(S(x)) satisfies homogeneity.
x → T(S(x)) is a linear transformation from P to M.
The completed statement is: "T maps n onto m if and only if A has pivot columns in every row."
One theorem that explains why this is true is the Rank-Nullity Theorem, which states that the rank of a matrix plus the nullity of the matrix (the dimension of the nullspace) equals the number of columns. If A has pivot columns in every row, then the rank of A is equal to the number of rows, which means that the nullity is 0, and therefore T is onto. Conversely, if T is onto, then the range of T has dimension equal to the number of rows, which means that the rank of A is equal to the number of rows, so A has pivot columns in every row.
To show that the mapping x → T(S(x)) is a linear transformation, we need to show that it satisfies the two properties of linearity: additivity and homogeneity.
Additivity: Let x and y be vectors in P. Then we have:
T(S(x + y)) = T(S(x) + S(y)) (by definition of + in P)
= T(S(x)) + T(S(y)) (since T is linear)
= (x → T(S(x))) + (y → T(S(y))) (by definition of the mapping)
= (x + y) → (T(S(x)) + T(S(y))) (by definition of + in M)
So x → T(S(x)) satisfies additivity.
Homogeneity: Let x be a vector in P and let c be a scalar. Then we have:
T(S(cx)) = T(cS(x)) (by definition of scalar multiplication in P)
= cT(S(x)) (since T is linear)
= c(x → T(S(x))) (by definition of the mapping)
So x → T(S(x)) satisfies homogeneity.
x → T(S(x)) is a linear transformation from P to M.
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Solve the following System of Equations using any method you prefer (x+y=2 -3x-y=5)
The solution of the system of equations given is (-7/2, 11/2)
What is a system of equations?A set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.
Given that, a system of equations using any method x+y = 2 and -3x-y = 5,
The equations are:
x+y = 2...(i)
-3x-y = 5...(ii)
Since, the signs of y variable in the both equations are opposite, if we add both the equations the y variable will get eliminated,
Therefore, the most suitable method to solve is elimination method,
Adding equations i and ii,
(x+y = 2) + (-3x-y = 5)
-2x = 7
x = -7/2
Put x = -7/2 in eq(i)
-7/2 + y = 2
-7 + 2y = 4
2y = 11
y = 11/2
Hence, the solution of the system of equations given is (-7/2, 11/2)
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20 Points
A slice is made perpendicular to the base of a right rectangular prism, as shown.
What is the area of the resulting two-dimensional cross-section?
Drag and drop the answer into the box.
The area of the resulting two-dimensional cross-section is 480 inch².
What is Area?The area of a plane figure is the area that its perimeter encloses. The quantity of unit squares that cover a closed figure's surface is its area.
Given:
The Resulting Cross section will Have the Size
= 20 inch by 14 inch
So, Area of two dimensional Cross section
= 20 x 14
= 240 inch²
As prism is Sliced so this cross section will on the face of two prism.
Then, the Total cross section area
= 2 x 240
= 480 inch²
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You are shopping and find the same shirt at two different
stores. Store "A" is selling the shirt for $25 and Store
"B" is selling the shirt for 10% off the original price of
$28. Which is the better buy?
a. The shirt at Store "A".
b. The shirt at Store "B".
Answer:
A. The shirt at Store "A".
Step-by-step explanation:
How to find 10% of 28.
First, we need to convert 10% into a decimal.
To do that, we just divide the number by 100.
[tex]\frac{10}{100}[/tex] [tex]= 0.1[/tex]
Now, we take the original number (28) and multiply it by the decimal
[tex]28 x 0.1 = 2.8[/tex]
Finally, we subtract.
[tex]28.00 - 2.80 = 25.20[/tex]
[tex]25.20[/tex] > [tex]25.00[/tex]
Therefore, Store "A" Has the cheapest shirt
100 days make how many months?
Answer:
There are 3.28542 months in 100 days.
Step-by-step explanation:
For every 100 days, there are approximately 3.28542 months. To solve for any given number of days, divide the time value by 30.417.
For example, to solve for 200 days:
200 ÷ 30.417 = 6.57534 monthTherefore, 100 days make approximately 3.28542 months.
Answer:
3.28542
Step-by-step explanation:
100 days make how many months?
Value in months = value in days × 0.0328542
Value in months = 100 × 0.0328542 = 3.28542 (months)
Consider the solid obtained by rotating the region bounded by the given curves about the y-axis.x=3√3y,x=0,y=5
Find the volume Vof this solid. Sketch the region, the solid, and a typical disk or washer.
The region bounded by[tex]x=3√3y,x=0,y=5[/tex] is rotated about the y-axis to form a solid. The volume of this solid is V. The region, the solid and a typical disk or washer can be sketched using the given curves.
To calculate the volume V of the solid obtained by rotating the region bounded by [tex]x=3√3y,x=0,y=5[/tex]about the y-axis, we will use the equation [tex]V=π∫a b[(R)^2-(r)^2]dy,[/tex] where R is the outer radius, r is the inner radius, a is the lower limit of the integral and b is the upper limit of the integral. Substituting the given values, we get
[tex]V=π∫0 5[(3√3y)^2-(0)^2]dy[/tex]
This simplifies to [tex]V=π∫0 5[9y^2]dy.[/tex] Integrating this expression, we get [tex]V=π(5^3-0^3)[/tex]. Substituting the limits, we get [tex]V=π(5^3-0^3)[/tex]. This simplifies to V=125π. Hence, the volume of the solid is 125π.
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express the given statement in terms of c(x), d(x), f(x), quantifiers, and logical connectives. for each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.
The given statement can be expressed in terms of c(x), d(x), f(x), quantifiers, and logical connectives as follows:
a) ∃x(C(x) ∧ D(x) ∧ F(x))
b) ∀x(C(x) ∨ D(x) ∨ F(x))
c) ∃x(C(x) ∧ F(x) ∧ ¬D(x))
d) ¬∃x(C(x) ∧ D(x) ∧ F(x))
e) ∀y∃x(P(x, y))
All of the pupils in your class should be a set. The domain is the set X. Denote
[tex]C(x)-'x has a cat'\\D(x)- 'x has a dog'\\F(x)- 'x has a ferret'[/tex]
a) A kid in your class owns a cat, a dog, and a ferret, so take that into consideration. This implies that ∃x ∈ X so that C(x), D(x), and F(x) are all true assertions. Using quantifiers, logical connectives, and C(x), D(x), and F(x) we can express that as follows.
∃x(C(x) ∧ D(x) ∧ F(x))
b) Take into account the claim that "Every student in your class has a cat, a dog, or a ferret." This proves ∀x ∈ X at least one of the claims made by C(x), D(x), and F(x) to be true. Using quantifiers, logical connectives, and C(x), D(x), and F(x) we can express that as follows.
∀x(C(x) ∨ D(x) ∨ F(x))
c) Take into account the claim that "Some student in your class has a cat and a ferret, but not a dog." Accordingly, ∃x ∈ X, statements C(x), F(x), and the negation of statement D(x) are true. Using quantifiers, logical connectives, and C(x), D(x), and F(x) we can express that as follows.
∃x(C(x) ∧ F(x) ∧ ¬D(x))
d) Take into account the claim that "No student in your class has a cat, a dog, and a ferret." This indicates ∀x ∈ X that neither C(x), D(x), nor F(x) is true. As a denial of the claim in section a), we may state that in terms of C(x), D(x), and F(x) by using quantifiers and logical connectives as follows.
¬∃x(C(x) ∧ D(x) ∧ F(x))
a) Take into account the adage, "There is a student in your class who has this animal as a pet. The three animals are cats, dogs, and ferrets."
This indicates that an element X from the domain exists for each of the propositions C, F, and D such that each statement is true.
Using quantifiers, logical connectives, and C(x), D(x), and F(x) we can express that as follows.
∀y∃x(P(x, y))
The complete question is:-
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret." Express each of these statements in terms of C(x), D(x), F(x), quantifiers, and logical connectives. Let the domain consist of all students in your class. a) A student in your class has a cat, a dog, and a ferret. b) All students in your class have a cat, a dog, or a ferret. c) Some student in your class has a cat and a ferret, but not a dog. d) No student in your class has a cat, a dog, and a ferret. e) For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.
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Mallory's Border Collie had 18 puppies in 3 litters. Determine the rate for a ratio of the two different quantities.
18 over 3 puppies per litter
3 over 18 puppies per litter
18 over 21 puppies per litter
1 over 6 puppies per litter
Answer:
3 over 18 puppies per litter
Step-by-step explanation:
usually, you want to go with the smaller number first, it's like a fraction.
write y=d^2-8d-10 in vertex form
The vertex form of the equation is,
⇒ y = (d - 4)² - 26
What is Quadratic equation?An algebraic equation with the second degree of the variable is called an Quadratic equation.
Given that;
The equation is,
⇒ y = d² - 8d - 10
Now, We can change in vertex form as;
⇒ y = d² - 8d - 10
⇒ y = d² - 8d + 16 - 16 - 10
⇒ y = (d - 4)² - 16 - 10
⇒ y = (d - 4)² - 26
Thus, The vertex form of the equation is,
⇒ y = (d - 4)² - 26
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Roll a number cube. If the number cube comes up odd, you win the same number of points as the number
on the cube. If the number comes up even, you lose 4 points.
What is the expected number of points per roll?
O-0.25
O-0.5
O 0
O 0.25
O 0.5
The expected number of points per roll is -1.5.
What is probability?It is the chance of an event to occur from a total number of outcomes.
The formula for probability is given as:
Probability = Number of required events / Total number of outcomes.
We have,
Outcomes when rolling a number cube.
= 1, 2, 3, 4, 5, or 6.
If the number is odd, you win the same number of points as the number on the cube.
So,
If the number is 1, you win 1 point.
If the number is 3, you win 3 points.
If the number is 5, you win 5 points.
Now,
If the number is even, you lose 4 points.
If the number is 2, you lose 4 points.
If the number is 4, you lose 4 points.
If the number is 6, you lose 4 points.
The probability of rolling an odd number.
= 3/6
= 1/2
Similarly,
The probability of rolling an even number.
= 3/6
= 1/2
Now,
The expected number of points per roll.
= Probability of rolling an odd number x (1 + 3 + 5) + Probability of rolling an even number x (-4 - 4 - 4)
= (1/2) x (1 + 3 + 5) + (1/2) x (-12)
= (1/2) x 9 - 6
= 9/2 - 6
= (9 - 12)/2
= -3/2
= -1.5
Thus,
The expected number of points per roll is -1.5.
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