A screw Jack whose pitch is 2mm is used to raise a bus of mass 900kg through height of 20cm. The length of the Tommy of the Tommy of the jack is 40cm. Calculate the velocity ratio of the machine

Answers

Answer 1

R= 40cm —> R= 0.4 m

P= 2mm —> P= 0.002 m

[tex]V.R = \frac{2πR}{p} = \frac{2 \times 3.14 \times 0.4}{0.002} = 1256[/tex]

I think this is the answer

I hope I helped you

Good luck ^_^


Related Questions

Velocity is vector quantity because??​

Answers

Velocity is vector quantity because it has both magnitude and direction.

Explanation:

velocity is a vector quantity because the person always returns to the original position,the motion would never result in a change in a position.

A delivery boy on a bicycle drags a wagon full of newspapers by pedaling at 0.90 m/s for 45 minutes using a force of 40 N. How much work has the boy done?

Answers

Answer:

Explanation:

The equation for work is

W = FΔx

We are looking for work, so that means we have to be able to fill in the Force and the displacement. We have Force, but we don't have displacement. But the thing we need to do first is change the 45 minutes to seconds because the velocity is in m/s, not m/min.

45 minutes is 2700 seconds.

That means that  the displacement is

Δx = (.90)(2700) so

Δx = 2430 m

Now we plug that in to find work, along with the given Force:

W = 40(2430) so

W = 97200 J (and that is not the correct number of sig fig's but I have a feeling you're not too into that in class, because if you were, the 40 N would be expressed as 40.0 or 4.0 × 10¹)

In a science museum, a 130 kg brass pendulum bob swings at the end of a 14.4 m -long wire. The pendulum is started at exactly 8:00 a.m. every morning by pulling it 1.7 m to the side and releasing it. Because of its compact shape and smooth surface, the pendulum's damping constant is only 0.010kg/s. You may want to review (Pages 405 - 407) . Part A At exactly 12:00 noon, how many oscillations will the pendulum have completed

Answers

Answer:

The time in which the pendulum does a complete revolution is called the period of the pendulum.

Remember that the period of a pendulum is written as:

T = 2*pi*√(L/g)

where:

L = length of the pendulum

pi = 3.14

g = 9.8 m/s^2

Here we know that  L = 14.4m

Then the period of the pendulum will be:

T = 2*3.14*√(14.4m/9.8m/s^2) = 7.61s

So one complete oscillation takes 7.61 seconds.

We know that the pendulum starts moving at 8:00 am

We want to know 12:00 noon, which is four hours after the pendulum starts moving.

So, we want to know how many complete oscillations happen in a timelapse of 4 hours.

Each oscillation takes 7.61 seconds.

The total number of oscillations will be the quotient between the total time (4 hours) and the period.

First we need to write both of these in the same units, we know that 1 hour = 3600 seconds

then:

4 hours = 4*(3600 seconds) = 14,400 s

The total number of oscillations in that time frame is:

N = 14,400s/7.61s = 1,892.25

Rounding to the next whole number, we have:

N = 1,892

The pendulum does 1,892 oscillations between 8:00 am and 12:00 noon.

In 'coin on card' experiment a smooth card is used. ​

Answers

Answer:

In coin card experiment smooth card is used so that the card can slide easily from glass

In three words I can sum up everything I’ve learned about life: it goes on. ― Robert Frost

In a softball game a batter hits at the velocity of 28 and an angle shown 45 below . What is the maximum range of the ball

Answers

Answer:

80 m

Explanation:

Given :

Initial Velocity, U = 28 m/s

θ = 45°

The maximum range occurs at angle, θ = 45°

The maximum range, R is given by ;

R = U²sin2θ / g

g = acceleration due to gravity = 9.8 m/s²

Plugging in the values :

R = [28² * sin2(45)] / 9.8

R = [28² * sin90] / 9.8

R = 784 / 9.8

R = 80 m

Is it possible to get a body accelerated even if it is moving with uniform speed? justify.​

Answers

Answer:Yes, A body can have constant speed but still accelerate as in case of uniform circular motion. In uniform circular motion speed remains constant and direction of velocity changes with every point in the direction of tangent drawn from that point.

Explaination:

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A plane is flying a circular path at a speed of 55.0 m/ s, with a radius of 18.3 m. The centripetal force needed to maintain this motion is 3000 N. What is the plane's mass?

Answers

The plane has a centripetal acceleration a of

a = v ²/r

where v is the plane's tangential speed and r is the radius of the circle. By Newton's second law,

F = mv ²/r

Solve for the mass m :

m = Fr/v ² = (3000 N) (18.3 m) / (55.0 m/s)² ≈ 18.1 kg

what is gama rays an it's uses​

Answers

Answer:

GAMMA RAYS:

A photon emitted spontaneously by a radioactive substance also : a photon of higher energy than that of an X-ray.

USES OF GAMMA RAYS:

Gamma rays are used in medicine (radiotherapy), industry (sterilization and disinfection), and the nuclear industry. Shielding against gamma rays is essential because they can cause diseases to skin or blood, eye disorders, and cancers.

How much energy has 4×10^10m^3 of water collected in a reservoir at a hight of 100 m from the power house ?What kind of energy is that?

Answers

Answer:

PE = 3.92x10^16J

potential energy

Explanation:

PE = m*g*h

mass of water = 1000kg/m³

(4*10^10m³)*1000kg = 4*10^13kg

PE = (4*10^13kg)*(9.81m/s²)*(100m)

PE = 3.92x10^16J

scientists are seen very busy in designing the solar power equipments, why?

Answers

Answer:

it is because solar energy is the perpetual source of energy and by using it non renewable sources of energy can be conserved for the future

Which statement best describes how pigments affect what colors humans
see?

Answers

Answer:

the component of light reflected by that object

Explanation:

Which of these would have the greatest pressure?
Group of answer choices

A large balloon with few gas molecules at a high temperature

A small balloon with many gas molecules at a low temperature

A small balloon with many gas molecules at a high temperature

A large balloon with few gas molecules at a low temperature

Answers

The third one because it is a small one and it had high and high temp so it has the most modecules.

Hope this helps

No me sale este problema :c, plano inclinado

Answers

Answer:

i didn't understand,

Explanation:

sorry

Mary drives at a speed of 35 mph (mile/hour). How long does it take for her to drive 98 miles?
__ hours

Answers

Answer:

2.8 hours

Explanation:

98 ÷ 35 = 2.8

6. traction a. friction between a tire and the road.b. pushes a moving object out of a curve and into a straight linec. the ability of a car to hold a straight lined. a road higher in the center than on either edge 7. kinetic energy a.a force that keeps objects moving in a straightb. reduces the effects of inertiac. energy of motiond. a road higher in the center than on either edge 8. force of impact a. a force that keeps objects moving in a straight line.b. a road higher in the center than on either edgec. the force with which a moving vehicle hits another objectd. perception distance, reaction distance, and braking distance

Answers

Answer:

6. a. friction between a tire and the road

7. c. energy of motion

8. c. the force with which a moving vehicle hits another object

Explanation:

6. As a car moves along the road, the tires push back against the ground. As tires push back against the ground, the road exerts and opposing force to the motion of the tires. This opposing force is the friction between the tires and the road. This opposing force between the tires and the rad is called traction.

So, the answer is a

7. As an object moves, it has energy. This energy due to its motion is called kinetic energy.

So, the answer is c

8. When a moving vehicle hits another object, it exerts a force on the object. The process of the vehicle hitting the other object is called impact and the force exerted on the object is called the force of impact.

So, the answer is c.

What kind of waves are present during an earthquake?​

Answers

Body Waves - Primary (P) & Secondary (S) Waves.
Surface Waves - Rayleigh & Love Waves.

Answer:

There are four main types of earthquake waves:

P-waves S-waves (which are body waves), Rayleigh waves Love waves (which are surface waves).

HOPE IT HELPS!!

a vehicle starts from rest and has an acceleration of 2 metre per second square how long does it take to gain the speed of 20 metre per second ​

Answers

Answer:

x,y

jjoffos

fif

hofdhDJiyfuID pork chop it off the bus to school today I am not a mixture of my favorite thing in life that is the best of the day before

When the motion of one or both of the particles is at an angle to the line of impact, the impact is said to be ________

Answers

Answer: Oblique impact

Explanation:

When the motion of one or both of the particles is at an angle to the line of impact, the impact is said to be oblique impact.

On the other hand, when the directions of motion of the two colliding particles are moving along a line of impact, then it's refered to as central impact.

Hey, I'm a Turk. What language do you speak? I'm very curious. ​

Answers

Answer:

What languages do i sqeak?

English, Korean and Filipino

Uhh why are you asking it?

English and a little German

Are mass and weight the same thing?
Yes
No

Answers

Answer:

Explanation:

Definitely NOT! Mass is unchanging, wherever you go. On the moon you will have the same mass as you will on the earth. Mass is just a measure of the matter that makes up a body. Weight, however, is dependent upon the pull of gravity which is different on earth than it is on the the moon, for example.

Mass doesn't change with proximity whereas weight can.

Answer: No

Explanation: The terms'mass' and 'weight' are frequently used interchangeably, yet they have distinct meanings. Your mass remains constant regardless of where you are in the universe; nevertheless, your weight varies. The mass of anything is a measure of how much power is required to change its course.

(Serious Please) patulong​

Answers

Answer:

a. Potential energy is highest at Part A

The kinetic energy is highest at Part C and Part D

b. The potential energy is lowest at Part C and Part D

c. The roller coater has equal amount of potential and kinetic energy at Part B, Part D and part F

2) Yes, the mechanical energy is the same from point A to F according to the first law of thermodynamics

Explanation:

The total mechanical energy is constant where the roller coaster moves by only the initial velocity, and the the force of gravity

Total mechanical energy, M.E. = Kinetic energy, K.E. + Potential energy, P.E.

M.E. = K.E. + P.E. = Constant

Therefore, we have;

a. Potential energy is the energy stored in a body, due to its position or elevation, state or arrangement

The higher the elevation, the higher the potential energy, therefore, the highest amount of potential energy is gained when the roller coaster is at the  highest point in the motion = Part A

From M.E. = K.E. + P.E. = Constant, the highest kinetic energy is given at the point the roller coaster has the lowest potential energy, which corresponds with the lowest points = Part C and Part D

b. Potential energy, which is the energy of body due to its position or state is lowest at the lowest points = Part C and Part D

c. The value of potential energy, P.E. due to elevation, can be found as follows

P.E. = Mas, m × Gravity, g × Height, h

Therefore, the potential energy will be half the maximum value where the height, h = (Maximum height)/2 and given that M.E. = K.E. + P.E., the kinetic energy, will increase by the same amount, and we have;

K.E. = P.E. at the half the maximum height of the track = Part B, Part D and part F

2) The mechanical energy is the input energy, which according to the first law of thermodynamics cannot be created and destroyed an it is therefore, constant and it is the same from point A to F

how much of the electro magnetic spectrum is visible to us​

Answers

Answer:

The entire rainbow of radiation observable to the human eye only makes up a tiny portion of the electromagnetic spectrum – about 0.0035 percent. This range of wavelengths is known as visible light.

Explanation:

Please Mark me brainliest

A system consists of multiple objects connected by ropes. How many equations need to be written to solve this problem?

A) two for each object
B) one or two for each object
C) one for each object
D) two for the system

Answers

Answer:

the correct answer is B

Explanation:

To solve the system they must have the same amount of unknowns as equations,

a) If the system does not have friction, we must write the x-axis equation for each body, therefore we need to write N equations

b) if the system has friction, two equations are needed for each particle

therefore the correct answer is B

A spherical cell has a radius of 2.3 μm , and the phospholipid bilayer that constitutes its membrane has a thickness of 3.75 nm . At its normal resting state, the outer membrane is at a voltage of 0V, and the inner membrane is at a voltage of -70mV. The dielectric constant of the cell membrane is roughly 9.0. What is the capacitance of the cell? (Note: the surface area of a sphere is 4πr2)

Answers

Answer:

Explanation:

The cell is acting like a shell .

Capacity of a shell is given by the following expression.

C= 4πk ε₀ x ab / (b-a )

k is dielectric constant , b and a are outer and inner radius ε₀ is a constant .

Here a = 2.3 x 10⁻⁶ m

b = 2.3 x 10⁻⁶ + .00375 x 10⁻⁶

= 2.30375 x 10⁻⁶ m

b -a = 3.75 x 10⁻⁹ m .

k = 9

4π ε₀ = 1 / 9 x 10⁹ = .111 x 10⁻⁹

C=  .111 x 10⁻⁹ x 9 x 2.3 x 10⁻⁶ x 2.30375 x 10⁻⁶ / 3.75 x 10⁻⁹

= 1.41 x 10⁻¹² F

= 1.41 pF .

If a planet has the same mass as the earth, but has twice the radius, how does the surface gravity, g, compare to g on the surface of the earth

Answers

Answer:

The surface gravity g of the planet is 1/4 of the surface gravity on earth.

Explanation:

Surface gravity is given by the following formula:

[tex]g=G\frac{m}{r^{2}}[/tex]

So the gravity of both the earth and the planet is written in terms of their own radius, so we get:

[tex]g_{E}=G\frac{m}{r_{E}^{2}}[/tex]

[tex]g_{P}=G\frac{m}{r_{P}^{2}}[/tex]

The problem tells us the radius of the planet is twice that of the radius on earth, so:

[tex]r_{P}=2r_{E}[/tex]

If we substituted that into the gravity of the planet equation we would end up with the following formula:

[tex]g_{P}=G\frac{m}{(2r_{E})^{2}}[/tex]

Which yields:

[tex]g_{P}=G\frac{m}{4r_{E}^{2}}[/tex]

So we can now compare the two gravities:

[tex]\frac{g_{P}}{g_{E}}=\frac{G\frac{m}{4r_{E}^{2}}}{G\frac{m}{r_{E}^{2}}}[/tex]

When simplifying the ratio we end up with:

[tex]\frac{g_{P}}{g_{E}}=\frac{1}{4}[/tex]

So the gravity acceleration on the surface of the planet is 1/4 of that on the surface of Earth.

An object 2cm high is placed 3cm in front of a concave lens of focal length 2cm, find the magnification?​

Answers

Answer:

0.4

Explanation:

A concave lens is a diverging lens, so it will always have a negative focal length. Image distance is always negative for a concave lens because it forms virtual images.

From the lens formula;

1/f = 1/u+ 1/v

- 1/2 = 1/3 - 1/v

1/v = 1/3 + 1/2

v= 6/5

v= 1.2 cm

Magnification = image distance/object distance

Magnification = 1.2cm/3cm

Magnification = 0.4

An inquisitive physics student and mountian climber climbs a 43.6 m cliff that overhangs a calm pool of water. He throws two stones vertically downward, 1.35 s apart and observes that they cause a single splash. The first stone has an initial velocity of 1.8 m/s. How long after release of the first stone do the two stones hit the water

Answers

Answer:

Explanation:

What we are basically looking for here is how long it takes the first stone to hit the water. We have everything we need to figure that out. We will use the equation

Δx = . Filling in, we will solve for t, the time is takes the first stone to hit the water (which is the same for both since they both hit the water at the same time):

which is a quadratic that we will have to factor. Get it into standard form, setting it equal to 0:

and factor to get that

t = 3.2 s and t = -2.8 s

Since time can't ever be negative, it takes 3.2 s for the stones to hit the water.

The Displacement is 5m. We found that using the
Pythagorean Theorem.
Vector Quantities require both a Displacement and a
Direction.
What direction is this Vector?
South
Northeast
West

Answers

Answer:

A vector can be written as:

(R, θ)

Where R is the magnitude, in this case, we know that the magnitude of the displacement is 5m

Then:

R = 5m

and θ defines the direction, it's an angle measured from the positive x-axis.

(In the image, θ would be the angle located at the point A)

Now, if you look at the image, you can see a triangle rectangle.

Where the adjacent cathetus has a length of 4,

the opposite cathetus has a length of 3 units

the hypotenuse has a length of 5 units.

So we can use any trigonometric rule to find the value of θ, like:

sin(θ) = (opposite cathetus)/hypotenuse

Then:

sin(θ) = 3m/5m

Now we can use the inverse sin function, Asin(x), in both sides

Asin( sin(θ)) = θ = Asin( 3/5) = 36.87°

then the vector is:

(5m, 36.87°)

Now, if we define the positive y-axis as the North, and the positive x-axis as the East.

This vector would point at 36.87° North of East.

(or almost Northeast)

A gas at a pressure p is compressed to half it original volume and twice its original temperature. The new pressure is

Answers

Answer:

4p

Explanation:

If you halve the volume the pressure will double as they are inversely proportional. If you double the temperature the particles have double the kinetic energy so the pressure will double again.

So:

p×2×2 = 4p

Answer:

P V = n R T

P2 V2 / (P1 V1) = T2 / T1

P2 = (T2 / T1) (V1 / V2)  P1   =   2 * 2 = 4

Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 11.7 revolutions/s. Find the linear speed v of the car, assuming that the tires are not slipping against the ground. v

Answers

Answer:

The linear speed of the car, v, is 24.26 m/s

Explanation:

Given;

radius of the car's tire, r = 0.330 m

angular speed of the car, ω = 11.7 revolutions/s

The angular speed of the car in radian per second:

[tex]\omega = 11.7 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 73.523 \ rad/s[/tex]

The linear speed of the car, v, is calculated as;

v = ωr

v = 73.523 rad/s  x  0.33 m

v = 24.26 m/s

Therefore, the linear speed of the car, v, is 24.26 m/s

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