A school and sold 30 tickets if each ticket is labeled from 1 to 30. One winning ticket will be drawn. What is the probability that the number of the winning ticket will be a multiple of 4 or the number 19

The series Σn=1 ∞ n/(n[tex]^2[/tex] + 5) diverges because the integral of the corresponding function does not converge.

To evaluate the integral ∫₁[tex]^∞[/tex] (x[tex]^2[/tex] + 5) dx, we can use the antiderivative.

Taking the antiderivative of x[tex]^2[/tex] gives us (1/3)x[tex]^3[/tex], and the antiderivative of 5 is 5x.

Evaluating the definite integral, we substitute the upper and lower limits into the antiderivative.

Substituting ∞, we get ((1/3)(∞)[tex]^3[/tex] + 5(∞)), which is ∞.

Substituting 1, we get ((1/3)(1)[tex]^3[/tex] + 5(1)), which is (1/3 + 5) = 16/3.

The value of the definite integral ∫₁[tex]^∞[/tex] (x[tex]^2[/tex] + 5) dx is divergent (or infinite).

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The arithmetic sum of the given sequence 4, 9, ..., 219, 224 is 5130.

First, we need to find the common difference (d) between the consecutive terms in this arithmetic sequence. We can do this by subtracting the first term from the second term: 9 - 4 = 5.

Now that we know the common difference, we can determine the number of terms (n) in the sequence using the formula for the last term (L) in an arithmetic sequence: L = a + (n - 1)d, where a is the first term. In this case, the last term (L) is 224, and we have:

224 = 4 + (n - 1)5

Solving for n, we get:

220 = (n - 1)5

n - 1 = 44

n = 45

Now that we have the number of terms, we can compute the sum (S) of the arithmetic sequence using the formula: S = n/2(a + L). Plugging in the values, we get:

S = 45/2(4 + 224)

S = 45/2(228)

S = 45 × 114

S = 5130

So, the arithmetic sum of the given sequence is 5130.

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Answer: To estimate the number of people who want the toll road in their city, we can use the percentage range provided and calculate the interval estimate. Here's how you can do it:

Therefore, the interval estimate for the number of people who want the toll road in their city is (123,442, 225,608).

The equation y = 5x/2 represents a proportional relationship with a constant of 5/2.

A proportional relationship is a type of relationship between two quantities in which they maintain a constant ratio to each other.

The equation that defines the proportional relationship is given as follows:

y = kx.

In which k is the constant of proportionality, representing the increase in the output variable y when the constant variable x is increased by one.

The equation for this problem is given as follows:

y = 5x/2.

Which is a proportional relationship, as it has an intercept of zero, along with a constant of k = 5/2.

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(a) Zeetopia has an absolute advantage in producing coconuts since it can produce more coconuts than Freshland by using the same amount of resources.

(b) Zeetopia has a comparative advantage in producing coconuts because it has a lower opportunity cost of producing coconuts than Freshland.

The opportunity cost of producing one tonne of coconuts in Zeetopia is 3/5 tonne of mangoes, whereas, the opportunity cost of producing one tonne of coconuts in Freshland is 2 tonne of mangoes.

Therefore, Zeetopia has a comparative advantage in producing coconuts.

(c) According to the principle of comparative advantage, both islands should specialize in producing the good for which they have a lower opportunity cost. Thus, Zeetopia should specialize in producing coconuts and Freshland should specialize in producing mangoes. Both islands will gain from specialization and trade if they exchange one ton of coconuts for one ton of mangoes.

For Freshland, the opportunity cost of producing one tonne of mangoes is 2/3 tonnes of coconuts, whereas, for Zeetopia, the opportunity cost of producing one tonne of mangoes is 5/3 tonnes of coconuts.

Therefore, Freshland has a comparative advantage in producing mangoes. By specializing in producing mangoes, Freshland can produce 30 tonnes of mangoes, which can be exchanged for 30 tonnes of Zeetopia's coconuts. This exchange will benefit both countries as they will get a good that they are not efficient in producing.

(d) The production possibilities for Zeetopia and Freshland can be shown on the graph below. The horizontal axis represents the production of coconuts, while the vertical axis represents the production of mangoes. The slope of each production possibility curve (PPC) represents the opportunity cost of producing one good in terms of the other. The numerical values from the table above are plotted on the graph.

(e) The combination of coconuts and mangoes labeled X is unattainable for Freshland but feasible and inefficient for Zeetopia. Therefore, Freshland cannot produce at point X due to its limited resources, while Zeetopia is not using all of its resources efficiently if it produces at point X.

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In mathematics, an integral is a mathematical object that represents the area between a function and the x-axis on a graph, or the accumulation of a quantity over time.

(a) Integrate by parts, letting dv = 5 − x dx.

Using integration by parts, we can write:

∫x(5-x) dx = x ∫(5-x) dx - ∫[d/dx(x) ∫(5-x) dx] dx

= x [5x - (1/2)x^2] - ∫(0 - (5-x)dx)

= x [5x - (1/2)x^2] - (5x - (1/2)x^2) + C

= - (1/2)x^2 + 10x + C, where C is the constant of integration.

(b) Integrate by substitution, letting u = 5 − x.

Using u-substitution, we can write:

∫x(5-x) dx = ∫(5-u)u du

= ∫(5u - u^2) du

= (5/2)u^2 - (1/3)u^3 + C

= (5/2)(5-x)^2 - (1/3)(5-x)^3 + C, where C is the constant of integration.

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Answer:

No real roots, two complex roots

Step-by-step explanation:

By calculating the discriminant:

[tex]D=b^2-4ac=5^2-4(5)(21)=25-420=-395 < 0[/tex], then there will be no real zeroes. However, there will be two complex roots.

In an analysis of variance where the total sample size for the experiment is and the number of populations is k, the mean square due to error is SSE/(k-1). The answer is c. SSE/(k-1).

In an analysis of variance (ANOVA), the total sum of squares (SST) is partitioned into two parts: the sum of squares due to treatment (SSTR) and the sum of squares due to error (SSE). The degrees of freedom associated with SSTR is k-1, where k is the number of populations or groups being compared, and the degrees of freedom associated with SSE is nT-k, where nT is the total sample size. The mean square due to error (MSE) is defined as SSE/(nT-k). The MSE is used to estimate the variance of the population from which the samples were drawn. Since the total variation in the data is partitioned into variation due to treatment and variation due to error, the MSE provides a measure of the variation in the data that is not explained by the treatment. Therefore, the MSE is a measure of the variability of the data within each treatment group.

Use induction to prove that if a graph G is connected with no cycles, and G has n vertices, then G has n 1 edges. Hint: use induction on the number of vertices in G. Carefully state your base case and your inductive assumption. Theorem 1 (a) and (d) may be helpful.Let T be a connected graph. Then the following statements are equivalent:

(a) T has no circuits.

(b) Let a be any vertex in T. Then for any other vertex x in T, there is a unique path

P, between a and x.

(c) There is a unique path between any pair of distinct vertices x, y in T.

(d) T is minimally connected, in the sense that the removal of any edge of T will disconnect T.

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The random variable x follows an exponential distribution with a parameter λ = 3. This distribution is commonly used to model the time between events occurring at a constant average rate.

The exponential distribution is characterized by its probability density function (PDF) and cumulative distribution function (CDF).

In the exponential distribution, the parameter λ represents the rate parameter or the average number of events occurring per unit of time. In this case, with λ = 3, we can interpret it as an average of 3 events occurring per unit of time.

The PDF of the exponential distribution with parameter λ is given by f(x) = λe^(-λx), where x is a non-negative value. This function describes the probability of observing a specific value of x.

The CDF of the exponential distribution is given by F(x) = 1 - e^(-λx). It represents the probability that x is less than or equal to a given value.

The exponential distribution is widely used in various fields such as reliability analysis, queueing theory, and survival analysis. It is particularly useful when modeling the time between events with a constant average rate.

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Lisa needs 2 pints of blue paint and 4 pints of white paint.

To paint her bedroom walls, Lisa needs a total of 6 pints of blue paint and white paint.

One-fourth (1/4) of this quantity is blue paint and the rest is white paint. We have to find what amount of blue paint and white paint Lisa need.

The total quantity of paint Lisa needs to paint her bedroom is 6 pints.

Let B be the quantity of blue paint Lisa needs.

Then the quantity of white paint she needs is 6 - B (since one-fourth of the total quantity is blue paint).

Hence, B + (6 - B) = 64B + 6 - B = 24B = 2

Therefore, Lisa needs 2 pints of blue paint and (6 - 2) = 4 pints of white paint. (Here, the total quantity of paint is taken as 24 units in order to avoid fractions).

Lisa needs 2 pints of blue paint and 4 pints of white paint.

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Natalie needs 2 and 2/3 cups of graham cracker crumbs to make 4 pies.

To find out how many cups of graham cracker crumbs Natalie needs for 4 pies, we can multiply the amount needed for a single pie by the number of pies.

The recipe calls for 2/3 cup of graham cracker crumbs for 1 pie.

To calculate the amount for 4 pies, we multiply 2/3 by 4:

Amount of graham cracker crumbs needed = (2/3) * 4

= (2 * 4) / 3

= 8/3

Since 8/3 is an improper fraction, let's convert it to a mixed number:

8/3 = 2 and 2/3

Therefore, Natalie needs 2 and 2/3 cups of graham cracker crumbs to make 4 pies.

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Answer:

[tex]x > 0[/tex]

Step-by-step explanation:

The x-values (domain/input) are greater than 0

In other words, the graph covers the x-axis on all points greater than 0

Answer: the function is defined for all real values of x. Therefore, the domain of the function is the set of all real numbers, which can be denoted as:

Domain = (-∞, ∞) or (-∞, +∞)

In a multiple regression model, the error term ε is assumed to satisfy certain assumptions for accurate statistical analysis and inference. The assumptions made about the error term are crucial for valid statistical analysis and inference.

In multiple regression, the error term ε represents the discrepancy between the observed data and the predicted values from the regression model. The assumptions made about the error term are crucial for valid statistical analysis and inference.

The error term ε is assumed to have a mean of zero, indicating that, on average, the predicted values align with the observed data. This assumption allows the regression model to capture the systematic relationship between the independent variables and the dependent variable.

Additionally, the error term is assumed to be independent and identically distributed (IID). This means that the errors for each observation are unrelated and have the same probability distribution. The independence assumption ensures that the errors do not exhibit any systematic patterns or correlations, allowing for reliable statistical analysis. The identical distribution assumption allows for the use of statistical techniques that rely on certain distributional properties, such as hypothesis testing and confidence intervals.

Furthermore, it is commonly assumed that the error term ε follows a normal distribution. This assumption enables the use of statistical techniques based on the normal distribution, such as estimating parameters and conducting hypothesis tests using t-statistics.

Overall, these assumptions about the error term in a multiple regression model are essential for valid statistical analysis and inference, ensuring accurate interpretation of the model's coefficients and significance tests.

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It is not possible to ascertain the magnitude of angle x without receiving further information.

In order to calculate the magnitude of angle x, we must further data concerning the connection that exists between the points A, B, C, and D. We are unable to draw any judgements regarding the size of angle x because we do not have any additional information.

However, if we have additional information, such as the location of point D in relation to points A, B, and C, then we can use circle theorems to compute the magnitude of angle x. One of the possibilities is that point D lies on the segment of the line AB; in this case, the angle x would be a straight angle, which is equal to 90 degrees. This is because a tangent and a radius always make an angle of 90 degrees with one another at the place where they contact one another. In alternate circumstances in which point D is situated in a different area, the magnitude of angle x will shift proportionately. Therefore, it is not possible to estimate the magnitude of angle x without first determining the precise location of point D or any other information that is pertinent to the problem.

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Heritability is a statistic that quantifies the proportion of observed variance in a group of individuals that can be attributed to genetic variance.

Heritability is a fundamental concept in genetics and behavioral sciences that helps understand the extent to which genetic factors contribute to observed variations in a particular trait within a population. It measures the proportion of phenotypic variation (differences in traits) that can be explained by genetic variation. Heritability estimates range from 0 to 1, where a value of 0 indicates that all observed variation is due to environmental factors, and a value of 1 suggests that all observed variation is due to genetic factors.

To calculate heritability, researchers typically study populations with varying degrees of genetic relatedness, such as twins or family members. By comparing the similarity of traits between individuals with known genetic relatedness, it is possible to estimate the contribution of genetic factors to the observed variance. Environmental factors that contribute to phenotypic variation are considered as part of the non-genetic or "environmental" component.

It is important to note that heritability estimates are population-specific and apply only to the particular group being studied. Additionally, heritability does not provide information about specific genes or the precise mechanisms by which genetic factors influence traits. Nonetheless, heritability serves as a valuable tool in understanding the relative importance of genetic and environmental factors in shaping individual differences within a population.

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There are 62,208,000 5-letter sequences (formed from the 26 letters) with repetition allowed that contain exactly 2 a's and exactly 1 n.

To form a 5-letter sequence with exactly 2 a's and exactly 1 n, we need to select the positions for the 2 a's and the 1 n, and then fill the remaining 2 positions with any of the remaining 24 letters (since repetition is allowed).

The number of ways to select the 2 positions for the a's out of the 5 positions is given by the binomial coefficient C(5,2) = 10. Once the 2 positions for the a's have been selected, there is only 1 position left for the n. Therefore, the number of ways to select the 3 positions for the 2 a's and 1 n is 10.

10 × 26 × 26 × 26 × 24 × 24 = 62,208,000

Therefore, there are 62,208,000 5-letter sequences (formed from the 26 letters) with repetition allowed that contain exactly 2 a's and exactly 1 n.

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We first list all the partitions of integers from 1 to 7, then use these lists to compute the values of the partition function p(n) for n from 1 to 7. Therefore, the values of the partition function for integers from 1 to 7 are 1, 2, 3, 5, 7, 11, and 15, respectively.

A partition of a positive integer n is a way of writing n as a sum of positive integers, where the order of the summands does not matter. For example, the partitions of 4 are 4, 3+1, 2+2, 2+1+1, and 1+1+1+1. To compute the partition function p(n), we count the number of partitions of n.

Here are the partitions of integers from 1 to 7:

1: {1}

2: {2}, {1,1}

3: {3}, {2,1}, {1,1,1}

4: {4}, {3,1}, {2,2}, {2,1,1}, {1,1,1,1}

5: {5}, {4,1}, {3,2}, {3,1,1}, {2,2,1}, {2,1,1,1}, {1,1,1,1,1}

6: {6}, {5,1}, {4,2}, {4,1,1}, {3,3}, {3,2,1}, {3,1,1,1}, {2,2,2}, {2,2,1,1}, {2,1,1,1,1}, {1,1,1,1,1,1}

7: {7}, {6,1}, {5,2}, {5,1,1}, {4,3}, {4,2,1}, {4,1,1,1}, {3,3,1}, {3,2,2}, {3,2,1,1}, {3,1,1,1,1}, {2,2,2,1}, {2,2,1,1,1}, {2,1,1,1,1,1}, {1,1,1,1,1,1,1}

Using this list, we can compute the values of the partition function p(n) for n from 1 to 7:

p(1) = 1

p(2) = 2

p(3) = 3

p(4) = 5

p(5) = 7

p(6) = 11

p(7) = 15

Therefore, the values of the partition function for integers from 1 to 7 are 1, 2, 3, 5, 7, 11, and 15, respectively.

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There is an 88% chance that he will complete his next free throw.

Now, When Steph Curry has an 88% free throw rating, that means on average he makes 88 free throws out of 100 attempts.

Now, let's look at the probability of him making 16 free throws in a row.

Since each free throw is independent of the others, the probability of making 16 in a row is simply 0.88 to the power of 16

since he has an 88% chance of making each one).

That comes out to about, 0.284, or 28.4% chance of making 16 in a row.

Therefore, the probability that he completes his next free throw after making 15 in a row is still 88%,

since each free throw is independent of the others.

So, there is an 88% chance that he will complete his next free throw.

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If W = U ⊕ V, then U ∩ V = {0} which can be proved by proving {0} is an element of U ∩ V and there are no other elements in U ∩ V besides {0} for the vector space.

To show that if W = U ⊕ V, then U ∩ V = {0}, we need to prove two things:

1. {0} is an element of U ∩ V.
2. There are no other elements in U ∩ V besides {0}.

Step 1: Show that {0} is an element of U ∩ V.

Since U and V are subspaces of the vector space W, they both must contain the zero vector (0) as per the definition of a subspace. Therefore, the zero vector is in both U and V, which implies that 0 is an element of U ∩ V.

Step 2: Show that there are no other elements in U ∩ V besides {0}.

Suppose there is a nonzero vector x that belongs to U ∩ V. This means x is in both U and V. Since W = U ⊕ V, any vector in W can be uniquely written as the sum of a vector from U and a vector from V. Thus, x can be written as:

x = u + v

where u is a vector from U and v is a vector from V. However, x is also in both U and V, so we can rewrite the equation as:

x = x + 0

Since the sum of vectors from U and V is unique, we must have u = x and v = 0. But this contradicts our initial assumption that x is a nonzero vector, as x ∈ V and we assumed x ≠ 0. Therefore, there can be no other elements in U ∩ V besides {0}.

In conclusion, if W = U ⊕ V, then U ∩ V = {0}.

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The z-score corresponding to a sample mean of 84 for a sample size of 9 scores, with a population mean of 80 and a population standard deviation of 12, is 1.

To find the z-score corresponding to a sample mean of m = 84 with a population mean (μ) of 80 and a population standard deviation (σ) of 12, the z-score can be calculated using the formula z = (x - μ) / (σ / √n).

In this case, the population mean (μ) is 80 and the population standard deviation (σ) is 12. The sample mean (m) is given as 84, and the sample size (n) is 9.

To calculate the z-score, we use the formula:

z = (x - μ) / (σ / √n)

Substituting the given values, we have:

z = (84 - 80) / (12 / √9)

Simplifying the expression, we get:

z = 4 / (12 / 3)

z = 4 / 4

z = 1

Therefore, the z-score corresponding to a sample mean of 84 for a sample size of 9 scores, with a population mean of 80 and a population standard deviation of 12, is 1. This indicates that the sample mean is one standard deviation above the population mean. The z-score allows us to compare the sample mean to the population distribution and assess how unusual or typical the sample mean is relative to the population.

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The points that represent viable solutions include the following:

B. (5, 3,000).

C. (20, 2200).

E. (10, 1,100).

In order to graphically determine the viable solution for this system of equations on a coordinate plane, we would make use of an online graphing tool to plot the given system of quadratic equations while taking note of the point of intersection;

y = x² + 4x - 1          ......equation 1.

y + 3 = x       ......equation 2.

Based on the graph shown (see attachment), we can logically deduce that the viable solutions for this system of quadratic equations is the point of intersection of each lines on the graph that represents them in quadrant I, which are represented by the following ordered pairs;

(5, 3,000).

(20, 2200).

(10, 1,100).

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Ryan grew 1/2 foot (or 0.5 feet) in a year.

Last year's height: 4 ¾ feet

This year's height: 5 ¼ feet

To find the difference, we subtract the height from last year from the height from this year:

5 ¼ feet - 4 ¾ feet

To perform the subtraction, we need to make sure both heights have the same denominator. The common denominator for 4 and ¾ is 4.

5 ¼ feet - 4 ¾ feet = 5 + 1/4 - 4 - 3/4

Converting the whole numbers to fractions:

5 + 1/4 - 4 - 3/4 = 5 + 1/4 - 4 - 3/4 = 5 - 4 + 1/4 - 3/4

Simplifying the expression:

5 - 4 + 1/4 - 3/4 = 1 + (1 - 3)/4

Performing the subtraction:

1 + (-2)/4 = 1 - 1/2 = 1/2

Therefore, Ryan grew 1/2 foot (or 0.5 feet) in a year.

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Since our test statistic of 4.5 is greater than the critical value of 2.700, we reject the null hypothesis. Therefore, we say there is enough evidence to reject the manufacturer's claim.

A good way to test if a sample with Variance of 4.3 is worth rejecting by manufacturer, we can use a Chi-Square test with (n-1) degrees of freedom. Where n is the sample size.

null hypothesis: the variance of the population is equal to 8.6

alternative hypothesis: the variance of the population is less than 8.6.

The test statistic is given by:

Chi-Square = (n - 1) * sample variance / population variance

From the problem statement, we have

n = 10

sample variance = 4.3

population variance = 8.6

Substituting these values, we get:

chi-square = (10 - 1) * 4.3 / 8.6 = 4.5

The critical value for a chi-square distribution with 9 degrees of freedom at a significance level of 0.01 is 2.700.

Since our test statistic of 4.5 is greater than the critical value of 2.700, we reject the null hypothesis.

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The general solution of the given system is x(t) = c1t(1 1) + c2t(1 -1).

To find the general solution of x′ = (−1 1 −1 −1 ) x, we first need to find the eigenvalues and eigenvectors of the matrix A = (−1 1 −1 −1).

The characteristic polynomial of A is given by det(A - λI) = 0, where I is the 2x2 identity matrix and λ is the eigenvalue:

|−1-λ 1 |

|-1 -λ| = (-1-λ)(-1-λ) - (-1)(1) = λ^2 + 2λ = λ(λ+2) = 0.

So the eigenvalues of A are λ1 = 0 and λ2 = -2.

To find the eigenvectors corresponding to each eigenvalue, we need to solve the equations:

(A - λ1I)x1 = 0 and (A - λ2I)x2 = 0.

For λ1 = 0, we have:

(A - λ1I)x1 =

| -1 1 |

| -1 -1 | x1 = 0.

Solving this system of equations, we get x1 = t(1 1), where t is any scalar.

For λ2 = -2, we have:

(A - λ2I)x2 =

| 1 1 |

| -1 -3 | x2 = 0.

Solving this system of equations, we get x2 = t(1 -1), where t is any scalar.

Thus, the general solution of x′ = (−1 1 −1 −1 ) x can be written as a linear combination of the eigenvectors:

x(t) = c1t(1 1) + c2t(1 -1),

where c1 and c2 are constants that depend on the initial conditions.

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The critical chi-square value for a one-tailed test (right tail) when the level of significance is 0.1 and the sample size is 15 is approximately 21.064.

Find the critical chi-square value for a one-tailed test (right tail) when the level of significance is 0.1 and the sample size is 15, follow these steps:
Determine the degrees of freedom: The degrees of freedom (df) can be calculated as df = sample size - 1. In this case, df = 15 - 1 = 14.
Identify the level of significance: The level of significance is given as 0.1.
Find the critical chi-square value: You can use a chi-square table or an online calculator to find the critical value. With a level of significance of 0.1 and 14 degrees of freedom, the critical chi-square value for a one-tailed test (right tail) is approximately 21.064.
The critical chi-square value for a one-tailed test (right tail) when the level of significance is 0.1 and the sample size is 15 is approximately 21.064.

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Security plan is a document that describes how an organization will address its security needs. Here are three factors that should be considered when developing a security plan:

Risk assessment: A thorough risk assessment should be conducted to identify potential security threats and vulnerabilities to the organization. This can include conducting a physical security assessment, reviewing current policies and procedures, and analyzing the organization's technology infrastructure.

Compliance requirements: Organizations may have legal and regulatory requirements that must be met in regards to security. It is important to identify these requirements and ensure that the security plan addresses them appropriately.

Resource allocation: Developing a comprehensive security plan can be resource-intensive. Organizations should consider the financial and human resources that will be required to implement and maintain the plan over time. This can include budgeting for security technology, hiring security personnel, and providing ongoing training for employees.

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As the population (t) grows, the probability of no birthday collision reduces. This is due to the fact that as the population grows, the likelihood of two or more people having the same birthday rises.

The probability of no birthday collision among t people can be computed using the formula:

P(no collision) = 1 x (364/365) x (363/365) x ... x [(365-t+1)/365]

For t = 10, we have:

P(no collision) = 1 x (364/365) x (363/365) x ... x (356/365)
P(no collision) = 0.883
Therefore, the probability of no birthday collision among 10 people is 0.883 or approximately 88.3%.

For t = 25, we have:

P(no collision) = 1 x (364/365) x (363/365) x ... x (341/365)
P(no collision) = 0.568
Therefore, the probability of no birthday collision among 25 people is 0.568 or approximately 56.8%.

For t = 40, we have:

P(no collision) = 1 x (364/365) x (363/365) x ... x (326/365)
P(no collision) = 0.108
Therefore, the probability of no birthday collision among 40 people is 0.108 or approximately 10.8%.

In general, the probability of no birthday collision decreases as the number of people (t) increases. This is because the likelihood of two or more people sharing the same birthday increases as the number of people increases.

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The simplified ratio is:    

1 : 2 : 6 or 1 : 2/1 : 6/1.

The question requires us to determine the ratio of the earnings of the three children in the Skosana family. Given that the eldest, middle and youngest children earn R270, R180 and R90 respectively, we can express these amounts as a ratio as follows:

R270 : R180 : R90

Let's simplify this ratio by dividing each amount by the highest common factor of 90.

R270 ÷ 90 = 3

R180 ÷ 90 = 2

R90 ÷ 90 = 1

Therefore, the ratio of the earnings of the three children in the Skosana family is:3 : 2 : 1.

An explanation of how we came up with the answer is as shown below:

We can express the eldest child's earning as a ratio of the total earnings as follows:

R270 : (R270 + R180 + R90)

Simplifying this ratio, we get:

3R : (3R + 2R + R) = 3R : 6R

= 1 : 2

Similarly, we can express the middle child's earning as a ratio of the total earnings as follows:

R180 : (R270 + R180 + R90)

Simplifying this ratio, we get:

2R : (3R + 2R + R) = 2R : 6R

= 1 : 3

Finally, we can express the youngest child's earning as a ratio of the total earnings as follows:

R90 : (R270 + R180 + R90)

Simplifying this ratio, we get:

R : (3R + 2R + R) = R : 6R

= 1 : 6

Therefore, the ratio of the earnings of the three children in the Skosana family is:

1 : 2 : 6.

However, we can further simplify this ratio by dividing each amount by the highest common factor of

6.1 ÷ 1 = 12 ÷ 2

= 36 ÷ 6

= 1

Therefore, the simplified ratio is:

1 : 2 : 6 or 1 : 2/1 : 6/1.

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The correct equation is 0.75w + 0.5w + 2 = 17.

To determine the error in the given equation and find the correct number of laps needed before the sprint to the finish, we can follow these steps:

Step 1: Examine the given equation, w(1.5 + 1)^2 = 17, and identify the error.

The equation provided is incorrect because it does not account for the width and height of the rectangle, as well as the 2-mile sprint to the finish line.

Step 2: Formulate the correct equation based on the given information.

The correct equation should be 0.75w + 0.5w + 2 = 17, where w represents the number of laps. This equation includes the distance covered by riding laps around the block (0.75w + 0.5w) and the additional 2-mile sprint to the finish line.

Step 3: Solve the equation to find the correct number of laps.

By simplifying the equation, we get 1.25w + 2 = 17. Subtracting 2 from both sides gives us 1.25w = 15. Dividing both sides by 1.25 yields w = 12.

Therefore, the correct equation is 0.75w + 0.5w + 2 = 17, and the cyclists will need to ride 12 laps before the sprint to the finish. The given equation and the incorrect number of laps mentioned in the other options do not accurately represent the race distance and the laps required.

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Answer:

missing : refrence

Step-by-step explanation: