A rope is wrapped three and a half times around a cylinder. Determine the range of force T exerted on the free end of the rope for maintaining equilibrium that is required to just support a 5 kN weight. The coefficient of friction between the rope and the cylinder is 0.2

Answers

Answer 1

The range of force exerted at the end of the rope is 285.7 N to 1,000 N.

Net horizontal force of the cylinder

The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.

∑F = 0

F - μFn = 0

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force increases as the number of turns of the rope increases.

minimum force = total force/number of turns of rope

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

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Related Questions

What does refractive index mean?

Answers

Refractive index, also called index of refraction, measure of the bending of a ray of light when passing from one medium into another. ... Refractive index is also equal to the velocity of light c of a given wavelength in empty space divided by its velocity v in a substance, or n = c/v. (ya think i can get brainliest)
Refractive Index (Index of Refraction) is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density. The refractive index variable is most commonly symbolized by the letter n or n' in descriptive text and mathematical equations.

the refractive index is the blank of the speed of light in a medium to the speed of light in a vacuum

Answers

Answer:

ratio

Explanation:

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Bumper car A (296 kg) moving +3.74 m/s makes an
elastic collision with bumper car B (222 kg) moving
+1.85 m/s. What is the velocity of car A after the
collision?

Answers

For a bumper car A (296 kg) moving +3.74 m/s, and a bumper car B (222 kg) moving +1.85 m/s, the velocity of car A after the collision is mathematically given as

V1=4.977m/s

What is the velocity of car A after the collision?

Generally, the equation for the Velocity of car A  is mathematically given as

[tex]V1=\frac{m1-m2v1}{m1+m2}v1 +\frac{2m_2}{m1+m2}v2[/tex]

Therefore

[tex]V1=\frac{296-222}{296+222}*23.74+\frac{2*222}{296+222}*1.85[/tex]

V1=4.977m/s

In conclusion, The velocity of car A after the collision

V1=4.977m/s

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Answer:3.74

Explanation:

it was given same goes for bumper car b

An astronaut weighs 104 newtons on the moon, where the strength of gravity is 1.6N/kg. What is her mass?

Answers

her mass is 65 kilograms
the answer is her mass is 64 Kg

which types of star cluster is shown

Answers

Open star clusters tend to orbit within the disk. Globular star clusters contain hundreds of thousands of stars, and some – like Omega Centauri, shown above – contain millions of stars. Open star clusters tend to contain only hundreds of stars.


The driver of a car steps on the brakes, and the velocity drops from 43 m/s due east to 3.38 m/s due east in a time of 70seconds. What is the acceleration?

Answers

Answer:

Explanation:

initial velocity, u = 43 m/s

final velocity, v = 3.38 m/s

time, t = 70 sec

acceleration, a = v - u / t

3.38 - 43 / 70

= -39.62/ 70

= -0.56 m/s^2

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A Home Depot worker pushes a lumber cart loaded with a mass of 115 kilograms of lumber. If he accelerates the cart with an acceleration 5.6m/s^2 what is the amount of force the worker applied.

Answers

Answer:

use math.way

Explanation:

i solved it.

difference between text-talk novel and flash fiction?​

Answers

See the flash fictions are small nov.els with para.graphs where as ch*.t story is a storyline that just look like some c

c.h.*.t.s.

Both "text-talk novels" and "flash fiction" are forms of written literature, but they have distinct characteristics and purposes.

Text-Talk Novel:

A text-talk novel, also known as a "chat novel" or "text-message novel," is a narrative written in the style of text messages or chat conversations. These novels are typically composed of short, informal messages exchanged between characters, presented in a way that resembles conversations on messaging apps. Text-talk novels often use emojis, abbreviations, and informal language to create a sense of immediacy and relatability. They are designed to be read on mobile devices and appeal to readers who are used to communication through texting and social media platforms. Text-talk novels often cater to a younger audience and can cover various genres, from romance to mystery.

Flash Fiction:

Flash fiction, also known as "microfiction," "short-short stories," or "sudden fiction," refers to extremely short works of fiction characterized by their brevity. Flash fiction stories are typically no longer than 1,000 words, and often much shorter. Despite their limited length, flash fiction stories aim to convey a complete narrative, evoke emotions, and leave a lasting impact on the reader. Due to their concise nature, flash fiction stories often focus on a single idea, moment, or theme, and they require skillful crafting to create a meaningful story within a tight word count. Flash fiction can cover a wide range of genres and styles, and its brevity challenges writers to distill their storytelling abilities to essentials.

Hence, a "text-talk novel" is a novel written in the style of text messages or chat conversations, aiming to engage readers familiar with mobile communication. On the other hand, "flash fiction" refers to very short stories that convey complete narratives or ideas within a limited word count, challenging writers to create impactful stories in a condensed format.

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In order to compare the thermal conductivities of two different insulators, a scientist pours hot water into two
beakers.
The different insulators are wrapped around the beakers.
The scientist records the initial temperatures of the hot water.
a) State two factors that should be kept constant in order to make the experiment fair.

Answers

Yes powers of sentience state can explore everything

A spacecraft passes you at 0.255 the speed of light. By what factor does the relativistic energy increase if its speed doubled and if you subtract out the constant rest energy

Answers

The factor increase in the relativistic energy  is 0.129.

Relativistic kinetic energy of the spacecraft

The relativistic kinetic energy of the spacecraft is determined as follows;

[tex]K = (\frac{1}{\sqrt{1- \frac{v^2}{c^2} } } )mc^2[/tex]

where;

v is the speed of the spacecraftc is the speed of light

At 0.255 speed of light, the relativistic kinetic energy is calculated as follows;

[tex]K = (\frac{1}{\sqrt{1- \frac{(0.255c)^2}{c^2} } } )mc^2\\\\K = (\frac{1}{\sqrt{1- \frac{0.065c^2}{c^2} } } )mc^2\\\\K = 1.034mc^2[/tex]

When the speed doubles, v = 2(0.255c)

[tex]K = (\frac{1}{\sqrt{1- \frac{(2 \times 0.255c)^2}{c^2} } } )mc^2\\\\K = (\frac{1}{\sqrt{1- \frac{0.261c^2}{c^2} } } )mc^2\\\\K = 1.163mc^2[/tex]

Increase in energy

ΔK = 1.163mc² - 1.034mc²

ΔK = 0.129mc²

Thus, the factor increase in the relativistic energy  is 0.129.

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A car driving down a street has a kinetic energy of 32,000 J. If the car has a mass of 1,600kg, at what velocity is the car moving?

Answers

Explanation:

The mechanical energy can be expressed as kinetic and potential energy, given by the equation;

ME=KE+PE

but since the car isn't elevated off the ground nor is it subjected to the restoring force of a spring, we can then say PE=0

ME=KE

The equation of KE=0.5mv²

ME=0.5mv²

32 000=0.5(1600)

[tex]v {}^{2} = \frac{32 \: 000}{1600 \times 0.5} [/tex]

[tex]v {}^{2} = \frac{32 \: 000}{800} [/tex]

[tex] {v}^{2} = 40[/tex]

[tex]v = \sqrt{40} = 6.324[/tex]

v=6.324 m/s :)

Select the correct answer.
What is proper technique for lifting?
A.
Bend your back
B.
Bend at your knees and lift with your legs.
C.
Focus your power from your back.
D.
None of the above

Answers

Answer:

B

Explanation:

Answer:

i think it's either B or C

Explanation:

median of 18 24 17 21 24 16 29 18​

Answers

Answer:

19.5

Explanation:

16,17,18,18,21,24,24,29

(fourth (18) and fifth(21)) ÷2=

(18+21)÷2=

39÷2=

19.5 is median

The space station Babylon 5 has a diameter of 1 miles, and rotated around its long axis to produce artificial gravity for its inhabitants. It completes 1 revolutions/min. Calculate the effective gravitational strength at the outer rim of the station, in units of g. (use g = 9.81 m/s^2)

Answers

This question involves the concept of artificial gravity.

The effective gravitational strength at outer rims is "0.9 g".

Artificial Gravity

The effective gravitational strength at the outer rims can be given by the following formula:

[tex]v=\frac{1}{2\pi}\sqrt{\frac{a_c}{r}}\\\\a_c=4\pi^2v^2r[/tex]

where,

[tex]a_c[/tex] = effective gravitational strength = ?v = rotational speed = 1 rev/min = 0.0167 rev/sr = radius = diameter/2 = 1 mile/2 = 0.5 miles = 804.672 m

Therefore,

[tex]a_c = 4\pi^2(0.0167\ rev/s)^2(804.672\ m)\\a_c =8.82\ m/s^2\\\\In\ terms\ of\ g:\\\\a_c=(8.82\ m/s^2)(\frac{g}{9.81\ m/s^2})\\\\a_c = 0.9g[/tex]

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Why is the international system of measurement helpful?
a.
They are not in English.
c.
All scientists can use them.
b.
No scientists can use them.
d.
They are easy to remember.



Please select the best answer from the choices provided


A
B
C
D

Answers

International system of measurements in helpful because all scientists can use them

International System of measurement abbreviated SI is the modern most widely accepted system of unit of measurement

An unbalanced force of 20 N is applied to a 10 kg mass. What is the acceleration of the mass?

Answers

Answer:

2 m/s2

Explanation:

Newton's 2nd law:

F=ma

20 N= (10 kg)a

a= 2 m/s2

what is the acceleration of a 10 kg mass pushed by a 5 newton force?

Answers

Answer:

0.5 m/s²

Explanation:

F=ma
F is force
m is mass
a is acceleration

F=ma
5 =  10 x a
a = 5/10
a = 0.5 m/s²

If a system absorbs 155.0 kJ of heat from its surroundings and the system does 45.0 kJ of work on its surroundings, what is the change in the internal energy of the system, in kJ

Answers

The change in the internal energy of the system is 110 kJ.

What is internal energy?

Internal energy is defined as the energy associated with the random, disorder motions of molecules.

calculate the change in internal energy, we apply the formula below.

Formula:

ΔU = Q-W.................... Equation 1

Where:

ΔU = Change in internal energyQ = Heat absorbed from the surroundingsW = work done by the system

From the question,

Given:

Q = 115 kJW = 45. 0 kJ

Substitute these values into equation 1

ΔU = 155-45ΔU = 110 kJ

Hence, The change in the internal energy of the system is 110 kJ.

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Answer:

110.0kJ

Explanation:

The following solution may contain one or more values that are different from the problem provided to you, however, the steps to solve the problem are the same.

.The internal energy (E) of a system can change as heat (q) flows into or out of the system, or work (w) is done on or by the system. The following equation represents the relationship.

ΔE=q+w

In this question, heat is absorbed by the system, so it has a positive sign. Work is done by the system, so it has a negative sign.

ΔE=(155.0 kJ)+(−45.0 kJ)=110.0 kJ

If 10 waves come in every 8 seconds with a wavelength of 2 meters, what is the frequency?

Answers

Answer:

Explanation:

frequency = 10/8 = 1.125 Hz

A force of 10 n acts on a mass of 5 kg producing an acceleration of 1.5 m/s2 what is the magnitude of the force of friction acting on the mass

Answers

The friction is 2.5N. The Net force is 10 N - 2.5 N .= 7.5 N.
acceleration = 7.5 / 5 = 1.5 m/s^2

Given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton

Given the data in the question;

Force acting on the object; [tex]F = 10N[/tex]Mass of the object; [tex]m = 5kg[/tex]Acceleration of the object; [tex]a = 1.5 m/s^2[/tex]Force of friction acting on the mass; [tex]F_k = \ ?[/tex]

To determine the magnitude of the force of friction acting on the mass,

From Newton's laws of motion

[tex]F = m\ *\ a[/tex]

Where F is the force applied, m is the mass of the object and a is the acceleration of the object.

Now, we know that Kinetic Friction is always opposite of the direction of motion.

So, in the question, the force applied overcomes the friction to produce an acceleration of [tex]1.5 m/s^2[/tex]

Hence

[tex]F = F_k + ma[/tex]

Where [tex]F_k[/tex] is the kinetic friction

Now, we substitute our given values into the equation

[tex]10N = F_k +\ ( 5kg\ *\ 1.5m/s^2)\\\\10N = F_k +\ 7.5kg.m/s^2[/tex]

We know that, A newton is defined as [tex]1 kg.m/s^2[/tex]

Hence;

[tex]10N = F_k\ *\ 7.5N\\\\F_k = 10N \ -\ 7.5N\\\\F_k = 2.5N[/tex]

Therefore, given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton.

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How is the gravitational force related to the distance between two objects?
S
It is directly proportional to the square of the distance.
It is inversely proportional to the square of the distance.
it is directly proportional to the distance.
it is inversely proportional to the distance.

Answers

gravitational force is inversely proportional to the square of the separation distance between the two interacting objects

Gravitational force is inversly proportional to the square of the distance. Option B is correct.

What is gravitational force?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

[tex]\rm F=G\frac{mM}{R^2}[/tex]

Gravitational force is inversly proportional to the square of the distance.

Hence option B is correct.

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An archerfish, peering from just below the water surface, sees a grasshopper standing on a tree branch that's just above the water. The archerfish spits a drop of water at the grasshopper and knocks it into the water. The grasshopper's initial position is 0.45 m above the water surface and 0.25 m horizontally away from the fish's mouth. The launch angle of the drop is 630 with respect to the water surface.
A. Find an expression for how fast the drop is moving when it leaves the fish's mouth. (Your expression should only contain symbols of physical quantities. No numbers are needed here. )
B. Find the numerical value for how fast the drop is moving when it leaves the fish's mouth. (Plug the values of physical quantities into your expression from part A (do not forget units!) Evaluate your answer that you found in part B by using it to find the value of a physical quantity given in the problem statement. (This is called evaluating for consistency.) For instance, suppose you knew the initial speed of the water (i.e., your answer in part B), the launch angle ( 63º) and the grasshopper's initial horizontal position (0.25 m). Using this information, find the initial vertical position of the grasshopper. Is this value consistent with the value given in the problem statement?

Answers

Answer:

Explanation:

Let the required velocity be V   at angle θ with the horizontal . Let time taken in the whole process be t

horizontal component = v cosθ

It will cover .25 m at this velocity

vertical component = v sinθ

It will cover .45 m with this initial velocity and with deceleration g .

v cosθ t = .25

.45 =v sinθ t - 1/2 g t²

putting the values of t from above

.45 = .25 tanθ - g .25² / 2 v² cos²θ

B ) putting the values of θ

.45 = .25 tan63 - 9.8 x .25² / 2 v² cos² 63

.45 = .49 - 1.53 / v²

1.53 / v² = .04

v² = 38.25

v = 6.18 m /s

time taken to cover distance of .25 m

t = .25 / 6.18 cos63 = .089 s

during this period , vertical displacement

= 6.18 sin 63 x .089  - 1/2 x 9.8 x .089²

= .4895 - .04  = .45 m which is consistence with given height .

Which of the following exerts the most pressure while resting on a floor?
a. a 25 N cube with 1.5 m sides
b. a 15 N cylinder resting vertically with a base radius of 1.0 m
c. a 25 N cube with 2.0 m sides
d. a 25 N cylinder resting vertically with a base radius of 1.0 m

Answers

The pressure of the cube that exerts the most pressure while resting on a floor is mathematically given as

P=16.6pascal, Option D is correct

Which of the following exerts the most pressure while resting on a floor?

Generally, the equation for the Pressure   is mathematically given as

P=force/Area

Therefore, In considering the one with the most pressure we look at the one with the most force/Area

In conclusion, the one with the most Force/Area is a 25 N cube with 1.5 m sides

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An object is pushed at an angle of 42˚ by a force of 135 N through a distance of 829 cm. Find the work done by the object.

Answers

The work done by the object is 831.69 J.

What is work?

Work can be defined as the product of mass and distance.

To calculate the work done by the object, we use the formula below

Formula:

W = Fdcos∅............ Equation 1

Where:

W = Work done by the objectF = Force on the object∅ = Angle.

From the question,

Given:

F = 135 Nd = 829 cm = 8.29 m∅ = 42°

Substitute these values into equation 1

W = 135×8.29×cos42°W = 831.69 J.

Hence, The work done by the object is 831.69 J.

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A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C. Its efficiency is

A. 13%
B. 39 %
C.61%
D. 88 %
E. 90 %​

Answers

The answer to this is A.13%

Hope this helped

The efficiency of a carnot engine with absorb temperature and exhaust temperature is 13%. The correct option is A.

What is Efficiency?

The efficiency is defined as the work done by the engine divided by the heat supplied.

So, efficiency η = 1 - T₁/T₂

Where T₁ is the lower temperature and T₂ is the higher temperature.

A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C

Substitute the value into the expression , we get

η = 1 -(77+273)  / (127+273) x 100 %

η = 12.5 %

or

η = 13 %

Thus, the efficiency of the carnot engine is 13%.

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An experiment is set up to determine the speed of charged particles as they move through a region that is traversed by a constant electric and a constant magnetic field. The particles are moving toward the right of the page when they encounter the region. The electric field points toward the top of the page, and the magnetic field points out of the page. Required:
Predict how the positively and negatively charged particles of various speeds will behave in this experiment

Answers

The deflection will be toward the backside for bad cost and closer to the pinnacle of the spread page for the high-quality charge.

What are charged particles?

Charged particles are simply defined as particles with an electric charge on them. This may sometimes result in being an ion, as a molecule with excess or a reduced amount of electrons relative to protons.

Generally, the Magnetic area points internal the airplane so through fleming left hand rule is

F = q ( V x B). Ie

hence

qVB = qE

V= E/B then no deflection.

V > E/B then magnetic pressure is dominant over electric powered force.

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If you apply a force of 200N to an object with a mass of 50kg, what will the acceleration be?​

Answers

Answer:

Acceleration = 4 m/s

Explanation:

Acceleration = force divided by mass

So;

a = 200 ÷ 50 = 4

An astronaut is floating in space. There is no rope connecting him to the ship. They have some tools and a
fire extinguisher.
Which action could propel the astronaut back to the ship? (Select two answers)
He could spray the fire extinguisher in the opposite direction of the ship
He could throw a tool in the opposite direction of the ship
He could throw a tool toward the ship
He could point the extinguisher towards the ship and spray it.

Answers

He could spray the fire extinguisher in the opposite direction of the ship. This is definitely the answer because its all about momentum

Answer:

It's A it is correct trust me and no I didn't copy the other person I just read the answers.

Hope this helps:)

Explanation:

Reuptake means that:

Answers

Answer:

it means absorption by a presynaptic nerve ending of a neurotransmitter that it has secreted.

Explanation: I hoped that helped please leave a 5 rate and thanks. Have a great day .

Stars appears to move from east to west because
A. all stars move from east to west
B. the earth rotates from west to east
C. the earth rotates from east to west
D. the background of the stars moves from west to east​

Answers

Answer:

The earth rotates from West to east

Explanation:

Every planet in our solar system rotates around their axis in West to east direction.Only Venus is the only planet which rotates from east to west
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