Answer:
0.62 m down.
Explanation:
Use the formula d= vi*t +1/2 at^2
So the initial speed or vi is -13 m/s and time is 2.7 s and a or acceleration is 9.8 m/s^2 down ( because it's the gravity). So you plugged all the values and you will get 0.62 m. We put the down because the acceleration is saying down. Because displacement is vector quantity you have to show the direction of it.
An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds. What is the truck’s acceleration and how much momentum does it have after it has reached this final velocity?
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
a = (18.0 m/s − 0 m/s) / (6.00 s)
a = 3.00 m/s²
Momentum is mass time velocity.
p = mv
p = (8000 kg) (18.0 m/s)
p = 144,000 kg m/s
When an 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds then the truck’s acceleration would be 3 m/s² and the momentum after it has reached this final velocity would be 144000 kgm/s.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
Mathematically the formula of the momentum is
P = mv
where P is the momentum of the particle
m is the mass of the particle
v is the velocity by which the particle is moving
As given in the problem An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds
By using the first equation is given as follows
v = u + at
18 =0 + a×6
a = 3 m/s²
As given in the problem the final velocity of An 8000.0 kg truck is 18 m/s
the momentum is given by the formula
P = mv
P= 8000×18
P = 144000 kgm/s
Thus, the truck’s acceleration would be 3 m/s², and the momentum after it has reached this final velocity would be 144000 kgm/s.
Learn more about momentum from here
brainly.com/question/17662202
#SPJ5