A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision.

B. The springs stretched to double the original displacement, is the the statement that best describe the effect this had on the springs.

The displacement is the shortest distance in geometry and mechanics between the initial and final positions of a point P. From the starting position to the ending position of the point trajectory, it measures the length and direction of the net motion, or total motion, in a straight line. A displacement can be discovered by using the translation that joins the starting point and ending point.

Another way to define a displacement as a relative position is the relationship between a point's final position, or xf, and its starting position, or xi (resulting from motion). The corresponding displacement vector can be defined by the difference between the starting and final positions:

                                            [tex]$ s=x_{\textrm {f}}-x_{\textrm {i}}=\Delta {x}}$[/tex]

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Hence, the ladder top to touch ground the ladder base should pull back a distance of ( 6 - 3 ) = 3 meters on ground As the rate of sliding of base of ladder is 0.5 meter per second , it takes a time of [  3/ (0.5) ] = 6 seconds.

What is Distance? Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.

Distance measures length. For example, the distance of a road is how long the road is. In the metric system of measurement, the most common units of distance are millimeters, centimeters, meters, and kilometers.

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The mass added to the object to change the period to 2.05 s is 0.42 kg

What is the time period of an oscillation?

The time taken for an oscillating particle to complete one cycle of oscillation is known as the Period of oscillating particle.

Given :

A 0.480-kg mass suspended from a spring oscillates with a period of 1.50 s.

The formula of the time period is given by:

 [tex]T=2\pi \sqrt{m/K}[/tex] ------(1)

where m is the mass and K is the spring constant.

The new time period is given by:

[tex]T'=2\pi \sqrt{m^{'} /K[/tex]-----(2)

where m' is the total mass after the addition and K is the spring constant.

Dividing equation (1) by equation (2).

[tex]T/T'=\sqrt{m/m'}[/tex]

Now, substitute the known terms in the above expression.

[tex]\frac{1.50}{2.05} =\sqrt{0.480/m'}[/tex]

[tex]m'=\frac{0.480}{0.5329}[/tex]

[tex]m'=0.9[/tex] kg

Now, the mass added to the object to change the period to 2.05 s is given by:

m" = 0.9 - 0.480

m" = 0.42 Kg

Thus, 0.42kg of mass must be added to the object to change the period to 2.05s.

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A force on the free-body diagram above which represents the normal force acting on the car include the following: D. Force A.

In Science, a free-body diagram can be defined as a graphical illustration which is typically used in the field of science to visualize moments, tension, and applied forces that are acting on an isolated or rigid object (body), while using arrows to point in the direction of these forces.

Since this car was driven to the right, with a large amount of air resistance acting on it, and its engine provides the forward motion, we can reasonably infer and logically deduce that the normal force which is acting on the car is represented by Force A as illustrated by the free-body diagram shown in the image attached above.

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Answer: N 0.072

Explanation:

First thing i did was figure out what the negative charge was originaly

The charge and the polarity of the 2nd object is 0.072 N.

Contact forces are the kinds of forces that develop when two objects interact and appear to be in physical contact with one another.

Frictional forces, tensional forces, normal forces, air resistance forces, and applied forces are a few examples of contact forces. Lesson 2 and subsequent lessons will cover these particular forces in greater depth.

Action-at-a-distance forces are those that happen even when the two interacting objects are not physically touching each other but are nevertheless able to push or pull against each other despite their physical separation.

Therefore, The charge and the polarity of the 2nd object is 0.072N.

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Answer:

The potential energy (P.E.) stored in an elastic spring is equal to the work done in compressing or stretching the spring.

When a spring is compressed or stretched, the force required to do so is given by Hooke's law, which states that the force F required to compress or stretch a spring by an amount x is given by

F = kx, where k is the spring constant.

The work done in compressing or stretching a spring is equal to the force required to do so multiplied by the distance over which the force is applied.

In the case of a spring, this distance is equal to the amount x by which the spring is compressed or stretched.

Therefore, the work done in compressing or stretching a spring is given by

W = Fd = kx * x = kx^2.

The potential energy stored in the spring is equal to the work done to compress or stretch it.

Therefore, the potential energy of a spring that is compressed by an amount x is given by P.E. = W = kx^2.

Substituting kx^2 = 1/2 kx^2, we find that

P.E. = 1/2 kx^2.

This shows that the potential energy stored in an elastic spring is equal to 1/2 times the spring constant multiplied by the amount x by which the spring is compressed or stretched.

Explanation:

The work W required to lift an object varies jointly with the object's mass m and the height h that the object is lifted. The work required to lift a 120-kilogram object 1.8 meters is 2116.8 joules is 1,372J.

In physics, the term "work" refers to the measurement of energy transfer that takes place when an item is moved over a distance by an external force, at least a portion of which is applied in the direction of the displacement.

Work done can be computed using the formula:

[tex]w=Fd[/tex]

Where:

W = work (J)

F = Force (N)

d = Distance (d)

Looking at the given, you know that you do not have a value for force, so you will have to solve for it. 

[tex]F=Ma[/tex]

Where:

F = Force

m = mass

a = acceleration

Because the object is being lifted, the acceleration will rely on gravity. Acceleration due to gravity is a constant 9.8 m/s^2. Let's list our given first:

F = ?

m = 100kg

a = 9.8m/s^2

Put that into our equation and solve:

[tex]F=mA\\F=100*9.8\\F=980Kg.m/s^{2}[/tex]

Our force is then 980 N. 

Now that we have force we can solve for Work. The given for work is as follows:

F= 980N

d = 1.4mPut that into our formula and solve:

[tex]W=Fd[/tex]

[tex]W=(980)*(1.4)\\W=1372[/tex]

The work done is 1,372J.

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Answer:

forest

Explanation:

cause of the echo

Answer:

forest

Explanation:

very spacious enough to make echo

It is False that  Visual inspection of the brake drum friction surface is not required, only measure drum diameter.

No matter whether the vehicle is moving forward or backward, drum brakes produce uniform braking force. Drum brakes produce the same amount of braking force in both directions, which explains this. This kind is typically utilized for the passenger car's rear brakes.

Unusual brake pedal sensation is one of the first indications when drum brakes are damaged or failing. Excessive brake drum wear might result in vibrations that can be felt in the pedal. When you press the pedal, any trembling or pulsating brought on by worn drums will be audible.

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Answer:

The object's mass is 41.1125 kilograms.

Explanation:

We can use the general density equation to determine the mass.

Density Equation

[tex]p=\frac{m}{V}[/tex]

[tex]p[/tex] is the density

[tex]m[/tex] is the mass

[tex]V[/tex] is the volume

Lets solve for [tex]V[/tex].

Multiply both sides of the equation by [tex]V[/tex].

[tex]p*V=\frac{m}{V}*V[/tex]

Cancel out the common factor of [tex]V[/tex] on the right side.

[tex]pV=m\\m=pV[/tex]

Now we have an equation for mass.

We are given

[tex]p=3.25[/tex]

[tex]V=12.65[/tex]

Substituting our values into our equation gives us

[tex]m=3.25*12.65\\m=41.1125[/tex]

Notice the unit of the given density

[tex]kg/m[/tex]

Our answer will be in kilograms

The radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.

The radius of the event horizon of a black hole is known as the Schwarzschild radius and it is a function of the mass of the black hole. The Schwarzschild radius is given by the formula:

r = 2GM/c^2

where

r = radius of the event horizon (in meters)

G = gravitational constant (6.674 x 10^-11 N*(m/kg)^2)

M = mass of the black hole (in kg)

c = speed of light in a vacuum (2.998 x 10^8 m/s)

For a 10-Solar-mass black hole, we can use the mass conversion factor 1 Solar mass = 1.989 x 10^30 kg.

M = 10 x 1.989 x 10^30 kg

Now, we can substitute the values into the formula

r = 2 x 6.674 x 10^-11 x M/ (2.998 x 10^8)^2

r = 2GM/c^2 = 2 x 6.674 x 10^-11 x (10 x 1.989 x 10^30) / (2.998 x 10^8)^2

r = 2.95 x 10^3 m = 2950 kilometers

So, the radius of the event horizon of a 10-Solar-mass black hole is 2950 kilometers.

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There is a drag force that opposes a person's motion while they are moving through a fluid, whether it be air or liquid. Range of motion is constrained by the drag force. Drag force is overcome by the suits. The drawback is overheating.

A bodysuit's main function is to give you support and a seamless tuck-in so you may dress comfortably and easily. Bodysuits can be skin-tight or loose, and because of the tension they create from the shoulders to the crotch, they can embrace your curves and serve as the ideal foundation for whichever bottom you choose.

They can be warm and tight or very thin - useful for warmth - or even be very light (say, 60g), cooling underwear. They are typically elastic and stretchy. They can serve as both underwear and outerwear, but a pair of trousers, pants, or a skirt must be worn below.

Benefits include being thin, warm or cooling, extremely snug, occasionally shapewear, suitable for layering, and warm without bulk (you can get a big deal from a 60g torso garment). fitting in.

They interfere with using the restroom and can occasionally make it difficult to distinguish their front from back sides. Typically, the longer portion of the crotch, called the tail, is at the back. The bodysuits without arms, however, can also be worn buttoned up.

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The sun will become a red giant but it will not be a problem for humanity because the Earth will become inhabitable before that.

As per the research conducted it is said that the sun will eventually become a red giant and it engulf our planet Earth. The Earth will become extremely giant. This in turn will not become a problem for humanity, flora and fauna as the Earth will be completely inhabitable. All the forms of life will completely perish and no life form will exist. The planet will be engulfed by the red giant Sun. This is the reason it is not a problem for humanity.

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The force that prevents motion between any two surfaces that are contacting is called friction. Every machine has friction because it involves motion. As a result, efficiency is never 100 percent.

Efficiency is the proportion of user-inputted work (input work) that is converted into output work by a machine (output work). Because some of the input work is used to overcome friction, the output work is always less than the input work.

The force that would grow or decrease in the absence of friction is reflected in the ideal mechanical advantage of a machine. It is consistently larger.

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Answer:

Simple cell has liquid chemicals and it is difficult to carry from one place to another. Dry cell has no solution. So, it is easier to carry it from one place to another and there is no risk of spilling acid from the dry cell. So, dry cell is more useful than simple cell in our daily life.

Answer: 66.02dB

Explanation: We use the equation β=(10dB)㏒([tex]\frac{I}{I_0}[/tex])

[tex]I_{0}[/tex]= the threshold of hearing which is 1.0×[tex]10^{-12}[/tex]W/[tex]m^{2}[/tex]

Plug in our knowns β=(10dB)㏒([tex]\frac{4.0*10^{-6} }{1.0*10^{-12} }[/tex])=66.02dB

The potential energy of Nan suitcase of mass 14 kg is 54.88 J.

Potential energy is the energy of a body due to its position in the gravitational field.

To calculate the potential energy, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the potential energy is 54.88 J.

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The value W' along inclined plane = (150 sin α ) N

W = m x g = 150 N --> based on case

W = weigth

m = massa

g = gravity acceleration

Fn = Normal force

Fn = m x g x cos α = W cos α = 150 N x cos α

W’ = m x g x sin α = W sin α = 150 N x sin α

Since the angle α is not known it will be still variable, so we could say that the W’ = (150 sin α ) N

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The kinetic energy would be 96 J, for the car moving at 4m/s and with 3kg mass.

The kinetic energy (Ek) of the toy car is given by Ek = ½ mv2, where m is the mass of the car (3 kg) and v is the velocity (4 m/s). Thus, the kinetic energy of the car is 24 J. If the car were moving twice as fast (8 m/s), the kinetic energy would be 96 J. The units are Joules (J).

Kinetic energy is the energy of a body or system due to its motion. It is the energy that an object has due to its motion. Kinetic energy is equal to one half of the mass of the object multiplied by the square of its velocity.

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It is believed that human activity has increased the amount of particulates or aerosols in the atmosphere, including sulfate aerosols.

dimmed, dimming, verb (used with subject), dimmeddull or make dimmer. to change (a vehicle's headlights) from high to low beam.dimmed, dimming, verb (and use it without object), dimmed

The restaurant's dim sum was quite well-liked.On the weekends, waiters drive a cart that contains the dim sum in the old-fashioned manner.

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Dynamic stretching is recommended before activity because it helps to prepare the muscles for the upcoming activity.

It increases range of motion, flexibility, and muscular coordination, and also helps to increase blood flow to the muscles. This helps to improve the performance of the muscles and reduce the risk of injury. Additionally, dynamic stretching helps to improve the overall physical conditioning of an individual, which is beneficial for any type of physical activity.

Dynamic stretching is typically recommended for individuals preparing for physical activity. Dynamic stretching involves movements that gradually increase in range of motion and muscle length, such as arm swings, leg swings, and torso twists.

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when it takes 4x units of distance from the light for you to receive 4Y units of light in a given amount of time.

Distance is a measurement of the separation between two things or locations, either quantitatively or qualitatively. A physical distance or perhaps an estimate relying on other physics- or usage-related characteristics can both be referred to as distance. The phrase is also employed metaphorically to denote a measurement of the degree of distance between two common pieces since spatial intelligence is a rich source of implicatures in human understanding. The majority of these concepts of distance, both literal and figurative, are codified using the idea of a metric space.

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The steady deceleration of a car traveling at 15 m/s starts. After ten seconds, it abruptly ends. starting speed of the vehicle

When subtracting the distance even by travel time, speed is calculated. The distance and time information must be understood in order to calculate the pace units. The measurements in the this case will be performed in meters per second (m/s), as the length was measured in meters and the time is stated in minutes (s).

Velocity is the rate and direction of an object's motion, whereas speed is the rate at which an object moves along a path over time. In other words, whereas speed is in fact a scalar value, velocity is a vector.

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The angle turned in 5.26 s is 6470 degrees. An initial angular speed of 12.5 rad/s and a constant angular acceleration of 3.41 rad/s2 are the characteristics of a pulley.

The angular acceleration provides the rate of change of angular velocity, just like in the case of linear velocity and acceleration: The rate at which the angular velocity varies is determined by the angular acceleration's magnitude, and the change's direction is determined by the direction.

The rate at which angular velocity changes is referred to as angular acceleration. In an equation, angular acceleration is written as follows: = t, where t is the change in time and is the change in angular velocity.

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The method used when an entire mole is removed for examination under a microscope is called an excisional biopsy.

This method involves the surgical removal of the entire mole and some surrounding skin which is then examined under a microscope to check for any abnormal cells or signs of cancer. This method is typically used when a mole is suspected to be malignant or when it cannot be clearly diagnosed as benign through other methods such as a shave or punch biopsy.

The key benefit is that, as opposed to an incisional biopsy, when a bit of the tissue is taken to provide a diagnosis but it will likely still need to be treated later, the aberrant tissue may be identified, diagnosed, and removed in one operation.

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Answer:

i believe it would be 64 kJ

Explanation:

Option B is V2/Mg  gives the total distance travelled by the mass before it is slowed to a stop by friction

The total distance traveled by the mass before it is slowed to a stop by friction can be determined by calculating the work done by the force of friction on the mass. As we have seen before, the force of friction acting on the mass is given by the equation F = friction = umg.

Now, the work done by the force of friction on the mass is given by W = Fd. Using the definition of force of friction and assuming that the final velocity of the mass is zero, we can write the following equation:

umgd = (1/2)mv^2

Dividing both sides by m*g and simplifying the equation we get:

d = (1/2) * u^-1 *v^2 /g

If we compare this expression with the options provided, we can see that it matches with option B: V^2/Mg. Therefore, the total distance traveled by the mass before it is slowed to a stop by friction is given by V^2/Mg.

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The complete question is :

With velocity, a mass moves horizontally along a nearly frictionless floor. The mass now comes into contact with a section of the floor that has a coefficient of kinetic friction equal to Which option gives the total distance travelled by the mass before it is slowed to a stop by friction?

Option A is 2V2/Mg.

Option B is V2/Mg

According to the given statement (a) power in this case will be P=38,933.2428 Watts (b) power in this case will be P=91,788.4599\ W

Average power is defined as the work done per unit time.

Work done can be found by change in kinetic energy.

[tex]W=Kf-Ki\\\\=\frac{1}{2}\mathrm{\ }m(Vf)^2-\frac{1}{2}\mathrm{\ }m(Vi)^2\\\\\Rightarrow\frac{m}{2}\left\{(28.4)^2-(0)^2\right\}\\\\=403.28\mathrm{\ }mJ oules.[/tex]

[tex]P=\frac{W}{t}=\frac{403.28\ m}{6.68}=60.37125mWatts.[/tex]

Explanation: Please refer to solution in this step.

a.) mass of the car will bemass [tex]=\frac{\mathrm{\ Weight\ }}{g}=0.644897\times{10}^3Kg[/tex]

using above equation we can find the power, [tex]P=60.37125\left(0.644897\times{10}^3\right)[/tex]

[tex]=38,933.2428 Watts[/tex]

b.) mass of the car will be [tex]=\frac{\mathrm{\ Weight\ }}{g}=0.152040\times{10}^4Kg[/tex]

using above equation we can find

the power, [tex]P=60.37125\left(0.152040\times{10}^4\right)=91,788.4599 Watts[/tex]

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Answer:

Explanation: