A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h cm3. Find the rate at which the volume of the box is changing when the edge length of the base is 10 cm, the edge length of the base is increasing at a rate of 3 cm/min, the height of the box is 5 cm, and the height is decreasing at a rate of 1 cm/min.
A.The volume of the box is decreasing at a rate of 200 cm3/min.
B.The volume of the box is increasing at a rate of 400 cm3/min.
C.The volume of the box is decreasing at a rate of 400 cm3/min.
D.The volume of the box is increasing at a rate of 200 cm3/min.

Answers

Answer 1

Answer:

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Related Questions

Write a function rule for the table.

Answers

Answer:

A

Step-by-step explanation:

slope=(1-0)/(5-4)=1

eq. of line through (4,0) with slope 1 is

y-0=1(x-4)

put y=f(x)

f(x)=x-4

Function A and Function B are linear functions. Function A x y – 10 – 14 – 1 – 5 9 5 Function B y=2x+4 Which statement is true?

Answers

Answer:

See explanation

Step-by-step explanation:

Function A is not clear; I will use the following in place of function A

Function A:

[tex]x \to\ 1 |\ 3 |\ 4 |\ 6[/tex]

[tex]y \to -1|\ 3|\ 5|\ 9[/tex]

Function B:

[tex]y = 2x + 4[/tex]

Required

Compare both functions

For linear functions, we often compare the slope and the y intercepts only.

Calculating the slope of function A, we have:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where:

[tex](x_1,y_1) = (1,-1)[/tex]

[tex](x_2,y_2) = (3,3)[/tex]

So, we have:

[tex]m = \frac{3 - -1}{3 - 1}[/tex]

[tex]m = \frac{4}{2}[/tex]

[tex]m = 2[/tex]

To calculate the y intercept, we set [tex]x = 0[/tex], then solve for y

i.e.[tex](x,y) = (0,y)[/tex]

Using the slope formula, we have:

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where:

[tex]m = 2[/tex]

[tex](x_1,y_1) = (0,y)[/tex]

[tex](x_2,y_2) = (3,3)[/tex]

So, we have:

[tex]2 = \frac{3 - y}{3 - 0}[/tex]

[tex]2 = \frac{3 - y}{3}[/tex]

Multiply by 3

[tex]6 = 3 - y[/tex]

Collect like terms

[tex]y = 3 - 6[/tex]

[tex]y = -3[/tex]

So, for function A:

[tex]m = 2[/tex] -- slope

[tex]y = -3[/tex] --- y intercept

For function B

[tex]y = 2x + 4[/tex]

A linear function is represented as:

[tex]y = mx + b[/tex]

By comparison

[tex]m = 2[/tex] --- slope

[tex]b = 4[/tex] --- y intercept

By comparing the results of both functions, we have the following conclusion:

Functions A and B have the same slope (i.e. 2)

Function B has a greater y intercept (i.e. 4)

what is f(2)=
this thing had to be atleast 20

Answers

Can you clarify because this would be 2f and I don’t think this is the answer you are looking for

can someone please help me..

Answers

Answer:

A. It acts perpendicular to an object

It acts perpendicular to an object

Find the area of the region between the curve x^3+2x^2-3x and the x-axis over the interval [-3,1]

Answers

Answer:

[tex]\displaystyle A = \frac{32}{3}[/tex]

General Formulas and Concepts:

Calculus

Integrals

Definite IntegralsArea under the curve

Integration Rule [Reverse Power Rule]:                                                                   [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                        [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                             [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                           [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Area of a Region Formula:                                                                                       [tex]\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

Curve: x³ + 2x² - 3x

Interval: [-3, 1]

Step 2: Find Area

Set up:                                                                                                               [tex]\displaystyle A = \int\limits^1_{-3} {(x^3 + 2x^2 - 3x)} \, dx[/tex][Integral] Rewrite [Integration Property - Addition/Subtraction]:                   [tex]\displaystyle A = \int\limits^1_{-3} {x^3} \, dx + \int\limits^1_{-3} {2x^2} \, dx - \int\limits^1_{-3} {3x} \, dx[/tex][Integrals] Rewrite [Integration Property - Multiplied Constant]:                   [tex]\displaystyle A = \int\limits^1_{-3} {x^3} \, dx + 2\int\limits^1_{-3} {x^2} \, dx - 3\int\limits^1_{-3} {x} \, dx[/tex][Integrals] Integrate [Integration Rule - Reverse Power Rule]:                      [tex]\displaystyle A = (\frac{x^4}{4}) \bigg| \limits^1_{-3} + 2(\frac{x^3}{3}) \bigg| \limits^1_{-3} - 3(\frac{x^2}{2}) \bigg| \limits^1_{-3}[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:              [tex]\displaystyle A = -20 + 2(\frac{28}{3}) - 3(-4)[/tex]Evaluate:                                                                                                           [tex]\displaystyle A = \frac{32}{3}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Find the prime factorization on 168

Answers

Answer:

The prime factors of 168 are 2, 3, and 7.

Step-by-step explanation:

let's write the whole numbers from 90 to 100 . Select the appropriate number to form the following sets . Then , write the type of sets .
A={ even number}
B={ odd number}
C={ X:X is a prime numbers}
D={ y:y is a composite number}
E={z:z is a square number}
F={ cube number}
G={ multiples of 7}
H={ X:X is divisible by 11}​

Answers

A={ even number}

B={ odd number}

C={ X:X is a prime numbers}

D={ y:y is a composite number}

E={z:z is a square number}

F={ cube number}

G={ multiples of 7}

H={ X:X is divisible by 11}

꧁Aɴsᴡᴇʀ꧂

A

The even numbers between 90 and 100 are: 90, 92, 94, 96, 98, 100B

The odd numbers between 90 and 100 are: 91, 93, 95, 97, 99

C

The prime number between 90 and 100 is: 97D

The composite numbers between 90 and 100 are: 91, 92, 93, 94, 95, 96, 98 and 99.

E

The square numbers between 90 and 100 are:

90 = 8100

91 = 8281

92 = 8464

93 = 8649

94 = 8836

95 = 9025

96 = 9216

97 = 9409

98 = 9604

99 = 9801

100 = 10000

F

The answer for this is on the attached picture above. Kindly look at it. The cube numbers between 90 and 100. G

The multiples of 7 between 90 and 100 are: 91 and 98

H

Divisible by 11 (between 90 and 100) is: 99

ʰ ʰˡˢ

Answer:

A

The even numbers between 90 and 100 are: 90, 92, 94, 96, 98, 100

B

The odd numbers between 90 and 100 are: 91, 93, 95, 97, 99

C

The prime number between 90 and 100 is: 97

D

The composite numbers between 90 and 100 are: 91, 92, 93, 94, 95, 96, 98 and 99.

E

The square numbers between 90 and 100 are:

90 = 8100

91 = 8281

92 = 8464

93 = 8649

94 = 8836

95 = 9025

96 = 9216

97 = 9409

98 = 9604

99 = 9801

100 = 10000

F

The answer for this is on the attached picture above. Kindly look at it. The cube numbers between 90 and 100.

G

The multiples of 7 between 90 and 100 are: 91 and 98

H

Divisible by 11 (between 90 and 100) is: 99

Find the area of circle x that has a radius at coordinates X = (0, 3) and Y = (-3, -1). Round to the nearest tenth.

Answers

Answer:

78.5 units²

Step-by-step explanation:

Area of circle:

A = πr²

Distance between x and y is same as r, so:

r² = (0 + 3)² + (3 + 1)² = 9 + 16 = 25

Then the area is:

A = π*25 = 78.5 units² (rounded)

12 times 12 divided by 6

Answers

Answer:

24 , 12x12 = 144. , 144/6 =24

What percent of 45 is 27

Answers

Answer:

60%

Step-by-step explanation:

27/45 = .6

.6 = 60%

The lines r: x+3=0 and s: y-2=0 intersect at a point P.
a) Determine the coordinates of point P.
b)What is the distance of P from the origin?​

Answers

Answer:

(-3,2)

Step-by-step explanation:

The given Equations of lines are ,

[tex]\implies x + 3 = 0 [/tex]

[tex]\implies y -2 = 0 [/tex]

On plotting the graph of the given two equations we will get that the two lines will intersect each other at a point and that point will be the solution of the system of equation. On drawing a graph ,

On looking at graph , Point P will be ,

[tex]\implies Solution = P(-3,2) [/tex]

Solve -x/3>5 i don't know what to do

Answers

Answer:

It's D, x≤-15

A radar station located at ground level picks up a plane flying at a direct distance of 47,440 feet
away. If the angle of elevation from the station to the plane is 29°, what is the altitude of the plane?

Answers

Answer:

22,999 feets

Step-by-step explanation:

Given the solution diagram attached,

The altitude, h of the plane can be solved using trigonometry :

Using :

Sin θ = opposite / hypotenus

Opposite = h

Hypotenus = 47440

Sin 29 = h / 47440

h = 47440 * sin29

h = 22999.368

h = 22,999 feets

Emmy just bought a new laptop! She used a student discount code that took $50.75 off the original price. The discounted price of the laptop was $349.24. Let p represent the original price of the laptop. Which equation models the problem?

Answers

Answer:

can you show the equations?

HELP!!!!!!!!!!!!!!!! pls

Answers

Answer: y = 25 - 2x

Step-by-step explanation:

y = mx + b

m = slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{23-25}{1-0} =\frac{-2}{1} =-2[/tex]b = y-intercept = when x = 0 = 25

y = -2x + 25

What is the simplified value of the expression below?
1/3 divided by 2/3

0

1/3

1/2

1

Answers

1/2
Is the answer
To the problem

Answer:

option C : 1/2

Step-by-step explanation:

[tex]\frac{1}{3} \div \frac{2}{3} \\\\\frac{\frac{1}{3}}{\frac{2}{3}}\\\\\frac{1}{3} \times \frac{3}{2} \\\\\frac{1}{2}[/tex]

6 foxes catch 6 hens in 6 minutes, how many foxes will it take to catch 60 hens in 60 min. AND NO ITS NOT 60 I ALREADY TRIED. WHOEVER ANSWERS GETS 50 POINTS!

Answers

Answer:

It is 6 foxes

Step-by-step explanation:

Because if 6 foxes can catch 6 hens in 6 minuets then 6 foxs can can 60 hens in 60 minutes because you just multiply 6 minutes by 10 and get 60 minutes which is also the same for hens.

Answer:

6 foxes

Step-by-step explanation:

For 6 foxes to catch 60 hens (10 x 6 or 10 times more than 6 hens) they will need 10 times more time than they had to catch 6 hens, or 10 x 6 = 60 minutes.

The measurement of the angle K is 3x - 42, and it is obtuse. Find the restriction(s) on the values of x.

Answers

Answer:

x = 44° and 74°: x cannot be less than 44°, x cannot be greater than 74°.

Step-by-step explanation:

Obtuse angles are greater than 90° but less than 180°.

We can first solve for the lower bound of x.

[tex]3x-42=90[/tex][tex]3x=132\\[/tex][tex]x=44[/tex]°

Thus the lower bound restriction of x is 44°

We can now solve for the upper bound of x.

[tex]3x-42=180[/tex][tex]3x=222[/tex][tex]x=74[/tex]°

Thus the upper bound restriction of x is 74°

The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are (_,_)
The coordinates of the point that is a reflection of Y across the y-axis are (_,_) also anwser the top u know

Answers

Answer:

(-4,2)

Step-by-step explanation:

pls hurry!! helpppp i wil give brainliest..

Answers

the answer is triangle a
i believe it’s triangle p

Kelly has $25 in her purse, and Dante has d dollars in his wallet
Which algebraic expression represents the total amount that Kelly and dante have?

Answers

The equation will be:

25 + d = t

where t is total money

Help me ASAP please

Answers

Step-by-step explanation:

similar triangles are simply like a linear protection, a "zoom" without distortion from one triangle to the other.

so, all linear distances and connections change by the same scaling factor.

therefore also the height EF of the smaller triangle colors the same scaling factor as the other lines. and EF is half the length of CG.

the area of a triangle is defined as baseline × height /2.

so, 2 linear distances are multiplied.

each one now contains the same scaling factor. so, the formula for the similar triangle multiplies the original distances and fire each also the scaling factor leading to the square of the scaling factor.

so, area new = area old × scaling²

in our example the scaling factor is 2, and 2² = 4.

so the area of ABC is 4 times as large as the area of ADE.

In ∆ABC if AB = 6 cm , BC = 8cm, AC = 10 cm then value of ∠B is ________​

Answers

Answer:

90 degrees

Step-by-step explanation:

B is the corner and angle opposite of the side AC.

so, AC is becoming side c, and the other two are a and b (it does not matter which is which).

we use the enhanced Pythagoras formula for general triangles

c² = a² + b² - 2ab×cos(C)

in our example the angle C is named B.

but other than that we simply calculate

10² = 6² + 8² - 2×6×8×cos(B)

100 = 36 + 64 - 96×cos(B)

100 = 100 - 96×cos(B)

0 = -96×cos(B)

cos(B) = 0

=>

B = 90 degrees

A bakery offers 4 different flavors of cake, 3 types of icing, 6 toppings, and 3 different sizes. If one option is chosen from each list, how many different cakes are possible? *

Answers

Answer:

216 different cakes are possible.

Step-by-step explanation:

Given that a bakery offers 4 different flavors of cake, 3 types of icing, 6 toppings, and 3 different sizes, if one option is chosen from each list, to determine how many different cakes are possible the following calculation must be performed:

4 x 3 x 6 x 3 = X

12 x 18 = X

216 = X

Therefore, 216 different cakes are possible.

3x + y = 10 x - y = 2 2​

Answers

Answer: in the picture

A jewellery shop is having a sale. A bracelet is now reduced to £420. This is 70% of the original price. Work out the original price of the bracelet.

Answers

Answer:

Step-by-step explanation:

x is the original price.

420/x = 70% = 0.7

x = 420/0.7 = 600

Original price of bracelet was £600

at the farmers market 8 apple cost $5.20 if each apple cost the samw amount what is the price per apple

Answers

[tex]\displaystyle\bf Solve:8\times p=5,2 \$ => p=\frac{5,2}{8} =\frac{5,2:\boxed{8}}{8:\boxed{8}} =0,65\$\quad She \:unit\: cost\:is\:\underline{ 0,65} \\\\Check :\:8\times\underline{0,65} =5,2\$ \\\\0,65=0,65 \\\\\rightarrow The\: price\:per \:apple \:is \: 0,65 \$[/tex]

he sum of the first two terms of a G.P is 27 whereas the sum of the second and third term is 54. Find the first term and the common ratio.​

Answers

Answer:

[tex]{ \tt{sum = \frac{a(r {}^{n - 1} )}{n - 1} }} \\ 27 = \frac{a(r {}^{2 - 1} )}{2 - 1} \\ { \bf{27 = ar - - - (i)}} \\ \\ 54 = \frac{a( {r}^{3 - 1} )}{3 - 1} \\ { \bf{108 = a {r}^{2} - - - (ii) }} \\ { \tt{(ii) \div (i) : }} \\ r = \frac{108}{27} \\ { \bf{common \: ratio = 4}} \\ { \bf{first \: term = \frac{27}{4} }}[/tex]

Ted can clear a football field of debris in 3 hours. Jacob can clear the same field in 2 hours. When they work together, the situation can be modeled by the equation, where t is the number of hours it would take to clear the field together.



How long will it take Ted and Jacob to clear the field together?

Answers

Answer:

[tex]\frac{6}{5}[/tex] of an hour = 1 1/5 hour = 72 minutes

Step-by-step explanation:

[tex]\frac{1}{3} h + \frac{1}{2}h = 1\\\\\frac{2}{6} h + \frac{3}{6}h = 1\\\\\\\frac{5 }{6} h =1\\\\h=\frac{6}{5}[/tex]

It would take Ted and Jacob 6/5 or 1.2 hours to clear the field together.

What is an equation?

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

Let's use the formula for the work rate:

Ted's work rate = 1/3 of the field per hour

Jacob's work rate = 1/2 of the field per hour

Together, their work rate.

= (1/3 + 1/2) of the field per hour

Now,

We can simplify the equation for the combined work rate by finding a common denominator:

(1/3 + 1/2)

= (2/6 + 3/6)

= 5/6 of the field per hour

Now we can use the formula for the work rate to solve the time it would take them to clear the field together:

(5/6)t = 1

(where t is the time in hours)

Solving for t:

(5/6)t = 1

t = 6/5

Therefore,

It would take Ted and Jacob 6/5 or 1.2 hours to clear the field together.

Learn more about equations here:

https://brainly.com/question/17194269

#SPJ7

Cathy ran 10 meters in 2 seconds. How much time did she take to complete 100 meters?

Answers

Answer:

If Cathy ran at a constant speed of 10 meters in 2 seconds, it took Cathy 20 seconds to run 100 meters.

Step-by-step explanation:

Hope this helps.

Answer:

If Cathy run at constant speed of 10 meters in 2 seconds, it took Cathy 20 second to run 100 meters.

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