A radio transmission tower is 180 feet high. How long should a guy wire be if it is to be attached to the tower 11 feet from the top and is to make an angle of 45° with the ground?​

Answer:

34n=306

Step-by-step explanation:

Use inverse operation to find it, 306÷34= 9, check again 34(9)=306, so it's correct!

Answer:

(12+2)(15+3)(9+4)(2+5)-48

=4

Answer:

32°

Step-by-step explanation:

in 32° is right answer

In isosceles triangle, △HAM, m∠H is 74 degree.

A triangle in which any two sides are equal in length and angles opposite to equal side are also equal. And sum of all angles in a triangle is 180.

Given, m∠A = 32°

sum of all angles = 180°

In △HAM

∠H = ∠M

∠H+ ∠A+ ∠M = 180°

2∠H = 180 - 32

2∠H = 148

∠H = 74°

To learn more about isosceles triangle here

https://brainly.com/question/10147636

#SPJ2

Answer:

Ideez

Step-by-step explanation:

Answer:

Relative minimum: [tex]\left(-\frac{5}{2}, -\frac{33}{4}\right)[/tex], Relative maximum: [tex]DNE[/tex]

Step-by-step explanation:

First, we obtain the First and Second Derivatives of the polynomic function:

First Derivative

[tex]f'(x) = 2\cdot x + 5[/tex] (1)

Second Derivative

[tex]f''(x) = 2[/tex] (2)

Now, we proceed with the First Derivative Test on (1):

[tex]2\cdot x + 5 = 0[/tex]

[tex]x = -\frac{5}{2}[/tex]

The critical point is [tex]-\frac{5}{2}[/tex].

As the second derivative is a constant function, we know that critical point leads to a minimum by Second Derivative Test, since [tex]f\left(-\frac{5}{2}\right) > 0[/tex].

Lastly, we find the remaining component associated with the critical point by direct evaluation of the function:

[tex]f\left(-\frac{5}{2} \right) = \left(-\frac{5}{2} \right)^{2} + 5\cdot \left(-\frac{5}{2} \right) - 2[/tex]

[tex]f\left(-\frac{5}{2} \right) = -\frac{33}{4}[/tex]

There are relative maxima.

Answer:

8.2 miles per minute

Step-by-step explanation:

Given

See attachment for graph

Required

The rate of Tyler's graph

This means that we calculate the slope (m) of the graph using:

[tex]m = \frac{y_1 - y_2}{x_1 - x_2}[/tex]

So, we have:

[tex](x_1 ,y_1) = (0,0)[/tex]

[tex](x_1 ,y_1) = (1,8.2)[/tex]

So, we have:

[tex]m = \frac{y_1 - y_2}{x_1 - x_2}[/tex]

[tex]m = \frac{0 - 8.2}{0 - 1}[/tex]

[tex]m = \frac{-8.2}{- 1}[/tex]

[tex]m = 8.2}[/tex]

Answer: D

Step-by-step explanation:

Try to draw the X and Y axis: When you shift the function to left it translates as going to the left of the X axis. So what you want is that every value of X on the parent function to correspond to the same x value minus four.

You can apply the same logic to get the + 6

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { 18 {x}^{2} - 69x - 55}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] = (9x + 5) - ( - 2 x+ 10)(9x + 5) - ( - 2x + 10)[/tex]

[tex] = (9x + 5) + 2x (9x + 5) - 10(9x + 5) - ( - 2x + 10)[/tex]

[tex] = 9x + 5 + 18 {x}^{2} + 10 x- 90x - 50 + 2x - 10[/tex]

Collect the like terms.

[tex] = 18 {x}^{2} + (9x + 10x- 90x + 2x) + (5 - 50 - 10)[/tex]

[tex] = 18 {x}^{2} + (21x - 90x) +(5 - 60)[/tex]

[tex] = 18 {x}^{2} - 69x - 55[/tex]

[tex]\sf\pink{PEMDAS\: rule.}[/tex]

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

Answer:

A: x = 0

B: x = All real numbers

Step-by-step explanation:

A.

Any number to the power of (0) equals one. This applies true for the given situation; one is given an expression which is as follows;

[tex](6^2)^x=1[/tex]

Simplifying that will result in;

[tex]36^x=1[/tex]

As stated above, any number to the power of (0) equals (1), thus (x) must equal (0) for this equation to hold true.

[tex]36^0=1\\x=0[/tex]

B.

As stated in part (A), any number to the power (0) equals (1). Therefore, when given the following expression;

[tex](6^0)^x=1[/tex]

One can simplify that;

[tex]1^x=1[/tex]

However, (1) to any degree still equals (1). Thus, (x) can be any value, and the equation will still hold true.

[tex]x=All\ real \ numbers[/tex]

Answer:

first thing is y - 35 = 5

then y = 35 + 5 because when = come here - will be + and

then we should do+ y=40 answer

Answer:

[tex]b=h=\sqrt{6}[/tex] m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=[tex]2b^2+4bh[/tex]

[tex]2b^2+4bh=36[/tex]

[tex]b^2+2bh=18[/tex]

[tex]2bh=18-b^2[/tex]

[tex]h=\frac{18-b^2}{2b}[/tex]

Volume of box, V=[tex]b^2h[/tex]

Substitute the values

[tex]V=b^2\times \frac{18-b^2}{2b}[/tex]

[tex]V=\frac{1}{2}(18b-b^3)[/tex]

Differentiate w. r.t b

[tex]\frac{dV}{db}=\frac{1}{2}(18-3b^2)[/tex]

[tex]\frac{dV}{db}=0[/tex]

[tex]\frac{1}{2}(18-3b^2)=0[/tex]

[tex]\implies 18-3b^2=0[/tex]

[tex]\implies 3b^2=18[/tex]

[tex]b^2=6[/tex]

[tex]b=\pm \sqrt{6}[/tex]

[tex]b=\sqrt{6}[/tex]

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

[tex]\frac{d^2V}{db^2}=-3b[/tex]

At  [tex]b=\sqrt{6}[/tex]

[tex]\frac{d^2V}{db^2}=-3\sqrt{6}<0[/tex]

Hence, the volume of box is maximum at [tex]b=\sqrt{6}[/tex].

[tex]h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}[/tex]

[tex]h=\frac{18-6}{2\sqrt{6}}[/tex]

[tex]h=\frac{12}{2\sqrt{6}}[/tex]

[tex]h=\sqrt{6}[/tex]

[tex]b=h=\sqrt{6}[/tex] m

Answer:

Tisco: 12 for £5.16

Azda: 12 for £5.04

Azda has the better value.

Step-by-step explanation:

Tisco: 3 for £1.29

Multiply both numbers by 4.

12 for £5.16

Azda:

4 for £1.68

Multiply both numbers by 3.

12 for £5.04

Azda has the better value.

Answer:

0.65m

Step-by-step explanation:

28cm is equal to 0.28m

37/100 is 37% of a metre so 0.37m

0.28 + 0.37 = 0.65m

Answer:

A. No, because the arcs do not have the same measure.

Step-by-step explanation:

Two arcs can be said to be congruent when the length measure of the two arcs are the same and not necessarily the degree measure. This implies that two arcs can have the same degree measure measure but their length may not be the same.

If two arcs have the same measure in one circle, therefore we can say they are congruent or if they have the same measure in congruent circles respectively, they are congruent.

In the two circles given above, although we are not told if both circles are congruent, however, since both arcs have different degree measure, both arcs cannot be congruent.

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

↦∠ 3, ∠ 2, ∠ 6, ∠ 5 are the exterior angles in this figure.

↦ They aren't located inside the figure like ∠ 1 & ∠ 4, so they are exterior angles.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

Step-by-step explanation:

The answer b

Answer:

There are 8 penguins and 6 reindeers.

Step-by-step explanation:

Since Brian, the gorilla, was planning a party for his zoo friends, and he sent his elves Jamie and Nancy into the North Pole exhibit to count the penguins and reindeer, and Jamie said there were 40 legs and Nancy said there were 14 heads To determine how many penguins and reindeer were in the exhibit, the following calculation must be performed:

Penguins: 1 head and 2 legs

Reindeers: 1 head and 4 legs

40 - (14 x 2) = X

40 - 28 = X

12 = X

12/2 = 6

14 - 6 = 8

8 x 2 + 6 x 4 = X

16 + 24 = X

40 = X

Therefore, there are 8 penguins and 6 reindeers.

Answer:

[tex]x = 5600 + 5600 * 0.042 * 1[/tex]

Step-by-step explanation:

Given

[tex]P = 5600[/tex] -- Principal

[tex]R = 4.2\%[/tex] -- Rate

[tex]T = 1[/tex] -- Time

Required

The amount (x) to be paid

This is calculated as:

[tex]x = P + I[/tex]

Where:

[tex]I = PRT[/tex]

So, we have:

[tex]x = 5600 + 5600 * 4.2\% * 1[/tex]

Express percentage as decimal

[tex]x = 5600 + 5600 * 0.042 * 1[/tex]

(c) is correct

Step-by-step explanation:

Let us take a nominal square of area 25 cm².

So, in this question, we can say that:-

a. The length of one of its sides will be less than 5 cm.

b. Its perimeter will be less than 20 cm.

Hope it helps :)

Step-by-step explanation:

area= 25cm squared

length of one side = 5cm as 5*5 =25

perimeter= 5*4= 20cm

But since the area is less than 25cm squared

we can say that the length of one side is less than 5cm and we can also say that the length of the perimeter is less than 20cm.

Hope this helps.

Solution :

The significant figure of a number are defined as the positional notation of that number which are most reliable and are absolutely necessary to represent the quantity of something.

In the context, we have to express the given numbers into three significant figures in the form of scientific notation or in the exponential form :

(i). 5590    -----    [tex]$5.59 \times 10^3$[/tex]

(ii).  0.000498   -----    [tex]$4.98 \times 10^{-4}$[/tex]

(iii) 135000  -----   [tex]$1.35 \times 10^5$[/tex]

(iv) 0.000438   -----  [tex]$4.38 \times 10^{-4}$[/tex]

Answer:

Question 1: x = 6

Question 2: Correct!

Question 3: x = 11

Question 4: Correct!

Step-by-step explanation:

Question 1:

Angle 22x - 2 DOESN'T equal 50 degrees. Only Alternate Interior Angles will equal each other. These two angles are Same Side Interior Angles, meaning if you added them together, they would equal 180 degrees.

Knowing that adding 22x - 2 and 50 will equals 180 degrees, here's how we solve for x:

First, subtract 50 from 180 to find what angle 22x - 2 will equal:

180 - 50 = 130

130 = 22x - 2

Now use basic algebra to solve for x:

130 = 22x - 2

(add 2 to both sides)

132 = 22x

(divide both sides by 22)

x = 6

Question 3:

Angle 5x + 15 DOESN'T equal 9x + 11. They make up a line, which is 180 degrees, so they are supplementary angles.

With that in mind, to solve for x, add the two equations and set it equal to 180:

5x + 15 + (9x + 11) = 180

Now use basic algebra to solve for x:

5x + 15 + 9x + 11 = 180

(add like terms)

14x + 26 = 180

(subtract 26 from both sides)

14x = 154

(divide 14 from both sides)

x = 11

Hope it helps (●'◡'●)

Answer:

6546 students would need to be sampled.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.

This means that [tex]n = 200, \pi = \frac{118}{200} = 0.59[/tex]

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].

If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?

n students would need to be sampled, and n is found when M = 0.01. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}[/tex]

[tex]0.01\sqrt{n} = 1.645\sqrt{0.59*0.41}[/tex]

[tex]\sqrt{n} = \frac{1.645\sqrt{0.59*0.41}}{0.01}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.645\sqrt{0.59*0.41}}{0.01})^2[/tex]

[tex]n = 6545.9[/tex]

Rounding up:

6546 students would need to be sampled.

Answer:

17

Step-by-step explanation:

So, this is a percentage problem.

Start off by finding how many students 0.28% is:

If 100% = 5780

0.01% = 0.578                          

Now:

0.01% = 0.578

0.28% = 16.184

The exercise tells you to round for a whole person, so 16.184 turns 17

And that's the answer!

Answer:

Step-by-step explanation:

we are given  the angles ∠5 , ∠4 , ∠3 , but with one variable,  "X"  :)

also we are told ∠AOC is bisected by OB , meaning that ∠1 = ∠2

and the EC is perpendicular to OD ,  so ∠4+∠5=90°

since we are given ∠4 & ∠5,  lets use that to solve for "X"

:)

90= x-6 + 2x+4

90= 3x -2

92 =3x

30[tex]\frac{2}{3}[/tex] ° = x

30.6666666666666666 ° = x

Answer: x=4, y=-6

Step-by-step explanation:

Answer:

2ml

Step-by-step explanation:

50mg of some potent agent has to be given every 12 hours.

there is a solution that has a concentration of that agent of 125mg/5ml

we need to administer some part of this solution, which we cannot (or should not) change in its structure.

that means the ratio of agent to overall solution stays the same, no matter how much of the solution we administer.

all we need to do is to transit the ratio of 125/5 to represent 50/x (maintaining the said ratio).

in other words, we need to find how many ml we need to administer, so that 50mg of the agent enter the body.

so,

125/5 = 50/x

125x/5 = 50

25x = 50

x = 50/25 = 2

2ml of the solution needs to be administered every 12 hours.

Answer:

There are 460 feet of wire contained on one spool.

Step-by-step explanation:

Since Aaron used ordinary electrical wire to connect the lights around the new factory, and I have ended up using 3 entire spools of wire, which totaled 1,380 feet, to determine what is the number of feet of wire contained on one spool, written as a ratio, the following calculation must be performed:

1380/3 = X

460 = X

So there are 460 feet of wire contained on one spool.

Answer:

Hereeeeeeeeeeeeeeeee