Answer: 4.236km
Explanation:
Let's define the point (x, y) as:
x = horizontal distance moved.
y = vertical distance moved.
If the plane starts in the point (0, 0) then:
"A plane travels down a runway 2750 m before it lifts off..."
At this time, the position will be:
P = (0 + 2750m, 0) = (2750m, 0).
"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."
In this case, as the angle is measured from the horizontal, the components will be:
x = 1.8km*cos(37°) = 1.438km
y = 1.8km*sin(37°) = 1.083 km
Then the new position is:
P = (2750m + 1.438 km, 0 + 1.083 km)
Let's write it using the same units for all the quantities:
we know that
1km = 1000m
Then:
2750m = (2750/1000) km = 2.750 km.
Then we can write the new position as:
P = (2.750 km + 1.438km, 1.083km) = (4.188km, 1.083km)
Now, we define the displacement as the distance between the final position and the initial position.
The distance between two points (a, b) and (c, d) is:
D = √( (a c)^2 + (b - d)^2)
In this case the points are:
(0, 0) for the initial position
(4.188km, 1.083km) for the final position.
And the displacement will be:
D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km
Which is a characteristic of a physical change? (1 point)
a
The chemical bonds in the substance are unchanged.
b
The change cannot be seen.
c
The molecules all move at the same speed.
d
The substance has reacted with another substance.
I WILL GIVE BRIANLEST I NEED HELPPP HELPP PLEASE
Answer:
solar system is the first blank
Answer:
atmosphere; solar system; rotations; energy; features; surface; solid; measurements
Explanation:
To be honest there really isn't an explanation. Hope this helps!
The head of a 245 g golf club traveling at 62 m/s just before it strikes a 48 g golf ball at rest on a tee. After the collision, the club travels in the same direction at 43 m/s. Use the law of conservation of momentum find the speed of the golf ball just after impact.
Answer:
The speed of the golf ball just after impact is 96.98 m/s
Explanation:
Given;
mass of the club, m₁ = 245 g = 0.245 kg
initial velocity of the club, u₁ = 62 m/s
mass of the golf ball, m₂ = 48 g = 0.048 kg
initial velocity of the golf ball, u₂ = 0
final velocity of the club, v₁ = 43 m/s
let the final velocity of the golf ball
Apply the law of conservation of momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.245(62) + (0.048 x 0) = 0.245(43) + 0.048v₂
15.19 = 10.535 + 48v₂
15.19 - 10.535 = 48v₂
4.655 = 48v₂
v₂ = 4.655 / 0.048
v₂ = 96.98 m/s
Therefore, the speed of the golf ball just after impact is 96.98 m/s
the object is in _________ when the vector sum of the force is acting on the object is equal to zero
Answer:
Equilibrium
Explanation:
An object is in equilibrium when the vector sum of the force acting on the object is equal to zero.
A body in equilibrium is at state of rest of rest or in motion with no external force acting on it.
The resultant of all forces acting on the body is zero. In this case there is no net force and the body will be at rest.Where do we get the matter for us to grow?
Answer:
We get mater to grow by eating food, drinking water and breathing in oxygen
Explanation:
Growing shows an increase in size or mater of a living organism over time, such that the present state of a living organism has an increased amount of matter or inertia than its previous status.
However, by the law of conservation of mater, the amount of mater in a closed system is constant, therefore, we have that for us to grow, new mater must be ingested, which comes from what we take into our bodies
Therefore, we get mater to grow by eating food, drinking water and breathing in oxygen
3. Light travels from the Sun to Earth in 8.3 min. Given that the speed of light is 3.00108 m/s, what is the distance in meters between the Sun and Earth?
Answer:
13
Explanation:
13.0120481928 it is the distance
A body fell freely for 6s.From what height did it start to fall and what was it's speed at the end of the fall?
Answer:
Free fall / falling speed equations1. The force of gravity, g = 9.8 m/s2 Gravity accelerates you at 9.8 meters per second per second. ...
2. Time to splat: sqrt ( 2 * height / 9.8 ) ...
3. Velocity at splat time: sqrt( 2 * g * height ) ...
4. Energy at splat time: 1/2 * mass * velocity2 = mass * g * height.
Explanation:
(FREE FALL) An object falls from an unknown height, crosses last 196m in 4s. Find the falling time and height.
Answer: An object is dropped from a height of 75.0 m above ground level.
Explanation: I hoped that helped !
Water is boiled. The resulting steam is blown again huge turbine blades. The turbine blades spin in a magnetic field, producing electricity. The electricity is used to light a lamp. Describe the energy conversions involved.
Answer:
Explanation:
A turbine is a mechanical device that can be used for the conversion of one form of energy into another.
The boiled water generates thermal energy which is blown against a huge turbine blades. The thermal energy is converted to mechanical energy (which drives the blades of the turbine), and sound energy in the turbine. The spinning blades thereby cut the magnetic field as they rotates inducing electric current (Fleming's left hand rule), thus electrical energy is produced.
The electrical energy is now converted to light energy and heat energy by the lamp.
please help!!!!!!!!!!
Answer:
D
Explanation:
I might be wrong but if I was you i would go with D
1 kg ball and a 9 kg ball have the same Ex. Compare
their speeds.
Answer:
The speed of 1 kg ball is 3 times of the speed of 9 kg ball.
Explanation:
It is given that, 1 kg ball and 9 kg ball have the same kinetic energy.
We need to compare their speeds.
The kinetic energy of an object is given by :
[tex]K=\dfrac{1}{2}mv^2[/tex]
Where
m is mass and v is speed
As kinetic energy is same. So,
[tex]m_1v_1^2=m_2v_2^2\\\\\dfrac{v_1^2}{v_2^2}=\dfrac{m_2}{m_1}\\\\\dfrac{v_1^2}{v_2^2}=\dfrac{9}{1}\\\\\dfrac{v_1}{v_2}=\dfrac{3}{1}\\\\v_1=3v_2[/tex]
So, the speed of 1 kg ball is 3 times of the speed of 9kg ball.
7
The diagram shows a wooden beam PQ, of negligible weight, which is attached to a wall by a
hinge at P and kept in a horizontal position by a vertical rope attached at Q.
The beam is 3.0m in length.
A man of weight 800 N walks along the beam from P to Q.
wall
man
-rope
beam
Р
Q
hinge
1200
What is the distance of the man from P when the tension in the rope at Q becomes equal to
500N?
Gadifada
Answer:
Explanation:
Taking moment of forces about the hinge ,
moment of weight of man = 800 x p where p is his distance of man from hinge , in clockwise direction .
moment of tension force in rope in anticlockwise direction
= 500 x 3
For rotational balancing
800 x p = 500 x 3
p = 1.875 m .
From the principle of moment, the distance of the man from P is 1.9 m
From the question, below are the given parameters;
The Length of the beam = 3mThe weight of the man = 800 NThe tension in the string = 500 NAs the man walks toward the string, the tension on it will act downward, while the normal reaction on the man will act upward.
From the principle of moment,
Clockwise moment = anticlockwise moment
Let us take our moment from point P. That is,
500 x 3 = 800 x d
Make d the subject of formula
d = 1500 / 800
d = 1.875 m
Therefore, the distance of the man from P when the tension in the rope at Q becomes equal to 500N is 1.9 meters approximately.
Learn more about moment here: https://brainly.com/question/6278006
A hot-air balloon is ascending at a rate of 7.5m/s when a passenger drops a camera. If the camera is 27m above the ground when its dropped, how much time does it take for the camera to reach the ground? What is its velocity just before it lands?
Answer:
v_{f}=21.75[m/s] (velocity just before it lands)
t = 2.98 [s]
Explanation:
The key to solving this problem is the initial velocity since when the camera falls it is moving up, we will take this velocity as negative and the acceleration gravitation down as positive.
We will use the following equation of kinematics to solve this problem.
[tex]V_{f}^{2} =V_{o}^{2}+2*g*y[/tex]
where:
Vf = final velocity [m/s²]
Vo = initial velocity = 7.5 [m/s]
g = gravity acceleration = 9.81 [m/s²]
y = elevation = 27 [m]
[tex]v_{f}^{2} = - (7.5)^{2} +(2*9.81*27)\\ v_{f}^{2} = 473.5\\v_{f}=\sqrt{473.5}\\v_{f}=21.75[m/s][/tex]
Now using the following equation of kinematics, we can calculate the time that the fall lasts.
[tex]v_{f}=v_{o}+g*t[/tex]
[tex]21.75 = -7.5 +9.81*t\\9.81*t = 29.25\\t = 2.98[s][/tex]
The strength of force is expressed by a. Weight b.mass
Answer:
Weight.
Explanation:
If a body is sliding on a inclined plane of angle 30° angle of friction is
Answer: don´t know
Explanation:
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What effect do you think thermal energy and the transfer of heat in Earth’s interior have on the surface of the planet?
Answer:
I love your pfp also! Put the image i put in full screen and theres your answer
please help!!!!!!!!!!
Answer:
the line b aka the option d
Explanation:
If a book has a mass of 3 kg, what is the book's weight in N?
Answer:
29.4 N
Explanation:
F = ma
F = (3 kg) (9.8 m/s²)
F = 29.4 N
Is it true or false that A proton traveling to the right moves in between the two large plates. A vertical electric field, pointing downwards with magnitude 3.0 N/C, is produced by the plates, the field points is in the same direction on the proton as the force felt by a positive test charge
Answer:
False
Explanation:
In the question it is given that a proton travels in the right moves in between the two plates. An electric field that is pointing in the vertically upward direction has magnitude of 3 N/C. The electric field is produced by the plates.
Now from here we can conclude that the direction of the force acting on the proton when the proton is in between the plates acts in the downward direction. While the electric field lines points in the upward direction. Thus the electric point will not be in the direction of the force that acts on the proton.
A car’s velocity changes from 35 m/s to stopped in 13 seconds. Calculate
acceleration.
Answer:
Acceleration = 3m/s^2
Vf= 0 Vi =35m/s t= 13s
Explanation:
[tex]Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2[/tex]
The process repeats, producing a
within the gas.
Please help asap
Answer:
Energy materials are traditionally made with a linear approach—materials are taken, products are made, and when they expire or break, they are disposed of. The process repeats.
Explanation:
This may help I don't know
A 25 N force is used to push a box across a floor against a frictional force of 14 N. The box accelerates from rest to a speed of 4 m/s in 16 s. What is the mass of the box?
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Which of the following is a derived physical quantity?
A. Time
B. Mass
C. Length
D. Volume
Jane is a crime scene investigator. She wants to reveal small particles with high contrast. So, she positions the forensic lamp at a very low angle against the surface. Which technique is she using? A. fluorescence B. oblique lighting C. absorption D. spectroscopy E. stereoscopy
Answer:
Pretty sure it's B. Oblique Lighting
Explanation:
A. is clearly wrong, C. is also clearly wrong, D and E both have nothing to do with lighting, Oblique Lighting is defined as "using a light source positioned at a low angle. Oblique lighting is usually used to show detail by creating shadows on the surface of the evidence." Hope this helps.
HELPP ITS DUE IN 5 MINUTES FREE BODY DIAGRAMS
Answer:
I think it's part c . but sorry if its wrong
What is the mass of a truck that has a momentum of 10,000 kg*m/s and a velocity of 4m/s North?
Answer:
2500 kg
Explanation:
m=p/v
?=10000kgm/s/4m/s
?=2500 kg
The atomic mass of an element is of that element
Answer:
The atomic mass of an element is the average mass of the atoms of an element, according to google. Sum of protons and neutrons in nucleus is the mass number and multiply by 1 amu gives you the mass of the atom
what change should a rahul make
Answer:
Whats a rahul?
Explanation:
I'll edit this once I know :)
Answer: its B
Explanation: just took the quiz
How long does it take for an 8 kg pumpkin to hit the ground if dropped from a height of 55 m.
Answer:
t = 3.35 s
Explanation:
It is given that,
Mass of a pumpkin, m = 8 kg
It is dropped from a height of 55 m
We need to find the time taken by it to hit the ground.
Initial velocity of the pumpkin, u = 0
Using second equation of motion to find it as follows :
[tex]h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2(55)}{9.8}} \\\\t=3.35\ s[/tex]
So, it will take 3.35 seconds to hit the ground.
A 20-kg dog on ice skates is accelerating at 2 m/s2. What is the net
force on the dog?
Answer:
22
Explanation: