Answer:
Explanation:
Given that:
[tex][\sigma] = \left[\begin{array}{cc}800&300\\ \\300&-400\end{array}\right] (MPa)[/tex]
[tex][\sigma] = \left[\begin{array}{cc}\sigma_{xx}&\sigma_{xy}\\ \\\sigma_{yx}&\sigma_{yy}\end{array}\right][/tex]
Using Determinant method
The principal stress is the maximum or minimum normal stress acting on any plane. For the 2D stress system, the 2-principle plane always carries zero shear stress.
For principal stress [tex]( \sigma_1, \sigma_2)[/tex]
[tex]\sigma_{1,2} = \dfrac{\sigma_x+ \sigma_y}{2} \pm \sqrt{( \dfrac{\sigma_x - \sigma_y}{2} )^2 + \sigma^2_{xy}}[/tex]
[tex]\sigma_{1} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]
[tex]\sigma_{1} = \dfrac{400}{2} \pm \sqrt{ (600)^2 + (300)^2}[/tex]
[tex]\sigma_{1} = 200+ 670.82 \\ \\ \sigma_{1} = 870.82 \ MPa[/tex]
[tex]\sigma_{2} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]
[tex]\sigma_{2} = 200- 670.82 \\ \\ \sigma_{1} = - 470.82 \ MPa[/tex]
According to Mohr's circle;
Mohr's circle is the locus provided that the position of the normal stress and the shear stress is acting on any plane.
Center = (a,0)
[tex]a = \dfrac{\sigma_{x}+\sigma_{y}}{2}[/tex]
[tex]a = \dfrac{800+(-400)}{2}[/tex]
a = 200 MPa
radius (r) = [tex]\sqrt{ (\dfrac{\sigma_{x}-\sigma_{y}}{2})^2 + \sigma^2 _{xy}}[/tex]
[tex]=\sqrt{ (\dfrac{800-(-400)}{2})^2 + (300)^2}[/tex]
[tex]=\sqrt{ (600)^2 + (300)^2}[/tex]
r = 670.82 MPa
[tex]\sigma_1 = a +r \\ \\ \sigma_1 = 200 + 670.82 \\ \\ \sigma_1 = 870.82 \ MPa[/tex]
[tex]\sigma_2 =-(r-a)[/tex] (it is negative because of the negative x-axis)
[tex]\sigma_2 =670.82 - 200 \\ \\ \sigma_1 = 470.82 \ MPa[/tex]
[tex]\tau_{max} = radius \ of \ Mohr's \ circle[/tex]
[tex]\tau_{max} = 670.82 \ MPa[/tex]
determine the steady state temperature distribution between two concentric spheres with radii 1 and 4
Answer:
Hence, the steady state temperature distribution between concentric spheres with radii 1 and 4 is:
u = [tex]\frac{C1}{r }[/tex] + C2
u = [tex]\frac{\frac{-320}{3} }{r}[/tex] + [tex]\frac{320}{3}[/tex]
Explanation:
Solution:
Note: This question is incomplete and lacks necessary data to solve this question. But I have found a similar question and will try to solve it.
This question has this following part missing:
"If the temperature of the outer sphere is maintained at 80 degrees and the inner sphere at 0 degrees.
Now, this question is complete.
Let's find out the steady state temperature distribution.
As, we know the spherical symmetric heat equation:
[tex]\frac{du}{dt}[/tex] = [tex]\frac{k}{r^{2} }[/tex] [tex]\frac{D}{Dr}[/tex] ([tex]r^{2}[/tex] [tex]\frac{Du}{Dr}[/tex])
Where, small (d) represents the partial differentiation and Capital D represents simple derivative.
And the ordinary differential equation (ODE) for steady state temperature distribution is:
[tex]\frac{k}{r^{2} }[/tex] [tex]\frac{D}{Dr}[/tex]([tex]r^{2}[/tex] [tex]\frac{Du}{Dr}[/tex]) = 0
So it can be said that:
[tex]r^{2}[/tex] [tex]\frac{Du}{Dr}[/tex]
Consequently,
[tex]\frac{Du}{Dr}[/tex] = [tex]\frac{C1}{r^{2} }[/tex]
Taking derivative of the above equation we get:
u = -[tex]\frac{C1}{r }[/tex] + C2
Solution of the ordinary differential equation
u = [tex]\frac{C1}{r }[/tex] + C2 (Consuming the negative sign into C1 constant)
As, it is given in our question that our boundary conditions are: 1 and 4
So,
Putting the boundary conditions into the variable (r) to find the constants we get:
u1 = [tex]\frac{C1}{1} }[/tex] + C2 = 0 (degrees)
u1 = C1 + C2 = 0 (degrees) equation (1)
Similarly,
u4 = [tex]\frac{C1}{4}[/tex] + C2 = 80 (degrees)
u4 = [tex]\frac{C1}{4}[/tex] + C2 = 80 (degrees) equation (2)
Solving for C1, we get:
Equation 1 - Equation 2
(C1 - C2 = 0) - ([tex]\frac{C1}{4}[/tex] + C2 = 80)
[tex]\frac{-3}{4}[/tex]C1 = 80
Solving for C1
C1 = -[tex]\frac{320}{3}[/tex]
With the help of value of C1, we get value of C2
Put the value of C1 in equation (1) to get value of C2
C1 + C2 = 0
-[tex]\frac{320}{3}[/tex] + C2 = 0
Solving for C2
C2 = [tex]\frac{320}{3}[/tex]
Hence, the steady state temperature distribution between concentric spheres with radii 1 and 4 is:
u = [tex]\frac{C1}{r }[/tex] + C2
Plugging in the values of C1 and C2
u = [tex]\frac{\frac{-320}{3} }{r}[/tex] + [tex]\frac{320}{3}[/tex]
this is it dont anwser this is for my other account
Answer:
thanks for the poiunts
Explanation:
Consider a 20 cm thick granite wall with a thermal conductivity of 2.79 W/mK. The temperature of left surface is 50°C and right surface is exposed to 22°C air with a convection heat transfer of 15W/m^2K. Neglecting radiation heat transfer, determine the heat flux through the wall.
6. What is the resistance of a curling iron that draws 12 A of current on a 120 V circuit?
Answer:
10 ohms Ω
Explanation:
V = IR
120 = I(12)
120/12 = 10Ω
A train starts from rest at station A and accelerates at 0.6 m/s^2 for 60 s. Afterwards it travels with a constant velocity for 25 min. It then decelerates at 1.2 m/s^2 until it is brought to rest at station B. Determine the distance between the stations.
Answer:
The distance between the station A and B will be:
[tex]x_{A-B}=55.620\: km[/tex]
Explanation:
Let's find the distance that the train traveled during 60 seconds.
[tex]x_{1}=x_{0}+v_{0}t+0.5at^{2}[/tex]
We know that starts from rest (v(0)=0) and the acceleration is 0.6 m/s², so the distance will be:
[tex]x_{1}=\frac{1}{2}(0.6)(60)^{2}[/tex]
[tex]x_{1}=1080\: m[/tex]
Now, we need to find the distance after 25 min at a constant speed. To get it, we need to find the speed at the end of the first distance.
[tex]v_{1}=v_{0}+at[/tex]
[tex]v_{1}=(0.6)(60)=36\: m/s[/tex]
Then the second distance will be:
[tex]x_{2}=v_{1}*1500[/tex]
[tex]x_{2}=(36)(1500)=54000\: m[/tex]
The final distance is calculated whit the decelerate value:
[tex]v_{f}^{2}=v_{1}^{2}-2ax_{3}[/tex]
The final velocity is zero because it rests at station B. The initial velocity will be v(1).
[tex]0=36^{2}-2(1.2)x_{3}[/tex]
[tex]x_{3}=\frac{36^{2}}{2(1.2)}[/tex]
[tex]x_{3}=540\: m[/tex]
Therefore, the distance between the station A and B will be:
[tex]x_{A-B}=x_{1}+x_{2}+x_{3}[/tex]
[tex]x_{A-B}=1080+54000+540=55.620\: km[/tex]
I hope it helps you!
Block A has mass of mA = 58kg and rests on a flat surface. The coefficient of static friction between the block and the surface is 0.300. The coefficient of static friction between the rop and the fixed peg B is 0.310. The width of the block is d = 0.290m. Find the greatest mass, mC, that weight C can have such that block A does not move.
Answer:
The greatest mass, that the weight C can have such that block A does not move is approximately 23.259 kg
Explanation:
The given parameters are;
The mass of the block A= 58 kg
The coefficient of static friction between the block and the surface, [tex]\mu _s[/tex] = 0.300
The coefficient of static friction between the rope and the fixed peg, B [tex]\mu _B[/tex] = 0.310
Let T represent the tension in the rope
Therefore, when the rope is static, T = The normal reaction at the peg, B, [tex]N_B[/tex]
The angle of inclination of the rope holding the block A = arctan(3/4) ≈ 36.87°
The length of the rope = √(0.4² + 0.3²) = 0.5
∴ sin(θ) = 3/5 = 0.6
cos(θ) = 4/5 = 0.8
The vertical component of the tension in the rope = T × sin(θ) = 0.6·T
The horizontal component of the tension in the rope = T × cos(θ) = 0.8·T
The friction force = μ×(W - 0.6·T) = 0.300×(58×9.8 - 0.6·T) = 170.52 - 0.18·T
The block will start to move when we have;
The horizontal component of the tension in the rope = The friction force
∴ 0.8·T = 170.52 - 0.18·T
0.8·T + 0.18·T = 170.52
0.98·T = 170.52
T = 170.52/0.98 = 174
Therefore, the tension in the rope = T = 174 N = The normal reaction at the peg, B [tex]N_B[/tex]
The frictional force at the peg, [tex]F_B[/tex] = [tex]\mu _B[/tex] × [tex]N_B[/tex] = 0.310 × 174 N = 53.94 N
The weight of the mass, [tex]m_c[/tex], [tex]W_c[/tex] = The frictional force at the peg, [tex]F_B[/tex] + The tension in the rope
∴ The weight of the mass, [tex]m_c[/tex], [tex]W_c[/tex] = 53.94 N + 174 N = 227.94 N
Weight, W = Mass, m × The acceleration due to gravity, g, from which we have;
m = W/g
Where;
g = 9.8 m/s²
∴ [tex]m_c[/tex] = [tex]W_c[/tex]/g = 227.94 N/(9.8 m/s²) ≈ 23.259 kg.
The greatest mass, that the weight C can have such that block A does not move = [tex]m_c[/tex] ≈ 23.259 kg.
If a shear stress acts in one plane of an element, there must be an equal and opposite shear stress acting on a plane that is
Answer:
90 degrees
Explanation:
In the case when the sheer stress acts in the one plane of an element so it should be equal and opposite also the shear stress acted on a plan i.e. 90 degrees from the plane
Therefore as per the given situation it should be 90 degrees from the plane
hence, the same is to be considered and relevant too
The gross weight of a two-place Piper Cherokee is 2000lb and its wing area is 160 ft^2. What is its wing loading
Answer:
[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]
[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]
Explanation:
Given
[tex]Weight=2000lb[/tex]
[tex]Area = 160ft^2[/tex]
Required
Determine the wing loading (W)
Wing loading is calculated using:
[tex]W = \frac{Weight}{Area}[/tex]
Substitute values for Weight and Area
[tex]W = \frac{2000lb}{160ft^2}[/tex]
[tex]W = 12.5\ lb/ft^2[/tex]
The answer can also be converted to N/m^2
[tex]1\ lb = 4.4482216153N[/tex]
[tex]1ft^2 = 0.092903m^2[/tex]
So, we have:
[tex]W = \frac{12.5 * 4.4482216153N}{0.092903m^2}[/tex]
[tex]W = \frac{55.6027701912N}{0.092903m^2}[/tex]
[tex]W = 598.503N/m^2[/tex]
Hence, the wing loading is:
[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]
[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]
Prepare 250 cm3 2M NAOH: molar mass M = 40g/mol. calculate substance mass
Answer: The mass of the substance is 20 g
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml = 250 ml [tex](1cm^3=1ml)[/tex]
moles of [tex]NaOH[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{40g/mol}[/tex]
Now put all the given values in the formula of molality, we get
[tex]2=\frac{x\times 1000}{40\times 250}[/tex]
[tex]x=20g[/tex]
Therefore, the mass of the substance is 20 g
Assuming an n-type transistor with Vds of 1.8V and Vt of 0.7V, find the ranges of Vgs to put the transistor in cutoff, linear, and saturation regions.
Answer:
1. Vgs<0.7
2. Vgs>2.5
3. 0.7<vgs<2.5
Explanation:
The information below was used to answer to answer this question.
Vds = 1.8V
Vt = 0.7V
1.
The cutoff region
Vgs < Vt
= Vgs < 0.7 volts
This the cut off region
2.
Linear region
Vds < Vgs - Vt
When we put in the values
1.8V < Vgs - 0.7V
1.8V+0.7V < Vgs
2.5Volts < Vgs
This is the linear region when Vgs > 2.5 volts
3.
The saturation region
Vds > Vgs - Vt
When we put in the values we have:
1.8V > Vgs - 0.7V
2.5V > Vgs
And 0.7 < Vgs
Then the saturation region is:
0.7V < Vgs < 2.5 V
Visual interpretations when driving are two things: first, what the driver sees around him or her passively, so it is what the eyes receive, and the second is:
Choose one
A. How the driver understands and processes the things his or her eyes receive.
B. How the driver disregards these things.
C. How the driver violates these things whenever he can.
D. How the driver appreciates all the colors he sees.
Answer:
A. How the driver understands and processes the things his or her eyes receive.
Explanation:
When driving, visual interpretation occurs in two things;
What the driver sees around him or her passively, mainly what is received by the eyeHow the driver understands and processes the things his or her eyes receiveProper vision is vital while driving. There is the central vison and the peripheral vision. The central vision is what the driver sees in front through the windshield straight ahead. The Peripheral vision is what is seen at the corners of the eyes.
In driving, visual interpretations are important as it entails what the driver sees and A. How the driver understands and processes the things his or her eyes receive.
It's important for drivers to have proper vision when driving. A driver should be able to interpret what the driver sees around him or her passively.
Also, it's important for the drive to be able to understand and processes the things his or her eyes receive. This is vital in order to prevent accidents.
Learn more about driving on:
https://brainly.com/question/24606937
The hazard communication standard requires employers to do all of the following except
A.) Obtain SDS for hazardous in toxic substances
B.) Train employee on how to safely use and obtain information about the hazardous substances in their workplace
C.) Label containers of hazardous
D.) prepare and post a list of employees who handle hazardous and toxic substances in the workplace
Answer:D
Explanation:
All the options given regarding the hazard communication standard are correct except option D "prepare and post a list of employees who handle hazardous and toxic substances in the workplace".
The main requirements of employers that use hazardous chemicals are:
• ensure that chemicals are properly labelled.
• provide safety data sheets.
• train employees.
• create a written hazard communication program.
It should be noted that preparing and posting a list of employees who handle hazardous and toxic substances in the workplace is incorrect.
Therefore, the correct option is D.
Read related link on:
https://brainly.com/question/17611643
how many robots does bailey nursery own
Answer:
The Bailey family has flourished during its business’ 110-year history. But Bailey Nurseries’ leaders still operate with the belief that the family doesn’t always know best. The company has grown from a one-man operation selling fruit trees and ornamental shrubs to one of the largest wholesale nurseries in the United States, thanks to insights from those who are family and those who aren’t.
“For a business to thrive, you have to ask for outside help,” says Terri McEnaney, president of the Newport-based company and a fourth-generation family member. “We get an outside perspective through family business programs, advisors and our board, because you can get a bit ingrained in your own way of thinking.”
When Bailey Nurseries chose its current leader in 2000, it brought in a facilitator who gathered insights from key employees, board members and owners. Third-generation leaders (and brothers) Gordie and Rod Bailey picked Rod’s daughter McEnaney, who had experience both inside and outside the company.
Explanation:
What percentage is 122 out of 222?
Answer:
Divide the first number by the second.
Explanation:
~55%
Answer:
About 54-55% It depends on if you need to round.
Explanation:
Need help tryna get a good grade
Answer:
C - Prototype model
Explanation:
I believe it's C but Hope this Helps!
What does abbreviation vom stand for
Answer:
vom = Volt Ohm Meter
Explanation:
(Giving Brainliest to 1st!)Which organelle acts as a temporary storage center, containing water, waste, and other products?
A. cell membrane
B. cytoplasm
C. vacuole
D. nucleus
6 A square silicon chip (k 150 W/m K) is of width w 5 mm on a side and of thickness t 1 mm. The chip is mounted in a substrate such that its side and back surfaces are insulated, while the front surface is exposed to a coolant. If 4 W are being dissipated in circuits mounted to the back surface of the chip, what is the steady-state temperature difference between back and front surfaces
Answer:
1.1⁰C
Explanation:
Width W = 5mm = 0.005
Thickness t = 1 mm = 0.001
K = thermal conductivity = 150W/m.K
P = q = heat transfer rate = 4W
We are to find the steady state temperature between the back and the front surface
We have to make these assumptions:
1. There is steady state conduction
2. The heat flow is of one dimension
3. The thermal conductivity is constant
4. The heat dissipation is uniform
We have:
∆t = t*P/k*W²
= (0.001m x 4W)/150x(0.005)²
= 0.004/0.00375
= 1.06667
This is approximately,
1.1⁰C
Thank you!
Technician A says that the refractometer reading is determined at the point of the scale where the dark and light areas meet. Technician B says that the reading is determined by where a dial points on a scale. Who is correct
Answer:
Technician B says that the reading is determined by where a dial points on a scale.
Explanation:
A refractometer is a devise used by scientists to gauge a liquids index of refraction.
The refractive index of a liquid is the ratio of light velocity of a specific wavelength in air to its velocity in the substance in evaluation.
The steps of reading a measurement are;
point the front of the refractometer towards the light source and view into the eyepieceYou will see the line outlined at a different point on the refractometer's internal indexRead the point on the index at which the line falls
List 3 specific things you can do with a Tape measure (not just measure things)
Answer:
See how many inches are in a foot
measure width and hight of places
Nail grabbing
Explanation:
What are the environmental factors that cause the formation of rust?
Air
A Friction
B )Water
C )Iron Alloys
D )A, B and C
E )A, B, C and D
SP2
Copyright 2021 S/P2. All Rights Reserved.
Answer:
AirWaterIron AlloysExplanation:
Rust is quite simply hydrated Iron oxide because it is as a result of iron allows coming into contact with oxygen(air) and water.
The resulting reaction gives off rust as a product. The chemical reaction is:
4Fe + 3O₂ + 6H₂O → 4Fe(OH)₃.
You can see from above how rust is formed from Iron alloys, Oxygen and water.
As iron is a widely used components in the production of many things such as cars, rust presents a problem because in dissolving away iron, the object produced is compromised and this can lead to serious consequences if left unchecked.
The is the area where filler metal intersects the base metal and extends the furthest into the weld joint.
Answer:
Weld root
Explanation:
Weld root is the point where the back of a weld intersects with the base metal surfaces.
The weld root determines the penetration of the weld and the fusion to form a joint that is rigid.
IF YOUR VEHICLE BREAKS DOWN, YOU SHOULD?
Answer:
1. TURN ON YOUR HAZARD/EMERGENCY LIGHTS
Turn on your hazard lights to warn other drivers as soon as you sense something's wrong. Keep them on until help arrives, recommends the National Motorists Association (NMA).
2. SLOW DOWN AND PULL OFF THE ROAD
Aim for the right shoulder of the road. Consumer reports recommends that you pull over to a safe, flat location that is as far away from moving traffic as possible.
3. TURN YOUR WHEELS AWAY FROM THE ROAD AND PUT ON THE EMERGENCY BRAKE
The California Department of Motor Vehicles (DMV) recommends pulling your emergency brake, sometimes called the parking brake. If you have to park on a hill or slope, turn the car's wheels away from the road to help prevent the care from rolling into traffic, says the California DMV.
4. STAY IN YOUR VEHICLE
If you're on a highway or crowded road, the Insurance Information Institute (III) recommends that you avoid getting out of your vehicle to look at the damage or fix a mechanical problem. If you need to get out of the car, get your vehicle to a safe place and make sure the road around you is completely clear. If you're stopped on the right-hand side of the road, get out through the passenger-side door.
5. BE VISIBLE
Once you're safely out of the vehicle, prop up your hood to let other drivers know they should proceed with caution. This will alert other drivers that you're broken down, according to the NMA.
6. SET UP FLARES OR TRIANGLES
Place flares or triangles with reflectors behind your car to alert other drivers to the location where you've stopped, says the III.
7. CALL FOR HELP
Call or use an app to get a tow truck, mechanic or roadside assistance to come help. your insurance company or other provider who may be able to help. If you're in an emergency situation or are not sure who to contact, call 911 or the local police for help.
Hope this helps :)
. Assuming an n-type transistor with Vds of 1.8V and Vt of 0.7V, find the ranges of Vgs to put the transistor in cutoff, linear, and saturation regions.
Answer:
1. Cut off region: Vgs < 0.7 volts
2. Linear region: Vgs > 2.5
3. Saturation region: 0.7 < Vgs < 2.5
Explanation:
This question has provided us with these details
Vds = 1.8V
Vt = 0.7V
1. To get The cutoff region
Vgs < Vt
Such that when we put in the value, we have:
Vgs < 0.7 volts
This gives us the cut off region
2. The we get the Linear region using this formula:
Vds < Vgs - Vt
After we put in the values;
1.8V < Vgs - 0.7V
Such that
1.8V + 0.7V < Vgs
2.5V < Vgs
This is therefore the linear region of the transistor when Vgs > 2.5 volts
3. We get The saturation region using
Vgs < Vt and
Vds > Vgs - Vt
When we put in the values we have:
Vgs < 0.7V and
1.8V > Vgs - 0.7V
1.8V+0.7V > Vgs
2.5V > Vgs
Then our saturation region would be
0.7V < Vgs < 2.5 V
if citrus overlord is 200 (I'm offering for a lucid leaf) and shiny eternal contrast is 250, 450 so far and I'm also last thing offering for lucid (which is 100 secret value and I'm offering in shiny value and Lucid's shiny value is 500 but gets op's because it's a secret pet) is a shiny dark omen which is 100, I'm offering 550 for 500 but gets op's, w or l, I think w.
Answer: I'm pretty sure your taking a W.
your getting a W, lucid isn't that bad to trade, you can probably flip lucid for more shiny's and getting a better offer because omen has bad demand and you can tell someone to switch it for something better you can flip lucid and get better pets ok so accept and trade lucid unless you wanna keep it.
Explanation:
Answer:
gg's if you did it cause w
Explanation:
For the following production environments, indicate whether the preferred production system is more likely to be a job shop (process layout), production line (product layout), batch process (group technology layout), or hybrid. Provide support for your answer.
a. Manufacturer of Clothes: makes many styles (shirts, pants, coats, rain jackets, etc.) and sells to small specialty stores.
b. Manufacturer of Gaskets: makes styles for 4-5 engine blocks: sells to GM and Ford (i.e., high volume).
c. Independent Automobile Service Shop: body work, general service, engine repair, serving many makes of automobiles.
d. Producer of Pharmaceutical Drugs: make approximately 50-75 drugs in tablet form: sell to pharmacies nationwide.
Answer:
A) Batch shop production
B) Batch shop production
C) Job shop production
D) production line
Explanation:
A)The preferred production system here will be Batch shop production because the manufacturer produces different styles of clothing and sells to small specialty stores hence producing in Batches can help meet up the needs
B) The preferred production system here will be Batch shop production because the manufacturer produces Gaskets and they are of different styles hence he needs to produce them in batches
C) Job shop production
D) production here is streamlined to a particular ( tablet form ) hence the production system here would be a Production line system of production
How are deltas formed?
erosion of softer rock
connection of channels
deposition from flow into a lake or an ocean
creation of large, flat areas by flooding deposits
Answer:
It is created from deposition from flow into a lake or an ocean like the Missisippi delta
Explanation:
Answer:
C: deposition from flow into a lake or an ocean
Explanation:
deposition from rivers creates a variety of features, delta deposits created by flow into lake or ocean, is one of them.
Vacancy diffusion statement refer to that a mechanism that
atom at lattice traveled to a vacant latblèe
• True
• False
Answer:
true
Explanation:
The Jones family paid
$
253
in August for electricity. The September bill was
21
%
lower.
How much was the September bill?
Answer:
$199.87
Explanation:
Just take $253 times 0.21 to get $53.13. This is how much lower the bill was. Next take 253 - 53.13 to get 199.87, which is the total bill amount for September.
What happens to the amperage draw of a condensing unit on a split AC system if the liquid line is restricted
Answer:
The amperage draw of the condensing unit will be low.
Explanation:
A condensing unit is made up of a compressor and condenser, while an evaporating unit is made up of an evaporator coil.
A split AC system is a type of air conditioner system that has a condensing unit which is placed separately from the evaporative coil unit. Then the two units are connected to each other via a copper tube containing refrigerants.
The liquid line connects the condenser to the evaporator, and if this liquid line is restricted, the amp consumed by the condensing unit will be low.