A piece of silver metal weighting 194.3 g is placed in a graduated cylinder containg 242.0 ml of water.the volume of water now reads 260.5 ml. calculate the denstyof the metal​

Answers

Answer 1

Answer:

10.50 g/mL

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

volume = final volume of water - initial volume of water

volume = 260.5 - 242 = 18.5 mL

We have

[tex]density = \frac{194.3}{18.5} \\ = 10.5027[/tex]

We have the final answer as

10.50 g/mL

Hope this helps you


Related Questions

11)
B.
A.
D.
Which position represents spring in the southern hemisphere?
A)
А
B)
B
C)
С
D)
D

Answers

Answer:

Cccccccccccccccccccccccccccccccccccccccccccc

Why is it important to have control???

Answers

Answer:

A control is important for an experiment because it allows the experiment to minimize the changes in all other variables except the one being tested.

Explanation:

do u mean that kind of control

How many grams are in 4.7 moles of Na2O?

Answers

Answer:

290 g Na₂O

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisExplanation:

Step 1: Define

4.7 mol Na₂O

Step 2: Identify Conversions

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol

Step 3: Convert

Set up:                                [tex]\displaystyle 4.7 \ mol \ Na_2O(\frac{61.98 \ g \ Na_2O}{1 \ mol \ Na_2O})[/tex]Multiply:                              [tex]\displaystyle 291.306 \ g \ Na_2O[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

291.306 g Na₂O ≈ 290 g Na₂O

what's the pH of a solution composed of 0.2 moles of NH3 and 0.15 moles of nh4cl​

Answers

Answer:

[tex]pH=4.63[/tex]

Explanation:

Hello!

In this case, since the ionization of ammonia, which is a weak base, is written as:

[tex]NH_3+H_2O\rightleftharpoons NH_4^++OH^-[/tex]

We can see that the ammonium ion is the conjugate acid whereas the hydroxide ions the conjugate base; that is why we use the Henderson-Hasselbach equation to compute the pH, given the pKb of ammonia 4.75:

[tex]pH=pKb+log(\frac{[conj\ acid]}{[base]} )[/tex]

In such a way, for the given moles of ammonia, base, and those of ammonium chloride, conjugate acid form, we obtain:

[tex]pH=4.75+log(\frac{0.15}{0.2} )\\\\pH=4.63[/tex]

Best regards!

For the reaction between aqueous solutions of acetic acid (CH3COOH) and barium hydroxide, Ba(OH)2, write

Answers

Answer:

See explanation.

Explanation:

Hello!

In this case, since we are asked to note down the complete molecular equation, complete ionic equation and the net ionic equation for the reaction between acetic acid (weak acid) and barium hydroxide (strong base), we proceed as shown below:

- Complete molecular equation:

[tex]2CH_3COOH(aq)+Ba(OH)_2(aq)\rightarrow Ba(CH_3COO)_2(aq)+2H_2O(l)[/tex]

- Complete ionic equation: in this case, since acetic acid is a weak one, it is not ionized, so we do this:

[tex]2CH_3COOH(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow Ba^{2+}(aq)+2CH_3COO^-(aq)+2H_2O(l)[/tex]

- Net ionic equation: in this case, we cancel out the barium ions as they are the spectators one because they are present at both reactants and products:

[tex]2CH_3COOH(aq)+2OH^-(aq)\rightarrow 2CH_3COO^-(aq)+2H_2O(l)\\\\CH_3COOH(aq)+OH^-(aq)\rightarrow CH_3COO^-(aq)+H_2O(l)[/tex]

Best regards!

d. Calculate the initial reaction rate that would be seen in a solution in which [BF3] is 5.0 x10 -1M and [NH3] is 2.0 x10 -2 M

Answers

Answer:

[tex]r=0.0341\frac{M}{s}[/tex]

Explanation:

Hello!

In this case, considering the given table, we are able to represent the symbolic rate law as shown below:

[tex]r=k[BF_3]^m[NH_3]^n[/tex]

Thus, by using the following steps, we can find both m (BF3 order of reaction) and n (BF3 order of reaction):

- Experiment 1 and 2 for the calculation of n:

[tex]\frac{r_1}{r_2}=\frac{k[BF_3]_1^m[NH_3]_1^n}{k[BF_3]_2^m[NH_3]_2^n}[/tex]

So we plug in to obtain:

[tex]\frac{0.2130}{0.1065}=\frac{k*0.250^m*0.250^n}{k*0.250^m*0.125^n}\\\\2=\frac{0.250^n}{0.125^n}\\\\2=2^n\\\\log(2)=n*log(2)\\\\n=1[/tex]

So the order of reaction with respect to NH3 is 1.

- Experiment 3 and 4 for the calculation of m

[tex]\frac{r_3}{r_4}=\frac{k[BF_3]_3^m[NH_3]_3^n}{k[BF_3]_4^m[NH_3]_4^n}[/tex]

So we plug in to obtain:

[tex]\frac{0.0682}{0.1193}=\frac{k*0.200^m*0.100^n}{k*0.350^m*0.100^n}\\\\0.57=0.57^m\\\\log(0.57)=m*log(0.57)\\\\m=1[/tex]

So the order of reaction with respect to BF3 is also 1.

Now, we can compute the rate constant by solving for it on any of the experiments there, say experiment 1:

[tex]k=\frac{r_1}{[BF_3][NH_3]} =\frac{0.2130M/s}{0.250M*0.250M}\\\\k=3.41M^{-1}s^{-1}[/tex]

Thus, the initial reaction rate for the 0.50M BF3 and 0.020M NH3 is:

[tex]r=3.41M^{-1}s^{-1}*0.50M*0.020M\\\\r=0.0341\frac{M}{s}[/tex]

Best regards!

Are the nuclei of all atoms

a) Positive

b) Negative

c) Neutral

Answers

I’m pretty sure it’s C neutral

What is the function/job of the digestive system?



Question 2 options:

to take in oxygen and remove carbon dioxide


to transport nutrients and waste throughout the body


to get energy and materials from food


to remove waste from the body

Answers

Answer:

The answer is B (to transport nutrients and waste throughout the body)

Explanation:

Took the test

If an object has a density of 25 g/cm and a mass of 100 grams, what is its volume? O 40 cm3 0.25 cm 4 cm3 125 cm3​

Answers

Answer:

4 cm³

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtract Property of Equality

Chemistry

Gas Laws

Density = Mass over Volume

D = m/V Explanation:

Step 1: Define

D = 25 g/cm³

m = 100 g

Step 2: Solve for V

Substitute variables [D]:                    [tex]\displaystyle 25 \ g/cm^3 = \frac{100 \ g}{V}[/tex]Multiply V on both sides:                  [tex]\displaystyle V(25 g/cm^3) = 100 \ g[/tex]Isolate V:                                            [tex]\displaystyle V = 4 \ cm^3[/tex]

A student read an article about natural resources and listed some resources in the
chart shown. Which answer choice best classifies the natural resources in the chart?
Natural Resources
Coat
Air
Tree
Petroleum
Wheat
Natural
gas
Sheep
Lake
Fish

Answers

Air, Tree’s, natural, and sheep, fish, lake. All those are natural resources

Answer:

Explanation:

Airs and trees

A symbiotic relationship in which both organisms benefit
A. parasitism
B. mutualism
C. commensalism

Answers

The answer is B. Mutualism.


Parasitism is when one is benefiting while the other is being harmed; commensalism is when one is benefiting and the other isn’t affected; and mutualism is basically in its name, they’re both mutually benefiting.

Answer: B

Mutualism.

Explanation:

What reactive species is produced in the initiation step of the free radical chlorination of 2,2-dimethylpropane

Answers

Answer:

See explanation

Explanation:

An initiation step is the first step in a free radical mechanism. In this step, free radicals are generated from a stable compound. The initiation step tends to increase the concentration of radicals present in the system.  It leads to a net increase in the number of free radicals in the system.

For the chlorination of 2,2-dimethylpropane, the initiation step is;

Cl2 + hv --------->2Cl.

Note that hv is used to represent light

50 POINTS How many liters of O2 gas are in 4.21 moles?
and How many liters of PH3 gas are in 14.71 moles?

Answers

Explanation:

I mol of water = 22.4 lts of O2

thus, 4.21 moles of water = 4.21× 22.4= 94.304 lts.

You have 11 blue cars, 7 red cars and 4 green cars
What percent of cars are green?
Answer to 1 Decimal Place (Check your rounding)

Answers

18.2% is your answer I believe
18.2% I’m pretty sure

A student is investigating potential and kinetic energy by stretching a spring across a table. When the student lets go
The spring recoils.

Answers

Answer: When the spring is recoiling

Explanation:

Answer:

When the spring is recoiling

Explanation:

The IR spectrum of a sample contains absorptions at 3050, 2950, and 1620 cm-1. To what class of organic compound does this sample most likely belong

Answers

Answer:

Alkene

Explanation:

The IR spectrum of an organic compound shows us the functional groups present in the compound.

By looking at the various stretching frequencies given in wave numbers, we can decide what functional groups are in the compound and hence the class of organic compounds to which it belongs.

The stretch 3080 cm-1 shows a mono-substituted alkene

The stretch 2950 cm-1 shows a C-H bond

The stretch 1620 cm-1 shows an alkenyl stretch.

Hence the compound is an alkene.

2 points
A student saw the Moon rise at 6:20 a.m. on Monday. If he wants to see
the Moon rise again on Tuesday, vhat time should he look in the sky?(Mark
the one best answer.)
About 6:20 am
About 6:20pm
About 5:30 am
About 7:10am

Answers

6:20 am unless time changes

Photosynthesis is? (Single choice)
A. chemical reaction that occurs in the mitochondria of a cell in all living organisms.
B. a chemical reactions that occurs in the chloroplast of a plant.
C. a chemical reaction that uses food molecules and converts it into ATP.
D. a chemical reaction that occurs mainly in protists.

Answers

Answer:

B. a chemical reactions that occurs in the chloroplast of a plant.

Explanation:

Answer:

B.

Explanation:

it is b because I took science

lol have a good day

When color changes from yellow to brown, what has happened?

Answers

Answer:

its a diffrent color :)

Explanation:

I need to fix the equations

Answers

Answer:

try looking the equations or find a calulator for those type of eqautions

Explanation:

Please help me thanks so much....I’ll mark you?!?!:))))

Answers

Answer:

chemical

Explanation:

A 25.0 mL sample of 0.25 M potassium carbonate (K2CO3) solution is added to 30.0 mL of a 0.40 M barium nitrate (Ba(NO3)2) solution. What is the concentration of the excess metal ion after the precipitation reaction is complete

Answers

Answer:

0.10M of Ba²⁺ is the concentration of the metal in excess

Explanation:

Based on the chemical reaction:

K₂CO₃(aq) + Ba(NO₃)₂(aq) → BaCO₃(s) + 2KNO₃(aq)

1 mole of potassium carbonate reacts per mole of barium nitrate

To solve this question we need to find the moles of each salt to find then the moles of Barium in excess:

Moles K₂CO₃:

0.025L * (0.25mol / L) = 0.00625moles K₂CO₃ = moles CO₃²⁻

Moles Ba(NO₃)₂:

0.030L * (0.40mol/L) = 0.012 moles of Ba(NO₃)₂ = 0.012 moles of Ba²⁺

That means moles of Ba²⁺ that don't react are:

0.012 mol - 0.00625mol = 0.00575 moles Ba²⁺

In 25 + 30mL = 55mL:

0.00575 moles Ba²⁺ / 0.055L =

0.10M of Ba²⁺ is the concentration of the metal in excess

The concentration of the excess metal ion after the precipitation reaction is complete is 0.1045 M

From the question,

We are to determine the concentration of the excess metal ion after the precipitation reaction is complete

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

K₂CO₃ + Ba(NO₃)₂ → BaCO₃ + 2KNO₃

This means

1  mole of K₂CO₃ is required to react completely with 1 mole of Ba(NO₃)₂

Now, we will determine the number of moles of each reactant present.

For K₂CO₃

Volume = 25.0 mL = 0.025 L

Concentration = 0.25 M

Using the formula

Number of moles = Concentration × Volume

∴ Number of moles of K₂CO₃ present = 0.25 × 0.025

Number of moles of K₂CO₃ present = 0.00625 mole

For Ba(NO₃)₂

Volume = 30.0 mL = 0.03 L

Concentration = 0.40 M

∴ Number of moles of Ba(NO₃)₂ present = 0.40 × 0.03

Number of moles of Ba(NO₃)₂ present = 0.012 mole

Since

1 mole of K₂CO₃ is required to react completely with 1 mole of Ba(NO₃)₂

Then,

The 0.00625 mole of K₂CO₃ will react with 0.00625 mole of Ba(NO₃)₂

∴ Only 0.00625 mole of the Ba(NO₃)₂ will react

This means Ba(NO₃)₂ is the excess reactant.

Now, we will determine the number of moles of Ba(NO₃)₂ remaining

Number of moles of Ba(NO₃)₂ remaining = 0.012 mole - 0.00625 mole

Number of moles of Ba(NO₃)₂ remaining = 0.00575 mole

Now, for the concentration

Using the formula

[tex]Concentration = \frac{Number\ of\ moles}{Volume}[/tex]

Volume = Total volume of the solution = 0.025L + 0.03L

Volume = 0.055 L

∴ Concentration of the excess metal ion = [tex]\frac{0.00575}{0.055}[/tex]

Concentration of the excess metal ion = 0.1045 M

Hence, the concentration of the excess metal ion after the precipitation reaction is complete is 0.1045 M

Learn more here: https://brainly.com/question/1825674

Which of the following best describes how water evaporates? *
3 points
A. Water molecules that move with higher energy evaporate first
B. Water molecules that are cooled evaporate
C. None of the above

Answers

The answer is A because water can only evaporate if a liquid substances becomes gas , in this case it’s the water. When water is heated it evaporates. The molecule moves and vibrates so quickly that they can move to the atmosphere

how does mixture relate to your life​


PLEAEEEE QUICKKKK AND FASTTT

Answers

Ans: Mixtures is a common occurrence in our everyday lives. They are the air we breathe, the food and drink we consume and the fabrics we wear. By studying how chemists distinguish pure substances from mixtures and solutions, students will start to appreciate how matter is organised at the atomic level.


There are some cells that do not have DNA.
O True
O false

Answers

Answer:

false

Explanation:

It’s false hope this helps

Islands have cool and calm weather throughout the year? Why?

Answers

There’s no one around and the breeze from the Ocean makes it cool

HEY THIS ANSWER CORRECT ?

Answers

Answer:

I don't think that answer is right. I got 543.04 grams.

Explanation:

I think the question is asking for grams in the samlpe instead of the moles in the sample because it already gives you the amount of moles.

what energy transfer and transformation occurs when riding a bicycle?

Answers

Answer: You pedaling the bike is transforming chemical energy

Explanation:

A chemist adds of a calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask. Round your answer to significant digits.

Answers

The given question is incomplete. The complete question is:

A chemist adds 0.85 L of a 0.0050M calcium sulfate to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask. Round your answer to significant digits.

Answer: The mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in L

moles of [tex]CaSO_4[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{136g/mol}[/tex]

Now put all the given values in the formula of molarity, we get

[tex]0.0050=\frac{x}{136\times 0.85}[/tex]

[tex]x=0.58 g[/tex]

Therefore, the mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g

Provide one example of how life on Earth would not be possible without water based on its characteristics.

Answers

Answer: ice is less dense than liquid water. If ice was more dense, Earth would freeze.

Explanation: There are many reasons why life on Earth depends on the characteristics of water. One could discuss hydrogen bonds and its role as a solvent, but the unusual property of water is is the change in density with change in temperature. Water is densest at 4 degC, which is why ice floats - it is less dense than cold water (it melts quickly in warm water, so density isn’t impotant at higher temperatures). Most liquids are less dense than the solid, frozen form. If this was the case with water, any ice that formed would sink, and sease would freeze from the bottom up. Furthermore, the lowest layers would be insulated and would not all melt in summer. Thus over time, the seas would become a thin layer of liquid water at best, over solid ice. Life could not develop without liquid seas. In addition, ice is reflective, reducing the amount of sunlight absorbed, further reducing temperatures. Without ocean circulation, polar areas would be even colder, and there would be no rain.

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