Complete Question
Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
Answer:
The value is [tex]T_R = 11.8 \ days[/tex]
Explanation:
From the question we are told that
The semi - major axis of the rocky debris [tex]a_R = 45.0\ AU[/tex]
The semi - major axis of Planet D is [tex]a_D = 60 \ AU[/tex]
The orbital period of planet D is [tex]T_D = 18.164 \ days[/tex]
Generally from Kepler third law
[tex]T \ \ \alpha \ \ a^{\frac{3}{2} }[/tex]
Here T is the orbital period while a is the semi major axis
So
[tex]\frac{T_D}{T_R} = \frac{a^{\frac{3}{2} }}{a_R^{\frac{3}{2} }}[/tex]
=> [tex]T_R = T_D * [\frac{a_R}{a_D} ]^{\frac{3}{2} }[/tex]
=> [tex]T_R = 18.164 * [\frac{ 45}{60} ]^{\frac{3}{2} }[/tex]
=> [tex]T_R = 11.8 \ days[/tex]
The orbital period of the rocky debris in space is 12 days.
From Kepler's law, we know that the square of the period of a planet in years is equal to the cube of its mean distance from the sun in astronomical units (AU).
Mathematically;
[tex]T^2 = r^3[/tex]
Now, we have the mean distance as 45.0 AU, we need to obtain its period.
semi major axis of debris rR= 45.0 AU
semi major axis of planet D rD = 60 AU
Period of planet D TD = 18.164 days
Period of debris TR = ?
[tex]\frac{TR^2}{TD^2} = \frac{rR^3}{rD^3}[/tex]
[tex]\frac{rR^3}{rD^3} * TD^2[/tex]
[tex]TR^2 = 45^3/60^3 * 18.164^2[/tex]
TR = 12 days
Missing parts:
Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
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As the frequency of a wave decreases, the wave's -
Answer:
When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.
a person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. Use the vertical motion model, h = -16t squared + vt + s, where v is the initial velocity in feet per second and s is the height in feet, to calculate the amount of time the baseball is in the air before it hits the ground. Round your answer to the nearest tenth if necessary.
Time in air:_____ seconds
Answer:33s
Explanation:
Answer: 3.3 seconds
Explanation:
I just did it
A student creates a circuit using a 10V battery, as shown in the picture below.
38
Battery
Switch
20
What is the current in the circuit?
Answer:
I = 2 [amp]
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the current by the resistance.
The resistances in the diagram are connected in series, in this way the total resistance will be equal to the algebraic sum of the resistivity.
R = R1 + R2
R = 3 + 2
R = 5 [ohm]
Now, using ohm's law we have:
V = I*R
where:
V = voltage = 10 [V]
I = current [amp]
R = resistance = 5 [ohm]
I = V/R
I = 10/5
I = 2 [amp]
I need a bit of help on this one, can anyone answer?
Potential energy = m · g · h
-- When you held the ball at 2.0 meters above the floor, it had
(0.5 kg) · (9.8 m/s²) · (2.0 m) = 9.8 Joules of potential energy.
-- After it bounced and went back up as high as it could, it was only 1.8 meters above the floor. Its potential energy was
(0.5 kg) · (9.8 m/s²) · (1.8 m) = 8.82 Joules
-- Between the drop and the top of the bounce, it lost
(9.8 - 8.82) = 0.98 Joule .
-- The energy was lost when the ball hit the floor. During the hit, 0.98 joule of kinetic energy turned to thermal energy, which slightly heated the ball and the floor.
A plane has a speed of 285 km/h west relative to the air. A wind blows 25 km/h east relative to the ground. what are the planes speed and direction relative to the ground?
Answer:
260 km/h
Explanation:
Motion is said to be relative when the motion observed by the observer depends on the location (frame) of the observer.
When two objects are moving in opposite directions, the relative motion is obtained by subtraction.
Hence the plane is moving at (285 - 25) km/h giving 260 km/h
If a car travels 30 kilometers in 2 hours, it’s average speed is?
Answer:
15km/h
Explanation:
Time taken to complete 30km/h=2 hours=15km/h hence the average speed is 15km/h.
Select the correct answer. An object has one force acting on it. It is a 33-newton force pointing downward. To create a net force of zero on the object, which force must be applied to it? Group of answer choices a 1-newton force pointing right a 0-newton force pointing downward a 33-newton force pointing upward a 33-newton force pointing left a 1-newton force pointing upward
Answer:
33 Newton upwards to get a net force of zero.
Answer:
The answer is 33 newtons with a net force of 0
Explanation:
A bungee cord stretches 17 meters and has a spring constant of 130 N/m. How much energy is stored
in the bungee?
Answer:
U = 18,785 J
Explanation:
Elastic Energy
Elastic energy is energy stored in an object due to a force that temporarily changes its shape, such as shrinking or stretching.
The elastic energy can be calculated as follows:
[tex]\displaystyle U=\frac{1}{2}k(\Delta x)^2[/tex]
Where k is the spring constant, and \Delta x is the change in the size of the spring.
The bungee cord stretches \Delta x =17 m, and k=130 N/m, thus:
[tex]\displaystyle U=\frac{1}{2}130(17)^2[/tex]
U = 18,785 J
please help me!!!
A pigeon is walking around the courtyard looking for food the pigeon walks 4.0 m West 2.5 M North 1.1 M and 7.3 m south what is the pigeons final displacement vector
Answer: ARE YOU DOING PRIMAVERA?!? PLEASE I KNOW YOU ARE I CANT DO PHYSICS-
Explanation:
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The pigeon final position displacement vector represented as , [tex]-2.9i-4.8j[/tex]
Given that Pigeon walks 4.0 m West then 2.5 m North then 1.1 m east and then 7.3 m south.
A diagram is attached below which describe the above situation.
In attached diagram, Distance DO represent the displacement.
From Diagram, it is observed that final position D of Pigeon is 4.8 m away from x axis and 2.9 m away from y axis.
Thus, Displacement vector represented as , [tex]-2.9i-4.8j[/tex]
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i need help solving this,
Answer:
8n
Explanation:
Type in the correct values to correctly represent the valence electron configuration of oxygen: AsB2pC A = B = C = What is the charge of an oxygen ion? -
Explanation:
Oxygen has an atomic number of 8 with 2 electrons in its innermost shell (s orbital) and 6 remaining electrons in its outermost shell.
The electronic configuration of the oxygen element will therefore be expressed as;
1s²2s²2p⁴
Since we are to find the valence electron configuration of oxygen, this means we are going to consider only electrons in the outermost shell. The outermost shell of oxygen only contains 6electrons. The electronic configuration will be;
2s²2p⁴ (ignoring the innermost electrons)
Comparing with As^B2p^C
we will have;
As^B = 2s²
A = 2, B = 2
2p^C = 2p⁴
p^c = p⁴
C = 4
Hence A = 2, B = 2 and C = 4
The oxygen ion is represented as O₂²⁻. Therefore the charge of an oxygen ion is -2
Answer:
a=2
b=2
c=4
-2
Explanation:
1. how Orienteering is an ideal sport for the most promotion of
physical activity and lifetime sports.
Answer:
Because it comprises both physical and mental activities.
Explanation:
Orienteering is a sport that is known for its physical and mental activities. It is an ideal sport for the most promotion of physical activity and lifetime sports because it involves moving through the wild or difficult terrain. This takes energy to be competitive, and it also requires participants to take challenging decisions now and then.
People of different ages can participate and allows them to apply real-world decision-making skills to the competition. It also gives participants the chance to learn about themselves more and how to face different situations.
If a 53 kg Boulder falls off a cliff, what is the force with which it will hit the ground?
Answer: 519.4 N
Explanation:
53 kg x 9.8 m/s = 519.4 N
If a 53 kg Boulder falls off a cliff, the force with which it will hit the ground is 519.4 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Given in the question a 53 kg Boulder falls off a cliff, what is the force with which it will hit the ground,
force = mass * acceleration due to gravity
= 53 kg x 9.8 m/s
= 519.4 N
If a 53 kg Boulder falls off a cliff, the force with which it will hit the ground is 519.4 N.
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Please helpers! I wrote the first questions answer but from there i didnt know how to calculate.
Answer:
3.
Force(f) =2000N
Distance (d) =10m
Time(t)=50 sec
We know,
P=W/t
=f×d/t
=2000×10/50
=400 watt
4.
Force(f) =30N
Distance (d) =10 m
Time(t) =5 sec
We know,
P=w/t
=f×d/t
=30×10/5
=60 watt
What physical property causes liquids to not separate in a container?
A) density
B) boiling point
C) specific heat
Answer:
B) boiling point
Explanation:
The movement of the particles causes the shape of the liquid to change. The liquid will flow and fill to the lowest part of the container, in the shape of the container
But the volume does not change. The limited amount of space between the particles means that the liquid has only very limited compressibility.
Answer:
A) Density
Explanation:
The air contained water that froze at 0 °C
The change in internal energy of the water as it froze was 0.70 kJ The specific latent heat of fusion of water is 330 kJ/kg
Calculate the mass of ice produced.
Answer:
The mass of the ice produced is approximately 0.00212 kg
Explanation:
The given parameters are;
The temperature at which the air changed from water to ice = 0°C
The internal energy change of the water as it froze = 0.7 kJ
The specific latent heat of fusion of water = 330 kJ/kg
Given that the change in internal energy causes the water to change state, from the principle of energy conservation, we have;
The latent heat of fusion = The change in internal energy of the water as it froze
∴ The latent heat of fusion [tex]\Delta H^{\circ}_{fus}[/tex] = 0.70 kJ
The formula for the latent heat of fusion, [tex]\Delta H^{\circ}_{fus}[/tex] = Mass × The specific latent heat of fusion, [tex]L^{\circ}_f[/tex]
Therefore, for the water, we have;
0.7 kJ = m × 330 kJ/kg
m = 0.7 kJ/(330 kJ/kg) ≈ 0.00212 kg
The mass, m, of the ice produced ≈ 0.00212 kg.
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Why does it feel cooler at 90°F when the relative humidity is 30% compared to the same temperature and the relative humidity is 80%?
a. Because the drier air evaporates moisture off your skin more easily.
b. There is no real difference because the temperature is the same.
c. Because there is less air movement at 80% humidity.
d. Because the lower humidity brings down the temperature.
If Phred throws a rock straight up, and Phran throws a rock straight up with twice the velocity of Pread's rock, how will the maximum height of Phred's rock compare to Phran's?
Answer:
The maximum height of Phran stone is four time that of Phred stone
Explanation:
From the question we are told that
The initial velocity of Phred stone is u
The initial velocity of Phran stone is 2u
Generally from kinematic equations
[tex]v^2 = u^2 + 2(-g)h[/tex]
Here the negative sign shows that the direction of the stone is against gravity
At the maximum height v which is the final velocity of the stone is zero
So
[tex]0 = u^2 - 2gh[/tex]
So for Phred stone the height attained is
=> [tex]h_1 = \frac{u^2}{2g}[/tex]
For Phran stone the height attained is
=> [tex]h_2 = \frac{(2u)^2}{2g}[/tex]
=> [tex]h_2 = \frac{4u^2}{2g}[/tex]
=> [tex]h_2 = 4 h_1[/tex]
Hence the maximum height of Phran stone is four time that of Phred stone
7. Which of the following best describes Philippine regional literature?
Explanation:
where is the option of the Question
6. An elephant is putting 25,000 newtons of force on Leah. The elephant
is accelerating at a rate of 10 mIs? what is its mass?
The harmfulness of a germ is called?
How many carrots does benny have if he has 8 times as many as Karen. Karen has 18 carrots.
Answer:
144
Explanation:
18 multiplied by 8 equals 144. Hope I helped! εїз
Answer:
The answer is 144.
Explanation:
18X8=144
Which part of the eye is responsible for the color of the eye?
OA.
cornea
O B.
iris
O c.
lens
OD.
retina
Answer:
D
Explanation:
Sabiendo que el indice de refracción dela gua es 1,33 calcula el ángulo de refracción resultante para un rayo de luz que incide sobre una piscina con un ángulo de incidencia de 50º
Answer:
35.16 degrees
Explanation:
Knowing that the index of refraction of the guide is 1.33, calculate the resulting angle of refraction for a ray of light that falls on a pool with an angle of incidence of 50º
Refractive index, n = 1.33
The angle of incidence, i = 50°
We need to find the angle of refraction. let it is r. It can be calculated using Snells law as follows:
[tex]n=\dfrac{\sin i}{\sin r}\\\\\sin r=\dfrac{\sin i}{n}\\\\r=\sin^{-1}(\dfrac{\sin i}{n})\\\\r=\sin^{-1}(\dfrac{\sin 50}{1.33})\\\\r=35.16^{\circ}[/tex]
So, the angle of refraction is 35.16 degrees.
If you stood on mars and lifted a 15kg pack, you would be pulling with a force greater than...?
Pls i need help and I will give brainliest to the best explained answer :)
Answer:
See the answers below
Explanation:
In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
[tex]W=m*g[/tex]
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
[tex]w_{mercury} = 15*3.8\\w_{mercury}= 57 [N]\\[/tex]
Venus
[tex]w_{venus}=15*8.8\\w_{venus}= 132 [N][/tex]
Moon
[tex]w_{moon}=15*1.6\\w_{moon}=24[N][/tex]
Mars
[tex]w_{mars}=15*3.7\\w_{mars}=55.5 [N][/tex]
Jupiter
[tex]w_{jupiter}=15*23.1\\w_{jupiter}= 346.5[N][/tex]
Saturn
[tex]w_{saturn}=15*9\\w_{saturn}=135[N][/tex]
Uranus
[tex]w_{uranus}=15*8.7\\w_{uranus}=130.5[N][/tex]
Neptune
[tex]w_{neptune}=15*11\\w_{neptune}=165[N][/tex]
Pluto
[tex]w_{pluto}=15*0.6\\w_{pluto}=9[N][/tex]
pls don't answer if you don't know the answer.
does anyone know how to do the Student Exploration: Longitudinal Waves on Gizmos worksheet.
I don't understand it.
Answer:
Search it
Explanation:
its on it
On the same spring day, a station near the equator has a surface temperature of 25°C, 15°C higher than the middle-latitude city mentioned in part a. Vertical soundings reveal an environmental lapse rate of 6.5°C per kilometer and indicate that the tropopause is encountered at 16 km. What is the air temperature at the tropopause?
Answer:
The air temperature at the tropopause is - 79 °C
Explanation:
We know that a station near the equator has a surface temperature of 25°C
Vertical soundings reveal an environmental lapse rate of 6.5 °C per kilometer.
The tropopause is encountered at 16 km.
In order to find the air temperature at the tropopause we are going to deduce a linear function for the temperature at the tropopause.
This linear function will have the following structure :
[tex]f(x)=ax+b[/tex]
Where ''[tex]a[/tex]'' and ''[tex]b[/tex]'' are real numbers.
Let's write [tex]T(x)[/tex] to denote the temperature '' T '' in function of the distance
'' x '' ⇒
[tex]T(x)=ax+b[/tex]
We can reorder the function as :
[tex]T(x)=b+ax[/tex] (I)
Now, at the surface the value of ''[tex]x[/tex]'' is 0 km and the temperature is 25°C so in the function (I) we write :
[tex]T(0)=25=b+a(0)[/tex] ⇒ [tex]b=25[/tex] ⇒
[tex]T(x)=25+ax[/tex] (II)
In (II) the value of ''[tex]a[/tex]'' represents the change in temperature per kilometer.
Because the temperature decrease with the height this number will be negative and also a data from the question ⇒
[tex]T(x)=25-(6.5)x[/tex] (III)
In (III) we deduced the linear equation. The last step is to replace by [tex]x=16[/tex] in (III) ⇒
[tex]T(16)=25-(6.5)(16)=-79[/tex]
The air temperature at the tropopause is - 79 °C
If an earthquake wave travels a distance of 4000m in 8 seconds, how fast is the earthquake wave traveling?
4000 ÷ 8 = 500
Its 500 m/s as shown in the calculation above.
A model rocket Was built last weekend. We launched it in a nearby field. The rocket took off Straight up with an initial velocity 62.3 m/s. If it accelerates upward at 4.30 m/s2 until the engines stop 3.73 s later: (a) What is the maximum height the rocket reaches? (b) How long is the rocket in the air? (c) What is the velocity of the rocket as it hits the ground?
Answer:
a) y_total = 575.4 m , b) t_total = 22.56 s , c) v = 106.20 m
Explanation:
a) We can solve this exercise using the scientific relations
Let's find the height reached while the engines are running
v₁ = v₀ + a t
v₁ = 62.3 + 4.30 3.73
v₁ = 78.339 m / s
in this time it rose
y₁ = v₀ t₁ + ½ a t₁²
y₁ = 62.3 3.73 + ½ 4.30 3.73²
y₁ = 262.29 m
At this moment the engines are turned off and the rocket continues in a vertical launch, suppose that the acceleration of gravity is constant in this path
v₂ = v₁ 2 - 2 g y₂
at maximum height the velocity is zero (v₂ = 0)
y₂ = v₁ 2 / 2g
y₂ = 78.339 2/2 9.8
y₂ = 313.11 m
the total height is
y_total = y₁ + y₂
y_total = 262.29 + 313.11
y_total = 575.4 m
b) the time the rocket is in the air is
t_total = t₁ + t₂
where t₂ is the time after the engines have shut down
y = y₁ + v₁ t₂ - ½ g t₂²
y = 0
0 = 262.29 + 78.339 t₂ - ½ 9.8 t₂²
t₂² - 15.99 t₂ - 53.53 = 0
t₂ = [15.99 ±√ (15.99² +4 53.53)] / 2
t₂ = [15.99 ± 21.67] / 2
t₂´ = 18.83 s
t₂´´ = -2.84 s
since the time must be a positive quantity the correct result is t2 = 18.83 s, the total time in the air is
t_total = 3.73 + 18.83
t_total = 22.56 s
c) the speed when it hits the ground
We can perform this calculation starting with the maximum height y = 575.4 m where it has zero initial velocity (vo = 0)
v² = v₀² + 2 g y
v = √ 2gy
v = √ (2 9.8 575.4)
v = 106.20 m
Which statement best describes the two reactions?
A Upper C l subscript 2 plus upper H subscript 2 right arrow 2 upper H upper C l.
B Superscript 2 subscript 1 upper H plus superscript 3 subscript 1 upper H right superscript 4 subscript 2 upper H e plus superscript 1 subscript 0 n.
Reaction A involves a greater change, and reaction B involves a change in element identity.
Reaction B involves a greater change and a change in element identity.
Reaction A involves a greater change and a change in element identity.
Reaction B involves a greater change, and reaction A involves a change in element identity.
Answer:
b
Explanation:
i guessed annd got it right
Answer:
Reaction B involves a greater change and a change in element identity.
Explanation: