A particle with charge q and mass m moving with speed v in the x direction enters a magnetic field of strength B pointing in the y direction. The magnitude of the acceleration of the particle as it travels one semicircle is

Answers

Answer 1

Answer:

The acceleration of the particle as it travels one semicircle is

[tex]a= \frac{\pi R}{t^2}[/tex]

Explanation:'

Kindly see attached a sketch of a semi-circle

Step one:

given data

velocity =v

let the time taken be t

The path PQM is the distance covered

so distance [tex]d= \pi R[/tex]

we know that time= distance/velocity

t= πR/v

step two:

velocity =distance/time

[tex]velocity=\frac{\pi R}{t}[/tex]

also, we know that acceleration is velocity/time

[tex]a= \frac{\pi R}{\frac{t}{t} }[/tex]

[tex]a= \frac{\pi R}{t}*\frac{1}{t}[/tex]

[tex]a= \frac{\pi R}{t^2}[/tex]

A Particle With Charge Q And Mass M Moving With Speed V In The X Direction Enters A Magnetic Field Of

Related Questions

In a two-dimensional Cartesian system, the x-component of a vector is known, and the angle between vector and x-axis is known. Which operation is used to calculate the magnitude of the vector?

a. dividing by cosine
b. dividing by sine
c. multiplying by cosine
d. multiplying by sine

Answers

I think it’s A. Dividing by cosine

An astronaut with mass 84kg is at rest in space, before firing her water pack to move toward the shuttle. If the amount of water shot out is
2kg and it is fired at a speed of 10m/s, what will the speed of the astronaut be?

Answers

Answer:

The astronaut is moving at a speed of 0.238 m/s in a direction opposite the direction of the water shot out.

Explanation:

We are given;

Mass of astronaut; m1 = 84 kg

Mass of water shoot out; m2 = 2 kg

Initial speed of astronaut; u1 = 0 m/s

Initial speed of water shoot out; u2 = 0 m/s

Final speed of shoot out; v2 = 10 m/s

From law of conservation of momentum, we can say that;

Initial momentum = final momentum

Thus;

m1•u1 + m2•u2 = m1•v1 + m2•v2

Where v1 is the final speed of the astronaut

Plugging in the relevant values, we get;

(84 × 0) + (2 × 0) = (84 × v1) + (2 × 10)

0 = 84v1 + 20

-20 = 84v1

v1 = -20/84

v1 = -0.238 m/s

The negative sign indicates that the astronaut is moving 0.238 m/s in a direction opposite the direction of the water shot out.

What is the ratio of the radii of curvature for a proton and an an electron traveling through this apparatus

Answers

Answer:

hello your question is incomplete below is the missing part of the question

Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.55 T.

answer :   ≈ 42

Explanation:

Ratio of the Radii of curvature for a proton and an electron travelling through this apparatus

= [tex]\frac{Rp}{Re}[/tex] = 0.025 m / 5.94 * 10^-4 m = 42.08

Rp = 0.025 m ( calculated )

Re = 5.94 * 10^-4 ( calculated )

Each mass in the figure is 3 kg. Find the magnitude and direction of the net gravitational force on mass A due to the other masses.


A. 2.45 × 10–7 N toward B
B. 3.75 × 10–7 N toward C
C. 2.00 × 10–7 N toward D
D. 1.15 × 10–7 N toward D

Answers

Answer:

THE ANSER IS B

Explanation:

The magnitude and direction of the net gravitational force on mass A due to the other masses is 1.15 × 10⁻⁷ N toward D.

The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In this case, all of the masses are equal to 3 kg, and the distance between mass A and mass D is 3 m.

The gravitational force between mass A and mass D is therefore:

F = G * m_A * m_D / r²

= 6.674 × 10⁻¹¹ N m² / kg² * 3 kg * 3 kg / 3 m²

= 1.15 × 10⁻⁷ N

The direction of the gravitational force is towards mass D.

Therefore, the net gravitational force on mass A due to the other masses is 1.15 × 10⁻⁷ N toward D.

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From the 1780s to the late 1800s, people thought the amount of land and resources in the West was limited

Answers

Answer:true

Explanation:

A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy

Answers

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

For the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.

Given the data in the question;

Speed of the car; [tex]v_1 = 15m/s[/tex]

Speed for the car to double its kinetic energy; [tex]v_2 = \ ?[/tex]

Using the expression for kinetic energy:

[tex]K_E = \frac{1}{2}mv^2[/tex]

Where m is the mass and v is the velocity

Now, Initial Kinetic Energy will be;

[tex]K_E_1 = \frac{1}{2}mv_1^2 \\\\K_E_1 = \frac{1}{2}*m*(15)^2\\\\K_E_1 = \frac{1}{2}*m*225\\\\K_E_1 = 112.5*m[/tex]

For the kinetic energy to become double

[tex]K_E_2 = 2 * K_E_1\\\\\frac{1}{2}mv_2^2 = 2 * ( 112.5 * m)\\\\\frac{1}{2}mv_2^2 = 2m( 112.5)\\\\v_2^2 = 4( 112.5)\\\\v_2^2 = 450\\\\v_2 = \sqrt{450}\\\\v_2 = 21.21m/s[/tex]

Therefore, for the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.

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Selection
boy throws a 1.2 kg ball straight up at 12 m/s. How high does the ball go? 1 point
(Answer to two digits)

Answers

Answer:

69

Explanation:

A local AM radio station broadcasts at a frequency of 627 kHz. Calculate the wavelength at which it is broadcasting. Wavelength

Answers

Answer:

Wavelength = 478.46 m

Explanation:

It is given that,

A local AM radio station broadcasts at a frequency of 627 kHz, f = 627000 Hz

We need to find the wavelength at which it is broadcasting. The wavelength is given by :

[tex]\lambda=\dfrac{c}{f}\\\\=\dfrac{3\times 10^8}{627\times 10^3}\\\\=478.46\ m[/tex]

So, the wavelength is 478.46 m.

which of the following require that you also state direction
A. speed
B. displacement
C. acceleration
D. instantaneous speed
SCIENCE QUESTION FOR 20 POINTS

Answers

Answer:

d

Explanation:

I think the answer is D

The earth rotates every 86,160 seconds. What is the tangential speed (in m/s) at Livermore (Latitude 37.6819° measured up from equator, Longitude 121.

Answers

Answer:

The tangential speed at Livermore is approximately 284.001 meters per second.

Explanation:

Let suppose that the Earth rotates at constant speed, the tangential speed ([tex]v[/tex]), measured in meters per second, at Livermore (37.6819º N, 121º W) is determined by the following expression:

[tex]v = \left(\frac{2\pi}{\Delta t}\right)\cdot R \cdot \sin \phi[/tex] (1)

Where:

[tex]\Delta t[/tex] - Rotation time, measured in seconds.

[tex]R[/tex] - Radius of the Earth, measured in meters.

[tex]\phi[/tex] - Latitude of the city above the Equator, measured in sexagesimal degrees.

If we know that [tex]\Delta t = 86160\,s[/tex], [tex]R = 6.371\times 10^{6}\,m[/tex] and [tex]\phi = 37.6819^{\circ}[/tex], then the tangential speed at Livermore is:

[tex]v = \left(\frac{2\pi}{86160\,s} \right)\cdot (6.371\times 10^{6}\,m)\cdot \sin 37.6819^{\circ}[/tex]

[tex]v\approx 284.001\,\frac{m}{s}[/tex]

The tangential speed at Livermore is approximately 284.001 meters per second.

When Danny Diver who weighs 500 N steps off a diving board 10 m above the water, he hits the water with kinetic energy of

Answers

Answer:

5000 J

Explanation:

Given that,

Weight of Danny Diver, F = 500 N

He steps off a diving board 10 m above the water

We need to find the kinetic energy of the water with which it hits. Let its is K. It is given by :

E = mgh

Where g is acceleration due to gravity

[tex]E=500\ N\times 10\ m\\\\=5000\ J[/tex]

So, he hits the water with kinetic energy of 5000 J.

5. A man has a weight of 100 Newtons. How much work is done if he climbs 4 meters up a ladder? Plug numbers under the equation. Solve and circle your answer. Include the proper units.

Answers

Answer:

400 J

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 100 × 4

We have the final answer as

400 J

Hope this helps you

A film of soapy water ( n= 1.33 ) on top of a plastic cutting board has a thickness of 233 nm. What color is most strongly reflected if it is illuminated perpendicular to its surface?

Answers

Answer:

620nm

Explanation:

The most strongly reflected color will be "Orange".

According to the question,

Refractive index, n = 1.33Thickness, t = 233 nm

As we know,

→ [tex]t = \frac{\lambda}{2n}[/tex]

or,

→ [tex]\lambda = 2tn[/tex]

By putting the values, we get

      [tex]= 2\times 233\times 10^{-9}\times 1.33[/tex]

      [tex]= 620 \ nm[/tex]

Thus the above response is correct.

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A 0.106-A current is charging a capacitor that has square plates 4.60 cm on each side. The plate separation is 4.00 mm.
(a) Find the time rate of change of electric flux between the plates in V·m/s
(b) Find the displacement current between the plates in A

Answers

Answer:

a

 [tex]\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s[/tex]

b

 [tex]I = 0.106 \ A[/tex]

Explanation:

From the question we are told that

  The current is  [tex]I = 0.106 \ A[/tex]

   The length of one side of the square [tex]a = 4.60 \ cm = 0.046 \ m[/tex]

    The separation between the plate is  [tex]d = 4.0 mm = 0.004 \ m[/tex]

Generally electric flux is mathematically represented as

       [tex]\phi_E = \frac{Q}{\epsilon_o}[/tex]

differentiating both sides with respect to t is  

       [tex]\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} * \frac{d Q}{ dt}[/tex]

=>     [tex]\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} *I[/tex]

Here [tex]\epsilon_o[/tex] is the permitivity of free space with value  

        [tex]\epsilon _o = 8.85*10^{-12} C/(V \cdot m)[/tex]

=>   [tex]\frac{d \phi_{E}}{dt} = \frac{0.106}{8.85*10^{-12}}[/tex]

=>   [tex]\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s[/tex]

Generally the displacement current between the plates in A

    [tex]I = 8.85*10^{-12} * 1.1977 *10^{10}[/tex]

=>  [tex]I = 0.106 \ A[/tex]

 

in the one pulley system when you move the Mass from The 20-centimeter Mark to the 15 centimeter mark it moves to my 5cm how far did you pull the string?

5 cm
10cm
15cm
20cm​

Answers

Answer:

5 cm

Explanation:

Remember that in the pulley system the rope moves the same distance in both ends of the pulley, what the pulley system does is creating a mechanical advantage which basically means that it takes less effort to pull than the actual effort it would take, so for example if you have to lift a box that is 800 N, with a pulley system and the mechanical advantage you'd have to pull with less force.

I need the answer asap thank you !!!

Answers

Answer:

whats the question??????

What does BMI (Body Mass Index) attempt to measure?
O A. Target heart rate
O B. Energy levels
O C. Body fat percentage
O D. Weight

Answers

Answer: C. Body fat percentage

Explanation:

Answer:

your answer is C

Explanation:

a sample of steam at 15 bar pressure and 400°c temperature is first expanded at a constant enthalpy to 6 bar and then expanded isentropically where the dryness fraction of the steam is 0.90. find the change of enthalpy, the pressure of isentropically expanded steam and change of entropy.

Answers

Answer:

Answer.

Explanation:

Explanation.

A car is traveling at the bottom of a 9.00-meter-radius circular hill with a constant speed v. The moment the car is at the bottom of the hill, it is noted that a person sitting on a scale in the car reads a value off the scale that is 80% more than normally when the scale is at rest in a bathroom. With what speed is the car traveling

Answers

Answer:

Explanation:

reading of scale = reaction force of surface R

centripetal force = R - mg = m v² / R , m is mass , v is velocity and R is radius of the circular path .

R = mg + m v² / R

given ,

m v² / R = .80 mg

v² = .80 x g x R

= .8 x 9.8 x 9 = 70.56

v = 8.4 m /s

Need help with this physics question!
A baseball is hit straight up at 60 m/s. At 9 seconds what is the displacement, the acceleration and velocity?

Answers

Answer:

Acceleration: -9.8 m/s^2

Velocity: -28.2 m/s

Displacement: 143.1 m

Explanation:

The acceleration of gravity for any object close to earth is approximately -9.8 m/s^2.

Now, to find the velocity after 9 seconds, we can use a kinematics formula, where x is the final velocity:

Final Velocity = Initial Velocity + Acceleration * Time

x = 60 + -9.8*9

x = 60 - 88.2

x = -28.2

The velocity is -28.2 m/s.

Lastly, to find the displacement, we can use another kinematics formula, where y is the displacement:

Displacement = (Final Velocity + Initial Velocity)/2 * Time

y = (-28.2 + 60)/2 * 9

y = 143.1

The displacement is 143.1 meters.

it is rate for any motion to

a. stay the same for very long
b. change quickly
c. increase in velocity
d. decrease in speed

Answers

Answer:

a. stay the same for very long

Explanation:

It is rare for any motion to stay the same for a very long time. The force applied on a body causes changes in the magnitude of motion.

For motion to remain constant, there must not be a net force acting on the body All the forces on the body must be balanced. This is very hard to come by. Motion changes very frequently.

What is the approximate efficiency of the engine?
A heat engine has a temperature of 1800 K. Some of the
heat from the engine flows to the surroundings, which
are at a temperature of 160 K.
0 16%
O 91%
O 103%
O 109%

Answers

Answer:91% I think

Explanation:

The typical engine efficiency for a modern petrol combustion engine is from 20 to 30 percent. The remaining 70 to 80 percent of the heat energy of the petrol is released from the engine as friction loss, mechanical sound energy, or exhaust heat. Thus, option B is correct.

What approximate efficiency of the engine?

An engine's efficiency is measured by the heat produced divided by the amount of useful work done. Is the task complete. Is the task finished. Please be aware that the phrase “work done” refers to the force applied to the clutch or driveshaft.

Utilizing the following formula, efficiency may be represented as a ratio: output input. Output, often called work output, is the entire quantity of productive work completed, excluding waste and spoilage.

You may determine the efficiency by figuring out what proportion of the energy input results in the desired output: Efficiency is defined as Energy Out/Energy In 100%.

Therefore, This implies that the work produced by thermodynamic expansion is reduced by the friction and other losses.

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In a Young's double slit experiment, the separation between the slits is 1.20 × 10–4 m; and the screen is located 3.50 m from the slits. The distance between the central bright fringe and the second-order bright fringe is 0.0375 m. What is the wavelength of the light used in this experiment?

Answers

Answer:

Explanation:

separation between slit d = 1.2 x 10⁻⁴ m

distance of screed D = 3.5 m

distance of second order right fringe

= 2λD / d where λ is wavelength of light .

2λD / d  = .0375

2 x λ x 3.5 / 1.2 x 10⁻⁴ = .0375

λ = 6428 x 10⁻¹⁰ m

= 643 nm .

A toy rocket is launched straight up by using a spring. The rocket is initially pressed down on the spring so that the spring is compressed by 9 cm. If the spring constant is 830 N/m and the mass of the rocket is 50 g, how high will the rocket fly?

Answers

Answer:

6.86 meters

Explanation:

Let the compression of the string be represented by x, and the height of projection of the toy rocket be represented by h.

So that;

x = 9 cm = 0.09 m

In its rest position (i.e before the launch), the spring has a stored potential energy which is given as;

PE = [tex]\frac{1}{2}[/tex] K[tex]x^{2}[/tex]

    = [tex]\frac{1}{2}[/tex] x 830 x [tex](0.09)^{2}[/tex]

    = 415 x 0.0081

    = 3.3615

The potential energy in the string = 3.36 Joules

Also,

PE = mgh

where: m is the mass, g is the gravitational force and h the height.

m = 50 g = 0.05 kg, g = 9.8 m[tex]s^{-2}[/tex]

Thus,

PE = 0.05 x 9.8 x h

3.3615 = 0.05 x 9.8 x h

3.3615 = 0.49h

⇒ h = [tex]\frac{3.3615}{0.49}[/tex]

      = 6.8602

The height of the toy rocket would be 6.86 meters.

A bag of groceries has a weight of 44 Newton’s. Find it’s mass in kilograms

Answers

Answer:

It's mass would be 4.486768kg..

Now write a short paragraph comparing "fast" to "speeding up quickly" and "slow" to "speeding up slowly".

Answers

Answer:ok yes

Explanation:yes of course

Why would a baseball traveling at 20 m/s have more kinetic energy than a baseball traveling at 5 m/s?

Answers

Answer:

because formula of kinetic energy is K=1/2mv^2 that means more the velocity then more kinetic energy

A dog walks 24 steps north and then walks 55 steps west to bury a bone. If the dog walks back to the starting point in a straight line, how many steps will the dog take and in which direction will the dog walk? On paper, use the graphical method to find the magnitude of the net displacement.

Answers

Answer:

The dog should walk 60 steps to the southeast to return to its starting point.

Explanation:

To solve the present mathematical problem, we must use the Pythagorean theorem. This establishes that in right triangles the sum of their squared legs is equal to the hypotenuse squared, that is:

A ^ 2 + B ^ 2 = X ^ 2

Thus, in the case, the calculation would be the following:

24 ^ 2 + 55 ^ 2 = X ^ 2

576 + 3,025 = X ^ 2

√3,601 = X

60 = X

Therefore, the dog should walk 60 steps to the southeast to return to its starting point.

100 POINTS + BRAINLIEST, HEART, & FIVE STAR.

In the one pully system when you move the mass from the 20 cm mark to the 15 cm mark, it moves 5 cm. How far did you pull the string.

Question 1 options:
5 cm
10 cm
15 cm
20 cm

In the two pully system if you lifted the weight from the 20 cm mark to the 15 cm mark moving 5 cm. How far did you pull the rope down?

Question 2 options:
5 cm
10 cm
15 cm
20 cm

Answers

Answer:

Question 1 the answer is 5 cm for the one pulley system, I just took the quiz

Question 2 is 10 cm

Explanation:

The rope only needs to move 5 cm for the mass to move from 15 to 20.

For the 2 pulley system the string has to move twice as far making it 10 cm. I took the quiz and got 100%

When a person wearing a helmet rides a bicycle, the helmet experiences which type of friction?
A. Fluid
B. Static
C. Sliding
D. Rolling

Answers

Answer:

B

Explanation:

Answer:

B.)Static

Hope I helped

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