Answer:
95.7 degrees
Explanation:
The angle through which the particle rotate in radians is 1.667 rad.
Given the following data:
Radius of circle = 1.50 meterArc length = 2.50 meters.To determine the angle through which the particle rotate in radians:
Mathematically, the angular displacement or arc length in circular motion is given by the formula:
[tex]S=r\theta[/tex]
Where:
S is the angular displacement or arc length.r is the radius.[tex]\theta[/tex] is the angle measured in radians.Making [tex]\theta[/tex] the subject of formula, we have:
[tex]\theta=\frac{S}{r}[/tex]
Substituting the given parameters into the formula, we have;
[tex]\theta = \frac{2.50}{1.50} \\\\\theta =1.667 \;rad[/tex]
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A motorcycle moving 18.8 m/s has
57800 J of KE. What is its mass?
Answer:
m = 327.07 kg
Explanation:
Given that,
Kinetic energy of a motorcycle, E = 57800 J
Velocity of the motorcycle, v = 18.8 m/s
We need to find the mass of the motorcycle. The kinetic energy of an object is given by :
[tex]E=\dfrac{1}{2}mv^2[/tex]
m is mass
[tex]m=\dfrac{2E}{v^2}\\\\m=\dfrac{2\times 57800 }{(18.8)^2}\\\\m=327.07\ kg[/tex]
So, the mass of the motorcycle is 327.07 kg.
The label on a bottle of soda can shows the can contains 397 ml of soda how many litters of soda are in one can
A.)0.397 L
B.)3.97 L
C.)39,700 L
D.)397,000L
Answer:
A
Explanation:
1000ml = 1l
397ml = 0.397l
A 20 kg sled is pulled up a 10m tall hill. What work is done against gravity?
Answer:
1962
Explanation:
w = f × d
= 20×9.81 × 10
= 1962
Suppose the maximum safe intensity of microwaves for human exposure is taken to be 1.00 W/m2 . (a) If a radar unit leaks 10.0 W of microwaves (other than those sent by its antenna) uniformly in all directions, how far away must you be to be exposed to an intensity considered to be safe
Answer:
We must be approximately at least 1.337 meters away to be exposed to an intensity considered to be safe.
Explanation:
Let suppose that intensity is distributed uniformly in a spherical configuration. By dimensional analysis, we get that intensity is defined by:
[tex]I = \frac{\dot W}{\frac{4\pi}{3}\cdot r^{3}}[/tex] (1)
Where:
[tex]I[/tex] - Intensity, measured in watts per square meter.
[tex]r[/tex] - Radius, measured in meters.
If we know that [tex]\dot W = 10\,W[/tex] and [tex]I = 1\,\frac{W}{m^{2}}[/tex], then the radius is:
[tex]r^{3} = \frac{\dot W}{\frac{4\pi}{3}\cdot I }[/tex]
[tex]r = \sqrt[3]{\frac{3\cdot \dot W}{4\pi\cdot I} }[/tex]
[tex]r = \sqrt[3]{\frac{3\cdot (10\,W)}{4\pi\cdot \left(1\,\frac{W}{m^{2}} \right)} }[/tex]
[tex]r \approx 1.337\,m[/tex]
We must be approximately at least 1.337 meters away to be exposed to an intensity considered to be safe.
how do you use vectors daily without realizing it was a vector?
I need help ASAP !!!
Explanation:
Vectors are quantities that has both magnitude and direction. A vector is described in terms of quantity and the direction it is headed.
There are different forms of vectors that are used in our daily life.
When we describe the motion of a car and the direction it is heading, we are simply talking about its velocity which is a vector. When we say James treks 2km from his school to the house everyday, we are simply describing his displacement. When we apply a force to push the table from one corner of the room to another point, is simply a vector When we change position, it is a vector application.An electron traverses a vacuum tube with a length of 2 m in 2 X 10- 4
sec. What is the average speed of the
electron during this time?
Answer:
[tex]v=10^4\ m/s[/tex]
Explanation:
Given that,
The length of a vacuum tube, d = 2 m
Time, [tex]t=2\times 10^{-4}\ s[/tex]
We need to find the average speed of the electron during this time. Average speed is equal to total distance covered divided by total time taken.
Here, total distance = length of the vacuum tube
[tex]v=\dfrac{2}{2\times 10^{-4}}\\\\=10^4\ m/s[/tex]
So, the average speed of the electron is [tex]10^4\ m/s[/tex].
What do all forms of electromagnetic radiation have
in common?
a. Their strength
b. Their speed
c. Their wavelength
d. Their frequency
Answer:
Explanation:
B. Their speed
Answer: b. Their speed
Explanation:
What is the density of an object whose volume is 100 cubic centimeters that has a mass of 100 grams?
Answer:
search omni calculator and these problems can be solved easily:) hope this helps! 62.43
Answer:
1 g/cm3
Explanation:
just had it and this was the answer
A sample contains 10g of radioactive isotope. How much radioactive isotope will remain in the sample after 3 half-lives?
Answer:
After 1 half-life (500 years), 500 g of the parent isotope will remain. After 2 half-lives (1000 years), 250 g of the parent isotope will remain. After 3 half-lives (1500 years), 125 g of the parent isotope will remain. After 4 half-lives (2000 years), 62.5 g of the parent isotope will remain.
Explanation:
A small car of mass 833 kg is parked behind a small truck of mass 1767 kg on a level road. The brakes of both the car and the truck are off so that they are free to roll with negligible friction. A 41 kg woman sitting on the tailgate of the truck shoves the car away by exerting a constant force on the car with her feet. The car accelerates at 1.5 m/s 2 . What is the acceleration of the truck
Answer: the acceleration of the truck a_t is 0.6911 m/s²
Explanation:
Given the data in the question;
There is no external force on the system; net force on the system is 0
Mass of the truck with the woman M = 1767 kg + 41 kg = 1808 kg
mass of the car m = 833 kg
car acceleration a_c = 1.5 m/s²
now let a_t be the acceleration of the truck in opposite direction
Action force on the car = Reaction force on the car
ma_c = Ma_t
a_t = ma_c / M
we substitute
a_t = (833 × 1.5) / 1808
a_t = 1249.5 / 1808
a_t = 0.6911 m/s²
Therefore, the acceleration of the truck a_t is 0.6911 m/s²
A man pushes a 10 kg box a distance of 5 m for 3 hours. How much work
did the man complete?*
Answer:
alot
Explanation:
cuz he pushed for a long time
consider two point charges of 1.60uC and -22.25uC. Determine the magnitude of the force between the two charges when placed 6.50cm apart.
Answer:
[tex]F$\approx$76[/tex]
Explanation:
From the question we are told that
Point charges [tex]q_1=1.60uC[/tex]
[tex]q_2=-22.25uC[/tex]
Displacement [tex]d=6.50cm=>0.065m[/tex]
Generally the equation for Coulomb's law is Mathematically given as
[tex]F=\frac{k*q_1*q_2}{r^2}[/tex]
Therefore
[tex]F=\frac{9*10^9*-22.25*10^-^6*(1.60)*10^-^6}{(6.50*10^-^2)^2}[/tex]
[tex]F=-75.83431953[/tex]
[tex]F$\approx$-76[/tex]
with -(negative) showing form of force Magnitude => [tex]F$\approx$76[/tex]
Explain how scientific knowledge develops through making observations about the natural world. FOR SCIENCE!
Answer number four because it is one of the factors evaluating science
help!!!
middle school physics also please explain :)
Answer:
hope its helps
good luck
Answer:
0.1 cm/s
Explanation:
16 min 40 second = 1000 sec
1m = 100cm
100/1000 = 0.1 (speed = distance/time)
ASAP what causes the earth to orbit just like Mars
Answer:
Like all the planets in our solar system, Earth and Mars orbit the sun. But Earth is closer to the sun, and therefore races along its orbit more quickly. Earth makes two trips around the sun in about the same amount of time that Mars takes to make one trip.
What happens to friction if the velocity is constant? What will it equal to and what formula can be used to find it? Is it Fn = Ff?
Answer:
If the velocity is constant there is no friction it will equal to zero. It is Fn=Ff
Explanation:
How is property belonging to individuals protected under the Fifth Amendment?
By preventing the government from taking property without fair payment.
By preventing a police search of private property without a warrant
By prohibiting the quartering of soldiers without permission
By guaranteeing every citizen the right to apply for a home loan
Answer:
By preventing the government from taking property without fair payment.
Explanation:
Answer 1
Please mark me as brilliant and thank you
Answer:
this is under the wrong section
You and your friends are organizing a trip to Europe. Your plan is to rent a car and drive through the major European capitals. By consulting a map you estimate that you will cover a total distance of 5000 kmkm. Consider the euro-dollar exchange rate given in the introduction and use unit conversion to work through these simple problems.
Required:
a. You select a rental package that includes a car with an average consumption of 6.00 liters of fuel per 100 km. Considering that in Europe the average fuel cost is 1.063 euros/liter, how much (in US dollars) will you spend in fuel on your trip?
b. How many gallons of fuel would the rental car consume per mile?
c. What is the average cost, in dollars per gallon, of fuel in Europe?
Answer:
$383
0.0255
4.83
Explanation:
We're asked to find the total fuel consumed over distance traveled and the cost of given fuel.
To start with, we convert Euro value to USD
Total distance traveled is 5000 km
Average fuel consumption is 6 ltr per 100 km = 0.06 ltr/km
Average fuel cost is 1.063 EUR/ltr
We're going to use a flat rate of 1 EUR to USD = 1.2 USD
To get the total fuel consumption, we use the formula
Total fuel consumption = total distance * average fuel consumption
Total fuel consumption = 5000 km * 0.06 ltr/km
Total fuel consumption = 300 ltr
Finding the total fuel cost, we use the formula
Total fuel cost = total fuel consumption * average fuel cost
Total fuel cost = 300 ltr * 1.063 EUR/ltr
Total fuel cost = 318.9 EUR
Total fuel cost in USD then is, 318.9 EUR × 1.2 USD/EUR
Total fuel cost = 383 USD
b
To convert given fuel consumption to mile per km
Average fuel consumption is 0.06 ltr/km
Conversion rate of Ltr to gal is 1 ltr = 0.264 gal/ltr
Conversion of Km to mile is 1 km = 0.621 mile/km
Going forward, the Average fuel consumption = 0.06 ltr/km * 0.264 gal/ltr ÷ 0.621 mile/km
Average fuel consumption = 0.01584 / 0.621
Average fuel consumption = 0.0255 gal/km
c) to convert given cost of fuel to USD/gal, we say
Average fuel cost is 1.063 EUR/ltr
We'd already stated that the following rates
EUR to USD = 1.2 USD/EUR
Ltr to gal = 0.264 gal/ltr
Average fuel cost = 1.063 EUR/ltr * 1.2 USD/EUR ÷ 0.264 gal/ltr
Average fuel cost = 1.2756 / 0.264
Average fuel cost = 4.83 USD/gal
Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022 kg, respectively
Answer:
[tex]F=1.95\times 10^{20}\ N[/tex]
Explanation:
Mass of Earth, [tex]m_e=5.98 \times 10^{24}\ kg[/tex]
Mass of Moon, [tex]m_m=7.26\times 10^{22}\ kg[/tex]
The distance between Earth and the Moon is, [tex]d=384,400\ km[/tex]
We need to find the force of gravitational attraction between the Earth and the moon. The force of gravity is given by :
[tex]F=G\dfrac{m_em_m}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{5.98 \times 10^{24}\times 7.26\times 10^{22}}{(384400 \times 10^3)^2}\\\\F=1.95\times 10^{20}\ N[/tex]
So, the required force is [tex]1.95\times 10^{20}\ N[/tex].
A 22.0 kg child is riding a playground merry-go- round that is rotating at 40.0 rev/min. What centripetal force must
Answer:
F = 482.51 N
Explanation:
Given that,
Mass of a child, m = 22 kg
Angular velocity of the merry-go-round, [tex]\omega=40\ rev/min[/tex]
Let the radius of the path, r = 1.25 m
We need to find the centripetal force acting on the child. The formula for the centripetal force is given by :
[tex]F=m\omega^2r\\\\=22\times (4.18879)^2\times 1.25\\\\=482.51\ N[/tex]
So, the required centripetal force is 482.51 N.
A 720 g softball is traveling at 15.0 m/s when caught. If the force of the glove on the ball is 520 N, what is the time it takes the ball to stop
Answer:
The time it takes the ball to stop is 0.021 s.
Explanation:
Given;
mass of the softball, m = 720 g = 0.72 kg
velocity of the ball, v = 15.0 m/s
applied force, F = 520 N
Apply Newton's second law of motion, to determine the time it takes the ball to stop;
[tex]F = ma = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{0.72 \ \times \ 15}{520} \\\\t = 0.021 \ s \\[/tex]
Therefore, the time it takes the ball to stop is 0.021 s.
A 1.6-cm-wide diffraction grating has 1000 slits. It is illuminated by light of wavelength 530 nm. What are the angles of the first two diffraction orders?
Answer:
The answer is "[tex]1.96^{\circ} \ and \ 3.94^{\circ}[/tex]"
Explanation:
[tex]N= 1000 \frac{slit}{cm} \\\\\lambda=550 nm\ \ =550 \times 10^{-9} \ m\\\\width=1.6 \ cm[/tex]
We can find the distance between any two adjacent slits by using
[tex]\to d= \frac{1.6}{N}\\\\ \therefore\\ \to d= \frac{1.6}{1000} \ cm= 1.6 \times 10^{-5} m\\[/tex]
We know that the angle of the mth fringe is given by
[tex]\sin \theta_m = \frac{m\lambda}{d}\\\\ \sin \theta_1 = \frac{1\lambda}{d}\\\\\theta_1 = \sin^{-1} \frac{1\lambda}{d}\\\\\theta_1 = \sin^{-1}(\frac{1 \times 550 \times 10^{-9}}{1.6 \times 10^{-5}})\\\\ \theta_1=1.96^{\circ}\\\\[/tex]
Using the same way:
[tex]\sin \theta_2 = \frac{2\times \lambda}{d}\\\\\theta_2 = \sin^{-1} \frac{2\times \lambda}{d}\\\\\theta_2 = \sin^{-1}(\frac{2 \times 550 \times 10^{-9}}{1.6 \times 10^{-5}})\\\\\theta_2=3.94^{\circ}\\\\[/tex]
By using the Huygens formula, the angles of the first two orders are 4 degrees and 8 degrees approximately.
Given that a 1.6cm wide diffraction grating has 1000 slits.
The slit spacing = (1.6 x [tex]10^{-2}[/tex]) / 1000
The slit spacing = 1.6 x [tex]1.6^{-5}[/tex]
Also, it is given that It is illuminated by light of wavelength 530 nm
Sin∅ = nλ/d
When n = 1
Sin∅ = 530 x [tex]10^{-9}[/tex]/1.6 x [tex]10^{-5}[/tex]
Sin∅ = 0.033125
∅ = [tex]Sin^{-1}[/tex] ( 0.033125)
∅ = 1.898 x 2
The angle of the first order = 2∅
2∅ = 4 degrees approximately
When n = 2
Sin∅ = nλ/d
Sin∅ = 2 x 530 x [tex]10^{-9}[/tex]/1.6 x [tex]10^{-5}[/tex]
Sin∅ = 0.06625
∅ = [tex]Sin^{-1}[/tex] ( 0.06625)
The angle of the second order = 2∅
2∅ = 3.7986 x 2
2∅ = 8 degrees approximately
Therefore, the angles of the first two orders are 4 degrees and 8 degrees approximately.
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HELP CORRECTLY FOR BRAINLIEST!!!!! According to the graph, what type of relationship exists between
time and temperature?
50.0
40.0
С
trend line
30.0
Temperature (°C)
20.0
10.0
B
0.0
0
10
40
50
60
20
30
Time (minutes)
O direct
O inverse
O codependent
O equivalent
Answer: direct
Explanation: as the time (independent variable) goes on the temperature drops, it’s cooling down because time is passing by
a person lifts a book 2 meters off the ground using 50 n of force how much work was done
Answer:
100 joules
Explanation:
you cant use this all the time to solve it all the time but 50x2 is 100
A person lifts a book 2 meters off the ground using 50 n of force how much work was done was 100 joules.
What is Work done?When an object is moved across a specific distance by an external force, work is the quantity of energy that is transmitted to the object.
The quantity of energy transmitted to an object through work is referred to as the work done on the thing.
Force on and displacement of the object are the two basic parts of work done on an object. For a force to exert its force along an object's path of motion, the object must be moved along that path. The units of measurement for work, force, and displacement are joules, newtons, and meters, respectively.
Therefore, A person lifts a book 2 meters off the ground using 50 n of force how much work was done was 100 joules.
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a 10.0 kg mass is at the origin. A 20.0 kg mass is 0.500 m to the left of it, and a 30.0 kg mass is 1.25 m to the right of it, what is the net gravitational force on the 10.o kg mass?
? x 10^-8 n
Explanation:
100N please mark me brainliest
What is the acceleration aaa of the refrigerator 4 ss after the person begins pushing on it with a force of 400 NN
Answer:
2 ms^2
Explanation:
Given that the mass of the refrigerator is 200Kg
The net force acting on the refrigerator is 400N
The time takes is 4s
From Newtons's second law of motion;
F =ma
a = F/m
a = 400/200
a = 2 ms^2
This is a constant acceleration
If you travel from Tucson to Argentina, you will see some different constellations in the night sky. true or false
Answer:
its true!!
Explanation: have a nice day !!
Two forces act on a 7.5-kg object. One of the forces is 10.0 N. If the object accelerates at 1.97 m/s2, what is the greatest possible magnitude of the other force
Answer:
24.775N
Explanation:
According to Newton's second law
\sum Fx = ma
F- Ff = ma
F and Ff are the forces acting on the object
m is the mass
a is the acceleration
Given
Ff = 10N
m = 7.5kg
a = 1.97m/s²
Required
F
Substitute the given parameters into the formula
F - 10 = 7.5(1.97)
F-10= 14.775
F= 10+14.775
F = 24.775N
Hence the greatest possible magnitude of the other force is 24.775N
What is the mass of a reindeer (on earth) that has a weight of 623 N
Answer: 140 pounds
Explanation:
Weight on an object on Earth is different from other bodies in space due to the gravity acting on the object.
Gravity on Earth is 9.80665 m/s². A kg on earth is therefore 9.80665 newtons (N).
With a weight of 623, the mass of the reindeer is:
= 623 / 9.80665
= 63.52832 kg
Converting to pounds:
A kilogram is about 2.20462 pounds:
= 63.52832 * 2.20462
= 140 pounds
The angular velocity (in rpm) of the blade of a blender is given in. If θ=0rad at t=0s, what is the blade's angular position at t=20s?
Answer:
θ = 20.9 rad
Explanation:
In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship
w = θ / t
θ = w t
if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians
suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system
w = 10 rpm [tex](\frac{2\pi rad}{1 rev}) ( \frac{1 min}{60 s} )[/tex]
= 1,047 rads
let's calculate
θ = 1,047 20
θ = 20.9 rad