A particle has velocity v⃗1 v → 1 as it accelerates from 1 to 2. What is its velocity vector v⃗2 v → 2 as it moves away from point 2 on its way to point 3?

Answer:

A.46.7mph

B.50mph

Explanation:

We know that from the data given

Julie drove 50 miles at a speed of 38 mph, and another 50 miles for 62mph. Thus , for the first 50 miles, she drove for the following time

T1= distance/speed

====> 50/38= 1.3hrs

the next 50 miles, she drove for

T2= 50/62

= 0.8hrs

So average speed is

Totaldistance/ total time

100/2.1

= 46.7mph

B. Because the time she used driving at 35 mph is the same amount of time she used driving at 65 mph, the average speed is just the average of the two speeds given which is

(50+50)/2 = 50mph

Explanation:

Answer:

46.95 mph

50 mph

Explanation:

first, we start by finding the average speed. The average speed if given by the relation

Average Speed = Total distance / Total Time

from the question, we know that

total distance is 100 mi

total time is time of the first distance + time of the second distance

t = (50mi / 38) + (50mi / 62)

t = 1.32 + 0.81

t = 2.13 hrs

Then, the average speed going to grandmothers house will be

Speed = 100mi / 2.13 hrs

Speed = 46.95 mph

on her return trip

speed on the first distance * half the time + speed on the second distance * half the time

x = V1 * t/2 + V2 * t/2

100 = 38 * t/2 + 62 * t/2

100 = 100 * t/2

t/2 = 100/100

t/2 = 1

t = 2 hrs

The average speed then will be, = 100 mi / 2 hrs = 50mph

0.37 dg

1 dg ....... 100 mg

x dg .........37 mg

x = 1×37/100 = 37/100 = 0.37 dg

Answer:

Condensation

Explanation:

Condensation is the process by which water vapor in the air is changed into liquid water. Condensation is crucial to the water cycle because it is responsible for the formation of clouds.

Answer:

This process is called condensation.

Explanation:

When a cloud becomes full of liquid water, it falls from the sky as rain or snow.

Answer: [tex]v_{rms} =[/tex] 273m/s

Explanation: Root Mean Square Speed of an atom or molecule is the speed of a particle in a gas. It is the average speed a particle in a gas can have.

It can be calculated:

[tex]\frac{1}{2}mv^{2} = \frac{3}{2} k_{B}T[/tex]

[tex]v^{2} = \frac{3k_{B}T}{m}[/tex]

[tex]v = \sqrt{\frac{3k_{B}T}{m}}[/tex]

m is mass of one atom or molecule in kg.

An atom of Arsenic sublimes at 614°C. Converting to Kelvin:

T = 614 + 273 = 887K

Molecular mass of As4 is approximately 0.3kg.

[tex]m = \frac{0.3}{6.10^{23}}[/tex]

[tex]m=5.10^{-25}[/tex]kg

Calculating Root mean square speed :

[tex]v = \sqrt{\frac{3*1.4.10^{-23}*887}{5.10^{-25}}[/tex]

[tex]v = \sqrt{745.08.10^{2}[/tex]

v = 273m/s

The root mean square speed of As4 is approximately 273m/s.

Answer:

The interpretation including its given subject is listed in the subsection below on explanatory.

Explanation:

Homeostasis should be any mechanism of self-regulation from which an individual seeks to preserve equilibrium when adapting to requirements better suited towards its existence.

Two mechanisms are given below:

Answer:

m₂ = 15660 kg

Explanation:

Given that,

Before collision,

Mass of box car 1, m₁ = 8700 kg

Speed of box car 1, u₁ = 14 m/s

Speed of box car 2, u₂ = 0 (at rest)

After collision,

The two stick together and move off with a speed of 5 m/s

Let m₂ is the mass of the second car. As cars stick together, it is a case of inelastic collision. Using the conservation of momentum as follows :

[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\8700\times 14+0=(8700+m_2)5\\\\121800=43500+5m_2\\\\121800-43500=5m_2\\\\m_2=\dfrac{78300}{5}\\\\m_2=15660\ kg[/tex]

So, the mass of the second car is 15660 kg.

Answer:

15000 kg

Explanation:

m1v1+m2v2=(m1m2)Vf

8700(15)=(8700+m)5.5

130500=8700+m(5.5)

130500/5.5=8700+m

130500-8700=m

m=15027.3 kg

Answer:

17.7 lb

Explanation:

Assuming the force is parallel to the incline, draw a free body diagram of the object.  There are 3 forces:

Normal force N pushing perpendicular to the incline,

Weight force mg pulling down,

and applied force F pushing parallel to the incline.

Sum the forces in the parallel direction:

∑F = ma

F − mg sin 45° = 0

F = mg sin 45°

F = (25 lb) sin 45°

F = 17.7 lb

Answer:

The detector temperature doesn't affect retention time

Explanation:

Retention time is one of the chromatographic parameters. Is defined as the time of a compound spends from injection to detection.

A solute in GC is added to the injector where is volatilized. When volatilized, it pass through a column until the detector.

The detector temperature doesn't affect retention time. To change retention time you must change injector temperature or column temperature. An increase in column or injector temperature results in a decrease in retention time.

Answer:

4.8E-19C

Explanation:

Charge is calculated by getting the net sum of protons and electrons

So

87protons - 84electrons= +3

So the charge of the ion is +3

But 1proton= 1.6*10^-19C

So charge will be 3 x 1.6E-19C

4.8x10^-19C

Answer:

The  force is [tex]F_1 = 400.8 \ N[/tex]

Explanation:

From the question we are told that

   The first  diameter is  [tex]d_1 = 4.0 \ cm = 0.04 \ m[/tex]

   The second diameter is  [tex]d_2 = 8.0 \ cm = 0.08 \ m[/tex]

Generally the first area is  

         [tex]A_1 = \pi * \frac{d^2_1 }{4}[/tex]

=>      [tex]A_1 = 3.142 * \frac{0.04^2}{4}[/tex]

=>       [tex]A_1 = 0.00126 \ m^2[/tex]

The  second area is  

     [tex]A_2 = \pi * \frac{d^2_2 }{4}[/tex]

     [tex]A_2 = 3.142 * \frac{0.08^2}{4}[/tex]

     [tex]A_2 = 0.00503 \ m^2[/tex]

For a hydraulic press the pressure at both end must be equal .

Generally  pressure is mathematically represented as

    [tex]P = \frac{F}{A}[/tex]

=>  

   [tex]\frac{F_1}{A_1 } = \frac{F_2}{A_2 }[/tex]

=>   [tex]F_1 = \frac{1600}{0.00503} * 0.00126[/tex]

=>    [tex]F_1 = 400.8 \ N[/tex]

Answer:

A) Beam B carries twice as many photons per second as beam A.

Explanation:

If we have two waves with the same wavelength, then their intensity is proportional to their power, or the energy per unit time.

We also know that the amount of photon present in an electromagnetic beam is proportional to the energy of the beam, hence the amount of beam per second is proportional to the power.

With these two facts, we can say that the intensity is a measure of the amount of photon per second in an electromagnetic beam. So we can say that beam B carries twice as more power than beam A, or Beam B carries twice as many photons per second as beam A.

Answer:

1.25cm

Explanation:

Using

Minimum, as dsinစ = (m+1/2) lambda

Third dark fringe m= 2

dsinစ = (2+1/2)lambda

d(y/L)= (5/2) lambda

Y= 5/2* lambda *L/d

So substituting

=[ (500E-9m)(5m)/0.5E-3] 5/2

=0.0125m

= 1.25cm

Explanation:

Answer:

1 second later the vehicle's velocity will be:

[tex]v(1)= 6\,\,\frac{m}{s} \\[/tex]

5 seconds later the vehicle's velocity will be:

[tex]v(5)=14\,\,\frac{m}{s}[/tex]

Explanation:

Recall the formula for the velocity of an object under constant accelerated motion (with acceleration "[tex]a[/tex]"):

[tex]v(t)=v_0+a\,t[/tex]

Therefore, in this case [tex]v_0=4\,\,\frac{m}{s}[/tex]  and [tex]a=2\,\,\frac{m}{s^2}[/tex]

so we can estimate the velocity of the vehicle at different times just by replacing the requested "t" in the expression:

[tex]v(t)=v_0+a\,t\\v(t)=4+2\,\,t\\v(1)=4+2\,(1) = 6\,\,\frac{m}{s} \\v(5)=4+2\,(5)=14\,\,\frac{m}{s}[/tex]

Answer:

299.4 MeV

Explanation:

For 40 Ar

Number of neutrons = 22

Number of protons= 18

Mass of each proton = 1.007277 amu

Mass of each neutron= 1.008665 amu

Total mass of protons= 18 × 1.007277 amu = 18.130986 amu

Total mass of neutrons = 22 × 1.008665 amu = 22.19063 amu

Total mass of protons and neutrons= 18.130986 + 22.19063 = 40.321616 amu

Mass defect = 40.321616 amu - 40 amu

Mass defect = 0.321616 amu

Since 931 is the conversion factor from amu to MeV

Binding energy = 0.321616 amu × 931 = 299.4 MeV

Binding energy = 299.4 MeV

Answer:

The  values is  [tex]f_b =14.9 \ beats/s[/tex]

Explanation:

From the question we are told that

   The  speed of the fire engine is  [tex]v = 5\ m/s[/tex]

    The frequency of the tone is  [tex]f = 500 \ Hz[/tex]

    The speed of sound in air is [tex]v_s = 340 \ m/s[/tex]

The  beat frequency is mathematically represented as

     [tex]f_b = f_a - f[/tex]

Where  [tex]f_a[/tex] is the frequency of sound heard by the people in the fire engine and is is mathematically evaluated as

   [tex]f_a = [\frac{v_s + v }{v_s -v} ]* f[/tex]

substituting values

  [tex]f_a = [\frac{340 + 5 }{340 -5} ]* 500[/tex]

  [tex]f_a = 514.9 \ Hz[/tex]

Thus  

      [tex]f_b =514.9 - 500[/tex]

      [tex]f_b =14.9 \ beats/s[/tex]

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{see \: below}}}}}[/tex]

Explanation:

[tex] \underline{ \bold{ \sf{To \: prove \: that \: kinetic \: energy = \frac{1}{2} m {v}^{2} }}}[/tex]

Let us consider, a body of mass ' m ' is lying at rest ( initial velocity = 0 ) on a smooth surface. Let a constant force F displaces this body in its own direction by a displacement ' d '. Let 'v' be it's final velocity. The work done ' W ' by the force is given by :

[tex] \sf{W = FD}[/tex]

⇒[tex] \sf{W = m \: \times a \: \times s} \: \: \: \: \: \: \: \: \: ( \: ∴ \: f \: = \: ma \: ; \: s \: = d)[/tex]

⇒[tex] \sf{W = m \: \times \frac{v - u}{t} \times \frac{u + v}{2} \times t \: \: \: \: \: \: \: \: \: (∴ \: a = \frac{v - u}{t} and \: s = \frac{u + v}{2} \times t}[/tex]

⇒[tex] \sf{W = m \times \frac{ {v}^{2} - {u}^{2} }{2} }[/tex]

⇒[tex] \sf{W = \frac{1}{2} m {v}^{2} \: \: \: \: \: \: \: \: \: \: \: \: (since, \: initial \: velocity(u) = 0)}[/tex]

The work done becomes the kinetic energy of the body. Thus, the kinetic energy of a body of mass ' m : moving with the velocity equal to 'v ' is 1 / 2 mv²

∴ [tex] \sf{KE= \frac{1}{2} m {v}^{2} }[/tex]

[tex] \sf{ \underline{ \bold{ {proved}}}}[/tex]

Hope I helped!

Best regards!!

Answer:

54.4ev

Explanation:

Using

E = - me⁴Z²/8Eo²h²n²

Where n= 1

Z= 1

h=6.6E-31Js

me= 9.1x 10-31kg

Eo=8.85E-12m-3 kg-1 s4 A2

So by substituting

E= -(9.1x 10-31kg)⁴x 1²/8(8.85E-12m-3 kg-1 s4 A2)² x (6.6E-31Js)² x 1²

So E= 54.4ev

Answer:

that there would be more clouds.

Explanation:

one of the cycles is precipitation. without water there would be no rain and clouds are what causes the rain to come down

Answer:

it's D or 4 that there would be more clouds

Explanation:

hoped it helped!!

Answer:

False

Explanation:

This is because according to newtons second law which says the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. So take for example a net a net force in opposite direction will cause an object to slow down.

velocity vector here is not the same as acceleration vector

The question is missing. Here is the complete question.

A point charge Q moves on the x-axis in the positive direction with a speed of 160 m/s. A point P is on the y-axis at y = + 20mm. The magnetic field produced at point P, as the charge moves through the origin is equal to  -0.6μT k. What is the charge Q? [tex]\mu_{0}=4.\pi.10^{-7}[/tex]T.m/A)

Answer: Q = [tex]-0.015.10^{-3}[/tex]C

Explanation: Magnetic Field (B) is a vector field, i.e., has magnitude and direction, and describes the distribution of magnetic force in the space around. It happens when an electrical charge is in movement.

Its magnitude is determined by the formula:

[tex]B = \frac{\mu_{0}}{4.\pi}\frac{Qvsin(\theta)}{r^{2}}[/tex]

where

[tex]\mu_{0}[/tex] is the vacuum permeability constant;

r is the distance between charge and a point you want to know the magnetic field;

θ is the angle between velocity and distance r;

For this question, magnetic field has that magnitude when charge is passing through the origin. So, angle between velocity and distance is 90°.

Calculating to determine charge:

[tex]-0.6.10^{-6} = \frac{4.\pi.10^{-7}}{4.\pi}\frac{Q.160.sin(90)}{(2.10^{-2})^{2}}[/tex]

[tex]-0.6.10^{-6} = 10^{-7}\frac{Q.160.1}{(2.10^{-2})^{2}}[/tex]

[tex]-2.4.10^{-10} = Q.160.10^{-7}[/tex]

[tex]Q = \frac{-2.4.10^{-10}}{160.10^{-7}}[/tex]

[tex]Q = -0.015.10^{-3}[/tex]

Charge Q is [tex]-0.015.10^{-3}[/tex]C or [tex]-0.015[/tex]mC.

Answer:

1. 88370.45 N/[tex]m^{2}[/tex]

2. 2500 N.

Explanation:

Pressure, P, is define as the force, F, per unit area, A, applied on/ by an object.

i.e P = [tex]\frac{F}{A}[/tex]

1. The area, A, of the piston of the hydraulic elevator can be determined by;

A = [tex]\pi[/tex][tex]r^{2}[/tex]

where r is the radius of the piston.

A = [tex]\frac{22}{7}[/tex] × [tex](0.3)^{2}[/tex]

  = [tex]\frac{22}{7}[/tex] × 0.09

  = 0.2829 [tex]m^{2}[/tex]

Pressure required to lift a truck of 2500 kg mass can be determined as;

P = [tex]\frac{F}{A}[/tex]

F = W = mg

  = 2500 × 10

  = 25 000 N

So that,

P = [tex]\frac{25000}{0.2829}[/tex]

  = 88370.45 N/[tex]m^{2}[/tex]

The pressure required is 88370.45 N/[tex]m^{2}[/tex].

2. [tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]

 Area of small piston = [tex]\pi[/tex][tex]r^{2}[/tex]

                                   = [tex]\frac{22}{7}[/tex] × [tex](0.03)^{2}[/tex]

                                   = 0.02829 [tex]m^{2}[/tex]

So that,

[tex]\frac{25000}{0.2829}[/tex] = [tex]\frac{F_{2} }{0.02829}[/tex]

[tex]F_{2}[/tex] = 2500 N

The force applied to the small piston is 2500 N.

Answer:

A) W= 200N, B) m = 20.4 kg , C) N = 200 N , D)  F = 100 N ,

E) F_reaction = 200 N , F)  F _net = 40 N

Explanation:

This exercise can be solved using Newton's second law

A) The gravitational force is the weight of the block

          Fg = W = m g

          W = 200 N

B) m = W / g

          m = 200 / 9.8

          m = 20.4 kg

C) Normal is the reaction of the floor to the weight of the block

          N-W = 0

          N = W

          N = 200 N

D) we write Newton's second law on the x-axis

          F - fr = 0

          F = fr

the friction force equation is

         fr = μ_s N

         fr = μ_s W

subtitute

          F = 0.50 200

         F = 100 N

E) As the forces in the natural are in pairs, by Newton's third law or law of action and reaction, the block responds with a force of equal magnitude, but opposite direction

         F_reaction = 200 N

F and G) We write Newton's second law

         F - fr = m a

         fr =  N = μ_k mg

         F - μ_k m g = m a

        μ_k = (F - ma) / mg

        μ_k  = (200 - 20.4 1.96) / 200

        μ_k = 0.8

In general, the coefficient of kinetic friction is lower than the static one

the net force is

       F_net = F -fr = F - μ_k W

       F_net = 200 - 0.8 200

       F _net = 40 N

Answer:

 Q = 80000 cal  

Explanation:

La expresin para el calor es

           Q = m [tex]c_{e}[/tex]ce ΔT

el calor especifico del agua es  ce= 1 cal/gr ºC

la temperatura de ebullición del agua es Ef = 100ºC y partimos de la temperatura ambiente To= 20 OC

           Q = m 1 ( 100 – 20)

            q= 80 m

en el ejercicio no se da la masa de agua, pro podemos suponer,  pote lleva 1 litros  = 100 G

            Q = 80 1000  

            Q = 80000 cal  

Answer:

velocity = 7.7558 m/s

Explanation:

s = u × t

s - distance u - velocity t - time

59 - 12 = (7.98 - 1.92) *u

47 = ( 6.06) u

u = 7.7558 m/s

When a sprinter is running a 100m sprint race. The race begins, and the stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s, then the sprinter's average velocity between the two-time marks would be

The total displacement covered by any object per unit of time is known as velocity. The velocity of an object depends on the magnitude as well as the direction of the object.

the mathematical expression for velocity is given by

velocity = total displacement /time

As given in the problem a sprinter is running a 100m sprint race. The race begins, and the stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s

The total displacement covered by the sprinter

S = 59-12

S= 47 m

The total time is taken by the sprinter

T= 7.98 -1.92

 = 6.06 seconds

Velocity = S/T

             =47/6.06

             =7.75 m/s

Thus. the average velocity of the sprinter would be 7.75 m/s

Learn more about Velocity from here

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Answer:

Current can be induced in a lot of ways. I'll try and list as much of these methods as I can here.

1. Moving a bar magnet relative to a wire coil

2. Moving a wire coil relative to a magnet.

3. Move a wire coil that has electricity flowing though it relative to a wire coil without electricity flowing through it.

4. Moving a current carrying circuit relative to a non-current carrying circuit

5. Rapidly opening and closing the switch of a current carrying circuit beside a non current carrying circuit.  

6. Moving a bar magnet through the middle of a  wire coil.

7. Moving a wire coil through a magnet

8. Moving a circuit relative to a magnetic field.

The main idea is to cause a change in the magnetic field, or to change the available area of the wire loop, or to change the angle between the field and the loop.

Answer:

E) the energy stored will quadrupled

Explanation:

The correct question is

A parallel plate capacitor consists of two square parallel plates separated by a distance d. If i double the potential across the plates, while keeping everything else constant, what happens to the energy stored in the capacitor?

A) There will be 1/4 of the energy stored

B) There will be 1/2 of the energy stored

C) The energy stored will remain constant

D) The energy stored will double

E) the energy stored will quadruple

The initial energy stored in the capacitor [tex]E_{i}[/tex] = [tex]\frac{1}{2}CV^{2}[/tex]

where C is the capacitance

V is the potential difference

If I double this voltage, while holding every other parameters constant, the new energy stored will be

[tex]E_{n}[/tex] = [tex]\frac{1}{2}C(2V)^{2}[/tex] = [tex]\frac{4}{2}CV^{2}[/tex]

[tex]E_{n}[/tex] = [tex]2CV^{2}[/tex]

dividing new energy stored by the initial energy stored, we have

[tex]E_{n}/E_{i}[/tex] = [tex]2CV^{2}[/tex] ÷ [tex]\frac{1}{2}CV^{2}[/tex] = 4

the energy stored will be quadrupled.

Answer:

4.5%

Explanation:

efficiency = energy out / energy in

e = 9.3×10⁴ J / 2.06×10⁶ J

e = 0.045

Answer:

A) f = 1.28x10¹⁵ Hz

B) y = 0.20 m

Explanation:

A) The frequency of light can be found as follows:

[tex] f = \frac{c}{\lambda} [/tex]

Where:

c: is the speed of light = 3.0x10⁸ m/s

λ: is the wavelength

The wavelength can be calculated using the following equation:

[tex] sin(\theta) = \frac{\lambda(m - 1/2)}{d} [/tex]

Where:

m = 3, d = 6 μm, θ = 5.6°        

[tex] \lambda = \frac{d*sin(\theta)}{m - 1/2} = \frac{6 \cdot 10^{-6} m*sin(5.6)}{3 - 1/2} = 2.34 \cdot 10^{-7} m [/tex]      

Now, the frequency is:

[tex] f = \frac{c}{\lambda} = \frac{3.0 \cdot 10^{8} m/s}{2.34 \cdot 10^{-7} m} = 1.28 \cdot 10^{15} Hz [/tex]    

Hence, the frequency of light used for this experiment is 1.28x10¹⁵ Hz.

B) The distance between the second bright fringe and central fringe (y) is:

[tex] tan(\theta) = \frac{y}{D} [/tex]        

[tex] y = D*tan(\theta) = 2 m*tan(5.6) = 0.20 m [/tex]

Therefore, the distance between the second bright fringe and central fringe is 0.20 m.

I hope it helps you!