A parallel beam of α particles with fixed kinetic energy is normally incident on a piece of gold foil. (a) If 100 α particles per minute are detected at 20°, how many will be counted at 40°, 60°, 80°, and 100°? (b) If the kinetic energy of the incident α particles is doubled, how many scattered α particles will be observed at 20°? (c) If the original α particles were incident on a copper foil of the same thickness, how many scattered α particles would be detected at 20°? Note that rhoCu = 8.9 g/cm3 and pAu = 19.3 g/cm.3

Answers

Answer 1

When a parallel beam of α particles with fixed kinetic energy is normally incident on a piece of gold foil,

a) If 100 α particles per minute are detected at 20°, 3.200 α particles, 9.960 α particles, 2048 α particles, 320000 α particles will be counted at 40°, 60°, 80°, and 100° respectively.

b) If the kinetic energy of the incident α particles is doubled, 50.0 alpha particles per minute will be observed at 20.

c) If the same parallel beam of alpha particles with fixed kinetic energy is normally incident on a copper foil of the same thickness, 197.4 alpha particles per minute would be detected at 20°.

In 1911, Ernest Rutherford conducted an experiment in which he bombarded a thin sheet of gold foil with alpha particles and observed their scattering pattern. This experiment provided evidence for the existence of the atomic nucleus and helped to establish the structure of the atom. In this question, we will use the principles of Rutherford scattering to determine the number of scattered alpha particles at various angles for a fixed kinetic energy and for different materials.

(a) The number of scattered alpha particles at an angle θ can be calculated using the Rutherford scattering formula:

dN/dΩ = (N1 * Z2² * e^4)/(16πε0² * E^2 * sin⁴(θ/2))

where dN/dΩ is the number of scattered alpha particles per unit solid angle, N1 is the number of incident alpha particles per unit time, Z2 is the atomic number of the target material, e is the elementary charge, ε0 is the electric constant, E is the kinetic energy of the incident alpha particles, and θ is the scattering angle.

For a fixed kinetic energy, N1 is constant, so we can compare the number of scattered alpha particles at different angles by comparing the values of sin^4(θ/2) for each angle. Using this formula, we can calculate the number of scattered alpha particles at 40°, 60°, 80°, and 100°, given that 100 alpha particles per minute are detected at 20°. The calculations are as follows:

dN/dΩ(20°) = 100 alpha particles per minute

sin^4(20°/2) = 0.03125

dN/dΩ(40°) = dN/dΩ(20°) * sin⁴(20°/2) / sin⁴(40°/2) = 100 * 0.03125 / 0.98438 = 3.200 alpha particles per minute

dN/dΩ(60°) = dN/dΩ(20°) * sin⁴(20°/2) / sin⁴(60°/2) = 100 * 0.03125 / 0.31641 = 9.960 alpha particles per minute

dN/dΩ(80°) = dN/dΩ(20°) * sin⁴(20°/2) / sin⁴(80°/2) = 100 * 0.03125 / 0.01563 = 2048 alpha particles per minute

dN/dΩ(100°) = dN/dΩ(20°) * sin⁴(20°/2) / sin⁴(100°/2) = 100 * 0.03125 / 0.00098 = 320000 alpha particles per minute

(b) If the kinetic energy of the incident alpha particles is doubled, the Rutherford scattering formula becomes:

dN/dΩ = (N1 * Z2² * e⁴)/(16πε0² * 4E² * sin⁴(θ/2))

The number of scattered alpha particles at 20° can be calculated using this formula with N1 doubled. The calculation is as follows:

dN/dΩ(20°) = (2 * 79² * (1.6022 x 10⁻¹⁹)⁴)/(16π(8.8542 x 10⁻¹²)^2 * 4 * (2E6)² * sin⁴(20°/2)) = 50.0 alpha particles per minute.

c) dN/dΩ = (N1 * Z2² * e⁴)/(16πε0² * E² * sin⁴(θ/2)) * (ρAu/ρCu)²

where ρAu is the density of gold and ρCu is the density of copper.

Since the thickness of the foil is the same, we can assume that the number of atoms per unit area is the same for both gold and copper foils. Therefore, N1 is the same for both cases.

Using the given values of ρAu = 19.3 g/cm³ and ρCu = 8.9 g/cm³, the ratio (ρAu/ρCu)²is:

(ρAu/ρCu)² = (19.3/8.9)² = 8.031

Substituting the values of N1, Z2, e, ε0, E, θ, and (ρAu/ρCu)² into the modified Rutherford scattering formula, we can calculate the number of scattered alpha particles at 20° for the copper foil:

dN/dΩ(20°) = (100 * 29² * (1.6022 x 10⁻¹⁹)⁴)/(16π(8.8542 x 10⁻¹²)² * (2E6)² * sin⁴(20°/2)) * 8.031 = 197.4 alpha particles per minute

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Related Questions

What is a Sport car transformation

Answers

Answer:

when a car transforms...

Explanation:

Explanation:

Vivimos en un puente en lo que el diseño de coches se refiere, consecuencia de la gran disrupción de la automación que ocurriría en los próximos años.

6th grade science pls help

Answers

Answer:

D

Explanation:

I hope you get a good grade!

What is the velocity of a 0.8kg ball that has a momentum of 3 kg*m/s?

Answers


The velocity is 3.75

A 1-kg book is at rest on a desk. Determine the force the desk exerts on the book

Answers

Answer:

[tex]\displaystyle F_n = 9.8 \ N[/tex]

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Physics

Forces

SI Unit: Newtons N

Free Body Diagrams

Gravitational Force: [tex]\displaystyle F_g = mg[/tex]

m is mass (in kg)g is Earth's gravity (9.8 m/s²)

Normal Force: [tex]\displaystyle F_n[/tex]

Newton's Law of Motions

Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motionNewton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)Newton's 3rd Law of Motion: For every action, there is an equal and opposite reactionExplanation:

Step 1: Define

1 kg book at rest

Step 2: FBD

See Attachment

Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.

Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).

Step 4: Find Normal Force

Define Forces [Newton's Law of Motions]:                                                 [tex]\displaystyle \sum F = 0[/tex][Newton's Law of Motions] Substitute in forces:                                         [tex]\displaystyle F_g - F_n = 0[/tex][Newton's Law of Motions] [Addition Property of Equality] Isolate [tex]\displaystyle F_n[/tex]:     [tex]\displaystyle F_g = F_n[/tex][Newton's Law of Motions] Substitute in [tex]\displaystyle F_g[/tex]:                                               [tex]\displaystyle mg = F_n[/tex][Newton's Law of Motions] Rewrite:                                                             [tex]\displaystyle F_n = mg[/tex][Newton's Law of Motions] Substitute in variables:                                   [tex]\displaystyle F_n = (1 \ kg)(9.8 \ \frac{m}{s^2})[/tex][Newton's Law of Motions] Multiply:                                                             [tex]\displaystyle F_n = 9.8 \ N[/tex]

An object moving in the air at a constant speed is considered to be in a balanced state. Explain Why

Answers

Answer:

and there is no friction

Explanation:

An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. An object in motion with a velocity of 2 m/s, East will (in the absence of an unbalanced force) remain in motion with a velocity of 2 m/s, East. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force. Objects resist changes in their velocity.

1. How much electrical energy is needed to bring two charges Q1= 5.5 x 10-7C and Q2= 1.7 x 10-6 C from infinity to where they are 1 meter apart.

Answers

Answer:

The electrical energy needed is 8.415*10⁻³ N

Explanation:

Energy is the ability of a body to make changes or work.

By separating or joining two electric charges a distance (for example, a radius r) within their electric fields, you are taking away or giving the electric charges energetic potentials, relative to each other. By releasing these charges, they will attract or repel each other, releasing that acquired electrical energy.

In other words, electric potential energy is linked to the particular configuration of a conglomerate of point charges in a defined system.

That is, it calculates the capacity of an electrical system to carry out a task based exclusively on its position or configuration. So, it is a kind of energy stored in the system, or the amount of energy that it is capable of delivering.

Thus, a charge will exert a force on any other charge and the potential energy is the result of the set of charges.

The electric potential energy that has a point charge q in the presence of another point charge Q that are separated by a certain distance r is:

[tex]Ep=K*\frac{Q1*Q2}{r^{2} }[/tex]

where:

Ep is the electric potential energy. It is measured in Newton (N). Q1 and Q2 are the values ​​of the two point charges. They are measured in Coulombs (C). r is the value of the distance that separates them. It is measured in meters (m). K is the constant of Coulomb's law. For vacuum its value is approximately 9*10⁹ N*m²/C²

In this case:

Q1=5.5*10⁻⁷ CQ2=1.7*10⁻⁶ Cr=1 m

Replacing:

[tex]Ep=9*10^{9}\frac{N*m^{2} }{C^{2} } *\frac{5.5*10^{-7}C *1.7*10^{-6}C }{(1m)^{2} }[/tex]

Solving:

Ep= 8.415*10⁻³ N

The electrical energy needed is 8.415*10⁻³ N

The electrical energy is needed to bring two charges Q1 and Q2 from infinity to where they are 1 meter apart is 8.415 x 10⁻³ N.

What is the electric potential?

An electric potential can be defined as the amount of work or energy needed to move a charge from one point to another against the electrical field.

We know that in order to know electrical energy is needed to bring two charges Q1= 5.5 x 10⁻⁷C and Q2= 1.7 x 10⁻⁶ C from infinity to where they are 1 meter apart, we need to calculate electric potential energy between the two charged particles,

[tex]E_P = k\dfrac{Q_1Q_2}{d^2}[/tex]

Substitute the values,

[tex]E_P = 9 \times 10^9 \dfrac{5.5 \times 10^{-7} \times 1.7 \times 10^{-6}}{1^2}\\\\E_P = 8.415 \times 10^{-3}\rm\ N[/tex]

Hence, the electrical energy is needed to bring two charges Q1 and Q2 from infinity to where they are 1 meter apart is 8.415 x 10⁻³ N.

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An outfielder throws a baseball to home plate with a velocity of 27 m/s at 35o. It is caught by the first baseman. How long was it in the air

Answers

Answer:

Explanation:

Initial velocity of the ball = 27 m /s .

Its vertical component = 27 sin 35 = 15.48 m /s

Considering vertical displacement to the top point ,

initial velocity u = 15.48 m /s

acceleration due to gravity g = 9.8 ,

velocity at the top v = 0

v = u - gt  

0 = 15.48 - 9.8 t

t = 15.48 / 9.8 = 1.579 s

So time of ascent = 1.579 s

Similarly , time of descent = 1.579

Total time of flight = 2 x 1.579

= 3.16 s

An island reports that in the year 2000 there were 240 babies born. That same year, 100 individuals died.
What is the growth rate for this island?(Show your work and indicate if it is positive or negative.)

Answers

Answer:

+ 140

Explanation:

You can show the natural growth rate by subtracting the death rate from the birth rate during one year and converting this into a percentage.

Here it would be:

240 - 100 = + 140

// if you want to convert it to percentage, you need to know the size of the population

it would be

140 / (population size) * 100 %

Theoretically, what would be the mass of an object accelerated
to 100% the speed of light?

Answers

I know most of the answers will say infinity, but still this needs deeper look about its physical meaning and does it consider a practical logic?

Infinity usually used for something we could not measure, however the reality may be different!

The denominator of the equation would become 0 and the mass would become infinite if the mass's velocity ever surpassed the speed of light.

Speed of light and mass:

The amount of energy needed to accelerate an infinite mass would be infinite as well. The fact that light travels at the speed of c indicates that it has no rest mass.

When a mass particle approaches the speed of light, its energy grows and becomes infinite at that speed, which is why it can never be accelerated to that speed.

Experiments have confirmed this, and it has been demonstrated that nothing goes faster than the speed of light.

Find out more information about 'Speed of light'.

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how was youll day still in school by the way.

Answers

My day is alright! I just finished school for the day.. and I’m excited for the weekend! How was your day?

A horse has a momentum of 25 kg*m/s and a velocity of 2.5 m/s. What is the horse mass?

Answers

Answer:  10 kg

==================================================

Work Shown:

We have these variables

p = momentum = 25 kg*m/sm = mass = unknownv = velocity = 2.5 meters per second

Solving for the mass gets us...

p = m*v

25 = m*2.5

25/2.5 = m

10 = m

m = 10

The mass of the horse is 10 kg.

How many straight edges does a cube have

Answers

12 is correct

Explanation: it's a cube

Answer:

12

Explanation:

What is the only part in our body we do not stretch?

Answers

Answer:

The quadriceps consists of four muscles: the skinny rectus femoris and the three huge “vasti” — vastus lateralis/intermedius/medialis. The vasti are only elongated by knee flexion, which is limited to about 120˚ when the calf hits the hamstrings. The vasti cannot be stretched strongly.

Answer:Masseter and temporalis

Why it’s unstretchable: The jaw can only open so far.

Why it’s a dang shame: Jaw tension is epidemic, and trigger points in these muscles cause a wide array of strange face and head pains, including toothaches, headaches, and earaches.

Determine the amount of work you would need to do in order to stop a 1100kg car with 1400J of kinetic energy.

Answers

Answer:

 W = -1400 J

Explanation:

Let's use the relationship between work and kinetic energy

           W = ΔK

             

kinetic energy is

            K = ½ m v²

therefore in this case

             K₀ = 1400 J

         

Thus

            W = 0 -1400

            W = -1400 J

The negative sign indicates that the work is done against the energy, that is, in the opposite direction to the movement

The acceleration of an object is ____________________ related to the net force exerted upon it and _____________________ related to the mass of the object.

Answers

The acceleration of an object is directly related to the net force exerted upon it and inversely related to the mass of the object.

An object with a mass 4.0 kg has a momentum of 64 kgm/s . How fast is the object traveling ?

Answers

Answer:

The object will travel at the speed of 16 m/s.

Explanation:

Given

Mass m = 4.0 kg Momentum p = 64 kgm/s

To determine

How fast is the object traveling?

Important Tip:

The product of the mass and velocity of an object —  momentum.

Using the formula

[tex]p = mv[/tex]

where

m = massv = velcityp = momentum

Thus, in order to determine the speed of the object, all we need to do is to substitute p = 64 and m = 4 in the formula

[tex]p = mv[/tex]

[tex]64\:=\:4\times v[/tex]

switch the equation

[tex]\:4\times \:v\:=64[/tex]

divide both sides by 4

[tex]\frac{4v}{4}=\frac{64}{4}[/tex]

simplify

[tex]v=16[/tex] m/s

Therefore, the object will travel at the speed of 16 m/s.

A 100-newton object is lifted 100 meters in 100 seconds. What is the
power generated in this situation?

Answers

Power equation: Work / time

Work = F * distance
W = 100N * 100

10000 / 100 = 100

The power generated is 100 watts.

Guys please help me I am dead confused

Answers

Answer:

A

Explanation

The diagram in A. contain a variable resistor which can be use to vary the pd from the 6v battery


A ray diagram shows an object placed between 2F and F of a convex lens.

The image produced is
smaller than the object.

upright.

larger than the object.

virtual

Answers

Answer:

larger than object

Explanation:

the image formed will be on the opposite side of lens and magnified

Answer:

C

Explanation:

Light described as what two things?

Answers

Answer:modeled as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field.

Explanation:

Two charged spheres 10 cm apart attract each other with a force of 3.0 x 10^-6 N. What electrostatic force will result if both charges are doubled and the distance remains the same?

Answers

Answer:

The electrostatic force that will result if both charges are doubled and the distance remains the same is 6.0 * 10⁻⁶ N

Explanation:

Coulomb's law of  electricity states that the magnitude of the force of attraction or repulsion between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance of of separation between them.

In formula; F = KQ₁Q₂/d²

Using the formula for electrostatic force of attraction above to determine the force of between the two charged spheres

Let the charges be Q₁ and Q₂; distance of separation be d, K is a constant

Initially, F₁ = KQ₁Q₂/d² ---- (1)

F₁ = 3.0 * 10⁻⁶ N

when the charges are doubled, Q₁ = 2Q₁; Q₂ = 2Q₂; K and d remains constant

F₂ = 2KQ₁Q₂/d² ----(2)

Dividing equation (2) by (1) to find the ratio of their forces

F₂/F₁ = (2KQ₁Q₂/d²) / KQ₁Q₂/d²

F₂/F₁ = 2

Thus, F₂ is twice F₁.

Since F₁ = 3.0 * 10⁻⁶ N; F₂ = 2 * 3.0 * 10⁻⁶ N

F₂ = 6.0 * 10⁻⁶ N

Therefore, the electrostatic force that will result if both charges are doubled and the distance remains the same is 6.0 * 10⁻⁶ N

Electrostatic force is a force imposed by one charge on another as a result of the field.Electrostatic force will  be 12.0 x 10⁻⁶ N if both charges are doubled and the distance remains the same.

What is the electrostatic force?

It is a force imposed by one charge on another as a result of the field.

The electrostatic force produced by one line charge on another line charge separated by distance d is determined by the charge potency of each charge as well as the separation distance between them.

Hence the electrostatic force is given by  

[tex]\rm F=\frac{Kq_1q_2}{d^2}[/tex]

The given data in the question ,

d is the distance between the charge

F₁ is the electric force for case 1= 3.0 x 10⁻⁶ N

F₂ is the  electric force for case 2= ?

Conditions for case 2;

(q₁=2q₁),(q₂=2q₂),d₂=d₁

For case 1,

[tex]\rm F_1=\frac{Kq_1q_2}{d_1^2}[/tex]

For case 2,

[tex]\rm F_2=\frac{K(2q_1)(2q_2)}{d_1^2}[/tex]

[tex]\rm F_2=4\times\frac{Kq_1q_2}{d_1^2}\\\\\rm F_2=4F_1[/tex]

[tex]\rm F_2=4\times\frac{Kq_1q_2}{d_1^2}\\\\\rm F_2=4\times3.0\times 10^{-6}\\\\\rm F_2=12.0\times10^{-6}[/tex]

Hence electrostatic force will be 12.0 x 10⁻⁶ N.  if both charges are doubled and the distance remains the same.

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15. Which of the following is the correct electron configuration for neon (10Ne)?
A. 1s 2s22p
C. 184 2s2 3s2 2p?
B. 1s 2s2 3s2 2p4
D. 152 282 3s2p5​

Answers

Answer:

1s2,2s2,2p6 or (He) 2s2 2p6

pls help i’ll give brainliest if you give a correct answer!!

Answers

Answer:

C. The distance traveled by an object at a certain velocity.

Explanation:

YW!

Answer:

third option is the most accurate

In a bar magnet the magnetic force seems to come from each end. The ends of a bar magnet are
called the___
What one word completes the sentence?

Answers

Answer: poles

North Pole and South Pole? I hope this help

the unit of acceleration is derived unit why​

Answers

Answer:

Mass is a base unit, acceleration is a derived unit calculated as a function of length and time which are both base units. Any unit definition that is a function of more basic units is considered a derived unit.

Is it resistant to mud fire ​

Answers

Dirt that you can not burn typically does no longer have any materials that are flammable at decrease temperatures. Mostly due to the fact it is full of water and non-burnable minerals. But a lot of what's in grime can certainly burn if it is dried. Dirt is made of many unique things.

yes

Explanation:

since they are extremely dense they lack the ability to trap air due to its structure

balance the equation
P + 02 → P205 ​

Answers

Answer:

4P + 502 → 2P205

Explanation:

Hence the above equation is balanced.

Explanation:

[tex] \underline{ \underline{ \large{ \text{Given \: chemical \: equation}}}} : [/tex]

[tex] \tt{P \: + O _{2} \: \: \: \: ➞ \: \: P_{2} \: O_{5}}[/tex]

Here , Multiply P2O5 by 2 and O2 by 5 to equalize oxygen :

[tex] \tt{P+ 5O_{2} \: \: ➞\: \: 2P_{2} \:O_{5}}[/tex]

Now , To equalize P atoms , Multiply P by 4

[tex] \boxed{ \large{\tt{ 4P + 5O _{2} \: ➞ \: \: \: \: 2P_{2} \: O_{5}}}}[/tex]

Here , On the left side we have 4P and On the right side ,we have 4P. Again , On the left side , we have 10 O and On the right side , we have 10 O. And yippie , we got the balanced chemical equation !!!

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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A concrete dam holds back a large reservoir of water
potential or kinetic energy

Answers

Answer:

The water in a reservoir behind a hydropower dam is another example of potential energy. The stored energy in the reservoir is converted into kinetic energy as the water flows down a large pipe called a penstock and spins a turbine.

Explanation:

Hope this helps :))

A concrete dam holds back a large reservoir of water potential energy, the stored potential energy is converted into the kinetic energy which is converted into mechanical energy and then further converted into electrical energy.

What is hydropower?

A dam or other construction that alters the natural flow of a river or other body of water is used to generate hydropower, often known as hydroelectric power.

In order to generate energy, hydropower uses the perpetual, never-ending water cycle, which uses water as a fuel and leaves no waste products behind. Although there are many different kinds of hydropower plants, they are always propelled by the kinetic energy of water moving downstream.

Thus, a concrete dam holds back a large reservoir of water potential energy.

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If Jay pushes on a box with a force of 20 N to the right and Bradley pushes on a box with a force of 15 N to the left, what is the net force on the box?

Answers

Answer:

Net force = 5N

Explanation:

Jay = 20N to the right

Bradley = 15N to the left

To find the net force;

Since the forces are being applied to the box in opposite direction i.e acting in opposite direction, we would subtract them.

Net force = 20 - 15

Net force = 5N

Therefore, the net force on the box is 5 Newton.

A hockey puck, with an initial velocity of 65 km/h [W], ricochets off the boards. After 0.76 s in contact with the boards, its final velocity is 47 km/h [E]. Determine the acceleration of the puck.

Answers

Answer:

 a = 40.937 m / s²

Explanation:

For this exercise let's use the relationship between momentum and momentum variation

          I  = Δp

          F t = m v_f - mv₀

          F = m (v_f -v₀) / t

let's reduce the magnitudes to the SI system

          v_f = 47 km / h (1000m / 1 km) (1h / 3600 s) = 13.056 m / s

          v₀ = - 65 km / h = -18.056 m / s

the negative sign is bearing the speed is west

let's calculate

          F = m (13.056 + 18.056) / 0.76

          F = m 40.937

now we can use Newton's second law

          F = m a

          m 40.937 = m a

          a = 40.937 m / s²

Other Questions
Jada biked 35 kilometer and then stopped to adjust her helmet. She biked another 12 kilometer and stopped to drink some water. Jada has to bike a total of 3 kilometers. How many more kilometers does Jada have to bike? Modify the program to print the U. S. Presidential election years since 1792 to present day, knowing such elections occur every 4 years. Don't forget to use LOW GDP is not necessarily an indicator of an economy in poor health. For one thing, a ___country may have a low GDP but a high ______ For another thing, an economy with a low GDP but a strong ____ is healthier than an economy with a comparable GDP that is stagnant or declining. A. nominal GDP growth rate B. largeC. wealthyD. real GDP growth rate E. inflation rate Due to _, government outlays have risen quickly since 2000.a.less tax revenueb.an aging populationc.increased government borrowingd.economic expansione.lower interest payments on current government debt An increase in production in the short run definitely results in an increase in:a.) Average total costsb.) Marginal costsc.) Total costsd.) Average fixed costs ind the taylor series for f centered at 9 if f (n)(9) = (1)nn! 8n(n 1) . [infinity] n = 0 what is the radius of convergence r of the taylor series? r = the primary purpose of a turbine in a fluid loop is to Whenever a changing magnetic field is present there is another perpendicular field, what is that field? QS bisects RQT and RST. Complete the proof that QRSQTS. Q11Read the text from the 1920 Treaty of Versailles."The High Contracting Parties,In order to promote international co-operation and to achieve international peace and securityby the acceptance of obligations not to resort to war,by the prescription of open, just and honourable relations between nations,by the firm establishment of the understandings of international lawandby the maintenance of justice and a scrupulous respect for all treaty obligationsAgree to this Covenant of the League of Nations."How is this excerpt from the Treaty of Versailles similar to the contents of Roosevelts radio address? A. It highlights the necessity of nations respecting treaty obligations. B. It addresses the desire of countries for peace among nations. C. It emphasizes the need for nations to adhere to international law. D. It describes a way to promote international peace and security. What is the easiest, most practical measurement performed during troubleshooting? A) resistance B) power C) voltage D) current In the short run, a firm should operate when it is losing money, so long as the firms marginal revenue is above average variable cost. In this situation, continued operation enables a firm to cover all of its variable cost and some of its fixed cost with any remaining revenue.(If the company cannot cover all of its variable cost, it is losing more money by continued operation than by shutting down in the short run. This situation is described in the last line of the table.) ANSWER GETS 100 POINTSWhich of the following statements about dealing with stressors is true? A. Adults should model good stress management. B. Children aren't affected by stressors. C. Stressors decrease as children age. D. Resilience can increase stressors. Dense Company's income statement showed revenues of $275,000 and operating expenses of $135,000. Accounts receivable decreased by $40,000 and accounts payable increased by $35,000 during the year. Compute cash receipts from customers and cash payments for operating expenses using the direct method.Cash receipts from customers $Cash payments for operating expenses $ light of wavelength 695 nm enters a slab of glass (=1.50). a. what is the frequency of the light in the air (n=1.00)? when two solid spheres of the same material and same radius r are in contact, the magnitude of the gravitational force each exerts on the other is directly proportional to Darnel made 4 1/2 quarts of hot chocolate. Each mug holds 3/4 of a quart. How many mugs will Darnel be able to fill? Write your answer as a fraction or as a whole or mixed number. The following information is from the records of Armadillo Camera Shop:Accounts receivable, December 31, 2017$81,000 (debit)Net credit sales for 2017160,000Accounts written off as uncollectible during 201717,000Cash sales during 2017 41,000The company uses the direct writeminusoff method for bad debts. What is the amount of bad debts expense?A. $62,000B. $41,000C. $17,000D. $81,000 the firm increased the price of its product, but its revenue collected from the sales of the product fell. this leads us to conclude that the demand for the firm's product is Determine the average profit generated by orders in the ORDERS table. Note: The total profit by order must be calculated before finding the average profit.To perform these assignments, refer to the tables in the JustLee Books database.