A motorcycle, which has an initial linear speed of 9.7 m/s, decelerates to a speed of 4.0 m/s in 4.4 s. Each wheel has a radius of 0.61 m and is rotating in a counterclockwise (positive) directions.
What is (a) the constant angular acceleration (in rad/s2) and (b) the angular displacement (in rad) of each wheel?

Answers

Answer 1

Hi there!

We can begin by solving for the linear acceleration as we are given sufficient values to do so.

We can use the following equation:

vf = vi + at

Plug in given values:

4 = 9.7 + 4.4a

Solve for a:

a = -1.295 m/s²

We can use the following equation to convert from linear to angular acceleration:

a = αr

a/r = α

Thus:

-1.295/0.61 = -2.124 rad/sec² ⇒ 2.124 rad/sec² since counterclockwise is positive.

Now, we can find the angular displacement using the following:

θ = ωit + 1/2αt²

We must convert the initial velocity of the tire (9.7 m/s) to angular velocity:

v = ωr

v/r = ω

9.7/0.61 = 15.9 rad/sec

Plug into the equation:

θ = 15.9(4.4) + 1/2(2.124)(4.4²) = 20.56 rad


Related Questions

What is friction ??? ​

Answers

Answer:

Frictional force is produced when two bodies are rubbed against each other. It is the force that oppose the motion and therefore it stops or slow down a moving body.It depends upon the roughness or smoothness of the surface of the body in contact.Rough surface have more friction that the smooth surface. Similarly, the heavier body produces more friction than a lighter body. Frictional force acts in the opposite direction of the motion of the body.

A 0.015 kg marble sliding to the right at 0.225 m/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg marble moving to the left at 0.180 m/s. After the collision, the first marble moves to the left at 0.180 m/s. Find the velocity of the second marble after the collision.

Answers

Explanation:

[tex]if \: the \: masses \: of \: the \:two \: marbles\: equal \\ then \: each \: velocity \: sharing \: with \: other \: velocity[/tex]

A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resistance

Answers

Explanation:

The power P dissipated by a heater is defined as

[tex]P = VI[/tex]

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

[tex]I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}[/tex]

b) The resistance R of the heater is

[tex]P = VI = (IR)I = I^2R[/tex]

where [tex]V= IR[/tex] is our familiar Ohm's Law.

[tex]\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}[/tex]

[tex]R = 110.8\:Ω[/tex]

The current running through the heater when it is operating is 1.08 A.

The resistance of the heater is 110.8 ohm.

What is current?A current is a flow of Charges.The formula of current is , current I = power P / voltage VThe SI unit of current is ampere A.

So, from the above equation we can calculate,

              current I = P/V

                      ∴   I = 130 / 120

                      ∴   I = 1.08 A

What is resistance?The resistance is a quantity which oppose the current flow in a circuit.The formula of resistance is ( in the terms of power P and ohm's law V=IR )  resistance R = P/I^2.The SI unit of resistance is ohm.

So, from the equation we can calculate,

                   Resistance R = P/I^2

                                  ∴  R = 130/(1.08)^2

                                  ∴  R = 110.8 ohm

Thus, the current running through the heater when it is operating is 1.08 A.

The resistance of the heater is 110.8 ohm.

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A load of 250 kg is hung by a crane's cable. The load is pulled by a horizontal force such that the cable makes a 30 angle to the vertical plane. If the load is in the equilibrium, calculate the magnitude of the tension in the cable​

Answers

Answer:

1250[tex]\sqrt{3}[/tex]

Explanation:

Let's look at this in a simple manner, because it is.

The crane weights 250Kg. Okay.

Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)

Since F = m * a

F = 250 * 10

F = 2500

Now we know that the downward Force is 2500N.

To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be [tex]\frac{\sqrt{3}}{2}[/tex].

Therefore, the force pulling the box in the cable's direction is:

[tex]\frac{2500\sqrt{3} }{2} = 1250\sqrt{3}[/tex]

If you have any questions feel free to comment.

Have a great one and mark brainliest if it helped, please

‏Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per day? a) 1.25 O b) 1.5 c) 1 O d) 2
I think the answer is a but I'm not sure I'm really a little confused I want to check with this app please can someone heelp me

Answers

Answer:

c

Explanation:

It really depends on what the stuff is. This should not be a math or physics question.

Having said that, I answer it by rounding it to 1.       1.04 is closest two one.

That is not entirely a satisfactory answer. Most people who take medications have pill splitters. They easily cut a pill in half. They can do this only if a the medicine's directions, or a pharmacist, or a doctor tells you can do this. Cutting it into quarters should never be done.

So a is really incorrect medically.

1.5 is too far away

C is probably the intended answer; it would annoy me no end if it was anything but c. If this was just a rounding question, it rounds to c. There is no medication that requires an intake of 1.04. No one could get that kind of accuracy.

2 is really too far away.

During a picnic, you and two of your friends decide to have a three-way-tug-of-war, with three ropes in the middle tied into a knot. Roberta pulls to the west with 277 N of force; Michael pulls to the south with 603 N. a) With what force should you pull to keep the knot from moving

Answers

Answer:

Explanation:

I'm not 10% sure but i think that if you were to do:

603 + 277 = 880

1000 - 880 = 120

So to keep it from moving, i think you would need to pull with a force of 120N

The force with which it should be pulled to keep the knot from moving is 663.58 N.

What is Newton's third law ?

Newton's third law states that, for every action, there is an equal and opposite reaction.

Here,

Force exerted by Roberta, F₁ = 277 N

Force exerted by Michael, F₂ = 603 N

Since, Roberta is pulling to the west and Michael is pulling towards the south, the angle between the forces applied by them is 90°.

The force needed to keep the knot from moving is the resultant force of these two forces.

Therefore, the resultant force,

Fₙ = √F₁² + F₂²

Fₙ = √(277)² + (603)²

Fₙ = 663.58 N

Hence,

The force with which it should be pulled to keep the knot from moving is 663.58 N.

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Youssef and Sophia are driving in two different cars and not paying attention to their surroundings. Youssef approaches an intersection moving 11 m/s East while Sophia approaches the same intersection moving 13.5 m/s North. Both speeds are measured relative to the ground. When Youssef is 220 m from the intersection, Sophia is 275 m from the intersection. Do the two cars collide when they reach the intersection

Answers

Answer:

I think  E--

Explanation:

question below................

Answers

Answer:

do your work why you in class and you would know

Explanation:

can you classify matter based on chemical properties

Answers

Answer:

Explanation:

Matter can be broken down into two categories: pure substances and mixtures. Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. A chemical substance is composed of one type of atom or molecule.

How long do elephants live?

Answers

65 years but anything can happen to them
I’m not really sure but I hope this helps
The average lifespan of an elephant is 60-70 years

The current in the long wire is decreasing. What is the direction of the current induced in the conducting loop below the wire

Answers

Answer:

anlatamadım herkeze ben sorulara bakamiyorum cumku analmaiyirum yardim edin

bu sorunu nasil cozebilirim

lutfsn...

¿Por qué el origen de ciertos metales se relaciona con la dinámica terrestre?

Answers

Yo no hablo espanol

Which statement about reversible reactions is correct?(1 point)

They are always at equilibrium.
They are always at equilibrium.

The forward and reverse reactions must happen at the same rate.
The forward and reverse reactions must happen at the same rate.

They can occur in either direction.
They can occur in either direction.

They always involve gases.
They always involve gases.

Answers

Answer:

I think the answer would be C

C = They can occur in either direction.

Explanation:

the answer is C. They can occur in either directions

You apply the same force to two objects. Object 1 has mass M and object 2 has mass 5M. The acceleration of object 2 is

Select one:

a. one-fifth as that of object 1.


b. ten times that of object 1.


c. has no relation to that of object 1.


d. the same as that of object 1.


e. five times that of object 1.

Answers

five times that of object l

TRUE OR FALSE! PLZ HELP

Magnitude is a measure of how strong a force is.

A. True
B. False

Answers

Answer:

True

Explanation:

Magnitude is the "value" the greater the value the greater the force is and vice versa

Answer:

TRUE

Explanation: I did the test

Hope this helps

50 points please help ASAP! !

What is the average velocity of an object that moves from 6 meter to 2 meter relative to origin in 2 second?

Answers

Total Displacement=6-2=4mTime=2s

[tex]\\ \rm\rightarrowtail Avg\: velocity=\dfrac{Total\: Displacement }{Total\: time}[/tex]

[tex]\\ \rm\rightarrowtail Avg\: velocity=\dfrac{4}{2}=2m/s[/tex]

Suppose that you release a small ball from rest at a depth of 0.590 m below the surface in a pool of water. If the density of the ball is 0.370 that of water and if the drag force on the ball from the water is negligible, how high above the water surface will the ball shoot as it emerges from the water? (Neglect any transfer of energy to the splashing and waves produced by the emerging ball)

Answers

Answer:

Explanation:

The work of the buoyancy force will convert to gravity potential energy

Fresh Water has a density of 1000 kg/m³

The ball has a density of 370 kg/m³

assume the ball is 1 m³

weight of the ball is 370g

The buoyancy force is 1000g

Assume the buoyancy force drops suddenly to zero when the center of the ball clears the water level.

The Work done on the ball is

W = Fd = 1000g(0.590)

the change in potential energy is

PE = mgh = 370g(0.590 + y)

where y is the height above the water level.

1000g(0.590) = 370g(0.590 + y)

1000(0.590) = 370(0.590 + y)

y = (0.590)(1000 - 370) / 370

y = 1.004594... ≈ 1.00 m

The same type of engine is placed in iwo different airplanes The first airplane is twice as heavy as the second suchane Wrich
statement is correct about the mass of the airplane and its acceleration, assuming a constant not forest (1 point)
Increasing the acceleration of the airplane causes the enging to provide more force
Decreasing the mass of the airplane will result in the airplane accelerating loss
O Decreasing the mass of the airplane will result in the airplane accelerating more
increasing the acceleration of the airplane causes the engine to provide les force

Answers

Answer:

Explanation: If the engines in both of the airplanes are at the same Weight  then The engines in both of the airplanes would stil have the same mass because mass stays the same everywhere

Since mass is constant everywhere, if the engines in both airplanes are at the same weight, the engines in both airplanes would still have the same mass.

What is Weight?

Weight is the force an object exerts, mass is the amount of matter that makes up an object. Newton is the SI unit of weight while kilogram is the SI unit of mass.

Given that in question the same type of engine is placed in two different air-planes The first air-plane is twice as heavy as the second Suchane Wrich statement is correct about the mass of the air-plane and its acceleration, assuming a constant net force.

Increasing the acceleration of the air-plane causes the enging to provide more force.

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Two students were climbing stairs at school. Student 1 has a weight of 700 N. Student 2 has a weight of 650 N. How much power would each student have if each took 6 s to climb a 4 m tall flight of stairs?

Student 1 would have 4200 W, and Student 2 would have 3900 W of power.

Student 1 would have 116 W, and Student 2 would have 108 W of power.

Student 1 would have 2800 W, and Student 2 would have 2600 W of power.

Student 1 would have 467 W, and Student 2 would have 433 W of power.

Answers

Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.

From the question,

We are to calculate the power each student would have to climb the flight of stairs.

Power can be calculated using the formula

[tex]P = \frac{F \times d}{t}[/tex]

Where

P is Power

F is the force

d is the distance

and t is the time

NOTE: The weight of the students represent the force

For student 1

F = 700 N

d = 4 m

t = 6 s

∴ [tex]P = \frac{700 \times 4}{6}[/tex]

P = 467 W

For student 2

F = 650 N

d = 4 m

t = 6 s

∴ [tex]P = \frac{650 \times 4}{6}[/tex]

P = 433 W

Hence, Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.

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If work stays the same and the distance is increased, then less force is needed to do the work.
True
False

Answers

Not sure what “work” defines but from my understanding I’d go with false.

Answer:

False

Explanation:

This is because the work is the same so the force won't change

A pumpkin is shot upwards at a speed of 15.5 m/s from the ground and lands on a 3.00m
high platform. How long before it hits and smashes?

Answers

Answer:

0.2seconds

Explanation:

Speed=distance/time

15.5m/s=3.00m/x seconds

x=3/15.5

x=0.1935

x=0.2sec

hope this helped

A Projectile of mass 0.277 kf is shot from a cannon. The end of the cannon's barrel is at heiht 6.8 m. The initial velocity of the projectile has a horizontal component of 6.1 m/s. The projectile rises to a maximum height above the end of the cannon's barrel and strikes th ground a horizontal distance past the end of the cannon;s barrel. What is the time it takes for the projectile to reach its maximm height? The acceleration of gravity is 9.8 m/s^2.

Answers

Ms2 is the answer to this Q

The time taken by  the projectile to reach its maximum height is 0.62 second.

Given parameters:

Horizontal component of initial velocity of the projectile: [tex]u_x[/tex] = 6.1 m/s.

To reach maximum height, the projectile should be throwed in 45 degree. So, vertical component of initial velocity of the projectile: [tex]u_y[/tex] = 6.1 m/s.

Given,  The acceleration of gravity is 9.8 m/s².

At maximum height the vertical component of velocity of the projectile becomes zero due to acceleration due to gravity acts downwards.

So, from formula [tex]v_y[/tex] = [tex]u_y[/tex] - gt; we can write:

0 = 6.1 - 9.8t

⇒ t = 6.1/9.8 = 0.62 s.

Hence, the time taken by  the projectile to reach its maximum height is 0.62 second.

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