A mixture of purple paint contains 6 teaspoons of red paint and 15 teaspoons of blue paint. To make the same shade using the 35 teaspoons of blue paint, how much red paint would you need? Complete the double number line below to find the amount of red paint and circle this ratio.

Answers

Answer 1

Answer:

87.5 teaspoons

Step-by-step explanation:

Given that a mixture of purple paint contains 6 teaspoons of red paint and 15 teaspoons of blue paint.

So, Purple paint : Blue paint =  6 :15

To make the same shade the ratio of purple and blue paint must be the same.

In the new mixture, the amount of purple paint =35 teaspoon.

let the amount of red paint =x teaspoon.

So, in the new mixture,

Purple paint : Blue paint =  35 : x

So, to make the same shade, the ratio of purple and red paint must be the same, i.e

35 : x =  6 :15

[tex]\Rightarrow \frac {35}{x}=\frac{6}{15}[/tex]

[tex]\Rightarrow x={35\times15}{6}=87.5[/tex]

Hence, 87.5 teaspoons of red paint required to mix with 35 teaspoons of purple paint to make the same shade.


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Step-by-step explanation:

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Step-by-step explanation:

[tex]

\underline{\bf{Given\::}}

Given:

\underline{\bf{To\:find\::}}

Tofind:

\underline{\bf{Explanation\::}}

Explanation:

\boxed{\bf{\frac{1}{f} =\frac{1}{v} -\frac{1}{u} }}}}

\begin{gathered}\longrightarrow\sf{\dfrac{1}{-10} =\dfrac{1}{v} -\dfrac{1}{-30} }\\\\\\\longrightarrow\sf{\dfrac{1}{v} =\dfrac{1}{-10} +\dfrac{1}{30} }\\\\\\\longrightarrow\sf{\dfrac{1}{v} =\dfrac{-3+1}{30} }\\\\\\\longrightarrow\sf{\dfrac{1}{v} =\cancel{\dfrac{-2}{30} }}\\\\\\\longrightarrow\sf{\dfrac{1}{v} =\dfrac{1}{-15} }\\\\\\\longrightarrow\sf{v=-15\:cm}\end{gathered}

−10

1

=

v

1

−30

1

v

1

=

−10

1

+

30

1

v

1

=

30

−3+1

v

1

=

30

−2

v

1

=

−15

1

⟶v=−15cm

\boxed{\bf{M \:A \:G \:N\: I \:F \:I \:C\: A\: T \:I \:O\: N :}}

MAGNIFICATION:

\begin{gathered}\mapsto\sf{m=\dfrac{Height\:of\:image\:(I)}{Height\:of\:object\:(O)} =\dfrac{Distance\:of\:image}{Distance\:of\:object} =\dfrac{v}{u} }\\\\\\\mapsto\sf{m=\cancel{\dfrac{-30}{-15}} }\\\\\\\mapsto\bf{m=2\:cm}\end{gathered}

↦m=

Heightofobject(O)

Heightofimage(I)

=

Distanceofobject

Distanceofimage

=

u

v

↦m=

−15

−30

↦m=2cm

Thus;

The magnification will be 2 cm .

[/tex]

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