A map has a scale of 3 cm:20 km. If two cities are 30 cm apart on a map, how far are the cities actually apart?

Answer:

-10

Step-by-step explanation:

5 - 3*5

= 5 - 15

= -10

[tex]\mathsf\pink{♧ANSWER♧}[/tex]

[tex] \mathsf \purple{0.85 = \frac{85}{100} = \frac{17}{20} }[/tex]

85/100 = 17/20

first we write the fraction from of 0.85 which is 85/100

then for simplifying it, we divide both 85 and 100 by 5

then we get to 17/20 which is our final answer

Answer: 44 units

Step-by-step explanation:

Opposite sides of a parallelogram are equal, hence sides

AB = DC

4y-2 = 2y+6

2y=8

y=4

and

BC = AD

2x+2=3x-1

x=3

AB = 4Y-2

y=4

AB=14

BC=2x+2

x=3

BC=8

Perimeter = 2 X (AB + BC)

= 2 X (14+8)

= 44

Answer:

44 units

Step-by-step explanation:

LETTER B IS THE CORRECT ANSWER

Answer:

1 and -9

Step-by-step explanation:

We can find the number by looking at the factors of -9, which include 1 and -9, -1 and 9, and -3 and 3.

1 * -9 = -9

1 + (-9) = -8

Answer:

Length: 360. Width: 240.

Step-by-step explanation:

360 * 2 = 720

240 * 2 = 480

720 + 480 = 1,200

Answer:

6x-3y=12

+3y

6x=3y+12

divide by 3

2x=y+4

-4

y=2x-4

Hope This Helps!!!

Answer:

B. 1/4

Step-by-step explanation:

Even though A is a fraction it is also an integer (4)

Answer:

  x = 9

  x+7 = 16

Step-by-step explanation:

The triangles in this geometry are similar, so the ratios of corresponding sides are proportional.

  long side/short side = (x+7)/12 = 12/x

  x(x +7) = 12²

  x +7x -144 = 0 . . . . . subtract 144 to put in standard form

  (x +16)(x -9) = 0 . . . . factor

  x = 9 . . . . . . only the positive solution is useful here

The missing lengths are ...

Answer: 48

Step-by-step explanation:

Answer:

the answer is 67.5

Step-by-step explanation:

look at the photo

Answer:

1 quick fix            2 solving               3 result

Step-by-step explanation:

hope it helps

Velocity of jet in still air is

970

miles per hour and velocity of wind is

210

miles per hour.

Explanation:

Jet's velocity against wind is

3040

4

=

760

mile per hour and flying with wind it is

8260

7

=

1180

miles per hour.

Let the velocity of jet in still air be

x

miles per hour and velocity of wind be

y

miles per hour.

As such its velocity against wind is

x

−

y

and with wind is

x

+

y

and therefore

x

−

y

=

760

and

x

+

y

=

1180

Adding the two

2

x

=

1940

and

x

=

970

and

y

=

1180

−

970

=

210

Hence velocity of jet in still air is

970

miles per hour and velocity of wind is

210

miles per hour.

The speed of an aircraft in still air is 200kmh−1. The wind blows from the west at a speed of 85.0kmh−1.

1 Expert Answer

The speed of the plane in still air is 110 mph.

Multiply the headwind or tailwind component by your estimated flight time expressed as a decimal, such as "3.2 hours." Add the result (don't forget that tailwinds are negative numbers) to the geographic distance of your route. The resulting number will be total nautical air miles of your trip.

Answer:

$1470 coupon of their product I have

Answer:

tan m‹G = 28.2/45.8

m‹G= 31.62°

Answer:

Length: 17 in, Width: 12 in

Step-by-step explanation:

Let l=length and w=width

l=w+5

2(w+5)+2w=58

4w=48

w=12, l=17

Answer:

⠀

Step-by-step explanation:

⠀

As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

⠀

Now, According to the Question :

⠀

[tex]{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{2 ( 2x + 5 )= 58 }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{ 4x = 58 - 10}}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{ 4x = 48}}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{ x = \dfrac{48}{4} }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\: \: \bigstar[/tex]

⠀

Therefore,

⠀

Now, We are to find the length of the rectangle:

[tex]{\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}[/tex]

⠀

[tex]{\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}[/tex]

⠀

[tex]{\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}[/tex]

⠀

Therefore,

⠀

Answer: C

Step-by-step explanation:

[tex]2x+5y=5[/tex]

[tex]\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}[/tex]

[tex]2x+5y-2x=5-2x[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]5y=5-2x[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}5[/tex]

[tex]\frac{5y}{5}=\frac{5}{5}-\frac{2x}{5}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\bf{y=-\frac{2}{5}x + 1}[/tex]

Answer:

no solution,because the Is no 83=512 there

Answer:

28, 28, 34, 34

Step-by-step explanation:

8x - (6 + y)

8(5) - (6 + 6)

40-12

28

w ¾ + x²

4(¾) + 5²

3 + 25

28

y² - 0.5w

6² - 0.5(4)

36 - 2

34

w / 4 + 3(x + y)

4 / 4 + 3(5 + 6)

1 + 3(11)

34

let's recall that d = rt, distance = rate * time.

a = speed of the airplane in still air.

w = speed of the wind

the distance travelled with the wind is 960 miles, so the return trip is pretty much just that, 960 miles.

when the airplane is going with with wind, the airplane is really not going as fast as "a" mph, is really going faster due to the wind, so the speed of the plane is "a + w", because the wind is adding its speed to it.

when the airplane is going against the wind is not really going "a" mph fast either, is really going slower at "a - w" mph, because the wind is subtracting speed from it, so

[tex]\begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{with the wind}&960&a+w&5\\ \textit{against the wind}&960&a-w&6 \end{array}~\hfill \begin{cases} 960=(a+w)(5)\\\\ 960=(a-w)(6) \end{cases} \\\\\\ \stackrel{\textit{using the 1st equation}}{960=(a+w)(5)}\implies \cfrac{960}{5}= a + w\implies 192=a+w\implies \boxed{192-w=a}[/tex]

[tex]\stackrel{\textit{substituting on the 2nd equation}}{960=(\underline{192-w}~~ - ~~w)(6)}\implies \cfrac{960}{6}=192-w-w\implies 160=192-2w \\\\\\ 2w+160=192\implies 2w=32\implies w=\cfrac{32}{2}\implies \blacktriangleright w=16 \blacktriangleleft ~\hfill \blacktriangleright \stackrel{192 - 16}{176=a} \blacktriangleleft[/tex]

Answer:

27

Step-by-step explanation:

       Let g be Gabrielle's age and m be Mikhail's age.

       We can turn the statements the problem gives us into mathematical expressions to help us solve.

       Gabrielle's age is two times Mikhail's age:

                      g = 2m

       The sum of their ages is 81:

                      g + m = 81

       This gives us a system of equations that will allow us to solve for Gabrielle's age.

g + m = 81

(2m) + m = 81

3m = 81

m = [tex]\frac{81}{3}[/tex]

m = 27

       If we need to solve for Gabrielle's age, we can do the following.

g = 2m

2(27) = g

54 = g

g = 54

Mikhail's age is 27.

Gabrielle's age is 54.

Answer:

Mikhail is 27

Step-by-step explanation:

**If you want to find Gabrielle's age, multiply Mikhail's age by two, as represented by the equation g=2m. Gabrielle is 57.

Hope this helps!

Answer:37,500

Step-by-step explanation: Find 60% of 25000 which is 15000 then multiply by 2.5

Answer:

  0.772 seconds; 9.228 seconds

Step-by-step explanation:

The given projectile formula with the given numbers filled in is ...

  [tex]\displaystyle h=-16t^2+v_0t+h_0\\\\114=-16t^2+160t[/tex]

We can "complete the square" to solve this for t, the times at which the height is 114 feet.

  16(t² -10t) = -16(7.125) . . . . . rearrange, showing factor of 16

  t² -10t +25 = -7.125 +25 . . . . divide by 16, add 25 to complete the square

  t = 5 ±√17.875 ≈ 5 ± 4.228 . . . . take the square root, add 5

  t ∈ {0.772, 9.228}

The arrow is 114 feet high after 0.772 seconds and again after 9.228 seconds.