A manager does not know how to program code. What could he use communicate his programming ideas effectively to his team?

ANSWER: B) pseudocode

Answer:

The choices we make as citizens online or in real life have both positive and negative effects on others because we are social beings, who live in an interconnected world.  Every choice has some consequences on the decision maker or on others.  We make the choices, but the consequences follow natural laws, which we cannot control.  When Adam and Eve chose to disobey God, human beings down the ages lost their innocence and freedom.  When the Nazis chose to purify their race of European Jews, there was the Holocaust between 1941 and 1945.  When the Minneapolis police officer chose to slaughter George Floyd in cold blood, violent protests erupted throughout the U.S.

Another current example to buttress this is the ravaging coronavirus pandemic, which originated in Wuhan - China.  When the Chinese Communist  government chose to suppress the information about the virus as it usually does, the aftermath is the thousands of dead humans all over the world, the economic downturn, loss of jobs, virus infections with other public health side effects, plus many other untold consequences.

Had the Chinese government made a different choice, the virus could not have spread worldwide as it had.  Similarly, some citizens online choose to circulate unverifiable ("fake news") information.  Many people have been misled by their antics, some have lost their lives, while many others live in perpetual bigotry and hatred.  All these are because of individual choices.

Explanation:

Choice is a concept in decision making.  It is the judging of the merits of multiple options so that one or some of the options are selected.  When a voter votes for one candidate against others, she has made a choice (decision).  Of course, choices have consequences, which we must live with.  Choices also define our present and our future.

Answer:

Let's implement the program using JAVA code.

import java.util.*;

import java.util.ArrayList;

import java.io.*;

public class ScrambledStrings

{

/** Scrambles a given word.

* atparam word the word to be scrambled

* atreturn the scrambled word (possibly equal to word)

* Precondition: word is either an empty string or contains only uppercase letters.

* Postcondition: the string returned was created from word as follows:

* - the word was scrambled, beginning at the first letter and continuing from left to right

* - two consecutive letters consisting of "A" followed by a letter that was not "A" were swapped

* - letters were swapped at most once

*/

public static String scrambleWord(String word)

{

// iterating through each character

for(int i=0;i<word.length()-1;)

{

//if the condition matches

if(word.charAt(i)=='A' && word.charAt(i+1)!='A'){

//swapping the characters

word=word.substring(0,i)+word.charAt(i+1)+word.charAt(i)+word.substring(i+2);

//skipping the letter

i+=1;

}

//skipping the letter

i+=1;

}

return word;

}

Explanation:

Note: Please replace the "at" on the third and fourth line with at symbol that is shift 2.

Answer:

num = 0

while (num < 50):

if (num is Odd)

print(num is Odd)

num = num + 1

num = 0

repeat:

if (num is Odd)

print(num is Odd)

num = num + 1

until (num>=50)

Answer:

well, idc

Explanation:

Answer:

The body of water that is most likely to be a marine ecosystem would be an estuary.

Explanation:

An estuary is a widened, often funnel-shaped mouth of a river, where fresh river water and salt sea water are mixed and thus brackish water is created, and where tidal differences can be observed. When a river flows as a system of branches, it is called a delta.

Estuaries often have a great natural value. They typically consist of swallows and salt marshes that are very rich in invertebrates and thus have a great attraction for birds, among other things.

#!/bin/bash

usage() {

       echo "Usage: $0 [ -f outfile ] name password" 1>&2

       exit 1

}

while getopts "f:" o; do

       case "${o}" in

       f)

               filename=${OPTARG}

           ;;

       *)

               usage

           ;;

   esac

done

shift $((OPTIND-1))

name=$1

password=$2

if [ -z "$password" ] ; then

       usage

fi

set -x

if [ -z "$filename" ] ; then

       useradd -p `crypt $password` $name

else

       useradd -p `crypt $password` $name > $filename

fi

Answer:

The answer is below

Explanation:

Since the type of Implementation is not stated specifically, it is believed that, the question is talking about ERP Implementation, because it is related to subject in which the question is asked.

Hence, Enterprise Resource Planning (ERP) implementation deals basically, by carrying out installation of the software, transferring of finanancial data over to the new system, configuring application users and processes, and training users on the software

ERP Implementation Risks involve the following:

1. Inefficient Management and Project Activities.

2. Inadequate or No Training and Retraining of Customers or End-Users.

3. Inability to Redesign Business Processes to meet the Software requirements.

3. Incompetent or lack of Technical Support Team and Infrastructure.

4. Incapability to Obtain Full-Time Commitment of Employee.

5. Failure to Recruit and Maintained Qualified Systems, and Developers.

Answer:

Following are the method to this question:

void selectionSort(string strArr[], int s) //defining selectionSort method

{

int i,ind; //defining integer variables

string val; //defining string variable

for (i= 0; i< (s-1);i++) //defining loop to count value

  {

      ind = i; //assign loop value in ind variable

      val = strArr[i]; // strore array value in string val variable

      for (int j = i+1;j< s;j++) // defining loop to compare value

      {

          if (strArr[j].compare(val) < 0) //using if block to check value

          {

              val = strArr[j]; //store value in val variable  

              ind= j; //change index value

          }

      }

      strArr[ind] = strArr[i]; //assign string value in strArray  

      strArr[i] = val; // assign array index value

  }

}

void print(string strArr[], int s) //defining print method

{

  for (int i=0;i<s;i++) //using loop to print array values

  {

      cout << strArr[i] << endl; //print values

  }

  cout << endl;

}

Explanation:

In the above-given code, two methods "selectionsort and print" is declared, in which, both method stores two variable in its parameter, which can be described as follows:

Answer:

its A C E

Explanation:

Answer: A Transaction Processing System (TPS) is a type of information system that collects, stores, modifies and retrieves the data transactions of an enterprise. Rather than allowing the user to run arbitrary programs as time-sharing, transaction processing allows only predefined, structured transactions.

Three cycles: Transaction processing systems generally go through a five-stage cycle of 1) Data entry activities 2) Transaction processing activities 3) File and database processing 4) Document and report generation 5) Inquiry processing activities.

Explanation: hope this helps!

Answer:

A program in C++ was written to prompts the user to enter the area of the flat cardboard.

Explanation:

Solution:

The C++ code:

#include <iostream>

#include <iomanip>

#include <cmath>

using namespace std;

double min(double,double);

void max(double,double,double&,double&);

int main()

{double area,length,width=.001,vol,height,maxLen,mWidth,maxHeight,maxVolume=-1;

cout<<setprecision(3)<<fixed<<showpoint;

cout<<"Enter the area of the flat cardboard: ";

cin>>area;

while(width<=area)

{length=area/width;

max(length,width,vol,height);

if(vol>maxVolume)

{maxLen=length;

mWidth=width;

maxHeight=height;

maxVolume=vol;

}

width+=.001;

}

cout<<"dimensions of card to maximize the cardboard box which has a volume "

<<maxVolume<<endl;

cout<<"Length: "<<maxLen<<"\nWidth: "<<maxLen<<endl;

cout<<"dimensions of the cardboard box\n";

cout<<"Length: "<<maxLen-2*maxHeight<<"\nWidth: "

<<mWidth-2*maxHeight<<"\nHeight: "<<maxHeight<<endl;

return 0;

}

void max(double l,double w,double& max, double& maxside)

{double vol,ht;

maxside=min(l,w);

ht=.001;

max=-1;

while(maxside>ht*2)

{vol=(l-ht*2)*(w-ht*2)*ht;

if(vol>max)

{max=vol;

maxside=ht;

}

ht+=.001;

}

}

double min(double l,double w)

{if(l<w)

return l;

return w;

}

Note:  Kindly find the output code below

/*

Output for the code:

Enter the area of the flat cardboard: 23

dimensions of card to maximize the cardboard box which has a volume 0.023

Length: 4.796

Width: 4.796

dimensions of the cardboard box

Length: 4.794

Width: 4.794

Height: 0.001

*/

Answer:

See attached images

Answer:An electronic device for storing and processing data, typically in binary form

Explanation:

Answer:

With the analysis of the case, we can infer that regarding the model or algorithm of the work set, we want to reduce page faults in each individual process, guaranteeing that the set of pages are included before executing the process.

There are things that should not change, such as the set of pages used in the process or the working set as they are called, they could only change if a program moves to a different phase of execution. In this way the most suitable and profitable approach is proposed for the use of time in the processor, by avoiding bringing oagines from the hard disk and instead of this the process is executed, because otherwise it would take a long time what was observed in decreased performance.

Regarding what was mentioned in the question, it follows that 2 extremes lead to a problematic behavior, to define the first as a page fault and the second refers to a small number of processes executed.

Answer:

The third point i.e " Use an alternating least squares (ALS) algorithm to create a collaborative filtering solution" is the correct answer .

Explanation:

The Alternating Less Squares  is the different approach that main objective to enhancing the loss function.The Alternating Less Squares process divided the matrix into the two factors for optimizing the loss .The divided of two factor matrix is known as item matrix or the user matrix.

Answer:

It is difficult to convince top management to commit funds to develop and implement an SIS because it can lead to reengineering, which requires businesses to revamp processes to undergo organizational change to gain an advantage.

Explanation:

Answer:

Following are the code to this question:

import java.util.*; //import package for user input

public class Main //defining main class

{

public static double sumMajorDiagonal(double [][] m) //defining method sumMajorDiagonal

{

double sum = 0; //defining double variable sum

int i, j; //defining integer variable  

for(i = 0; i <m.length; i++) //defining loop to count row

{

for(j = 0; j < m.length; j++) //defining loop to count column  

{

if(i == j) //defining condition to value of i is equal to j

{

sum=sum+ m[i][j]; //add diagonal value in sum variable

}

}

}

return sum; //return sum

}

public static void main(String args[]) //defining main method

{

int n,i,j; //defining integer variable    

System.out.print("Enter the dimension value: "); //print message

Scanner ox = new Scanner(System.in); //creating Scanner class object for user input

n = Integer.parseInt(ox.nextLine()); //input value and convert value into integer

double m[][] = new double[n][n]; //defining 2D array

for(i = 0; i < m.length; i++)

{

String t = ox.nextLine(); // providing space value

String a[] = t.split(" "); // split value

for(j = 0; j < a.length; j++) //defining loop to count array value

{

double val = Double.parseDouble(a[j]); //store value in val variable

m[i][j] = val; //assign val in to array

}

}

double d_sum = sumMajorDiagonal(m); //call method store its return value in d_sum variable

System.out.println("diagonal matrix sum: "+ d_sum); //print sum

}

}

output:

Enter the dimension value: 3

1 2 3

1 2 3

1 2 4

diagonal matrix sum: 7.0

Explanation:

Program description:

Answer:

PEAP is the correct answer to the given question .

Explanation:

The  PEAP are implemented to meet the demands because it is very much identical to the EAP-TTLS design also it includes the server-side PKI authentication .

Answer:

see explaination

Explanation:

If I am to select I will select the strategy Impute the missing values . Because rather than deleting and all the other strategies. This is the best option because, this is an optional field as described there is no need for such accurate information about salary.

If we want to maintain this field we can just fill the value by identifying the similar records which is the other customers who is visiting the same no of times and fill that.

Answer:

a. False

Explanation:

It is false as more than one calendar is visible in outlook.

Explanation:

it is false

i think it helps you

Answer:

import java.io.File;

import java.io.FileInputStream;

import java.io.FileNotFoundException;

import java.io.FileOutputStream;

import java.io.IOException;

import java.util.Scanner;

public class EncryptFileData

{

public static void main(String args[]) throws IOException, FileNotFoundException

{

String inputFileName="input.txt";

String outputFileName="EncryptedFile.txt";

String decryptFileName="DecryptedFile.txt";

byte codeValue;

Scanner sc=new Scanner(System.in);

//Accept code value from user

System.out.println("Enter the value of code");

codeValue=sc.nextByte();

//Encrypt the input file

encryptFileContent(inputFileName, codeValue,outputFileName);

//Decrypt the input file

decryptFileContent(outputFileName, codeValue,decryptFileName);

}

//function to encrypt the input file

private static void encryptFileContent(String inputFileName,

byte encodeValue, String outputFileName) throws IOException, FileNotFoundException{

File file = new File(inputFileName);

FileInputStream fin = new FileInputStream(file);

FileOutputStream fout = new FileOutputStream(outputFileName);

try{

while(fin.available() != 0){

int inData = fin.read();

//For every character in input add code value and

//write result to file "EncryptedFile.txt"

fout.write(inData+encodeValue);

}

}finally{

fin.close();

fout.close();

}

}

//function to decrypt the encrypted file

private static void decryptFileContent(String inputFileName,

byte encodeValue, String outputFileName) throws IOException, FileNotFoundException{

File file = new File(inputFileName);

FileInputStream fin = new FileInputStream(file);

FileOutputStream fout = new FileOutputStream(outputFileName);

try{

while(fin.available() != 0){

int inData = fin.read();

//For every character in encrypted file

//subtract the code value from each character and

//write it to file "DecryptedFile.txt"

fout.write(inData-encodeValue);

}

}finally{

fin.close();

fout.close();

}

}

}

Explanation:

Given the following conditions to follow in the question;

=> "The encryption program should work like a filter, reading the contents of one file, modifying the data into code, and then writing the code contents out to a second file. "

=> "The second file will be a version of the first file, but written in a secret code."

Thus, the Java code is given below(one can just copy and run it to give a sample output of: Enter the value of code 1 2.

The Java code is;

import java.io.File;

import java.io.FileInputStream;

import java.io.FileNotFoundException;

import java.io.FileOutputStream;

import java.io.IOException;

import java.util.Scanner;

public class EncryptFileData

{

public static void main(String args[]) throws IOException, FileNotFoundException

{

String inputFileName="input.txt";

String outputFileName="EncryptedFile.txt";

String decryptFileName="DecryptedFile.txt";

byte codeValue;

Scanner sc=new Scanner(System.in);

//Accept code value from user

System.out.println("Enter the value of code");

codeValue=sc.nextByte();

//Encrypt the input file

encryptFileContent(inputFileName, codeValue,outputFileName);

//Decrypt the input file

decryptFileContent(outputFileName, codeValue,decryptFileName);

}

//function to encrypt the input file

private static void encryptFileContent(String inputFileName,

byte encodeValue, String outputFileName) throws IOException, FileNotFoundException{

File file = new File(inputFileName);

FileInputStream fin = new FileInputStream(file);

FileOutputStream fout = new FileOutputStream(outputFileName);

try{

while(fin.available() != 0){

int inData = fin.read();

//For every character in input add code value and

//write result to file "EncryptedFile.txt"

fout.write(inData+encodeValue);

}

}finally{

fin.close();

fout.close();

}

}

//function to decrypt the encrypted file

private static void decryptFileContent(String inputFileName,

byte encodeValue, String outputFileName) throws IOException, FileNotFoundException{

File file = new File(inputFileName);

FileInputStream fin = new FileInputStream(file);

FileOutputStream fout = new FileOutputStream(outputFileName);

try{

while(fin.available() != 0){

int inData = fin.read();

//For every character in encrypted file

//subtract the code value from each character and

//write it to file "DecryptedFile.txt"

fout.write(inData-encodeValue);

}

}finally{

fin.close();

fout.close();

}

}

}

Answer:

see explaination

Explanation:

SCRIPT :

drop table Vendor;

create table Vendor (VendorName varchar2(20), InvoiceNumber number (20), InvoiceDueDate date, Balance number(32,6));

insert into VENDOR (VENDORNAME,INVOICENUMBER,INVOICEDUEDATE,BALANCE) values ('ABC',121,TO_TIMESTAMP('01-01-18','DD-MM-RR HH12:MI:SSXFF AM'),1000);

Insert into Vendor (VENDORNAME,INVOICENUMBER,INVOICEDUEDATE,BALANCE) values ('XYZ',1212121,to_timestamp('02-01-18','DD-MM-RR HH12:MI:SSXFF AM'),100000);

declare

cursor c1 is select * from Vendor;

begin

for i in c1

loop

if I.BALANCE < 1001 then

DBMS_OUTPUT.PUT_LINE('Vendor Name '||I.VENDORNAME||', Invoice Number '||I.INVOICENUMBER||', Invoice DueDate '||I.INVOICEDUEDATE||',BALANCE '||I. BALANCE);

else

dbms_output.put_line('Vendor Name '||i.VendorName||', Invoice Number '||i.InvoiceNumber||', Invoice DueDate '|| i.InvoiceDueDate||' Balance due is less than $1000');

end if;

end LOOP;

end;

output : SCRIPT OUTPUT

table VENDOR dropped.

table VENDOR created.

1 rows inserted.

1 rows inserted.

anonymous block completed

dbms output :

Vendor Name ABC, Invoice Number 121, Invoice DueDate 01-JAN-18,BALANCE 1000

Vendor Name XYZ, Invoice Number 1212121, Invoice DueDate 02-JAN-18 Balance due is less than $1000

Answer:

Explanation:

.Car can Travel a m miles tank on a gas

2.For N distance there are n+1 adjacent gas stations.

Output Conditions:

Tacoma will fill the gas station while going.

Tijuana will fill up gas for the return trip

3.Dynamic self Reduction Algorithm

Start

if(n==0)

Tacoma is a gas station number 0;

else

Tijuana is a gas station n+1;

stop

Answer:

Quick sort and Merge sort supports parallelism

Explanation:

When we talk about parallelism, we are referring to the idea of breaking down a problem into a number of many subproblems after which we combine the solutions of these subproblems into a single solution. Here we allocate these subtasks to the multicore processors where each core gets assigned each of the subtasks are assigned to a core according to its ability or functionality. After each of the core are through with its evaluation, all their results are collated and combined to come up with a full rounded and complete solution to the given problem.

If we take a look at sorting algorithms such as selection sort, bubble sort and insertion sort, we will find out that these algorithms cant be simulated on a multicore processor efficiently because they are sequential algorithms.

On the other hand, we have sorting algorithms that can easily be simulated in a multicore processor since they can divide the given problem into subproblems to solve after which the solutions can be combined together to arrive at or come up with a complete solution to the problem. This algorithms includes Quick sort and Merge sort, they make use of Divide and Conquer paradigm.

Answer:

honestly i dont know but I used to have computer programming classes on java and I'd get all my answers from repl.it forums. Wist you best of luck!!

Answer:

The TCP socket state will be as 'Closed'.

Explanation:

TCP seems to be a framework that describes how well a web discussion can be established and maintained through which software applications could access information.

The accompanying is the finished status whenever the connection is suspended by TCP:

CLOSE-WAIT:

This means that the end destination had already chosen to take a similar requirement from the 'remote endpoint.'

CLOSING:

This indicates the position for the cancellation of server access verification from either the faraway TCP.

LAS-ACK:

This indicates the view for approval including its extermination previously sent through the cell tower TCP.

TIME-WAIT:

This symbolizes a lengthy delay for all the remote to accept verification of its cancellation request.

CLOSED:

This means that there is no link region or anything like that.

Answer:

A python script:

months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

numbers = [31,28,31,30,31,30,31,31,30,31,30,31]

counter = 0

numbers_length=len(numbers)-1

while counter <= numbers_length:

month=months[counter]

number=numbers[counter]

print (month + " has " + str(number) + " days")

counter = counter+1

Explanation:

The Python script above will generate this output:

January has 31 days.

February has 28 days.

March has 31 days.

April has 30 days.

May has 31 days.

June has 30 days.

July has 31 days.

August has 31 days.

September has 30 days.

October has 31 days.

November has 30 days.

December has 31 days.

Answer:

they give a clear understanding of the problem and its solution

Answer:

The answer is in the question,A

Explanation:

They give a clear understanding of the problem and its solution