A man pushes a 10 kg box a distance of 5 m for 3 hours. How much work
did the man complete?*

Answers

Answer 1

Answer:

alot

Explanation:

cuz he pushed for a long time


Related Questions

An electric motor spins at 1000 rpm and is slowing down at a rate of 10 t rad/s2 ; where t is measured in seconds. (a) If the motor radius is 7.165 cm, what is the tangential component of acceleration at the edge of the motor at t = 1.5 seconds? (b) How long will it take, in seconds, to decrease its angular velocity by 75%?

Answers

Answer:

a) The tangential component of acceleration at the edge of the motor at  [tex]t = 1.5\,s[/tex] is -1.075 meters per square second.

b) The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

Explanation:

The angular aceleration of the electric motor ([tex]\alpha[/tex]), measured in radians per square second, as a function of time ([tex]t[/tex]), measured in seconds, is determined by the following formula:

[tex]\alpha = -10\cdot t\,\left[\frac{rad}{s^{2}} \right][/tex] (1)

The function for the angular velocity of the electric motor ([tex]\omega[/tex]), measured in radians per second, is found by integration:

[tex]\omega = \omega_{o} - 5\cdot t^{2}\,\left[\frac{rad}{s} \right][/tex] (2)

Where [tex]\omega_{o}[/tex] is the initial angular velocity, measured in radians per second.

a) The tangential component of aceleration ([tex]a_{t}[/tex]), measured in meters per square second, is defined by the following formula:

[tex]a_{t} = R\cdot \alpha[/tex] (3)

Where [tex]R[/tex] is the radius of the electric motor, measured in meters.

If we know that [tex]R = 7.165\times 10^{-2}\,m[/tex], [tex]\alpha = 10\cdot t[/tex] and [tex]t = 1.5\,s[/tex], then the tangential component of the acceleration at the edge of the motor is:

[tex]a_{t} = (7.165\times 10^{-2}\,m)\cdot (-10)\cdot (1.5\,s)[/tex]

[tex]a_{t} = -1.075\, \frac{m}{s^{2}}[/tex]

The tangential component of acceleration at the edge of the motor at  [tex]t = 1.5\,s[/tex] is -1.075 meters per square second.

b) If we know that [tex]\omega_{o} = 104.720\,\frac{rad}{s}[/tex] and [tex]\omega = 26.180\,\frac{rad}{s}[/tex], then the time needed is:

[tex]26.180\,\frac{rad}{s} = 104.720\,\frac{rad}{s}-5\cdot t^{2}[/tex]

[tex]5\cdot t^{2} = 104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}[/tex]

[tex]t^{2} = \frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s} }{5}[/tex]

[tex]t = \sqrt{\frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s} }{5} }[/tex]

[tex]t \approx 3.963\,s[/tex]

The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

Planet Zero has a mass of 4.0 x 1023 kg and a radius of 2.0 x 106 m. A 10-kg space probe is launched vertically from the surface of Zero with an initial kinetic energy of 8.0 x 107 J. What maximum distance from the center of Zero is achieved by the probe

Answers

Answer:

r2 = 1.25 × 10^(6) m

Explanation:

We are given;

Initial kinetic energy; K_1= 8.0 x 10^(7) J

Mass of planet zero; M = 4.0 x 10^(23) kg

Mass of space probe; m = 10 kg

Radius of planet zero; r1 = 2 × 10^(6) m

From conservation of energy, we can say that;

Initial potential energy + Initial kinetic energy = Final potential energy + Final kinetic energy

This is;

U1 + K1 = U2 + K2

Using formula for potential energy: U = GMm/r, we can write it as;

GMm/r1 + K1 = GMm/r2 + K2

Where Maximum distance = r2

At maximum distance from the center of Zero, K2 = 0.

Thus;

GMm/r1 + K1 = GMm/r2

Making r2 the subject, we have;

r2 = GMm/((GMm/r1)+ K1)

Where G is gravitational constant = 6.67 × 10^(-11) N/m²/kg2

Thus;

r2 = (6.67 × 10^(-11) × 4.0 x 10^(23) × 10)/((6.67 × 10^(-11) × 4.0 x 10^(23) × 10)/(2 × 10^(6)) + (8.0 × 10^(7)))

r2 = 1.25 × 10^(6) m

what are examples of an insulator, conductor, and semiconductor?

Answers

Examples of insulators are rubber, glass and dry wood. Examples of conductors are metals, graphite and the human body. Examples of semiconductors are silicone, germanium and gallium arsenide.

Air in a balloon does 40 J of work expanding the balloon while absorbing 60 J of heat. What is the change in internal energy

Answers

Answer:

DU = 20 Joules

Explanation:

Given the following data;

Heat absorbed, Q = 60J

Workdone, W = 40J

To find the internal energy;

We would use first law of thermodynamics given by the formula;

Change in internal energy (DU) = Q - W

where;

U is internal energy.

Q is the heat absorbed.

W is the work done.

Substituting into the equation, we have;

DU = 60 - 40

DU = 20 Joules

mmmeeeee,I'M BEING TIMED

Answers

Answer:

D) See the explanation below.

Explanation:

Heat transfer is always given from a body of higher temperature to a lower temperature. In this way the heat from the boiling water is transferred to the ice bars and the energy of the phase change from solid to liquid from the ice is transferred to the environment

How does the mass of and distance between the Sun and the Earth impact the number of days in a year?

Answers

Answer:

Force of sun on  earth can  be written:

F = G M m / R^2

Centripetal force on earth can be written:

F= m w^2 R

Equating these:

G M / R^2 = w^2 R

Or   w^2 = G (M / R^3)

Since no/ days per year is proportional to w (time for 1 revolution)

Increasing M (mass of sun) would increase w or decrease length of year

Increasing the mean radius R would decrease w  or increase length of year

A coin lies at the bottom of a tank containing water to a Dept of 130cm. If the refractive index of the water is 1.3, calculate the apparent displacement of the coin viewed vertically from above

Answers

Answer: 100 cm

Explanation: When an object at the bottom of a tank with water is viewed vertically from above, to the observer, it seems the object is closer to the eye, i.e., the apparent depth of the object is less than the real depth the object is. This is caused by Refraction, which happens when an incident light passing through an interface between two different media causing the light to be deflected.

The relation between real and apparent depths is given by:

[tex]n=\frac{Dr}{Da}[/tex]

where

n is refractive index of the surface

Dr is real depth

Da is apparent depth

For the coin at the bottom of a tank, apparent depth is:

[tex]n=\frac{Dr}{Da}[/tex]

[tex]Da=\frac{Dr}{n}[/tex]

[tex]Da=\frac{130}{1.3}[/tex]

Da = 100

Apparent displacement of the coin viewed vertically from above is 100 cm.

Given an area of 8 ft^2. Express this area in the following terms. (a)m^2 5.9458 Incorrect: Your answer is incorrect. m^2 (b) in^2 WebAssign will check your answer for the correct number of significant figures. 96 Incorrect: Your answer is incorrect. in^2 (express to 4 significant figures)

Answers

Answer:

0.7432m²

1152in²

Explanation:

a) Usng the conversion

1ft² = 0.0929m²

8ft² = y

y = 8 × 0.0929

y = 0.7432m²

Hence 8ft² in m² is 0.7432m²

For ft² to in²

1ft² = 144in²

8ft² = x

X =8×144

x = 1152in²

Hence 8ft² expressed in in² is 1152in²

Water runs out of a horizontal drainpipe at the rate of 135 kg/min. It falls 3.1 m to the ground. Assuming the water doesn't splash up, what average force does the water exert on the ground

Answers

Answer:

The average force exerted by the water on the ground is 17.53 N.

Explanation:

Given;

mass flow rate of the water, m' = 135 kg/min

height of fall of the water, h = 3.1 m

the time taken for the water to fall to the ground;

[tex]h = ut + \frac{1}{2}gt^2\\\\h = 0 + \frac{1}{2}gt^2\\\\t = \sqrt{\frac{2\times 3.1}{9.8} } \\\\t = 0.795 \ s[/tex]

mass of the water;

[tex]m = m't\\\\m = 135 \ \frac{kg}{min} \ \times \ 0.795 \ s \ \times \ \frac{1 \ \min}{60 \ s} \ = 1.789 \ kg[/tex]

the average force exerted by the water on the ground;

F = mg

F = 1.789 x 9.8

F = 17.53 N

Therefore, the average force exerted by the water on the ground is 17.53 N.

Experiencing a "jump scare" in a frightening movie most immediately activates your:

somatic nervous system.

sympathetic nervous system.

parasympathetic nervous system.

decentralized nervous system.

Answers

Answer:

Somatic I think

Explanation:

Answer:Sympathetic nervous system

Explanation:

A 100g mouse and an elephant want to find balance by sitting on a really long see-saw that is balanced at its center of mass. Of the 5000 kg elephant is sitting 0.75m away from the axis of rotation, how far away from the axis of rotation must the mouse sit

Answers

Answer:

3.75 km away

Explanation:

From the law of moments, clockwise moments = anticlockwise moment

So WL = wl where W = weight of elephant = Mg and M = mass of elephant = 5000 kg, L = distance of elephant from axis of rotation = 0.75 m, and w = weight of mouse = mg where m= mass of mouse = 100 g = 0.1 kg and l =  distance of mouse from axis of rotation = unknown and g = acceleration due to gravity.

So, MgL = mgl

ML = ml

l = ML/m

= 5000 kg × 0.75 m/0.1 kg

= 3750 kgm/0.1 kg

= 37500 m

= 3.75 km away

Three tension forces OA, OB and OC are equal in magnitude and magnitude of their summation is 200 N. What is the magnitude of each force

Answers

Answer:

The magnitude of each force is 66.67 N

Explanation:

Given that the magnitude of the tension forces are equal. Let the magnitude of the tension forces be represented by x, such that;

|OA| = |OB| = |OC| = x

Since their summation = 200 N, then;

|OA| + |OB| + |OC| = 200

This implies that;

x + x + x = 200

3x = 200

x = [tex]\frac{200}{3}[/tex]

    = 66.6667

x = 66.67 N

Therefore, the magnitude of each tension force is approximately 66.67 N

Potential energy diagrams for a particle are useful in predicting the motion of that particle.

a. True
b. False

Answers

Answer:

True

Explanation:

How many significant figures are there in each of the following?
(a) 85.8 + 0.9

Answers

Answer:

86.7

Explanation:

sana makatulong yung answer ko

A system increases in internal energy by 80 J and 50 J of work are done on it at the same time. What is the heat change of the system

Answers

Answer:

The heat change of the system is 30 J.

Explanation:

Given;

increase in internal energy of a system, ΔU = 80 J

work done on the system, W = 50 J

The heat change of the system can be calculated from first law of Thermodynamics;

ΔU = Q - W

where;

Q is the heat absorbed by the system

W is the work done by the system (negative when work is done by the system and positive when work is done on the system)

Since work was done on the system the increase internal energy is given as;

ΔU = Q  + W

ΔU  - W = Q

80 J - 50 J = Q

30 J = Q

Therefore, the heat change of the system is 30 J.

Expert Answer please 100 points \\ Find the largest value P can have and the boxes move together with equal accelerations?

Answers

P= 71.51KG i think but double check

Distinguish between elastic collasin
and inelastic collasin

Answers

Explanation:

In an elastic collision, two or more bodies are in contact with one another and there is no net loss of kinetic energy in the system. By the virtue of this, the bodies and objects do not stick together after they collide.

Both momentum and kinetic energy are conserved in an elastic collision. An example is when a football hits a wall.

For an inelastic collision, the bodies sticks together after they collide and there is a loss of kinetic energy after they collide. An example of this type of collision is when a gum is throw against a wall.

If both the pressure and volume of a given sample of an ideal gas are doubled, what happens to the temperature of the gas in Kelvins

Answers

Answer: Four times

Explanation:

Given

If Pressure and Volume is double

For ideal gas

PV=nRT

where P=Pressure

V=volume

n=no of moles

R=gas constant

T=temperature

Initially

PV=nRT......(i)

after doubling

(2P)(2V)=nRT'.......(ii)

divide (i) and (ii)

[tex]\frac{PV}{4PV}=\frac{nRT}{nRT'}\\T'=4T[/tex]

So, Temperature becomes 4 times

A projectile is launched at an angle of 60° from the horizontal and at a velocity of
12.0 m/s. What is the horizontal velocity of the projectile? *

Answers

Answer:

60*12.0= 720 = v/60 * 12.0 squared which is 1,728

Explanation:

Horizontal velocity component: Vx = V * cos(α)

The horizontal velocity of the projectile is 6.0m/s

If a projectile is launched at an angle from the horizontal and at a velocity v, the horizontal velocity of the projectile is expressed as:

[tex]v_x =vcos \theta[/tex]

Given the following parameters

v = 12.0m/s

[tex]\theta=60^0[/tex]

Substitute the given parameters into the formula to have:

[tex]v_x=12.0cos60\\v_x=12.0(0.5)\\v_x=6.0m/s\\[/tex]

Hence the horizontal velocity of the projectile is 6.0m/s

Learn more here: https://brainly.com/question/23916021

C
D
А
E
15
Which letter represents the position at which the basketball has the greatest potential energy? Explain

Answers

Which letter represents the position at which the basketball has the greatest potential energy? Explain. Point C. At this point, which is the highest point, all of the ball's energy is gravitational potential energy.

A missile is launched upward with a speed that is half the escape speed. What height (in radii of Earth) will it reach?

Answers

Answer:

The height (h) will be: [tex]\frac{3}{4}R =h[/tex]  

Explanation:

The scape speed equation is given by:

[tex]v_{scape}=\sqrt{\frac{2GM}{R}}[/tex]

Now, the speed of the missile is

[tex]v_{missile}=\frac{1}{2}v_{scape}[/tex]

[tex]v_{scape}=\frac{1}{2}\sqrt{\frac{2GM}{R}}[/tex]

Using the conservation of energy, we can find the maximu height of the missile.

[tex]E_{i}=E_{f}[/tex]

[tex]\frac{1}{2}mv_{scape}^{2}-mgR =-mgh[/tex]

[tex]\frac{1}{2}\frac{2GM}{4R}-gR =-gh[/tex]

[tex]\frac{GM}{4R}-gR =gh[/tex]

Let's recall that g = GM/R², using the equivalence principle. When R is the radius of the earth and M is the mass of the earth.

[tex]\frac{1}{4}gR-gR =-gh[/tex]

[tex]\frac{1}{4}R-R =-h[/tex]    

Therefore the height (h) will be:

[tex]\frac{3}{4}R =h[/tex]    

I hope it helps you!

A person runs up 33 stairs of height 0.25 m. The person weighs 599.85 N. How much energy does it take for the person to reach the top of the stairs? I need the answer ASAP

Answers

Answer:

149.96J

Explanation:

Given parameters:

Number of stairs = 33

Height  = 0.25m

Weight  = 599.85N

Unknown:

Energy the person takes to reach the top  = ?

Solution:

To solve this problem;

  The energy it takes is given as:

          Energy  = weight x height

          Energy  = mass x gravity x height

Now,

  Insert the given parameters and solve;

        Energy  = 599.85 x 0.25  = 149.96J

A particle moves in a circle 1.50 m in radius. Through what angle in radians does it rotate if it moves through an arc length of 2.50 m

Answers

Answer:

95.7 degrees

Explanation:

The angle through which the particle rotate in radians is 1.667 rad.

Given the following data:

Radius of circle = 1.50 meterArc length = 2.50 meters.

To determine the angle through which the particle rotate in radians:

Mathematically, the angular displacement or arc length in circular motion is given by the formula:

[tex]S=r\theta[/tex]

Where:

S is the angular displacement or arc length.r is the radius.[tex]\theta[/tex] is the angle measured in radians.

Making [tex]\theta[/tex] the subject of formula, we have:

[tex]\theta=\frac{S}{r}[/tex]

Substituting the given parameters into the formula, we have;

[tex]\theta = \frac{2.50}{1.50} \\\\\theta =1.667 \;rad[/tex]

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Small cuts or scratches on your body, which are easier to "repair," lead to very rapid
blood clotting; more serious wounds, like a deep gash in your leg, clot more slowly.

True

False

Answers

Small cuts or scratches on your body, which are easier to "repair," lead to very rapid

blood clotting; more serious wounds, like a deep gash in your leg, clot more slowly.

TRUE   ☜(゚ヮ゚☜)

True I believe.......

What is the Pythagorean Theorem used to find and what must you have to use it?
a. magnitude, fight triangle
b. direction, right triangle
c. magnitude, parallelogram
d. direction, parallelogram

Answers

Answer:

A

Explanation:

Sorry it’s twisted but please help, thank you!

Answers

Answer:

A-50 N

Explanation:

Match each disease to the correct pathogen type

Answers

Protist:

Virus:

Fungus:

A) AIDS

B) Histoplasmosis

C) Amoebic dysentery

Answer:

Protist: C) Amoebic dysentery

Virus: A) AIDS

Fungus: B) Histoplasmosis

Hope that helps

Which is another way of saying the law of conservation of mass?
The mass of the reactants always equals the mass of the products.
Matter cannot be created or destroyed.
the law of conservation of matter
all of the above

Answers

Answer:is there a 1 2 3 4 answer?

Explanation:

Summarize what you have learned about power and electrical energy.

Answers

Answer:

i dont know.

Explanation:

school is pointless

The five general principles from the APA are meant to __________. A. be enforceable rules B. be posted in every office C. guide and inspire good conduct D. stand up in court Please select the best answer from the choices provided

Answers

The answer is C guide and inspire good conduct

The five general principles from the APA are meant to: C. Guide and inspire good conduct.

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