A man expends energy at the rate of 200J/s in ascending a vertical height of 44m. If his mass is 75Kg,determine the time taken​

Answer:

gallium ion has 31 electrons

titanium ion has 20 electrons

The displacement y of a wave travelling in the x-direction is given by y=10−4sin(600t−2x+2π) metres.

Where x is expressed in metre and t in second.

What is motion?

It should be noted that when the wave is travelling in the positive x-direction, the equation for the wave is given as y=Asin(kx−ωt).

But if this wave is travelling in the negative x-direction then the wave equation is given as y=Asin(kx+ωt)

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A. The initial PE of the tire is 200 Joules (PE = mgh = 10 kg x 20 m x 9.8 m/s² = 200 J).

B. The kinetic energy of the tire at the bottom of the hill is 200 Joules (KE = PE = 200 J).

C. The speed of the tire at the bottom of the hill is 14.4 m/s (KE = ½ mv² = 200 J, so v = √(2KE/m) = √(400/10) = 14.4 m/s).

What is K.E.?

Kinetic energy is the energy an object has due to its motion. It is defined as the work needed to accelerate an object of a given mass from rest to its stated velocity. It is calculated by multiplying half the object's mass by the square of its velocity. Kinetic energy is a scalar quantity, having magnitude but no direction.

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The required work done in stretching the spring from its natural length to the specified length is calculated to be 105.63 lb.in.

The spring is stretched for 8 in.

The force the spring holds is 10 lb.

The spring is being stretched from its natural length to 13 in.

Work done is calculated to be = ?

The relation between force, spring constant and extension is,

F = k x

Making k as subject, we have,

k = F/x = 10/8 = 1.25 lb/in

The work done in stretching from natural length to 13 in is,

W = 1/2 k x² = 1/2 (1.25) 13² = 105.63 lb.in

Thus, the required work done is calculated to be 105.63 lb.in.

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Answer:

It allows the body to increase blood flow.

If an airplane is flying supersonic, its speed creates a cone-shaped disturbance of compressed air known as a Mach cone. The angle of the Mach cone is dependent on the airplane's speed relative to the speed of sound. If the airplane's speed decreases while it is still supersonic, the Mach cone angle will widen.

When an airplane travels faster than the speed of sound, it generates a Mach cone. The Mach cone is created by the compression of the air in front of the airplane as it moves through the air. The Mach cone's angle depends on the airplane's speed relative to the speed of sound.

If the airplane's speed decreases while it is still supersonic, the Mach cone angle will increase or become wider. This is because the Mach cone angle is inversely proportional to the airplane's speed. The slower the airplane travels, the wider the Mach cone angle becomes.

The Mach cone angle is an important consideration in supersonic flight because it affects the aerodynamics and stability of the airplane. A wider Mach cone angle can lead to increased drag, which can affect the performance of the airplane. This is why monitoring and controlling the Mach cone angle during supersonic flight is important.

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Our simple expression for the canoe's relative velocity to the river is vc/r=( x, y). When compared to the earth, the river is moving at a vr/e= angle (0.54,0). vc/e=(0.55cos(45),0.55sin(45)) is the canoe's angle to the earth.

Magnitude is simply "distance or quantity," according to the definition given in physics. It shows how an object moves when it is in motion, whether that movement is absolute, relative, or of a certain size. It serves as a way to describe something's size or scope.

Scalar values serve as measurement units, and scalar multiplication provides the definition of magnitude. The original quantity is equal to the magnitude of a quantity multiplied by the supplied unit. This is true for all types of tensors, including.

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On the off chance that you spin the yo-yo head in an even circle, you should apply force toward the circle's middle. This force is known as the centripetal force.

The centripetal force continually pulls the yo-yo towards the center of the circle, keeping it moving in a round movement.

The power that conveys the centripetal force to the yo-yo is the pressure in the string.

The string, which pulls the yo toward the circle's middle, gives the centripetal force important to keep up with movement. The string is focused on because of the heaviness of the yo-yo and the speed at which it turns.

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8 kw of shaft work is done on a system while 3 kw of heat is lost from the system. 5 kW  is the rate of energy change of the system.

The rate of energy change of the system can be calculated by subtracting the amount of heat lost from the system from the amount of shaft work done on the system.  while 3 kw of heat is lost from the system. 5 kW  is the rate of energy change of the system.

So, the rate of energy change of the system can be calculated as follows:

Energy change = Shaft work - Heat loss

Energy change = 8 kW - 3 kW

Energy change = 5 kW

So, the rate of energy change of the system is 5 kW.

8 kw of shaft work is done on a system while 3 kw of heat is lost from the system. 5 kW  is the rate of energy change of the system.

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The wrong statement about size of temperature unit is 1 Celsius degree is bigger than 1 Kelvin (b)

The answer choices should have as follow :

A. 1 kelvin is bigger than 1 fahrenheit degree

B. 1 celsius degree is bigger than 1 kelvin

C. 1 celsius degree is bigger than 1 fahrenheit degree

D. 1 celsius degree is equal to 1 kelvin.

The temperature is measured using three different scales, Fahrenheit, Celsius, and Kelvin. 

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The Earth's main energy outputs are reflected light and thermal infrared radiation. Option D is correct.

The Earth reflects a portion of the incoming solar radiation back into space, mainly in the form of visible light. Additionally, the Earth radiates thermal energy back into space in the form of infrared radiation, which is produced by the warm surface and atmosphere of the planet.

Ultraviolet radiation, gamma rays, and X-rays are not the main energy outputs of the Earth, but they do reach the Earth's surface in small amounts, mainly as a result of the Sun's emission of these types of radiation.

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--The given question is incorrect, the correct question is

"Earth's main energy outputs are : A) ultraviolet radiation and visible radiation. B) gamma rays, x-rays, and ultraviolet radiation. C) visible and infrared radiation. D) reflected light and thermal infrared radiation."--

Answer:

It depends on the amount of pressure needed to cut the material.

Iron is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the iron.

Cloth on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.

Explanation:

Answer:

2N

Explanation:

works one=force/weight

10N/5m

2N

The thermal contact resistance can be viewed as being in series. The resistance due to the direct contact locations at the interface and the resistance due to the gaps are both contributing to the overall thermal resistance of the interface.

The thermal resistance of the interface is the sum of the resistances of all the components in the thermal path. If the direct contact resistance and the gap resistance were in parallel, they would have an additive effect on the overall thermal resistance, but that is not the case for thermal contact resistance.

Thermal resistance is a measure of the ability of a material or system to resist the flow of heat. It is defined as the ratio of the temperature difference across the material to the heat flux through it.

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The weight of an object with a mass of 665 N on the surface of the neutron star significantly higher than on Earth, due to the much stronger gravitational pull of the massive neutron star is [tex](6.67 x 10^-11 m^3 / kg s^2)[/tex].

The weight of an object on the surface of a celestial body depends on its mass and the gravitational force acting on it. The equation for the force of gravity is given by[tex]F = G * (m1 * m2) / r^2,[/tex] where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers.

To calculate the weight of an object on the surface of a neutron star with the same mass as the sun and a diameter of 17.0 km, we need to first find the mass of the neutron star and then the radius. The mass of the neutron star can be taken to be the same as that of the sun, which is approximately [tex]1.989 x 10^30[/tex]  kilograms.

Next, we can use the formula for the radius of a sphere to find the radius of the neutron star: [tex]r = (3 * M) / (4 * pi * density)[/tex], where M is the mass of the neutron star and density is the average density of the star. The density of a neutron star is extremely high, on the order of several times that of atomic nuclei. For a neutron star with the same mass as the sun and a diameter of 17.0 km, the radius can be calculated to be about 5.6 km.

Finally, we can use the equation for the force of gravity to find the weight of an object on the surface of the neutron star:

[tex]F = G * (m1 * m2) / r^2[/tex]

where m1 is the mass of the object (665 N), m2 is the mass of the neutron star (1.989 x 10^30 kilograms), r is the radius of the neutron star (5.6 km), and G is the gravitational constant[tex](6.67 x 10^-11 m^3 / kg s^2)[/tex].

The weight of an object with a mass of 665 N on the surface of the neutron star would be significantly higher than on Earth, due to the much stronger gravitational pull of the compact and massive neutron star.

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Answer:

The time it takes for an object to hit the ground depends on its vertical velocity, which is determined by the force of gravity. In this scenario, the vertical velocity of the baseball is determined by its initial vertical velocity (0 m/s) and the acceleration due to gravity (-9.8 m/s^2). The vertical displacement of the baseball can be found using the equation:

d = v_0t + 0.5at^2

where d is the vertical displacement (0.8 m), v_0 is the initial vertical velocity (0 m/s), t is the time, and a is the acceleration due to gravity (-9.8 m/s^2).

Rearranging the equation and solving for t:

t = √(2d/a)

t = √(2 * 0.8 / -9.8)

t = 0.44 seconds

So it takes the baseball 0.44 seconds to hit the ground.

Answer:pizza party

Explanation:

The thrusters must operate for 50 seconds to increase the velocity of the probe to 420 miles per minute.

What is velocity?

Velocity is a vector quantity that measures the rate of change in an object’s position. It is defined as the rate of change of displacement, or the rate of change of an object’s position over time. It has both magnitude, which is the speed of the object, and direction, which is the direction the object is traveling.

To answer this question, we must first calculate the change in velocity that is needed to bring the probe up to its desired speed of 420 miles per minute. We can do this by subtracting the current velocity of the probe from 420 miles per minute. For example, if the current velocity of the probe is 350 miles per minute, the change in velocity needed is 70 miles per minute (420 - 350 = 70).

Next, we need to calculate the thrust force that the thrusters must generate to achieve the desired change in velocity. This can be calculated using the equation Force = Mass x Acceleration, where Mass is the mass of the probe and Acceleration is the desired change in velocity divided by the time period in which it is achieved. For example, if the mass of the probe is 500 kg and the desired change in velocity is 70 miles per minute, the acceleration needed is 0.14 m/s2 (70 miles per minute / 500 kg = 0.14 m/s2).

Finally, we can calculate the amount of time that the thrusters must operate to achieve the desired change in velocity. This can be calculated using the equation Time = Force / Acceleration, where Force is the force generated by the thrusters and Acceleration is the desired change in velocity divided by the time period in which it is achieved. For example, if the thrusters generate a force of 1000 Newtons and the desired change in velocity is 70 miles per minute, the time required to achieve this is 50 seconds (1000 Newtons / 0.14 m/s2 = 50 seconds).

Therefore, in this example, the thrusters must operate for 50 seconds to increase the velocity of the probe to 420 miles per minute.

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Answer:

2.05 Ω

Explanation:

We are here given that the

We need to find out the resistance of the given wire . As we know that,

[tex]\implies R = \rho \dfrac{l}{A} \\[/tex]

[tex]\implies R =\rho \dfrac{ l}{\pi r^2} \\[/tex]

[tex]\implies R =\rho \dfrac{l}{\pi \dfrac{d^2}{4}} \\[/tex]

[tex]\implies R =\rho \dfrac{4l}{\pi d^2}\\[/tex]

substitute the respective values,

[tex]\implies R = 1.720 \times 10^{-8}\times \dfrac{4\times 5000m}{3.14\times (0.74\times 10^{-2}} \\[/tex]

[tex]\implies\underline{\underline{ R = 2.05 \Omega }} \\[/tex]

and we are done!

A hiker walking with an average speed of 1.5 m/s would travel a distance of 2.55 kilometers in 1.7 hours.

This can be calculated using the equation Distance = Speed x Time, or D = S x T. Substituting the given values, we get D = 1.5 m/s x 1.7 hours = 2.55 kilometers.

Speed is a scalar quantity that refers to how quickly an object is moving. It is typically measured in meters per second (m/s). Speed is related to how much distance an object covers over a given amount of time. The faster an object moves, the greater the distance it covers in a given amount of time, and thus the greater its speed. Speed can also be measured in other units, such as miles per hour (mph).

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The charge on the styrofoam plate never seems to run out, as the charge cannot move away from the surface due to its insulating properties.

The aluminum plate and the styrofoam plate have different electrical properties that affect their ability to hold charge. Aluminum is a conductor, meaning it allows the flow of electrical charge, whereas styrofoam is an insulator, which does not allow the flow of charge. When an aluminum plate is charged, the charge can easily move through the conductor, and any excess charge can flow away to ground.

Therefore, the aluminum plate can be charged again and again, as long as there is a source of charge to transfer. In contrast, the styrofoam plate, being an insulator, cannot conduct charge, and any charge that is deposited on it stays trapped on the surface.

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Wilbur's velocity when he reaches the horizontal landing will be approximately 55.6 m/s.

What do you mean by velocity?

Velocity is a vector quantity, meaning it has both a magnitude and a direction. It is a measure of the rate of change of an object's position in a given direction. The velocity of an object is the rate of change of its position in a given direction and is usually expressed as a vector quantity, with speed and direction.

First, we need to calculate the acceleration due to gravity (g):

g = 9.8 m/s²

We can then use the equation for constant acceleration:

V₂ = V₁ + (a * t)

Where V₂ is the final velocity, V₁ is the initial velocity, a is the acceleration and t is the time.

Since Wilbur's initial velocity is 0 (V₁ = 0) and the acceleration is 9.8 m/s², we can solve for the time (t):

t = (V₂ - V₁) / a

Since the final velocity is unknown, we can rearrange the equation to solve for it:

V₂ = (a * t) + V₁

We can now substitute in the values for a and t:

V₂ = (9.8 m/s² * (55 m / 9.8 m/s²)) + 0

V₂ = 55.6 m/s

Wilbur's velocity once he reached the horizontal landing would be 55.6 m/s.

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In the second scenario, more work done on the box by the 5.2 N force compared to the first scenario where no work was done.

The work done on an object is equal to the force applied to it multiplied by the distance it moves in the direction of the force. In the first scenario, the 5.2 N vertical force applied to the box is perpendicular to the direction of motion, so no work is done by this force.

In the second scenario, the 5.2 N horizontal force is in the same direction as the movement, so work is done by this force. The work done by the force can be calculated as follows:

W = F × d = 5.2 N × 2.5 m = 13 Nm

So, in the second scenario, more work was done on the box by the 5.2 N force compared to the first scenario where no work was done.

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1.573 m/s² is the magnitude, in meters per squared second, of the car's average acceleration during the given time period.

Using given numerical values:

a_avg = ((v₁x - v₀x)/ Delta t) i + (v₁y/ Delta t) j

a_avg = (37 - 39)/2.9 i + 4.1/2.9 j

a_avg = -0.690 i + 1.414 j

Magnitude of average acceleration will be:

|a_avg| = √ ((-0.690)² + 1.414²)

|a_avg| = 1.573 m/s²

The greatest size and direction of an item are referred to as the object's magnitude in physics. Vector and scalar values both employ magnitude as a common denominator. Scalar quantities are understood to be those that have only magnitude, according to their definition. Vector quantities, on the other hand, are those that have both magnitude and direction.

Magnitude may be used in a number of different contexts. To name a few of them:

seismic event's strength

Dimension of an electron's charge

force's magnitude

Distance in magnitude

the gravitational force's strength.

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The complete question is:

Give a vector expression for the average acceleration of the car during the given time period in terms of the variables in the problem and

unit vectors i and j.

a_ave = (V₀x + V₁x) i + (V₁y) j/Δt

Part (b) What is the magnitude of the car's acceleration during the time period in question, in m/s²?

a) More than 13% of cats would weigh more than 12 kg.

b) Between 7.2 kg and 9.8 kg of mass would be found in 39.68% of cats.

A measuring of an object's gravitational characteristic, or the quantity of matter it includes, is the object's mass. The gravity forces acting on an object or the force required to carry it is measured by the weight of the thing. An object's downward acceleration due to gravity on earth is roughly 9.8 m/s2.

a) P( x > 12 ) = 1 - P( x < 12 )

= 1 - P[(x - \mu) / \sigma < (12 - 10) / 1.8)

= 1 - P(z < 1.11)                                  

= 1 - 0.8665

= 0.1335

Percentage = 13.35%

b)  P(7.2 < x < 9.8) = P[(7.2 - 10) / 1.8) < (x - \mu) /\sigma  < (9.8 - 10) / 1.8) ]

= P(-1.56 < z < -0.11)

= P(z < -0.11) - P(z < -1.56)

= 0.4562 - 0.0594

= 0.3968

Percentage = 39.68%

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Answer:

Explanation:

If air resistance is ignored , then there is no acceleration in horizontal direction in projectile motion.

The ball is 10 feet off the ground, it has a climbing velocity of 1.33 feet/second. 

Using the equations of motion for motion, we can solve for the upward velocity of the ball when it is 10 feet off the ground.

Let's assume the positive direction is up. We know that it takes 30 seconds for the ball to bounce off the ground, so the total time the ball is in the air is 60 seconds (30 seconds up + 30 seconds down).

Using the equations of motion relating displacement, initial velocity, final velocity, acceleration, and time, we get:

displacement = (final velocity + initial velocity) / 2 * time

When the ball reaches its maximum height, its final velocity is 0. The initial velocity of the ball when it is 10 feet off the ground can be solved for:

10 feet = (0 feet/sec + v0) / 2 * (30 seconds / 2)

where v0 is the initial upward velocity of the ball. Solving for v0 gives:

v0 = 10 feet / (15 seconds / 2) = 1.33 feet/second

So if the ball is 10 feet off the ground, it has a climbing velocity of 1.33 feet/second. 

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The tension force in the rope must withstand a force of 12,270 N to accelerate the 1110-kg car horizontally at 1.20 m/s^2 along a frictionless surface.

The tension force in the rope must be equal to the gravitational force plus the net force required to accelerate the car horizontally.

The equation for this can be determined using Newton's second law of motion, which states that the net force acting on an object is equal to its mass times acceleration (F = ma).

Given that the car has a mass of 1110 kg and is being accelerated at a rate of 1.20 m/s^2, the net force can be calculated as follows:

F = ma = 1110 kg * 1.20 m/s^2 = 1332 N

Since the surface is frictionless, the only force acting against the car is gravity. The gravitational force acting on the car can be calculated using the equation:

Fg = m * g

where m is the mass of the car (1110 kg) and g is the acceleration due to gravity (9.8 m/s^2).

Fg = 1110 kg * 9.8 m/s^2 = 10,938 N

Therefore, the tension force in the rope must be equal to the sum of the gravitational force and the net force, or:

Tension force = F + Fg = 1332 N + 10,938 N = 12,270 N

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Whenever low pressure builds up upon that earth's surface, we might expect divergence and rising air.

What does physics' SI unit for pressure mean?

Pressure is defined as the force acting on a body's surface area divided by its volume. Mathematically, it can be expressed as follows: The SI pressure unit is the Pascal (Pa). Every Newton of force exerts one Pascal of pressure on a square centimeter of ground.

What factors determine pressure?

P = F / A, meaning force per unit of surface area, is the formula for computing pressure. The sign representing pressure in scientific theory is p, and the Standard unit for maintaining pressure is the pascal (symbol: Pa). One pascal is equivalent to one Newton per square meter of force applied perpendicularly to a surface.

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Full question-

The cell boundary's net flux measures -0.887 [tex]Wb.m^{2}[/tex] in both magnitude and direction (inward or outward).

Any impact that seems to flow through or move through a surface or substance is referred to as a magnetic flux. The following formulas are used to determine the size and direction (inward or outward) of the net flux through the cell boundary:

Ф = Q/ε, where:

Q is the net charge

ε is the permittivity of free space.

As per the question,

Φ = (-7.85 x 10⁻¹²)/ (8.85 x 10⁻¹²)

Φ = - 0.887 Wb.m²

The negative sign here indicates the outward flow of the flux. Magnetic flux is a measure of the strength of a magnetic field over a specific area, to put it simply. It has [[tex]ML^{2} T^{-2} A^{-1}[/tex]], as the dimension of mass length squared per square of time and electric current.

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Complete question is:

The human nerve cells have a net negative charge and the material in the interior of the cell is a good conductor. if the cell has a net charge of - 7.85 pc, what are the magnitude and direction (inward or outward) of the net flux through the cell boundary.