A loop of radius r = 3.0 cm is placed parallel to the xy-plane in a uniform magnetic fieldB= 0.75 Tˆk. The resistance of the loop is 18 Ω. Starting at t = 0, the magnitude of thefield decreases uniformly to zero in 0.15 seconds. What is the magnitude of the electric currentproduced in the loop during that time?

Answer: Solid to a Liquid Liquid to a Solid Liquid to a Gas Gas to a Liquid Solid to a Gas Gas to a Solid

Explanation:

Answer:

Question 1 the answer is 5 cm for the one pulley system, I just took the quiz

Question 2 is 10 cm

Explanation:

The rope only needs to move 5 cm for the mass to move from 15 to 20.

For the 2 pulley system the string has to move twice as far making it 10 cm. I took the quiz and got 100%

Answer:

F = 93.49 × 10^(-9) N

Explanation:

We are given;

Length of rectangle; a = 1.1 m

Width of rectangle; b = 0.9 m

Charge on rectangle; q = 2.3 × 10^(-9) C

Formula for force is;

F = kq²/r²

Where;

k is a constant = 8.99 x 10^(9) N.m²/C²

a) on the width side, we have;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/0.9²

F = 58.79 × 10^(-9) N

This is on the y-axis

b) on the length side, we have;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/1.1²

F = 39.3 × 10^(-9) N

This is on the x-axis

C) using pythagoras theorem, for the diagonal side, we have c² = a² + b².

Thus;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/(1.1² + 0.9²)

F = 23.54 × 10^(-9) N

Using trigonometric ratios, we can find the angle θ.

tan θ = b/a

tan θ = 0.9/1.1

tan θ = 0.8182

θ = tan^(-1) 0.8182

θ = 39.29°

Resolving along x and y axis, we have;

F_x = 23.54 × 10^(-9) × cos 39.29°

F_x = 18.22 × 10^(-9) N

F_y = 23.54 × 10^(-9) × sin 39.29°

F_y = 14.91 × 10^(-9) N

Resultant force will be;

F = √((Σf_x)² + (ΣF_y)²)

F = √[(18.22 × 10^(-9)) + (39.3 × 10^(-9))]² + [(14.91 × 10^(-9)) + (58.79 × 10^(-9))²]

F = √[(33.0855 × 10^(-16)) + (54.317 × 10^(-16))]

F = 93.49 × 10^(-9) N

Answer Expert Verified

Hello here is your answer and also please mark me as brainlest

Since one revolution around a circle is 2 pi radian; hence 1 rpm equals 2 pi radians per minute. And because a minute has 60 seconds, 1 rpm equals 1/60 revolution per second. Therefore, we have 2 pie/60 * 15.3 = 0.2513 rps. The linear velocity v = wr where w is the angular velocity in rad/s and r is the distance. So we have 0.2513 * 10.0 = 2.513 rad/s The centripetal acceleration is given by a = w^2 r = (2.513)^2 * 10 = 63.15 rad/s2 The centripetal force F = mass * centripetal acc = 75 * 63.15 = 4736.25 N The torque = centripetal force * distance = 4736 * 63.15 = 299078.4 Nm Two forces acts on the astronaut. The normal force and acceleration due to gravity.

I hope this help you

brainlest

Rotational kinematics and Newton's second law allow to find the results for the astronaut's movement in the centrifuge are:

       a) The angular velocity is: w = 1.927 rad / s

       b) The linear velocity is: v = 23.1 m / s

       c) The centripetal acceleration is: a = 6.417 10³ m / s²

       d) The centripetal acceleration is: a = 6.548 10² g

       e) The centripetal force F = 5.49 10⁵ N

given parameters

To find

    a) angular velocity

    b) linear velocity

    c) centripetal acceleration

    d) acceleration in units of gravity (g)

    e) the centripetal force

The angular velocity is defined as the rotated angle in the unit of time.

         [tex]w = \frac{\Delta \theta}{t}[/tex]  

Angular and linear variables are related.

         v = w r

Where w is the angular velocity, θ  is the angle, t the time, v the lienal velocity and R the radius of the cetnrifuga

Let's answer the questions:

a) The angular velocity of the centrifuge and the astronaut are equal

         w = 1.927 rad / s

b) Linear velocity

         v = 1.927 12.0

         v = 23.1 m / s

c) Centripetal acceleration has the formula:

          a = [tex]\frac{v^2}{R}[/tex]  

          a = [tex]\frac{23.1^2}{12.0}[/tex]  

          a = 6.417 10³ m / s²

d) The value of this eceleration as a function of gravity

          [tex]\frac{a}{g}[/tex]  = 6.417 10³ / 9.8

          [tex]\frac{a}{g}[/tex]  = 6.548 10²

          a = 6.548 10² g

e) The centripetal force

           F = ma

           F = 85.5 6.417 10³

           F = 5.49 10⁵ N

In conclusion, using rotational kinematics and Newton's second law we can find the results for the movement of the astronaut in the centrifuge are:

       a) The angular velocity is: w = 1.927 rad / s

       b) The linear velocity is: v = 23.1 m / s

       c) The centripetal acceleration is: a = 6.417 10³ m / s²

       d) The centripetal acceleration is: a = 6.548 10² g

       e) The centripetal force F = 5.49 10⁵ N

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Answer:

θ₁ = 5.4°

θ₂ = 10.86°

Explanation:

The angle ca be found by using grating equation:

mλ = d Sinθ

where,

m = order of diffraction

λ = wavelength = 405.3 nm = 4.053 x 10⁻⁷ m

d = grating element = 1/230 lines/mm = 0.0043 mm/line = 4.3 x 10⁻⁶ m/line

θ = angle = ?

FOR m = 1:

(1)(4.053 x 10⁻⁷ m) = (4.3 x 10⁻⁶ m/line) Sin θ₁

Sin θ₁ = 0.09425

θ₁ = Sin⁻¹(0.09425)

θ₁ = 5.4°

FOR m = 2:

(2)(4.053 x 10⁻⁷ m) = (4.3 x 10⁻⁶ m/line) Sin θ₁

Sin θ₂ = 0.1885

θ₂ = Sin⁻¹(0.1885)

θ₂ = 10.86°

Answer:

Because when you move a object the energy stored in moving objects. As the object moves faster, more energy is stored. Motion energy is the sum of potential and kinetic energy in an object that is used to do work.

Explanation:

answer it please

What is the Central Idea of "Shelter Dog Protects Owner with Epilepsy“

What is the author’s viewpoint?

Do you agree or disagree with that viewpoint?

Why? Explain your answer.

parpgraph 1-2

Answer:

Yes, the energy used to lift the book was stored in the book as potential energy. The book moved when it was let go.

Explanation:

This is what edmentum sample answer says so I hope this helps out!

Answer:

The value of 96,745 joules in Btus is 91.6965673 or 91.7 Btus.

Explanation:

Btus stands for British thermal unit. It is the unit of energy. 96,745 Joules is equal to 91.7 Btus of energy.

Energy is the quantitative property of an object which is transferred to an object or to a physical system, that is recognizable in the performance of the work done and in the form of heat and light generated by the object or system. Energy is a conserved quantity, according to the law of conservation of energy which states that energy can be transformed, but not created or destroyed.

A British thermal unit (Btu) is a measure of the heat content or energy of fuels or energy sources. 1 BTU is roughly equal to the amount of energy which is required to raise the temperature of one pound of water by 1 degree Fahrenheit.

1 Joule = 0.000947817 Btu

Therefore, 96,745 Joules = 91.696 or 91.7 Btus

The value of 96,745 joules in Btus is 91.6965673 or 91.7 Btus.

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Answer: The displacement is 18.8 meters.

Explanation:

Let's define the North as the positive y-axis and the East as the positive x-axis.

We also can assume that if the point (x, y) represents the position of the boy, the initial position is (0 paces, 0 paces).

"A boy on a treasure hunt walks 12 paces West,"

West would be the negative x-axis in this case, then:

the position will be (-12 paces, 0 paces)

"then 21 paces North"

Now the position will be (-12 paces, 21 paces)

"then 25 paces East."

Now the position will be (-12 paces + 25 paces, 21 paces)

                                       = (13 paces, 21 paces)

Now we have the initial and final positions of the boy,  (0 paces, 0 paces) and (13 paces, 21 paces) respectively.

We want to find the displacement, which is defined as the distance between the final position and the initial position.

Remember that for two vectors (a, b) and (c, d), the distance is:

D = √( (a - c)^2 + (b  - d)^2)

In this case, the displacement will be:

D = √( ( 13 paces - 0 paces)^2 + (21 paces - 0 paces)^2) = 24.7 paces.

But we want this quantity in meters, so we can use the relation:

1 pace = 0.762 meters.

Then 24.7 paces, are 24.7 times 0.762 meters.

D = 24.7*0.762 m = 18.8 meters.

Answer:

10 seconds a mile. D. 10 s

Explanation:

25-24.6= .4

To find how long she will take to move 4 m relative to the train, take the distance she wants to travel divided by her velocity relative to the train.

4 / .4 = 10

Hope this helps you! :)

Answer:

10s

Explanation:

Answer:

induced electromotive force (Voltage)    E = - N dΦ / dt

Explanation:

When the magnetic flux this coil induces a current in each turn of the coil, which is why an induced electromotive force (Voltage) appears at the ends of the coil.

This phenomenon is fully explained by Faraday's law

        E = - dΦ / dt

where in the case of a coil with N turns of has

        E = - N dΦ / dt

Rl flux is the product of the normal to the area by the magnetic field, in this case the flux changes so we can assume that the area of ​​the coil is constant

Answer:

The energy stored in the solenoid is 7.078 x 10⁻⁵ J

Explanation:

Given;

diameter of the solenoid, d = 2.80 cm

radius of the solenoid, r = d/2 = 1.4 cm

length of the solenoid, L = 14 cm = 0.14 m

number of turns, N = 200 turns

current in the solenoid, I = 0.8 A

The cross sectional area of the solenoid is given as;

[tex]A = \pi r^2\\\\A = \pi (0.014)^2\\\\A = 6.16*10^{-4} \ m^2[/tex]

The inductance of the solenoid is given by;

[tex]L = \frac{\mu_0 N^2A}{l} \\\\L = \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H[/tex]

The energy stored in the solenoid is given by;

E = ¹/₂LI²

E = ¹/₂(2.212 x 10⁻⁴)(0.8)²

E = 7.078 x 10⁻⁵ J

Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J

The energy stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A is 7.07 × 10⁻⁵ J.

A solenoid is a type of electromagnet, whose purpose is to generate a controlled magnetic field through a coil wound into a tightly packed helix.

First, given the diameter of the solenoid (d) is 2.80 cm (0.0280 m), we can calculate the cross-sectional area (A) using the following expression.

[tex]A =\pi \times (\frac{d}{2} )^{2} = \pi \times (\frac{0.0280}{2} )^{2} = 6.16 \times 10^{-4} m^{2}[/tex]

Next, we will calculate the inductance (L) of the solenoid using the following expression.

[tex]L = \frac{\mu _0 \times N^{2} \times A}{l} = \frac{(4\pi \times 10^{-7}H/m ) \times 200^{2} \times (6.16 \times 10^{-4}m^{2} )}{0.140m} = 2.21 \times 10^{-4} H[/tex]

where,

Finally, for a current (I) of 0.800 A, we can calculate the energy stored (E) using the following expression.

[tex]E = \frac{1}{2} \times L \times I^{2} = \frac{1}{2} \times (2.21 \times 10^{-4}H ) \times (0.800A)^{2} = 7.07 \times 10^{-5} J[/tex]

The energy stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800 A is 7.07 × 10⁻⁵ J.

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Answer:

The value of a is 5 and b is -4.

Explanation:

You have to solve it by comparison :

(8 , 3) + (b , 2) = (4 , a)

(8+b , 3+2) = (4 , a)

8 + b = 4

b = 4 - 8

b = -4

3 + 2 = a

a = 5

Answer:

1: 51 m

2: some energy was transformed to other forms

3: 3.24

4: 45j

5: 1020

Explanation:

The required height of hill is 51 m. Hence, option (C) is correct.

Given data:

The mass of person is, m = 80 kg.

The energy expended during climbing is, E = 40,000 J.

The energy possessed by the body by virtue of height is known as potential energy. In the given case, the energy expended by the person will be stored in the form of potential energy. Then,

E = U

E = mgh

here, h is the height of hill and g is the gravitational acceleration.

Solving as,

40000 = 80(9.8) h

h ≈ 51 m

Thus, we can conclude that the required height of hill is 51 m. Hence, option (C) is correct.

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Let H and D denote the height and diameter, respectively, of cylinder P, and h and d the height and diameter of cylinder Q.

Then the volumes of P and D, denoted V and v, respectively, are

V = π (D / 2)² H = π D ² H / 4

v = π (d / 2)² h = π d ² h / 4

The height of P is twice the height of Q, so H = 2h.

The diameter of P is half the diameter of Q, so D = d / 2.

Substitute these into equation for the volume of cylinder P:

V = π (d / 2)² (2h) / 4

V = π (d ² / 4) (2h) / 4

V = π d ² h / 8

V = 1/2 • π d ² h / 4

V = v / 2

That is, cylinder P has half the volume of cylinder Q.

Recall that density is equal to mass per unit of volume. So R and ρ, the respective densities of cylinders P and Q, are

R = m / V = m / (v / 2) = 2 m / v

ρ = m / v

which means cylinder P has twice the density of cylinder Q (assuming both cylinders have the same mass m).

Answer:

Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.

Answer:

Frequency and period are distinctly different, yet related, quantities. Frequency refers to how often something happens. Period refers to the time it takes something to happen. Frequency is a rate quantity.

Explanation:

Answer:

The right approach will be "1.3". A further explanation is given below.

Explanation:

As we know,

In Decibels, the change in sound volume will be:

= [tex]10log\frac{I_1}{I_2}[/tex]

Now,

According to the question,

⇒ [tex]1=10 log \frac{I_1}{I_2}[/tex]

By applying cross multiplication and putting the value of log, we get

⇒ [tex]10^{\frac{1}{10} }=\frac{I_1}{I_2}[/tex]

⇒ [tex]1.26=\frac{I_1}{I_2}[/tex]

⇒ [tex]\frac{I_1}{I_2}=1.3[/tex]

Answer:

363

Explanation:

80g of kerosene was burned to raise the temperature

k = 90+273

= 363

Answer:

Its color

Explanation: I got it right

Answer:

2.1 rad/s

Explanation:

Given that,

Mass of a tether ball, m = 0.546 kg

Length of a rope, l =  4.56 m

The maximum tension the rope can withstand before breaking is 11.0 N

We need to find the maximum angular speed of the ball. Let v is the linear velocity. The maximum tension is balanced by the centripetal force acting on it. It can be given by :

[tex]F=\dfrac{mv^2}{r}\\\\v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{11\times 4.56}{0.546}} \\\\=9.584\ m/s[/tex]

Let [tex]\omega[/tex] is the angular speed of the ball. The relation between the angular speed and angular velocity is given by :

[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\=\dfrac{9.584}{4.56}\\\\=2.1\ rad/s[/tex]

So, the maximum angular speed of the ball is 2.1 rad/s.

Answer:

0.2Nm

Explanation:

F1 = 30.0N

F2 = 20.0N

R = 2.0cm = 0.02m

F1R1 - F2R2 = net Torque

30(0.02) - 20(0.02) = net Torque

0.6-0.4 = net Torque

Therefore net Torque = 0.2Nm

The figure below shows two forces [tex]F_1[/tex] = 30.0 N and [tex]F_2[/tex] = 20.0 N acting on an object that can rotate around a centre axle. The net torque in 0.2 N-m

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is a torque.

Torque is defined as Γ=r×F=r F sin(θ). In other words, torque is the cross product of the force vector, where 'a' is the angle between r and F, and the distance vector (the distance between the pivot point and the place where force is applied).

Torque due to [tex]F_1[/tex] = 30.0 N is 0.6 N-m outside the plane and due to   [tex]F_2[/tex] = 20.0 N is 0.4 N-m inside the plane so net torque is 0.2 N-m outside the plane.

The figure below shows two forces [tex]F_1[/tex] = 30.0 N and  [tex]F_2[/tex] = 20.0 N acting on an object that can rotate around a centre axle. The net torque in 0.2 N-m outside the plane.

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Explanation:

Track and Field is a sport, which is includes disciplines of running, jumping, and throwing events. The sport traces back to Ancient Greece. The first recorded examples of this sport were at the Ancient Greek Olympics. In Ancient Greece, only one event was contested, the stadion footrace. Later on, the game expanded to more events.Events of track and field are divided into three: track events, field events, and combined events. Track events consist of Sprints, middle-distance, long distance, hurdles and relays; Field events consist of jumps and throws; while combined events consist of pentathlon, heptathlon, and decathlon. Track and field is usually played outdoors in stadiums. The usual features of a track and field stadium are the outer running track, and the field within the track

Answer:

i want the answer

Explanation:i want the answer

a. The power consumed by this appliance is 931.7W

b. The electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is 4.65kWh

c. The  monthly cost of using this food processor is 32.55 $

The rate of consumption of energy is power. it is given by the product of potential difference(V) and current(I)

a. P = VI  

here V  = 110V . I = 8.47 A

P = 110 x 8.47 = 931.7W

hence power consumed is 931.7 W

b. electrical energy  consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day is

E = P/t

Here, P = 931.7 W = 0.93kW

t = 10 x 30 = 300 min = 5 h

So, E =0.93 x 5 =  4.65 kWh

hence electrical energy consumed is 4.65kWh

c. The monthly cost of using the food processor is

given ,

Cost of one unit is 7.00$

Cost of 4.65 unit will be  7.0 x 4.65 =  32.55$

monthly cost of using the food processor  is  32.55$

2.

a.  Power consumption of refrigerator is  416 W

P = E/t  

Here, E = 70 kwh . t = 1 week = 168 h

So, P=  70/168 = 0.416 kW = 416 W

b. Current drawn by the refrigerator  is 3.46A

P = VI

Here, V = 120V, P = 416 W

So, I = P/V = 416/120 = 3.46 A

3.

a. The resistance of the element is 5.14 Ω

b. Current drawn by the boiler is 23,33A

Resistance is the hindrance caused in the flow of current

a. The resistance is given by [tex]R = v^{2} / P[/tex]

here V = 120V , P = 2.8kW = 2800W

R = (120 x 120)/ 2800 = 5.14Ω

Hence Resistance of the boiler is 51.4Ω

b.   V = IR so, I = V /R

Here, V = 120V , R = 5.14Ω

So, I = 120/51.4 = 23.33 A

Hence current drawn by the boiler is 23.33A

The alternate way to find the current is by using formula

P = VI  

I = P/V

Since, P = 2800W,   V = 120V

So, I = 2800/120 =23.33 A

Hence Current comes out to be the same from both the method which verifies the answer .

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Answer:

Explanation:

When discussing Newton's laws of motion, the most likely used terms when talking about Newton's third law of motion are action and reaction. According to this law, for every action there is an equal and opposite reaction

Answer: C. "action" and "reaction"

Explanation: Newtons 3rd law of motion: for every action, there is an equal and opposite reaction (action and reaction forces are described by this law).

Have a nice day. :)

Answer:

a = 2.94 m/s²

Explanation:

In order for the cup not to slip, the unbalanced force on cup must be equal to the frictional force:

Unbalanced Force = Frictional Force

ma = μR = μW

ma = μmg

a = μg

where,

a = maximum acceleration for the cup not to slip = ?

μ = coefficient of static friction = 0.3

g = acceleration due to gravity = 9.8 m/s²

Therefore,

a = (0.3)(9.8 m/s²)

a = 2.94 m/s²

Answer:

one time i was one the flat ground at my aunts house then we went on a hike so i brought my bike it had just rained that day so it was kinda muddy so there was sticks everywhere.i was riding up hill and noticed that it was very hard,then i rode down hill and it was much better

Explanation:

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is [tex]|v| = 6.93[/tex]

Explanation:

From the question we are told that

    The initial point is [tex](x_1 , y_1 , z_1 ) = (-1 , 7 , 4 )[/tex]

    The  terminal point is  [tex](x_2 , y_2 , z_2) = (-5 , 11, 8 )[/tex]

Generally the magnitude of the vector is mathematically represented as

     [tex]|v| = \sqrt{(x_2 -x_1 )^2 + (y_2 - y_1 )^2 + (z_2 -z_1)^2}[/tex]

=>   [tex]|v| = \sqrt{(-5 -(-1) )^2 + (11 - 7 )^2 + (8 -4)^2}[/tex]

=>   [tex]|v| = 6.93[/tex]

Answer:

125 m

Explanation:

m = 3kg

v = 50m/s

u = 0m/s

a = +g = 10m/s²

s = H = ?

using the formula,

v² = u² + 2as

50² = 0² + 2(10)(H)

2500 = 20H

H = 2500/20

H = 125m

Answer:

They both hit the ground at the same time.

Explanation:

if you drop a 100 g and 200 g mass simultaneously from the same height they’ll hit the ground at the same time.

Yes, there is a role of a very simple equation of kinematics i.e.

s=ut+1/2(at^2)

so, s means the height is the same for both masses(h), u(initial velocity) is obviously zero cause you are dropping it, a (acceleration) is due to the gravity here only ‘g’.

time is taken for a particular object to hit the ground,

t= (2h/g)^1/2 .

We can see that there is no term for the mass of objects, meanwhile, the mass of the object has nothing to do with the time taken in hitting the ground in this case.