A lion and a pig participate in a race over a 2.20 km long course. The lion travels at a speed of 18.0 m/s and the pig can do 2.70 m/s. The lion runs for 1.760 km and then stops to tease the slow-moving pig, which eventually passes by. The lion waits for a while after the pig passes and then runs toward the finish line. Both animals cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.
(a) How far (in m) is the pig from the finish line when the lion resumes the race? (b) For how long in time (in s) was the lion stationary?

Explanation:

C) is incorrect.  The mass is equivalent to the moment of inertia in an angular formula.

The others appear all correct.

T * theta = F * r * theta = F * (r theta) = fx = work

This is the only one that needed explanation.  The others should be obvious.

Answer:

E = - 500 V / m,  v = 30.95 10⁴ m / s   and    t = 6.46 10⁻⁶ s

Explanation:

For this problem we use the relation

           ΔU = - E s

           E = -ΔU / s

           E = - 500/1

           E = - 500 V / m

Now we can look for the proton approach

           F = q E

let's use Newton's second law

           F = m a

           a = F / m

           a = q E / m

Now let's use kinematics relations, where the proton starts from the rest

v₀ = 0

           v² = v₀² + 2 a x

           v = √2 q E / m x

           v = √ (2 1.6 10⁻¹⁹ 500 / 1.67 10⁻²⁷  1)

           v = √ (958.08 108)

           v = 30.95 10⁴ m / s

for time let's use the equation

          x = v₀ t + ½ to t2

          t = √2x / a

          t = √ (2x m / qE)

          t = √ (2 1 1.67 10⁻²⁷ / (1.6 10⁻¹⁹ 500))

          t = √ (0.004175 10⁻⁸)

          t = 0.0646 10⁻⁴ s

          t = 6.46 10⁻⁶ s

Answer:

The purpose of adding force vectors is to determine the net force acting upon an object. In the above case, the net force (vector sum of all the forces) is 0 Newton. ... We would say that the object is at equilibrium. Any object upon which all the forces are balanced (Fnet = 0 N) is said to be at equilibrium.

Explanation:

hope that helps you

Answer:

Explanation:

The y component of the force is 100 sinØ . But given that y component is 30N

so 100 sinØ = 30

sinØ = 0.3

Ø = 17.5°.

X component of force = 100 cosØ

= 100 cos17.5

= 95.35 N .

Y component of force = 30 N .

Angle Ø = 17.5°.

Answer:

convex lens

Explanation:

Answer:

A) is repelled by the sphere.

Explanation:

When a charged insulated rod is touched with an insulated conducting sphere , some  charge on the rod gets transferred to the sphere . So they become similarly charged . We all know that there is repulsion when two similarly charged object are brought near to each other . Hence here too there will be repulsion between the rod and the sphere when the rod is brought near the sphere.

Answer:

Explanation:

When an unplanted tree is pulled across the lawn then a variety of forces will be acting on the tree i.e.

1.There will be gravity force

2.Friction force to oppose the motion

3.Applied force which is pulling the tree

4. Normal force in response to the gravity force.

Answer:

Explanation:

he created the bulb first. He was an American. He was an inventor and also a businessman. Moreover he invented the phonograph, and the motion picture camera, as well as improving the telegraph and telephone.

hope this helps

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Answer:

400 W

Explanation:

Ignoring the efficiency rating for the transformer we have to assume 100% .. Also, the power input to primary is equal to the power output in secondary.

This means that power input = 400 W = power output

Answer:

Explanation:

The initial vertical velocity of the stone is given by:

Vyo= VSin theta

Given: V = 15m/s , theta = 31°

Vyo = 15 Sin 31

Vyo = 7.73m/s

Final vertical velocity, Vf can be determined by using kinematic equation

Vf^2 - U^2 = 2as

Vf^2 -( 7.73)^2 = 2(9.8×(-8))

Vf^2 = 59.75 + 156.8

Vf^2 = 216.6

Vf = sqrt(216.46)

Vf = 14.72m/s

Therefore,The stone strikes the ground in 14.72m/s

Answer:

40N

Explanation:

Answer:

Explanation:

Heat energy naturally transfers from a high temperature substance to a low temperature substance.

It  is not a statement or direct application of the second law of thermodynamics.

The change in internal energy of a system can be found by combining the heat energy added to a system minus the work done by the system.

It  is not a statement or direct application of the second law of thermodynamics. This statement is in accordance with first law of thermodynamics.

All the other two statements are in accordance with second law of thermodynamics.

The statement B is not a statement or direct application of the second law of thermodynamics.

Statements given to us:

(a.) There are no 100% efficient heat engines.

(b.) Heat energy naturally transfers from a high temperature substance to a low temperature substance.

(c.) The change in internal energy of a system can be found by combining the heat energy added to a system minus the work done by the system.

(d.) All natural processes tend toward states of increased entropy.

According to the Second Law of Thermodynamics:

So, according to the above points statement B is not a statement or direct application of the second law of thermodynamics.

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Answer:

the tension in the string is 5.59 N

Explanation:

Here ,

m_1 = 0.385 Kg

m_2 = 0.710 Kg

Using second law of motion ,

a = F_net / effective mass

a = (0.710- 0.385)×9.8/(0.710 + 0.385 + 0.0125/0.15^2)

a = 1.93 m/s^2

Now , let tension be T ,

then,

mg-T=ma

0.710×g - T = 0.710×1.93

T = 5.59 N

the tension in the string is 5.59 N

Answer:

Explanation:

A rectifier is an electrical device that converts alternating current (AC) to direct current (DC), a process known as rectification. Rectifiers have many uses including as components of power supplies and as amplitude modulation detectors (envelope detectors) of radio signals. Rectifiers are most commonly made using solid state diodes but other type of components can be used when very high voltages or currents are involved. When only a single diode is used to rectify AC (by blocking the negative or positive portion of the waveform), the difference between the term diode and the term rectifier is simply one of usage. The term rectifier describes a diode that is being used to convert AC to DC. Most rectifier circuits contain a number of diodes in a specific arrangement to more efficiently convert AC power to DC power than is possible with only a single diode.

Answer:

a)

[tex]u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)[/tex]

b)

m = 48lb

c)

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

[tex]u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)[/tex]    (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

[tex]|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s[/tex]

Then, you obtain by replacing in (1):

6in = 0.499 ft

[tex]u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)[/tex]

b.

mass, m = 48lb

c.

b = 144.76 lb/s

Answer:

m = 0.217 kg

Explanation:

We can solve this exercise using the conservation of angular momentum. For this the system is formed by the bar and the disk, so that the forces during the crash have been internal and the angular momentum is preserved

initial angular mount. Before impact

        L₀ = L_bar + L_ disk

        L₀ = I_bar w₀ + m r v₀

final angular momentum. Right after the crash

         [tex]L_{f}[/tex] = I_bar wf = m r v_{f}

The moment of inertia of a bar that rotates at its ends is

        I_bar = 1/12 M L

how the angular momentum is conserved

       L₀ = L_{f}

      I_barr w₀ + mr v₀ = I_barr w_{f} + m r v_{f}

      I_bar (w₀- w_{f}) = m r (v₀- v_{f})) r

      m = I_bar (w₀ - w_{f}) / r (v₀ -v_{f})

      m = 1/12 M L (w₀ -w_{f} ) / r (v₀ -v_{f})

in the exercise it indicates that the initial speed of the disc is v₀ = 20 m / s and its final speed is v_{f} = -16 m / s, the negative sign is because the disc recoils

we calculate

     m = 1/12 35 0.90 (0 + 1.14) / [0.30 (30- (-16))]

     m = 0.217 kg

Answer:

The answer is 1

Explanation:

It's fr 1

Sinec the light rays bends away from the normal when it enters into medium 2, the denser medium is medium 1.

Refraction is the bending of light waves at the boundary of media of different densities.

During refraction, if light travels from less dense to a denser medium, the light rays is bent towards the normal.

However when light travels from denser to less dense medium, the light rays bends away from the normal.

Therefore, since the light rays bends away from the normal when it enters into medium 2, the denser medium is medium 1.

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Answer:

0.18 Nm

Explanation:

Note: Torque is independent of the mass of a body.

From the question,

T = F×d.......................Equation 1

Where T = Torque, F = force applied to the wrench, d = length of the wrench.

Given: F = 12 N, d = 15 cm = 0.015 m

Substitute into equation 1

T = 12(0.015)

T = 0.18 Nm.

Hence the torque applied is 0.18 Nm

Answer:

662480 J

Explanation:

The heat required to convert 0.8Kg of ice at -35°c to steam at 100°c is the sum of the heat required to raise the temperature of the ice from -35°c to 0°C, the latent heat of fusion of ice and the heat required to raise the temperature of the ice from 0°c to 100°c.

Latent heat of fusion for ice= 3.36× 10^5 J Kg-1

Specific heat capacity of ice= 2060 J kg−1K−1

Specific heat capacity of water= 4200 JKg-1K-1

Heat required to raise the temperature of the ice to fusion point

H= 0.8 × 2060 × [0-(-35)]

H= 57680 J

Latent heat of fusion of ice;

H= mL

H= 0.8 ×3.36× 10^5

H= 2.688×10^5 J

Heat required to raise the temperature of the water to 100°C

Since mass is conserved, the mass of ice that has melted has been turned into an equivalent mass of water.

Therefore mass of water formed= 0.8Kg

H= 0.8× 4200 × 100

H= 336000J

Therefore total heat required;

H= 57680 + 2.688×10^5 + 336000

H= 662480 J

Answer:

2468,080j

Explanation:

Answer:

C. Television

Explanation:

Mostly in cathode ray television, a TV has many of different types of capacitors, used as connections between circuits, as timing components and as electronic filters. TV capacitors perform many functions.

capacitor acts as a reservoir for electric charge, storing and releasing electricity in precise amounts.

What is a Capacitor  ?

A capacitor is a simple device consisting of a pair of metal foils separated by a thin insulator, such as plastic, used basically for storing charge

Answer:

D) Heating and Cooling system

Explanation:

just took the test and got it right :)

Answer:

The velocity of the ball is 3.52 m/s.

Explanation:

A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.

Given that the ball was thrown vertically upward on the top of a skyscraper of  height 61.9 m. So that the velocity can be determined by;

      u = [tex]\sqrt{\frac{2H}{g} }[/tex]

Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/[tex]s^{2}[/tex], then;

 u = [tex]\sqrt{\frac{2*61.9}{10} }[/tex]

   = [tex]\sqrt{\frac{123.8}{10} }[/tex]

u  = 3.5185

The velocity of the ball is 3.52 m/s.

Answer:

[tex]T = 6.75\,N\cdot m[/tex]

Explanation:

Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:

[tex]T = F\cdot r \cdot \sin \theta[/tex]

[tex]T = F_{\bot} \cdot r[/tex]

Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:

[tex]T = (15\,N)\cdot (0.45\,m)[/tex]

[tex]T = 6.75\,N\cdot m[/tex]

Answer:

9780 W

Explanation:

Power: This can be defined as the rate at which work is done. The S.I unit of power is Watt (W).

From the question,

P = W/t....................... Equation 1

Where P = power, W = work, t = time.

But,

W = F×d.............. Equation 2

Where F = force, d = distance.

Substitute equation 2 into equation 1

P = (F×d)/t................. Equation 3

Given: F = 24450 N, d = 12 m, t = 30 s.

Substitute these vales into equation 3

P = (24450×12)/30

P = 9780 W.

Hence the power needed for the elevator trip = 9780 W

Answer:

Explanation:

Power is defined as the rate of workdone with respect to time.

The formula for calculating power P needed by the eleveator is expressed as;

Power = [tex]\frac{workdone}{time}[/tex]

Since Workdone = Force*distance then;

[tex]Power = \frac{force * distance}{time}[/tex]

Given the weight of elevator = 24,450Newtons

distance moved by the elevator = 12m

time taken = 12seconds.

Substituting this values in the formula given will give;

[tex]Power = \frac{24,450*12}{30} \\Power = \frac{293,400}{30} \\Power = 9,780Watts\ or\ 9.78kW[/tex]

The amount of power needed for the elevator trip is 9,780Watts

Answer:

a)   y = 0.459 m , b)   t = 13 s

Explanation:

a) For this exercise we use Newton's second law to find the acceleration of the block

we fix a reference system with the x axis parallel to the plane and the y axis perpendicular to it

X axis

          -Wₓ - fr = m a               (1)

Axis y

          N - [tex]W_{y}[/tex] = 0

          N = W_{y}

the friction force has the formula

          fr = μ N

let's use trigonometry to find the components of the weight

          sin 25 = Wₓ / W

         Wₓ = W sin 25

          cos 25 = W_{y} / W

          W_{y} = W cos 25

we substitute in 1

          - W sin 25 - μ W cos 25 = m a

          - g (sin 25 - μ cos 25) = a

let's calculate

          a = - 9.8 (sin 25 - 0.12 cos 25)

         a - 0.25 m / s

this is the acceleration on the plane, so we can use the kinematic relations in one dimension

the highest point where the block rises the speed is zero (va = 0)

          v² = v₀² - 2 a y

           y = v₀² / 2g

          y = 3 2 / (2 9.8)

           y = 0.459 m

this is the distance the cantes block travels to stop

  b) the time of the entire journey is

               y = v₀ t - ½ a t²

the point where the body recesses is y = 0

            0 = (vo - ½ a t) t

whose solutions are

           t = 0

           0 = vo - ½ a t

           t = 2vo / a

           t = 2 3 / 0.459

           t = 13 s

Answer:

[tex]\theta=\frac{\pi}{4}+2\frac{rad}{s}t[/tex]

Explanation:

To find the expression in terms of time t you take into account the following equation for the angular distance traveled by an object with angular acceleration w and initial angular position θo:

[tex]\theta=\theta_o+\omega t+\frac{1}{2}\alpha t^2[/tex]   ( 1 )

α is the angular acceleration, but in this case you have a circular motion with constant angular speed, then α = 0 rad/s^2. θo is the initial angular position, the information of the question establishes that Enrique is at 3-o'clock. This position can be taken, in radian, as π/4 (for 12-o'clock = 0 rads).

The angular speed is:

[tex]\omega=2\frac{rad}{min}[/tex]

You replace the values of θo, α and w in the equation ( 1 ):

[tex]\theta=\frac{\pi}{4}+2\frac{rad}{s}t[/tex]

Furthermore, the arc length is:

[tex]s=r\theta=(40ft)[\frac{\pi}{4}+2\frac{rad}{s}t][/tex]

Answer:

wrong

Explanation:

it depends your perspective on it

Answer:

Amplitude and Frequency

Explanation:

Analog signals are composed of continuous waves that can have any values for frequency and amplitude. These waves are smooth and curved.

Radio transmissions are a combination of two kinds of waves: audio frequency waves that represent the sounds being transmitted and radio frequency waves that "carry" the audio information. All waves have a wavelength, an amplitude and a frequency as shown in the figure. These properties of the wave allow it to be modified to carry sound information.

The two most common types of modulation used in radio are amplitude modulation (AM) and frequency modulation (FM). Frequency modulation minimizes noise and provides greater fidelity than amplitude modulation, which is the older method of broadcasting . Both AM and FM are analog transmission systems, that is, they process sounds into continuously varying patterns of electrical signals which resemble sound waves.

Answer:

Explanation:

a )

While breaking initial velocity u = 62.5 mph

= 62.5 x 1760 x 3 / (60 x 60 )  ft /s

= 91.66 ft / s

distance trvelled s = 150 ft

v² = u² - 2as

0 = 91.66²  - 2 a x 150

a = - 28 ft / s²

b ) While accelerating initial velocity u = 0

distance travelled s = .24 mi

time = 19.3 s

s = ut + 1/2 at²

s is distance travelled in time t with acceleration a ,

.24 = 0 + 1/2 a x 19.3²

a = .001288 mi/s²

= 2.06 m /s²

c )

If distance travelled s = .25 mi

final velocity v = ? a = .001288 mi / s²

v² = u² + 2as

= 0 + 2 x .001288 x .25

= .000644

v = .025 mi / s

= .0025 x 60 x 60 mi / h

= 91.35 mph .

d ) initial velocity u = 59 mph

= 86.53 ft / s

final velocity = 0

acceleration = - 28 ft /s²

v = u - at

0 = 86.53 - 28 t

t = 3 sec approx .

Answer:

There is less gravitational force in space.

Explanation:

Gravity doesn't exist as it does on Earth. Earth's gravity is as 6 times stronger as it is on the moon.