A jet plane flies at a velocity of 200 m/s, east in still air. a) If it flies into a 20 m/s wind heading west, what is its velocity relative to the ground? b) If it flies into a 20 m/s wind heading east, what is its velocity relative to the ground?

Explanation:

where is the option of the Question

Answer:

(d) R>1

Explanation:

Let the wave is passing from the medium [tex]M_1[/tex] to medium [tex]M_2[/tex] as shown in the figure.

Given that there is an increase in the speed in the medium [tex]M_2[/tex] , this is only due to the fact that medium

As when light passes from denser to rare medium, it moves away from the normal as shown in the figure.

So, the angle made by light rays with the normal in the rare medium, angle of refraction [tex]r[/tex], is more than the angle made by light rays with the normal in the denser medium, angle of incident [tex]i[/tex].

Hence, r>i

[tex]\Rightarrow \frac r i >1[/tex]

[tex]\Rightarrow R >1[/tex]  [as r/i = R]

Hence, option (d) is correct.

Answer:

static stretching

Explanation:

hope this helped ^^

Answer:

1080 meters is the answer

Answer:

Elastic Collision

Inelastic Collision

The total kinetic energy is conserved. The total kinetic energy of the bodies at the beginning and the end of the collision is different.

Momentum does not change. Momentum changes.

No conversion of energy takes place. Kinetic energy is changed into other energy such as sound or heat energy.

Highly unlikely in the real world as there is almost always a change in energy. This is the normal form of collision in the real world.

An example of this can be swinging balls or a spacecraft flying near a planet but not getting affected by its gravity in the end.

Answer:

Please find the answer in the explanation.

Explanation:

The variable/s you can manipulate in the simulation to make all the items get the same proximate values for their acceleration will be the variable final velocity. Since all of them have zero initial velocity, the acceleration will tend to zero if they have a constant velocity.

If the final velocity is also zero or approximately equal to zero, that means the velocity is constant. And whenever there is constant velocity, the acceleration will be equal to zero.

Also, if the final velocity of all the parameters are very closed, they will surely have approximately same acceleration.

The variable which can be manipulated in the simulation will be the final

velocity.

The table shows all of them having the same initial velocity which is zero,

then the final velocity will have to be varied in order to get the same

proximate values for their acceleration.

Acceleration is the rate of change of velocity with time and when the velocity

is constant or equal to zero, the acceleration will be equal to zero.If the final

velocity of all the parameters are very close in value , then they will have

proximate values for acceleration.

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Answer:

260 km/h

Explanation:

Motion is said to be relative when the motion observed by the observer depends on the location (frame) of the observer.

When two objects are moving in opposite directions, the relative motion is obtained by subtraction.

Hence  the plane is moving at (285 - 25) km/h giving 260 km/h

Answer:

Please find attached, the required force diagram of the 23 kg box of eel tails being pulled with a rope horizontally across the bumpy floor

Explanation:

The steps required to draw a force diagram includes

1) The object on which the applied forces act is identified

2) The forces acting on the object are identified by the condition or state of the object, which may be stationary or in motion

3) Specify the object on the diagram using a spot

4) Each of the forces acting on the object (the spot) are added, in vector format, showing both the magnitude and the direction of the forces

The forces acting on the box are;

a) The weight of the box, [tex]F_w[/tex], acting vertically downwards, with a magnitude given as follows;

[tex]F_w[/tex] = Mass of box × Acceleration due to gravity = 23 × 9.81 = 225.63 N

b) The force of friction, [tex]F_f[/tex], acting in the opposite direction of motion of the box, with a magnitude given as follows;

[tex]F_f[/tex] = Weight of the box × Coefficient of friction

[tex]F_f[/tex] = 225.63 N × [tex]\mu _x[/tex]

c) The force pulling the box, [tex]F_p[/tex], = The mass of the block × The acceleration of the block

The direction of the pulling force = The forward direction of motion of the box.

Answer: ARE YOU DOING PRIMAVERA?!? PLEASE I KNOW YOU ARE I CANT DO PHYSICS-

Explanation:

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The pigeon final position displacement vector represented as , [tex]-2.9i-4.8j[/tex]

Given that Pigeon walks 4.0 m West then  2.5 m North then  1.1 m east and then 7.3 m south.

A diagram is attached below which describe the above situation.

In attached diagram, Distance DO represent the displacement.

From Diagram, it is observed that final position D of Pigeon is 4.8 m away from x axis and 2.9 m away from y axis.

Thus, Displacement vector represented as  , [tex]-2.9i-4.8j[/tex]

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Answer:

The mass of the ice produced is approximately 0.00212 kg

Explanation:

The given parameters are;

The temperature at which the air changed from water to ice = 0°C

The internal energy change of the water as it froze = 0.7 kJ

The specific latent heat of fusion of water = 330 kJ/kg

Given that the change in internal energy causes the water to change state, from the principle of energy conservation, we have;

The latent heat of fusion = The change in internal energy of the water as it froze

∴ The latent heat of fusion [tex]\Delta H^{\circ}_{fus}[/tex]  = 0.70 kJ

The formula for the latent heat of fusion, [tex]\Delta H^{\circ}_{fus}[/tex] = Mass × The specific latent heat of fusion, [tex]L^{\circ}_f[/tex]

Therefore, for the water, we have;

0.7 kJ = m × 330 kJ/kg

m = 0.7 kJ/(330 kJ/kg) ≈ 0.00212 kg

The mass, m, of the ice produced ≈ 0.00212 kg.

Answer:

D-A radiator emitting warm air and drawing in cool air

Explanation:

Answer:

Explanation:

The question is not complete, here is the complete question, also see attached the image.

"A bicycle gear wheel is a disc with 50 ‘teeth’ equally spaced around its edge, as shown. The gear  wheel is rotated 10 times each second. A springy strip of metal is vibrated by the rotating ‘teeth’.  The metal strip produces a sound of frequency that is equal to the frequency of vibration of the  strip. The speed of sound in air is 330ms–1.  What is the wavelength of the emitted sound?"

given data

number of teeth= 50        

we are told that the gear is rotated 10 times in 1 sec,  

hence the frequency of the rotation past the strip is

=50*10  

=500Hz    

speed of sound= 330m/s

we know that

  [tex]v_w = f \Lambda[/tex]-----------1

where Vw is the speed of sound,

f is its frequency, and

λ is its wavelength.

λ=Vw/f

λ=330/500

λ=0.66m

Answer:

Search it

Explanation:

its on it

Answer:

Explanation:

19116 being the distance from the centre of the earth to the point you want to check in metres. So after all that you get G = 1.0888m/second squared. Hope that helps you/ you should be able to pop in any height you want.

plz mark as brainliest

Answer:

70km/h

Explanation:

speed  = distance /time

            = 35/0.5

           =70km/h

Answer:

Newtons third law of motion

Explanation:

For each action, there is an equal and opposite reaction.

Answer: Option B.

Strong nuclear force Gravity.

Explanation:

Nuclear force is the strongest force while Gravity is the weakest force. Strong nuclear force is the strongest force because it's act and hold atoms of matter together. It also binds neutrons and protons together to form atomic nuclei and it's has strength of 1.

Gravity is considered the weak force out of the four fundamental forces because it has a very small strength of 10^40 than electromagnetic force.

Answer:

Unit

Explanation:

The reference standard used for the measurement of physical quantity is called the unit of that quantity.

Most units follow an agreed system of expressing quantities across all instances of such quantity.

Answer:

See the answers below

Explanation:

In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

[tex]W=m*g[/tex]

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

Mercury

[tex]w_{mercury} = 15*3.8\\w_{mercury}= 57 [N]\\[/tex]

Venus

[tex]w_{venus}=15*8.8\\w_{venus}= 132 [N][/tex]

Moon

[tex]w_{moon}=15*1.6\\w_{moon}=24[N][/tex]

Mars

[tex]w_{mars}=15*3.7\\w_{mars}=55.5 [N][/tex]

Jupiter

[tex]w_{jupiter}=15*23.1\\w_{jupiter}= 346.5[N][/tex]

Saturn

[tex]w_{saturn}=15*9\\w_{saturn}=135[N][/tex]

Uranus

[tex]w_{uranus}=15*8.7\\w_{uranus}=130.5[N][/tex]

Neptune

[tex]w_{neptune}=15*11\\w_{neptune}=165[N][/tex]

Pluto

[tex]w_{pluto}=15*0.6\\w_{pluto}=9[N][/tex]

Answer:

Explanation:

For vertical displacement of food-supply

if time taken to reach the ground be t

235 = 1/2 g t²  , initial velocity downwards is zero.

t = 6.92 s

Horizontal displacement of food during this period

= 6.92 x 69.4 m

= 480.25 m .

b )

time required to cover horizontal distance of 425 m

= 425 / 69.4 = 6.124 s  

This time period will be the time of vertical fall of 235 m . Let initial vertical velocity required be u

h = ut + 1/2 gt²

235 = u x 6.124 + .5 x 9.8 x 6.124²

235 = u x 6.124 + 183.76

u = 8.36 m /s

c )

v = u + gt

= 8.36 + 9.8 x 6.124

= 68.37 m /s

This will be vertical component of velocity .

horizontal velocity = 69.4 m /s

resultant velocity = √ ( 68.37² + 69.4²)

= √(4674.45 +4816.36)

= 97.42 m /s

Answer:

33 Newton upwards to get a net force of zero.

Answer:

The answer is 33 newtons with a net force of 0

Explanation:

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{110000}{45000} = \frac{110}{45} = \frac{22}{9} \\ = 2.4444444...[/tex]

We have the final answer as

Hope this helps you

Answer:

1. The elephant has more kinetic energy at this speed and mass. It has 4,500 J more KE.

2. The elephant would have to go at a speed of 2.5 m/s to reach the same KE as the cheetah.

Explanation:

You would use the formula KE=1/2mv^2.

This formula would be filled in and completed twice, once for the elephant and once for the cheetah.

Cheetah:

KE = 1/2 (40) (25) ^2

KE = 12,500 J

Elephant:

KE = 1/2 (4,000) (2) ^2

KE = 8,000 J

This shows that the cheetah has more KE.

Then you would subtract the elephants amount of J from the cheetahs to find the difference.

Difference = 12,500 J - 8,000 J

Difference = 4,500 J

I hoped this helped with the first part :)

For the second part:

To find the speed the elephant would have to run you would fill in and complete the equation once more with different distance results.

KE = 1/2 (4,000) (2.5) ^2

KE= 12,500 J

(1) The kinetic energy of the cheetah is 12,500 J while kinetic energy of the elephant is 8,000 J

(2) The speed that the animal with lowest kinetic energy need to match up with the animal with highest kinetic energy is 2.5 m/s.

(3)    At the highest point, the kinetic energy of the ball is zero while the potential energy will be maximum.

       At the lowest point, the kinetic energy of the ball will be maximum while potential energy will be zero.

The kinetic of object, is the energy possessed by the object due to its motion.

The kinetic energy of the cheetah is calculated as;

K.E = ¹/₂mv²

K.E = ¹/₂  x 40 x 25²

K.E = 12,500 J

The  kinetic energy of the elephant is calculated as;

K.E = ¹/₂  x 4000 x 2²

K.E = 8,000 J

(2) The speed of the animal with less kinetic energy to match up with the animal with higher kinetic energy;

12,500 = ¹/₂  x 4000 x v²

25,000 = 4000v²

[tex]v^2 = \frac{25,000}{4000} \\\\v^2 = 6.25\\\\v= \sqrt{6.25} \\\\v = 2.5 \ m/s[/tex]

(3) In a simple pendulum motion, point A (initial position) is the lowest point while point B (final position) is the highest point in the motion path.

At the highest point, the velocity of the ball is zero and the ball will have zero kinetic energy while the potential energy which increases with height will be maximum.

At the lowest point, the velocity of the ball will be maximum and the ball will have maximum kinetic energy while potential energy will be zero since the height is zero.

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Answer:

sound waves need to travel through a medium such as solids,liquids and gases. hoped this helped  

Explanation:

sound waves

Explanation:

To determine your total daily calorie needs, multiply your BMR by the appropriate activity factor, as follows: If you are sedentary (little or no exercise) : Calorie-Calculation = BMR x 1.2. If you are lightly active (light exercise/sports 1-3 days/week) : Calorie-Calculation = BMR x 1.375.

HAPPY TO HELP

Energy is measured in form of calories.

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

To determine your total daily calorie needs, multiply your BMR by the appropriate activity factor, as follows:

If you are sedentary (little or no exercise) :

Calorie-Calculation = BMR x 1.2.

If you are lightly active (light exercise/sports 1-3 days/week) :

Calorie-Calculation = BMR x 1.375

Energy is measured in form of calories.

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Answer:

The maximum height of Phran stone is four time that of Phred stone

Explanation:

From the question we are told that

   The initial velocity of Phred stone is  u

    The initial velocity of  Phran stone is  2u

Generally from kinematic equations

       [tex]v^2 = u^2 + 2(-g)h[/tex]

Here the negative sign shows that the direction of the stone is against gravity

At the maximum height v which is the final velocity of the stone is zero  

So

      [tex]0 = u^2 - 2gh[/tex]

So for Phred stone the height attained is  

=>   [tex]h_1 = \frac{u^2}{2g}[/tex]

For  Phran stone the height attained is  

=>   [tex]h_2 = \frac{(2u)^2}{2g}[/tex]

=>    [tex]h_2 = \frac{4u^2}{2g}[/tex]

=>    [tex]h_2 = 4 h_1[/tex]

Hence the maximum height of Phran stone is four time that of Phred stone