Answer:
function
Step-by-step explanation:
A function is a rule that pairs each element in one set with exactly one element from a second set.
A function is a rule that pairs each element in one set with exactly one element from a second set.
What is Function?A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.
Function is a relation.
Let a set A = {1, 2, 3, ........} and set B = {1, 4, 9, .....}
Let f(x) = x² be the function.
f(1) = 1 , so 1 is mapped to 1
f(2) = 4, so 2 is mapped to 4.
...............
It goes on like this.
No element would map to more than one element.
1 will only map to 1, not to 4, 9, .......
Similarly, 2 will map to 4 only, not any other element.
But more than one element in set A can be mapped to same element in set B.
Suppose A = {......, -2, -1, 0, 1, 2, .......} and B = {1, 4, 9, .....}
We have f(1) = f(-1) = 1
Also, f(2) = f(-2) = 4
But this is a function.
Hence the rule is that pairs each element in one set with exactly one element from a second set.
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pt 3 7/7 lasttt one helpppp
Answer:
2n+2
Step-by-step explanation:
-n + (-3) +3n + 5 -3
(-3+5) =2
-n +2+n+3n
3n-n = 2n
2n+2
HELP MEEEEE
(The problem is in the picture)
Answer:
Hey there!
We don't have enough information. 7(n+5) can be written as either the 7 times the sum of n+5, or 7 multiplied by n+5.
Let me know if this helps :)
Using this figure, A' is the ____ of A
Image
Step-by-step explanation:
It's actually called Translation but image is the same thing as translation
solve:
[tex]\underset{x\rightarrow~3}{\lim}~\dfrac{2x^2-18}{x^2-3x}[/tex]
Hello, please consider the following.
[tex]\displaystyle \lim_{x\rightarrow3}~\dfrac{2x^2-18}{x^2-3x} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x^2-3^2)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x-3)(x+3)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x+3)}{x} \\ \\ \\=\dfrac{2(3+3)}{3}\\ \\ \\=\dfrac{2*3*2}{3} =\Large \boxed{\sf \bf \ 4 \ }[/tex]
Thank you
[tex]\\ \tt\longmapsto {\displaystyle{\lim_{x\to 3}}}\dfrac{2x^2-18}{x^2-3x}[/tex]
[tex]\\ \tt\longmapsto {\displaystyle{\lim_{x\to 3}}}\dfrac{2(x^2-9)}{x^2-3x}[/tex]
[tex]\\ \tt\longmapsto {\displaystyle{\lim_{x\to 3}}}\dfrac{2(x^2-3^2)}{x^2-3x}[/tex]
(a+b)(a-b)=a^2-b^2[tex]\\ \tt\longmapsto {\displaystyle{\lim_{x\to 3}}}\dfrac{2(x+3)\cancel{(x-3)}}{x\cancel{(x-3)}}[/tex]
[tex]\\ \tt\longmapsto {\displaystyle{\lim_{x\to 3}}}\dfrac{2x+6}{x}[/tex]
[tex]\\ \tt\longmapsto \dfrac{2(3)+6}{3}[/tex]
[tex]\\ \tt\longmapsto \dfrac{6+6}{3}[/tex]
[tex]\\ \tt\longmapsto \dfrac{12}{3}=4[/tex]
The sum of two numbers is 167. The second number is 29 less than three times the first number. Fine the numbers. The two required numbers are:
Answer:
49 and 118
Step-by-step explanation:
Let the two numbers be x and y
x+y = 167
y = 3x-29
Substitute into the first equation
x+ 3x-29 = 167
Combine like terms
4x - 29 = 167
add 29 to each side
4x = 167+29
4x = 196
Divide by 4
4x/4 = 196/4
x = 49
x+y = 167
49+y = 167
y = 167-49
y =118
Answer:
[tex]\Huge \boxed{\mathrm{49 \ and \ 118}}[/tex]
Step-by-step explanation:
Let the first number be [tex]x[/tex]
Let the second number be [tex]y[/tex]
[tex]x+y=167[/tex]
[tex]y=3x-29[/tex]
Applying substitution method.
[tex]x+3x-29=167[/tex]
Combining like terms.
[tex]4x-29=167[/tex]
Adding 29 to both sides.
[tex]4x=196[/tex]
Dividing both sides by 4.
[tex]x=49[/tex]
Substituting x = 49 for the second equation.
[tex]y=3(49)-29[/tex]
Multiplying the numbers.
[tex]y=147-29[/tex]
Subtracting.
[tex]y=118[/tex]
The two required numbers are 49 and 118.
(04.07A)
Two quantities are related, as shown in the table below:
x y
2 3
4 4
6 5
8 6
Which equation best represents the relationship?
Answer:
The equation that best represents the relationship is [tex]y=\frac{1}{2}x+2[/tex].
Step-by-step explanation:
We are given the following table representing the two quantities below;
x y
2 3
4 4
6 5
8 6
Firstly, we will find the two-point slope here, that is;
Consider two points; ([tex]x_1,y_1[/tex]) = (2, 3) and ([tex]x_2,y_2[/tex]) = (4,4)
Now, the formula for finding slope is;
Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{4-3}{4-2}[/tex] = [tex]\frac{1}{2}[/tex]
Similarly, finding the slope for the points (6,5) and (8,6);
Slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{6-5}{8-6}[/tex] = [tex]\frac{1}{2}[/tex]
Now, the linear equation of the line having slope is given by;
[tex]y-y_1=m\times (x-x_1)[/tex] ; where m = slope and consider ([tex]x_1,y_1[/tex]) = (2, 3)
So, the equation of the line is;
[tex]y-3=\frac{1}{2} \times (x-2)[/tex]
[tex]y-3=\frac{1}{2}x-1[/tex]
[tex]y=\frac{1}{2}x+2[/tex]
Hence, the equation that best represents the relationship is [tex]y=\frac{1}{2}x+2[/tex].
Answer:
y = -1/2x + 11
Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2y3zi + sin(xyz)j + xyzk, S is the part of the cone y2 = x2 + z2 that lies between the planes y = 0 and y = 3, oriented in the direction of the positive y-axis.
Answer:
[tex]$ \frac{2187 \pi}{4}$[/tex]
Step-by-step explanation:
Using Stoke's theorem, we get
[tex]$ \int \int_S curl F.dS = \int_C F.dr$[/tex]
Now parametrize C
r(t) = ( 3 cos t, 3 - 3 sin t ) where, t in [0 2π]
[tex]$ \int_C F. dr= \int_0 ^{2 \pi}F ( 3 \cos t, 3 - 3 \sin t). r'(t)dt$[/tex]
[tex]$= \int_0^{2 \pi}(( 9 \cos^2 t)(27)(-3\sin t), \sin t \times (-27 \cos t \sin t)) . (-3 \sin t, 0 - 3 \cos t) dt $[/tex]
[tex]$ = 27 \int_0^{2 \pi} 81 \cos ^2 t \sin ^2 t + 3 \cos ^2 t \sin tdt $[/tex]
[tex]$ = 27 \int_0^{2 \pi} \frac{81}{4} \sin ^2 2t+27 [ - \cos^3 t]_0^{2 \pi}$[/tex]
[tex]$ = 27 \times \frac{81}{4} \int_0^{2 \pi} \frac{(1- \cos 4t)}{2} $[/tex]
[tex]$= \frac{2187}{8}[t-\frac{1}{4} \sin 4t]_0^{2 \pi} $[/tex]
[tex]$= \frac{2187 \pi}{4}$[/tex]
By using Stokes Theorem the required S curl F.ds is [tex]\dfrac{2187\pi }{4}[/tex].
Given that,
Function F(x, y, z) = (x^2y^3z)i + sin(xyz)j + xyzk,
S is the part of the cone y^2 = x^2 + z^2 that lies between the planes y = 0 and y =3, oriented in the direction of the positive y-axis.
We have to determine,
Use Stokes' Theorem to evaluate S curl F·dS.
According to the question,
By using Stokes Theorem to evaluate S curl F .dS.
[tex]\int\ \int _s curlF.ds = \int _c F.dr\\\\[/tex]
Now parametrize C
r(t) = ( 3 cos t, 3 - 3 sin t ) ,
Where, t in [0 2π]
Then,
[tex]\int_c F.dr = \int^{2\pi }_0 F(3cost, 3-3sint).r'(t)dt\\\\[/tex]
[tex]= \int^{2\pi }_0 ((9cos^2t)(27)(-3sint),(sint) \times (-27cost.sint). (-3sint,0-3cost)dt\\\\= 27 \int^{2\pi }_0 81cos^2t .\ tsin^2t + 3 cos^2t. t sintdt\\\\= 27 \int^{2\pi }_0 \dfrac{81}{4}sin^22t+ 27[-cos^3t]^{2\pi }_0\\\\= 27 \times \dfrac{81}{4} \int^{2\pi }_{0} (\dfrac{1-cos4t}{2})\\\\= \dfrac{2187}{8}[t-\dfrac{1}{4}sin4t]^{2\pi }_0\\\\= \dfrac{2187}{8}[2\pi -\dfrac{1}{4}sin4(2\pi )- 0-\dfrac{1}{4}sin4(0 )]\\\\= \dfrac{2187\pi }{4}[/tex]
Hence, By using Stokes Theorem the required S curl F.ds is [tex]\dfrac{2187\pi }{4}[/tex].
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1.
Harriet has deposited $693 in a savings account that earns interest at a rate of 4.6% compounded monthly. What will the account balance be in thirteen years? (2 points)
$1,258.77
$1,243.50
$724.88
$3,187.80
Answer:
Future amount (A) = $1,258.77 (Approx)
Step-by-step explanation:
Given:
Amount deposit (p) = $693
Rate of interest monthly (r) = 4.9% / 12 = 0.003833
Number of month (n) = 13 × 12 = 156
Find:
Future amount (A)
Computation:
[tex]A = p [1+r]^n \\\\ A = 693 [1+0.003833]^{156}\\\\ A= 693[1.8163]\\\\ A = 1258.77[/tex]
Future amount (A) = $1,258.77 (Approx)
how do you Evaluate. 58−(14)2= ________
Answer:
58-(14)2
58-28
30
Step-by-step explanation:
c) Chairs are placed in equal rows and column of a squared room. If there are 144 chairs in the room, how many chairs are there in the first row?
Answer:
12
Step-by-step explanation:
144 chairs in total.
the room is square, this means that the number must be multiplied by the same number
12x12= 144
there are 12 chairs on the first row.
1) write the equation of the
line in slope intercept form
that passes through (0,-2)
and (2,1).
Answer:
y=3/2x-2
Step-by-step explanation:
Find the slope first:
[tex]m=\frac{y_{2-y_{1} } }{x_{2}-x_{1} } =\frac{1-(-2)}{2-0}=\frac{3}{2}[/tex]
Then solve for y-intercept:
[tex]y=\frac{3}{2}x+b\\-2=\frac{3}{2}(0)+b\\-2=b[/tex]
Now, write out your complete equation:
y=3/2x-2
Which of the following presents can also be expressed as a mixed number 310% or 49% or 7.4% or 0.001%
Answer:
310%
Step-by-step explanation:
310% can be expressed as a mixed number because 150% would be 1 1/2.
310% would be 3 1/10.
Find the greatest number of 5 digits which
when divided by 25, 30 and 40 leaves a
remainder 20,25, and 35 respectively.
Answer:
99,595
Step-by-step explanation:
We are looking at division and remainders. What do you do when a remainder is present? You usually add it when multiplying to get the final number, but since we are doing this backwards, we have to subtract the numbers divided by the remainder.
25 - 20 = 5
30 - 25 = 5
40 - 35 = 5
Look for the LCM (Least Common Multiple) for 20, 30, and 40 :
600
Now for the equation :
n + 5 = Multiple of all numbers and LCM =
n + 5 = 166 * 600 = 99,600
n = 99,600 - 5 = 99,595
The greatest 5 digit number which when divided by 25, 30 and 40 has a remainder of 20, 25, and 35 is 99,595
The reason why the above value arrived at is correct is as follows:
The required parameter;
To find a 5 digit number that with remainder of 20, remainder of 25 and a remainder of 35, when divided by 25, 30, and 40 respectively
Strategy;
Find the LCM of the divisor, then find the highest common multiple of the
LCM that is a 5 digit number, equate the expression for the required 5 digit
number to the highest common multiple of LCM of the divisors by adding
a value that will give a factor of the divisor as follows;
Let x represent the 5 digit number, from the question, we get;
x = 25·a + 20
x = 30·b + 25
x = 40·c + 35
x < 99,999
The 5 digit number is not a multiple of 25, 30, and 40, therefore, the number is not a multiple of the LCM of 25, 30, and 40 which is 600
The highest multiple of 600 which is a 5 digit number = 99,600
Therefore, we can write;
25·a + 20 + 5 = 30·b + 25 + 5 = 40·c + 35 + 5 = 99,600
However;
25·a + 20 + 5 = x + 5
By transitive property, we get
x + 5 = 99,600
∴ x = 99,600 - 5 = 99,595
The 5 digit number, x = 99,595
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Which numbers in set ={,,,,,,,,,}eh equals left brace 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 right brace are elements in both the subset of odd numbers and the subset of multiples of 3?
Enter your answer.
Answer:
D={3,9}
The numbers are 3 and 9
Step-by-step explanation:
The set A
={,,,,,,,,,}
Let B be the sub set of A containing odd numbers
B={1,3,5,7,9}
Let C be the sub set of A containing multiply of 3
C= {3,6,9}
Now let D be the be the sub set of A containing both odd numbers and multiples of 3
D={3,9}
Given paralleogram ACDB-parallelogram FGHE, what
is the value of x?
O x= 40°
O x= 50°
O x= 65°
O x = 130°
The value of x will be 50 degrees. The correct option is B.
What is a parallelogram?A parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure
The opposite angles of the parallelogram are equal and the sum of the adjacent angles of the parallelogram is 180 degrees.
Angle A is 130 degrees then angle F will also be 130 degrees. The angle E will be calculated as below:-
∠F + ∠ E = 180
130 + ∠E = 180
∠E = 180 - 130
∠E = 50
Therefore, the value of x will be 50 degrees. The correct option is B.
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Help me please thank you
Answer:
135°
Step-by-step explanation:
Because the lines are parallel, <1 and <3 are the same.
if there are two numbers on one side, do i have to add them together?
Answer:
YES
Step-by-step explanation:
For example, in the figure displayed in the attachment, the length of [tex] YM = MS + SY [/tex]
[tex] MS = 3 [/tex]
[tex] SY = 10 [/tex]
Therefore, [tex] YM = 3 + 10 = 13 [/tex].
The lengths of segments MS and SY sums up to give you the length of YM.
Find the standard form (ax + by + c = 0) of the line using the following information. Please show your work! Point: (6, -1) Slope: m is undefined I'll give brainliest!!!
Answer:
x - 6 = 0
Step-by-step explanation:
The only lines that have undefined slopes are vertical lines. Vertical lines are found in the form x = c where c is a constant. With vertical lines, it doesn't matter what the y value is because x will always be c. In this case, c = 6 because the x-coordinate of (6, -1) is 6. Therefore, our equation is x = 6. In standard form, that would be x - 6 = 0.
Answer:
[tex]\huge \boxed{x-6=0}[/tex]
Step-by-step explanation:
Vertical lines have undefined slopes.
The line crosses (6, -1), x = 6.
The equation of the vertical line is x = 6.
The equation of the line in standard form would be x - 6 = 0.
Use inductive reasoning to determine the next term in the sequence -2, 5, -4, 3, -6, ... *
Answer:1,-8
Step-by-step explanation: -2,5( add 7) 5,-4(sub 9),-4,3(add 7), 3,-6(sub 9)
Pattern of +7,-9,+7,-9
-6+7=1 and 1-9=-8
Solve 3x-2=1/2 - x/3
I need help on this question, please stop by.
Answer:
last option from the left
Step-by-step explanation:
To find the price of one water bottle, we can calculate 6 / 24 because 24 bottles cost $6. Now, to find the price of 10 bottles, we can multiply the price of 1 bottle by 10 so the answer is 6 / 24 * 10.
hypothesis that there is a relationship between parents’ and children’s party identification. Would we be correct in inferring that such a relationship also exists in the population? Explain your answer. What is the probability that any relationship we found is due to pure chance?
Answer:
No
It could be purely due to chance.
Step-by-step explanation:
A population is defined as the whole group which has the same characteristics. For example a population of the college belongs to the same college . But a sample may be an element of a population.
So it is not necessary for a population to have the same characteristics as the sample.
But it is essential for the sample to have at least one same characteristics as the population.
So we would not be correct in inferring that such a relationship also exists in the population.
It is a hypothesis which can be true or false due to certain conditions or limitations as the case maybe.
For example in a population of smokers some may be in the habit of taking cocaine. But a sample of cocaine users does not mean the whole population uses it.
It could be purely due to chance if we find out that there is a relationship between parents’ and children’s party identification in the population.
Define the following sequence recursively: 4, 4/3, 4/9, ....
Answer:
Step-by-step explanation:
[tex]a_n=\frac{1}{3} a_{n-1}[/tex]
At the end of the day of teaching the skill of cutting and sewing to make capes, Ms. Ironperson and Mr. Thoro decided to go to the Shawarma Mediterranean Grill. Ms. Ironperson ordered 3 chicken shawarma wraps and 2 orders of spiced potatoes for a total bill of $42.95. Mr. Thoro ordered 5 chicken shawarma wraps and 4 orders of spiced potatoes for a total bill of $74.91. What is the cost of a chicken shawarma wrap? What is the cost of one order of spiced potatoes? If x denotes the cost of a chicken shawarma wrap and y denotes the cost of an order of spiced potatoes, what are the equations needed to solve this problem?
Answer:
The cost of a chicken shawarma wrap = $10.99
The cost of an order of spiced potatoes=$4.99
Equations needed
3x+2y =42.95
5x + 4y=74.91
Step-by-step explanation:
x = the cost of a chicken shawarma wrap
y = the cost of an order of spiced potatoes
Ms. Ironperson
3x+2y =42.95
Mr. Thoro
5x + 4y=74.91
3x+2y =42.95 (1)
5x + 4y=74.91 (2)
Multiply (1) by 2
6x + 4y=85.9 (3)
5x + 4y=74.91. (2)
Subtract (2) from (3)
6x - 5x= 85.9 - 74.91
x=$10.99
Substitute the value of x into (1)
3x+2y =42.95 (1)
3(10.99) + 2y =42.95
32.97 + 2y = 42.95
2y = 42.95 - 32.97
2y=9.98
Divide both sides by 2
y=9.98/2
=4.99
y=$4.99
Therefore,
The cost of a chicken shawarma wrap = $10.99
The cost of an order of spiced potatoes=$4.99
A brick layer can lay 320 bricks per day. Let y represent the total number of bricks he can lay in x days
Determine whether a graph created with each calculator display window defined in the table will show all points representing the total number of bricks that the brick layer can lay in 0 to 10 days
Select Yes or No for each display window.
The calculator display window shows:
Yes
No
O
о
400 < x < 3,400 and -1 < y < 11
-1
о
o
o
O
-1
-400 < x < 3,400 and - 400 < y < 321
о
O
Answer:
I may be incorrect but these are my answers
A) −400≤x≤3,400 and −1≤y≤11 NO
B) −1≤x≤11 and −400≤y≤3,400 YES
C) −1≤x≤11 and −1≤y≤321 YES
D) −400≤x≤3,400 and −400≤y≤321 YES
Step-by-step explanation:
The last three equations, B, C ,D all include the points needed to graph the total number of bricks he can lay in 0 to 10 days.
Answer:
Don't delete my answers!
No
Yes
Yes
Yes
I was doing the QUIZ!
Step-by-step explanation:
a companys product development division has 60 employees. Of these, 1/3 are engineers. If 40% of engineers are moved to another division. How many engineers will remain in the product development department?
Answer: There will be 12 engineers remaining in the product development department.
Step-by-step explanation:
So the givens are:
60 employees and 1/3 are engineers and if 40% of engineers are moved to another division and how many engineers will remain in the product development department?
So what we need to do:
60 * 1/3 = 60 / 3 = 20
There are 20 engineers.
20 * 40% = 8
There are 8 engineers that are going to be moved to another division.
20 - 8 = 12
12 engineers will remain in the development department.
Hence, your answer.
By calculations, 12 engineers will remain in the development department.
A companys product development division has 60 employees. Of these, [tex]\frac{1}{3}[/tex] are engineers.
The third part of a number is obtained by dividing a number by three, or what is the same, multiplying by a third ([tex]\frac{1}{3}[/tex]), thus dividing the number into a total of three equal parts.
In this case:
[tex]\frac{1}{3}[/tex]×60= 20
So, a companys product development division has 20 engineers.
40% of engineers are moved to another division.
The percentage is a way of referring to a proportion taking the number 100 as a reference. To calculate the percentage of a quantity, the quantity is multiplied by the percentage and divided by 100.
In this case:
40% of engineers= 40%×20=[tex]\frac{40x20}{100}[/tex]= 8
8 engineers are moved to another division.
The number of engineers who remain in the department is calculated by subtracting the total number of engineers in the department and the number of engineers who move to another division:
20 - 8= 12
12 engineers will remain in the development department.
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Zev read 15% of his 56-page book. Kelly read 12% of her 64-page book. Marneisha read 14% of his 68-page book Aleisha read 10% of her 72-page book.
Answer:
zev=15/100*56=9.6 pages
Find the following quotient and express the answer in standard form of a complex number.
Hello, please consider the following.
When you have a complex number in the denominator you need to multiply by its conjugate to eliminate the imaginary component.
The conjugate of 4 - 3i is 4 + 3i, right?
So, let's do it!
[tex]\dfrac{5-7i}{4-3i}=\dfrac{(5-7i)(4+3i)}{(4-3i)(4+3i)}\\\\=\dfrac{5(4+3i)-7i(4+3i)}{4^2-(3i)^2}\\\\=\dfrac{20+15i-28i-21i^2}{16+9}\\\\=\dfrac{20+21-13i}{25}\\\\\large \boxed{=\dfrac{41}{25}-\dfrac{13}{25}i\\}[/tex]
Thank you.
Complex numbers are numbers with real and imaginary parts.
The expression in standard form of a complex number is: [tex]\mathbf{\frac{41}{25}-\frac{13}{25}i}[/tex]
The expression is given as:
[tex]\mathbf{\frac{5 - 7i}{4 - 3i}}[/tex]
Rationalize
[tex]\mathbf{\frac{5 - 7i}{4 - 3i} = \frac{5 - 7i}{4 - 3i} \times \frac{4 + 3i}{4 + 3i}}[/tex]
[tex]\mathbf{\frac{5 - 7i}{4 - 3i} = \frac{20 +15i -28i - 21i.i}{(4)^2 - (3i)^2}}[/tex]
[tex]\mathbf{\frac{5 - 7i}{4 - 3i} = \frac{20 +15i -28i - 21(-1)}{16 - 9(-1)}}[/tex]
[tex]\mathbf{\frac{5 - 7i}{4 - 3i} = \frac{20 +15i -28i + 21}{16 + 9}}[/tex]
Collect like terms
[tex]\mathbf{\frac{5 - 7i}{4 - 3i} = \frac{20 + 21+15i -28i }{16 + 9}}[/tex]
[tex]\mathbf{\frac{5 - 7i}{4 - 3i} = \frac{41-13i }{25}}[/tex]
Split
[tex]\mathbf{\frac{5 - 7i}{4 - 3i} = \frac{41}{25}-\frac{13i }{25}}[/tex]
[tex]\mathbf{\frac{5 - 7i}{4 - 3i} = \frac{41}{25}-\frac{13}{25}i}[/tex]
Hence, the expression in standard form of a complex number is: [tex]\mathbf{\frac{41}{25}-\frac{13}{25}i}[/tex]
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I don’t understand this?
Answer:
11.5 cm²
Step-by-step explanation:
We know that the triangle has a base of 3 + 4 = 7 and a height of 3 + 2 = 5. Therefore, the area of the triangle is 7 * 5 / 2 = 17.5. The area of the 3 by 2 rectangle is 3 * 2 = 6 so the shaded area is 17.5 - 6 = 11.5 square cm.
Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147, and 190 ft?
Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.