The amount of heat required to raise the temperature of the system through 1°C is defined as the heat capacity of the system. The kilocalories of heat needed to heat the water from 62.0 °F to 105.0 °F is 40877.01.
What is specific heat capacity?The quantity of heat required to raise the temperature of one gram of the substance through 1°C is known as the specific heat capacity. It is usually denoted by c.
The equation connecting the specific heat capacity with the heat is given as:
q = mc (T₂ - T₁) = mc Δ T
1 gallons = 3.785 L
450 gallons = 450 × 3.785 = 1703.25 L
Density of water is 1 g/cm³
Then the mass of water is, m = Density × Volume
m = 1703.25 L × 1000 mL/ 1L × 1.0 g / 1mL × 1kg / 1000g
m = 1703 .25 kg
The temperature in °F can be converted into °C as:
T°C = T°F - 32 / 1.8
T₁ = 62 -32 / 1.8 = 17°C
T₂ = 105 - 32/ 1.8 = 41°C
Δ T = T₂ - T₁ = 41 - 17 = 24°C
q = 1703.25 kg × 4.184 kJ/kg K × 24°C
q = 171033.552 kJ
1 kilojoule = 0.239 kilocalorie
171033.552 kJ = 40877.01 kilocalorie
Thus the heat required in kilocalorie is 40877.01.
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Calculate the molarity of a solution prepared by diluting 60.02 mL of a 0.574 M potassium chloride solution to 150.00 mL.
The molarity of the solution prepared by diluting 60.02 mL of a 0.574 M potassium chloride solution to 150.00 mL is 0.229 M.
The initial molarity of the potassium chloride, M₁ = 0.574 M
The initial volume potassium chloride , V₁ = 60.02 mL
The final molarity potassium chloride, M₂ = ?
The final volume potassium chloride, V₂ = 150 mL
The expression is as follows :
M₁ V₁ = M₂ V₂
M₂ = M₁ V₁ / V₂
M₂ = ( 0.574 × 60.02 ) / 150
M₂ = 0.229 M
The molarity of the solution is 0.229 M with the volume of the 150 mL.
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using only your equation sheet, calculate the change in entropy of water when it freezes at its normal freezing point. use units of j/mol k.
When water freezes at its typical freezing point, its entropy changes to [tex]-22.08 J/mol K[/tex].
Entropy is a metric for how chaotic or unpredictable a system is. The quantity of energy in a thermodynamic system that is not usable for work is measured using this notion, which is utilised in thermodynamics and statistical mechanics. It is frequently referred to as the system's level of chaos or disorder.The change in entropy of water at its normal freezing point is given by the expression:
ΔS = -ΔH/T
Where ΔH is the enthalpy of fusion of water, which is 6.01 kJ/mol, and T is the freezing point of water, which is 273.15 K.
The change in entropy of water when it freezes at its normal freezing point is:
ΔS = [tex]\frac{-6.01 kJ/mol }{ 273.15 K}[/tex]
ΔS = [tex]-22.08 J/mol K[/tex]
Therefore, The change in entropy of water when it freezes at its normal freezing point is:-22.08J/molK
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Where do nitrogen in oxides of nitrogen come from
a sample of ground beef contains 18.9% protein and 21.4% fat both by mass. how many kilocalories are in 125g of the ground beef? assume all kilocalories come from, protein and fat, and that the sample contains only protein, fat, and water
A sample of ground beef contains 18.9% protein and 21.4% fat both by mass. Therefore, 147.5kilocalories are in 125g of the ground beef.
What is calories?The calorie is an energy unit derived from the now-defunct thermodynamic theory of heat. Two primary meanings of "calorie" are widely used for historical reasons.
Originally, a big calorie, meal calorie, dietary calorie, and kilo calorie was defined as the quantity of heat required to increase the temperature with one kilogram of water through one degrees Centigrade (or one kelvin). The amount of heat required to create the same rise in one gram of water was characterized as a tiny calorie or gram calorie.
Let the required calorie of ground beef be m .
protein in it = .18m
fat in it = .21m
1 gram of protein gives 4 cals .
1 gram of fat gives 9 cals .
4 x .18m + 9 x .21m = 350
m = 147.5kilocalories
Therefore, 147.5kilocalories are in 125g of the ground beef.
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what charge is expected for the following elements in ionic compounds--be, mg, ca, sr, ba, ra, zn, and cd?
Electron configurations written down. The energy level (the period) should come first when writing an electron configuration, followed by the subshell that needs to be filled and the superscript.
What do the letters 1s, 2s, and 3p mean?The energy levels of the electronic orbitals are 1s 2s 2p 3s 3p. Due to the fact that one atom can have numerous electronic orbitals, energy levels are classified as particular quantum numbers: 1s, 2s, 3s, 4s, 3d, 4p, 5s, 4d, 5p 7s 5f 6d 6p 4f 5d 6p. The orbital angular momentum quantum number, indicated by l, can be understood.
Let's list the elements that have changed. The following is anticipated
Every stable electron configuration element gains the maximum D- Te Te +2 2- Po Pot2 +2 se se Hele as well as all other elements. Be Be 12 нд Mg+2 2n+2
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ORGANIC CHEMISTRY
What would a chair conformation + a chair flip look like for the following molecules? :)
The chair conformation is obtained by a flip of the boat conformation.
What is the chair conformation ?In this conformation, the cyclohexane ring is bent into a chair-like shape, with alternating bonds in the ring adopting a "up" or "down" orientation.
The chair conformation is a very stable arrangement of bonds in cyclohexane, and it is the most common conformation observed in this type of molecule. The stability of the chair conformation is due to the fact that all of the bond angles in the ring are nearly tetrahedral, which is the preferred arrangement for carbon bonds. The chair conformation is also significant because it represents a compromise between the ring's need to minimize strain and its need to maintain its rigidity.
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what is the stoichiometry of the reaction between ferrous ions and permanganate ions.
The stoichiometry of the reaction between ferrous ion and permanganate ion can be expressed through the reaction below:
[tex]\rm MnO_{4}^{-} + 5 Fe^{2+} + 8 H^{+} \rightarrow Mn^{2+} + 5 Fe^{3+} + 4 H_{2}O[/tex]
What is redox reaction ?In a redox reaction, one reactant species is reduced and the other one oxidized. The species which is oxidized is donating one or more electrons to the other species and reduces it.
Iron metal donates 5 electrons to reduce Mn metal from oxidation state of + 7 to +2. One Fe furnish one electron. Thus, 5 Fe is needed.
The oxidation half reaction is written as:
[tex]\rm 5Fe^{2+} \rightarrow 5Fe^{3+} + 5e-[/tex]
The reduction half reaction of Mn is written as follows:
[tex]\rm MnO_{4}^{-} + 5e^{-} \rightarrow Mn^{2+}[/tex]
The whole reaction can be balanced for all the atoms and can be written as above.
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Match each property of a liquid to what it indicates about the relative strength of the intermolecular forces in that liquid:Strong intermolecular forces, Weak intermolecular forceshigh vapor pressurehigh surface tensionhigh viscosityhigh boiling point
The answer is 1) high vapor pressure = weak IMF, 2)high surface tension = strong IMF, 3) high viscosity = strong IMF, 4) high boiling point = strong IMF.
The strength of the intermolecular forces (IMF) is directly related to the boiling point of the compound. The higher the boiling point, the stronger the IMF. This is because a stronger IMF requires more energy to separate them, resulting in a higher boiling point.
The strongest IMFs involved in determining the boiling point of a compound are London dispersion forces (LDF), dipole-dipole interactions, and hydrogen bonding.
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If 2.1 moles of zinc react with 6.0 moles of hydrochloric acid in the equation Zn + 2HCl → ZnCl2 + H2, what is the limiting reactant?
Zn
HCl
ZnCl2
H2
The limiting reactant in the given equation [tex]Zn + 2HCl \rightarrow ZnCl_2 + H_2[/tex] is Zn. The correct answer is option A.
The limiting reactant, also known as the limiting reagent, is the substance that is completely consumed or in a chemical reaction, thereby determining the maximum amount of product that can be formed.
To determine the limiting reactant, we need to compare the stoichiometric ratios of the reactants to see which one will be completely consumed first.
In the balanced equation, the stoichiometric ratio between zinc (Zn) and hydrochloric acid ([tex]HCl[/tex]) is [tex]1:2[/tex], meaning that one mole of Zn reacts with two moles of [tex]HCl[/tex].
Given that,
we have 2.1 moles of Zn and 6.0 moles of [tex]HCl[/tex], we can calculate the number of moles of [tex]HCl[/tex] needed to react with 2.1 moles of Zn by multiplying 2.1 moles of Zn by the stoichiometric ratio:
2.1 moles Zn[tex]\times[/tex] (2 moles [tex]HCl[/tex]/ 1 mole Zn) = 4.2 moles HCl
Since, we have 6.0 moles of [tex]HCl[/tex], which is greater than the 4.2 moles required to react with 2.1 moles of Zn, [tex]HCl[/tex] is present in excess.
Therefore, the limiting reactant in the given equation [tex]Zn + 2HCl \rightarrow ZnCl_2 + H_2[/tex] is zinc (Zn), as it will be completely consumed before all the [tex]HCl[/tex] can react. Option A is the correct answer.
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Which of the following actions are permitted in balancing a chemical equation? Select all that apply.Multiplying all coefficients by a common factor
Inserting coefficients in front of formulas of reactants and products
When balancing a chemical equation, it is permitted to multiply all coefficients by a common factor, as well as inserting coefficients in front of formulas of reactants and products.
Additionally, you can also add reactants or products, and raise the coefficients.
When balancing a chemical equation, it is important to consider the mole ratio, which is the ratio of the number of moles of each reactant to the number of moles of each product. To balance the equation, you need to adjust the coefficients of the reactants and products until the mole ratios are equal.
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in this pair, identify all the molecular forces present for each substance, and select the substance with higher boiling point: circle one which has higher boiling point (a) ch3br or ch3f (b) ch3ch2ch2oh or ch3ch2och3 (c) c2h6 or c3h8 (d) mgcl2 or pcl3 (e) ch3nh2 or ch3f (f) ch3oh or ch3ch2oh (g) ch3ch2ch2ch2ch2ch3 or 2,2-dimethylbutane
In the pair (a) CH3Br or CH3F, the dominant intermolecular forces in CH3Br are dipole-dipole forces, while CH3F has London dispersion forces. Therefore, CH3Br has the higher boiling point [1].
In the pair (b) CH3CH2CH2OH or CH3CH2OCH3, the dominant intermolecular forces in CH3CH2CH2OH are hydrogen bonds, while CH3CH2OCH3 has dipole-dipole forces. Therefore, CH3CH2CH2OH has the higher boiling point.
In the pair (c) C2H6 or C3H8, the dominant intermolecular forces in C2H6 and C3H8 are London dispersion forces. Therefore, C3H8 has the higher boiling point.
In the pair (d) MgCl2 or PCl3, the dominant intermolecular forces in MgCl2 and PCl3 are ionic bonds. Therefore, MgCl2 has the higher boiling point.
In the pair (e) CH3NH2 or CH3F, the dominant intermolecular forces in CH3NH2 are hydrogen bonds, while CH3F has London dispersion forces. Therefore, CH3NH2 has the higher boiling point.
In the pair (f) CH3OH or CH3CH2OH, the dominant intermolecular forces in CH3OH and CH3CH2OH are hydrogen bonds. Therefore, CH3OH has the higher boiling point.
In the pair (g) CH3CH2CH2CH2CH2CH3 or 2,2-dimethylbutane, the dominant intermolecular forces in both molecules are London dispersion forces. Therefore, CH3CH2CH2CH2CH2CH3 has the higher boiling point.
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Identify the major product that is expected when acetaldehyde is treated with LiAlH4, followed by aqueous workup. A methanol, B.acetic acid C.propanol D.acetone E. etanol
The correct option is A. Methanol. When acetaldehyde is treated with LiAlH4, followed by aqueous then methanol will produce.
When acetaldehyde is treated with LiAlH4, the reaction results in the reduction of the aldehyde group to an alcohol. The LiAlH4 reacts with the acetaldehyde to form a charged intermediate species known as an enolate.
The enolate then undergoes hydrogenation, resulting in the production of methanol. Following the reaction, an aqueous workup is performed to hydrolyze the enolate and separate any impurities from the product. The aqueous workup also ensures that the LiAlH4 is completely neutralized, thus allowing for the recovery of the methanol as the major product.
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Write the symbol for every chemical element that has atomic number greater than 6 and atomic mass less than 25.2 u.
Answer:
C, Carbon
Explanation:
Write the symbol for every chemical element that has atomic number greater than 6 and atomic mass less than 25.2 u.
What would be the original Celsius temperature of a gas at a pressure of 4.5 atm if the temperature changes
to 110°C?
Please help I don’t understand thanks for your time if you solve this for me
The final temperature of the gas can be determined using Gay-Lussac's law. The temperature of the gas at 4.5 atm will be 66°C.
What is Gay- Lussacs law?According to Gay- Lussacs law at constant volume, the pressure of a gas is directly proportional to the temperature.
Hence, P/T = constant.
Let P1 and T1 be the initial pressure and temperature and P2, T2 be the final quantities, then
P1/T1 = P2/T2
Given P1 = 4.5 atm
T1 = ?
P2 = 7.5 atm
T2 = 110°C
Then T1 = P1 T2/P1
T1 = 4.5 atm ×110° C /7.5 atm
= 66°C
Therefore, the temperature of the gas at 4 .5 atm is 66°C.
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Your question is incomplete. But your complete question probably was:
What would be the original Celsius temperature of a gas at a pressure of 4.5 atm if the temperature changes to 110°C at 7.5 atm.
Which of the following elements would be a good selection as the sacrificial electrode in the cathodic protection of tin (Sn)?I. SilverII. CopperIII. NickelIV. Magnesium
Magnesium would be a good selection as the sacrificial electrode in the cathodic protection of tin (Sn).
Why is magnesium used as a sacrificial anode?
Chemically, magnesium is oxidation resistant and this is because its surface is covered with a thin layer of oxide which protects it from being vulnerable to air. This is why it is highly suitable for use in sacrificial anodes to limit the effects and susceptibility of other metal surfaces to corrosion.
What is the best sacrificial anode?
Magnesium anodes are the most active and are the only anodes that work well in the low conductivity of fresh water. Magnesium is also relatively non-toxic to aquatic life.
Why is tin resistant to corrosion?
Tin has good corrosion resistance properties in gas, weak base, and weak acid environment at room temperature because the super potential of hydrogen on the metal tin is high.
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Write correct ionic formulas for the following light emitting compounds by entering subscripts (remember that number of electrons that are given away has to be equal to the number of electrons that are accepted). if there is only one ion, then enter number 1.
A cation's name, symbol, and charge must be noted in order to determine the ionic compound's formula.The symbols for sodium and oxygen are respectively Na+ and O2.Na2O is the resultant substance.
What is the ionic formula ?A cation's name, symbol, and charge must be noted in order to determine the ionic compound's formula.Determine the anion's identity after which you should note its symbol and charge.Create an electrically neutral substance by combining the two ions.For ionic compounds, write a formula.Cation is on the left and anion is on the right. Write out the ions.Divide the charge by the number.Make subscripts out of the crossed-out numbers.Simplify if necessary.The symbols for sodium and oxygen are respectively Na+ and O2.Na2O is the resultant substance.To learn more about ionic formula refer
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Enter a formula for the compound that forms from strontium and chlorine
Express you’re answer as a chemical formula
on a piece of paper, write balanced molecular, total ionic, and net ionic equations for the reaction between aqueous solutions of acetic acid and potassium hydroxide
The balanced molecular equation for the reaction between aqueous solutions of acetic acid and potassium hydroxide is:
HC2H3O2(aq) + KOH(aq) → KC2H3O2(aq) + H2O(l).The total ionic equation for this reaction is:
H+(aq) + C2H3O2-(aq) + K+(aq) + OH-(aq) → K+(aq) + C2H3O2-(aq) + H2O(l).The net ionic equation for this reaction is:
H+(aq) + OH-(aq) → H2O(l).The net ionic equation for this reaction shows that the hydrogen ion (H+) and hydroxide ion (OH-) react to form water (H2O). This reaction is an example of a neutralization reaction, which occurs when an acid and a base react to form a salt and water.
The salt formed in this reaction is potassium acetate (KC2H3O2), which can be used in a variety of applications, including as a food preservative, in the production of perfumes, and as a source of potassium in fertilizer. In addition, the reaction can be used to titrate an acid to determine its concentration.
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15ml of 0.01m hcl is mixed with ml of 0.01m naoh. drag the appropriate quantities into the boxes to set up an equation that could be used to solve for the temperature change of the solution.
The equation for the temperature change of the solution when 15 ml of 0.01 M HCl is mixed with ml of 0.01 M NaOH is:
HCl + NaOH → NaCl + H2O
ΔT = (nHCl x ΔHCl) + (nNaOH x ΔNaOH)Where nHCl is the amount of moles of HCl and ΔHCl is the molar heat of reaction of HCl, and nNaOH is the amount of moles of NaOH and ΔNaOH is the molar heat of reaction of NaOH.
The temperature change of a solution is determined by the amount of heat energy it absorbs or releases during a reaction. For example, when a solute dissolves in a solvent, it can cause the temperature of the solution to rise or fall.
This is because the solute absorbs or releases heat energy in order to break the intermolecular forces between the solvent molecules and the solute molecules. Additionally, when two solutions are mixed, their temperatures may change due to endothermic or exothermic reactions.
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Completely classify liquid
Fe
.
A male client visits a health centre and reports that he is 5 feet 10 inches tall. Compute his ideal
body weight using Hamwi predictions imperial and metric and BMI predictions.
a. If the client actually weighs 164 lbs comment on his weight and the finding
In the equation:
2H₂ + O2 → 2H₂O
How many moles of hydrogen react with 0.37 mol of oxygen
Answer:
0.74 moles of hydrogen
Explanation:
f 0.37 mol of oxygen reacts, then the number of moles of hydrogen will also be 0.37 mol. According to the equation, 2 moles of hydrogen are required to react with 1 mole of oxygen, so 2 * 0.37 = 0.74 moles of hydrogen will react with 0.37 mol of oxygen.
how many molecules are in 1.64 moles of Br2?
The number of molecules in a certain number of moles can be calculated by multiplying the number of moles by Avogadro's number, which is approximately equal to 6.022 x [tex]10^{23}[/tex].
So, for 1.64 moles of Br2, the number of molecules would be:
1.64 moles × 6.022 x [tex]10^{23}[/tex] molecules/mole = 9.937 x [tex]10^{23}[/tex] molecules
Therefore, 1.64 moles of Br2 would contain approximately 9.937 x [tex]10^{23}[/tex] molecules.
What is Avogadro's number?The number of atoms, ions, or molecules in one mole of a substance is a key constant in chemistry. Named for the Italian scientist Amedeo Avogadro, it has a definition of 6.02214076 x [tex]10^{23}[/tex] particles per mole. Based on a sample's mass or molar quantity, this number is used to determine the number of atoms, ions, or molecules present. It is crucial for figuring out chemical reactions, putting chemical amounts into perspective, and figuring out how many particles are in a sample. The proportionality factor that connects the number of constituent particles in a sample with the amount of substance in that sample is called the Avogadro constant, often known as NA or L.
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What mass of iron(II) sulfate would be needed to provide 28 grams of iron?
Answer:
Explanation:
one half mole or 76 grams of Iron (II) Sulfate.
Oxide has a -2 charge. What is the overall negative charge in the formula, Ti*O_{2} which contains 2 oxide ions?
2 • -2 = ?
-2
+4
-4
+2
Answer:
-4
Explanation:
The overall negative charge in the formula Ti*O2 which contains 2 oxide ions, each with a -2 charge, is -4.
The total negative charge can be calculated by adding up the charges of all the oxide ions:
2 oxide ions x -2 charge/ion = -4
So, the overall negative charge in the formula Ti*O2 is -4.
Calculate the pOH of a 0.2 m hcl solution?
The pOH of a 0.2 m HCl solution is 13.3.
What is concentration?Concentration is the ability to focus on a particular task or activity, blocking out distractions and using cognitive resources efficiently. It is a key factor in achieving success in any area, whether it be in school, the workplace, sports, or leisure activities. Concentration requires a person to be able to pay attention to a specific task over a long period of time, while blocking out irrelevant or competing stimuli.
It also involves the ability to sustain focus and effort, even when faced with challenging or tedious tasks. Developing concentration skills can be beneficial in many aspects of life, including improved academic performance, increased productivity, better decision-making, and better problem-solving skills. Practicing mindfulness, taking regular breaks, and organizing tasks can all help to improve concentration.
pH=-log10[H+]
pH=-log10[0.2]
pH=0.7
You can then enter this into the equation
pH + pOH = 14
placing our pH value into this we get
0.7 + pOH = 14
You can rearrange this to find
pOH = 14–0.7
which means
pOH=13.3
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A student dissolves 15.g of styrenein (C8H8) in 250 mL of a solvent with a density of 0.88g/mL. The student notices that the volume of the solvent does not change when the styrene dissolves in it.Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.
The molar mass of styrene (C8H8) is 104 g/mol, when a student dissolves 15.g of styrenein (C8H8) in 250 mL of a solvent with a density of 0.88g/mL.
To calculate the molarity of a solution, you must divide the number of moles of solute (styrene) by the volume (liters) of the solution: 1438 mol ÷ 0.
25 L = 0.5752 M = 0.58 M (rounded to two significant figures)
To calculate the molarity of a solution, divide the number of moles of solute by the mass of solvent in grams.
0.1438 mol ÷ 250 g = 0.0005752 mol/g = 0.
00058 mol/g (rounded to 2 significant figures
A student dissolved 15 g of styrene (C8H8) in 250 ml of solvent with a density of 0.88 g/ml. Styrene has a molar mass of 104 g/mol, so the number of moles of solute is 15 g ÷ 104 g/mol = 0.1438 mol The molarity of the solution is zero.
1438 mol ÷ 0.25 L = 0.58 M. Molarity is calculated as 0.1438 mol ÷ 250 g = 0.
00058 mol/g. Both molarity and molarity are measures of concentration and indicate the amount of solute in a solution.
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Consider the following reaction mechanism and its associated energy diagram:
S1: C₂H4 (g) + HBr(g) --> C₂H5+ + Br
S2:
C₂H5 + Br --> C₂H5Br (1)
Answer:
From the energy diagram, we can see that the reaction mechanism is an example of a two-step reaction. The first step (S1) involves the combination of ethylene (C₂H4) and hydrogen bromide (HBr) to form an ethyl cation (C₂H5+) and a bromide anion (Br). In the second step (S2), the ethyl cation and bromide anion combine to form ethyl bromide (C₂H5Br). The reaction is exergonic as evidenced by the fact that the activation energy, represented by the peak in the energy diagram, is negative. This indicates that the reaction releases energy.
How many grams of sucrose, C12H22O11, (MM= 342.3 g/mol), must be added to 537 g of water to give a solution with a vapor pressure 0.513 mmHg less than that of pure water at 20°C? The vapor pressure of water at 20°C is 17.5 mmHg
There has to be 1.87 g of sucrose to be added to 537 g of water to make a solution with the specified vapor pressure.
Vapor Pressure Sucrose Solution
The vapor pressure of a solution is related to the concentration of solute particles in it. The decrease in vapor pressure, ΔP, is proportional to the molality of solute, m, in the solution: ΔP = -kPm, where k is a constant and P is the vapor pressure of pure water.
Since the vapor pressure of the solution is 0.513 mmHg less than that of pure water, we can write:
17.5 mmHg - 0.513 mmHg = 17.0 mmHg = -kP * m
Rearranging and solving for m, the molality, we have:
m = - ΔP / (kP) = 0.513 mmHg / (17.5 mmHg) = 0.0293 mol/kg.
We can then use the molality to find the amount of solute (sucrose) in grams needed to make the solution:
m = 0.0 293 mol/kg = 0.0 293 mol / (537 g) = 5.47 x 10^-5 mol
Finally, using the molar mass of sucrose, we can find the number of grams of sucrose needed:
5.47 x 10^-5 mol * 342.3 g/mol = 1.87 g.
So, 1.87 g of sucrose must be added to 537 g of water to make a solution with the specified vapor pressure.
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If concentrations are measured in M and time in seconds, what are the units for the rate constant, , for the rate law: Rate=[A][B]2.
If concentrations are measured in M and time in seconds, M³s⁻³ is the units for the rate constant, , for the rate law, Rate=[A][B]².
What is rate of reaction?The rate of the reaction or rate of the reaction is the rate at which an chemical reaction occurs, defined as proportionate to the rise in product concentration per unit time and the reduction in reactant concentration per unit time.
The speeds of reaction might vary greatly. For example, oxidative corrosion of iron in the Stratosphere is a slow reaction that really can take several years, but cellulose combustion in a fire occurs in fractions of a second.
Rate=[A][B]²
= Ms⁻¹×M²s⁻²
= M³s⁻³
Therefore, M³s⁻³ is the units for the rate constant, , for the rate law, Rate=[A][B]².
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