A horizontal spring on a frictionless surface has a spring constant of 10 N/m with a mass of 2kg attached to the end of the spring. If the spring is stretched 2m passed its point of equilibrium and released, how many times does the mass pass through equilibrium per second

Answers

Answer 1

Answer:

0.356 times the mass pass through equilibrium per second.

Explanation:

Given that,

Spring constant = 10 N/m

Mass = 2 kg

Stretched spring = 2m

We need to calculate the frequency

Using formula of frequency

[tex]f=\dfrac{1}{2pi}\sqrt{\dfrac{k}{m}}[/tex]

Where, m = mass

k = spring constant

Put the value into the formula

[tex]f=\dfrac{1}{2\pi}\sqrt{\dfrac{10}{2}}[/tex]

[tex]f=0.356\ Hz[/tex]

We know that,

Hertz = cycle per second

Hence, 0.356 times the mass pass through equilibrium per second.


Related Questions

Migration is the seasonal movement of a population of organisms from one place to another True or false

Answers

Answer:

true lol its jist common sense

Answer: Seasonal migration is the movement of various species from one habitat to another during the year. Resource availability changes depending on seasonal fluctuations, which influence migration patterns. ... Many species, especially birds, migrate to warmer locations during the winter to escape poor environmental conditions.

Explanation:

A material that restricts the flow of electricity or thermal energy is a what

Answers

Answer: Insulator

Explanation:

An insulator is a material that restricts the flow of electricity or thermal energy.

Answer:

plastic or wood

Explanation:

What is the internal resistance of a 12.0 V car battery whose terminal voltage drops to 8.2 V when the starter draws 75 A

Answers

Answer:

The internal resistance of the cell is 0.051 ohm.

Explanation:

Given;

emf of the battery, E = 12 V

terminal voltage of the cell, V = 8.2 V

current in the circuit, I = 75 A

let the potential drop of the cell due to internal resistance (r) = Ir

The internal resistance of the cell is calculated from the equation below;

E = V + Ir

where;

r is the internal resistance of the cell

[tex]Ir = E - V\\\\r = \frac{E-V}{I} \\\\r = \frac{12-8.2}{75} \\\\r = 0.051 \ ohm[/tex]

Therefore, the internal resistance of the cell is 0.051 ohm.

What type(s) of charges will be free to move around independently in a conductor under typical classroom conditions

Answers

Answer:

it is electron that is free to move in conductor

The force f is given in terms of time t and displacement X by the equation F= Asin Bx +C sin dt. What is the dimension of D/B?​

Answers

Answer:

Here's what I think,

A_Trigonometric_ratio (whatever)

The general form of sin/cos/tan(angle).

So here as in the general form the "whatever" is always an "angle" input which (may sound a bit unfair but) is a dimensionless quantity.

As mentioned in your question,

F= Asin(Bt) + C cos (Dy)

Dimentions of these terms will be same (by homogenity of dimensions).

So what we gotta do here is make Bt and Dy dimensionless for this whole equation to work.

According to your question t is time,

So to make Bt dimensionless,

B must be equal to inverse of time i.e T^(-1)

Using the same process on Dy, gives inverse of length i.e L^(-1)

So,

B= M^(0)L^(0)T^(-1)

D = M^(0)L^(-1)T^(0)

The dimension of D/B then will be M^(0)L^(-1)T^(1)

Suppose a race car accelerates horizontally 7.6 m/sec2 for 5.5 seconds. Assume the initial
velocity of the car is zero. How far did the race car travel while accelerating? This is a
displacement calculation.
Give your answer in standard form.

Answers

Answer:

d = 114.95 m

Explanation:

Givens:

a = 7.6 m/s^2

t = 5.5 s

v_i = 0 m/s

a = (v_f-v_i)/t

7.6 m/s^2 = (v_f-0 m/s)/5.5 s

v_f = (7.6 m/s^2)*(5.5 s)

v_f = 41.8 m/s

d = [(v_f+v_i)/2]*t

d = [(41.8 m/s)/2]*5.5 s

d = 114.95 m

a proton travelling along is x-axis is slowed by a uniform electric field E. at x = 20.0 cm, the proton has a speed of 3.5x10^6 m/s and at 80.0 cm the speed is zero. Determine the magnitude and direction of e,

Answers

Answer:

[tex]E=101955.8volt/m[/tex]

The electric field direction is toward the right

Explanation:

From the question we are told that

Initial X-co-ordinate of proton [tex]X_1=20.0cm => \frac{20}{100}m[/tex]

Initial speed of Proton [tex]V_1= 3.5*10^6 m/s[/tex]

Final X-co-ordinate of proton [tex]X_2=80.0cm => \frac{80.0}{100}m[/tex]

Final speed of Proton [tex]V_2=0[/tex]

Generally the mass of Proton is given by

[tex]m_P=1.67*10^-27[/tex]

Generally the kinetic energy of the proton is mathematically given by

 [tex]K.E_p=1/2mv^2[/tex]

 [tex]K.E_p=1/2*1.6*10^-^2^7*(3.5*10^6)^2[/tex]

  [tex]K.E_p=9.8*10^-^1^5[/tex]

Generally the change in electric potential [tex]\triangle V[/tex] is mathematically given by

   [tex]\triangle V =\frac{K.E_p}{q}[/tex]

Charge on a proton [tex]q=1.602*10^-^1^9[/tex]

   [tex]\triangle V =\frac{9.8*10^-^1^5}{1.602*10^-^1^9}[/tex]

   [tex]\triangle V =61173.5volts[/tex]

Generally the equation for magnitude of an electric field is mathematically given by

  [tex]E=\frac{\triangle V}{\triangle d}[/tex]

Where

[tex]d=0.8m-0.2m\\d=0.6m[/tex]

Therefore

    [tex]E=\frac{61173.5}{0.8-0.2}[/tex]

    [tex]E=\frac{61173.5}{0.6}[/tex]

    [tex]E=101955.8volt/m[/tex]

The direction of the charge is towards the right

     

Predict Phenomena A positively charged particle is placed next to an
negatively charged object. In which direction does the positively charged
particle move? Explain why.

Answers

Answer:

The positively charged particle will move towards the negatively charged particle.

Explanation:

According to Coulomb's Law, there are two types of charges--positive charge and negative charge. Coulomb said that they are either attractive or repulsive but the basic law in charges states that opposite attracts. Since they (the two charged objects) are oppositely charged, they will then move towards one another.

A pilot must fly his plane due north to reach his destination. The plane can fly at 300 km/h in still air. A wind is blowing out of the northeast at 90 km/h. (a) What is the speed of the plane relative to the ground

Answers

Answer:

229.5 km/h

Explanation:

Given that

Velocity of the plane relative to the ground = V.pg = ?

Velocity of air relative to the ground = V.ag = 90 km/h

Velocity of the plane relative to air = V.pa = 300 km/h

V.pg = V.ag + V.pa

Where

V.ag = 90 km/h

= -90 cos 45i - 90 sin 45j

V.pa = 300 km/h

= 300 cos θi + 300 sin θj

V.pg = [-90 cos 45i - 90 sin 45j] + [300 cos θi + 300 sin θj], on rearranging and collecting like terms

V.pg = [300 cos θ - 90 cos 45]i + [300 sin θ - 90 sin 45]j

If vector i = 0, then

300 cos θ - 90 cos 45 = 0

300 cos θ = 90 cos 45

cos θ = 90 cos 45 / 300

cos θ = 63.6396 / 300

cos θ = 0.2121

θ = cos^-1 0.2121

θ = 77.75

We then use this θ to find vector j

V.pg = 300 sin θ - 90 sin 45

V.pg = 300 sin77.75 - 90 sin45

V.pg = 293.1693 - 63.6396

V.pg = 229.5297 km/h

single phase ac voltage of 240 v is applied to a series circuit whose impedance is 10 60 find the resistance

Answers

Complete question

Single phase ac voltage of 240 v is applied to a series circuit whose impedance is 10<60 find the resistance

Answer:

[tex]R=5 ohms[/tex]

Explanation:

From the question we are told that

Voltage[tex]V=240[/tex]

Impedance[tex]Z= 10<60[/tex]

General converting from polar to Cartesian form is given by

   [tex]X=r*cos \theta[/tex]

   [tex]Y = r * sin\theta[/tex]

Therefore

  [tex]X=10 cos 60\texdegree[/tex]

   [tex]X=5[/tex]

   [tex]Y = 10 sin 60\textdegree[/tex]

   [tex]Y = 8.660[/tex]

Therefore

   [tex]Z=5+j8.660[/tex]

Generally the equation impedance is mathematically given as

[tex]Z=R+jX[/tex]

where

R is Resistance

X is Reactance

Therefore

[tex]R=5 ohms[/tex]

A 2.5 kg tribble is placed in a bucket and whirled in a 1.4 m radius vertical circle at a constant tangential speed. If the force on the tribble from the bucket does not exceed 10 times its weight (tribbles are a hardy species), the maximum tangential speed is

Answers

Given that,

Mass of a tribble, m = 2.5 kg

Radius, r = 1.4 m

The force on the tribble from the bucket does not exceed 10 times its weight.

To find,

The maximum tangential speed.

Solution,

The force acting on the tribble is equal to the centripetal force.

F = 10mg

The formula for the centripetal force is given by :

[tex]F=\dfrac{mv^2}{r}[/tex]

v is maximum tangential speed

[tex]v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{mgr}{m}} \\\\v=\sqrt{{10gr}} \\\\v=\sqrt{10\times 9.8\times 1.4} \\\\v=11.7\ m/s[/tex]

So, the maximum tangential speed is 11.7 m/s.

When Mary talks, she creates an intensity level of 60 dB at your location. Alice talks with the same volume, also giving 60 dB at your location. If both Mary and Alice talk simultaneously from the same spot, what would be the new intensity level that you hear

Answers

Answer:

hm

Explanation:

facil

Help please !

Which nucleotides form an RNA molecule?


Choose all that apply:


1) Adenine (A)
2) Uracil (U)
3) Thymine (T)
4) Cytosine (C).

Answers

Answer:

1) Adenine (A)   2. Uracil (U)   4) Cytosine (C)

Explanation:

"RNA consists of four nitrogenous bases: adenine, cytosine, uracil, and guanine."

Helppp plssss I am needing help for science and there is a photo pls answer

Answers

Answer:

sorry I don't really know :P

Explanation:

Answer:

how many of those questions do you need answers to?

Explanation:

An object accelerates downward at a constant rate of 2.00 m/s2 while completely submerged in water. Neglect the viscosity (fluid friction) of the water. The average density of the object is ______ kg/m3. Use g

Answers

Answer:

833kg/m³

Explanation:

We have volume as Vm³

Density of this object = dKg/m³

Water density = 1000kg/m³

g = 10m/s²

We calculate FB which is the the buoyant force on object. Calculated as volume of object multiplied by water density

Fb = 1000Vg upwards

W = Vdg

Acceleration = net upwards/m

M = mass

2 = (1000g-gd)/d

2d = 10000 - 10d

2d + 10d = 10000

12d = 10000

d = 833.33kg/m³

Approximately 833kg/m³

The average density of the object is therefore 833kg/m³

A record rotates on a turntable at 33 rpm. You may want to review What is the angular speed in rad/s?

Answers

Answer:

the angular speed in rad/s is 3.45

Explanation:

The computation of the angular speed in rad/s is as follows:

As we know that

1 rpm means 1 revolution per minute

Also 1 minute = 60 seconds

SO, for 33 rpm, the angular speed is

= 33 ÷ 60 × 2π

= 3.45  rad/s

As the revolution is of 360 degrees i.e. equivalent to 2π

Hence, the angular speed in rad/s is 3.45

A baseball has an approximate mass of 0.15 kg. If a bat strikes the baseball with a force of 6 N, what is the acceleration of the ball?

Answers

Answer:

a = 40 [m/s²]

Explanation:

These kinds of problems can be solved using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 6 [N]

m = mass = 0.15 [kg]

a = acceleration [m/s²]

[tex]a=F/m\\a=6/0.15\\a=40[m/s^{2} ][/tex]

Answer:

40 .............vxfhgcffffxxxhhxcjcxghxfgxsfg

A truck is carrying a load of furniture and has a momentum of 33,842 kg m/s. If half of the furniture falls off the truck (mass is cut in half), what is the truck’s new momentum?

Answers

Answer:

16921

Explanation:

Usually, if and when the truck does lose part of its load, or load gets cut into half, then it's momentum gets reduced to half of the original momentum. This is because, from the definition of momentum, we understand that it's the multiplication of mass and velocity. This means that if the mass gets reduced to half, then the total momentum goes ahead to be reduced to half just as well.

New momentum = 1/2 * 33842

New momentum = 16,921 kg∙m/s.

What is the maximum force that the student could apply to a 220kg object on the same surface before the box would start to slide

Answers

Answer:

Force needed to move the box is 2,158.2N

Explanation:

Step one:

We are given that the mass =220kg

The force needed to overcome friction is the same as the weight of the box

Step two :

So from

F=mg

W=mg

Substitute

W=220*9.81

W=2,158.2 N

How much work would be needed to lift the ball from the 2-m shelf to the 5-m shelf, and how much potential energy would it have on the 5-m shelf?

Answers

Answer:

a) 2.94 N

b) 4.90 N

Explanation:

Let us assume that the weight of the ball is 0.98 N

Solution:

a) An object’s gravitational potential energy depends on two factors which are height and its weight (or mass). The equation for gravitational potential energy (PE) is given as:  

Potential energy = weight (w) * height (h)

PE = wh

Potential energy at 2 m shelf = weight * height = 0.98 N * 2 m = 1.96 N

Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = Potential energy at 5 m shelf - Potential energy at 2 m shelf

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = 4.90 N - 1.96 N = 2.94 N

b) Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

The % DV (percent Daily Value) is based on an average 2,000-calorie diet. One gram of carbohydrate provides 4 calories of energy. If Anna’s doctor recommends getting 60% of her calories from carbohydrates, how many grams of carbohydrates should she consume each day?

Answers

Answer:

300

Explanation:

If the %DV is based on an average 2,000 calorie diet, and one gram of carbohydrate provides 4 calories, you would divide 2,000 by 4.

2,000 divided by 4 equals 500.

If Anna's doctor recommends 60% of her calories, you find out how much 60% of 500 is.

60% of 500 is 300.

Anna should consume 300 grams of carbohydrates daily.

Hope this helps!

Answer:

300

Explanation:

what does it mean to say that mass is conserved during a physical change?

Answers

When there is no change in chemical composition of a substance then it is known as physical change. When we say that mass is conserved during a physical change then it means that total mass of the substance or object will remain the same from beginning till the end.

Answer:

Explanation:

When a physical change occurs, the mass of the substance is conserved. This means that the total mass of the substance remains the same from beginning to end. The physical properties of the substance, such as size and shape, may change, but the amount of matter in the substance does not change.

( sample response )

A bungee cord stretches 25 meters and has a spring constant of 140 N/m. How much energy is stored in the bungee cord

Answers

Answer:

The energy stored in the bungee cord is 43,750 J.

Explanation:

Given;

extension of the bungee cord, x = 25 m

spring constant of the bungee cord, k = 140 N/m

The elastic potential energy stored in the bungee cord is calculated as;

U = ¹/₂kx²

U = ¹/₂(140)(25)²

U = 43,750 J

Therefore, the energy stored in the bungee cord is 43,750 J.

A force of 25 N acts on a 4.75 kg object for 8.4 s. What is the object's change in momentum?​

Answers

I’m Not Fa Sure but I really think is 45n hope it help sorry and good luck

How much heat Q2Q2 is transferred to the skin by 25.0 gg of steam onto the skin? The heat of vaporization for steam is L=2.256×106J/kgL=2.256×106J/kg.

Answers

Answer:

56400Joules

Explanation:

The quantity of heat required is expressed as;

Q = mL

m is the mass = 25g = 0.025kg

L is the latent heat of vaporization for steam = 2.256×10^6J/kg

Substitute into the formula as shown;

Q = 0.025×2.256×10^6

Q = 56400Joules

Hence the quantity of hear required is 56400Joules

The amount of heat transfer from the steam is of 56400 J.

Given data:

The mass of steam is, m = 25.0 g = 0.025 kg.

The latent heat of vaporization of steam is, [tex]L = 2.256 \times 10^{6} \;\rm J/kg[/tex].

When heat is to be given to a unit mass of substance to converts it from a liquid phase to vapor phase. Then it is known as Latent heat of vaporization. The amount of heat is expressed as,

[tex]Q = m \times L[/tex]

Solving as,

[tex]Q = 0.025 \times (2.256 \times 10^{6})\\\\Q = 56400 \;\rm J[/tex]

Thus, we can conclude that the amount of heat transfer from the steam is of 56400 J.

Learn more about the Latent heat of vaporization here:

https://brainly.com/question/24203857

if you go to space at 15000 mph. how long would it take you at the same speed to reach mars

Answers

Answer:

if your going 15000 mph all you can do is accelerate  or go fast  unless there is a opposite

Explanation:

A plastic ball has mass M. It floats in water with (1/5)th of its volume under the water line. What downward force must be applied to the ball to submerge it and hold it at rest below the surface of the water

Answers

Answer:

F = -4/5 W

Explanation:

We will do this exercise in parts, let's start with the data, The ball must be in balance

            B -W = 0

             B = mg                    (1)

where the thrust is given by Archimedes' principle

            B = ρ g V_liquid

In the problem we are told that the volume of the submerged body is 1/5 of the volume of the body, let's use the subscript 2 for the ball and the subscript 1 for the liquid

            V₁ = [tex]\frac{1}{5}[/tex] V₂

if we use the concept of density for the body

            ρ₂ = m / V₂

            m = ρ₂ V₂

We can see that mass and volume are directly proportional, so we can use a rule of three to find the submerged mass. If mass M is in volume V₂ what mass is there in volume V₂ /5

             m₂ = [tex]\frac{V_{2} }{5} \frac{M}{V_{2} }[/tex]

             m₂ = M / 5

we substitute in equation 1

             B = M / 5 g

This is the thrust that is an upward vertical force, therefore to submerge the whole ball we must apply a downward vertical force equal to the rest of the weight, the equilibrium condition in this case is

             B -W - F = 0

             F = B -W

             F = [tex]\frac{M}{5}[/tex] g - M g

             F = -4/5 Mg

             F = -4/5 W

The negative sign indicates that the force is vertical down

Calculate the average (mean) of these numbers: 6, 5, 7, 9.8*

1. 35

2. 8.75

3. 5

4. 7​

Answers

Answer:

13.94 to 2 d.p

Explanation:

just add them all up and i am confused the ones you said or the ones listed ?

the one i did was the listed ones

A 3.00-g bullet has a muzzle velocity of 230 m/s when fired by a rifle with a weight of 25.0 N. (a) Determine the recoil speed of the rifle. 0.27 Correct: Your answer is correct. m/s (b) If a marksman with a weight of 650 N holds the rifle firmly against his shoulder, determine the recoil speed of the shooter and rifle. Incorrect: Your answer is incorrect.

Answers

Answer:

0.27 m/s and 0.01 m/s

Explanation:

Given that

Mass of the bullet, m = 3 g = 0.003 kg

Velocity of the bullet, v = 230 m/s

Weight of the rifle, w = 25 N

From this, we know that the mass of the rifle, M = 25/9.8 = 2.55 kg

Using the law of conservation of momentum, we know that

Momentum of the gun = momentum of the bullet

M.g * V.g = m.b * v.b

2.55 * V.g = 0.003 * 230

2.55V.g = 0.69

V.g = 0.69 / 2.55

V.g = 0.27 m/s

If weight of the shooter = 650, then his mass = 650/9.8 = 66.33 kg

The recoil speed of the shooter is

0.69 / 66.33 = 0.010 m/s

what is one reason that john adams and benjamin franklin believed the articles of confederation should be revised.

Answers

Answer:

Explanation:

Their most intimate experience probably happened during an unsuccessful peace mission in September 1776. The British forces had recently raced across Long Island (New York) and almost destroyed the American Army. The British commander, Adm. Lord Richard Howe, then offered peace. Congress sent Adams, Franklin, and Edward Rutledge (South Carolina) to meet Howe on Staten Island.

Howe hoped to resolve the differences between what Great Britain still considered its colonies and the mother country. The Americans insisted on British recognition of independence, but Howe had no such authority, and Adams and Franklin had little of their own. Although cordial, the meeting broke up without success after just three hours.

During the mission, Adams and Franklin lodged together at crowded inn in a small room with only one window. Adams records an unforgettable and amusing story in his diary about that evening and hearing Franklin’s theory of colds.

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