Answer:
V=2.8 ml
Explanation:
volume of the cube is it would be 20.3 - 17.5 ml so 2.8 ml.
A soccer player applies a force of 48.4 N to a soccer ball while kicking it. If the ball has
a mass of 0.44 kg, what is the acceleration of the soccer ball?
A. 27.3 m/s2
B. 21.3 m/s2
C. 110 m/s2
D. 104 m/s2
Answer:
C. 110 m/s2
Explanation:
Force = Mass x Acceleration
Since we have the force and the mass, we can rearrange this equation to solve for acceleration by dividing both sides by mass:
Force/Mass = (Mass x Acceleration)/Mass
Acceleration = Force/Mass
Now we just have to plug in our values and calculate!
Acceleration = 48.4/0.44
Acceleration = 110m/s/s
It is option C. 110 m/s2
Hope this helped!
What type of change is making water from H^2 and O^2 ?
A. chemical
B. physical
Answer: chemical
Explanation: To change from hydrogen to oxygen is a chemical change because if you change hydrogen to oxygen, it is still a chemical. The answer is chemical.
Answer:
chemical possibly
Explanation:
fact
If an astronaut weighs 750 N on the ground, what will he weigh in earth orbit 400 km above the earth’s surface?
R_earth = 6.38 × 10^6 m,
m_earth=5.97×10^24 kg
G=6.674×10^−11 Nm^2/kg^2
Answer:
The weight of the astronaut in Earth's orbit 400 km above the Earth's surface is 664.115 N
Explanation:
The given parameters are;
The weight of the astronaut on the ground = 750 N
The height of the orbit above the Earths surface = 400 km
The radius of the Earth = 6.38 × 10⁶ m
The mass of the Earth = 5.97 × 10²⁴ kg
The universal gravitational constant G = 6.674 × 10⁻¹¹ Nm²/kg²
From Newton's law of universal gravitation, we have;
[tex]Weight \ on \ ground \ of \ astronaut \ F_W =G\times \dfrac{M_{Earth} \times m_{astronouat}}{R_{Earth}^{2}} = 750 \ N[/tex]
[tex]F_W =6.674 \times 10^{-11}\times \dfrac{5.97 \times 10^{24}\times m_{astronouat}}{(6.38 \times 10^6)^{2}} = 750 \ N[/tex]
[tex]m_{astronaut}[/tex] = ((6.38 × 10⁶)² × 750)/((6.674 × 10⁻¹¹) × (5.97 × 10²⁴)) ≈ 76.62 kg
The mass of the astronaut ≈ 76.62 kg
For the weight of the astronaut in Earth orbit 400 km (400 × 10³ m) above the Earth's surface, we have;
[tex]F_{W \ in \ orbit} =6.674 \times 10^{-11}\times \dfrac{5.97 \times 10^{24}\times 76.62}{(6.38 \times 10^6 + 400 \times 10^3)^{2} } = 664.115 \ N[/tex]
The weight of the astronaut in Earth's orbit 400 km above the Earth's surface = 664.115 N.
Janel did an experiment to see which spices can kill bacteria. She mixed a spice with bacteria food called agar. She poured the agar and spice mix into a petri dish(a plate used for growing bacteria) and added bacteria. She did the same for five different spices. This is an example of
Answer:
Antibacterial activity
Explanation:
The antibacterial property does not allow bacterias to live in an environment. Many spices have the ability to show antibacterial activity, few of these spices can be named as cinnamon, turmeric, or clove. Because they have antimicrobial or antibacterial characteristics that is why they are used for food preservation, disease prevention, and provide many health benefits. But, not every spice has antibacterial characteristics, that is why Janel experimented with five different spices to see which amongst them possess antibacterial characteristics.
Hence the correct answer is Antibacterial activity.
Suppose a scientist conducts a series of experiments and the results are so amazing she wants to share them with other experts in her field Why would it be risky for her to make the results public on her own website before publishing them to a scientific journal
Answer:
The results have not been through the rigorous process of peer review
Explanation:
When a scientist conducts a study and obtains results, those results ought to be submitted to a reputable journal where the results would go through the rigorous protocol of peer review.
During this process, the reliability of the data presented is ascertained before the results are published for other scientists to see.
If the results are hurriedly published on the internet, many researchers who come in contact with the work may be fed with inaccurate information.
m1=200g m2=150g
find the acceleration
the track is horizontal and frictionless
Answer:
50 or 1.3333
Explanation: Explanation you cancel out the mass and the force to see what your acceleration would be or you could divide F by M
Why is there no weather on the Moon?
Answer:
the moon has no atmosphere, and it cannot trap heat or insulate the surface.
Explanation:
the moon is too small. ... With weak gravity, gases that are emitted from the surface quickly are lost to outer space.
PLEASE HELP THIS IS DUE IN 10 MINUTES- (15 points!)
1st question- what are the weather fronts(use the pic for help)
2nd question- who has better weather— high pressure systems or low pressure systems and how do you know?
(Please add explanation)<3
Answer: I would say that B would have better weather because those dots on the right are cold fronts and the smooth side without the dots is a warm front. I hope this helps :)
Explanation:
A force applied to a 0.25 Kg hockey puck gives the puck an acceleration of 16 m/s2. What acceleration would the same force give to a 0.50 Kg baseball?
Answer:
8 m/s².
Explanation:
We'll begin by calculating the force applied to 0.25 Kg hockey puck. This is illustrated below:
Mass (m) = 0.25 Kg
Acceleration (a) = 16 m/s²
Force (F) =.?
Force (F) = mass (m) × acceleration (a)
F = ma
F = 0.25 × 16
F = 4 N
Therefore, a force of4 N was applied to the 0.25 Kg hockey puck.
Finally, we shall determine the acceleration in which the 4 N force will give to the 0.50 Kg baseball. This can be obtained as follow:
Mass (m) = 0.50 Kg
Force (F) = 4 N
Acceleration (a) =?
F = ma
4 = 0.5 × a
Divide both side by 0.5
a = 4 / 0.5
a = 8 m/s²
Therefore, the same force (i.e 4 N) applied to the hockey puck will give the 0.5 kg baseball an acceleration of 8 m/s².
Two fish swimming in a river have the following equations of motion:
X 1 = - 6.4 m + (- 1.2 m/s) t
X 2 = 1.3 m + (- 2.7 m/s) t
Which fish is moving faster?
Answer:
The second fish, X2, is moving faster than the first fish, X1
Explanation:
The given parameters for the equation of motion of the fishes are;
X1 = -6.4 m + (-1.2 m/s)×t
X2 = 1.3 m + (-2.7 m/s)×t
The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes
For the first fish, the intercept = -6.4 m, the slope = the speed = -1.2 m/s
For the second fish, the intercept = 1.3 m, the slope = the speed = -2.7 m/s
Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;
The magnitude of the speed of the second fish [tex]\left | -2.7 \ m/s \right | = 2.7 \ m/s[/tex], is larger than the magnitude of the speed of the first fish [tex]\left | -1.2 \ m/s \right | = 1.2 \ m/s[/tex]
Therefore, the second fish, X2, is moving faster than the first fish, X1.
An object with a charge of 1.2 C is located 4.5 m away from a second object that has a charge of 0.36 C. Find the electrical force that the objects exert on each other. Use 8.988×10 N⋅m2/C2 for the value of Coulomb's constant. Give your answer to two decimal places.
Answer:
[tex]1.917*10^8\ N[/tex]
Explanation:
Coulomb's law states that the electric force between two charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them. It is given by the formula:
[tex]F=k\frac{q_1q_2}{r^2}\\ \\q_1=first\ charge = 1.2C,q_2=second\ charge=0.36C,k=coulomb\ constant=8.988*10^9 N.m^2/C^2, r=distance=4.5m,F=force\\\\F=8.988*10^9*\frac{1.2*0.36}{4.5^2} =1.917*10^8\ N[/tex]
BRAINLIEST & 20 POINTS ANSWER THE BOTTOM TWO QUESTIONS PLEASE HURRY!!!!
Answer:
For 9 is 2,4,1 and 3.For 10 b-c moves 15 from each other and e-f moves 15 also from each other.
If a 3.1g ring is heated using 10.0 J, its temperature rises 19.7°C. Calculate
the specific heat capacity of the ring.
Answer:
Since 10 J / 4.19 J /cal = 2.39 cal is the heat absorbed by the ring
Q = Cs * m * (T2 - T1) heat absorbed by ring
Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C)
10 J / 4.19 J /cal = 2.39 cal is the heat absorbed by the ring, Q = Cs * m * (T2 - T1) heat absorbed by ring. Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C).
What is Specific heat capacity?The amount of heat required to raise the temperature per unit mass is known as specific heat capacity. The heat in Joules required to increase the temperature of 1 gram of sample by 1 Kelvin or degree Celsius is typically stated.
Water is an excellent temperature regulator because it has a very high specific heat capacity.
The amount of heat in joules needed to raise 1 gram of a substance by 1 Kelvin is known as the specific heat capacity (symbol: c). It could also be written as J/kgK. Molar heat capacity, measured in J/mol K, and volumetric heat capacity, measured in J/m3 K, are comparable values.
Therefore, 10 J / 4.19 J /cal = 2.39 cal is the heat absorbed by the ring, Q = Cs * m * (T2 - T1) heat absorbed by ring. Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C).
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Which of the following describes an ionic compound (or what is true for ionic compounds)?
a. It has a low melting points
b. It consists of shared electrons
c. It conducts electric current in water solution
d. It consists of two non-metals
Answer:
a b c
Explanation:
b. It consists of shared electrons
c. It conducts electric current in water solution
d. It consists of two non-metals
What are Ionic compound?Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.
For binary ionic compounds (ionic compounds that contain only two types of elements), the compounds are named by writing the name of the cation first followed by the name of the anion.
The properties of ionic compound are:
They form crystals. They have high melting points and high boiling points.They have higher enthalpies of fusion and vaporization than molecular compounds.They are hard and brittle.They conduct electricity when they are dissolved in water.They are good insulators.They consist of two non metals.Therefore,
b, c, d are the correct answer.
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Challenge: Write a Poem
Answer:
okkk soo...
Friendship is one of life's greatest treasures. Friends that are loyal are always there to make you laugh when you are down, they are not afraid to help you avoid mistakes and they look out for your best interest. This kind of friend can be hard to find, but they offer a friendship that will last a lifetime. Other friends may not be quite as loving. The pain caused by a friendship marred by betrayal is not easy to overcome. In fact, many poems find their inspiration from the joy brought about by a loving friendship or the pain caused by a failed friendship.
Explanation:
help do number 16 and 17
Answer:
16 is d and i have no idea for 17
* 22. Mmh A car is traveling along a straight road at a velocity of 36.0 m/s when its engine cuts out. For the next twelve seconds the car slows down, and its average acceleration is For the next six seconds the car slows down further, and its average acceleration is The velocity of the car at the end of the eighteen-second period is 28.0 m/s. The ratio of the average acceleration values is Find the velocity of the car at the end of the initial twelve-second interval.
Complete question is;
A car is traveling along a straight road at a velocity of 36.0 m/s when its engine cuts out. For the next twelve seconds the car slows down, and its average acceleration is For the next six seconds the car slows down further, and its average acceleration is The velocity of the car at the end of the eighteen - second period is 28.0 m/s. The ratio of the average acceleration values is a1/a2 = 1.5.
Find the velocity of the car at the end of the initial twelve - second interval.
Your answer
Answer:
30 m/s
Explanation:
To solve this, we will use Newton's first equation of motion;
v = u + at
Since we are dealing with acceleration ratio, let's make a the subject;
a = (v - u)/t
For the first 12 seconds and initial velocity u = 36 m/s, we have;
a1 = (v - 36)/12
For the remaining 6 seconds, initial velocity is the final velocity from the initial 12 seconds. Thus;
a2 = (28 - v)/6
We are given that a1/a2 = 1.5
Thus;
[(v - 36)/12]/[(28 - v)/6] = 1.5
(6/12)((v - 36)/(28 - v)) = 1.5
(v - 36)/(28 - v) = 1.5 × 12/6
(v - 36)/(28 - v) = 3
v - 36 = 3(28 - v)
v - 36 = 84 - 3v
4v = 120
v = 120/4
v = 30 m/s
Which of the above beak depth vs time graphs represent the change in finch beak depth that would occur due to successive years of above average rainfall?
Answer:
A
Explanation:
I just did it :)
Answer:
It is A
Explanation:
I did it and got a 100
Find the acceleration if the force is 10 N and the mass is 5 kg.
Explanation:
Hey there!
Given;
F = 10N
Mass = 5kg
Acceleration due to gravity (a)= 9.8m/s^2
We know that;
F = m*a
Put all values and solve for "m".
10 = m*9.8
Simplify it.
[tex]m = \frac{10}{9.8} [/tex]
Therefore, m= 1.0204kg.
Hope it helps...
plzzzzzzzzz I need to know for school!!!
What is the definition of law of conservation of energy???
Answer:
This law, first proposed and tested by Émilie du Châtelet, means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another. For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.
Explanation:
Answer:
Hi! I am confused
Explanation:
What distance is required for a train to stop if its initial velocity is 23 m/s and its
deceleration is 0.25 m/s²? (Assume the train decelerates at a constant rate.)
-- The train starts at 23 m/s and slows down by 0.25 m/s every second.
So it'll take (23/0.25) = 92 seconds to stop.
-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s
-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover
(11.5 m/s) x (92 sec) = 1,058 meters .
The distance required for the train to travel before stopping is 1,058 m.
The given parameters;
initial velocity of the train, u = 23 m/s
deceleration of the train, a = 0.25 m/s
The distance traveled by the train is calculated as follows;
[tex]v^2 = u^2 -2as[/tex]
where;
v is the final velocity of the train
The final velocity of the train is zero when the train stops
[tex]v^2 = u^2 -2as\\\\0 = 23^2 - 2(0.25)s\\\\0.5s = 529\\\\s = \frac{529}{0.5} \\\\s = 1,058 \ m[/tex]
Thus, the distance required for the train to travel before stopping is 1,058 m.
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What type of bond is shown in the figure?
Answer:
ionic
Explanation:
(Please answer quickly!)
Force and energy aren't the same thing but they are closely related. explain how.
Answer:
Explanation:
Bigger pushes and pulls cause bigger changes in an object's motion or shape. When objects collide, contact forces transfer energy so as to change the objects' motions. When two objects interact, each one exerts a force on the other, and these forces can transfer energy between them.
The velocity of an object is it’s speed and __ of motion .
Answer:
direction should be the answer
Which sentence describes Newton's first law?
A. Forces always come in pairs that have the same magnitude.
B. The action force applied by one object to another is opposite in
direction to the reaction force.
C. It takes a larger net force to accelerate an object at a greater rate.
D. Unbalanced forces cause an object to move.
SM
[tex]\Large{\red{\bf{\blue{\dag} Answer:-}}}[/tex]
Newton's First Law of Motion :
An object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .
Here this statement is best represented by the statement : Unbalanced forces cause an object to move. [ option c ]
More to know :-
Newton's 3 laws of motion :-
Newton's First Law of Motion :-
It states that an object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .
Ex - (i) We tend to fall backwards while standing in the bus , when it starts suddenly.
(ii) We tend to fall forward while standing in the bus , when it stops suddenly.
Newton's Second Law of Motion :-
It states that the rate of change of momentum is directly proportional to the applied force in the direction of the force . That is ∆p [tex]\propto[/tex] Force .
Ex - (i) When we push car & a truck with same force the car will have Greater acceleration due to less mass . (Imaginary case ).
(ii) We feel easy to push a empty cart than a full cart .
Newton's Third Law of Motion :-
It states that every action has equal and opposite reaction .
Ex - (i) We are able to walk on ground due to Newton's third law of motion .
(ii) When we push wall it also applies equal and opposite force .
"Unbalanced forces cause an object to move " is the sentence that describes Newton's first law.
Describe Newton's first law.A body remains in the state of rest or uniform motion in a straight line unless and until an external force acts on it.
The object is to be rest if the velocity and acceleration are zero. When an object is in motion, velocity is not equal to zero (v ≠ 0) but acceleration (a = 0) is equal to zero. Therefore, the object will continue in motion with constant velocity in the same direction.
Example:
If we jump from a bus while moving, our body will be like still moving in the same direction of the vehicle. When your feet hit the ground, the grounds act on your feet and stop moving. You will fall because the upper part of your body didn't stop and you will fall in the direction you were moving.
If the object have the greater mass, then the object will have more inertia. Forces can change the object's motion.
Hence, Option D is the correct answer.
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How long would it take Jesse with an acceleration of -2.50 m/s2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?
Answer: 5.4 seconds
Explanation:
The time taken to stop the bicycle is 5.4 seconds. The final velocity is zero. Then, the distance travelled by the bicycle is 36.45 m.
What is acceleration ?Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.
Given initial velocity = 13.5 m/s
final velocity is zero since the bicycle is stopping.
then Δt = Δv/a
Δt = 13.5 m/s/ 2.50 m/s² = 5.4 seconds.
Hence, the bicycle will take 5.4 s to complete stop.
The distance covered within this time can be determined using the equation as follows:
s = ut + 1/2 at²
where u is the initial velocity
s = (13 m/s × 5.4 s) + (-2.50 m/s² ×5.4 s ×5.4 s) = 36.4 m.
Therefore, the bicycle will travel up to 36.4 m before stopping.
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60 point!!!
Instructions-
Give a real life example of each of Newton's Laws in action. Be sure to specificy which law your
example is linked to.
Give examples with pulleys
Answer:
Playing hockey, driving a car, and even simply taking a walk are all everyday examples of Newton's laws of motion.
explain how the air balloon moves up and down.
Explain in terms of density
Answer:
hope it helps ....
Explanation:
The inside air that has been heated rises due to the difference of density between the hot and cold air particles. The heated air, the air that is inside the balloon, is less dense than the cool air, the air outside of the balloon. ... You can see that the bigger the volume gets, the smaller the density is.
A ship is travelling due east at
30 km/hr and boy runs across
the deck in a south east west
direction at 10 km/hr. Find the
veloocity of the boy relative to sea.
Answer:
The relative velocity of the boy with respect to the sea is 37.7 km/hr
Explanation:
Answer:
37.7 km/hr I'd the velocity
6. Most things you use every day are: a.compounds b. elements c. mixtures
Answer: B. Elements
Explanation:
Most things we use everyday are compounds which are composed of two or more elements.
What are compounds?
Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.
Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:
1)Molecular compounds where in atoms are joined by covalent bonds.
2) ionic compounds where atoms are joined by ionic bond.
3)Inter-metallic compounds where atoms are held by metallic bonds
4) co-ordination complexes where atoms are held by co-ordinate bonds.
They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.
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