A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°.

a. What is the horizontal component of the velocity?
b. What is the vertical component of the velocity?
c. How long does it take the ball to reach its highest point?
d. What is the maximum height of the ball?
e. What is the total amount of time that the ball is in the air?
f. How far is the ball from the football player when it lands?

I would appreciate any help :)

Answer:

C)2.08 g/ml

Explanation:

density = [tex]\frac{mass}{vloume\\}[/tex]

             =[tex]\frac{5}{2.4}[/tex]

             =2.08g/ml

Answer:

a = 0.01 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which says that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

F = forces = 10 [N]

m = mass = 100 [kg]

a = acceleration [m/s²]

10 = 100*a

a = 0.01 [m/s²]

Answer:

Explanation:

Step one:

given data

mass of bullfrog= 0.54kg

Step two:

Required

The force F in Newton

From newton first law

F=mg

The acceleration due to gravity acting on the frog is 9.81m/s^2

hence

F=0.54*9.81

F=5.3N

The normal force is 5.3N

Answer:

A. 16.67 m/s

Explanation:

Speed or velocity refers to the rate of change in distance over a change in time. That is;

Speed = Distance ÷ time

Where;

Speed is in metre/seconds

Distance is in metre

Time is in seconds.

In this question, Steve throws a football 50 meters in 3 seconds. The average speed can be calculated this:

S = D/t

Where; d = 50m, t = 3s

S = 50/3

S = 16.6666666

S = 16.67m/s

Answer:

[tex] \boxed{ \rm{Frequency = 2 hertz}}[/tex]

Explanation:

We know that,

"Frequency refers to the number of occurrences of a periodic event per time and is measured in cycles/second."

According to Question,

⇒ 5 seconds = 10 oscillations

⇒ 1 second = 10/5 oscillations

⇒ 1 second = 2 oscillations

In one second, there are 2 oscillations or cycles. The unit of frequency is Hertz. Hence, the frequency is 2 Hertz.

Answer:

coral reef

Explanation:

Answer:

The acceleration of the racecar is [tex]\mathbf{11.17~m/s^2}[/tex]

Explanation:

Uniformly Accelerated Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Following the definition above, the acceleration is defined as:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The racecar goes from vo=18.5 m/s to vf=46.1 m/s in t=2.47 seconds, thus the acceleration is:

[tex]\displaystyle a=\frac{46.1-18.5}{2.47}[/tex]

[tex]\displaystyle a=\frac{27.6}{2.47}[/tex]

[tex]a = 11.17~m/s^2[/tex]

The acceleration of the racecar is [tex]\mathbf{11.17~m/s^2}[/tex]

Answer:

52 km/h

Explanation:

When the two trucks move together after collision, the momentum of the system is conserved. The kinetic energy is not conserved. This is inelastic collision

The formula to apply here is :

m₁v₁ + m₂v₂ = {m₁+ m₂} *vf

Given that ;

m₁ = 8 ton ----convert to kg [ multiply by 907.185] =7258 kg

v₁ = 60 km/h

m₂ = 5 tons ------4536 kg

v₂ = 40 km/h

vf = final velocity

Using the values given;

m₁v₁ + m₂v₂ = {m₁+ m₂} *vf

8*60 + 5*40 = {8+5} * vf

480 + 200 = 13 * vf

680 = 13vf

680/13 = vf

52 km/h = vf

Answer:

The answer is b: mechanical to electrical

Answer:

500 kg

Explanation:

It is given that,

The mass of a open train car, M = 5000 kg

Speed of open train car, V = 22 m/s

A few minutes later, the car’s speed is 20 m/s

We need to find the mass of water collected in the car. It is based on the conservation of momentum as follows :

initial momentum = final momentum

Let m is final mass

MV=mv

[tex]m=\dfrac{MV}{v}\\\\m=\dfrac{5000\times 22}{20}\\\\=5500\ kg[/tex]

Water collected = After mass of train - before mass of train

= 5500 - 5000

= 500 kg

So, 500 kg of water has collected in the car.

The mass of the  water collected in the car due to the rain is 500 kg.

The given parameters;

The mass of water collected in the car is determined by applying the principle of conservation of linear momentum as shown below;

[tex]m_cu_c = v(m_c + m_w)\\\\5000 \times 22 = 20(5000 + m_w)\\\\110,000 = 100,000 + 20m_w\\\\20m_w = 10,000\\\\m_w = \frac{10,000}{20} \\\\m_w = 500 \ kg[/tex]

Thus, the mass of the  water collected in the car due to the rain is 500 kg.

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We can see here that in order for a protostar to transition to a full fledge star, A. Nuclear fusion must occur in the protostar

A protostar is a massive cloud of gas and dust in space that has the potential to become a star and is currently collapsing due to its own gravity. It is the initial stage of a star's development.

The protostar will continue to collapse and get hotter and denser until the conditions are right for nuclear fusion, when it will fuse and turn into a star.

A star gets its energy through nuclear fusion, which is the process of joining atomic nuclei to create heavier atoms. The star is not hot enough or thick enough during the protostar phase for nuclear fusion to take place.

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Answer:

Dry Arid, Coastal, Mountains

Explanation:

Took the text

Answer:

57 meters

Explanation:

Let's see what variables we have in this problem:

Let's set the upwards direction to be positive and the downwards direction to be negative.

We are given the initial velocity, 4 m/s. Since the ball is thrown directly downward, we can say that the initial velocity = -4 m/s.

We are also given the acceleration due to gravity, and since the acceleration is pointing downwards, we can say that a = -10 m/s².

The time is also given to us; the question wants to know the vertical displacement at time = 3 seconds, so we can plug in 3 seconds for t.

Since we are solving for vertical displacement, we can use [tex]\triangle x[/tex] as one of our variables.

Now we have all of the variables except for the final velocity, [tex]v_f[/tex].

Since we are dealing with constant acceleration, we can use this constant acceleration equation:

Subtract [tex]x_i[/tex] from both sides to get [tex]\triangle x[/tex].

Substitute in the known values:

Get rid of the units to make the equation more readable.

Simplify the equation and solve for delta x.

The vertical displacement is -57 meters, so we can say that the distance the ball falls in 3 seconds is most nearly 57 meters.

Answer:

Vf = 90km/h

      (90*1000)/3600 ==>

      (90*10)36

Vf = 25m/s

, Vi = 60km/h

         (60*1000)/3600

          16.666m/s =>16.7m/s

          , a = 4m/s^2

t = ?

Explanation:

Vf = Vi + at

25m/s = 16.7m/s +4m/s^2(t)

25m/s - 16.7m/s = 4m/s^2(t)

8.3m/s = 4m/s^2(t)

8.3m/s/4m/s^2 = t

2.075s = t => 2.1s

Answer:

N = 3.54 * 10²³ atoms

Explanation:

The formula to apply here is the idea gas law;

PV = nRT  where ;

P= pressure of the gas= 1.013 * 10⁵ Pa

V= volume of the gas = 4/3 * 3.14 *0.15³= 0.01414 m³

n= amount of a substance = ?

R= ideal gas constant= 8.314

T= temperature= 293 K

Applying the values to the formula;

PV = nRT

1.013 * 10⁵ * 0.01414 = n * 8.314*293

n= 1.013 * 10⁵ * 0.01414 / 8.314*293

n= 0.588 moles

1 mole = 6.022 * 10²⁷ atoms/ mole

0.588 moles = 0.588 * 6.022 * 10²⁷

N = 3.54 * 10²³ atoms

Answer:

B. Burned gas...

Explanation:

The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed.

RNA polymerase is an enzyme that aids in the transcription of DNA into RNA during transcript in the nucleus. The enzymes prevent many genetic mutations from being expressed.

Primase is an enzyme that synthesizes short RNA sequences called primers. These primers serve as a starting point for DNA synthesis during replication as the DNA polymerases cannot begin the synthesis of the new strand, they only extend it after primase begins it and primase produces RNA molecules, the enzyme can be said to be a type of RNA polymerase.

Therefore, The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed.

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Answer:

The intensity is  [tex] I  = 0.0175I_o [/tex]

Explanation:

From the question we are told that

   The wavelength is  [tex]\lambda = 633 \ nm = 633*10^{-9} \ m[/tex]

   The width of the slit is [tex]d = 0.24 \ mm = 0.00024 \ m[/tex]

   The distance from the screen is  [tex]D = 6.0 \ m[/tex]

   The distance of the position considered from the center is [tex]y = 3.0 \ mm = 0.003 \ m[/tex]

  Generally the intensity from at a point on the screen 3.0 mm from the center of the pattern is

       [tex]I = I_o * \frac{sin^2 [\frac{\pi d * y}{ \lambda D } ]}{[\frac{\pi d * y }{\lambda D} ]^2}[/tex]

 Here  [tex]I_o[/tex] is the intensity of the central bright fringe

=>    [tex] I  = I_o *  \frac{sin^2 [\frac{3.142  * 0.00024 * 0.003}{ 633*10^{-9} * 6 } ]}{[\frac{3.142*0.00024  * 0.003 }{633*10^{-9} * 6} ]^2}[/tex]

=>    [tex] I  = 0.0175I_o [/tex]        

Answer:

oxygen, water , energy

Explanation:

i took the instruction where this is from

Answer:

oxygen/water/energy

Explanation:

edge2020

God Bless You<3

Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. ... It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.

Explanation:

AnsA

Explanation:

The amount of matter in an object

Answer:

earth is not the center of the universe

Explanation:

i just took the test

Kepler's laws allow us to find that the correct answer, the basis is these is

 d) Earth is not the center of the universe.

Kepler made extensive measurements and created a mathematical model of the movement of the planets around the sun, these analyzes are written in the form of three laws

                [tex]T^2 = ( \frac{4\pi ^2}{G M_s} ) \ a^3[/tex]

Where T is the period, a the major axis, G the universal gravitational constant and [tex]M_s[/tex] the most of the sun.

When analyzing these Kepler's laws in all the sun is the center of movement.

Let's analyze the different claims;

a) False. The laws are not on a specific planet

b) False. Gravity is not in Kepler's laws

c) False. A ratio of the masses between planets and the sun is not established

d) True. In the laws the sun is the center of movement, therefore the earth is not the center of the universe.

In conclusion using Kepler's laws we can find that the correct answer for the bases of these is:

 d) Earth is not the center of the universe.

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Answer:

Explanation:

When coin is at a height and rest, it only has potential energy( by the virtue of its position). While the coin is falling its potential energy changes into kinetic energy. This means that its potential energy is decreasing and kinetic energy increases. just before its hits the ground kinetic energy is maximum and potential energy becomes zero.

When it hits the ground all its kinetic energy is converted into heat.

Answer:

If N is the number of forces acting on a body, the net force formula is given by, FNet = F1 + F2 + F3

Explanation:

Answer:

Let theta be angle of upper string with rod.

This a 3-4-5 triangle where R is distance of block from rod. (.75 - 1 - 1.25)

Fc = m w^2 R    where Fc the centripetal force and w the angular velocity

Fc = T sin theta = T * .75 / 1.25 = .6 T = 45.6 N

w^2 = 45.6 / (4 * .75)

w = 3.90 /sec

RPM = 3.90 / sec * 60 sec / min / (2 * pi) = 37.2 RPM      (2 pi rad / rev)

The number of revolutions per minute at which the lower cord just goes slack is 45.36 RPM.

The given parameters;

The following triangle can be formed from the given diagram;

     |

     | 1 m

     |---------x--------(θ)  4.00 kg

The hypotenuse of this triangle = 1.25 m

The height of the triangle = 1 m

The base of the triangle is calculated as;

[tex]x^2 = 1.25^2 - 1^2\\\\x^2 = 0.5625\\\\x = \sqrt{0.5625} \\\\x = 0.75 \ m[/tex]

Resolving the vertical component of the force;

Tension at the upper = Tension at the lower string

[tex]T_1 sin(\theta) = T_2 sin(\theta) + mg\\\\76 \times \frac{1}{1.25} = T_2 \times \frac{1}{1.25} + (4\times 9.8)\\\\76 = T_2 + 39.2\\\\T_2 = 76 - 39.2\\\\T_2 = 36.8 \ N[/tex]

Resolving the horizontal component of the force;

[tex]T_1cos(\theta) + T_2cos(\theta) = F_c\\\\T_1cos(\theta) + T_2cos(\theta) = mr\omega^2 \\\\76\times \frac{0.75}{1.25} \ + \ 36.8\times \frac{0.75}{1.25}= 4\times 0.75\tmes (\frac{2\pi N}{60} )^2\\\\67.68 = 0.0329N^2\\\\N^2 = \frac{67.68}{0.0329} \\\\N^2 = 2057.14\\\\N = \sqrt{2057.14} \\\\N = 45.36 \ rpm[/tex]

Thus, the number of revolutions per minute at which the lower cord just goes slack is 45.36 RPM.

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Answer:

v = 51.4 m/s

Explanation:

Given that,

Initial velocity of a penny, u = 2.4 m/s

It fall under the influence of gravity for 5 s.

We need to find the final velocity of the penny. Let v is its final velocity. It can be calculated using first equation of motion as follows :

[tex]v=u+at[/tex]

a = g

[tex]v=2.4+9.8(5)\\\\=51.4\ m/s[/tex]

So, the final velocity of the penny is 51.4 m/s.

Answer:

Answer: E moving down at 9.2 m/s​

Explanation:

Vertical Launch Upwards

This occurs when an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed, t is the time, and g is the acceleration of gravity, the speed of the object is given by:

[tex]v_f=v_o-g.t[/tex]

Considering the positive direction of the speed as upwards, if the speed is negative, it means the object is moving down back to the point where it was launched from.

The object is thrown with an initial speed of vo=30 m/s. Let's calculate its speed at t=4 s:

[tex]v_f=30-9.8\cdot 4[/tex]

[tex]v_f=30-39.2=-9.2[/tex]

[tex]v_f=-9.2\ m/s[/tex]

Since it's negative, the object is coming back down.

Answer: E moving down at 9.2 m/s​

Answer:

1) f = 38.63 Hz , 2)   f = 115.9 Hz

Explanation:

The elephant's trunk can be approximated by a tube with a closed end, in pipes the closed ends correspond to nodes and the open ends to antinodes or bellies.

The expression for the wavelengths of this system is

             4L = n λ

              n = 1, 3, 5, 7 ...

also let's use the relationship between frequency and wavelength and wave speed

            v = λ f

             f = v / λ

             f = v n / 4L

             f = v / 4L n

1) the fundamental frequency occurs for n = 1

            f = 340/4 2.2 1

            f = 38.63 Hz

2) The first harmonic

           n = 3

            f = 340/4 2.2  3

           f = 115.9 Hz

Answer:

Explanation:

Step one:

given data

mass m=5kg

compression x= 3.13cm to m= 0.0313m

According to Hooke's law, provided the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force

F=ke

where

k= spring constant in N/m

e= extension/compression in

Step two:

assume g= 9.81m/s^2

F=mg

F=5*9.81

F=49.05N

substitute in the expression F=ke

49.05=k*0.0313

k=49.05/0.0313

k=1567.09 N/m

The force constant (in N/m) of the spring is 1567.09 N/m

Answer:

where is the picture of star