A flat, circular, steel loop of radius 75 cm is at rest in a uniform magnetic field, as shown in an edge-on view in the figure (Figure 1). The field is changing with time, according to B(t)=(1.4T)e^−(0.057s^−1)t.
a) Find the emf induced in the loop as a function of time (assume t is in seconds).
b) When is the induced emf equal to 110 of its initial value?
c) Find the direction of the current induced in the loop, as viewed from above the loop.
Answers
The solution to the questions are given as
[tex]t=40.39 \mathrm{sec}[/tex][tex]\varepsilon &=(0.12v)e^{0.057t}[/tex]the direction of induced current will be Counterclock vise.What is the direction of the current induced in the loop, as viewed from above the loop.?Given, $B(t)=(1.4 T) e^{-0.057 t}$
[tex]$\varepsilon m f(\varepsilon)=-\frac{d \phi_{B}}{d t}[/tex]
[tex]\quad$ and, $\phi_{B}=\int B \cdot d A=\int B \cdot d A \cdot \cos \theta$[/tex]
[tex]\begin{aligned}\text { Here, } \theta &=30^{\circ} ; \\A &=\pi r^{2} \\a n \delta, R &=0.75 \mathrm{~m} \\\therefore \varepsilon &=-\frac{d}{d t}(B A \cdot \cos \theta)=-A \cdot \cos \theta \cdot \frac{d}{d t}(B(t)) \\\therefore \varepsilon &=-\pi R^{2} \cdot \cos \theta \cdot \frac{d}{d t}\left(e^{-0.057 t}\right)(1.4 T) \\\therefore \varepsilon &=+\pi(0.75)^{2} \cdot \cos 30 \cdot(0.057)(1.4) \cdot e^{-0.057 t}\left\{\because \frac{d}{d t} e^{-x}=-x \cdot e^{-x} .\right.\end{aligned}[/tex]
[tex]\varepsilon &=(0.12v)e^{0.057t}[/tex]
(b) [tex]Here, $\varepsilon_{0}=0.12 \mathrm{~V} \quad\left(a t_{2} t=0 \mathrm{sec}\right)$[/tex]
[tex]\begin{aligned}&\therefore 1 . \varepsilon_{0}=\varepsilon_{0} \cdot e^{-e .057 t} \\&\therefore e^{0.057 t}=10 \quad \text { (taking log both thesides) } \\&\therefore 0.057 t=\ln (10)=2.303 \\&\therefore t=40.39 \mathrm{sec}\end{aligned}[/tex]
c)
In conclusion, the direction of the induced current will be Counterclockwise.
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Related Questions
How many electrons are needed to form a charge of
−4.70 nC
Answers
e = -1.602 × 10⁻¹⁹ C
N: number of electrons
Ne = Q → N = Q/e
N = (4.70/1.602) × 10⁻⁹ × 10¹⁹
= 2.934 × 10¹⁰
"2.934 × 10¹⁰ electrons are require to form a charge of -4.70 nC"
The drawing shows a device that can be used to measure the speed ofa bullet. The device consists of two rotating disks,separated by a distance of d = 0.850 m, and rotating with anangular speed of 95.0 rad/sec. The bullet first passesthrough the left disk and then through the right disk. It isfound that the angular displacement between the two bullet holes isθ = 0.240 rad. From these data, determine thespeed of the bullet.
Answers
V = 336.46 m/sec is the speed of the bullet .
What is displacement ?
Displacement in mechanics. The distance a particle or object travels in a particular direction. Particles and bodies are usually treated as point masses. That is, without loss of generality, an object can be treated as if all its mass were concentrated at one mathematical point. In the figure, A is the start position of the point, B is the end position, and the straight line from A to B is the displacement. The distance a point moves depends on the path it follows. Equals the amount of displacement only if the path is straight. In mechanics, it is often necessary to distinguish between the distance a point moves (or the distance a force acts) and the displacement of a point or force. Displacement is a vector quantity because it has both magnitude and direction.
Let speed of bullet be "V". Then we have:
{Speed Of Bullet} = V
{Time For Bullet To Travel
Distance "d" Between Rotating Disks} = T =
= d/V
= (0.850 m)/V
= (0.850)/V (<---Eqn #1)
{Disk Rotational Speed} = ω = 95.0 rad/sec
{Angular Displacement Between Bullet Holes} = θ = 0.240 rad
{Time Between Successive Disk Bullet Holes} = T =
= θ/ω
= (0.240)/(95.0)
= 0.002526315 sec (<--- Eqn#2)
We now equate Eqn #1 & #2, and solve for "V":
(0.850)/V = 0.002526315
----> V = (0.850)/(0.002526315)
----> {Bullet Velocity} = V = 336.46 m/sec
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what would be the period of a satellite in a low orbit around this large, dense planet?
Answers
For the motion of a satellite around a planet: V = square (GM) / R), where G is gravity constant, M is the mass of the planet, and R is the radius of the orbit.
For the duration of a satellite around a planet: T = 2 x pi x (square (r ^ 3 / gm)), where g is gravitational constant, m is the mass of the planet, and radius of the orbit is. In both the cases, R is the distance from the planet's center, not only the height on its surface.
Thus, the orbital period in low orbit turns on only on the density of the central body, regardless of its size.
Yet, for the Earth become the central body (or any other spherically symmetric body with the same average density, about 5,515 kg/m 3.
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An absorption spectrum is:
a) various wavelengths emitted by an excited substance
b) a spectrum containing all wavelengths
c) the range of wavelengths emitted or absorbed by an object
d) the wavelengths that are removed from a continuous spectrum when it passes through a substance
e) a spectrum that contains only a few discrete wavelengths
Answers
so i could choose b
hope that helped<3
g during forced exhalation, such as when blowing up a balloon, the diaphragm and chest muscles create a pressure of 60.0 mm hg between the lungs and chest wall.
Answers
The force in newtons this pressure creates on the 600 cm2 surface area of the diaphragm is 4.802 N.
P =60.0mm×133.3pa/1mm hg = 7998.
= 600/100² = 0.06
= 7998×0.06= 4.802N.
Stress is the force applied perpendicular to the surface of an object in keeping with the unit location over which that force is shipped. Gauge strain is the strain relative to the ambient strain. Numerous gadgets are used for the specific strain. strain is defined to be the quantity of pressure exerted per location.
The pascal (Pa) is the same old unit of stress. A pascal is a very small quantity of stress, so the most beneficial unit for normal gasoline pressures is the kilopascal (kPa). A kilopascal is equal to a thousand pascals. Another usually used unit of pressure is the atmosphere (atm).strain is commonly measured in units of pressure in step with a unit of surface vicinity ( P = F / A). In bodily technological know-how, the image for strain is p and the SI unit for measuring stress is the pascal (image: Pa). One pascal is the pressure of one Newton consistent with a square meter appearing perpendicular on a floor.
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Complete Question:
During forced exhalation, such as when blowing up a balloon, the diaphragm and chest muscles create a pressure of 60.0 mm Hg between the lungs and chest wall. What force in newtons does this pressure create on the 600 cm2 surface area of the diaphragm?
This pressure exerts a 4.802 N force on the 600 cm2 surface area of the diaphragm.
The force delivered perpendicularly to an object's surface in accordance with the unit location across which that force is distributed is known as stress. The strain in relation to the ambient strain is known as gauge strain. There are several tools utilised for the particular strain. The amount of pressure applied to each site is referred to as strain.
The traditional unit of stress is the pascal (Pa). The kilopascal is the ideal measure for regular fuel pressures since a pascal is a relatively modest amount of tension (kPa). One thousand pascals is equivalent to one kilopascal. The atmosphere is another frequently used unit of pressure (atm). Pressure units along with a unit of surface proximity are widely used to quantify strain (P = F / A). In physical technology, the SI unit for measuring stress is the pascal, and the image for strain is p. (image: Pa). The pressure of one Newton equivalent to a square metre appearing perpendicular to the ground is one pascal.
Chest muscles create a pressure of 60.0 mm hg
P =60.0mm×133.3pa/1mm hg = 7998.
= 600/100² = 0.06
= 7998×0.06= 4.802N.
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A young boy of mass 45 kg is standing at rest on a stationary skateboard of mass 2.5 kg. He loses his balance and flies off the skateboard with a velocity of -2.8 m/s. What is the "recoil" velocity of the skateboard?
Answers
A young boy is standing at rest on a stationary skateboard. He loses his balance and flies off the skateboard, then the "recoil" velocity of the skateboard is calculated as 50.40 m/s.
What is recoil velocity?When you fire bullet from gun, then gun experiences a force in the backward direction. Because of this force, gun attains velocity in the backward direction and this velocity is known as recoil velocity.
Given; v1, velocity of boy = -2.8 m/s ands m1, mass of boy = 45 kg and m2, mass of skateboard is 2.5 kg
Let v2 be recoil velocity of skateboard
As, m1u1+m2u2=m1v1+m2v2
u1=0; u2=0( given boy and skateboard at rest initially)
So,0=m1v1+m2v2
Hence, recoil velocity v2= -(m1/m2)v1.
= (- 45/2.5 )* -2.8
= 50.40 m/s
The "recoil" velocity of the skateboard is 50.40 m/s
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If a compass is placed above a current-carrying wire, as in Figure Q24.34. the needle will line up with the field of the wire. Which of the views shows ihe correct orientation of the needle for the noted current direction?
Answers
According to the views shown B and D are the correct orientation of the needle for the noted current direction.
Does an electric field affect compasses?Normally, compasses align themselves parallel to magnetic field lines in response to the Earth's magnetic field. If we produce a magnetic field that is more powerful than the field of the Earth. For instance, a compass needle will align itself parallel to the new field by using electric current. Because a magnetic field is formed in the wire when the circuit is linked, the compass needle responds to electricity by moving.
What occurs when a compass is placed close to an electric current?In its magnetic field, a current-carrying wire acts like a magnet and has an impact on other magnets. When we set a compass close to a current-conducting wire, the needle in the compass will therefore be deflected.
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An example where reaction time wouldn’t matter very much for the results
Answers
When studying the properties of light, for example, reaction time would not matter much. Light moves at such a fast rate that reaction time has no effect on the results of experiments measuring the speed of light, the reflection of light, or any other property related to light.
What is reflection?
Reflection is when a wave, such as a light wave or sound wave, bounces off a surface and returns to the source. This happens when the wave encounters an obstacle such as a wall or other barrier, and the wave is redirected back towards the source. Reflection is one of the fundamental principles of physics, and is used to explain many phenomena such as the fact that light is reflected off of a mirror. Reflection is also used to help explain phenomena such as sound reverberation and the formation of shadows.
What is sound reverberation ?
Sound reverberation is the effect created when a sound is reflected off of surfaces in a room or area. This effect is created when the sound bounces off of walls, ceilings, and other objects, and then is heard again by the listener. This creates an echo-like effect, and can be used to create a more acoustically ‘live’ sound.
Therefore, One example of where reaction time wouldn't matter very much for the results is when studying the properties of light.
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when [s] = 20 km, what percentage (%) of vmax has been reached?
Answers
When s=20km the percentage of vmax reached is 83.33%.
As per the data given in the above question are as bellow,
The data share are as bellow,
The value of s is equal to 20km.
We have to determine the percentage of vmax reached.
We have to use the formula of rate of energy catayzed reaction.
A appropriate catalyst can be added to a reaction to accelerate its pace. A catalyst is a material that speeds up a chemical process without being consumed (remains chemically unchanged at the end). It offers a different, lower-activation-energy reaction route.
Rate of energy calculate reaction is equal to vmax upon km plus s
V=(vmax[s])/(KM+[s])
V=[tex]\frac{vmax\:5Km}{Km+5km}[/tex]
V=[tex]\frac{5vmax\:Km}{6km}[/tex]
Cancelling Km we get,
V=[tex]\frac{5}{6} vmax[/tex]
Percentage of Vmax reached [tex]\frac{\frac{5}{6}vmax }{vmax} \times 100[/tex]
83.33%
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The magnitude of charge A is half the magnitude of charge B. However, the electrostatic force experienced by charge A and by charge B is the same. It can be concluded that the electric field strength of charge A is ________ the electric field strength of charge B. one-fourth one-half two times four times
Answers
Answer:
Qb = 2 Qa magnitude of charge on B is twice that of A
F = K Qa * Qb / R^2 both charges experience the same force
Ea = K Qa / s^2 field strength of A at distance S
Eb = K Qb / s^2 field strength of B at distance S
The electric field strength of B is twice that of A
That means that charge on A is 1/2 that on B for the forces on each to be the same:
Fa = Qa * Eb
Fb = Qb * Ea
How would you describe the volume of the following object? the amount of water in a swimming pool O macroscopic O microscopic O submicroscopic O all of the above O none of the above
Answers
Macroscopic is the right answer. The word "macroscopic" best describes the volume of water in a swimming pool. The "large picture" might be referred to as a macroscopic position.
High energy physics, which studies the physical systems, is another name for particle physics. Low energy physics is the study of physics at larger length scales, such as the macroscopic scale. The macroscopic scale is the length scale when things are large enough to be seen with the eye without the use of optical magnifying devices. The polar opposite of microscopic, it. Pressure, volume, temperature, and other such things are typical instances of macroscopic characteristics. For instance, the only component of the structures of diamond and graphite is carbon.
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5) A 1200 kg racecar starts from rest and has a velocity of 35 m/s over a distance of 100 m. What is
the net force on the racecar?
Answers
F = - 600 N is the net force on the racecar .
What is acceleration ?
Acceleration is a measure of how quickly an object changes its velocity, or the rate at which its velocity changes over time. It is a vector quantity, which means it has both magnitude and direction. In physics, acceleration is usually defined as the change in velocity per unit time, and is expressed in units of meters per second squared (m/s^2). Acceleration can result from a change in speed, direction, or both. Objects that are accelerating are said to be undergoing a net force, and their acceleration is proportional to the magnitude of the force and inversely proportional to their mass.
Rate of change of momentum = net force acting on the object …………
m Vf - m Vi / t = net force acting on the object
m (Vf - Vi / t) = F
1200 ( 0 - 10 /20) = - 600 N = F
so, net force acting on the object =
F = - 600 N
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You hold a shiny tablespoon at arm's length and look at the front side of the spoon. a) is the image you see of yourself upright or inverted? b) is the image enlarge or reduced? c) is the image real or virtual?
Answers
The image formed is inverted. From the ray diagram, the object and image are on same side of the mirror. Thus, the imaged formed is real.
What is Inverted Image?
A section of physics called optics studies how light behaves and interacts with objects. Lenses are curved, transparent structures that are often constructed of glass and are used for focussing or dispersing light.
A convex lens is the opposite of a concave lens. Light rays converge in convex lenses as opposed to concave lenses. The convex lens converges incident rays towards its central axis because, in contrast to the concave lens, it is larger in the middle and thinner at the corners.
The edges of the convex lens are curled outward rather than inward. When the light is intensely focused beyond the focal length of the lens, the image appears smaller and inverted.
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2. what does it mean that the image is inverted when you look through the ocular lenses?
Answers
The light beams that are released through the light source and cross invert the picture that is created by the ocular lenses.
An image that depicts the topic in the opposite way is said to be inverted. In the concave mirrors, the genuine images are reversed. The concave mirror reflects the top edge of the object downward, below the principal axis. In a way similar to this, light rays from the lower edge of the mirror are reflected upward. When light is focused at a point that is farther away than the focal length of the lens, the picture is inverted and diminished. Microscopic objects are amplified and orientated in telescopes and microscopes using compound lenses, which are many lenses with a single focus point.
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a magnet allowed to stand freely , like a compass needle, will point to the north in response to earth's magnetic field unless it's near a strong magnet
Answers
It is true that if a magnet allowed to stand freely , like a compass needle, will point towards north in response to earth's magnetic field unless it's near a strong magnet.
Which direction will the magnet point if it can move freely in a compass?One end of any bar magnet will always point north if it is freely suspended. This is called north-seeking pole of magnet, or simply north pole and the opposite end is called south pole.
All the metals found on Earth (natural & man-made) are magnetic. Earth has huge magnetic field that extends from North & South Poles out into the space.
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This force exerted on you by the is also A. your mas b your wieght c. half you mass d. half your weigth
Answers
This force exerted on you by the earth is also your weight, option B.
What force is the earth's pull on the body?The gravitational pull of the Earth on a body is referred to as the body's weight. Also, weight is the gravitational force between the earth and an object. It is also equal to the product of gravity's acceleration and the object's mass.
The force you exert on the earth in free fall is equal to your weight. The third law of Newton. Forces that are equal and opposite. With your weight, the Earth pulls on you. In other words, an object's weight is determined by the pull of gravity on it.
The complete question is:
This force exerted on you by the earth is also
A. your mass
B. your weight
C. half you mass
D. half your weight
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When the speed of the electrons striking the anode is increased, the BLANK of the emitted X-rays increases.
frequency
density
wavelength
Answers
When the speed of electrons striking the anode increases, then the frequency of the emitted X rays increases.
What happens when the electrons hit the anode?Electrons lose their kinetic energy when they reach the anode surface because they slow down dramatically. Heat or x-rays are created from kinetic energy. Individual atoms of the anode material engage in interactions with the electrons.
As electrons are accelerated from cathode towards the anode, more number of X rays are emitted. As the speed of the electrons increases, thermionic emission increases resulting in more heat and number of X rays being released. frequency of the emitted x-rays increases?
Greater is the number of electrons striking the anode, then larger is the number of X−ray photons emitted.
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If, at a given time, the position of a subatomic particle is precisely known, then the time over which it was measured cannot be precisely known. the particle will disappear. its velocity cannot be precisely known. no other particles can have the same position.
Answers
If, at a given time, the position of a subatomic particle is precisely known its velocity cannot be precisely known.
What is a subatomic particle?
Simply put, a subatomic particle is a particle that is smaller than an atom. Protons, electrons, and neutrons are the three subatomic particles that may typically be separated from an atom.
The uncertainty principle, which was first put forth by German physicist and Nobel laureate Werner Heisenberg in 1927, states that we cannot know both the position and speed of a particle, such as a proton or electron, with absolute precision; the more precisely we can determine the particle's position, the less we know about its speed, and vice versa.
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PLEASE HELP ASAP! 100 Pts!
A force of 50 N acts on an object weighing 25 N for 5 seconds. Find the change in velocity of the object.
Answers
Force = 50N
Weight = Mass × Gravity = 25
Mass = 25 ÷ 10 = 2.5Kg
Time = 5 Seconds
we know
Force = mass × acceleration
50 = 2.5 × Velocity ÷ Time
50÷2.5 = Velocity ÷ 5
Velocity = 250 ÷ 2.5
Velocity = 100m/s.
Answer:
100m/s
Explanation:
force(f) = 50N
weight = 25N
weight = mass × gravity
25 = m × 10
25 = 10m
m = 25/10
m = 2.5kg
time(t) = 5sec
impulse formula
ft = m(∆v)
by substituting
50 × 5 = 2.5∆v
250 = 2.5∆v
∆v = 250/2.5
∆v = 100m/s
i hope this helped
Find the binding energy (in MeV) for lithium 3Li9 (atomic mass = 9.026789 u).
Answers
According to the given statement the binding energy (in MeV) for lithium 8.48 MeV.
What causes binding energy?In particle physics, the term "binding energy" describes the energy an atom receives via electromagnetic interaction as well as the quantity of energy needed to break an atom down into free nucleons.
Using the following formula, the binding energy of 3Li9 (atomic mass = 9.026789 u) may be determined:
B.E. = (Z * m_p + (A - Z) * m_n - m_Li) * c²
where:
Z = number of protons (atomic number) = 3
m_p = mass of proton (1.6726219 × 10⁻²⁷ kg)
m_n = mass of neutron (1.6749286 × 10⁻²⁷ kg)
m_Li = mass of lithium-9 atom (9.026789 × 10⁻²⁷ kg)
c = speed of light (2.998 × 10⁸ m/s)
Plugging in the known values, we get:
B.E. = (3 * 1.6726219 × 10⁻²⁷ kg + (9 - 3) * 1.6749286 × 10⁻²⁷ kg - 9.026789 × 10⁻²⁷ kg) * (2.998 × 10^8 m/s)²
This equals roughly 8.48 MeV.
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With the diagram and the data answer the question:
What is the magnitude of A +B?
DATA:
theta1 =43.7o,
theta2 =144.0o,
A =4.7 cm,
B =8.5 cm.
Answers
With the diagram and the data the magnitude of A +B is 13.2 cm.
What is Magnatitude?
Magnatitude is a measure of the strength of a magnetic field. It is typically expressed in units of tesla (T), which is equivalent to one newton per ampere-meter (N/A-m).Magnatitude is a useful tool for measuring the intensity of magnetic fields in various applications, such as in medical imaging, geophysics, and astrophysics. It can also be used to measure the strength of a permanent magnet.
What is Astrophysics?
Astrophysics is a branch of astronomy that deals with the physical and chemical properties of celestial objects, including stars, planets, galaxies, and the interstellar medium. It also focuses on the study of the origin and evolution of these objects, as well as their interactions with each other and with the surrounding environment. Astrophysics is a multidisciplinary field that draws on the principles and methods of physics, mathematics, and chemistry.
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1. A 1.15-kg block is released from rest on a frictionless inclined plane. The inclined plane forms an angle of 35° with the
ground. The block slides down the inclined plane and compresses a spring at the bottom by 3.5 cm and stops momentarily.
If 334 N are required to compress the spring by 2.4 cm, what distance has the block travelled?
>
Answers
Answer:
Explanation:
We can use the work-energy principle to solve this problem. The work-energy principle states that the work done on an object is equal to the change in kinetic energy of the object.
We can begin by finding the spring constant (k) of the spring. The spring constant is the force required to compress a spring by a certain distance. We can use the information given to us in the problem to find the spring constant:
k = F / x = 334 N / 0.024 m = 13,916.67 N/m
Now we can use the spring constant, the compression distance (3.5 cm) and the mass of the block (1.15 kg) to find the work done on the block as it compresses the spring:
work = 1/2 * k * x^2 = 1/2 * 13,916.67 N/m * (0.035 m)^2 = 97.4 J
Since the block is released from rest, its initial kinetic energy is zero. So, the work done on the block as it compresses the spring is equal to its final kinetic energy.
We know that the block slides down on a frictionless incline, so we need to consider the work done by gravity on the block during its motion. The work done by gravity is given by the equation:
work = force * distance * cos(theta)
where force is the force of gravity acting on the block, distance is the distance the block slides down the incline and theta is the angle of the incline with the ground.
force = m * g , where m = 1.15 kg and g = 9.8 m/s^2
distance = s
theta = 35°
substituting the values
work = (1.15 kg * 9.8 m/s^2) * s * cos(35°)
Now we can add the work done by gravity to the work done by the spring to find the total work done on the block.
work = 97.4 J + (1.15 kg * 9.8 m/s^2) * s * cos(35°) = 97.4 J + (11.37 N) * s * cos(35°)
Now we can solve for s, the distance the block travelled.
s = (97.4 J) / (11.37 N * cos(35°))
The final answer will be in meters.
A block of mass m and speed v collides with a spring, compressing it a distance Δx. What is the compression of the spring if the mass of the block is halved and its speed is doubled?
Answers
√2 times is the compression of the spring if the mass of the block is halved and its speed is doubled.
What is mass?
Mass is a unit used in physics to describe inertia, a fundamental property of all matter. It essentially refers to the resistance a mass of matter provides to a change in its speed or location brought on by the application of a force. The amount of the body's mass determines how much of a change an applied force produces.
What is speed ?
A shift in an object's location, either in direction or speed. How fast something is travelling is determined by how far it has travelled in relation to how long it took. Speed is considered a scalar quantity because it only has a direction and no magnitude.
let the compression in the spring be x
kE of block becomes PE of spring
1/2 * mv^2 = 1/2 * kx^2
x = v√(m/k)
So, if mass is halved and speed is doubled, compression becomes 2*√1/2 = √2 times
Therefore, √2 times is the compression of the spring if the mass of the block is halved and its speed is doubled.
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A square wire loop 13.0 cm on each side carries a clockwise current of 9.00 A Part A Find the magnitude of the magnetic field at its center due to the four 1.60 -mm wire segments at the midpoint of each side Express your answer with the appropriate units. B====
Part B Find the direction of this magnetic field. O into the page O to the left from the wire O out of the page O to the right from the wire
Answers
The explanation of part A and Part B about magnetic field is given below
What is magnetic field?A magnetic field is a force field created by a moving electric charge, such as an electron, or a group of electric charges that interact with each other. Magnetic fields can be invisible or visible, depending on the size and strength of the field. They can be created by permanent magnets, electric currents, or a moving charge in an electric circuit. Magnetic fields are invisible forces that can attract or repel objects, as well as interact with other magnetic fields. The Earth has its own magnetic field, which helps protect us from dangerous solar radiation.
Part A
The magnitude of the magnetic field at the center of the square wire loop due to the four 1.60 mm wire segments at the midpoint of each side is 5.22 x 10-3 T.
Part B
The direction of this magnetic field is out of the page.
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A football is 35.0 m from a goal post. The kicker kicks the ball at 18.7 m/s at a 48.0° angle. The goal post is 3.05 m above the ground.
How many meters will the ball
be short of clearing the goal post?
(Unit = m)
Answers
The ball will be 0.16 meters short of clearing the goal post.
What is vertical and horizontal motion and explanation of an given question?To find out how many meters the ball will be short of clearing the goal post, we need to determine the trajectory of the ball and compare it to the height of the goal post. This can be done by using some basic physics equations, such as the equations of motion for horizontal and vertical motion.First, we can use the initial velocity and the angle of launch to find the horizontal and vertical components of velocity using the following equations:Vx = V0 * cos(theta)Vy = V0 * sin(theta)where V0 is the initial velocity (18.7 m/s), theta is the launch angle (48 degrees), Vx is the horizontal component of velocity, and Vy is the vertical component of velocity.Next, we can use the horizontal and vertical velocities to find the horizontal and vertical distance the ball travels using the following equations:x = Vx * ty = Vy * t - 0.5 * g * t^2Where x and y are the horizontal and vertical distance the ball travels, t is the time of flight and g is the acceleration due to gravity.We can then use the time of flight to find the horizontal and vertical distance the ball travels.Finally, we can compare the height of the goal post (3.05 m) to the vertical distance the ball travels. The difference between these two values is the distance the ball is short of clearing the goal post.After solving the above equations we get the ball is 0.16 meters short of clearing the goal post.To learn more about horizontal motion refer:
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Why does the graph slant upward in the first part but then level out? Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
Answers
The graph slants upward in the first part and then levels out because it is showing the relationship between two variables that are not directly proportional.
What is graph in physics?Graph in physics is a visual representation of a relationship between two or more physical quantities. It is used to show how these physical quantities are related and to make predictions about the physical system being studied. Graphs are an essential tool in physics, as they help to illustrate the relationships between physical variables in a clear and concise way. Graphs can also be used to calculate specific values, such as the speed of an object or the area of a circle.
As the independent variable (on the x-axis) increases, the dependent variable (on the y-axis) increases at a diminishing rate, until the point of saturation is reached and the graph levels out. The relationship between the two variables is referred to as an exponential relationship, where the dependent variable reaches its maximum value as the independent variable approaches infinity.
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A light bulb operating at 110 V draws 1.40 A of current. What is its resistance?
Answers
The value of resistance for given current and potential difference is 78.6 ohm.
The obstruction to current flow in an electrical circuit is measured by resistance. The Greek letter omega () represents the unit of measurement for resistance, known as ohms.
The ratio of the electric current flowing through it to the voltage applied is the definition of electrical resistance for a circuit component or device: Ohm's law, I = V/R, can be used to anticipate the behavior of the material if the resistance remains constant over a wide range of voltage.
V = 110
VI = 1.4 A
The voltage in this case is V, while the current is I.
Write the voltage expression based on Ohm's law, then rearrange the terms to arrive at the resistance expression, R. The value of R can then be calculated by substituting the necessary numbers.
V = I R
R = V / I
R = 110 / 1.40
R = 78.6 ohm
Here, 78.6 ohm is the measured value of resistance. As a result, choice B is accurate.
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which of the following sound frequencies lie(s) in the audible range?
A. 10 Hz
B. 15 Hz
C. 30,000 Hz
D. 15,000 Hz
Answers
D. 15,000 Hz is the frequecy which lies in the audible range i.e. the range at which the sound is audible.
The audible range for humans is the range of sound frequencies that can be heard by the human ear, it varies depending on the age, sex and overall health of the individual. Generally, the range of audible frequencies for most human adults is between 20 Hz and 20,000 Hz. Frequencies below 20 Hz are considered infrasonic and cannot be heard by the human ear, while frequencies above 20,000 Hz are considered ultrasonic and also cannot be heard by the human ear. However, some people, such as young children and some animals, are able to hear a wider range of frequencies. The human ear is most sensitive to frequencies in the range of 1,000 Hz to 4,000 Hz, which is why these frequencies are often used for speech and music. The sensitivity to certain frequency ranges vary between people depending on their age and overall hearing health, for example, as people get older, they tend to lose sensitivity to higher frequencies.
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write an expression using the variables provided for the force applied by the student fs.
Answers
W = F. ds is the equation that results when a force F operates on a particle and the particle is moved by a displacement ds. F. ds. cos is equal to this dot product.
When there is force, there is work. There will always be a force, and that force will always work. The body will move slightly as a result of the imparted force. No force is applied if there is no displacement. Two requirements must be met in order for work to occur: a force must be applied. The force ought to result in some movement. Therefore, the formula for work is: work = product of force magnitude, displacement, and cosine of the angle formed by the vectors of force and displacement.
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what is the q value for the reaction 9be + α → 12c + n
Answers
The Q value for the reaction 9be + α → 12c + n is 4.68 Mev. The amount of energy absorbed or released during a nuclear reaction is known as the Q value for that reaction.
It is a measurement parameter by which we can describe it is exothermic or endothermic. If Q value is -ve then endothermic if +ve then exothermic
[tex]Q_{value}=(m_{r}- m_{p})931 .5~MeV[/tex]
where
[tex]m_{p} = sum ~of ~masses~ of~ products\\\\m_{r}= sum ~of~ masses~ of ~reactants[/tex]
Mass of reactants = Mass of Be + Mass of He
=9.0121+4.0015
= 13.0136 u
Mass of products = Mass of C + Mass of H
= 12+1.0086
=13.0086 u
Q={(13.0136)-(13.0086)(931.5}
Q=4.68 MeV
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