A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade​

Answers

Answer 1

Answer:

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to [tex]316.5[/tex] centimeter cube

Explanation:

Assuming Pressure is constant.

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

where T1 and T2 are temperature in Kelvin

Substituting the give values we get-

[tex]\frac{300}{273} = \frac{V_2}{288}[/tex]

[tex]V_2 = \frac{288*300}{273} \\V_2 = 316.5[/tex]

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to [tex]316.5[/tex] centimeter cube


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How does a cap rock allow humans to access oil and natural gas reserve?

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Cap rocks form the top of reservoirs and create a layer that is impervious to fluid flow By preventing fluids from flowing through it, the fluids are prevented from escaping the reservoir. This applies to oil and gas reservoirs. Oil and gas reservoirs often form in "traps"

What is the diffrence between organic and inorganic compounds?

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What is percent composition by mass?

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Percent composition indicates the relative amounts of each element in a compound. For each element, the mass percent formula is: % mass = (mass of element in 1 mole of the compound) / (molar mass of the compound) x 100% or. mass percent = (mass of solute / mass of solution) x 100%.

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Answer:

Explanation:

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How many mg of metallic ions are in 1.0 mL of 0.10 M LINO3

Answers

Answer:

0.6941 mg

Explanation:

First we calculate how many LiNO₃ moles there are, using the given concentration and volume:

1.0 mL * 0.10 M = 0.10 mmol LiNO₃

As 1 mol of LiNO₃ contains 1 mol of Li, in the problem solution there are 0.10 mmol of Li (the only metallic ion present).

Now we convert Li milimoles into miligrams, using its atomic mass:

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if you are using 657.0 grams of oxygen gas to react with calcium how many gram of calcium oxide will u product

Answers

Answer:

The amount in grams of CaO that will be produced is 2,302.67824 grams

Explanation:

The reaction between calcium and oxygen to produce calcium oxide (quicklime) can be presented as follows;

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From the above chemical equation, we have;

2 moles of calcium, Ca, react with 1 mole of oxygen gas, O₂, to produce 2 moles of CaO

With the assumption that there is an excess amount of Ca, we have;

The molar mass of O₂ = 32 g/mol

The number of moles, 'n', of O₂ in 657.0 grams of oxygen is therefore;

The number of moles of a substance =  Mass of substance/(Molar mass of substance)

∴ n = 657.0 g/(32 g/mol) = 20.53125 moles

The number of moles of O₂ in the 657.0 grams of oxygen present in the reaction, n = 20.53125 moles

1 mole of O₂ produces 2 moles of CaO, therefore, 20.53125 moles of oxygen will produce 2 × 20.53125 or 41.0625 moles of CaO

The molar mass of CaO = 56.0774 g/mol

Therefore, the mass of 41.0625 moles of CaO is given as follows;

Mass of substance = (The number of moles of a substance) × (Molar mass of substance)

The mass of CaO produced = 41.0625 moles × 56.0774 g/mol = 2,302.67824 g.

what element can you substitute to mercury in making battery

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Explanation:

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Answers

Answer:

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Explanation:

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Answer:

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To eliminate the carbon dioxide pollutants, the factory manager should employ unit operations for CO2 capture. One example is through absorption process by using commercial CO2 absorbents like soda lime.

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Telescope would be the correct answer

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Telescope

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i took the test

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Answers

The net ionic equation for the reaction between SnSO₄ and NaOH is:

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Cancel the spectator ions (i.e Na⁺ and SO₄²¯) and write 2 before OH¯ to obtain the net ionic equation.

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Answer:

Explain in terms of atomic structure, why Cesium (Cs) has a LOWER first ionization energy than Rubidium (Rb). Cesium is further down on the periodic table. ... The ion K+1 has one more electron than the atom K. K+1 has lost one electron from its valence shell, and therefore has one less electron shell than K.

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Answer:

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Explanation:

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Answer:

spatula I guess ..........

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Answer:

1. false

2. true

3.true

4.true

Explanation:

Answer:

1. True

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Paul went to his friend's 2 km from his house, he used his bike and took him 9 minutes.
Paul and his friend rode another 1.5 km to get some ice cream, it took them 10 minutes.
What was Paul's average speed of the whole trip?

Answers

The average speed : 3.07 m/s

Further explanation

Given

d1 = 2 km

t1 = 9 min

d2 = 1.5 km

t2 = 10 min

Required

The average speed

Solution

Average speed = total distance : total time

total distance :

= d1+d2

= 2+1.5

=3.5 km

total time :

= t1+t2

= 9 min + 10 min

= 19 min

Average speed :

= 3.5 km : 19 min

= 0.184 km/min

= 3.07 m/s

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