A) fifteen twentieths
B) twelve fifths
C) fifteen fourths
D) eight halves

Answer:

483

Step-by-step explanation:

I really really pray and hope this helpss.

Answer:

X=3(7+23)

Step-by-step explanation:

Answer:

Below

Step-by-step explanation:

According to a website, ebra

Solve for

N

by cross multiplying.

N

=

5

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Solve for s

Isolate the variable by dividing each side by factors that don't contain the variable.

s

=

8

r

−

5

t

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Solve for x

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

x

>

−

6

Interval Notation:

(

−

6

,

∞

)

Tap to view steps...

Solve by Substitution

Move all terms that don't contain

x

to the right side and solve.

x

=

9

2

−

y

2

Tap to view steps...

3/31/2022 4:07 PM

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Find the Function

Find the function by taking the integral of the derivative.

G

(

x

)

=

5

2

x

2

−

x

+

C

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How was this solution?

Tap to rate...

Find the Function

I am unable to solve this problem.

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Find the Function Rule

The chosen topic is not meant for use with this type of problem. Try the examples below.

x

q

(

x

)

1

1

2

2

3

3

4

4

x

q

(

x

)

1

3

2

6

3

11

4

18

x

q

(

x

)

1

2

9

162

2

8

8

128

3

18

Answer:

50.29in

Step-by-step instructions:

First find the semi-circular part:- 1/2×2πr

=1/2×2×22/7×9

=28.29

Find whole perimeter:- 28.29+5+5+12 = 50.29 in

Answer:

20% of 30

= 20/100 * 30

= 6

hence 6 students recieved A grade

Answer:

25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

Answer: 25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

What is it?

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

How do you find IQR?

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Answer:

The answer to this quesion is a measure of statistical dispersion, the spread of data or observations, first you need to get the data find the median calculate the median from both lower and upper half of the data and the iqr is the diffrence between the lower and upper.

Step-by-step explanation:

I Hope This Helps You!

-Justin:)

Answer:

v = 118.333333333

Step-by-step explanation:

formula: V=a^2h/3

The area is the base edge (so 5)

The height is the line going up the triangle (14.2)

Fill in:

v = 5^2(14.2/3)

Solve:

exponent first: 5^2 = 25

v = 25 (14.2/3)

divide/find out fraction: 14.2/3 = 4.73333333333

v = 23 x 4.73333333333

multiply: 23 x 4.73333333333 = 118.333333333

v = 118.333333333

you can also write as v = 118.3 with a line like “-“ over 3 to show the 3 is repeating:)

As per linear equation, there are 372 more girls in school than boys.

"A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form Ax + B = 0. Here, x is a variable, A is a coefficient and B is constant."

Given, there are 1970 pupils.

There are 799 boys in the school.

Therefore, the number of girls in the school is

[tex]= (1970-799)\\= 1171[/tex]

Therefore, the number of girls more than boys in the school is

[tex]= (1171-799)\\= 372[/tex]

In that school , there are 372 more girls than total number of the boys.

Learn more about linear equation here: https://brainly.com/question/11897796

#SPJ2

Answer:

Third option

Step-by-step explanation:

Given the following question:

[tex]7x-4=5x+15[/tex]

To find the answer we need to use inverse of operations to simplify the equation in till we isolate the variable and find the value of x.

[tex]7x-4=5x+15[/tex]
[tex]-4+4=0[/tex]
[tex]15+4=19[/tex]
[tex]7x=5x+19[/tex]
[tex]5x-5x=0[/tex]
[tex]7x-5x=2x[/tex]
[tex]2x=19[/tex]
[tex]2x\div2=x[/tex]
[tex]19\div2=\frac{19}{2}[/tex]
[tex]=\frac{19}{2}[/tex]

Your answer is the third option or "19/2."

Hope this helps.

Answer:

y = x + 9

Step-by-step explanation:

Since each x input can be added by 9 to get the y outputs, the equation is y=x+9
Hope this helps :)

Answer:

App. 83.33 kg

Step-by-step explanation:

10/60=0.167 kg/minute

0.167/3=0.056 kg/minute/person

0.056 x 25 x 60= 83.33...6

The cosine function for the ferris wheel ride is an illustration of a sinusoidial function

The equation of the Ferris wheel is y = -190cos(π / 120 t) + 195

A cosine function is represented as:

y = Acos(Bt - C) + D

From the complete question, the diameter of the ferris wheel is 380 feet.

The amplitude represents the radius, and this is calculated as:

A = 380/2

A = 190

The function becomes:

y = 190cos(Bt - C) + D

The period of the function is:

T = 2π / B

From the complete question, one full rotation is completed in 4 minutes.

Convert the time to seconds

T = 4 * 60

T = 240.

So, we have:

240 = 2π / B

Divide both sides by 2

120 = π / B

Make B the subject

B = π / 120

The function becomes

y = 190cos(π / 120 t - C) + D

From the question, the ferris wheel is 195 feet above the ground.

This represents the vertical shift.

So, we have:

D = 195

The function becomes

y = 190cos(π / 120 t - C) + 195

Also, we have:

The lowest point is at t = 0 and the function is a negative cosine function

So, we have:

C = 0

The function becomes

y = -190cos(π / 120 t) + 195

Hence, the cosine function is y = -190cos(π / 120 t) + 195

Read more about cosine functions at:

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Answer: 0.27

Population density of the species in water:

Population density of a species in the water is given by the expression,

       Density =Given in the question,

Number of goldfish in the tank = 12

Volume of the tank = 45 cubic feet

Substitute these values in the expression,

Density =

            = 0.267

            ≈ 0.27 goldfish per cubic feet

      Therefore, density of the tank will be 0.27 goldfish per cubic feet.

#1

First the rectangle

Area

For semicircle

Area

Total area

#2

Area:-

Answer:

2/5 > 1/4

Step-by-step explanation:

First convert the denominators to the LCM which will be 20

2/5 will convert to 8/20 because 5 x 4 = 20 so 2 x 4 = 8 and 1/4 will convert to 5/20 because 4 x 5 = 20 so 1 x 5 = 5

Answer:

Step-by-step explanation:

Notation for Cereal Set Roster

The roster form is one of the simplest ways to represent the set. The elements of a set are represented in a row and separated by a comma in roster form. For example, the first five positive even numbers are denoted as A = 2, 4, 6, 8, 10.

A = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100 is an example of roster notation: A = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100.

Hope that helps you understand :)

Using the midline property;

[tex]2wy = vz[/tex]

[tex]2(p - 21) = p - 7[/tex]

[tex]2p - 42 = p - 7[/tex]

[tex]2p - p = - 7 + 42[/tex]

[tex]p = 35[/tex]

The values of x in the triangles and the angles in the rhombus are illustrations of tangent ratios

Triangle 1

The value of x is calculated using the following tangent ratio

tan(25) = 10/x

Make x the subject

x = 10/tan(25)

Evaluate

x = 21.4

Triangle 2

The value of x is calculated using the following tangent ratio

tan(x) = 8/5

Evaluate the quotient

tan(x) = 1.6

Take the arc tan of both sides

x = arctan(1.6)

Evaluate

x = 58

Triangle 3

The value of x is calculated using the following tangent ratio

tan(x) = 0.34/0.15

Evaluate the quotient

tan(x) = 2.27

Take the arc tan of both sides

x = arctan(2.27)

Evaluate

x = 66

The lengths of the diagonals are:

L1 = 2 in

L2 = 5 in

Represent the angles with x and y.

The measures of the angles are calculated using the following tangent ratios

tan(0.5x) = 2/5 and y = 90 - x

Evaluate the quotient

tan(0.5x) = 0.4

Take the arc tan of both sides

0.5x = arctan(0.4)

Evaluate

0.5x = 22

Divide by 0.5

x = 44

Recall that:

y = 90 - x

This gives

y = 90 - 44

Evaluate

y = 46

Hence, the angles in the rhombus are 44 and 46 degrees, respectively

Read more about tangent ratio at:

https://brainly.com/question/13347349

The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml

Let y represent the amount of dirt on the floor after x passes.

The floor initially has 550 ml of dirt, hence a = 550.

During each pass, 24% of the dirt is removed. Hence b = 100% - 24% = 76% = 0.76

The equation is given by:

y = 550(0.76)ˣ

After 10 passes:

y = 550(0.76)¹⁰ = 35.36 ml

The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml

Find out more on exponential function at: https://brainly.com/question/12940982

Answer:

[tex]x=\pm\frac{1}{2}[/tex]

Step-by-step explanation:

On a unit circle, [tex](x,y)=(\cos\theta,\sin\theta)[/tex], so [tex]\sin\theta=\frac{\sqrt{3}}{2}[/tex] in this case. If you look at the attached circle, the only time that the y-coordinate is [tex]\frac{\sqrt{3}}{2}[/tex] is when [tex]x=-\frac{1}{2}[/tex] and [tex]x=\frac{1}{2}[/tex], which correspond to angles of [tex]\theta=\frac{2\pi}{3}[/tex] and [tex]\theta=\frac{\pi}{3}[/tex] respectively

Answer: 44 degrees

Step-by-step explanation:

Answer:

2x8=16 so there for y=x^18

Step-by-step explanation:

Answer:

The answer is 15

Step-by-step explanation:

Answer:

4 ways

Step-by-step explanation:

Given

Possible combinations

Answer:

tan ¤ = opp/adj

tan ¤ = 20/50

since opposite of the angle is 20, height of the tree is 20 feet.

Ans : D

Answer:

Explanation:

[tex]\sf tan(x)= \dfrac{opposite}{adjacent}[/tex]

[tex]\hookrightarrow \sf tan(x)= \dfrac{20}{50}[/tex]

Answer:

9.09

Step-by-step explanation:

[tex]\frac{0.81}{0.09} + \frac{0.81}{9}[/tex]

= 9 + [tex]\frac{0.81}{9}[/tex]

= 9+ 0.09

= 9.09

I hope this helped!! If so please rate and mark brainliest <3!!

[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{4}}}\implies \cfrac{6}{3}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{2}(x-\stackrel{x_1}{4})\implies y = 2x-8[/tex]