A falling object with a weight of 15N is moving downwards towards earth at a steady speed. What is the size of the drag force on this object?

Answers

Answer 1

Answer:

15 N :D

Explanation:

Answer 2

The size of the drag force on this object falling at a constant speed is determined as 15 N.

Drag force on the object

The drag force on the object is determined by calculating the net force on the object;

F(net) = W - D

where;

W is weight of the objectD is the drag force of air

ma = W - D

at constant speed, acceleration, a = 0

0 = W - D

W  = D

15 N = D

Thus, the size of the drag force on this object falling at a constant speed is determined as 15 N.

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Related Questions

The main goal of every defense is to __________. A. stop the ball B. regain possession of the ball C. protect the goal or basket D. all of the above

Answers

Answer:

D.

Explanation:

I believe it is D. Because in defense you are to stop others from scoring, while trying to score. But also while trying to protect the Goal or basket. I hope this helps you out.

Answer:

d

Explanation:

PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!

Medicine in Western cultures has not focused on the energy in the body as much as cultures in Asia have.
A.
True

B.
False

PLEASE NO LINKS

Answers

Answer:

A

Explanation:

This is true because culture in Asia focus more on energy that is why we see kung fu and taekwondo etc.

Answer:

A

Explanation:

Got it right.

A toy car travels down a sloping ramp at constant speed. toy car Which statement about
the forces acting on the car is correct?

A There are no forces acting on the car vertically.

B There is no resultant force acting on the car.

C There is no gravitational force acting on the car.

D There is no frictional force acting on the car.

Answers

Answer:

D There is no frictional force acting on the car.

Explanation:

There isnt any friction acting on the car while its going down.

Two towers of height 40 m and 30 m respectively support a transmission line conductor at water crossing. The horizontal distance between the towers is 300 m. If the tension in the conductor is 1590 kg, find the clearance of the conductor at a point mid-way between the supports. Weight of conductor is 0·8 kg/m. Bases of the towers can be considered to be at the water level.

Answers

The sag in the tensioned cable depends on the weight of the cable and

the applied tension.

The clearance midway between the support is approximately 29.34 meters

Reasons:

The given parameters are;

Height of the towers are; h₁ = 40 m and h₂ = 30 m

Horizontal distance between the towers, l = 300 m

The tension in the conductor, T = 1,590 kg

Weight of the conductor, w = 0.8 kg/m

Required:

The clearance space of the conductor mid-way between the support

Solution:

The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;

[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]

Where;

h = h₂ - h₁ = 40 m - 30 m = 10 m

Which gives;

[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]

The sag at the lowest point is give by the formula;

[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]

Therefore;

[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]

The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m

The distance of the midpoint from the lowest point, x, is therefore;

[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]

Which gives;

[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]

The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34

The clearance midway between the support ≈ 29.34 m

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I’m not sure what this is… help please

Answers

Answer:

A) Slower

Explanation:

    Less / low energy means less / slower speed.

Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

What is gibbs free energy.

Answers

Answer:

It’s a

Explanation:

an acorn falls from a tree. ignoring air resistance, what forces are on the acorn while it’s falling?

Answers

Answer: gravity

Explanation:

HELP
How much heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C? The specific heat for water is 4.184 J/g°C. (Include your calculation to receive credit.)

Answers

Answer: 5.05 J

Explanation:

Qcalorimeter: m*c* ΔT  --> (37.5g)*(4.184J/g ° C)*(55.2 °C – 23.0 °C)    Qcalorimeter: 5.05 J

According to specific heat capacity, 5.052 kJ of heat energy is required to raise the temperature of 37.5 g of water from 23.0°C to 55.2°C.

What is specific heat capacity?

Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.

It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.

It is given by the formula ,

Q=mcΔT

Substitution in above formula, givesQ= 37.5×4.184×32.2=5052.18 J or 5.052 kJ.

Thus , 5.052 kJ of  heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C.

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what is cheetah speed and strength?

Answers

Answer:

Speed: 109.4–120.7 km/h (68.0–75.0 mph)

Strength: Couldn't find out.

Explanation:

What feature of a planet's orbit does Kelper's first law of motion describe?
A. the time required for each orbit
B. the shape
C. the distance from the aphelion to the perihelion
D. the distance to the sun

Answers

The answer is going to be letter B

1. A student pushes horizontally on a book with a force of 2 N, which causes the book to slide at a constant velocity. What is the force of friction on the book?

Answers

Answer:

The horizontal forces are equal in size and opposite in direction. They are balanced, so the horizontal resultant force is zero. This means that there is no horizontal acceleration just a horizontal constant speed. If a submarine is not moving horizontally, then there are no horizontal forces.

I hope it helps.

What is the weight of a 68-kg astronaut in outer space traveling with constant velocity?.

Answers

The weight of an astronaut in outer space and traveling with constant velocity is equal to 0 Newton.

Given the following data:

Mass of astronaut = 68 kg

To determine the weight of an astronaut in outer space and traveling with constant velocity:

Mathematically, the weight of an object is calculated by using the following formula;

[tex]Weight = mg[/tex]

Where:

m is the mass of an object.g is the acceleration due to gravity.

At a constant velocity, the value of the astronaut's acceleration is equal to zero meter per seconds square ([tex]0\;m/s^2[/tex]).

Substituting the given parameters into the formula, we have;

[tex]Weight = 68 \times 0[/tex]

Weight = 0 Newton

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Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building?

Answers

Answer:

willie tower

Explanation:

mataas kasi

. Which of the following are forces that push upward on an indoor skydiver? Choose all that apply. *
gravity
acceleration
air resistance
lift


WILL GIVE BRAINLIST

Answers

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

gravity due to its weightdownward force due its acceleration

The upward force on the indoor skydiver include the following;

lift forceair resistance

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

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Reba knows that if she exercises it will help her body, but she is less sure how this will bring positive changes to other aspects of her life. What is the BEST way to explain this connection to Reba?
A.
When you are healthy, everything is automatically better.
B.
Exercise will lead her to meditate, allowing her to improve her mind and body.
C.
She will definitely lose a lot of weight, and thinner people are always happier.
D.
Exercise reduces stress and boosts confidence, which can create positive change.

PLEASE NO LINKS OR I WILL REPORT YOU

Answers

D.

Exercise reduces stress and boosts confidence, which can create positive change.

the answer is D exercise reduces stress and boosts confidence which can create positive change. lmk if this helps

Déterminer la charge de noyau d’atome d’oxygène en coulomb C

Answers

Answer:

determine a large mam I have no idea

What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a pressure of 35 lb/in2 Assume that the distance between each floors is 10ft.

Answers

The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

The given parameters;

Pressure on the 13 th floor, P₁ = 35 PSIDistance between each floor, d = 10 ft

The vertical pressure of the water is calculated as follows;

[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]

The vertical height of the first floor from the 13th floor = 130 ft

The vertical height of the 13 ft floor = 10  ft

[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]

Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

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plz help will mark brainliest ​

Answers

Explanation:

The rod can be in equilibrium only if the resultant force is 0 and the moment around any point of the rod must be equal to 0.

We have to take moments around the pivoted point.

Moment = Force × Perpendicular distance to the force

For the rod to be in equilibrium,

Clockwise moment - Anticlockwise moment = 0

Clockwise moment = Anticlockwise moment

The distance between pivoted point and the weight of rod = 50 cm - 30 cm = 20 cm

So 20 cm× 1.2 N produces a Clockwise moment

If Perpendicular distance between pivoted point and 2N load is x,

Anticlockwise moment = x × 2N

20 cm× 1.2N = 2N × x

x = 12 cm

So 2 N load is at 12 from the pivoted point.

From the left edge of the meter ruler, 2N load is at 30-12 cm distance

= 18 cm

Answer: 18 cm

Explanation:

Heat rising in a hot-air balloon is an example of __________.

Answers

Heat rising in a hot-air balloon is an example of convection.

what causes us to perceive objects in three dimensions?

a. objects in 3-D appear to have width and height, but no depth

b. light bouncing or reflecting off an object in different ways

c. The curvature of space-time relative to objects solar mass

d. The rate of time dilation as we approach objects

Answers

Answer:

Light bouncing or reflecting off an object in different ways.

I just took a quiz and this was the answer

(k12 answer)

Light bouncing or reflecting off an object in different ways causes us to perceive objects in three-dimensions. Thus, the correct option is B.

How do we perceive objects in three dimension?

Binocular fusion permits the perception of a single clear image and it also provides extra cues for the depth perception. That is, the binocular disparity between the two images is used by the nervous system of an individual to allow the perception of a three-dimensional world where the approximate distance of an object can be determined.

The depth perception is the ability to perceive the distance to objects using the visual system and visual perception.

Therefore, the correct option is B.


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Agatha the snake is 50 centimeters long.3 years from now she will be 152 centimeters long and fully grown. If Agatha grows at constant rate, how much does she grow in length each year​

Answers

Answer:  34cm each year

Explanation:

differential rotation is when a planet's equator and polar regions rotate at different rates. True False

Answers

the answer to that is false

Please help me on this 1 assignment im giving 25 points GOOD LUCK!

Answers

Answer:

Explanation:

im sorry if this doesn't help but i think  its A

4. symbol for the gravitational force ?

Answers

Answer: G

Explanation:

One g is the force per unit mass due to gravity at the Earth's surface and is the standard gravity (symbol: gn), defined as 9.80665 metres per second squared, or equivalently 9.80665 newtons of force per kilogram of mass.

Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________

Answers

Answer:

100 m/s

Explanation:

Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.

A potted plant falls from the window of an apartment building. It falls for 2.0
s and then hits the ground. What is the speed of the plant just before it hits
the ground? Assume only gravity is acting on it.
A)20 m/s
B) 9.8 m/s
C) 2.0 m/s
D) 4.9 m/s

Answers

Answer:

D) 4.9 m/s

Explanation:

Speed of Object in Free Fall

s = Rate of Acceleration, Due to Gravity × Length of Time

s = 9.8 × 2.0

s = m/s (Round Up to The Nearest Whole Number)

--

m/s = 9.8 ÷ 2.0 = 4.9 m/s

A ball is thrown from ground level at an angle of 0 and the initial velocity components are 7.5m/s and 13m/s. Ignoring air resistance, calculate each of:

1- The initial velocity is vi

2- The value of the angle at which the ball was thrown

3 - The horizontal range of the ball R​

Answers

I assume you mean an angle of θ, and not 0. I also assume the given components of the initial velocity are horizontal and vertical, respectively, so that

1. the initial velocity vector is

[tex]\boxed{\vec v_i = (7.5\,\vec\imath + 13\,\vec\jmath) \dfrac{\rm m}{\rm s}}[/tex]

which means the ball is thrown with an initial speed of

√((7.5 m/s)² + (13 m/s)²) ≈ 15 m/s,

and

2. the angle made by [tex]\vec v_i[/tex] with the positive horizontal axis is θ such that

[tex]\tan(\theta) = \dfrac{13}{7.5} \implies \theta \approx \arctan(1.7) \approx \boxed{60^\circ}[/tex]

3. At time t, the ball attains a height y and horizontal range x according to

y = (13 m/s) t - g/2 t²

x = (7.5 m/s) t

where g = 9.8 m/s². When the ball reaches the ground (y = 0) for t > 0, we have

(13 m/s) t - g/2 t² = 0

13 m/s - g/2 t = 0

t = 2 (13 m/s)/g = (26 m/s)/g

Plugging this time into the x equation gives a horizontal range of

x = (7.5 m/s) (26 m/s)/g ≈ 20. m

How do energy transformations occur in a hydroelectric plant?


The potential energy of water is converted to mechanical energy by a turbine.


The kinetic energy of water is converted by a dam into potential energy.


The kinetic energy of water is converted by a generator into electric energy.


The potential energy of water is converted by a transformer into electric energy.

Answers

Answer:

The answer is #3: The kinetic energy of water is converted by a generator into electric energy.

Explanation:

Hydropower plants capture the energy of falling water to generate electricity. A turbine converts the kinetic energy of falling water into mechanical energy. Then a generator converts the mechanical energy from the turbine into electrical energy.

Which is larger, the sun's pull on earth or earth's pull on the sun?.

Answers

Answer:

the suns pull

Explanation:

The Sun's pull on Earth is twice as large as Earth's pull on the much larger Sun.

a girl on a bridge throws a rock straight down at -12.5 m/s. it hits the ground 38.4 m below. How much time did it take?

Answers

The acceleration of both the rocks is only due to the gravitational force acting on them. Even though the speed of thrown rock would be greater than that of dropped rock, the acceleration of both the rocks would be g downwards.

Answer:

1.80

Explanation:

38.4=-12.5(a)-1/2(-9.80)(a)^2

a= acceleration
^2 is the exponent

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