It takes 2.04 seconds for the object to accelerate from -10.0 m/s to -30.0 m/s.
Velocity is a measure of an object's speed in a specific direction. It is calculated by dividing the distance traveled by the time taken and specifying the direction of the motion.
We can use the following formula to find the time taken for an object to change velocity under constant acceleration:
Δv = a × Δt
where Δv is the change in velocity, a is the acceleration, and Δt is the time taken.
In this case, the initial velocity is -10.0 m/s, and the final velocity is -30.0 m/s. So, the change in velocity is:
Δv = (-30.0 m/s) - (-10.0 m/s) = -20.0 m/s
The acceleration of the falling object is -9.80 m/s² (negative because the object is falling downward).
Now, we can rearrange the formula to solve for Δt:
Δt = Δv / a
Substituting the values we have:
Δt = (-20.0 m/s) / (-9.80 m/s²) = 2.04 seconds
Therefore, The object accelerates from -10.0 m/s to -30.0 m/s in 2.04 seconds.
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What information do you need to collect in order to study an object’s motion?
The information we will need to demonstrate that an object is in motion include;
initial position of the objectfinal position of the objecttime difference between the initial and final position of the objectWhat is an object in motion?An object is in motion when it changes its position with time, relative to a stationary object.
Mathematically, we can use the following equation to demonstrate the motion of an object.
v = Δx / Δt
where;
Δx is the change in the position of the objectΔt is the change in time of motion of the objectSo the data we will need to demonstrate that an object is in motion include;
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how is work and energy inter-related?? (in simple words)
Answer:
The work and energy is inter- related because if we are energetic then only we are able to work.
People who are weak and not energetic cannot work continuously.
Explanation:
hope this helps you....
a girl whose mass is 40kg walk up a flight of 20steps each 15mm hight in 10seconds.find power developed by the girl showing the solution
Answer: Approximately 11.76 joules per second
=========================================================
Work Shown:
Mass = 40 kg
Force pulling down = (mass)*(gravity) = 40*9.8 = 392 newtons
Roughly 392 newtons of force are pulling down on her.
To climb the steps, she must apply 392 newtons of force upward.
---------------
Displacement = 20*(15 mm) = 300 mm = 0.3 m
Work = Force*Displacement
Work = 392*0.3
Work = 117.6 joules of energy
---------------
Power = (Work)/(Time)
Power = (117.6 joules)/(10 seconds)
Power = (117.6/10) joules per second
Power = 11.76 joules per second, which is approximate
I love you
Please answer my question :-)
Answer:
A- Astronomical body
C- Galaxy
D- Comet
B- Moon
Hope this helps you! Have a great day!
Answer:
1. A
2. C
3. D
4. B
Explanation:
If a shopping cart is pushed by a person exerting 50 J of work on it, what is the energy transfer to the shopping cart if it has a mass of 2 kg?
A. 52 J
B. 50 J
C. 25 J
Answer:
B
Explanation:
f body with a mass of 6kg. (Ans: When we throw a stone with 12 N force to produce an acceleration of m/s², what is the mass of 6 kg? (Ans: 1.5kg) Calculate the acceleration produced when a force of 48 N is What They m
a. When the force = 12 N, mass = 6 kg, the acceleration is a = 2 m/s²
b. When the force = 48 N, mass = 6 kg, the acceleration is a = 8 m/s².
What is the acceleration of the body?The acceleration of the body is calculated by applying Newton's second law of motion as follows;
F = ma
where;
F is the force applied to the objectm is the mass of the objecta is the acceleration of the objecta = F / m
when the force = 12 N, mass = 6 kg, the acceleration is calculated as;
a = 12 N / 6 kg
a = 2 m/s²
when the force = 48 N, mass = 6 kg, the acceleration is calculated as;
a = 48 N / 6 kg
a = 8 m/s²
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A transformer used on a 220V line deliver 1.5A at 1800V. what current is drawn from the line assuming the ideal Transformers
The current drawn from the line, assuming an ideal transformer, is approximately 12.27A.
In an ideal transformer, the power remains the same before and after transformation. Therefore, we can use the power equation to determine the current drawn from the line.
The power equation for a transformer is given by:
P1 = P2
where P1 is the input power, P2 is the output power.
Given that the input voltage (V1) is 220V, the input current (I1) is unknown, the output voltage (V2) is 1800V, and the output current (I2) is 1.5A, we can rewrite the equation as:
V1 * I1 = V2 * I2
Substituting the known values:
220V * I1 = 1800V * 1.5A
Simplifying:
I1 = (1800V * 1.5A) / 220V
I1 ≈ 12.27A
Therefore, the current drawn from the line, assuming an ideal transformer, is approximately 12.27A.
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Two students on ice skates stand one behind the other. Student 2 pushes student 1 in the back; student 1 has less mass than student 2; student 1 has a great acceleration than student 2. which law of motion is this (Newton's laws)
Answer:
law in acting
Explanation:
Which of the following helps prevent and cope with heat-related conditions?
Drinking water
Wear proper clothing
Rest frequently
all of the above
An action which would help in preventing and coping with heat-related conditions is: A. Drinking water.
What is heat?Heat can be defined as a form of energy that is transferred from a physical object (body) to another, as a result of a difference in temperature. Also, heat is a condition of weather that is generally characterized by a high degree of temperature.
This ultimately implies that, heat is most likely to cause dehydration and high body temperature.
In order to prevent and cope with heat-related conditions, you should ensure that you drink water at regular intervals for hydration.
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during SHM an object has_____________at mean position
(a)P.E=0,K.E=0
(b)P.E=K.E
(c)P.E=MAX,K.E=0
(d)P.E=0,K.E=MAX
During Simple Harmonic Motion (SHM), an object at the mean position has potential energy (P.E)=0 and kinetic energy (K.E)=MAX. So, the correct option is (d).
In Simple Harmonic Motion (SHM), an object oscillates about a mean position, with the motion characterized by a restoring force proportional to its displacement from the mean position.
When the object is at the mean position, it has maximum kinetic energy (K.E) because it is at its maximum velocity, and it has zero potential energy (P.E) since it is not displaced from the equilibrium position.
As the object moves further from the mean position, its P.E increases, and K.E decreases. The correct answer to the question is option (d), where P.E=0 and K.E=MAX at the mean position.
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Work is a measurement of the transfer of which of the following?
A. Impulse
B. Power
C. Energy
Answer:Enegry
Explanation:Energy transfer is used to do work
A steel cylinder of length 10 cm, mass 160 g and density 8 g/em. The radius of the cylinder is
Answer:
0.8cm
Explanation:
Volume = mass/density = 160/8 = 20cm³
Volume = πr²h
r² = v/πh = 20/10π =0.64
r = √0.64 = 0.8
The "seeing" ability, or resolution, of radiation is determined by its wave length
The mass of an electrons is 9.10939 * 10^-31 kg and Planck's constant is 6.62607 * 10^-34 Js
If the size of an atom is an the order of 0.08 nm, how fast must an electron travel to have a wavelength small enough to "see" an atom? Answer in the units of m/s
can you ans please ?????????????????????????????????????????
Answer:
ans a
Explanation:
as the circuit should not be completed until switch is closed
One species of eucalyptus tree, Eucalyptus regnans, grow to heights similar to those attained by California redwoods. Suppose a bird sitting on top of one specimen of eucalyptus tree drops a nut that is 1.7 ounces. If the speed of the falling nut at the moment it is 50.3 m above the ground is 42.7 m/s, how tall is the tree
Answer:
The tree is 143.325 meters tall
Explanation:
The given parameters of the eucalyptus tree are;
The mass of the eucalyptus tree nut = 1.7 ounces
The speed of the nut at 50.3 m above the ground, v = 42.7 m/s
The equation for free fall is given as follows;
v² = 2·g·h
Where;
v = The velocity after falling through a height, h
g = The acceleration due to gravity = 9.8 m/s²
h = The height through which the seed has already fallen
Therefore, we have;
h = v²/(2·g) = (42.7 m/s)²/(2 × 9.8 m/s²) = 93.025 m
The height through which the seed has already fallen, h = 93.025 m
The height of the tree = h + The height of the seed above ground at the moment it was falling at 42.7 m/s
The height of the tree = 93.025 m + 50.3 m = 143.325 m
The height of the tree = 143.325 m.
The height of the eucalyptus tree is approximately 111.9 meters.
To determine the height of the tree, we can use the equations of motion. The initial velocity of the nut, u, is 0 m/s (since it is dropped), the acceleration due to gravity, a, is approximately 9.8 m/s², and the final velocity, v, is 42.7 m/s. We need to find the height, h. Using the equation v² = u² + 2a(h - u), we can rearrange it to solve for h: h = (v² - u²) / (2a) Plugging in the values, we get: h = (42.7² - 0²) / (2 * 9.8) = 111.9 meters Therefore, the height of the eucalyptus tree is approximately 111.9 meters.
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two small identical conducting spheres have charges of 2.0x10-9C and - 0.5x109 C respectively when they are placed 4cm apart, what is the force between them? If they are brought into contact and then separated by 4cm, what is the force between them?
Answer:
6
Explanation:
nothingnsbejejjdbsbzbawkje
The low-frequency speaker of a stereo set has a surface area of and produces 1W of acoustical power. What is the intensity at the speaker
Answer:
I = [tex]\frac{1}{4\pi \ r^2}[/tex]
we see the intensity decreases with the inverse of the distance squared
Explanation:
Intensity is defined as power per unit area,
I = P / A
in this case we have that the sound is emitted in a spherical form therefore the area is
A = 4 pi r2
therefore the intensity is
I = [tex]\frac{1}{4\pi \ r^2}[/tex]
as we see the intensity decreases with the inverse of the distance squared
A 0.15 kg baseball is traveling at 40 meters per second (about 90 miles per hour) if the ball comes to a complete stop when it hits the catchers mitt, what is the change in velocity?
Answer:
Please find attached pdf
Explanation:
Semiconductors can simplistically be thought of as an intermediate state between insulators and conductors. In a semiconductor, charges are normally bound in place (like in an insulator), but when injected with enough energy, the charges can move freely (like in a conductor). Given what we have observed about the behavior of conductors and insulators in this exploration, what would happen if we replaced the glass rod with a semiconductor material
Answer:
The semiconductor rod will conduct electricity
Explanation:
Glass rod does not conduct electricity. Glass is one of the best insulators of electricity. But when a glass rod is replace with a semi conductor, then the semi conductor rod starts conducting electricity as the electrons are free to move.
Semi conductors are special materials in which the energy band lies in between the conductor and the non conductor. The conductivity of a semi conductor increases with the increasing temperature.
In an semi conductor the electrons are free to move and as they starts moving they conduct electricity. Thus a semi conductor rod replacing a glass rod conducts electricity.
Stacy collected the data shown in the table.
Number of Washers Total Mass Total Force
0.6 kg 5.9 N
2
1.2 kg 11.8 N
3
1.8 kg 17.6N
4
2.5 kg 24.5 N
5
3.2 kg 31.4 N
What's the general relationship between mass and gravitational force?
Answer:
1.8 Kg 17.6N
Explanation:
I don't know the explanation hahaha
Answer:
The gravitational force on an object increases as the object’s mass increases.
Explanation:
This is the answer on Edmentum. :)
You will need to know that Force (N) is equal to mass (kg) multiplied by acceleration (m/s2) for this problem. A fearless space explorer has discovered a new planet with a frictionless surface! He pushes a large crate with a mass of 220kg a distance of 5.3 km, as he does so, it accelerates at a rate of 2m/s2. How much work has our intrepid hero done?
Our intrepid hero has done 2332 kJ of work pushing the crate on the frictionless surface of the newly discovered planet.
The work done by the space traveler can be determined utilizing the recipe W = F x d, where W is work, F is power, and d is distance. To find the power, we can utilize the recipe F = m x a, where m is mass and an is speed increase. Connecting the given qualities, we get F = 220 kg x 2 m/s^2 = 440 N.
Presently we can compute the work done by increasing the power by the distance: W = 440 N x 5.3 km = 2332 kJ. Accordingly, our fearless legend has done 2332 kJ of work pushing the container on the frictionless surface of the newfound planet.
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A flower as an object in front of a convex mirror. A smaller upright flower closer to the mirror. A smaller upright flower close to the mirror on the other side of the mirror. An inverted smaller flower on the on the other side of the mirror just past the focal point. An inverted flower the same size as the object right below it.
Which flower would most likely represent the image formed by the mirror? Justify your answer.
Answer:
There are 13 a
Explanation:
That's the answer how many a r there
Answer:
the convex mirror will produce image 3. the image is virtual and is now behind the mirror and it becomes smaller but remains upright.
Explanation:
30 A student blows air through a liquid using a straw. This causes the liquid to evaporate quickly and therefore to cool. Which statement explains why the remaining liquid cools?
A Slower-moving molecules are carried away by the air bubbles. B The air molecules conduct heat from the liquid. C The air sets up convection currents in the liquid. D The molecules with most energy leave the liquid.
The correct statement is B that explains why the remaining liquid cools when a pupil blows air through it using a straw .
The air molecules conduct heat from the liquid. When air is blown through a liquid, the moving air motes come into contact with the liquid motes and transfer some of their kinetic energy to them.
This transfer of energy results in the liquid motes gaining kinetic energy, which in turn causes the liquid to dematerialize snappily, leading to cooling.
Also, the air molecules also carry away some of the heat from the liquid's face, performing in farther cooling. This process is called convection and involves the movement of liquid due to the temperature differences created by the blown air.
Thus, Option B, which states that the air motes conduct heat from the liquid, is the most accurate explanation for why the remaining liquid cools.
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A Van de Graaff generator is one of the original particle accelerators and can be used to accelerate charged particles like protons or electrons. You may have seen it used to make human hair stand on end or produce large sparks. One application of the Van de Graaff generator is to create x-rays by bombarding a hard metal target with the beam. Consider a beam of protons at 1.10 keV and a current of 4.65 mA produced by the generator.
(a) What is the speed of the protons?
(b) How many protons are produced each second?
Solution :
Given that :
The energy of the protons, K.E. = 1.10 keV
[tex]$= 1.10 \times 10^3 \ eV $[/tex]
The current produced by the generator is I = 5 mA
[tex]$= 5 \times 10^{-3} \ A$[/tex]
Now [tex]$1 \ eV = 1.6 \times 10^{-19 }\ J$[/tex]
Mass of the proton, m = [tex]$1.67 \times 10^_{-27} $[/tex] kg
Charge of the proton, [tex]$q_p = 1.6 \times 10^{-19} \ C$[/tex]
a). Therefore using the formula for K.E. we can find out the velocity of the proton.
[tex]$K.E. =\frac{1}{2}mv^2$[/tex]
[tex]$v=\sqrt{\frac{2K.E.}{m}}$[/tex]
[tex]$v=\sqrt{\frac{2\times 10^3 \times 1.6 \times 10^{-19}}{1.67 \times 10^{-27}}}$[/tex]
[tex]$= 4.38 \times 10^5 \ m/s$[/tex]
b). We know that the current is :
[tex]$I=\frac{\Delta Q}{\Delta t}$[/tex]
Therefore, the total charge in one second is given by :
[tex]$\Delta Q = I \times \Delta t$[/tex]
[tex]$= 5 \times 10^{-3} \times 1$[/tex]
[tex]$= 5 \times 10^{-3}\ C$[/tex]
So, the number of protons in this charge is given by :
[tex]$n = \frac{\Delta Q}{q_p}$[/tex]
[tex]$=\frac{5 \times 10^{-3} }{1.6 \times 10^{-19}}$[/tex]
[tex]$= 3.13 \times 10^{16}$[/tex] protons
A motorcyclist is making an electric vest that, when connected to the motorcycle's 12 V battery, will warm her on cold rides. She is using 0.25-mm-diameter copper wire, and she wants a current of 4.2 A in the wire. Part A What length wire must she use
Answer:
L = 8.35 m
Explanation:
The lenght of a wire L can be calculated using the following expression:
L = R A/ρ (1)
Where:
R: resistance of the wire
A: Cross section area of the wire
ρ: resistivity of the copper wire.
With this expression we realize that we do not have the area of the cross section, and the resistance of the wire either.
To calculate the area we can use the following expression:
A = πr² (2)
If the diameter is 0.25 mm, then the radius is half, 0.125 mm. Converting this in meter it will have to be:
0.125 /1000 = 0.000125 m
Replacing we have:
A = π(0.000125)²
A = 4.91x10⁻⁸ m²
The reported resistivity of a copper wire is 1.68x10⁻⁸ Ω.m, so we just need to determine the resistance, which can be found using Ohm's law:
R = V/I (3)
Replacing (3) into (1) we have:
L = (V * A) / (I * ρ) (4)
So finally, the length of the copper wire will be:
L = (12 * 4.91x10⁻⁸) / (4.2 * 1.68x10⁻⁸)
L = 8.35 mHope this helps
What was the average speed in km/h of a car that travels 788 km in 7.1 h?
Answer:
Well the answer is 111 (rounded) km/h
Explanation:
788/7.1 is 110.9... so if you round it it would equal 111.
The blood pressure at your heart is approximately 100 mm Hg. As blood is pumped from the left ventricle of your heart, it flows through the aorta, a single large vessel with a diameter of about 2.5 cm. The speed of blood flow in the aorta is about 60 cm/s. Any change in pressure as blood flows in the aorta is due to the change in height: the vessel is large enough that viscous drag is not a major factor into successively smaller and smaller blood vessels until it reaches the capillaries. Blood flows in the capillaries at the much lower speed of approximately 0.7 mm/s. The diameter of capillaries and other small blood vessels is so small that viscous drag is a major factor..Because the flow speed in your capillaries is much less than in the aorta, the total cross-section area of the capillaries considered together must be much larger than that of the aorta. Given the flow speeds noted, the total area of the capillaries considered together is equivalent to the cross-section area of a single vessel of approximately what diameter?
a. 25 cm
b. 50 cm
c. 75 cm
d. 100 cm
Answer:
The correct option is c. 75 for this question
Explanation:
The correct option is c. 75 for this question:
Let's see how.
Continuity Equation is given as:
AcVc = AaVa
Where,
Aa = Area of Aorta
Ac = Area of the capillary
Va = Fluid speed in Aorta
Vc = Fluid speed in Capillary
So,
Assuming the fluid is the ideal one/
[tex]\pi[/tex]/4 [tex]Dc^{2}[/tex] Vc= [tex]\pi[/tex]/4 [tex]Da^{2}[/tex] Va
[tex]Dc^{2}[/tex] Vc= [tex]Da^{2}[/tex] Va
Dc = Da x [tex]\sqrt{\frac{Va}{Vc} }[/tex]
Dc = 2.5 cm x [tex]\sqrt{\frac{60 cm}{0.07 cm } }[/tex]
Dc = 73.192 cm
Dc = 75 approximately
Hence, the diameter of the capillary = 75 cm approximately
What is the equivalent resistance of this network?
The equivalent resistance of the circuit network is determined as 1.6 ohms.
What is the equivalent resistance of the network?The equivalent resistance of the circuit network is calculated as follows;
To determine the equivalent resistance of the circuit, we will decompose the circuit into series and parallel components.
The equivalent resistance at J₄ is calculated as follows;
The two 4 ohms are in series;
J₄ = 4Ω + 4 Ω = 8 Ω
The equivalent resistance at J₁ is calculated as follows;
The 4 ohms and 0 ohm are in series;
J₁ = 0 Ω + 4 Ω = 4 Ω
The equivalent resistance at J₂ and J₃ is calculated by applying the formula for parallel resistors;
1/Re = 1/J₁ + 1/J₄ + 1/J₂,₃
1/Re = 1/4 + 1/8 + 1/4
1/Re = 5/8
Re = 8/5
Re = 1.6 ohms
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Plzz answer correctly
How does altitude from the surface of earth affect the time period of a simple pendulum
Answer:
because the strength of Earth's gravitational field is not uniform everywhere, a given pendulum swings faster, and thus has a shorter period, at low altitudes and at Earth's poles than it does at high altitudes and at the Equator.