A coordinate plane with a line passing through the points (0, negative 1, 0) and (4, 0).
What is the equation of the graphed line written in standard form?

x – 4y = 4
x + 4y = 4
y = y equals StartFraction one-fourth EndFraction x minus 1.x – 1
y = –y equals negative StartFraction one-fourth EndFraction x minus 1.x – 1

Answers

Answer 1

Answer:

x-4y=4

Step-by-step explanation:

The equation of a straight line is in slope intercept form:

y = mx + b;

where y and x are variables, m is the slope of the line and b is the y intercept.

The standard form of a line is:

Ax + By = C

where A, B and C are constants, x and y are variables

The equation of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is given by:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\[/tex]

Given that a line passes through the points (0, -1) and (4, 0), the equation of the line is given by:

[tex]y-(-1)=\frac{0-(-1)}{4-0} (x-0)\\\\y+1=\frac{1}{4} x\\\\y=\frac{1}{4} x-1\\\\4y=x-4\\\\x-4y=4[/tex]

Answer 2

Answer:

Step-by-step explanation:


Related Questions

Can someone just check my answers please? Please let me know which questions are wrong. Thank you for your time.

Answers

Well done
All of these are correct

Given the following formula, solve for r.

Answers

It’s c, a and d just don’t make any sense at all

In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-shaped and has a mean of 47 and a standard deviation of 3. Using the empirical rule, what is the approximate percentage of daily phone calls numbering between 41 and 53? Do not enter the percent symbol.

Answers

Prob ( 41 = X = 77) =

Prob ( (41-59)/9 = Z = (77-59)/9 ) = --- changes to z scores

Prob ( -18/9 = Z = 18/9 ) =

Prob ( -2 = Z = 2) =

Prob ( z=2) - Prob(Z=-2) = by property of the normal bell curve

= 0.9772 - 0.0228 per the normal distribution table

= 0.9544

1. Nikita invests 6,000 for two years at a certain rate of interest compounded annually. At the end of first year it amounts to ? 6,720

plzzzz tell me​

Answers

Answer:

Hope it is helpful and useful

The heights (in inches) of a sample of eight mother/daughter pairs of subjects were measured. Using a spreadsheet with the paired mother/daughter heights, the linear correlation coefficient is found to be 0.693. Find the critical value, assuming a 0.05 significance level. Is there sufficient evidence to support the claim that there is a linear correlation between the heights of mothers and the heights of their daughters?
A. Critical value = ± 0.666; there is not sufficient evidence to support the claim of a linear correlation between heights of mothers and heights of their daughters.
B. Critical value = ± 0.707; there is sufficient evidence to support the claim of a linear correlation between heights of mothers and heights of their daughters.
C. Critical value =± 0.666; there is sufficient evidence to support the claim of a linear correlation between heights of mothers and heights of their daughters.
D. Critical value =± 0.707; there is not sufficient evidence to support the claim of a linear correlation between heights of mothers and heights of their daughters.

Answers

Answer:

D. Critical value =± 0.707; there is not sufficient evidence to support the claim of a linear correlation between heights of mothers and heights of their daughters.

Step-by-step explanation:

Given that :

Correlation Coefficient, r = 0.693

The sample size, n = 8

The degree of freedom used for linear correlation :

df = n - 2

df = 8 - 2 = 6

Using a critical value calculator for correlation Coefficient at α = 0.05

The critical value obtained is : 0.707

The test statistic :

T = r / √(1 - r²) / (n - 2)

T = 0.693 / √(1 - 0.693²) / (8 - 2)

T = 0.693 / 0.2943215

T = 2.354

Since ;

Test statistic < Critical value ; we fail to reject the null and conclude that there is not sufficient evidence to support the claim of a linear correlation between heights of mothers and heights of their daughters.

according to byu idaho enrollment statisct there are 1200 femaile studnet here on campus during any given semester of those 3500 have serced a msion what is the probability that a radnoly selcted femal studne ton cmapus wil have served a mission g

Answers

Answer:

0.2917 = 29.17% probability that a randomly selected female student on campus will have served a mission.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

1200 female students, out of them, 350 have served a mission. So

[tex]p = \frac{350}{1200} = 0.2917[/tex]

0.2917 = 29.17% probability that a randomly selected female student on campus will have served a mission.

If x=3 y=5 h=9 wat is xy+h​

Answers

Answer:

24

Step-by-step explanation:

3x5=15

15+9=24

what is the value of -2x²y³ when ×=2 and y=4?​

Answers

Answer:

1024

Step-by-step explanation:

Given :-

x = 2 y = 4

Value of -2x²y³

2x³ y³2 * (2)³ * (4)³2 * 8 * 64 1024

Answer:

254

Step-by-step explanation:

^ <- this is the square sign

-2x^y^3

x=2

y=4

put x values in to x place and y value in to y place.

-2(2)^2(4)^3

Find the squares and - it with 2

-2(4)(64)

2-256=254

:. the value of -2x^2y^3 =254

That the answer.

Hope this is what you asked.

Help please!!!!!!!!!!!

Answers

Answer:

y = 14

Step-by-step explanation:

[tex] \frac{15}{21} = \frac{5}{7} [/tex]

[tex] \frac{10}{x} = \frac{5}{7} [/tex]

[tex]x = 14[/tex]

Now,

10/15 = y/21

15y = 10*21

y = 210/15

y = 14

This is a Right answer...

I hope you understand..

Mark me as brainliest...

Given: CD is an altitude of triangle ABC.
Prove: a^2 = b^2 +c^2 = 2bccos A

Answers

Answer:

Step-by-step explanation:

                          Statements                                 Reasons

1). CD is an altitude of ΔABC                1). Given

2). ΔACD and ΔBCD are right              2). Definition of right triangles.

    triangles.

3). a² = (c - x)² + h²                                 3). Pythagoras theorem

4). a² = c² + x² - 2cx + h²                       4). Square the binomial.

5). b² = x² + h²                                       5). Pythagoras theorem.

6). cos(x) = [tex]\frac{x}{a}[/tex]                                           6). definition of cosine ratio for an angle

7). bcos(A) = x                                        7). Multiplication property of equality.

8). a² = c² - 2c(bcosA) + b²                    8). Substitution property

9). a² = b² + c² - 2bc(cosA)                    9). Commutative properties of

                                                                    addition and multiplication.

Find the factors of function f, and use them to complete this statement. f(x)=2x^(4)-x^(3)-18x^(2)+9x
From left to right, function f has zeros at

Answers

Hello,

[tex]f(x)=2x^4-x^3-18x+9x\\\\=x(2x^3-x^2-18x+9)\\\\=x(x^2(2x-1)-9(2x-1))\\\\=x(2x-1)(x^2-9)\\=x(2x-1)(x-3)(x+3)\\[/tex]

Zeros are : 0;  1/2; -3; 3.

The zeros of the function are -3, 0, 1/2 and 3.

The given function is [tex]f(x)=2x^{4} -x^{3} -18x^{2} +9x[/tex].

What are the zeros of a function?

Zeros of a function are the points where the graph of the function meets the X-axis i.e., at the solutions of f(x) = 0.

Now, factorise the given function, that is f(x)=x(2x³-x²-18x+9).

=x[x²(2x-1)-9x(2x-1)]

=x(2x-1)(x²-9)

=x(2x-1)(x+3)(x-3)

= -3, 0, 1/2, 3

Therefore, the zeros of the function are -3, 0, 1/2 and 3.

To learn more about the zeros of the function visit:

https://brainly.com/question/16633170.

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If you spin two times, what is the probability of landing on
green both times? (leave answer in fraction form in lowest
terms)
Red
Green
Yellow
Red
1/9
1/30
1/6
1/360

Answers

i think the answer is 1/36 because 1/6 times 1/6

PLEASE BE RIGHT FILL IN THE BLANKS

Answers

Answer:

3 units to the right and 2 units up

Step-by-step explanation:

Find, correct to the nearest degree, the three angles of the triangle with the given ven
A(1, 0, -1), B(4, -3,0), C(1, 2, 3)
o
CAB =
O
LABC =
O
LBCA =

Answers

9514 1404 393

Answer:

  ∠CAB = 86°

  ∠ABC = 43°

  ∠BCA = 51°

Step-by-step explanation:

This can be done a couple of different ways (as with most math problems). We can use the distance formula to find the side lengths, then the law of cosines to find the angles. Or, we could use the dot product. In the end, the math is about the same.

The lengths of the sides are given by the distance formula.

  AB² = (4-1)² +(-3-0)² +(0-(-1)) = 16 +9 +1 = 26

  BC² = (1-4)² +(2-(-3))³ +(3-0)² = 9 +25 +9 = 43

  CA² = (1-1)² +(0-2)² +(-1-3)² = 4 +16 = 20

From the law of cosines, ...

  ∠A = arccos((AB² +CA² -BC²)/(2·AB·CA)) = arccos((26 +20 -43)/(2√(26·20)))

  ∠A = arccos(3/(4√130)) ≈ 86°

  ∠B = arccos((AB² +BC² -AC²)/(2·AB·BC)) = arccos((26 +43 -20)/(2√(26·43)))

  ∠B = arccos(49/(2√1118)) ≈ 43°

  ∠C = arccos((BC² +CA² -AB²)/(2·BC·CA)) = arccos((43 +20 -26)/(2√(43·20)))

  ∠C = arccos(37/(4√215)) ≈ 51°

The three angles are ...

  ∠CAB = 86°

  ∠ABC = 43°

  ∠BCA = 51°

_____

Additional comment

This sort of repetitive arithmetic is nicely done by a spreadsheet.

Construct a frequency distribution and a relative frequency histogram for the accompanying data set using five classes. Which class has the greatest relative frequency and which has the least relative​ frequency?Complete the table below. Use the minimum data entry as the lower limit of the first class.Class Frequency, f Relative frequencyx-x x xx-x x xx-x x xx-x x xx-x x x sumf= X?​(Type integers or decimals. Round to the nearest thousandth as​ needed.)DATA:Triglyceride levels of 26 patients​ (in milligrams per deciliter of​ blood)138 199 240 143 294 175 240 216 223180 138 266 161 175 402 172 459 147391 152 199 294 188 320 421 161

Answers

Answer:

[tex]\begin{array}{cc}{Class}& {Frequency} & 138 - 202 & 14 & 203 - 267 & 5 & 268 - 332 & 3 & 333 - 397 & 1 & 398 - 462 & 3 \ \end{array}[/tex]

The class with the greatest is 138- 202 and the class with the least relative frequency is 333 - 397

Step-by-step explanation:

Solving (a): The frequency distribution

Given that:

[tex]Lowest = 138[/tex] --- i.e. the lowest class value

[tex]Class = 5[/tex] --- Number of classes

From the given dataset is:

[tex]Highest = 459[/tex]

So, the range is:

[tex]Range = Highest - Lowest[/tex]

[tex]Range = 459 - 138[/tex]

[tex]Range = 321[/tex]

Divide by the number of class (5) to get the class width

[tex]Width = 321 \div 5[/tex]

[tex]Width = 64.2[/tex]

Approximate

[tex]Width = 64[/tex]

So, we have a class width of 64 in each class;

The frequency table is as follows:

[tex]\begin{array}{cc}{Class}& {Frequency} & 138 - 202 & 14 & 203 - 267 & 5 & 268 - 332 & 3 & 333 - 397 & 1 & 398 - 462 & 3 \ \end{array}[/tex]

Solving (b) The relative frequency histogram

First, we calculate the relative frequency by dividing the frequency of each class by the total frequency

So, we have:

[tex]\begin{array}{ccc}{Class}& {Frequency} & {Relative\ Frequency} & 138 - 202 & 14 & 0.53 & 203 - 267 & 5 & 0.19 & 268 - 332 & 3 & 0.12 & 333 - 397 & 1 & 0.04 & 398 - 462 & 3 & 0.12 \ \end{array}[/tex]

See attachment for histogram

The class with the greatest is 138- 202 and the class with the least relative frequency is 333 - 397

Long division: 2/ 2769

Answers

Answer:

1384.5

Step-by-step explanation

Diviseion is just the oppisite of multiplication so you can think to yourself that what times two equals 2769. If you multiply 1384.5 on a calculater you get 2769.

1384.7 I think I’m not sure tho

sec x tanx( 1- sin^2 x) = __x

Answers

Answer:

sin(x)

Step-by-step explanation:

sec x tanx(1 - sin^2 x)

1 - sin^2 x = cos^2 x

sec(x)tan(x)cos^2(x)

[tex]\frac{1}{cos(x)}[/tex] * [tex]\frac{sin(x)}{cos(x)}[/tex] * cos^2(x)

[tex]\frac{sin(x)cos^2(x)}{cos^2(x)}[/tex]

sin(x)

A nut mixture has peanuts,almonds and cashews in the ratio 5:3:1. Question:How much nust mixture should Helen buy if she wants to ensure she has 750g of almonds in the mix? please help!!will submit it today....​

Answers

Answer:

2250 g of nut mixture

Step-by-step explanation:

In order to use the ratio, we have to divide that 750 g by 3.

So 250 g multiplied by 5 is 1250. That's the amount of peanuts. Then just 1 for the cashews.

So, adding all of that up, the answer is 2250 g of nut mixture.

Answer:

1350g of nut mixture

Step-by-step explanation:

5:3:1 = 5x + 3x + x

5x = 750

x = 150

5x + 3x + x

= 5(150) + 3(150) + (150)

=750 + 450 + 150

=1350g

Hope it helps...

Hannah ran 12 laps for 8 days. How many laps did she run in total if she take a break of 1 complete day and 1 half day.

Answers

Answer:

The correct answer would be - 9.75 laps (if runs 12 laps in 8 days) or 78 laps (if 12 laps each day for 8 days)

Step-by-step explanation:

Given:

a) Laps covered in 8 days = 12

interval = 1 and half day

total laps = ?

Solution:

To know the total laps with intervals we need to calculate the laps run each day :

= 12/8 laps per day

= 3/2 laps per day

Now multiply the daily run with days

= (3/2)*6.5              (due to 8 - 1.5 = 6,5 days)

= 9.75 laps

B) Given:

Laps covered in 8 days = 12*8 =96

interval = 1 and half day

total laps = ?

Solution:

To know the total laps with intervals we need to calculate the laps run each day :

= 96/8 laps per day

= 12laps per day

Now multiply the daily run with days

= 12*6.5              (due to 8 - 1.5 = 6,5 days)

= 78 laps

48. What is the volume of the cuboid below? 3cm 2cm 2cm

Answers

Answer:

Cuboid = width*height*length

Cuboid = 24 cm^2

How long will it take the same crew to clear the entire plot of 2 1/2 acres?

Answers

Answer:

It will take 15 days for the same crew to clear the entire plot of 2 1/2 acres.

Step-by-step explanation:

Given that a crew clears brush from 1/3 acre of land in 2 days, to determine how long will it take the same crew to clear the entire plot of 2 1/2 acres, the following calculation must be performed:

1/3 = 0.333

1/2 = 0.5

0.333 = 2

2.5 = X

2.5 x 2 / 0.333 = X

15 = X

Therefore, it will take 15 days for the same crew to clear the entire plot of 2 1/2 acres.

Help please somebody ASAP

Answers

Answer:

[tex]\frac{-2x+11}{(x-4)(x+1)}[/tex]

Step-by-step explanation:

I don't think we can factor this so we'll have to multiply to make the denominators the same

[tex]\frac{3(x+1)}{(x^2-3x-4)(x+1)}-\frac{2(x^2-3x-4)}{(x+1)(x^2-3x-4)}\\\\\frac{3x+3-(2x^2-6x-8)}{(x^2-3x-4)(x+1)}=\frac{-2x^2+9x+11}{(x^2-3x-4)(x+1)}\\-2x^2+9x+11=(x+1)(-2x+11)\\\\x^2-3x-4=(x+1)(x-4)\\\frac{(x+1)(-2x+11)}{(x+1)(x-4)(x+1)}=\frac{-2x+11}{(x-4)(x+1)}[/tex]


Joaquin drew the triangle below.

On a coordinate plane, triangle K L J has points (3, 6), (4, 0) and (negative 5, 0).

Which statement must be true about a figure that is congruent to Joaquin’s triangle?
It has two angles on the x-axis.
It has a side that is 9 units long.
It has a side that lies on the x-axis.
It has an obtuse angle.

Answers

Answer:

It has a side that is 9 units long.

Step-by-step explanation:

Answer:

B) It has a side that is 9 units long.

Step-by-step explanation:

Since it does not have two angles on the X-axis, a side that lies on the X-axis, or an obtuse angle the reasonable answer would be B as it is true, and all of the others are false.

6. What are the coordinates of W? (0,t) W 0 (,0) Rhombus (0, -1) o (-r, o) (0,r). (t,0)​

Answers

Answer:

B. (-r, 0)

Step-by-step explanation:

W is on the x axis, so the y coordinate is 0.

It is also r away from the origin, so the x coordinate is -r

Hope this helps!

Help me or ill fail plz

Answers

Answer:

1,108 in²

Step-by-step explanation:

SA = (12×20) + (2×20×5 + 2×12×5) + (2×½×12×9)

+ (2×20×11)

= 240+320+108+440

= 1,108 in²

ANSWER ASAP IM BEING TIMED
IF I GET AN A ON THIS I WILL DO ANOTHER POINT FREE DROP, PLEASE SHOW YOUR WORK

The side of a square measures (4x − 7) units.

Part A: What is the expression that represents the area of the square? Show your work to receive full credit. (4 points)

Part B: What are the degree and classification of the expression obtained in Part A? (3 points)

Part C: How does Part A demonstrate the closure property for polynomials? (3 points)

(10 points)

Answers

Step-by-step explanation:

Area of a square = s x s

(4x-7)x(4x-7)

Open brackets

4x(4x-7)-7(4x-7)

16x^2-28-28x+49

16x^2-28x+21

01:55:07
The point-slope form of the equation of the line that passes through (-9, -2) and (1, 3) is y – 3 = {(x - 1). What is the
slope-intercept form of the equation for this line?
O y = 3x+2
O y= 2x-4
O y=+*+
O y = 3x - 2

Answers

Answer

y = 3x - 2

Step-by-step explanation

The slope-intercept form of the equation for this line is,

⇒ y  = x + 2

What is Equation of line?

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

The point-slope form of the equation of the line that passes through points (-9, -2) and (1, 3) is,

⇒ y - 3 = (x - 1)

Now, We can simplify as;

⇒ y - 3 = (x - 1)

⇒ y - 3 + 3 = (x - 1) + 3

⇒ y  = x + 2

Thus, The slope-intercept form of the equation for this line is,

⇒ y  = x + 2

Learn more about the equation of line visit:

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what is the complete factorization of 8x^2-8x+2

Answers

Answer:

2x(4x-4+1)

Step-by-step explanation:

i hope it will help you

Answer:

x=1/2

Step-by-step explanation:

press the calculator

8x²-8x+2=0

x=1/2

min,x=1/2

min,y=0

Which of the following is an even function?
g(x) = (x – 1)2 + 1
g(x) = 2x2 + 1
g(x) = 4x + 2
g(x) = 2x

Answers

Answer:  Choice B

Consider that choice B is the same as saying 2x^2+1x^0.

The exponents 2 and 0 are both even, which is sufficient to say that the entire polynomial function itself is also even.

Something like choice A expands out and simplifies to x^2-2x+2, and that's equivalent to saying x^2+2x^1+2x^0. The presence of the x^1 term, with its odd exponent, is what makes choice A not even (it's not odd either).

Similarly, choices C and D also have exponents of 1, so they aren't even either.

Answer:

G(x)=2x2+1

Step-by-step explanation:

the campus bookshop sells exercise books and textbooks, where, the total cost of 10 exercise books and 2 textbooks is $1400.00. One also finds the total cost of 3 textbooks and 30 exercise books is $3000. Then determine the price of 1 exercise book?

Answers

Answer:

The price of 1 exercise book is $122.45.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the price of one exercise book.

y is the price of one textbook.

Total cost of 10 exercise books and 2 textbooks is $1400.00.

This means that:

[tex]10x + 2y = 1400[/tex]

Since we want x:

[tex]2y = 1400 - 10x[/tex]

[tex]y = 700 - 5x[/tex]

One also finds the total cost of 3 textbooks and 30 exercise books is $3000.

This means that:

[tex]3x + 30y = 3000[/tex]

Since [tex]y = 700 - 5x[/tex]

[tex]3x + 30(700 - 5x) = 3000[/tex]

[tex]3x + 21000 - 150x = 3000[/tex]

[tex]147x = 18000[/tex]

[tex]x = \frac{18000}{147}[/tex]

[tex]x = 122.45[/tex]

The price of 1 exercise book is $122.45.

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