A company manufactures a certain over-the-counter drug. The company samples 80 pills and finds that the mean amount of drug in the pills is 325.5 mg with a standard deviation of 10.3 mg. Find the 90% confidence interval for the mean of all the pills.'

The matrix M is:

M = [ 1/2 -1/2 ]

[ 0 0 ]

Let M = [a b]

[c d]

The matrix equation becomes:

[ a b ] [4 2] = [1 0]

[ c d ] [5 3] [0 1]

Which yields the linear system:

4a + 2b = 1

5c + 3d = 0

4c + 2d = 0

5a + 3b = 1

Now the matrix M is:

M = [a b]

[0 0]

Using the first and fourth equations:

4a + 2b = 1

5a + 3b = 1

Solving this system, we find a = 1/2 and b = -1/2.

So, the matrix M is:

M = [ 1/2 -1/2 ]

[ 0 0 ]

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The  NPV of the project is $331,085.70. Since the NPV is positive, the project should be undertaken as it creates value for the company.

To calculate the NPV of the project, we need to estimate the cash flows generated by the project and discount them back to their present value using the required return of 11 percent.

The annual cash inflows generated by the project are the annual sales of $2,590,000 minus the annual costs of $1,610,000, which equals $980,000. We can calculate the annual depreciation expense as the initial fixed asset investment of $2,350,000 divided by the three-year tax life, which equals $783,333 per year.

Using the straight-line depreciation method, the fixed asset will have a book value of $1,566,667 (i.e., $2,350,000 - $783,333) at the end of year 3, which is equal to its estimated salvage value. Therefore, the after-tax salvage value is:

($1,566,667 - $0) x (1 - 0.21) = $1,235,000

Now we can calculate the annual after-tax cash flows:

Year 1: $980,000 - $301,667 = $678,333
Year 2: $980,000 - $301,667 = $678,333
Year 3: $980,000 - $301,667 + $1,235,000 = $1,913,333

where $301,667 is the annual depreciation expense.

To calculate the NPV, we need to discount these cash flows back to their present value at the required return of 11 percent. Using a financial calculator or spreadsheet software, we find that the NPV of the project is:

NPV = -$2,350,000 + $678,333/(1+0.11)^1 + $678,333/(1+0.11)^2 + $1,913,333/(1+0.11)^3 = $331,085.70

Therefore, the NPV of the project is $331,085.70. Since the NPV is positive, the project should be undertaken as it creates value for the company.

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The surface area of the cylinder with a radius of 8 in and height of 6 in is 224π square inches.

The surface area of the cylinder is the total sum of the lateral surface area and the two cross-section area.

The formula for the surface area of a cylinder is:

SA = 2πr² + 2πrh

where r is the radius and h is the height.

Plugging in the given values, we have:

SA = 2π(8²) + 2π(8)(6)

SA = 2π(64) + 2π(48)

SA = 128π + 96π

SA = 224π

Therefore, the surface area of the cylinder with a radius of 8 in and height of 6 in is 224π square inches.

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To find the length of one side of Steve's hamster pen, we can use the formula for the perimeter of a square, which is P = 4s, where P is the perimeter and s is the length of one side. In this case, we know that the perimeter is 240 centimeters, so we can set up the equation 240 = 4s. To solve for s, we can divide both sides by 4, which gives us s = 60 centimeters. Therefore, the length of one side of Steve's hamster pen is 60 centimeters. This means that all four sides of the pen are equal in length, and the area of the pen would be 60 x 60 = 3600 square centimeters.
Hi! To find the length of one side of Steve's square hamster pen with a perimeter of 240 centimeters, you can follow these steps:

1. Understand that the perimeter of a square is the sum of all its sides. In a square, all sides are equal.
2. Since there are 4 sides in a square, you can divide the total perimeter by 4 to find the length of one side.
3. Perform the calculation: 240 cm / 4 = 60 cm.

So, the length of one side of Steve's hamster pen is 60 centimeters.

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When investigating the effect of exercise on myocardial infarction, it is important to consider the influence of potential confounding variables, such as gender. Confounding occurs when a third variable influences both the independent and dependent variables, leading to spurious relationships between them.

In this case, gender may influence the risk of myocardial infarction and also the likelihood of exercising regularly, creating a potential confounding effect.

To control for this confounding effect, multiple regression analysis can be used. This statistical technique allows for the simultaneous analysis of multiple predictor variables and their relationship to the outcome variable. By including gender as a predictor variable in the analysis, the effect of exercise on myocardial infarction can be assessed while controlling for the potential confounding effect of gender.

This method of control for confounding is known as statistical adjustment, and it is commonly used in observational studies where randomized controlled trials are not feasible or ethical. It is important to note that while statistical adjustment can help to minimize the influence of confounding variables, it cannot completely eliminate the possibility of residual confounding. Therefore, it is essential to carefully consider potential confounding factors when designing and analyzing studies on the effects of exercise on myocardial infarction or any other health outcome.

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The mean weight of certain sheets of wrapping paper is 10 g each.

The mean weight of the sheets of wrapping paper is given as 10 g each. This means that on average, each sheet weighs 10 grams. The standard deviation of the weight of the sheets is given as 0.05 g.

This indicates the degree of variability or spread in the weight of the sheets around the mean weight of 10 g. A standard deviation of 0.05 g suggests that most of the sheets will have a weight that is very close to 10 g, with only a few sheets having a weight that deviates significantly from the mean.

The mean weight of the sheets of wrapping paper can be used as a reference point for determining the weight of a particular sheet or for calculating the weight of a bundle of sheets.

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The receiver should be placed 3/4 feet away from the vertex of the dish.

Assuming that the satellite dish antenna is a perfect paraboloid, the receiver should be placed at the focal point of the paraboloid, which is located at a distance of one-fourth of the diameter from the vertex of the dish.

The diameter of the dish is given as 6 feet, so the radius (half of the diameter) is 3 feet. The depth of the dish is given as 2 feet.

The equation of the paraboloid in standard form is:

[tex]z = (x^2 + y^2) / (4f)[/tex]

where z is the depth of the dish (2 feet), x and y are the coordinates of any point on the paraboloid, and f is the focal length.

At the vertex of the paraboloid (where x = y = 0), the depth of the dish is 0. So, we can use this information to find the focal length f:

[tex]2 = (0^2 + 0^2) / (4f)[/tex]

f = 1/4

The focal length is 1/4 feet, or 3 inches.

The distance from the vertex of the dish to the receiver is equal to the distance from the focal point to the vertex, which is:

d = 1/4 × 3 = 3/4 feet

So the receiver should be placed 3/4 feet away from the vertex of the dish.

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a = 4 and b = 5 are the answers to the system of equations.

Let's square both sides of the first equation to eliminate the square root:

√a + b = 7

(√a + b)² = 7²

a + 2√ab + b² = 49

a + b² = 49 - 2√ab ---(1)

Now, let's square both sides of the second equation:

√b + a = 11

(√b + a)² = 11²

b + 2√ab + a² = 121

a² + b + 2√ab = 121 ---(2)

We can use equation (1) to substitute for √ab in equation (2):

a + b² = 49 - 2√ab

√ab = (49 - a - b²)/2

Substituting for √ab in equation (2), we get:

a² + b + 2(49 - a - b²)/2 = 121

Simplifying and rearranging, we get:

a² - a + b² - b - 36 = 0

(a - 1/2)² + (b - 1/2)² = 37.25

This is the equation of a circle centered at (1/2, 1/2) with a radius √37.25. We need to find the points where this circle intersects the line defined by equation (1).

Substituting b = 49 - a - 2√(a(49 - a))/2 into equation (1), we get:

a + (49 - a - 2√(a(49 - a)))² = 49 - 2√a(49 - a)

Simplifying and rearranging, we get:

4a³ - 294a² + 2421a - 5929 = 0

Using a numerical solver or the rational root theorem, we can find that one solution of this cubic equation is a = 4.

Substituting this value back into equation (1), we can solve for b:

4 + b² = 49 - 2√(4b)

b² + 2√(4b) - 45 = 0

Using the quadratic formula, we get:

b = 5

Therefore, the solutions of the system of equations are a = 4 and b = 5.

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Complete question:

√a+b=7 and √b +a = 11 If a and b are real numbers that satisfy the equation above, what is the value of a and b respectively?

The probability that a person who tests positive actually has the disease is 3.8%.

The probability that a person who tests positive actually has the disease can be computed using Bayes' Theorem. Let D be the event that a person has the disease, and T be the event that a person tests positive.

Then, using Bayes' Theorem:

P(D|T) = P(T|D) * P(D) / [P(T|D) * P(D) + P(T|~D) * P(~D)]

where P(T|D) is the true positive rate (1 - false negative rate), P(T|~D) is the false positive rate, and P(D) is the incidence rate of the disease.

Substituting the given values:

P(D|T) = (0.996 * 0.002) / [(0.996 * 0.002) + (0.05 * 0.998)]

= 0.038

Therefore, the probability that a person who tests positive actually has the disease is 3.8%.

This calculation illustrates the importance of considering both the false positive and false negative rates when interpreting diagnostic test results.

A positive test result may not necessarily mean that a person has the disease, especially if the false positive rate is relatively high. In this case, the false positive rate of 5% means that 5 out of 100 people who do not have the disease would test positive, leading to a relatively low probability of actually having the disease given a positive test result.

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Therefore, The physical addresses for the given logical addresses are 330, 2910, 255, 1700, and 2312.

To find the physical addresses for the given logical addresses, we need to use the segment base and segment limit values.
For logical address 0, we have segment base 0 and segment limit 400. So, the physical address would be 0 + 330 = 330.
For logical address 1, we have a segment base of 2300 and a segment limit of 700. So, the physical address would be 2300 + 610 = 2910.
For logical address 2, we have segment base 0 and segment limit 300. So, the physical address would be 0 + 255 = 255.
For logical address 3, we have a segment base of 1000 and a segment limit of 580. So, the physical address would be 1000 + 700 = 1700.
For logical address 4, we have a segment base of 2000 and a segment limit of 200. So, the physical address would be 2000 + 312 = 2312.

Therefore, The physical addresses for the given logical addresses are 330, 2910, 255, 1700, and 2312.

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Answer:

We can write the inequality as:

p > 175 (since the cost of the coat must be greater than $175)

and

p ≤ 430 (since the shopper cannot spend more than $430)

Combining these two inequalities, we get:

175 < p ≤ 430

Therefore, the prices p of coats that the shopper can buy must satisfy the inequality 175 < p ≤ 430

Step-by-step explanation:

I am seeking friends , add me on sn ap = m_oonlight781 and we can do school stuffs togetherwaiting

Answer:

Let s be the speed of the plane. Then s - 100 is the speed of the car.

640/s = 240/(s - 100)

640(s - 100) = 240s

8(s - 100) = 3s

8s - 800 = 3s

5s = 800, so s = 160 mph

The speed of the plane is 160 mph, and the speed of the car is 60 mph.

The probability that a randomly selected LA worker has a commute that is longer than 29 minutes is 0.1736.

The probability that a randomly selected LA worker has a commute that is longer than 29 minutes depends on the distribution of the commute times. Without information on this distribution, we cannot give a specific answer.

However, if we assume that the commute times are normally distributed with a mean of 26.2 minutes and a standard deviation of 6.1 minutes (as given in a previous question), we can use the normal distribution to estimate the probability.

Using a calculator, we can calculate the z-score for a commute time of 29 minutes:

z = (29 - 26.2) / 6.1 = 0.459

Then, we can find the probability of a z-score greater than 0.459, which represents the probability of a longer commute time than 29 minutes:

P(Z > 0.459) = 0.1736

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The volume of the solid generated is [tex]\frac{117}{3} π[/tex]

To find the volume of the solid generated by rotating the region in the first quadrant enclosed by the curves y = 0, x = 2, x = 5 about the x-axis, we need to use the disk method.

The radius of each disk is given by the distance from the x-axis to the curve y = f(x), which in this case is just the value of x itself since the curves y = 0 and x = 2 bound the region.

So, we can set up the integral as follows:

[tex]V = \int\limits {x} \,  [a,b] πr^2 dx[/tex]
V = ∫[2,5] πx^2 dx
[tex]V = \int\limits {x} \,  [2,4] πx^2 dx[/tex]
[tex]V= π(\frac{125}{3} ) - π (\frac{8}{3} )[/tex]
[tex]V=\frac{117}{3} π[/tex]

Therefore, the volume of the solid generated is [tex]\frac{117}{3} π[/tex] cubic units.

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The height and radius of the cup are 4.41 cm and 2.07 cm respectively

To minimize the amount of paper used, we need to minimize the surface area of the cup. Let h be the height and r be the radius of the cone. Then we have:
[tex]Volume of cone = \frac{1}{3}  πr^{2} h = 36 cm^{3}[/tex]

Solving for h, we get:
[tex]h = \frac{108}{(πr^2)}[/tex]

Now we can express the surface area of the cone as:
[tex]Surface area = πr^2+ πr\sqrt{r^{2}+h^{2}  }[/tex]

Substituting the expression for h, we get:

[tex]Surface area = πr^2+πr \sqrt{(r^{2} +(\frac{108}{(πr^2)^{2}) } )}[/tex]

To minimize this function, we take its derivative with respect to r and set it equal to zero:
[tex]\frac{d}{dx} (Surface area) =  \frac{2πr - 108r }{[(r^2+(\frac{108}{πr^2}))^{0.5}  }] - \frac{108π}{r^2 }  = 0[/tex]

Simplifying, we get:
[tex]2r^3 - \frac{108^2}{π} = 0[/tex]

Solving for r, we get:
[tex]r = (\frac{54}{π})^{\frac{1}{3} }[/tex]

Substituting this value into the expression for h, we get:
[tex]h = \frac{108}{\frac{54}{π} ^{(\frac{2}{3}π )} }[/tex]

Thus, the height and radius of the cup that will use the smallest amount of paper are:
height = 4.41 cm
radius = 2.07 cm (rounded to two decimal places)

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The legal description of a parcel in a subdivision that has been recorded with lot and block numbers on a plat of survey is the written description of the boundaries and location of the property, including the lot and block numbers as identified on the plat of survey. This legal description is used to define and identify the property for legal purposes such as real estate transactions, property taxes, and land use regulations.

The legal description of a parcel in a subdivision that has been recorded with lot and block numbers on a plat of survey is known as a "Lot and Block" description. This description typically includes the subdivision name, the specific lot number, and the block number within that subdivision. This information is used to accurately identify and locate the property within the larger plat of survey, ensuring proper documentation and reference for legal and real estate purposes.

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The area of the triangle is 19.5 square units.

To find the area of the triangle, we can use the formula:

Area = (1/2) * base * height

where the base and height are the distance between two of the vertices of the triangle. We can choose any two vertices to use as the base and height, as long as we use the same units for both. Let's choose (-3,2) and (6,-2) as our base.

The distance between (-3,2) and (6,-2) can be found using the distance formula:

d = [tex]\sqrt((6 - (-3))^2 + (-2 - 2)^2)[/tex]
d = [tex]\sqrt(81 + 16)[/tex]
d = [tex]\sqrt(97)[/tex]

Now we need to find the height of the triangle. The height is the perpendicular distance from the third vertex (3,5) to the line containing the base (-3,2) and (6,-2). We can use the formula:

height = [tex]|Ax + By + C| / \sqrt(A^2 + B^2)[/tex]

where A, B, and C are the coefficients of the line in the standard form Ax + By + C = 0, and x and y are the coordinates of the third vertex. We can find the coefficients of the line by using the two points (-3,2) and (6,-2):

A = 2 - (-2) = 4
B = (-3) - 6 = -9
C = 6*(-2) - (-3)*2 = -18

Now we can plug in the values to find the height:

height = [tex]|4*3 - 9*5 - 18| / \sqrt(4^2 + (-9)^2)[/tex]
height = [tex]39 / \sqrt(97)[/tex]

Finally, we can plug in the base and height to find the area:

Area = [tex](1/2) * \sqrt(97) * (39 / \sqrt(97))[/tex]
Area = 19.5

Therefore, the area of the triangle is 19.5 square units.

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Thus, the probability that it will rain on exactly one of the five days during the Hiking Club's camping trip in the State park is approximately 4.38%.

We can use the binomial probability formula to calculate the probability of rain on exactly one of the five days during the Hiking Club's camping trip in the State park. The formula is:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

where:
- P(X = k) is the probability of k successes (rain) in n trials (days)
- C(n, k) is the number of combinations of n items taken k at a time
- p is the probability of success (rain) on any given day (66% or 0.66)
- n is the number of trials (5 days)
- k is the number of successes (1 day with rain)

Plugging the values into the formula, we get:

P(X = 1) = C(5, 1) * 0.66^1 * (1 - 0.66)^(5 - 1)

First, we find the number of combinations C(5, 1) which is 5.

Next, we calculate the probabilities:
0.66^1 = 0.66
(1 - 0.66)^4 = 0.34^4 = 0.0133

Now, we multiply everything together:

P(X = 1) = 5 * 0.66 * 0.0133 ≈ 0.0438

So, the probability that it will rain on exactly one of the five days during the Hiking Club's camping trip in the State park is approximately 4.38%.

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Answer:

(x + 10)(2x + 5) - (x + 1)(x + 1)

= 2x^2 + 25x + 50 - (x^2 + 2x + 1)

= x^2 + 23x + 49

We cannot find the 90% confidence interval for all first-year students at the university that will be traveling to and from campus by train with the given information.

In mathematics, an interval is a set of real numbers that includes all the numbers between two given values. More formally, an interval is a connected subset of the real number line. Intervals are commonly represented using brackets or parentheses. For example, [a,b] represents the closed interval from a to b, including both endpoints, while (a,b) represents the open interval from a to b, excluding both endpoints. Half-open intervals, such as [a,b) or (a,b], include one endpoint and exclude the other.

Intervals play a crucial role in mathematical analysis, calculus, and many other areas of mathematics. They are used to define functions, measure lengths, and study the behavior of mathematical objects over a range of values. Intervals also have important applications in physics, engineering, and other sciences.

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Expect 665 out of the 950 employees to invest money into a retirement fund.

If 14 out of 20 employees prefer to invest in a retirement fund, then the fraction of employees who prefer to invest in a retirement fund is:

14/20

To find the expected number of employees who prefer to invest in a retirement fund out of a total of 950 employees, we can set up a proportion:

14/20 = x/950

where x is the expected number of employees who prefer to invest in a retirement fund.

We can solve for x by cross-multiplying:

14 x 950 = 20( x)

13300 = 20x

x = 665

Therefore, we can expect 665 out of the 950 employees to invest money into a retirement fund.

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Answer:

[tex] {5}^{ \frac{2}{3} } = \sqrt[3]{ {5}^{2} } [/tex]

[tex] {5}^{ \frac{1}{2} } = \sqrt{5} [/tex]

[tex] {3}^{ \frac{2}{5} } = \sqrt[5]{ {3}^{2} } [/tex]

[tex] {3}^{ \frac{5}{2} } = \sqrt{ {3}^{5} } [/tex]

The system of linear inequalities is y ≤ -1/3x and y ≥ 2x. To graph this system, we start by graphing the boundary lines, which are y = -1/3x and y = 2x.

The line y = -1/3x has a negative slope, and it passes through the origin (0,0). We can plot this point and another point on the line to draw the line. For example, if x = 3, then y = -1.

The line y = 2x has a positive slope, and it passes through the origin (0,0). We can plot this point and another point on the line to draw the line. For example, if x = 3, then y = 6.

Now, we need to shade the region that satisfies both inequalities. Since y ≤ -1/3x is a downward-sloping line and y ≥ 2x is an upward-sloping line, the region that satisfies both inequalities is the triangular region below the line y = -1/3x and above the line y = 2x.

We shade this region in the graph by clicking on the area bounded by these two lines and below the x-axis. This represents the solution set of the system of linear inequalities.

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In hypothesis testing, the tentative assumption about the population parameter is either the null hypothesis or the alternative hypothesis. The null hypothesis (denoted as H₀) represents the statement that there is no significant difference or effect between the variables being studied, while the alternative hypothesis (denoted as H₁) asserts that there is a significant difference or effect.

Hypothesis testing involves comparing observed data against these hypotheses to determine which one is more likely to be true. Researchers aim to either reject or fail to reject the null hypothesis, based on the evidence provided by the data. If the null hypothesis is rejected, it suggests that the alternative hypothesis is more likely to be true.

To make this decision, a significance level (usually denoted as α) is chosen to quantify the risk of making a Type I error, which is rejecting the null hypothesis when it is actually true. Common significance levels are 0.05 or 0.01. If the probability of observing the data (or more extreme) under the null hypothesis, called the p-value, is less than the chosen significance level, the null hypothesis is rejected in favor of the alternative hypothesis.

In summary, hypothesis testing involves evaluating the tentative assumptions about the population parameter using the null and alternative hypotheses to draw conclusions based on the observed data.

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In interval estimation, the t distribution is applicable when the sample size is small and the population variance is unknown. Therefore, options a, c, and d can be eliminated.

The t distribution is used when the sample standard deviation is used to estimate the population standard deviation, which is usually the case in practice. When the sample size is small, using the t distribution instead of the standard normal distribution results in wider confidence intervals, which takes into account the uncertainty associated with estimating the population standard deviation from the sample.

The t distribution also approaches the standard normal distribution as the sample size increases. Therefore, the correct answer is b.

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The conversion result of decimal numbers to hexadecimal representations of 2's complement numbers are the following

a) 100

b) 6F

c)75BCD15

d)FFFFFF04

A decimal number can be represent the two parts one is whole and a fractional part separated by a decimal point. The decimal point is represented by dot inbetween the whole and fractional part. Hexadecimal is one of number system with base 16. That means 16 possible digits used to represent numbers. Steps to convert a decimal number to hexadecimal number :

Representations of 2's complement numbers :

a) decimal number = 256

using above rules, it's hexadecimal representations of 2's complement numbers is 100.

b) decimal number = 111

it's hexadecimal representations of 2's complement numbers is 6F.

c) decimal number = 123,456,789

it's hexadecimal representations of 2's complement numbers is 75BCD15.

d) decimal number = -44

it's hexadecimal representations of 2's complement numbers is FFFFFF04.

Hence, required values are obtained.

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We know that the total number of people in the room is a whole number, so we can round up to 33 people.

Let's start by using variables to represent the unknowns in the problem.

Let's say the total number of people in the room is "x" and the total number of chairs in the room is "y".

According to the problem, 4/7 of the people in the room are seated, which means that 3/7 of the people are standing. We also know that 7/10 of the chairs are occupied, which means that 3/10 of the chairs are empty.

We can set up two equations based on the information given:

(4/7)x = 7/10y (equation 1)

3/10y = 8 (equation 2)

We can solve for "y" in equation 2:

3/10y = 8

y = (8 x 10) / 3

y = 26.67

We know that the total number of chairs in the room is a whole number, so we can round up to 27 chairs.

Now we can use equation 1 to solve for "x":

(4/7)x = 7/10(27)

(4/7)x = 18.9

x = (18.9 x 7) / 4

x = 32.925

We know that the total number of people in the room is a whole number, so we can round up to 33 people.

Therefore, there are 33 people in the room.

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There are 8 outcomes in the sample space.

When flipping a coin 3 times, there are 2 possible outcomes for each flip: heads (H) or tails (T). Thus, the total number of outcomes in the sample space is the number of possible combinations of H and T for 3 flips, which is 2³ = 8.

These outcomes can be listed as follows: HHH, HHT, HTH, THH, HTT, THT, TTH, and TTT. Each outcome is equally likely to occur, assuming the coin is fair and the flips are independent.

The concept of sample space is an important one in probability theory, as it represents the set of all possible outcomes of an experiment.

Knowing the sample space can help us calculate probabilities for specific events within that space and inform decision-making in a wide range of fields, from finance to sports to public health.

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These probabilities may be given in the problem statement or may need to be estimated based on past data or assumptions. Once we have these probabilities, we can use the multiplication rule to calculate the joint probability.

To find the probability that the next driver will use entrance 1 and park for more than two hours, we can use the multiplication rule of probability.

The multiplication rule states that the probability of two independent events occurring together is the product of their individual probabilities. In this case, the two events are:

The driver uses entrance 1

The driver parks for more than two hours

Let P(E1) be the probability that the next driver uses entrance 1, and let P(MT2) be the probability that the next driver parks for more than two hours.

Then, the probability that both events occur together is given by:

P(E1 and MT2) = P(E1) × P(MT2)

So, to find the probability that the next driver will use entrance 1 and park for more than two hours, we need to know the individual probabilities of these events.

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The expression 2^4×2^5/4^3×4^4 when evaluated has a solution of 2^-5

In this question, the expression is given as

2^4×2^5/4^3×4^4

Evaluating the exponents

So, we have

2^4×2^5/4^3×4^4 = 2^9/4^7

Express 4 as 2^2

So, we have

2^4×2^5/4^3×4^4 = 2^9/2^14

Apply the law of indices

So, we have

2^4×2^5/4^3×4^4 = 2^-5

Hence, the solution to the expression is 2^-5

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