A company is replacing cables with fiber optic lines in rectangular casing BCDE. If segment DE = 2.5 cm and segment BE = 3 cm, what is the smallest diameter of pipe that will fit the fiber optic line? Round your answer to the nearest hundredth. 3.54 cm 3.91 cm 4.24 cm 4.95 cm

Answer:  The x intercepts are -1 and -5  or  (-1,0)   and ( -5,0)

Step-by-step explanation:

Finding the x intercepts of  a parabola is the same as finding the roots of a parabola because the x intercept is when y or g(x) is equal to zero. So set the equation equal zero.

[tex]-x^{2} -6x -5 = 0[/tex]          First  divide each term by 0 to get the largest degree coefficient to equal 0.

x^2 + 6x +5 = 0         Now find two numbers that their product is 5 and their sum is 6.  The numbers 5 and 1 works out because the 5 times 1 is 5 and 5 plus 1 is 6.

Rewrite the whole equation as

x^2 + 1x+5x +5 = 0     Now factor the left side by grouping

x(x+1) 5(x+1) = 0         Factor out x+1

(x+1) (x+5) = 0       Now use the zero product by setting each of them equal zero.

x+ 1 = 0    or    x+5 = 0

    -1    -1               -5  -5

x = -1      or  x = -5

Answer:

The other number is 4/3

Step-by-step explanation:

Let the unknown number be x

Translate the equation :

[tex] - \frac{4}{3} \times x = - \frac{16}{9} \\ - \frac{4}{3} x = - \frac{16}{9} \\ [/tex]

Cross multiply

[tex] - 4x \times 9 = 3 \times - 16 \\ - 36x = - 48[/tex]

Divide both sides by -36

[tex] \frac{ - 36x}{ - 36} = \frac{ - 48}{ - 36x} \\ x = \frac{4}{3} [/tex]

Answer:

66%

Step-by-step explanation:

50 - 17 = 33, so that is the difference between the two numbers. Percent change is the change over the original, so 33/50. 33/50 equals 66/100, so the percent change is 66%

Work Shown:

T = C(3 + AB)

T = 3C + ABC .... distribute

3C + ABC = T

ABC = T - 3C ... subtract 3C from both sides

(AC)*B = T - 3C

B = (T - 3C)/(AC) .... divide both sides by AC

Answer:

T-AB-3=0

Step-by-step explanation:

Answer:

4 25/99 is the mixed fraction.

25/99 is the fraction

Answer:

Equation A doesn't have a rational solution

Step-by-step explanation:

Notice that the solutions for equation A is:

[tex]x^2=2\\x=+/- \sqrt{2}[/tex]

and [tex]\sqrt{2}[/tex] is an irrational number

The other equations have rational solutions:

Equation B:  x = 1 and x = -1 are solutions (both rational numbers)

Equation C:  x = 0 is the solution (rational number)

Equation D : x = 0 is the solution. (rational number)

Answer:

7

Step-by-step explanation:

a = 3, b=2 and c = -3

● -a^2 - 3b^3 + c^2 + 2b^3 -c^2

● -a^2 - b^3

● -(3)^2 + 2×2^3

● -9 + 16

● 7

Answer:

-35

Step-by-step explanation:

-3^2-3(2^3)-3^2 + 2(2^3)-3^2

Answer:

Line of course! So its B

Answer:

1

Step-by-step explanation:

Calculation steps:

-7-(-8) =                  ⇒ two negatives cancel and change to positive

- 7 + 8 =                  ⇒ 8-7 = 1

1                              ⇒ answer

All you have to do is find where the two circles intersect with each other ( where they meet ) and then draw your 5cm line from A to the intersection and the 3cm line from B to the intersection.

It should form a triangle*.

* The image should help you.

Elena should put a point where the two circles intersect and draw line segments connecting that point to points A and B to finish her triangle.

Answer:

                [tex]\bold{x=\dfrac3{7k}}[/tex]

Step-by-step explanation:

1kx + 13kx  =  6

   14kx  =  6

÷(14k)      ÷(14k)

x = 6/(14k)

x = 3/(7k)

Answer:

x=-4

Step-by-step explanation:

Since we know that the equation will be x= we will just have to take the x value of the coordinate point and that would be the x so in this case the x is -4 so the equation would be x=-4

Answer:

  $57,700

Step-by-step explanation:

The deductions are ...

  for pension and employment insurance, (5+2.4)% of $70,000

     = 0.074 × $70,000 = $5,180

  for income tax, ...

     8% of the 14,000 between $11,000 and $25,000 = $1,120

     12% of the 25,000 between $25,000 and $50,000 = $3,000

     15% of the 20,000 between $50,000 and $70,000 = $3,000

Then the total of deductions is ...

  $5,180 +1,120 +3,000 +3,000 = $12,300

Net salary after these deductions is ...

  $70,000 -12,300 = $57,700

Answer:

   11

  ----  

   4

Step-by-step explanation:

11       1

---  ÷ ----

12     3

just flip the 1/3 = 3/1 then multiply.

11       3         33        

---  x  ----  =  -----   just simplify if needed

12      1          12      

                     11

therefore    -----  

                     4

Answer:

$0.75 per candy bar

Step-by-step explanation:

For this problem, we simply need to set up a system of equations to find the value of a drink, and the value of a candy bar.

Let x represent the cost of a candy bar, and y represent the cost of a drink.

60x + 110y = 265

120x + 90y = 270

Now let's use the elimination method to solve for one of the variables:

60x + 110y = 265 --> -2 ( 60x + 110y = 265 ) --> -120x + -220y = -530

-120x + -220y = -530

120x + 90y = 270

-130y = -260

y = 2

Now plug the value of y into one of the equations to find the value for x:

60x + 110y = 265

60x + 110 (2) = 265

60x + 220 = 265

60x = 45

x = 45 / 60

x = 0.75

With this, we know that the cost of a candy bar is $0.75 and the cost of drink is $2.00.

Cheers.

Answer:

trinomial

Step-by-step explanation:

-x² - 1/2 + x

if you are asking for the specific name, it is a trinomial because there are 3 terms.

Answer:

D. m∠A=43, m∠B=55, a=20

Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

AB = c = 29

AC = b = 24

Required:

m<A, m<C, and a (BC)

SOLUTION:

Find m<B using the law of sines:

[tex] \frac{sin(B)}{b} = \frac{sin(C)}{c} [/tex]

[tex] \frac{sin(B)}{24} = \frac{sin(82)}{29} [/tex]

[tex] sin(B)*29 = sin(82)*24 [/tex]

[tex] \frac{sin(B)*29}{29} = \frac{sin(82)*24}{29} [/tex]

[tex] sin(B) = \frac{sin(82)*24}{29} [/tex]

[tex] sin(B) = 0.8195 [/tex]

[tex] B = sin^{-1}(0.8195) [/tex]

[tex] B = 55.0 [/tex]

m<B = 55°

Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

m<A = 43°

Find a using the law of sines:

[tex] \frac{a}{sin(A)} = \frac{b}{sin(B)} [/tex]

[tex] \frac{a}{sin(43)43} = \frac{24}{sin(55)} [/tex]

Cross multiply

[tex] a*sin(55) = 25*sin(43) [/tex]

[tex] a = \frac{25*sin(43)}{sin(53)} [/tex]

[tex] a = 20 [/tex] (approximated)

Answer:

20.0

Step-by-step explanation:

I got it correct on founders edtell

Answer:

A, B, D, and E

Step-by-step explanation: Hope it helps ^w^

Step-by-step explanation: I hope this helps.

Answer:

Answer:

4p+3

Step-by-step explanation:

4p+6+-3

[4p]+[6+-3]

4p+3

Answer:

X^2 +4y-2

Step-by-step explanation:

Substraction gives the difference between two points or two positions.

We were told to substraction 4x2 - 3y + 4, from (3x2 - 7y + 6)

Then we can say

(4x2 - 3y + 4) -(3x2 - 7y + 6)

If we open the bracket we have

4x2 - 3y + 4 - 3x2 + 7y - 6

Then if we collect like terms we have

4x2 - 3x2 -3y +7y +4 -6

Then we have

X^2 +4y-2

Hence the substraction between 4x2 - 3y + 4, and (3x2 - 7y + 6)

gives us X^2 +4y-2

Answer:

D. h(x) = 4(x - 5)² - 18

Step-by-step explanation:

Answer:

Rene needs 9 of these identical cylinder.

Step-by-step explanation:

diameter d = 6 cm

height h = 8 cm

volume of this cylinder v = [tex]\pi d^{2}h/4[/tex]

substituting, we have

v = (3.142 x [tex]6^{2}[/tex] x 8)/4

v = 226.224 cm^3

minimum number of identical containers Rene should use should be

n = 2,000/226.224 = 8.8

The minimum number must be a whole number, and must completely make this 2000 cm^3 volume of ice or more

answer will be 9

Answer:

The value of x is 16 and the width is 4.

Step-by-step explanation:

The area of a rectangle is the length multiplied by the width, which is [tex]9\sqrt{x}[/tex].

So, [tex]9\sqrt{x}[/tex] = 36.

We divide both sides by 9, getting [tex]\sqrt{x}[/tex] = 4.

We then square both sides, getting x = 16.

The value of x is 16, and the width is 4.

Answer: the distances can be 0.65 miles (in the opposite direction to the school) or 4.65 miles (in the same direction as the school)

Step-by-step explanation:

Ok, the data that we have is:

Total distance = 9.3 mi.

The travel is:

House to school = 4 mi.

school to library = A

library to house = B

Now, we have that:

4mi + A + B = 9.3mi.

We have three possibilities:

1) The order of locations is: house, library, school

The travel from: school to library + library to house is equivalent to a travel between the school to the house = 4mi.

Then we have A + B = 4mi

4mi + A + B = 8mi ≠ 9.3mi

Then the library can not be between the house and the school.

2) The order of locations is: house, school, library.

In this case we have that the distance between the library and the house is equal to the distance between the house and the school plus the distance between the school and the library, then:

4mi + A = B.

We can replace this in our original equation:

4mi + A + B = 9.3mi

4mi  + A + (4mi + A) = 9.3mi

8mi + 2*A = 9.3mi

2*A = 9.3mi - 8mi = 1.3mi

A = 1.3mi/2 = 0.65mi

Then the distance between the house and the library is:

The 4 miles between the house and the school, plus the 0.65 miles between the school and the library:

Distance = 4mi + 0.65mi. = 4,65mi

3) The third case is when the order of the locations is:

Library, house, school.

Then the distance between the house and the library is equal to the distance between the school and the library minus the distance between the house and the school, this is:

A - 4mi = B

Now we can replace this in our distance equation:

4mi + A + B = 9.3mi

4mi + A + (A - 4mi) = 9.3 mi

2A = 9.3mi

A = 9.3mi/2 = 4.65mi

Then the distance between the house and the library is:

B = A - 4mi = 4.65mi - A = 0.65mi

Then the distance between the house and the library is 0.65 miles in this case.

Answer:

A. 1/8 of the semester

B. 3/20 of the semester

Step-by-step explanation:

A professor wants to divide the remaining 3/4 of the semester evenly into 6 different units. A. What fraction of the semester should be spent on each unit?

B. The professor drops one unit. What fraction of the semester should be spent on each unit?

Solution

A.

A professor wants to divide the remaining 3/4 of the semester evenly into 6 different units

Total semester=3/4

Total units=6 units

Fraction of the semester that will be spent on each units = 3/4 ÷ 6

=3/4 × 1/6

=3/24

=1/8

1/8 of the semester will be spent on each units

B. If the professor drops one unit

That is 6 units - 1 unit = 5 units

Fraction of the semester that will be spent on each units=3/4 ÷ 5

=3/4 × 1/5

=3/20

Answer:

31

Step-by-step explanation:

=3^2+(8-2)x4-6/3​

=9+6 x 4 - 2

=9+24-2

=31

Answer:

31

Step-by-step explanation:

9+6*4-6/3

9+6*4-2

9+24-2

31

Answer:

Step-by-step explanation:

The world parlance represents jargon/terms used by a particular profession or by a group of related experts in a field.

In french parler, means "to speak, hence the word parlance has it root from the french word parler.

it is a noun and it often called a slang or a jargon.

for example in law, lawyers use world/terms like, plaintiff, witness, suspect, jury, etc

The terminology that is specific to a particular profession or group is called; Jargons

We are given examples such as;

T-tests, chi-square tests, confidence intervals being used exclusively by statisticians.

Now, these terms used exclusively by statisticians have a general term they are called which is Jargons.

In conclusion, Jargons is the general name for words or expressions that are used exclusively by a group that are not easy for others to understand.

Read more at; https://brainly.com/question/12320553

Answer:

i.  [tex]P(A) = \frac{1}{10}[/tex]

ii.  [tex]P(B) = \frac{1}{10}[/tex]

iii.   [tex]P(A) = \frac{3}{5}[/tex]

iv.   [tex]P(B) = \frac{2}{5}[/tex]

Step-by-step explanation:

Given

Time: 07 2(A) 5(B)

Calculating (a)

First, we need to list out the possible sample space, S of A

[tex]S = \{0,1,2,3,....,9\}[/tex]

[tex]n(S) = 10[/tex]

Probability of A being a 4 is the number of occurrence of 4 divided by the number of sample space

[tex]A = \{4\}[/tex]

[tex]n(A) = 1[/tex]

Hence;

[tex]P(A) = \frac{n(A)}{n(S)}[/tex]

[tex]P(A) = \frac{1}{10}[/tex]

Calculating (b)

First, we need to list out the possible sample space, S of B

[tex]S = \{0,1,2,3,....,9\}[/tex]

[tex]n(S) = 10[/tex]

Probability of B being a 8 is the number of occurrence of 8 divided by the number of sample space

[tex]B = \{8\}[/tex]

[tex]n(B) = 1[/tex]

Hence;

[tex]P(B) = \frac{n(B)}{n(S)}[/tex]

[tex]P(B) = \frac{1}{10}[/tex]

Calculating (c)

Using the sample space in (a)

[tex]n(S) = 10[/tex]

Probability of A being less than 6 is the number of occurrence of less than 6 divided by the number of sample space

[tex]A = \{0,1,2,3,4,5\}[/tex]

[tex]n(A) = 6[/tex]

Hence;

[tex]P(A) = \frac{n(A)}{n(S)}[/tex]

[tex]P(A) = \frac{6}{10}[/tex]

[tex]P(A) = \frac{3}{5}[/tex]

Calculating (d)

Using the sample space in (b)

[tex]n(S) = 10[/tex]

Probability of B being greater than 5 is the number of occurrence of greater than 5 divided by the number of sample space

[tex]B = \{6,7,8,9\}[/tex]

[tex]n(B) = 4[/tex]

Hence;

[tex]P(B) = \frac{n(B)}{n(S)}[/tex]

[tex]P(B) = \frac{4}{10}[/tex]

[tex]P(B) = \frac{2}{5}[/tex]