A company believes it has a 40% chance of being successful on bidding a contract that yields a net profit of $30,000. Assume it costs $5,000 in consultant fees to prepare the bid. What is the expected gain or loss for the company if it decides to bid on the contract?

Answer:

If we subtract 14 from both sides of the equation for RU, we get 6p = RU - 14, or 6p = RU - 14. We can then substitute this expression for 6p into the equation for ST to get:

ST = p + 31

ST = (RU - 14) + 31

Expanding RU, we get:

ST = RU - 14 + 31

ST = RU + 17

Since RU = 6p + 14, we can substitute this expression into the above equation to solve for p:

ST = 6p + 14 + 17

ST = 6p + 31

Finally, we can subtract 31 from both sides of the equation to find p:

ST - 31 = 6p + 31 - 31

ST - 31 = 6p

ST - 31 = 6p

p = (ST - 31) / 6

So, to find the value of p, we need to know the value of ST.

The size of angle BAC in the given circle is 50°

A circle is a round-shaped figure that has no corners or edges. In geometry, a circle can be defined as a closed, two-dimensional curved shape.

Since, no figure is given, we will draw a circle according the given information, [attached in the solution]

So, we get a circle with center O, having chords, BC, which is extended to F, DC and AB,

We have, Angle CBD = 28° and angle FCD = 78°

Therefore,

∠ DCB = 180° - ∠ DCF [Linear pair]

∠ DCB = 180° - 78°

∠ DCB = 102°

In Δ DCB,

∠ DCB + ∠ BCD + ∠ BDC = 180°

∠ BDC = 180° - (102°+28°)

∠ BDC = 50°

Since, the angles made by the same chord are equal in measure,

Therefore,

∠ BDC = ∠ BAC

Therefore,

∠ BAC = 50°

Hence, the size of angle BAC in the given circle is 50°

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The formula for the sum of cubes of the first n natural numbers is:

(1³+2³+3³+ ... + n³) = (1 + 2 + 3 + ... + n)²

Let us consider:

A(n)=1³+2³+⋯+n³--------(1)

B(n)=(1+2+⋯+n)²---------(2)

Now plug the numbers in the above equations(1)&(2) then,we get:

A(1)=B(1)=1

A(2)=B(2)=9

A(3)=B(3)=36

A(4)=B(4)=100

A(5)=B(5)=225

So both A and B are polynomials of degree at most 4 on n, and they coincide at 5 points.

Hence A(n) = B(n) for all n.

In general, p(n) is a polynomial of degree d on n,

∑kn=1 P(k)

is defined as a polynomial of the degree of d+1 on n. This trick will help solve every single issue involving the summation of polynomials, and then find the value on d+2 points, and we will determine the sum for all n.

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Work Shown:

[tex](f+g)(\text{x}) = f(\text{x})+g(\text{x})\\\\(f+g)(\text{x}) = (\text{x}+3)+(\text{x}^2-2)\\\\(f+g)(\text{x}) = \text{x}^2+\text{x}+1\\\\(f+g)(2) = 2^2+2+1\\\\(f+g)(2) = 4+2+1\\\\(f+g)(2) = 7\\\\[/tex]

----------------------------

Another approach:

[tex]\begin{array}{lll}f(\text{x}) = \text{x}+3& & g(\text{x}) = \text{x}^2-2\\f(2) = 2+3 & \text{ and } & g(2) = 2^2-2\\f(2) = 5 & & g(2) = 2\\\end{array}\\\\\\\text{Therefore, } (f+g)(2) = f(2)+g(2) = 5+2 = 7[/tex]

Answer: $14.22

Step-by-step explanation: 237*0.06

Step-by-step explanation:

The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. If a line is parallel to another line, it means they have the same slope. To find the slope of the line 7x - y = 3, we can rearrange it into slope-intercept form: y = 7x - 3. So, the slope of the line 7x - y = 3 is 7.

Since the line we want to find is parallel to 7x - y = 3 and has a slope of 7, the equation of the line can be written as y = 7x + b, where b is the y-intercept. To find b, we use the point (6, 3) as a solution:

y = 7x + b

3 = 7 * 6 + b

3 = 42 + b

b = -39

So, the equation of the line that passes through (6, 3) and is parallel to 7x - y = 3 is y = 7x - 39.

A group of students and adults are going to the museum and have spent a total of $115 on tickets. Adult tickets cost $5 each and student tickets cost $3 each. There are 25 more students than adults in the group therefore the number of students are in the group are 35 and the number of adults in the group are 5.

This is referred to as the value of money that has been used up to produce something or deliver a service.

Since we were told that  Adult tickets cost $5 each and student tickets cost $3 then  $5 × 5 = $25 and $3 × 30 = $90. Therefore the total is $115.

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The eigenvalues of a matrix are roots of its characteristic polynomial using this we prove  that a square matrix and its transpose have the same characteristic polynomial.

A collection of numbers lined up in rows and columns to form a rectangular array is called a matrix. The elements, or entries, of the matrix are the integers. In addition to numerous mathematical disciplines, matrices find extensive use in the fields of engineering, physics, economics, and statistics. In computer graphics, where they have been used to describe picture rotations and other transformations, matrices have vital applications as well.

Recall that the eigenvalues of a matrix are roots of its characteristic polynomial.

Hence if the matrices A and A Transpose have the same characteristic polynomial, then they have the same eigenvalues.

So we show that the characteristic polynomial pA(t)=det(A−tI) of A is the same as the characteristic polynomial p[tex]A^T[/tex] (t)=det(A ^T−tI)of the transpose [tex]A^T[/tex].

We have,

p[tex]A^T[/tex](t)=det([tex]A^T[/tex] −tI) =det([tex]A^T[/tex] −tI T )

=det((A−tI) [tex]A^T[/tex] )

=det(A−tI)

=pA(t)

Since I ^T =I

Since det([tex]B^T[/tex] )=det(B)for any square matrix B

Therefore, we obtain p[tex]A^T[/tex] (t)=pA(t), we conclude that the eigenvalues of A and [tex]A^T[/tex] are the same.

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As a result, the original discounted price is $1 while the weekly normal price is $9.

The fundamental formula for calculating a reduction is to increase the initial price by the provided percentage rate in decimal form. We must deduct the reduction from the initial price to determine the item's sale price.

From the given information, we have:

d + 6x = 55 (discounted price for 7 weeks)

d + 11x = 100 (discounted price for 12 weeks)

We can solve this system of equations by eliminating d. Subtracting the first equation from the second, we get:

5x = 45

Dividing both sides by 5, we get:

x = 9

Substituting x = 9 into one of the equations, we can solve for d. Using the first equation, we get:

d + 6(9) = 55

d + 54 = 55

d = 1

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Answer:

[tex]y=x-2[/tex]

Step-by-step explanation:

The slant, or oblique asymptote, is found by taking the quotient of the two polynomials and disregarding the remainder:

-3 |  1  1  2

____  -3_6

      1 -2 | 8

Hence, our slant asymptote is [tex]y=x-2[/tex]

The length of a pendulum that makes one full swing in 1.9 seconds is 3 feet.

As per the given data, the given formula is:

[tex]$T=2 \pi \sqrt{\left(\frac{L}{32}\right)}[/tex] gives the time it takes in seconds.

Where,

T is the time it takes for a pendulum to make one full swing back and forth (in seconds).

L is the length of the pendulum, in feet.

Here we need to find the length of a pendulum that makes one full swing in 1.9 seconds to the nearest foot.

Substitute the given parameters into the formula will give;

[tex]$1.9=2 \pi \sqrt{\left(\frac{L}{32}\right)}[/tex]

Now divide both sides by 2π.

[tex]$ \frac{1.9}{2 \pi}=\sqrt{\left(\frac{L}{32}\right)} \\[/tex]

[tex]$ 0.3024=\sqrt{\left(\frac{L}{32}\right)}[/tex]

Then taking square on both sides.

[tex]$ (0.3024)^2=\frac{L}{32} \\[/tex]

0.09144576 = [tex]$\frac{L}{32}[/tex]

Later multiply both sides by 32.

2.9262 = L

The approximate value of the length of a pendulum:

L ≈ 3

Therefore, the length of a pendulum is about 3 feet.

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Answer:

the number is 78

Step-by-step explanation:

call x is the tens digit (0<x<9)

y is the unit digit (0[tex]\leq[/tex]y[tex]\leq[/tex]9)

we have:

10y+x=[tex]\oveline{yx}[/tex] (1)

10x+y= [tex]\overline{xy}[/tex] (2)

acording (1),(2) and the topic we have: (10y+x)-(10x+y)=9 ⇔9y-9x=9

⇔y-x=1 (3)

and x+y=15 (4)

from (3), (4) we have a system of equation

[tex]\left \{ {{y-x=1} \atop {x+y=15}} \right.[/tex]

⇔[tex]\left \{ {2y=16} \atop {x+y=15}} \right.[/tex]

⇔[tex]\left \{ {{y=8} \atop {x+8=15}} \right.[/tex]

⇔[tex]\left \{ {{y=8} \atop {x=7}} \right.[/tex] (conditions are satified)

the number is 78

Answer: 4.8

Step-by-step explanation:

6.4 - 1.6 = 4.8

Answer:

[tex]6 {}^{3x} [/tex]

Step-by-step explanation:

Given expression to us is ,

2^{-x} . 3^{-x} . 6^{2x} . 3^{2x} . 2^{2x}

We can rewrite it as ,

[2^{-x} . 2^{2x} ] [ 3^{-x} . 3^{2x}] . 6^{2x}

we know a^m . a^n = a^{m+n} , so ;

2^{-x +2x} . 3^{-x+2x} . 6^2x

simplify,

2^x . 3^x . 6^{2x}

we know a^m . b^m = (ab)^m , so ;

(2*3)^x . 6^{2x}

6^x . 6^2x

6^{x+2x}

6^{3x}

And we are done!

Answer:

[tex]6^{3x}[/tex]

Step-by-step explanation:

Given exponential expression:

[tex]2^{-x} \cdot 3^{-x} \cdot 6^{2x} \cdot 3^{2x} \cdot 2^{2x}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^n \cdot c^n=(a \cdot c)^n:[/tex]

[tex](2\cdot 3)^{-x} \cdot 6^{2x} \cdot (3 \cdot 2)^{2x}[/tex]

Multiply the numbers:

[tex]6^{-x} \cdot 6^{2x} \cdot 6^{2x}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]6^{(-x+2x+2x)}[/tex]

Therefore:

[tex]6^{3x}[/tex]

Answer:y=5/3 x-5

Step-by-step explanation: first find the y-intercept, when the x value is 0 that is the y intercept, then the equation becomes -3x=15, there you get

x=-5, then do the same to the other to get the x value so you get the points (0,-5), and (3,0) there you find the slope and plug in

The variance clearing account is used to accumulate individual variances until they can be allocated to their respective variance accounts, and the formula used to calculate the variance clearing account is the sum of all the individual variances, plus the beginning balance of the account.

A variance clearing account is a temporary ledger account used to accumulate individual variances such as direct labor cost, direct material cost, and overhead cost. The variance clearing account is used to collect all the individual variances in one account until it can be allocated to its respective variance accounts. This account has a debit side and a credit side. The debit side of the variance clearing account is used to accumulate all the unfavorable variances, while the credit side is used to accumulate all the favorable variances.

The formula used to calculate the variance clearing account is the sum of all the individual variances, plus the beginning balance of the account. This can be expressed as follows:

Variance Clearing Account = Beginning Balance + Sum of All Individual Variances

For example, if the beginning balance of the variance clearing account is $500, and the sum of all individual variances is $400, the balance in the variance clearing account would be $900 ($500 + $400). This balance can then be allocated to the respective variance accounts.

The variance clearing account is used to accumulate individual variances until they can be allocated to their respective variance accounts, and the formula used to calculate the variance clearing account is the sum of all the individual variances, plus the beginning balance of the account.

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Answer:

7cm²

Step-by-step explanation:

volume of a triangular prism=1/2×b×h×l

1/2×b×h=cross sectional area

84cm³=C.A×12

C.A=84/12

base area=7cm²

The z score is -0.18 and 57 % of all Atlantic cod have more than 49.23 cm in length and

The relationship between a value and the mean of a set of values is expressed numerically by a Z-score. The Z-score is computed using the standard deviations from the mean. A Z-score of zero indicates that the data point's score and the mean score are identical.

The Z-score is calculated using the formula:

z = (x - μ)/σ

where z: standard score

x: observed value

μ: mean of the sample

σ: standard deviation of the sample

Given data ,

Let the probability that a randomly selected Atlantic cod has a length of 53.68 cm or less be represented as P

Now , the equation will be

The observed value of be x

The mean of the sample μ = 49.9 cm

The standard deviation of the sample σ = 3.74 cm

Now , z-score is calculated using the formula:

z = (x - μ)/σ

And , the length of 57% of all Atlantic cod have more than is calculated by

Now , the z score with a p value of 0.43 is

z = -0.18

Substituting the values in the equation , we get

-0.18 = ( x - 49.9 ) / 3.74

Multiply by 3.74 on both sides of the equation , we get

-0.6732 = x - 49.9

Adding 49.9 on both sides of the equation , we get

x = 49.2268 cm

Hence , 57 % of all Atlantic cod have more than 49.2268 cm in length and the z score is -0.18

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This means that the average sale price for a home in this sample was "$773" and that half the sales were for less than the median price of "$577", while half were more than the median price of "$577".

(a) To calculate the sample mean, we add up all the values and divide by the number of values:

x = (592 + 817 + 577 + 608 + 353 + 1,281 + 412 + 535 + 550 + 679)/10 = 7,727/10 = $773

The sample median is the middle value when all the values are ordered from smallest to largest:

353, 412, 535, 550, 577, 608, 592, 679, 817, 1,281

The median is 577.

This means that the average sale price for a home in this sample was $773 and that half the sales were for less than the median price of $577, while half were more than the median price of $577.

(b) If the 6th observation had been 985 rather than 1,281, the new mean would be calculated as:

x = (592 + 817 + 577 + 608 + 353 + 985 + 412 + 535 + 550 + 679)/10 = 7,610/10 = $761

The new median would still be $577.

(c) To calculate a 20% trimmed mean, we first need to find the two smallest and two largest observations, then remove them and take the average of the remaining values:

Two smallest: 353, 412

Two largest: 1,281, 817

Remaining values: 535, 550, 577, 608, 592, 679

The trimmed mean is (535 + 550 + 577 + 608 + 592 + 679)/6 = $592

(d) To calculate a 15% trimmed mean, we first need to find the three smallest and three largest observations, then remove them and take the average of the remaining values:

Three smallest: 353, 412, 535

Three largest: 817, 1,281, 679

Remaining values: 550, 577, 608, 592

The trimmed mean is (550 + 577 + 608 + 592)/4 = $576.

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The total surplus received by both Patricia and Cecilia is $55.

The process of combining two or more numbers is called the Addition. The 4 main properties of addition are commutative, associative, distributive, and additive identity.

Given that;

Patricia decides to buy a pair of boots for $90.00. She was willing to pay $120.00.

And, Her friend Cecilia sees the boots, she loves them and thinks they are worth $170.00. So she offers Patricia $145.00 for the boots, and Patricia accepts.

Hence, Consumer surplus is the difference between the willingness to pay of a consumer and the price of the good.

Consumer surplus = willingness to pay – price of the good

Consumer surplus received by Patricia = $120 - $90 = $30

Consumer surplus received by Cecilia = $170 - $145 = $25

Thus, Sum of the surpluses = $30 + $25 = $55

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Answer:

Cosine (cos)

Step-by-step explanation:

Sine, Cosine, and Tangent have their own properties.

Cosine is adjacent over hypotenuse. We have the angle of 59, the line adjacent is 17 and the hypotenuse is x. You could also do it for the right angle.

l=7m

Step-by-step explanation:

here us the answer of the solution

An equation of the best-fit line of data can be used to estimate untested values. Graphical data can be used to show relationships between variables, but those relationships do not have to be linear and do not always have a positive relationship.

Graphical data is a way of visually representing information in a way that can be easily understood. It is often used to determine relationships between variables, such as the relationship between prices and sales. Graphical data can be used to show correlations, even if the relationship is not linear. An equation of the best-fit line of data can be used to estimate untested values, which can be useful in predicting future values. The x-values and y-values of a graph can both be estimated based on the data presented, and do not necessarily need to start at the origin. Graphical correlations can have both positive and negative relationships, depending on the data presented. Graphical data can be a powerful tool for understanding relationships between data points.

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]Answer:

The area of a rectangle is calculated by multiplying its length by its width. If the length of the rectangle is 7 and its width is 4x, the area can be found by performing 7 * 4x. The answer would be 28x square units, where x represents the unit of measurement.

Solve for x in one of the equations and substitute it into the other equation.

To solve the system of equations 3x + 5y = 25 and x - 2y = -6 using substitution, we first solve for x in one of the equations. Let's solve for x in the second equation: x = 2y + 6. Next, we substitute this expression for x into the first equation: 3(2y + 6) + 5y = 25. This gives us 6y + 18 + 5y = 25, which simplifies to 11y + 18 = 25. Finally, we subtract 18 from both sides to obtain 11y = 7, and divide both sides by 11 to find y = 7/11. Now that we have y, we can substitute it back into either equation to find x.

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The unit rate for the games per loss are:

Jules’ Rules unit rate = 3 or 3/1

Pink sox unit rate = 4 or 4/1

Go - Girl unit rate = 4 or 4/1

High- 5s unit rate = 9 or 9/1

Unit rate = Games/Losses

Jules’ Rules unit rate = 36/12

Jules’ Rules unit rate = 3 or 3/1

Pink sox unit rate = 68/17

Pink sox unit rate = 4 or 4/1

Go- Girls unit rate = 52/13

Go - Girl unit rate = 4 or 4/1

High-5s unit rate = 72/8

High- 5s unit rate = 9 or 9/1

Therefore the Jules’ Rules unit rate 3, Pink sox unit rate 4, Go - Girl unit rate 4, High- 5s unit rate 9.

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Answer: 3y + 2

Step-by-step explanation: First, you can organize the equation into -3y + 6y + 4 - 2. Then, you get 3y + 2. :)))))

Answer:

5,4,2,0

Step-by-step explanation:

f(g(4))=5

g(f(3))=4

f(f(2))=2

g(g(5))=0

The value of composition function is:

1. f(g(4)) = 5

2. g(f(3)) = 4

3. f(f(2)) = 2

4. g(g(5)) = 0

To find the value of function focus on the graph of the function.

1. f(g(4))

From the graph of g(x), when x= 4 the value of y is 2.

So, g(4) = 2

Now, the value of f(g(4))

f(g(4))= f(2)

        = 5.

2. g(f(3))

From the graph of f(x), when x= 3 the value of y is 0.

So, f(3) = 0

Now, the value of g(f(3))

g(f(3))= g(0)

        = 4.

3. f(f(2))

From the graph of f(x), when x= 2 the value of y is 5.

so, f(2)= 5

Now, the value of f(f(2))

f(f(2)) = f(5)

        = 2

4. g(g(5))

From the graph of g(x), when x= 5 the value of y is 3.

so, g(5)= 3

Now, the value of g(g(5))

g(3) = 0

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ac is congruent to pr because those sides correspond