The size of the net charge contained within the surface charge inside = total flux *ε = 0.0938*(8.85*10^-12) = 8.301*10^-13 C
What is closed surface?Total flux = charge enclosed / ε
Therefore, you must first determine the overall flux. There is only flux via the two sides that are faced along the x axis since the E field is only in the x direction.
These faces are at x = a =0.269 m (left side of box)
and x = a+c = 0.5918 m (right side of box)
Left side of box E = 2+6*x^2 = 2+6*0.388^2 = 2.903
And the flux into the left side is E*A = 2.903*0.388*0.388 = 0.437
Now right side of box E = 2+6*0.5044^2 = 3.526
flux out of the right side is 3.526*0.388*0.388 = 0.5308
Total flux = flux out - fluxin = 0.5308 - 0.437 = 0.0938
charge inside = total flux *ε = 0.0938*(8.85*10^-12) = 8.301*10^-13 C
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A uniform beam xy is 100 cm long and weighs 4. 0 n. The beam rests on a pivot 60 cm from end x. A load of 8. 0 n hangs from the beam 10 cm from end x. The beam is kept balanced by a force f acting on the beam 80 cm from end x. What is the magnitude of force f?.
To keep the balance the beam's required magnitude of force f will be 22 N.
Given,
Length of the beam, xy = 100cm
Pivoted at 60 cm from end x
Weight force at 50 cm from x, W = 4 N
force due to hanging mass, F = 8 N 10 cm from x
and f at 80 cm at x.
Now, let the direction of force f is downward
so we have to balance the moment due to all the forces about the pivot,
So the total clockwise moment
= fx(80-60) = 20f Ncm
And anti-clockwise moment
= Wx(60-50) + F(60-10) = 4x10+8x50 = 440 Ncm
Now anticlockwise moment = Clockwise moment
or 20f = 440
or f = 22 N
Therefore, To keep the balance the beam's required magnitude of force f will be 22 N.
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Gauss's Law Problem 1 (a) Consider a solid sphere of radius R where the electric charges are uniformly distributed throughout the entire sphere with a uniform volume charge density p. Find the electric field everywhere at points both inside the sphere. d (b) A charged slab extends infinitely in two dimen- sions and has thickness d in the third dimension, as shown in the right figure. The slab carries a uniform volume charge density p and is extended between z =d/2 and z= -d/2. Find the expression for the electric field inside the slab. -2=0 Id y (c) As shown in the right figure, we have a slab with a uniform volume charge den- sity p extending to infinity in the c-y plan, with a thickness d. At the center of the system, we have a spherical cav- ity of radius R with R
The electric field within the sphere is given by E = (4p/3) * (R^3 - r^3) / (R^2 - r^2). The electric field inside the slab is given by E = pd/2. The electric field at the center of the spherical cavity is given by E = pd/2 * (R/d)2.
What is electric flux?Electric flux is the measure of the electric field through a particular surface in electromagnetism, despite the fact that an electric field cannot flow. At any location in space, the electric field E can impose a force on an electric charge. The gradient of the potential is represented by the electric field.
Here,
(a) According to Gauss's Law, the electric flux through any closed surface is proportional to the charge contained inside the surface. The electric field at a location inside a solid sphere may be computed by splitting the sphere into concentric shells and calculating the electric field owing to each shell. Inside the sphere, the electric field is given by:
E = (4πp/3) * (R^3 - r^3) / (R^2 - r^2)
(b) The electric field inside a charged slab may be calculated by splitting the slab into thin charge layers and adding the electric field owing to each layer. Inside the slab, the electric field is given by:
E = pd/2
(c) Subtracting the electric field owing to the slab from the electric field due to the entire space yields the electric field at the center of a spherical cavity in an indefinitely large charged slab. The electric field at the spherical cavity's center is given by:
E = pd/2 * (R/d)^2
The electric field inside the sphere is given by: E = (4πp/3) * (R^3 - r^3) / (R^2 - r^2). The electric field inside the slab is given by: E = pd/2. The electric field at the center of the spherical cavity is given by: E = pd/2 * (R/d)^2.
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when the velocity and acceleration of an object have opposite signs, the speed of the object increases. T/F
when the velocity and acceleration of an object have opposite signs, the speed of the object increases, is true statement.
What is velocity and how is it related to acceleration?Velocity is a vector quantity that represents the rate of change of an object's position with respect to time, including both the speed and direction of motion. It is defined as the derivative of position with respect to time. Acceleration and velocity are closely related quantities in mechanics. Acceleration is defined as the rate of change of velocity over time. In other words, acceleration is the derivative of velocity with respect to time. When an object's velocity is increasing, its acceleration is positive, and when its velocity is decreasing, its acceleration is negative. If an object is moving at a constant velocity, its acceleration is zero.
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an 80 kg man and 50 kg woman stand 0.5 m from each other. what is the force of gravitational attraction between the couple?
The force of gravitational attraction between the man and woman is 1.0672 × 10⁻⁶ N, if the mass of the man & woman is 80 kg & 50 kg respectively.
Let the Mass of the man, m₁ = 80 kg
Mass of the woman, m₂ = 50 kg
Distance between them, d = 0.5 m
We know the universal gravitational constant, G = 6.67 × 10⁻¹¹ Nm²/kg²
According to Newton's law of gravitation, Gravitational force between two objects having mass m₁ & m₂ at a distance apart d meter, is mathematically formulated as, F = Gm₁m₂/d²
F = (6.67 × 10⁻¹¹ × 80 × 50)/0.5²
F = (2.668 × 10⁻⁷) /0.25
F = 1.0672 × 10⁻⁶ N
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sketch at least two cycles of the voltage vs time graph for an ideal periodic digital waveform with a 1.0 volt amplitude, a 12 us period and a 25% duty cycle. label your axes clearly. what is the frequency of this waveform?
The sketch for the voltage vs time graph for an ideal periodic digital waveform with a 1.0 volt amplitude, a 12 us period and a 25% duty cycle would look like this:
The x-axis represents time and the y-axis represents voltage.The frequency of this waveform is 83.3 kHz (1/12 us).The voltage vs time graph for an ideal periodic digital waveform with a 1.0 volt amplitude, a 12 us period and a 25% duty cycle is a type of waveform that is commonly used in digital electronics. This type of waveform is important because it is used to represent the logical states of digital circuits, such as 0's and 1's.
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true/false - Sonar uses sound waves to measure water depth
Sonar (SOund Navigation And Ranging) uses sound waves to estimate water depth. It operates by producing a sound wave and monitoring how long it takes for the wave to bounce back after striking the ocean floor. The depth of the water may be determined based on this time measurement.
What is SONAR?Sonar is a technology for navigating, measuring distances, communicating with, or detecting things on or beneath the water's surface, such as other vessels. Sonar (from "sound navigation range") is an acoustic technology for detecting and estimating the distance and direction of underwater objects. Sonar equipment detects and analyzes sound waves generated or reflected by the item for the information they convey. sonar.
Here,
Sonar (SOund Navigation And Ranging) does utilize sound waves to estimate water depth. It operates by sending out a sound wave and monitoring how long it takes for the wave to bounce back after reaching the ocean floor. The depth of the water may be determined using this time measurement.
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You hit a ball with a bat that delivers 100 N of force. Which of the following scenerios will give the ball the greatest speed.
Time doesnt matteronly the force does.
Try to apply the 100 N force for 0.01 s.
Try to apply the 100 N force for 0.1 s
Try to apply the 100 N force for 0.2 s.
None of these
Answer:
Try to apply the 100 N for 0.2 s.
four or fewer luminaire conductors, smaller than awg, and/or small equipment grounding conductors that originate in the luminaire and terminate in the box, need not be counted when calculating box fill. a. 8 b. 10 c. 12 d. 14
Option a. 8 is the correct answer because Four or fewer luminaire conductors, smaller than AWG size, and small EGCs.
It's essential to guarantee that crates or nooks that contain electrical associations have sufficient space to oblige the transmitters and hardware establishing conveyors (EGCs) without surpassing the case fill limits determined by the Public Electrical Code (NEC).
As per the NEC, four or less luminaire channels, less than American Wire Check (AWG) size, and additionally little EGCs that start in the luminaire and end in the container need not be counted while computing box fill.
This standard is intended to give a specific level of adaptability and diminish the intricacy of box fill estimations, particularly in lighting establishments where luminaire guides and little EGCs are usually utilized. Notwithstanding, it's vital to take note of that this avoidance just applies to the guides and EGCs referenced, and different guides and fittings that consume space inside the container actually should be thought about while computing box fill.
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WILL MARK BRAINLIEST!!
A truck of a mass of 2 tons is traveling north at a speed v=70 km/h collides with a car of mass of 1.2 tons moving south at an equal speed. After collision, both vehicles remain tangled together.
With what speed and in what direction does the wreckage move?
(Would love it if it's solved in the GUESS method, but if not it's okay!)
The final speed of the wreckage after the collision is 17.5 km/h north.
What is the final speed of the wreckage after the collision?
The final speed of the wreckage after the collision is calculated by applying the principle of conservation of linear momentum.
m₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is the mass of the truckm₂ is the mass of the caru₁ is the initial speed of the trucku₂ is the initial speed of the carv is their final speed after the collisionlet north be positive and let south be negative direction
The final speed is calculated as follows;
(2 x 70) - (1.2 x 70) = v ( 2 + 1.2 )
56 = 3.2v
v = 56/3.2
v = 17.5 km/h north
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how many milliseconds after the switch opens is the energy stored in the capacitor 79 % of its final value?
The time cannot be calculated without those values but if we take R= 1 and C= 1, the switch opens at almost 4 milliseconds according to the question.
The time constant, τ, of the RC circuit would be τ = R × C = 1 × 1 = 1 (Where R denotes the resistance and C the capacitance).
The time it takes for the energy stored in the capacitor to fall to 79% of its final value after the switch opens is approximately equal to
4 × τ = 4 × 1 = 4 milliseconds.
After the switch opens, it takes around 4 times for the energy stored in the capacitor to decrease to 79% of its final amount.
Therefore, knowing the values of R and C is necessary in order to calculate the time in milliseconds. The time cannot be calculated without those values.
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a centripetal force of 155 n acts on a 1,500-kg satellite moving with a speed of 5,300 m/s in a circular orbit around a planet. what is the radius of its orbit?
A centripetal force of 155 n acts on a 1,500-kg satellite moving with a speed of 5,300 m/s in a circular orbit around a planet. The radius of its orbit is 1.35 x [tex]10^{7}[/tex] meters.
The radius of a satellite's orbit can be calculated using the equation for centripetal force:
F = m * [tex]v^{2}[/tex]/ r
Where,
m = the mass of the satellite
v = its speed
r = the radius of its orbit.
Rearranging the equation and plugging in the given values:
r = m * [tex]v^{2}[/tex] / F = (1500 kg) * [tex](5300 m/s)^{2}[/tex] / (155 N)
r = approximately 1.35 x [tex]10^{7}[/tex] meters.
So the radius of the satellite's orbit is approximately 1.35 x [tex]10^{7}[/tex] meters.
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What is the correct way to report the length of the rectangle in centimeters? Select one: 15.60 cm 15.6 cm 15.600 cm 16 cM
The correct way to report the length of the rectangle in centimeters is 15.60 cm.
What do you mean by significant figures ?The number that is given as digits is established using significant figures. A meaningful representation of numbers is carried by these digits. Frequently, significant digits are employed in place of figures.
By counting all of the values beginning with the first non-zero digit on the left, we may determine the number of significant digits. 12.45, for instance, has four significant digits.
The act of determining an object's length in some standard or non-standard units is known as length measurement. In our daily lives, the ability to measure length is crucial.
Therefore, The correct way to report the length of the rectangle in centimeters is 15.60 cm.
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A positive charge and a negative charge held near each other are released. As they move, the force on each particle a. increases. b, decreases. c. stays the same.Â
Placing a conductor increases the force between two charges because in the case of glass or other dielectrics, the effective distance between two charges rises as opposed to decreasing.
What occurs when a positive and negative charge are in close proximity to one another?Each charge repels the other. When a positive charge and a negative charge interact, their forces move from the positive to the negative charge in the same manner. Because of this, opposing charges are drawn to one another: the ensuing forces and electric field created by two electrical charges with different polarities.
What is the definition of Coulomb's law of force between charges?Coulomb listed the following characteristics of the electric force for charges in a resting state: Unlike charges attract each other whereas like charges repel one another. the two positive charges attract a negative charge, while negative charges repel one another.
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Paper clip Y is not attracted to the magnet. Which step should the student take to attract it?
O A The student should use a battery with less energy.
O
8
D
The student should use a smaller core in the magnet.
The student should wrap the coil fewer times around the nail.
The student should move the magnet closer to the paper clip.
Answer:d
Explanation:magnet is to weak
Answer: that means to shut your trap you little turd
Explanation:
Help please!!! What is the difference between corrosive and flammable?
Answer:
Explanation:
Most corrosive materials are non-flammable, except for acetic acid and formic acid. However, nitric acid and perchloric acid are oxidizers and should be segregated from combustible and flammable materials. Corrosive materials can have other hazards, however, the corrosivity is usually the primary hazard.Flammable liquids burn at normal working temperatures while combustible liquids need heat before they will ignite All this info should help…. ✨
An airplane flying North at 98. 7 m/ encounter a 47. 5 m/ headwind. What i the airplane’ peed relative to the ground?
Answer:
51.2 m/
Explanation:
The headwind will slow down the airplane and make it move slower relative to the ground 98.7 - 47.5 = 51.2 m/ relative to ground
1–61. if the 60-mm diameter shaft is subjected to an axial force of 5 kn, determine the average shear stress developed in the shear plane where the collar a and shaft are connected.problems 1–60/61
The average shear stress developed in the shear plane where the collar A and shaft are connected is 50.265 kPa.
The average shear stress can be calculated using the formula:
τ_avg = F / A
where F is the applied axial force of 5 kN and A is the shear area.
The shear area can be calculated using the formula:
A = π * d * t
where d is the diameter of the shaft (60 mm) and t is the thickness of the collar (15 mm).
Substituting the values, we get:
A = π * 60 * 15 * 10^-6 m^2
Calculating the average shear stress:
τ_avg = 5 kN / (π * 60 * 15 * 10^-6 m^2) = 50.265 kPa
Therefore, the average shear stress developed in the shear plane where the collar A and shaft are connected is 50.265 kPa.
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the terminator of a gene is located upstream of the coding region. TRUE OR FALSE
False. The terminator of a gene is located downstream of the coding region.The terminator of a gene is a DNA sequence that signals the end of transcription, or the process by which genetic information is converted from DNA to RNA.
It is located downstream of the coding region, which is the part of the gene that contains the instructions for making a particular protein. The terminator helps to regulate the amount of mRNA that is produced, as well as to prevent the production of unwanted transcripts. The precise location and sequence of the terminator vary among different genes, but its role in regulating transcription is an important aspect of gene expression.
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charge q1 = 3.00 nc is at x1 = 0 and charge q2 = 7.50 nc is at x2 = 4.00 m. at what point between the two charges is the electric field equal to zero
The point between the two charges where the electric field equal to zero is calculated to be 1.55 m.
The charge q₁ is given as 3 nc = 3 × 10⁻⁹ c
It is located at x₁ = 0.
The charge q₂ is given as 7.5 nc = 7.5 × 10⁻⁹ c
It is located at x₂ = 4 m.
Let us suppose that, electric field is zero at the point x, it is in between 0 and 4 m.
We know the formula for electric field as,
E = k q /r²
Let us equate the electric field at both the charges.
k q₁/x² = k q₂/(x₂ - x)²
q₁ (x₂ - x)² = q₂ x²
3 × 10⁻⁹× (4 - x)² = 7.5 × 10⁻⁹ × x²
3 × ( 16 + x² - 8x) = 7.5 ×x²
48 + 3x² - 24x = 7.5x²
4.5 x² + 24x - 48 = 0
The two values of x are,
x = 1.55, -6.883
The distance cannot be negative. So, the electric field at x = 1.55 m is said to be zero.
Thus, the required value of x is 1.55 m.
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two charges are on the x-axis (see below). charge 1 is is 50.0 nc and is located 20.0 cm to the left of the origin. charge 2 is located 35.0 cm to the right of the origin. 1) what is the magnitude and direction of the electric field at the origin due to charge 1?
The electric field due to charge 1 at the origin is 2.24 x 10^5 N/C in the direction to the left.
What is Coulomb's Law?Coulomb's Law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. It is represented as F = (k * q1 * q2) / r2, where F is the force, k is a constant, q1 and q2 are the charges, and r is the distance between the two particles.
Charge 1: 50.0 nC, located 20.0 cm to the left of origin
Charge 2: 35.0 cm to the right of origin
Using Coulomb's Law, the electric field at the origin due to charge 1 is:
E1 = kQ1/r^2
Where:
k = 8.99 x 10^9 Nm^2/C^2
Q1 = 50.0 nC = 5.00 x 10^-7 C
r = 20.0 cm = 0.20 m
Therefore,
E1 = (8.99 x 10^9 Nm^2/C^2)(5.00 x 10^-7 C)/(0.20m)^2
E1 = 2.24 x 10^5 N/C
Hence, the electric field due to charge 1 at the origin is 2.24 x 10^5 N/C in the direction to the left.
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The accelerations possible for a ball on an incline plane
A. Range from g to infinity
B. Have no limit
C. Range for 0 to g
A ball on an inclined plane (C) can accelerate at speeds between 0 and g.
An inclined plane, also referred to as a ramp, is a flat supporting surface that is tilted at an angle and has one end that is higher than the other.
One of the six simple machines, the inclined plane helps raise or lower a load. The unbalanced force causes objects placed on an inclined plane to accelerate.
In an inclined plane, the normal force does not act in the way that we are used to. Up until this point, normal force has always been seen to be directed upward, counter to the pull of gravity.
The truth is that normal forces are not always upward.
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A proton is located at <0, 4 × 10-8, 0> m. What is the force on the proton, due to the dipole? (Express your answer in vector form.)F→ on p+bydipole =< , , > N
Proton is subject to a dipole-induced force of F = 32.40 10-15 N. [(proh-ton)] A positively charged elementary particle that can be found in the atom's nucleus.
A proton, a subatomic particle, is found in the nucleus of every atom. The particle has a positive electrical charge, similar to the electron but moving in the other direction. The H+ ion or the hydrogen atom's nucleus are examples of protons. Each hydrogen atom, regardless of isotope, has one proton, each helium atom, two, each lithium atom, three, and so on. The electron, which is negatively charged, is a very light particle. These electrons go around the nucleus in different orbits. Protons are positively charged particles that have a mass of about 1 amu. These positively charged particles are found in the center of the atom, the nucleus.
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the force that charge q1 exerts on q2 is opposite and ________ the force that charge q2 exerts on q1.
The force that charge q1 exerts on q2 is opposite and equal in magnitude to the force that charge q2 exerts on q1.
What is charge?
Charge is a physical property of matter that can be either negative or positive. It is related to the electromagnetic force, and is measured in coulombs. Charge is the cause of electric fields and electric potential, which are important in many areas of physics and chemistry. Charge can be transferred from one object to another, and is conserved in any physical process. Charge can also be created from the motion of matter through a medium, such as when electrons are pushed from one material to another. Charge is always conserved, meaning that the net charge of a system will always be the same.
Therefore, The force that charge q1 exerts on q2 is opposite and equal in magnitude to the force that charge q2 exerts on q1.
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which of the following statements is not one of newton's laws of motion? group of answer choices in the absence of a net force, an object moves with constant velocity. for any force, there always is an equal and opposite reaction force. what goes up must come down. all of the above are newton's laws of motion. the rate of change of momentum of an object is equal to the net force applied to the object.
"What goes up must come down." is not newton's law. Option C is the correct option.
What is laws?
Laws of Physics are by definition stated facts that have been derived and inferred from empirical observations. Simply put, physical laws are a way to categorize how the world behaves and interacts with us.
Newton's laws are:
First law:
Unless a force acts upon a body that is at rest or moving in a straight line at a constant speed, it will continue to be at rest or move in that direction.
Second law:
A numerical description of the modifications to a body's motion that a force can cause. According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction.
Third law:
When two bodies come into contact, they exert forces on one another that are both equal in strength and directed in opposing directions.
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a 150 watt bulb has a surface area of 15 cm, a radius 0.05 m and an emissivity of 0.85. what is the temperature?
The temperature of a 150-watt bulb having a surface area of 15 cm², a radius of 0.05 m, and an emissivity of 0.85 is 1200K.
According to the Stefan-Boltzmann law, P=eσAT⁴. The power of the bulb is 150 watts. The value of emissivity, e=0.85, and the radius, r=0.05m. The surface area, A= 15 cm²= 0.0015 cm². The value of the Boltzmann constant,σ =5.67×10⁻⁸ Wm² K⁴. So, the temperature,T⁴= P/eσA = 150/(0.85×5.67×10⁻⁸×0.0015) =(150×10⁸)/ (0.85×5.67×0.0015) = 20750×10⁸. Therefore Temperature,T= (20750×10⁸)^¼ = 1200 K.
So the temperature of the 150-watt bulb is 1200 K. Stefan-Boltzmann describes about the power that is radiated by a black body in terms of temperature. It states that the amount of radiation emitted by a black body per unit area is directly proportional to the fourth power of the temperature. While the typical situation is envisioned here is the radiation of a hot object to its cooler surroundings, this law is not limited here.
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Four point-like charges are placed as shown in the figure, three of them are at the corners and one at the center of a square, 30.0 cm on each side. Find the magnitude of the net electrostatic force exerted on the point charge q4. Let q1 = q 3 = +31.0 pC, q2 = -23.0 µC, and q4 = -45.0 µC.
As a result, the point charge q₄ experiences a net electrostatic force of 4.80 x 10⁻² N.
What is the charge?The sum of the forces exerted on the point charge q₄ by the three other point charges is the magnitude of the net electrostatic force on that charge:
We can use Coulomb's law to determine the magnitude of [tex]F_{net}[/tex] :
[tex]F_{net}[/tex] = F₁₂ + F₁₃ + F₂
F is equal to k × |q₁×q₂ / r₂,
where k is the Coulomb's constant, q₁ and q₂ are the charges of the two points, and r is the distance between the points.
The side of the square is the distance r for F₁₂,
so r = 30.0 cm.
F₁₂ = k × |(31.0 pC)× (-23.0 C) / (30.0 cm)²
F₁₃ and F₂₃ have the same equation, but the charges are different, so we can calculate them in the same way.
We can then add the three forces to get the net force on q₄:
F₁₃ = k × |(31.0 pC)× |(-45.0 °C)| / (30.0 cm)²
F₂₃ = k × |(-23.0 °C)× |(-45.0 °C)| / (30.0 cm)²
Fnet = F₁₂ + F₁₃ + F₂₃
Fnet = (k × |(31.0 pC) × (-23.0 C)| / (30.0 cm)2) + (k × |(31.0 pC) × (-45.0 C)| / (30.0 cm)²) + (k × |(-23.0 C) × (-45.0 C)| / (30.0 cm)²)
When the charges and the distance are substituted
The magnitude of the net electrostatic force exerted on the point
charge q₄ is 4.80 x 10⁻² N
Fnet = (8.99 x 10⁹ Nm²/C² × |(31.0 pC)×(-23.0 °C)| / (30.0 cm)²) + (8.99 x 10⁹ Nm²/C² × |(31.0 pC) × (-45.0 °C)| / (30.0 cm)²)
[tex]F_{net}[/tex] = 4.80 × 10 ⁻²
What gives rise to electric charge?When electrons are added to or taken away from an object, an electrical charge is created. When electrons are added to an object, it takes on a negative charge due to their negative charge. Positive charge is created when an object loses its electrons.
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A speed versus time graph is shown:
Which statement accurately describes the motion of the object in the graph above?
Group of answer choices
From 2s to 6s, the object is at rest.
From 0s to 4s, the object is moving at 1.5 cm/s.
From 6s to 7s, the object speeds up.
From 2s to 6s, the object is moving at 1.5 cm/s.
The statement accurately describes the motion of the object in the graph above is from 2s to 6s, the object is moving at 1.5 cm/s.
option D is the correct answer
What is speed time graph?
A speed time graph is a graph that shows the motion of an object against time. They can also be referred to as velocity-time graphs.
The motion of the object in the graph above can be described as follows;
between 0 to 2 seconds, the speed of the object = 0 cm/s
between 2 to 6 seconds, the speed of the object = 1.5 cm/s
between 6 to 8 seconds, the speed of the object = 0 cm/s
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Which two equations represent double replacement reactions.
A. HCl+KOH=KCl+H2O
B. BaCl2+Na2SO4=2NaCl+BaSO4
C. 2C2H6+7O2=4CO2 +6H2o
D. Ca+MgS=CaS+Mg
Two equations represent double replacement reactions are:
C. 2C2H6+7O2=4CO2 +6H2o
D. Ca+MgS=CaS+Mg
ABOUT METATHESIS REACTIONA metathesis reaction, sometimes referred to as a double exchange reaction, double replacement reaction, or multiple decomposition reaction, is a chemical reaction involving the exchange of bonds between two non-reacting chemical species resulting in the formation of products with the same type of bond. This reaction is illustrated by the following scheme:
A-B + C-D → A-D + C-B
A metathesis reaction involves the exchange of two groups or ions between the reactants.
The bond between reacting species can be either ionic or covalent. Usually, this reaction produces an insoluble product from the soluble reactant. This product is referred to as precipitate.
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a 2.5 kg mass is rotated into a conical pendulum where the length of string connected to the mass is 0.68 m and the angle between the string and vertical is 35°. determine:
The tension in the string of a conical pendulum is 18.6 N.
What is the tension in the string?
The tension in the string of a conical pendulum can be determined using the following formula:
T = mg(L / L + lcos(θ))
where:
m = 2.5 kg (mass of the object)g = 9.8 m/s² (acceleration due to gravity)L = 0.68 m (length of the string)θ = 35° (angle between the string and vertical)The tension in the string of a conical pendulum is calculated as
T = 2.5 x 9.8 x (0.68 / (0.68 + (2.5 x 9.8 x cos(35°)))
T = 18.6 N.
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a 2 μc charge is at the origin. a 5 μc charge is on the x-axis at 1 m. at what point between the charges is the electric field zero?
The point between the two charges where the electric field equal to zero is calculated to be 0.32 m.
The charge q₁ is given as 2 μc = 2 × 10⁻⁶ c
It is located at x₁ = 0.
The charge q₂ is given as 5 μc = 5 × 10⁻⁶ c
It is located at x₂ = 1 m.
Let us suppose that, electric field is zero at the point x, it is in between 0 and 1 m.
We know the formula for electric field as,
E = k q /r²
Let us equate the electric field at both the charges.
k q₁/x² = k q₂/(x₂ - x)²
q₁ (x₂ - x)² = q₂ x²
2 × 10⁻⁶× (1 - x)² = 5 × 10⁻⁶× x²
2 × ( 1 + x² - 2x) = 5 × x²
2 + 2x² - 4x = 5x²
7 x² + 4x - 2 = 0
The two values of x are,
x = 0.32, -0.892
The distance cannot be negative. So, the electric field at x = 0.32 m is said to be zero.
Thus, the required value of x is 0.32 m.
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