Explanation:
Gold (AU)................
A change resulting in one or more new substances being formed is a?
A. nuclear reaction
B.physical property
C. chemical change
D.physical change
Answer:
C. Chemical change
Explanation:
A physical change is where something is changed but it doesnt affect the build up of the chemical. For example, if you broke sticks and threw them on the ground, that would be a physical change because the change is happening to the physical being of the object and not its chemical buildup. However, if you lit those sticks on fire, that would be considered a chemical change because you end up with two substances, ash and the remnants of the stick. A nuclear reaction would result in something blowing up so its not that. And a physical property is like what it looks like or how it smells. Hope I helped you!
PLEASE HELP 30 POINTS PLS PLS
Many types of fungi are responsible for the breakdown and
recycling of organic material in an ecosystem. Fungi are an
example of a(n)
Answer:
mushroom are a type of fungi
Explanation:
The half-life of 226Ra is 1.60x103 years. How long until only 12.5% of the original sample of 226Ra remains?
Answer:
4.80×10³ years
Explanation:
Let the original amount (N₀) of ²²⁶Rn = 1 g
Therefore,
12.5% of the original amount = 12.5% × 1 = 12.5/100 × 1 = 0.125 g
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Original amount (N₀) = 1
Amount remaining (N) = 0.125 g
Number of half-lives (n) =?
N = 1/2ⁿ × N₀
0.125 = 1/2ⁿ × 1
0.125 = 1/2ⁿ
Cross multiply
0.125 × 2ⁿ = 1
Divide both side by 0.125
2ⁿ = 1/0.125
2ⁿ = 8
Express 8 in index form with 2 as the base
2ⁿ = 2³
n = 3
Thus, 3 half-lives has elapsed.
Finally, we shall determine the time taken for only 12.5% of the original sample of ²²⁶Rn to remain.
This can be obtained as follow:
Half-life (t½) = 1.60×10³ years
Number of half-lives (n) = 3
Time (t) =?
t = n × t½
t = 3 × 1.60×10³
t = 4.80×10³ years.
Thus, it will take 4.80×10³ years for 12.5% of the original sample of ²²⁶Rn to remain.
This equation shows the combustion of methanol.
2CH2OH(1) +302(g) → 2C02(g) + 4H2O(g)
How many liters of carbon dioxide gas at STP are produced by the combustion of 64.0 g of methanol
(CH3OH)
A. 44.8L
B. 89.6 L
C. 11.2L. D. 22.4L
Answer: 44.8 L
Explination:
44.8 liters of carbon dioxide gas at STP are produced by the combustion of 64.0 g of methanol. Therefore, option A is correct.
What is combustion ?Combustion is a chemical reaction between two or more substances, usually involving oxygen, that produces heat and light in the form of a flame.
Combustion is a high-temperature exothermic redox chemical reaction that occurs between a fuel and an oxidant, frequently atmospheric oxygen, to produce oxidized, often gaseous products in a mixture known as smoke.
The flash point of methanol is extremely low. This means that even trace amounts of ignition material can start a fire. 44.8 liters of carbon dioxide gas at STP are produced by the combustion of 64.0 g of methanol.
Thus, option A is correct.
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Which of these processes removes carbondioxide from the air?
Answer:
It’s Photosynthesis
Explanation:
Don’t click the file it’s a virus ! Also I hope I helped!
Assuming the partial pressure of oxygen in air (0.20 atm) and nitrogen in air (0.80 atm). Calculate the mole fractions of oxygen and nitrogen in water at 298 K. FOR THIS QUESTION report the mole fraction of OXYGEN
Answer:
oxygen = 4.7 * 10^-6
Nitrogen = = 9.7 * 10^6
Explanation:
partial pressure of oxygen = 0.20 atm
partial pressure of Nitrogen = 0.80 atm
calculate the mole fractions of oxygen and Nitrogen in water
Temp = 298k
applying henry's law
molar conc of oxygen in water ( Coxygen )
= Kp = 1.3 * 10^-3 Mol/L.atm * 0.20 atm = 2.6 * 10^-4 Mol
molar conc of Nitrogen in water ( Cnitrogen )
= Kp = 6.8 * 10^-4 Mol/L.atm * 0.80 atm = 5.4 * 10^-4
next Given that the number of moles in 1 liter of water = 55.5 mol
therefore the mole fraction of oxygen
= 2.6 * 10^-4 / 55.5
= 4.7 * 10^-6
mole fraction of Nitrogen
= 5.4 * 10^-4 / 55.5
= 9.7 * 10^6
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Simone is helping her mom cook. She takes a glass casserole dish directly from the refrigerator and put it in the oven. Which best explains the result of putting the cold dish in the hot oven?
Group of answer choices
The dish stays cool and will not warm.
The dish quickly changes color.
The dish cracks or breaks.
The dish contracts and shrinks.
Answer:
I think the dish contracts and shrinks
Answer:
The dish cracks or breaks.
Explanation:
When glass changes temperature rapidly, it may undergo thermal shock. This is stress that is produced by a sudden change in temperature.
1. a) Define the term electricity ?
Answer:
a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.
Explanation:
How many Calories are in 5,926 joules
A certain metal M forms a soluble nitrate salt M(NO3), Suppose the left half cell ofa galvanic cell apparatus is filled with a 4.00 M solution of M (NO,), and the right half cell with a 20.0 mM solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 35.0 °C.
Required:
a. Which electrode will be positive?
b. What voltage will the voltmeter show?
Answer:
Explanation:
The left electrode will be positive on the grounds that focus on the concentration that the cell electron moves from a lower concentration fixation to a higher concentration. Thus right electrode will go about and act as an anode and will be negative. Also, the left electrode will be the cathode and will be positive.
The concentration cell [tex]E_{Cell} = \dfrac{-0.0591}{1} log \dfrac{0.02}{4}[/tex]
[tex]E_{Cell} =0.136 V[/tex]
= 136 mV
Which of the following statements is correct?
A. 2 moles of O2 is equal to 64 g of O2.
B. 2 moles of O2 is equal to 32 g of O2.
C. 2 moles of O2 is equal to 2 g of O2.
D. 1 moles of O2 is equal to 2 g of O2.
Answer:
pretty sure its B but if not I'm sorry
2 moles of O₂ is equal to 64 g of O₂ is the only correct statement among the given statements. Hence, Option (A) is correct. It can be solved by mole concept
What is Mole concept ?
The mole, symbol mol, is the SI base unit of amount of substance.
The quantity amount of substance is a measure of how many elementary entities of a given substance are in an object or sample.
formula ;
n = given weight / molecular weight
= 64 / 32
= 2 moles
Therefore, 2 moles of O₂ is equal to 64 g of O₂ is the only correct statement among the given statements. Hence, Option (A) is correct.
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Answer:
A i took the quiz
Explanation:
What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The density of water is 1.00 g/mL)
Answer:
13.5 %
Explanation:
First we calculate the mass of 500 mL of water, using its density:
Volume * Density = Mass500 mL * 1.00 g/mL = 500 gThen we calculate the mass percent of potassium sulfate, using the formula:
Mass of Potassium Sulfate / Total Mass * 100%
78 g / (78 + 500) g * 100 % = 13.5 %Rank the following compounds in order of decreasing acidity. Be sure to answer all parts. A) Benzyl alcohol B) Methylbenzene C) Benzoic acid
The order of decreasing the acidity of the given compounds:
Benzoic acid > Benzyl alcohol > Methylbenzene.
What is the acidic strength?The acidic strength of an acid can be described as the ability of the acid to lose its H⁺ ion. In general, the dissociation of acid can be represented as:
HA → H⁺ + A⁻
Some examples of strong acids are hydrochloric acid, sulfuric acid (H2SO₄), perchloric acid (HClO₄), etc.
The benzoic acid is a very strong acid with pka value of 4.5 as it contains the (-COOH) group. The Benzyl alcohol with pka value of 15.4 as it contains the (-CH₂OH) group attached to the benzene ring. The methylbenzene with pka value of 41 has the lowest acidity as it contains the methyl group attached to the benzene ring.
Therefore, the order of acidic strength for the given compounds is Benzoic acid > Benzyl alcohol > Methylbenzene.
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QUESTION 6 Consider the following reaction between the diatomic and monatomic forms of iodine: I2 (g) <-> 2I (g) When 0.095 M I2 is initially placed in a previously empty container and sealed, the system slowly reaches equilibrium. When equilibrium is reached, it is found that there is an equilibrium concentration of 0.0055 M of the monatomic form of iodine. Calculate the (unitless) equilibrium constant Kc. Round your answer to two sig figs, and express it in scientific notation.
Answer: The equilibrium constant is [tex]3.3\times 10^{-4}[/tex]
Explanation:
Initial concentration of [tex]I_2[/tex] = 0.095 M
The given balanced equilibrium reaction is,
[tex]I_2(g)\rightleftharpoons 2I(g)[/tex]
Initial conc. 0.095 M 0 M
At eqm. conc. (0.095-x) M (2x) M
Given : 2x = 0.0055
x = 0.00275
The expression for equilibrium constant for this reaction will be,
[tex]K_c=\frac{[l]^2}{[I_2]}[/tex]
Now put all the given values in this expression, we get :
[tex]K_c=\frac{(0.0055)^2}{(0.095-0.00275)}[/tex]
[tex]K_c=\frac{(0.0055)^2}{0.09225}=0.00033[/tex]
Thus the equilibrium constant is [tex]3.3\times 10^{-4}[/tex]
8. Zeolite is used to remove moisture from methane. A vertical column is filled with 1000.0 kg of dry zeolite. The zeolite has the capacity to hold 0.100 kg water/kg dry zeolite. Once the zeolite becomes saturated with moisture, it must be regenerated by heating. The inlet moisture content of the methane is 7.00% (by mass) and the outlet moisture content is 0.05% (by mass). How much methane (kg) will be produced before the zeolite must be regenerated
Answer:
Follows are the solution to this question:
Explanation:
Methane inlet humidity content of [tex]=7.00\%[/tex]
Methane moisture outlet content [tex]=0.05\%[/tex]
Zeolite absorption humidity [tex]= 6.95\%[/tex]
Dry zeolite 1 kg will accommodate water[tex]= 0.1000 \ kg[/tex]
One kilogram of Dry Zeolite will carry water from [tex]=0.1000\ kg[/tex]
The water can contain 1000 kg of zeolite [tex]= 100 \ kg[/tex]
Methane which would be made [tex]=\frac{100}{6.95\%}= 1,439 \ kg[/tex]
That's why it will be producing 1439 kg of methane.
The amount of methane that can be produced before the regeneration of zeolite is 1,439 kg.
What is zeolite?
Zeolite belongs from the family of hydrated aluminosilicate minerals, in which alkali and alkaline earth metals are present.
In the question, it is given that:
Capacity of 1kg of zeolite to hold water = 0.100kg
Capacity of 1000kg of zeolite to hold water = 100kg
Inlet moisture content of the methane = 7.00 % (by mass)
Outlet moisture content of the methane = 0.05% (by mass)
Capacity of zeolite to absorb methane content = 6.95 %
Amount of methane before the regeneration of zeolite = 100kg / 6.95% = 14.39% of kg = 1,439 kg
Hence, 1,439 kg methane will be produced before the zeolite must be regenerated.
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Heat flows from hotter objects to colder objects until it reaches a state where heat is no longer flowing.What have the objects reached when heat is not longer flowing?
What is measured by the heat of reaction?
Answer:
The heat of reaction is basically the energy that is being released and or absorbed when chemicals are transformed in a type of chemical reaction. However, the heat of reaction or also called reaction enthalpy is mostly or typically expressed as a molar enthalpy in kJ/mol and or as just a specific enthalpy in kJ/kg or kJ/L.
Mg(s) + Cu(NO3)2(aq) → Mg(NO3)2(aq) + Cu(s)
How will the rate of the chemical reaction change if the solid piece of magnesium metal is ground into a powder?
Select one:
a. Increase
b. Cannot be predicted
c. Will not change
d. Decrease
Answer: increase
Explanation: when Mg is powder it has greater surface area and
Reaction occurs faster
Which of the different components of smog depicted in the graph are most likely released from automobile exhaust?
A
A and B
B
B and C
с
A, B, and C
D
B, C, and D
Answer:
B, B and C
Explanation:
The two components (AA, hydrocarbons and BB, nitrogen oxide) are most likely released from automobile exhaust.
What is Smog?This is referred to a type of air pollution which could be from carbon emission etc and reduces the visibility.
(AA, hydrocarbons and BB, nitrogen oxide peaked midmorning when traffic is highest which means they were most likely released from automobile exhaust?.
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How many grams are in 1.2 x 10^24 atoms of sodium?
The mass ratio of H to O in water (H2O) is 1:8. What is the mass
ratio of H to O in hydrogen peroxide (H2O2)?
Answer: 1:16
Explanation:
Mg(s) + 2HCl (aq) -----> MgCl2 (aq) + H2
You have 6.00 g HCl and 4.8 g Mg.
What is the limiting reaction
Answer:
HCl is the limiting reactant
Explanation:
To find the limiting reactant of a reaction we must find the moles of each one as follows:
Moles Mg (Molar mass: 24.305g/mol)
4.8g Mg * (qmol / 24.305g) = 0.20 moles Mg
Moles HCl (Molar mass: 36.46g/mol)
6.00g HCl* (1mol / 36.46g) = 0.165 moles HCl
Based on the chemical reaction, for a complete reaction of 0.20 moles of Mg are necessaries:
0.20 moles Mg * (2mol HCl / 1mol Mg) = 0.40 moles HCl
As there are just 0.165 moles of HCl:
HCl is the limiting reactantAny time a reaction procedure involves separation steps during the workup, it is a good idea to outline a separation scheme.
a. True
b. False
Answer:
True
Explanation:
Benzene is formed as a result when benzoic acid is generated by Grignard reaction. We must therefore isolate it from the desired benzoic acid compound, as the rest is not dismissed after dissolution in aqueous NAOH solution. Therefore, it a good idea to outline a separation scheme for such cases.
This implies that the given statement is true.
A liquid is placed in a closed container and time passes until
the level of the liquid is constant
The general situation described by the rate of evaporation is
equal to the rate of condensation called a:
a
state balance
b static equilibrium
chemical balance
d dynamic equilibrium
Answer: Dynamic equilibrium
Explanation:
Identify the techniques used in the work-up and characterization of benzoic acid. The analytical method used to confirm the structure and functional groups of the product NMR spectroscopy The technique used to separate the pure product from any excess reagent, impurities, and byproducts Recrystallization The quick, numeric analysis used to characterize the product and assess the purity Melting point.
Answer:
Explanation:
[tex]\text{From the list of the options given; we are to identify the suitable techniques} \\ \\ \text{for the characterization of benzoic acid.}[/tex]
[tex]\text{The analytical method used to confirm the structure and functional groups}\\ \\ \text{present in the product is} \ \ \mathbf{IR \ spectroscopy.}[/tex]
[tex]\text{The technique used to separate pure products from any excess reagents,} \\ \\ \text{impurities, and byproducts is}\ \ \mathbf{Recrystallization.}[/tex]
[tex]\text{The quick, numeric analysis done to characterize the product and assess the purity is}[/tex][tex]\mathbf{melting \ point.}[/tex]
How many moles of NaHCO3 are in 2.4 x
1024 molecules of NaHCO:?
4.0 moles NaHCO
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 2.4 × 10²⁴ molecules NaHCO
[Solve] moles NaHCO
Step 2: Identify Conversion
Avogadro's Number
Step 3: Convert
[DA] Set up: [tex]\displaystyle 2.4 \cdot 10^{24} \ molecules \ NaHCO(\frac{1 \ mol \ NaHCO}{6.022 \cdot 10^{23} \ molecules \ NaHCO})[/tex][DA] Divide [Cancel out units]: [tex]\displaystyle 3.98539 \ moles \ NaHCO[/tex]Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
3.98539 moles NaHCO ≈ 4.0 moles NaHCO
What is the percent composition of hydrogen in glucose
Answer:
67%Explanation:
Thus the % composition of glucose by mass is carbon 40.0 % oxygen 53.3 % hydrogen 6.7 % in this way, the % composition by mass of any compound can be calculated provided that is formed is known.