The direction of the child's average velocity between locations A and D on the merry-go-round will be in the direction of the displacement of the child, which is the change in position from location A to location D.
If the child is traveling at a constant speed, the average velocity will be in the same direction as the actual velocity at any given moment. The actual velocity of the child is always tangent to the circular path of the merry-go-round, and so the average velocity will also be tangent to the circular path. This means that the direction of the average velocity will be perpendicular to the line connecting the origin (center of the merry-go-round) to the position of the child.
The direction of the average velocity depends on the direction of the child's movement along the circular path of the merry-go-round.
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use the v field sensor to find points with the same reading. make a map of these locations. record the readings (magnitude and direction) of the e field sensor at these same locations. what patterns do you notice in the v field and e field readings?
The amplitude and direction of the electric field, E, at any given position can be determined by taking into account a slight positive test charge.
Describe a vector?In science, anything that possesses a both path and a magnitude is referred to as a vector. They are typically represented by pointing lines, the height of which denotes the size of the vector. In physics, a vector is a quantity with both direction and magnitude. It is often depicted by such an arrow whose height was proportional to the magnitude of the quantity but whose orientation is identical to that of the quantity. Despite having a size and a direction.
How do directions work?The definition of direction is the course that something follows or the course that must be followed to arrive .
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To transfer a quantity of charge between points C and D of a circuit, which have a potential difference of 30 volts, 600 joules of energy is required.
How much charge is transferred?
Therefore, 20 Coulombs of charge is transferred between points C and D of the circuit.
What do you mean by the term potential difference?Potential difference, also known as voltage, is a measure of the electric potential energy per unit of charge in an electrical circuit. It is the force that drives the flow of electric charge through a circuit and is commonly expressed in volts (V).
The charge transferred can be calculated using the equation:
Q = W / V
Where Q denotes the charge transferred, W states the energy required, and V is the potential difference (30 Volts).
So, Q = 600 J / 30 V = 20 Coulombs.
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for the circuit shown, the supply vin is a variable frequency, fixed magnitude sinusoidal voltage. at 100hz, the voltage drop across the resistor is vr and it equals the voltage across the inductor. if the frequency of vin is reduced to 50hz, what is the new voltage across the resistor in terms of vr?
The new voltage across the resistor in terms of [tex]V_r[/tex] is [tex]\frac{\sqrt\frac{5}{4} }{\sqrt2 }[/tex]
When referring to the "pressure" that propels electricity, voltage is utilized. Volts (V) are the unit of voltage. and higher voltages cause an electrical device to receive more electricity. However, because too high voltage could damage their circuitry, electrical devices must operate within a range of voltages. A voltage that is too low, on the other hand, can also be a problem since it inhibits circuits from operating and renders the devices built around them worthless. One needs to understand voltage and how to fix related issues in order to handle electronic equipment correctly and identify the underlying causes of issues when they occur.
fxed magnitude sinusoidal voltage. at 100hz, at 100Hz:
[tex]V_r[/tex]= [tex]\frac{V_in}{2}[/tex]
Using the voltage division formula we find that the transfer function is:
Resistor = R
Inductor = jωL
[tex]\frac{R}{R+j \times\omega L}[/tex]
we then equate the magnitude with [tex]\frac{1}{2}[/tex]
[tex]\frac{R}\sqrt{R^2+ (\omega L)^2}[/tex] = [tex]\frac{1}{2}[/tex]
next step assume R =1 and ωL = 1 above
that means that at 50Hz:
R =1 and ωL = .5
plugging into that formula we get [tex]\sqrt{(5/4)[/tex] and [tex]\frac{\sqrt\frac{5}{4} }{\sqrt2 }[/tex] because this was in terms of [tex]V_in[/tex] not [tex]V_r[/tex].
so the answer is C.
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Question:
For the circuit shown, the supply Vin is a variable frequency, fixed magnitude sinusoidal voltage. At 100Hz, the voltage drop across the resistor is Vr and it equals the voltage across the inductor. If the frequency of Vin is reduced to 50Hz, what is the new voltage across the resistor in terms of Vr?
a.) square root of (5/8) * Vr
b.) square root of (2/3) * Vr
c.) square root of (8/5) * Vr
d.) square root of (3/2) * Vr
a child pushes a toy car so it rolls across the floor. the car rolls about a meter and then comes to a stop. why doesn't the toy car continue to move in a straight line at the same speed?
The toy car doesn't continue to move in a straight line at the same speed because there are several factors that cause it to slow down and eventually come to a stop.
Some of these factors are:
Friction: The friction between the floor and the tires of the toy car slows down the motion of the car. As the car rolls, the friction acts in the opposite direction to its motion and reduces its speed.
Air resistance: The air resistance also slows down the motion of the toy car. The faster the car moves, the greater the air resistance, which acts in the opposite direction to its motion.
Inertia: The tendency of an object to continue moving at the same velocity unless acted upon by an external force also plays a role in stopping the toy car. As the car slows down due to friction and air resistance, it gradually comes to a stop.
Imperfections in the floor: Unevenness in the floor, small bumps, or other imperfections can also cause the car to slow down and eventually stop.
All of these factors combined result in the toy car slowing down and eventually coming to a stop, rather than continuing to move in a straight line at the same speed.
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consider research that you have heard in class or in the media. how did a visual presentation of the data help you understand the information that was presented?
The visual presentation of the data helps us to understand the information better, because: it provides clearer data which easier for us to identify patterns, trends, and outliers, especially in super large data.
How does the visual presentation advantages?In presenting data from experiments, it is strongly recommended to use visual presentation, such as graphics, diagrams, pictures, etc. The advantages of using visual presentations are as follows:
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When 50 g of a certain material at 100°C is mixed with 100 g of water at 0°C, the final temperature is 40°C. What is the specific heat of the material? The specific heat of water is 1.00 kcal/kg • C°.
we can equate the two quantities of heat to find c: m_water * c_water * ΔT = m_material * c * ΔT, c = (m_water * c_water * ΔT) / (m_material * ΔT)
the above expression yields c = 0.20 kcal/kg * C°.
The formula for calculating the specific heat (c) of a material is:
ΔQ = m * c * ΔT
c = ΔQ / (m * ΔT)
ΔT = 100°C - 40°C = 60°C
m_water = 100 gΔQ = m_water * c_water * ΔT = 100 g * 1.00 kcal/kg * ΔT
m_material = 50 g
ΔT = 40°C - 0°C = 40°C
ΔQ = m_material * c * ΔT
So, we can equate the two quantities of heat to find c:
m_water * c_water * ΔT = m_material * c * ΔT
c = (m_water * c_water * ΔT) / (m_material * ΔT)
the above expression yields temperature c = 0.20 kcal/kg * C°.
How is mixing temperature determined?The first container's mass and temperature are multiplied together, and the result is added to the second container's mass and temperature to determine the mixture's water temperature. Finally, divide that outcome by the combined water masses in each container.
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A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of the carriage has__ energy. Calculate it.
The required energy the carriage has, when the displacement of the carriage and mass of the carriage with the baby are given is calculated to be 1029 J.
The energy in the above case is nothing but the work done by the carriage.
The work is defined as,
W = F d
where,
F is force
d is displacement
Entering the values in the above equation, we have,
W = F d = m × a × d = 5 × 9.8 × 21 = 1029 J
Thus, the required energy the carriage has is calculated to be 1029 J.
The given question is inappropriate. The question is 'a baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 5kg whats the energy the carriage has?'
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0%) problem 8: a dolphin in an aquatic show jumps straight up out of the water at a velocity of 14. 5 m/s
A. The knowns in this problem are initial velocity, final velocity and acceleration due to gravity on the dolphin.
B. The calculated height the dolphin rises is not reasonable.
C. The time the dolphin stays in the air is calculated to be 1.48 s.
A. The initial velocity of the dolphin is given as vi = 14.5 m/s
The final velocity of the dolphin is zero.
As the dolphin jumps upwards, the gravity acting is considered negative
So, g = -9.8 m/s²
B. According to kinematics, we know the equation,
v² - u² = 2 a s
The height raised by the body of the dolphin is,
s = (v² - u²)/2a = -14.5²/(2× -9.8) = 10.73 m
The answer does not seem reasonable as it is approximately equal to three-storeyed building.
C. The time dolphin stays in the air is given by the equation,
v = u + a t
Here, a = -g
v - u = -g t
t = -(v - u)/g = -(0-14.5)/9.8 = 14.5/9.8 = 1.48 s.
The given question is incomplete. The complete question is 'A dolphin in an aquatic show jumps straight up out of the water at a velocity of 14.5 m/s.(a) List the knowns in this problem. (b) How high does his body rise above the water? To solve this part, first note that the final velocity is now a known, and identify its value. Then, identify the unknown and discuss how you chose the appropriate equation to solve for it. After choosing the equation, show your steps in solving for the unknown, checking units, and discuss whether the answer is reasonable. (c) How long a time is the dolphin in the air? Neglect any effects resulting from his size or orientation.'
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. how long has it been raining on venus? how would you describe the rain in your own words? all summer in one day
On Venus, it has rained nonstop for the past seven years. The rain destroyed thousands of forests, which then multiplied thousand times before being destroyed once more.
Seven years had passed since Venus had last seen rain. Several forests had been trampled by the rain, regrown a thousand times, and then trampled once more. No concrete evidence of past or existing life on Venus has been discovered as of yet.
Venus's severe surface temperatures, which can reach around , and atmospheric pressure that is times that of Earth make it implausible that water-based life as we know it could exist there. The rocket people had gone to Venus, a planet with rain, to establish a civilization and live out their lives.
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an object of mass 80kg was placed in a lift ascending at 1.25m/s square.Calculate it's weight in the lift(g=10m/s square)
Explanation:
work = mgh
work= 80×10×1.25
w= 1000 joules
Answer:
800N
Explanation:
W=mg
where m=mass,g=acceleration due to gravity,W=weight
W=80×10
W=800N
a power station delivers 620 kw of power at 12,000 v to a factory through wires with total resistance 3.0 ohms. how much less power is wasted if the electricity is delivered at 50,000 v rather than 12,000 v?
A plant receives 620 kw power at 3000 V from a power source via lines with a 3.0 total resistance.
Describe a power?The watt W is the SI unit of power, and 1 watts equals 1 joule per second (1W=1J/s). Power is the process by which energy is used up since power is an energy transfer. For instance, a 60-W bulb mieux J of energy every second.
Power is a metric for how quickly energy is transformed from one kind to the other. Energy spent over that time can be calculated by integrating, or adding, power over time. Using different units where power is stated as a rate may make the relationship between strength and power more obvious.
Describe energy?According to scientists, energy is the capacity .
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the weight of an object on earth varies inversely as the square of its distance d from the center of the earth. if a pilot weighs 175 lbs at sea level on earth (approx. 6400 kilometers from the center of the earth), how far above the earth must the pilot fly in order to weigh 150 lbs?
The weight of an object on Earth varies inversely as the square of its distance from the center of the Earth. This means that if the distance from the center of the Earth is doubled, the weight of the object will be reduced to one fourth of its original weight.
At sea level, the pilot weighs 175 lbs. If the pilot were to fly at a distance of 8800 kilometers above the Earth, their weight would be reduced to 150 lbs. This is because the distance from the center of the Earth is now 4 times the distance at sea level, which results in their weight being reduced to one fourth of its original value.
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objects with masses of 270 kg and a 570 kg are separated by 0.340 m. (a) find the net gravitational force exerted by these masses on a 61.0 kg mass placed midway between at what position the 61.0 kg mass be placed so as to experience a net force of zero? m from the 570 kg mass
The 61.0 kg mass would need to be placed a distance of x = 0.147 m from the 570 kg mass to experience a net force of zero.
The net gravitational force between two masses can be calculated using Newton's law of gravitation:
F = G(m1 × m2) / r²
where:
F is the force,
G is the gravitational constant (G = 6.67 x 10⁻¹¹ Nm²/kg²),
m1 and m2 are the masses of the two objects,
r is the separation distance between the two objects.
The net gravitational force exerted by the 270 kg and 570 kg masses on a 61.0 kg mass placed midway between the two masses can be calculated as follows:
F1 = G (270 kg × 61.0 kg) / ((0.34 m / 2)²)
F2 = G (570 kg × 61.0 kg) / ((0.34 m / 2)²)
The net force would be equal to the sum of these two forces:
Fnet = F1 + F2
To find the position at which the 61.0 kg mass would experience a net force of zero, we need to find the position at which the force from the 270 kg mass is equal and opposite to the force from the 570 kg mass.
F1 = F2
G (270 kg × 61.0 kg) / (x²) = G (570 kg × 61.0 kg) / ((0.34 m - x)²)
Solving for x, we find that:
x = (0.34 m×(270 kg - 570 kg)) / (270 kg + 570 kg)
So, the 61.0 kg mass would need to be placed a distance of x = 0.147 m from the 570 kg mass to experience a net force of zero.
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How does orbital speed at aphelion compare to the speed at perihelion?
At perihelion (closest approach to the Sun), objects move the fastest; at aphelion, they move the slowest. Since the orbits of the planets in the Solar System are almost circular.
What is the difference between a planet's orbital speed during perihelion and aphelion?As a result, the planet moves more quickly when it is closer to the Sun and less rapidly when it is farther away. As a planet travels around its orbit, its speed is continually changing. A planet moves most quickly when it is closest to the sun, and most slowly when it is further away (farthest). Law 3.
Why do planets travel more quickly at their perihelion than their aphelion?Because we are nearer the Sun at perihelion and more aware of its gravity, the precise speed changes. We are moving a little bit more quickly around the Sun than we were at aphelion because of this. Our overall orbital velocity, which varies with distance from the Sun, is the sum of our tangential and radial velocities.
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Television broadcasts utilize _________ waves. Select one: magnetic gamma radio ultraviolet
The radio waves used in television transmissions.
Lower frequency electromagnetic waves than microwaves are radio waves.
Radio waves have wavelengths that range from tens of thousands of metres to 30 centimetres. These are equivalent to frequencies between 3 Hz and 1 GHz (109 Hz).
Straight-line radio-wave communication signals pass through the atmosphere, reflect off of clouds or ionosphere layers, or are transmitted by satellites in space.
They are utilised in remote-controlled toys as well as traditional broadcast radio and television, shortwave radio, navigation and air traffic control, and more.
Particularly, the wavelengths of television waves range from around 50 centimetres to about 10 metres.
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if two vehicles are identical, except for one weighing twice as much as the other vehicle, and they roll down a hill, which car reaches the bottom first?
The heavier car descends first because its rotational inertia (wheels) account for a greater proportion of its mass.
Will a car with double the mass accelerate more quickly or slower?The roller coaster car's mass is unrelated to speed, so doubling the mass would have no impact on the speed of the vehicle. The car with twice the mass will therefore travel at the same speed from top to bottom.
What decides if one car in a collision with another has greater momentum than the other?The momentum of an object in motion is calculated by dividing its mass by its speed. An item has a lot of momentum if its mass or speed is greater than 1. A fast-moving car has more momentum than a slow-moving one because they have the same mass.
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Discuss the ethical considerations in providing immunization.
There are numerous, interconnected ethical problems that arise with delivering immunizations and vaccine mandates.
Many interconnected ethical problems can be present in debates about vaccine mandates. This is true of the human papillomavirus (HPV) vaccine, which prevents the sexually transmitted disease (STD). The initial HPV vaccination was given b approval in 2006. Several state legislatures attempted to impose immunizations requirements after the ACIP recommended three doses of the vaccine for girls between the ages of 11 and 12. Religious objections to the mandate range from worries that an STD vaccine goes against abstinence-based teachings to worries that the vaccine would force a child to have an intervention that isn't in line with her family's values.
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what conclusions can you make regarding the total energy of the released marble(s) and the total energy of the marble(s) knocked away from the row?
Due to momentum conservation, energy from one marble is transferred into another marble when it collides with another marble.
At repose is the larger marble. The marble with a lower mass bounces off in the other direction following the contact. Moving in the same direction as the smaller stone is the larger one. If only one marble was able to strike the marbles in the line, then only one marble will shoot out the other end.
The initial momentum before the collision and the end momentum after the impact are equal, assuming an elastic collision. Momentum is preserved in a collision, as stated by Newton's third law of motion. That implies that what is put in must come out.
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a lightweight crate a and a heavy crate b are side-by-side on a frictionless horizontal surface. a horizontal force f (> 0) is applied to crate a, causing both crates to start moving. how do the accelerations of the crates compare
Newton's second equation of motion, which states that the net force acting on an item is equal to its mass times its acceleration, can be used to compare the acceleration of the two crates.
The only forces acting on both crates are the applied force, f, and the gravitational force, mg, where m is the mass of each container and g is the acceleration brought on by gravity. This is because both crates are resting on a frictionless surface.Crate A will suffer a greater net force and, thus, a greater acceleration than Crate B since the applied force, f, is being applied just to Crate A. Due to its greater mass, crate B's acceleration will be less. The following formula can be used to determine the two crates' acceleration: Where m is the mass of each container, an is equal to f / m.Crate A will move more quickly and Crate B will trail behind because Crate A's acceleration is larger than Crate B's acceleration.
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In this pulley system, what is the minimum force (applied in the directio of the red arrow) required to move the weight upward? 1,000lbs 685 lbs 501 lbs
The minimum force or effort required to move the weight upward is 500 lbs.
option C.
What is the minimum force required to move the weight upward?The minimum force (applied in the direction of the red arrow) required to move the weight upward is determined by applying the formula for ideal mechanical advantage as shown below.
IMA = load / effort
from the number of pulleys, IMA = 2
Load = 1,000 lbs
The minimum force or effort required to move the weight upward is calculated as;
effort = load / IMA
effort = ( 1,000 lbs ) / 2
effort = 500 lbs
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5.How can we determine if an object is charged or not?
Answer:
through the use of a Gold leaf electroscope
with the horizontal; 84,9 N. **18. A car weighing 8 000 N rests on a slope of 20. (a) With what force does the car tend to move down the slope? (b) What is the force, at right angles to the slope, exerted by the ground on the car
The force that the car move down the slope is 1.4 KN
The force, at right angles to the slope, exerted by the ground on the car is 7.7 kN
How to find the force(a) The force with which the car tends to move down the slope is given by weight times the sine of the slope angle:
F = 8 000 N * sin(20°)
F = 1,366 N
(b) The force exerted by the ground on the car at right angles to the slope is given by weight times the cosine of the slope angle:
F = 8 000 N * cos(20°)
F = 7,679 N
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what is the magnitude of road friction force that is needed to bring her car to a halt in 9.0 s ? express your answer with the appropriate units.
The magnitude of road friction force that is needed to bring her car to a halt in 9.0 s is 1777.78N.
Mass (m) = 1000 kg.
initial speed (u) = 16 m/s.
time (t)= 9.0 Sec.
final speed (v) = 0 m/s.
F = ma
F=m[tex]\times (\frac{v-u}{t})[/tex]
a = [tex]\frac{v-u}{t}[/tex]
force is any action that tends to maintain, change, or distort a body's motion. Isaac Newton's three laws of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the concept of force. Newton's first law states that until a force is applied to a body, it will remain in either its resting or uniformly moving state in a straight path. According to the second law, when an external force acts on a body, the body accelerates in the force's direction. The amount of matter in the body is inversely proportional to the magnitude of the acceleration and directly related to the strength of the external force.
force (F)= [tex]1000\times (\frac{0-16}{9})[/tex]=-1777.78N
The opposite force is indicated by the negative sign, which indicates this.
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B. A guitar string has a length of 0. 90 m. When you pluck it, it plays a "C" that has a frequency of 256 Hz. How fast is the wave moving back and forth along the string? (Choose one of the equations from the box at the top of the page to solve this problem. )
Equations to use: v= λ ∙ f v=d/t
The wave on the guitar string is moving back and forth with a speed of 460.8 m/s.
What is the frequency of a string calculated from?
The frequency is given by f = 1/T = v/. So f = v/λ. We also noticed that the fundamental frequency, f1, has a string length of /2, making f1 equal to v/2L. The linear density, or mass per unit length, and the string tension F are what determine the wave speed. v = (F/)1/2 = (FL/M)1/2.
The speed of a wave (v) on a guitar string can be calculated using the equation:
v = λ * f
The wavelength of the wave can be calculated using the equation:
λ = 2 * L/n
where L is the length of the guitar string, n is the harmonic number (in this case, n = 1 for the fundamental mode).
Substituting L = 0.9 m and n = 1, we get:
λ = 2 * 0.9 m/1 = 1.8 m
The frequency of the wave is given as f = 256 Hz.
Substituting λ = 1.8 m and f = 256 Hz into the first equation, we get:
v = λ * f = 1.8 m * 256 Hz = 460.8 m/s
Therefore, the wave on the guitar string is moving back and forth with a speed of 460.8 m/s.
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the sun, on average, is 93 million miles from earth. how many meters is this? express (a) using powers of 10, and (b) using a metric prefix (km).
Answer:
1 km = .6214 mi
9.3E7 mi / .621 mi/km = 1.50E8 km
S = 1.5 * 10^8 km * 10^3 m / km = 1.5 * 10^11 meters
S = 1.5 * 10^11 meters
why is steel from old cars not considered a renewwable resource even though it is used to make nwe steel products?
"Steel is not considered renewable resource as it contains of iron and iron is found inside the earth."
As they are created over an extended period of time by geological processes, minerals and metals are non-renewable resources.
Only iron can be used to make steel, and in order for iron to be effective, it must first be mined from the earth. Despite being the fourth most frequent material on Earth, there is a finite amount of iron, and once it is all used up, there will be no way to make more steel.
Instead, direct-reduced iron plants can be used by steelmakers to react the rock with gas in order to remove iron from ore. Then, using an electric arc furnace powered by sustainable energy, these iron pellets can be transformed into steel.
Steel is therefore not regarded as a renewable material.
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an alpha particle (which is a helium nucleus, ) is emitted in a radioactive decay with . what is its speed?
An atomic nucleus emits an alpha particle (the helium nucleus), which causes it to change or "decay" into an other atomic nucleus with a mass number that is decreased by four and an atomic number that is reduced by two.
This process is known as alpha decay or -decay. In essence, alpha particles are helium nuclei that are bonded together by two protons and two neutrons. They are unable to penetrate as deeply as other particles like protons and electrons as a result of their enormous mass and electrical charge.
A positively charged particle similar to the helium-4 nucleus is spontaneously released during alpha decay.
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If a gas exerts 3.54 atmospheres at a temperature of 295 K, what pressure will it exert at
275 K?
Considering the Gay-Lussac's law, the gas exerts at a pressure of 3.3 atmospheres at a temperature of 275 K.
Definition of Gay-Lussac's lawGay-Lussac's law states that the pressure of a gas is directly proportional to its temperature when the volume is constant. This is because as the temperature increases, the gas molecules move faster and therefore the number of collisions against the walls increases, that is, the pressure increases.
Mathematically, Gay-Lussac's law states that the ratio between pressure and temperature always has the same value:
P÷T= k
where:
P is the pressure.T is the temperature.k is a constant.Being 1 an initial state and 2 a final state, it is fulfilled:
P₁÷T₁= P₂÷T₂
Pressure at 275 KIn this case, you know:
P₁= 3.54 atmT₁= 295 KP₂= ?T₂= 275 KReplacing in Gay-Lussac's law:
3.54 atm ÷295 K= P₂ ÷275 K
Solving:
(3.54 atm ÷295 K)× 275 K= P₂
3.3 atm= P₂
The final pressure is 3.3 atm.
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how does the fujita scale measure tornado intensity?
The Fujita or Fujita-Pearson scale is majorly used to measure the intensity of the tornadoes. It takes into account the degree of destruction which is caused by the tornado in structures built by men.
On the other hand, the intensity of hurricanes is measured using the Saffir-Simpson scale, which classifies them from level 1 (the lowest) to level 5 (the highest) depending on the strength of the winds.
The Fujita Scale (F Scale) also known as the Fujita-Pearson Scale (FPP Scale) measures and classifies the intensity of tornados. The scale bases and its rating on the destruction caused by the tornado. The scale recently was modified in the United States in 2007. It was renamed it as the Enhanced Fujita Scale (EF Scale).
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A 1=2.40 μF
capacitor is first charged by being connected across a battery with voltage b=8.00 V.
It is then disconnected from the battery and connected across an uncharged capacitor with capacitance 2=5.60 μF.
Calculate the final charge 1,f
and 2,f
on 1
and 2,
respectively.
The final charge on the first capacitor is 7.20 μC and the final charge on the second capacitor is 12.00 μC.
How to find the final chargeThe initial charge on the first capacitor, 1, can be calculated using the formula:
Q = C * V
where
Q is the charge,
C is the capacitance, and
V is the voltage.
Substituting the values, we get:
Q = 2.40 μF * 8.00 V = 19.2 μC
Let's call the final charge on the first capacitor 1,f and the final charge on the second capacitor 2,f.
Since the two capacitors are now connected in parallel, their equivalent capacitance is C_eq :
C_eq = C1 + C2
C_eq = 2.40 μF + 5.60 μF = 8.00 μF
The final charge on the equivalent capacitance is equal to the initial charge on the first capacitor, so:
Q_eq = Q1,f = 19.2 μC
From this, we can calculate the final charge on each capacitor:
Q1,f = (C1 / C_eq) * Q_eq
Q1,f = (2.40 μF / 8.00 μF) * 19.2 μC = 7.20 μC
Q2,f = (C2 / C_eq) * Q_eq
Q2,f = (5.60 μF / 8.00 μF) * 19.2 μC = 12.00 μC
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