Explanation:
Given that,
Force with which a child hits a ball is 350 N
Time of contact is 0.12 s
We need to find the impulse received by the ball. The impulse delivered is given by :
[tex]J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m[/tex]
So, the impulse is 42 N-m..
We know that he change in momentum is also equal to the impulse delivered.
So, impulse = 42 N-m and change in momentum =42 N-m.
The moon Umbriel orbits Uranus (mass = 8.68 x 1025 kg) at a distance of 2.66 x 108 m. What is Umbriel's orbital speed?
Answer:
the orbital speed of umbriel is 16,800 km/h
Explanation:
The computation of the orbital speed is shown below
According to the question the Data provided in the question
Uranus mass = 8.68 × 10^25 kg
Distance = 2.66 × 10^8 m
Based on the above information, the orbital speed of Umbriel is
[tex]V = \sqrt{\frac{GM}{R} } \\\\ = \sqrt{\frac{((6.673e-11)(8.68e25)}{2.66e8} }[/tex]
V = 4666 m/s
= 16,800 km/h
Hence, the orbital speed of umbriel is 16,800 km/h
Therefore it can be calculated by applying the above formula
Answer: 4665
Explanation: I got it right after on acellus
a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we neglect air friction, how high is the cliff
Assuming the cannonball is fired horizontally, its horizontal velocity stays at a constant 76 m/s. At the point it hits the ground, it has a speed of 89 m/s, so if its vertical velocity at that moment is [tex]v_y[/tex], we have
[tex]89\dfrac{\rm m}{\rm s}=\sqrt{\left(76\dfrac{\rm m}{\rm s}\right)^2+{v_y}^2}\implies{v_y}^2\approx2145\dfrac{\mathrm m^2}{\mathrm s^2}[/tex]
(taking the negative square root because we take the downward direction to be negative)
Recall that
[tex]{v_f}^2-{v_i}^2=2a\Delta x[/tex]
where [tex]v_i[/tex] and [tex]v_f[/tex] are the initial and final velocities, respectively; [tex]a[/tex] is the acceleration; and [tex]\Delta x[/tex] is the change in position of a body. In the cannonball's case, it starts with 0 vertical velocity and is subject to a downward acceleration with magnitude [tex]g=9.80\frac{\rm m}{\mathrm s^2}[/tex]. So we have
[tex]2145\dfrac{\mathrm m^2}{\mathrm s^2}-0=-2g\Delta y\implies\Delta y\approx-109.44\,\mathrm m[/tex]
(which is negative because we take the cannonball's starting position at the top of the cliff to be the origin) so the cliff is about 109 m high.
which solid state component allows a mobile phone to store data even if the battery is removed
Answer:
Capacitor
Explanation:
Capacitor ; A capacitor is a passive two-terminal electrical component that can store energy in an electric field electrostatically. It works as a small rechargeable battery that stores electricity. However, unlike a battery, it can charge and discharge in the split of a second. Capacitors are widely used to build different types of electronic circuits.
How does work affect energy between objects so it can cause a change in the form of energy? Work transfers energy. Work changes energy. Work increases energy. Work decreases energy.
'Doing work' is a way of transferring energy from one object to another, energy is transferred when a force moves through a distance.
If i explain with formula
Work done (J) = Energy transferred (J)
So more energy, more work done bc u transferred more energy to move the object and doing the work. and if you only use a little of energy, the work done also only a little.
Work affect energy between objects so it can cause a change in the form of energy by transferring energy.
According to work energy theorem, the work done on an object is directly proportional to the change in the average kinetic energy of the body.
For example, a catapult used to project a stone, does a work by converting or transferring its stored elastic potential energy into kinetic energy of the flying stone.Thus, we can conclude that work affect energy between objects so it can cause a change in the form of energy by transferring energy.
Learn more here: https://brainly.com/question/10063455
A physics student throws a ball straight up. The student catches the ball in exactly the same place from which it was released. The ball’s time of flight is T, and its maximum height above its release point is H. Neglect air resistance and assume up is the positive direction. Find the ball’s average velocity during the second half of its trip. (Hint: Your answer should only have the variables H and T in it.)
Answer:
The correct answer is H ÷ ¹/₂T
Explanation:
The formula for velocity is distance covered ÷ time.
Neglecting air resistance;
If the ball's time of overall time flight is T, the time it will take for the second half/return trip is ¹/₂T.
If the ball's maximum height above its released point is H, the height will also be the distance it covered for the second part of the trip since the student caught the ball in the exact same place the ball was thrown. Hence, the distance for the second half of the trip will be H.
Since velocity = distance/time
The average velocity during the second half of the trip will be = H ÷ ¹/₂T
A running back with a mass of 70 kg travels down the field with a velocity of 5.0 ms . Calculate the kinetic energy of the football player
Explanation:
KE = ½ mv²
KE = ½ (70 kg) (5.0 m/s)²
KE = 875 J
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? Show all calculations and use SALT to describe the image.
Answer:
The height of the image of the candle is 20 cm.
Explanation:
Given that,
Size of the candle, h = 12 cm
Object distance from the candle, u = -6 cm
Focal length of converging lens, f = 15 cm
To find,
The height of the image of the candle.
Solution,
Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.
[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}[/tex]
v is image distance
[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm[/tex]
If h' is the height of the image. Magnification is given by :
[tex]m=\dfrac{h'}{h}=\dfrac{v}{u}[/tex]
[tex]h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm[/tex]
So, the height of the image of the candle is 20 cm.
andy runs 40 meters east in 5 seconds and then 100 meters west in 15 seconds his average velocity is?
Answer:
[tex]\Large \boxed{3}[/tex]
Explanation:
Info given;
∵ 40 meters east in 5 seconds
∵ 100 meters west in 15 seconds
=> [tex](100 -40)[/tex]
=> Divided by;
=> [tex](5 + 15)[/tex]
=> [tex]3 m/s[/tex]
Answer; 3 m/s
(Average velocity is; 3 m/s )
Why rolling friction less than sliding friction
The force of friction depends on the area of contact between the two surfaces. As the area of contact is less in the case of rolling than in the case of sliding that's why rolling friction is less than the sliding friction. More the contact area more the friction.
a ballon filled with nitrogen gas has a small leak. Another ballon filled with hydrogen gas has an identical leak. How much faster will the hydrogen balloon deflate
Answer:
4 times that of nitrogen gas, N2.
Explanation:
Let R1 be the rate of diffusion of nitrogen gas, N2.
Let R2 be the rate of diffusion of Hydrogen gas, H2.
Let M1 be the molar mass N2
Let M2 be the molar mass of H2.
Next, we shall determine the molar mass of N2 and H2.
This is illustrated below below:
Molar mass of N2 (M1) = 2 x 14 = 28 g/mol
Molar mass of H2 (M2) = 2 x 1 = 2 g/mol
Finally, we shall determine the rate of diffusion of Hydrogen gas, H2 as follow:
R1/R2 = √(M2/M1)
M1 = 28
M2 = 2
R1/R2 = √(M2/M1)
R1/R2 = √(2/28)
R1/R2 = √(1/14)
R1/R2 = 0.27
Cross multiply
R1 = R2 × 0.27
Divide both side by 0.27
R2 = R1/0.27
R2 = R1 × 1/0.27
R2 = R1 × 4
R2 = 4R1
Therefore, the rate of diffusion of H2 (R2) is 4 times that of N2 (R1)
The work function for cesium is 1.96 eV. (a) Find the cutoff wavelength for the metal, (b) what is the maximum kinetic energy for the emitted electrons when 425 nm light is incident on the metal
Answer:
Explanation:
λ = hc/¢
Where
h = the Plank constant 6.63 x 10-34 Is
C = 3.0×10^8
¢= 1.96eV
= (6.63×10^-34Js)×(3×10^8)÷( 1.96eV) × 1eV/1.6×10^-19J
= (1.989×10^-25)÷( 1.96eV)×1eV/1.6×10^-19J
= 6.342×10^-7m
B) maximum kinetic energy
= K=hf−ϕ ........1
ϕ = hc
Where
h = constant 6.63 x 10^-34Js
ϕ= 1.96eV
Recall
λ =425×10^-9m
f = frequency in Hz
f = c / λ
C = 3.0×10^8
f = 3.0×10^8 / 425×10^-9m
f = 0.000705Hz
From equation 1
K = (6.63 x 10^-34Js×0.000705Hz )- 6.63 x 10^-34Js×3.0×10^8
= 4.68×10^-37 - 1.989×10^-25
= - 1.98×10^-25J
When two bodies of different temperatures are placed together and left for sometime, Both of them attain the same temperature.
(Heat flows from a body of Higher temperature to a body of lower temperature)
Now after they attain the same temperature will there be
No transfer of heat between them
Or
Will there be an equal amount of heat lost and gained by both the bodies?
My answer would be an equal amount of heat is lost and gained by both the bodies
You can't exactly say that there is no heat transfer just because equal amount is lost and gained by the bodies right?
My text book says that there is NO transfer of heat once both the bodies attain same temperature
hi olivia hope this helps you
a ball is thrown down at 25 m/s from a 500m tall building. how fast is it traveling when it hits the ground?
Answer:
The speed of the ball when it hits the ground is 102.1 m/s
Explanation:
Given;
initial velocity of ball, u = 25 m/s
distance traveled by the ball = height of the building = h = 500 m
when the ball hits the ground, the final velocity, v = ?
The final velocity of the ball is given by;
v² = u² + 2gh
where;
g is acceleration due to gravity = 9.8 m/s²
v² = (25)² + 2(9.8)(500)
v² = 10425
v = √10425
v = 102.1 m/s
Therefore, the speed of the ball when it hits the ground is 102.1 m/s
How long will it take a charter bus full of people traveling 216 km/hr from Georgia to go 36 km to Florida's
Disney World theme park?
Answer:
t = 10.02 minutes
Explanation:
It is given that,
Speed of bus, v = 216 km/h
Distance to be traveled by the bus, d = 36 km
We need to find the time taken by the bus to cover the distance. Let the time is t.
Speed = distance/time
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{36\ km}{216\ km/h}\\\\t=0.167\ h[/tex]
or
t = 10.02 minutes
So, 10.02 minutes is taken by the bus.
who was albert einstien describe his contributions???
Answer:
Albert Einstein was from Germany he was born theoritical physicist, from childhood only he loved mechanical toys, he was highly gifted in Mathematics, He was a world citizen and a scientific genius too. His contribution were:
1) he developed the theory of relativity
2) he also discovered the process of nuclear fission
3)he developed the quantum theory of specific heat
4)theory of stimulated emission, on which laser device technology is based
5) law of photoelectric effect
hope it helped you :)
A metal sphere of radius 3cm made of brass is heated from
30°C to 100°C , Calculate the initial and final volume of the
metal sphere (Iinear expansivity of brass =0.000019k-¹ and volume of sphere =⁴/3 πr³
Answer:
Let:
r= radius= 3cm= 0.03m
∅1= initial temperature= 30°C
∅2= final temperature= 100°C
∆∅= change in temperature= ∅2 - ∅1= 70°C
L.E.= linear expansivity= 0.000019k^-1
¥= 3L.E.= volume expansivity= 3(0.000019)= 0.000057k^-1
The initial volume of the metal sphere= 4/3(πr³)
= 4/3(π×0.03³)
= 4(π×0.03²×0.01)
= 4(3.142×0.0003×0.01)
= 4(0.000009426)
= 0.000037704
= 3.7704 × 10^-5m³
¥= V2 - V1/V1∆∅
V2= ¥V1∆∅ + V1
= (1.5044 × 10^-7) + (3.7704×10^-5)
= 0.00003785
= 3.785 × 10^-5m³
Therefore, the initial and final volume of the metre sphere are 3.7704 × 10^-5 and 3.785 × 10^-5 respectively.
Q3. Three ants 1, 2 and 3 are pulling a grain with forces of magnitude 10 N, 4 N and FN as shown in the figure. Find the force F if the grain remains in equilibrium under the action of the above forces.
Answer:
F = 7.21 N
Explanation:
There are two methods to find the magnitude of F.
The first method is the analytical one and the second one is the geometrical one.
The easiest is the geometrical one.
We will start with it
■■■■■■■■■■■■■■■■■■■■■■■■■■
● Method 1:
The geometrical method
The grain remains in equilibrum under the action of 3 forces.
The 3 forces must give if joined together a close path.
There are 3 forces so the resulting shape is a triangle. (Picture 1)
● Al Kashi theorem:
We will use Al Kashi theorem (law of cosine) to find the magnitude of F.
● F^2 = b^2 + c^2 + 2bc×cosA
● F^2 = 10^2 + 4^2 + 2×10×4 × cos(37°)
● F^2 = 52.1
● F = 7.21 N
■■■■■■■■■■■■■■■■■■■■■■■■■■
● method 2 (analytical one)
This method is based on projecting each vector on the x and y axis.
Since the grain remains in equilibrum the relation between the vectors is:
● Vector F + Vector 1 + Vector 2 = Null vector
Vector one is the one with 4 N magnitude and 2 is the 10 one.
Project each vector following the x-axis and the y-axis and add them together.
(Picture 2)
● x-axis
F1 is the 4 N force and F2 is the 10 N one
● Fx + F1x + F2x = 0
● Fx -4 + 10 × cos(37°) = 0
F1x is negative since it goes toward the negatives numbers. It is parallel to the x-axis that's why we have put directly the magnitude
Fx2 is not parallel to the x-axis that's why we have expressed it using the cosine relation. (Picture 3)
● Fx -4 + 10 × cos(37°) = 0
● Fx = 4 -10 × cos(37°)
● Fx = -4 after rounding to the nearest unit
● y-axis
● Fy + F1y + F2y = 0
● Fy + 0 + sin(37°) × 10 = 0
F1y equals 0 since when projecting the vector's head and tail, both were in the same point. In other words the direction of the vector was perpendicular to the y-axis.
F2y is'nt parallel to the y-axis. That's why we have expressed it using the sine.
● Fy + sin(37°)×10 =0
● Fy = -10×sin(37°)
● Fy = -6 after rounding it to the nearers unit
Notice that F, Fx and Fy are creating a right triangle.(picture 4)
● The Pythagorian theorem
● F^2 = Fx^2 + Fy^2
● F^2 = (-4)^2 + (-6)^2
● F^2 = 16+36
● F^2 = 52
● F^2 = 7.21 N
That's the same result we got using the first method.
Answer:
F = 7.21 N
Explanation:
horizontal sum of forces = ∑h = 10 cos(37) - 4 = 3.98 N
vertical sum of forces = ∑v = 10 cos(90-37) = 6.02 N
therefore, the resultant F² = ∑h² + ∑v²
F = sqrt (3.98² + 6.02²)
F = 7.21 N
zeros are always considered significant digits when they are to the left of the decimal point True or False
Answer:
false
Explanation:
because they does'nt Work for anything, are like they are not there
Answer:
False
Explanation:
The rules for significant figures are:
Non-zero digits are always significant.Zeros between significant digits are also significant.Trailing zeros are significant only after a decimal point.A zero before a decimal point is only significant if there's a non-zero digit before it.
For example, in the number 10.5, the zero is significant, because it is between significant digits.
But in the number 0.5, the zero is not significant.
A charge of 19 nC is uniformly distributed along a straight rod of length 15 m that is bent into a circular arc with a radius of 5.7 m. What is the magnitude of the electric field at the center of curvature of the arc?
Answer:
The magnitude of the electric field at the center of curvature of the arc is 3.87 N/C
Explanation:
Please see the attachments below
What is the magnitude of displacement if a person goes 290 m east followed by 150 m west?
Answer:140 m
Explanation:
Displacement = 290-150= 140 m
Where on the periodic table would this element most likely be found? Group 1 Group 2 Group 12 Group 13
Answer:
The right approach will be Option C "Group 12".
Explanation:
A table that further arranges the chemical components in addition to expanding the electron configuration. Elements possessing identical characteristics are positioned in almost the same section (column or group), although elements in almost the same row become positioned with a similar amount of electron spheres.Group 12 components therefore partially replaced (n − 1)d subshells, and therefore aren't metals, technically accurate. However, although much their chemistry seems to be comparable to something like the components throughout the d block which includes establishing themselves.Some other options in question are not relevant to something like the given scenario. Because then the option here is just the right one.
Answer:
option C group 12
Explanation:
i did the test
Suppose all of the apples have a mass of 0.10 kg. If apple (A) is sitting on the ground, what is its potential energy?
Answer:
The answer is C 0.0
Explanation:
Because its sitting still on the ground.
Answer:
0.0j
Explanation:
convert 0.000238 m to cm
Answer:
0.0238 centimetre
Explanation:
multiply the length value by 100
Ariver is flowing at 3.6 m/s. A boy in a tube is floating the river downstream. If the boy can use
his arms to paddle at 1.7 m/s with the current, how fast will it appear he is moving to anyone on
the riverbank?
Answer:
The total speed is 5.3 m/s
Explanation:
The speed of river = 3.6 m/s
The speed of the tube that a boy use for downstream = 1.7 m/s
Now we have to find the total speed of the boy in the case of downstream. However, in this case, the total speed can be determined by adding both the given speeds.
The total speed = Speed of rive + speed of the tube
Total speed = 3.6 + 1.7
Total speed = 5.3 m/s
A tortoise travels 15 meters (m) west, then another 13 centimeters (cm) west. How many meters total has she walked?
Answer:
15.13m
Explanation:
change 15m to cm
1m=100cm
15m times 100=1500cm
add 1500+13 = 1513cm
in metres it will be 15.13m
Multiple of a unit of measure are found by multiplying the unit by an unteger larger than one
The total distance the tortoise walked in meters is 15.13 m
Reason:
Known parameter are;
The distance west the tortoise travels = 15 meters
The further distance west the tortoise walks = 13 cm = 0.13 m
Required:
The total (distance) in meters she has walked
Solution:
The total distance the tortoise walked in meters = 15 m + 0.13 m = 15.13 m
Learn more about multiples of units of measurement here:
https://brainly.com/question/1643372
A wrench weighs 5.24 N on Earth. When it is taken to the Moon, where g = 1.60 m / s? how much does it weigh? (Hint: Its mass does not change.) (Unit = N)
Answer:
The weight of the wrench on the Moon is approximately 0.8555 N
Explanation:
On Earth, the acceleration of gravity at sea level is 9.8 m/s^2
then if the wrench weights 5.24 N that means that its mass according to Newton's second law is:
[tex]F = m \, a\\m=\frac{F}{a} \\m=\frac{5.24}{9.8} \, kg\\m=0.5347[/tex]
Now we can use the wrench's mass to find its weight on the Moon, knowing that the acceleration due to gravity there is 1.6 m/s^2:
[tex]W=m\,g\\W=(0.5347) \,(1.6) \,N\\W=0.8555\,\,N[/tex]
Answer:
Explanation:
0.8555
What does this student most likely need to do in order to be better prepared to stay safe in a lab?
take off the goggles
change into lighter shoes
wear different clothing
tie back her hair
she needs to tie back her hair
A pair of narrow, parallel slits separated by 0.275 mm is illuminated by the green component from a mercury vapor lamp (λ = 546.1 nm). The interference pattern is observed on a screen 1.25 m from the plane of the parallel slit. Calculate the distance from the central maximum to the first bright region on either side of the central maximum.
Answer:
2.481 mm
Explanation:
Given that
Distance between the slits, d = 0.275 mm = 2.75*10^-4 m
Wavelength of the lamp, λ = 546.1 nm
Distance between slit and the screen, L = 1.25 m
To solve this question, we would be applying the formula for Young's double slit fringes, from the path difference equal to a whole number of wavelengths.
mλ = dy/L
The question states that we should find the distance from the centre to the 1st order bright fringe, thus, m = 1
Now, we apply all these values into the question
1 * 546.1*10^-9 = (2.75*10^-4 * y) / 1.25
1.25 * 1 * 546.1*10^-9 = 2.75*10^-4 * y
6.825*10^-7 = 2.75*10^-4 * y
y = 6.825*10^-7 / 2.75*10^-4
y = 0.002481 m or 2.481 mm
Contrast the sizes between that of a red blood cell against a single motor neuron.
Answer:
Explanation:The average human adult has more than 5 liters (6 quarts) of blood in his or her body. Blood carries oxygen and nutrients to living cells and takes away their waste products. It also delivers immune cells to fight infections and contains platelets that can form a plug in a damaged blood vessel to prevent blood loss
24. Compare and contrast the 'Big Bang Theory' with the 'Creation Model for the origin of the
universe.
*** Be sure to include similarities and differences between the 2 theories and information on
how and why these theories have developed over time. Use the Ven diagram on the next
page to assist you.