A car C moving with a speed of 65 km/h on a straight road is ahead of motorcycle M moving with the speed of 80 km/h in the same direction. What is the velocity of M relative to A?

Answers

Answer 1

Answer:

The answer is 15. Step by step is you times 80 by 65 and then you divided by 2 and you call your teacher


Related Questions

Which term describes one kind of movement of Earth?

eclipse
revolution
tilted orbit
lunar cycle

Answers

Answer:

revolution

Explanation:

the earth revolves around the sun

Answer: B, revolution

Explanation:

last one i promise!!

Answers

Answer:

B

Explanation:

because when they are in opposite direction we subtract so 10N-10N=0 the second one is in the same direction so we simply add the 2 numbers so 10N+10N=20N the last one is as the same as the first picture we subtract 10N-8N=2N

SOMEONE HELP! If I don't get this done i will fail, I have been trying for hours.

p.s. both questions have no answer choices.

1. If a baseball has a mass of 0.075kg and is traveling with an acceleration of 25 m/s2. What is the force that the baseball will hit the bat?

````````````````````````````````````````

2. Given the force diagram of the basketball, what can you tell about the basketball motion? (Diagram below)



Thanks in advance!!

Answers

Answer:

1. The baseball will hit the bat at a force of 1.875 Newtons (N)

2. The basketball is being pushed to roll to the right of its original position with an applied rightward force. There is a force of friction to the left, a normal force of the floor acting upwards on the ball, and a gravity force of the Earth acting downwards on the ball.

Explanation:

1. To calculate force, you just have to multiply mass (m) and acceleration (a). F = m * a --> F = 0.075kg * 25 m/s^2 = 1.875 N.

2. Use your knowledge of different types of forces and free-body diagrams to come to this conclusion.

How is aquatic biome classification different from terrestrial biome classification?

Answers

It’s by making baby’s with baby boomers

Answer: Terrestrial biomes are based on land, while aquatic biomes include both ocean and freshwater biomes.

Explanation:

A. A small, closed chamber of gas is heated. When the gas in the
chamber expands, it does 5 J of work on a piston. The gas has
an initial energy of 8 J and a final energy of 30 J. Considering
the equation for the first law of thermodynamics (AU = Q + W.
does the work done in this scenario have a positive or negative
value? Explain.
B. How much heat is added to the gas in the chamber?

Answers

A.

The work has a negative value.

Since the gas in the chamber expands, it increases in volume and does positive work on the piston since the change in volume is positive.

Work, W = pΔV. Since the gas expands, ΔV > 0. So, W > 0. Thus Work done by the gas is positive.

Since in ΔU = Q + W, W here is work done by the surroundings, W is negative since it is the opposite of the work done on the surroundings by the gas..

So, the work has a negative value.

B.

The heat added to the gas chamber is 17 J

From the first law of thermodynamics, ΔU = Q + W where ΔU = internal energy change = U₂ - U₁ where U₁ = initial energy = 8 J and U₂ = final energy = 30 J, Q = heat added to the gas chamber and W = work on piston = - 5 J

ΔU = Q + W

U₂ - U₁  = Q + W

30 J - 8 J = Q + (-5 J)

22 J = Q - 5 J

Q = 22 J + 5 J

Q = 27 J

The heat added to the gas chamber is 27 J.

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Short, difficult activities that push your body are called
A.
aerobic activity
B.
anaerobic activity
C.
muscle strength
D.
exercise

Answers

Answer:

B. is your answer

Explanation:

Have a good day

Sincerly, lipor

Short, difficult activities that push your body are called anaerobic activities.  Option b is correct

They are high-intensity exercises that do not require oxygen and primarily use stored energy sources within the muscles. Examples include weightlifting or sprinting.

Short, difficult activities that push your body are called anaerobic activity. Anaerobic activities are high-intensity exercises that do not require oxygen and primarily use stored energy sources within the muscles, such as weightlifting or sprinting. These activities help build muscle strength and improve power and speed.

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A object travels at constant negative acceleration. What does the graph of the object's velocity as a fun
(1 point)
O a curved line increasing from left to right
O a straight line with negative slope
O a straight line with positive slope
O a curved line decreasing from left to right

Answers

Constant = straight line
“Travels at constant negative acc.”
Which is negative slope

Solution: B. Straight line w/ neg. slope

Question 2 (4 points)
Listen
A 14,000kg freight train, coasting at 8.1m/s, strikes another car, and the two move
forward together at 3.6m/s.
What is the mass of the second car?
Paragraph
B
1
U
A
+

Answers

Answer:

Explanation:

I will ASSUME that the struck car was initially at rest. Would not have to be, but a different mass will result if it was

Conservation of momentum

14000(8.1) + m(0) = (14000 + m)(3.6)

14000(8.1) = 14000(3.6) + m(3.6)

m = 14000(8.1 - 3.6) / 3.6

m = 17500 kg

The mass of the second car is 17500 kg.

What is law of conservation of momentum?

The law of conservation of momentum asserts that, unless an external force is applied, the total momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.

Newton's third law of motion has a direct impact on the idea of momentum conservation.

mass of the first car = 14000 kg.

Initial speed of first car = 8.1 m/s.

Final speed of the two cars = 3.6 m/s.

From law of conservation of momentum; we can write:

Total initial momentum = total final momentum

14000 kg ×8.1 m/s + m×0 = (14000 + m) kg × (3.6 m/s)

14000(8.1) = 14000(3.6) + m(3.6)

m = 14000(8.1 - 3.6) / 3.6

m = 17500 kg

Hence, the mass of the second car is 17500 kg.

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Identify the direction of the net force acting on the object. Explain your reasoning

Answers

Answer:

See Below

Explanation:

I am not sure what you exact question is to know what direction it is but here is how you do it.

The direction of the net force is the direction of the largest force.

for example if you were to push a box forward with 100 newton's of force and someone pushed at the same time 50 newton's backwards on the box, the box would move forwards because the was a greater force on the box in a forward direction. hope this helps

What is gravitation ? ​

Answers

Explanation:

1. Movement, or a tendency to move, toward a center of gravity, as in the falling of bodies to the earth.

2. Movement toward or attraction to something.

"a tentative gravitation toward the prices that we saw before the announcement"

This drawing of the field lines between these two charged plates is correct.

True or false

Answers

Answer:

True

Explanation:

Since positive and negative forces are both opposites of each other they attract. But if the forces are the same where both are positive or negative thye repel do to being the same charges in that case the picture would show lines moving in opposite directions.

HELP ASAPPPPPPPPPPPPPP

Answers

Answer:

F=15N

Explanation:

F=m.a

m=1500g ÷1,000 = 1.5kg

a= 10m/s/s

F =1.5 × 10

F = 15 Newton

 A wooden box with a mass of 10.0 kg rest on a ramp that is incline at an angle of 25° to the horizontal. A rope attached to the box runs parallel to the ramp and then passes over a frictionless bully. A bucket with a mass of M hangs at the end of the rope. The coefficient of static friction between the ramp in the box is 0.50. The coefficient of Connecticut friction between the ramp in the box is 0.35.

Suppose the box remains at rest relative to the ramp. What is the maximum magnitude of the friction force exerted on the box by the ramp?

Answers

The maximum magnitude of the friction force exerted on the box by the ramp is 44.41 N.

The given parameters;

Mass of the box, m = 10 kgInclination of the ramp, θ = 25⁰Coefficient of static friction, μ = 0.5 Coefficient of kinetic friction, μk = 0.35

The normal force on the wooden box is calculated as follows;

[tex]F_n = mg \times cos(\theta)\\\\F_n = 10 \times 9.8 \times cos(25)\\\\F_n = 88.8 2 \ N[/tex]

The maximum magnitude of the friction force exerted on the box by the ramp is calculated as follows;

[tex]F_f = \mu \times F_n\\\\F_f = 0.5 \times 88.82 \\\\F_f = 44.41 \ N[/tex]

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A boat is headed north at a velocity of 8 km h-1. A strong wind is blowing whose pressure on the boat’s superstructure causes it to move sideways to the west at a velocity of 2 km h-1. There is also wave present that flows in a direction 30° south of east at a velocity of 5 km h-1. What is the velocity of the boat?​

Answers

The velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

The given parameters;

velocity of boat northwards, = 8 km/hvelocity of the boat westwards, = 2 km/hvelocity of the wind, = 5 km/h 30° south of east

The resultant vertical velocity of the boat is calculated as;

[tex]v_y = 8 \ - \ 5 sin(30)\\\\v_y = 8 - 2.5\\\\v_y = 5.5 \ km/h[/tex]

The resultant horizontal velocity of the boat is calculated as;

[tex]v_x = -2 \ + 5cos(30)\\\\v_x = 2.33 \ km/h[/tex]

The resultant boat velocity is calculated as follows;

[tex]v = \sqrt{v_x^2 + v_y^2} \\\\v = \sqrt{2.33^2 + 5.5^2} \\\\v = 5.97 \ km/h[/tex]

The direction of the velocity;

[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{5.5}{2.33} )\\\\\theta = 67 \ ^0[/tex]

Thus, the velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

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Can you please do this for me I’ll do 75 points

Answers

Answer:

Answer below, hope this helps!

Explanation:

1. Chemical - e

2.Light - b

3. Sound - g

4. Mechanical - f

5. Kinetic - a

6. Potential - d

7. Energy - j

8. Thermal - c

9. Nuclear - i

10. Electrical - h

Answer:

Chemical - e

Light - b

 

Sound - g

Mechanical - f

Kinetic - a

Potential - d

Energy - j

Thermal - c

Nuclear - i

Electrical - h

Explanation:

David and Fiona want to know about how mass affects the motion of an object. David uses three objects with masses of 2 kg, 3 kg, and 8 kg, writes out his procedure, and records his observations on the force needed to move the objects. Fiona is investigating three different objects using observation. What is the difference in the way they approached this question?

A. Only Fiona gathered evidence from her investigation.
B. David used scientific articles for evidence.
C. David's observations can be replicated by repeating his procedure.
D. Fiona's observations can be replicated by observing different objects.

Answers

Answer: the answer is D if its not i'm really sorry

a=100m/s2
Vi=10m/s
T=10sec
Vf?

Answers

Answer:

v=u+at

v= 10+100×10

v = 10+1000

v = 1010 m/s

During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the hanging masses and other forces present is 0.91 J. At the initial time of observation the cart moves with speed 0.61 m/s. Determine the speed at the second point of observation. The mass of the cart is 0.80 Kg.

Answers

Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

KE₀ + W = KE₁

½mv₀² + W = ½mv₁²

½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²

v₁ = 1.626991...

v₁ = 1.6 m/s

The speed of the cart at the second point of observation is equal to 1.62 m/s.

What is the work done?

Work can be demonstrated as the energy utilized when a force is exerted to make an object move through a particular displacement. Work done by this force is calculated from the product of the magnitude of the exerted force (F) and the distance (d) covered by the body

W= F.d

Where 'F' is the exerted force and 'd' is the displacement and W is work done.

Work and energy have a direct relationship with each other. Work done by an object can be expressed as a change in kinetic energy:

[tex]W =\frac{1}{2}mv_2^2- \frac{1}{2}mv_1^2[/tex]

Where m is the mass of the object, v₂ is the final velocity (m/s), and v₁ is the initial velocity (m/s).

Given, the work done by the cart, W = 0.91 J

The mass of the cart, m = 0.80 Kg

The speed of the cart at the first point, v₁ = 0.61 m/s

[tex]0.91 =\frac{1}{2}\times 0.80 \times v_2^2- \frac{1}{2}0.80 \times (0.61)^2[/tex]

0.40 v₂² = 1.06

v₂² = 2.65

v₂ = 1.62 m/s

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. If the frequency of a system undergoing simple harmonic motion doubles, by what factor does the maximum value of acceleration change

Answers

Answer:

a1 = -w^2 A sin w t        where w is the angular frequency

a2 =  - (2 w)^2 A sin 2 w t       where w2 = 2 w1

a2 / a1 = 4 sin 2 w t / sin  w t

Since sin 2 w t / sin w t = 2     sin w t will change twice as fast

a2 / a1 = 8      the max acceleration must change 8 tims as fast

HELPP

When two forces are in opposite directions, and they are the exact same magnitude, the forces will _______.

a. subtract from each other
b. cancel out
c. go on infinitely
d. eventually reach equilibrium

Answers

Answer:

i think the correct answer is B. cancel out

A and E are wrong i think please solve this thank you.

Answers

Answer:

I think number 3.

Explanation:

A wooden barrel full of water has a flat circular top of radius 25.0 cm with a small hole in it. A tube of height 8.00 m and inner radius 0.582 cm is suspended above the barrel with its lower end inserted snugly in the hole. Water is poured into the upper end of the tube until it is full. The density of water is 1.00 × 103 kg/m3.
What is the force with which the water in the barrel pushes up on the top of the barrel?

Answers

Answer:

that is all i know

Explanation:

radius= 25.0cm

height= 8m

inner radius= 0.582cm

density= 1.00 × 103kgf= m× a

5. The net external force on a rock of mass 4.2 kg is 8.0 N forward. Find the acceleration of the rock.

Answers

Answer:

1.904

Explanation:

F= ma

8 = 4.2 a

a = 8/4.2

a = 1.904

The flow of ground water is

Answers

Answer:

In hydrogeology, groundwater flow is defined as the "part of streamflow that has infiltrated the ground, entered the phreatic zone, and has been (or is at a particular time) discharged into a stream channel or springs; and seepage water." It is governed by the groundwater flow equation.

At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away

Answers

Answer:

op

Explanation:

At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away

If you have a light bulb connected to a circuit and you increase the current, what happens to the light bulb and the power (assuming the voltage remains the same)? A. The light bulb shines brighter and the power decreases. B. The light bulb shines brighter and the power increases. C. The light bulb gets dimmer and the power decreases. D. The light bulb gets dimmer and the power increases.

Answers

Answer:

B. The light bulb shines brighter and the power increases.

Explanation:

Power is the product of voltage and current . Increasing the current at a constant voltage will increase the power.

Increasing the power means more heat and therefore more light must be emitted.

can someone help me answer this question? A student connected an ammeter as shown in this picture. Did the student connect the ammeter correctly? Explain

Answers

Answer:

No - It is connected in parallel instead of series

Explanation:

The answer is No, the reason behind the answer that the ammeter is connected in parallel which is wrong it must be connected in series.

What is Ammeter?

An ammeter is a device for detecting electric current in amperes, either directly (DC) or alternating (AC). Due to the fact that a shunt running parallel to the meter carries the majority of the electricity at high current values, the digital multimeter can measure a wide range of current values. A circle with the capital A in it serves as the icon for an ammeter for circuit diagrams.

The moving coil of the electrodynamics ammeter rotates in the field created by the fixed coil. It measures alternating and direct current with 0.1 to 0.25 percentage points (by converting Ac power To DC power using a rectifier).

The ammeter is connected in series and, on the other hand, the voltmeter is connected in parallel.

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i’m confused on this worksheet can someone help

Answers

Answer:

well for C the horse is at rest at 10 to 15

D is 0 to 10

E is 15 to 25

Explanation:

If you search up examples it will help with this worksheet.

If I am work then I appologize

what do i do for #17

Answers

Answer:

whats the question...............

Explanation:

i need help with these please

Answers

Answer:

                             

Explanation:

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