A bungee jumper jumps from a bridge and starts accelerating towards a lake below. What energy transfer is he experiencing?

Group of answer choices

a. Elastic potential to kinetic

b. Kinetic to elastic potential

c. Kinetic to gravitational potential

d. Gravitational potential to kinetic

B. The amount of work done by the worker on the wheelbarrow is 250 J.

The amount of work done by the worker on the wheelbarrow is calculated as follows;

W = Fd

where;

W = 50 x 5

W = 250 J

Thus, the amount of work done by the worker on the wheelbarrow is 250 J.

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i. The work done by the load is load x distance moved by load.

ii. The work done by effort is effort applied x distance moved by effort.

iii. The mechanical advantage of the simple machine is Load/effort.

iv. The velocity ratio of the simple machine is 2.

v. The efficiency of the machine is M.A/V.R x 100%.

The work done by the load is the product of the load and the distance through which the load is moved. The magnitude is calculated as follows;

Work done by the load = load x distance moved by load

The work done by the effort is the product of the effort and the distance through which the effort is applied. The magnitude is calculated as follows;

Work done by effort = effort applied x distance moved by effort

M.A = Load/Effort

V.R = distance moved by effort / distance moved by load

V.R  = 30 cm/15 cm

V.R = 2

E = (M.A/V.R) x 100%

Thus, the work done by the load is load x distance moved by load.

The work done by effort is effort applied x distance moved by effort.

The mechanical advantage of the simple machine is Load/effort.

The velocity ratio of the simple machine is 2.

The efficiency of the machine is M.A/V.R x 100%.

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A vehicle that weights 400 n on the surface of the earth is traveling in outer space at a speed of 400 m/s. It can be stopped by applying a constant force of 20 n for 800 secs.

Newtons 3 law whilst one object exerts pressure on any other object, the second object exerts a force on the first item this is identical in significance, but opposite in course; for each movement, there is an identical, but opposite response; referred to as the law of action-reaction.

You can use the equal formulation d = rt because of this distance equals the price instance's time. To solve for speed or rate use the components for pace, s = d/t this means that pace equals distance divided by way of time. To clear up for time use the components for time, t = d/s this means that time equals distance divided by way of velocity.

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The correct option  is D.

The three lowest-pitch tones generated by this pipe have wavelengths of = 2 L, L, 2 L/3

Measuring a wave's size from one peak to the next is all that is required. The wavelength is only the separation between the crests of the successive waves, if one thinks of a sound wave as being similar to a water wave.

The length of a pipe with an opening at either end and a length l is given by:

[tex]l=\frac{n \lambda}{2}[/tex]

or

[tex]\lambda=\frac{2 l}{n}[/tex]

Initial pitch tone: n = 1.

[tex]\lambda_{1}=2 l[/tex]

The first pitch tone has n = 2

[tex]\begin{aligned}\lambda_{2} &=\frac{2 l}{2} \\\lambda_{2} &=l\end{aligned}[/tex]

The initial pitch tone has n = 3.

[tex]\begin{aligned}&\lambda_{3}=\frac{2 l}{3} \\&\lambda_{3}=\frac{2 l}{3}\end{aligned}[/tex]

The three lowest-pitch tones generated by this pipe have wavelengths of 2 L, L, and 2 L/3, respectively.

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I understand that the question you are looking for is :

Consider a pipe of length L that is open at both ends. What are the wavelengths of the three lowest-pitch tones produced by this pipe?

Answer

A. 2L, L, L/2

B. 2L, L, L/2

C. 4L, 2L, L

D. 2L, L, 2L/3

E. 4L, 4L/3, 4L/5

length of V-50 = 49mm

length of V-1 = 49/50mm

= 0.98mm

so,

minor measurement = (M-1) - (V-1)

= 1mm -0.98mm

= 0.02mm

☆ Therefore,

The minor measurement of the vernier scale is 0.02mm.

☆...hope this helps...☆

_♡_mashi_♡_

The measure of the angle EFD = 34°. That is option A.

The radii of the given circle are CE and CD.

The measure of the given angle of the arc is = 68°

But the central angle of an intercepted arc measure the double of the inscribed angle by the same arc.

Therefore, the measure of angle of an intercepted arc is 68/2 = 34°

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Answer:

34

Explanation:

edge 2023

The time lapse between when the bat emits the sound and when it hears the echo is 0.05 s.

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

Time (t) =?

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

t = 0.05 s

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s.

A bat emits a sound wave and carefully listens to the echoes that return to it. The returning information is processed by the bat's brain in the same way that we processed our shouting sound with a stopwatch and calculator. The bat's brain determines the distance of an object by measuring how long it takes for a noise to return.

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Correction question:

A bat emits a sonar sound wave (343 m/s) that bounces off a mosquito 8.42 m away. How much time elapses between when the bat emits the sound and when it hears the echo? (Unit = s)

If you will be rinsing your regulator after removing it from the cylinder, you must make sure that the dust cap is firmly in place.

A dust cap is a gently curved dome mounted either in concave or convex orientation over the central hole of most loudspeaker diaphragms.

Thus, if you will be rinsing your regulator after removing it from the cylinder, you must make sure that the dust cap is firmly in place.

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Answer:

Solids

Explanation:

Solids, liquids, and gases all have mass.

The emf in the coil when the magnetic field is 50.0 mT is 31.78 V.

What is emf?

According to Faraday's law of electromagnetism, the emf of a coil  

is the negative of the rate of change of magnetic flux with respect to time.

The emf of a coil is given by the formula,

[tex]E=-\frac{d\phi}{dt}[/tex]

where E is the emf, dΦ is the change in flux and dt is the change in time.

Magnetic flux: The scalar product of the magnetic field B and the total area vector A perpendicular to it is called the magnetic flux. The magnetic flux for a circular coil with n number of turns is given by,

[tex]\phi=n\pi r^2B[/tex]

where r is the radius of the coil.

Substitute [tex]\phi=n\pi r^2B[/tex] in the above equation and solve it.

[tex]E=-\frac{d(n\pi r^2 B)}{dt}\\E=-n\pi r^2 \frac{dB}{dt}[/tex]

Where dB/dt is the rate of change in the magnetic field with respect to time.

Note: 1mT/ms= 1 T/s, 1 cm= 0.01 m and 1mT=0.001 T

Given the magnetic field changes from 10.0mT to 80.0mT, the change in magnetic field dB = 80-10=70mT. The time interval dt= 20.0ms. Therefore,

dB/dt = 70/ 20 =3.5mT/(ms)

dB/dt = 3.5 T/s

Substitute dB/dt= 3.5T/s,  n=400, r=8.5 cm or r=0.085 m in the formula of E and solve it. Since the value of magnitude is positive, ignore the negative sign.

E=400*π*(0.085)^2*(3.5)

E=31.78 V

Since the rate of change of magnetic field is constant, so the magnitude of the emf of the coil will remain the same at all instants. Hence E=31.75 V when the magnitude of the magnetic field is 50.0 T

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Explanation:

Step I: 1 day means 24 hours * 60 minutes * 60 seconds.

So 1 day have 86400 seconds.

Step I:

Now,

To calculate the travel distance 20,000m/s* 84600 is 1728000000m

Step Ill:

Now convert the meter in kilometer

Because 1 km = 1000 m

So, = 1728000000/1000 = 172800OKm

The orbital speed of the satellite is 7.35*10^3 m/s.

What is orbital speed?

The speed of the satellite in its orbit is termed the orbital speed.

The orbital speed is given by the formula,

[tex]v=\sqrt{\frac{GM}{r}}[/tex]

where G is the universal gravitational constant, M is the mass of the planet and r is the distance of the satellite from the center of the planet.

Here the distance of the satellite from the center of the planet is the sum of the planet's radius and the height attained by the satellite above the ground. So

r=6370 + 1000

r=7370 km

Given the mass of the planet is 5.97*10^24 kg and the value of the gravitational constant is 6.67*10^(-11) N m^2 kg^(-2), substitute these values in the formula of the orbital speed.

Note: 1 km=1000 m

[tex]v=\sqrt{\frac{6.67\times10^{-11}\text{ N m}^2\text{kg}^{-2}\times5.97\times10^{24} \text{ kg}}{7370 \text{ km}}} \\ v=\sqrt{\frac{6.67\times10^{-11}\text{ N m}^2\text{kg}^{-2}\times5.97\times10^{24} \text{ kg}}{7370\times 1000 \text{ m}}} \\ v= 7.35\times 10^3 \text{ m/s}[/tex]

Hence the orbital velocity of the satellite is 7.35*10^3 m/s.

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Answer:

Explanation:

v = 30m/s, u = 6m/s, t = 6s

Change in velocity = v(final velocity) - u (initial velocity)

v-u = 30-6 = 24m/s

acceleration = (v-u)/t

(24m/s)/6s = 4m/s^2

Volt is the unit that measures the pressure or force that pushes the flow of electrons forward through a conductor.

When there is a circuit having a cell / battery , that cell/battery forms an electric field due to difference in voltages , and set a voltage of value equals to the difference in the voltage of two end of that cell/ battery . Because of which a electric field got set up in the conductor , which pushes electron to move inside the conductor . Unit of voltage is volt .

VOLT - A unit of electrical pressure (or electromotive force) which causes current to flow in a circuit. One volt is the amount of pressure required to cause one ampere of current to flow against one ohm of resistance. VOLTAGE - That force which is generated to cause current to flow in an electrical circuit.

Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light. In brief, voltage = pressure, and it is measured in volts (V).

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Voltage is the unit that measures the pressure or force that pushes the flow of electrons forward through a conductor.

Voltage is the electrical potential, potential difference and electromotive force in meter , kilogram, second system.The standard unit of measurement used for the expression of voltage is volt which is represent by symbol "V".

High voltage cable is used for electric power transmission at high voltage.A cable that includes conductor and insulation. cable which are considered to be fully interested. That means that they have fully rated insulted system that will consist of insulation , semi-con layers.

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1. E is a vector pointing to the right.

2. E is a vector pointing to the left.

3. E is a vector pointing to the right.

4. E is a vector pointing to the left

A vector is an object that has both a magnitude and a direction

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Explanation:

a. The force acting down is gravity, on Earth gravity is 10 m/s^2. When the skydiver jump, the acceleration will start out as -10 m/s^2, but it will eventually equals the air resistance , which is called terminal velocity.

For vibrational motion, the amplitude denotes the maximum displacement from the equilibrium position.

What is vibrational motion?

The motion in which there are some vibrations about the fixed position called mean position is termed vibrational motion. For example, the motion of a wave on the string has perpendicular vibration.

What is amplitude?

The amplitude is defined as the maximum displacement of the vibration from its mean position. For vibrational motion, the mean position is the equilibrium position. So amplitude is the term that denotes the maximum displacement from the equilibrium position. For example, the displacement of the string wave from its equilibrium position is the amplitude of the string wave.

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The membrane is depolarized compared to the resting membrane potential.

Through conformational changes from closed, nonconducting states to an open, current-conducting state, membrane depolarization activates sodium channels. Na+ channels open slowly and change from an open state to a nonconducting, rapidly inactivated state as a result of delayed openings, which contribute to the declining fraction of INa induced by prolonged depolarization. Additionally, sodium channels can move swiftly from the closed state to the fast-inactivated state. When the membrane is depolarized, inactivated channels are prevented from opening.

The distribution of channels between the closed and slow-inactivated states, however, limits the number of excitable sodium channels as a function of the membrane potential since slow inactivation acts at greater negative potentials than fast inactivation.

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noob anyways I can't get u vape because first reason I lost ur money and second I felt bad for losing ur and I will not on yourself as I am thinking of a number my number is a multiple of 6.What other numbers must my number is a multiple of 6.What other numbers

The initial temperature of the metal was 94.24⁰C.

The initial temperature of the metal is calculated as follows;

Q = mcΔθ

where;

Δθ = Q/mc

Δθ = (3,300) / (0.854 x 150)

Δθ = 25.76⁰C

Δθ = T₂ - T₁

T₁ = T₂ - Δθ

T₁ = 120 - 25.76

T₁ = 94.24⁰C

Thus, the initial temperature of the metal was 94.24⁰C.

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The horizontal component of the plane's velocity is 85.96 mph and the vertical component of the plane's velocity is 487.5 mph.

The component form of the velocity of the airplane includes both horizontal and vertical velocity and it is calculated as follows;

Vx = V cosθ

Vy = V sinθ

where;

θ = 170 - 90 = 80⁰

Vx = 495 mph (cos 80)

Vx = 85.96 mph

Vy = 495 mph (sin 80)

Vy = 487.5 mph

Thus, the horizontal component of the plane's velocity is 85.96 mph and the vertical component of the plane's velocity is 487.5 mph.

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Answer:

The direction of the net force is at a tangent to the circle.

The thick cloud cover of Venus makes it difficulty in visibility  because of impenetrable in visible light which has made it tough for astronomers to measure the length of the planet's day . Whereas Mars have clear atmosphere which do not hinder visibility

The most important reason of why is it difficult to measure the length of the day on Venus is tougher than in mars is that Mars' atmosphere is generally clear because of which their is no visibility issue on mars but due to the thick cloud covering of Venus makes it impenetrable in visible light , due which visibility is not that clear  and it become tough to observe the length of the day on Venus.

Mars is much larger than Venus in size which makes easier to observe

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Galaxy M33 is classified as a Triangulum normal spiral.

The galaxy M33 is the third largest galaxy in the Local Group after M31 and the Milky Way. The galaxy M33 has a moderate-sized central bulge and two spiral arms that emerge directly out of the bulge and wrap around in rather poorly defined arcs with many cross-connections between the arms.

This spiral galaxy is located in the triangle shaped constellation earning a pet name as triangular galaxy. This galaxy star formation rate is ten times higher than average found in Andromeda galaxy.  It has relatively bright apparent. This galaxy was given by Charles Messier and he classified it as Triangulum normal spiral.

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Answer:

F = Q E      force acting on charge Q due to field E

A positive electric field is directed from positive to negative.

An electron will be attracted to the positive terminal.

Thus if the electric force is upwards the direction of the field must be directed downwards, or

if F is positive and Q is negative E must also be negative or downwards.

(taking upwards as positive)

A 1500 pound car is stopped in traffic on a hill that is at an incline of 10. The force that is required to keep the car from rolling down the hill will be 1133.53 N.

When all the forces that act upon an object are balanced, then the object is said to be in equilibrium motion. The forces are considered to be balanced if the rightward forces are balanced by the leftward forces and the upward forces are balanced by the downward forces.

It can be observed from the diagram that in order resist the car to rolling down the hill we need to apply an equal and opposite force against the inclined force( that is mgsin(x)) to form an equilibrium position because rolling is associated with horizontal forces hence we need to apply force against the force which can drive down the car .

mass = 1500 pound = 680.39 kg

sin(10) = 0.17

F (counter force ) = m*g*sin(x)

                             = 680.39  * 9.8 * 0.17

                             = 1133.53 N

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The change in the object’s gravitational potential energy is 2.11 J.

ΔP.E = mg(hf - hi)

where;

ΔP.E = 0.54 x 9.8(1.1 - 0.7)

ΔP.E = 2.11 J

Thus, the change in the object’s gravitational potential energy is 2.11 J.

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A. What can happen to energy in a system is that it can be converted.

The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

The energy of a system can be converted from one form to another.

Thus, what can happen to energy in a system is that it can be converted.

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Clouds of gas in space

A protostar resembles a star, but its core is still too cool for fusion to occur. The protostar's heating as it contracts is the only source of brightness. The light that protostars release is typically blocked by dust, making them challenging to study in the visible spectrum.

By the time a protostar is produced, the cloud has flattened and a protostellar disk is spinning around it. The cloud starts spinning as it collapses. These disks occasionally form planetary systems and are thought to slow the protostar's rotation. The protostar produces a powerful magnetic field as it revolves.

Additionally, a strong protostellar wind—a movement of particles into space—is produced by the magnetic field. A lot of protostars also release gas into space in the form of fast-moving streams or jets.

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Answer: A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. Energy loss will be 0.29J

Explanation: To find the correct answer, we have to know more about the Gravitational potential energy.

                                          [tex]U=mgh[/tex]

                                        [tex]E=U_i-U_f[/tex]

                 [tex]U_i=mgh_i=60*10^-3kg*9.8m/s^2*2m=1.176 J[/tex]

                 [tex]U_f=mgh_f=60*10^-3kg*9.8m/s^2*1.5m=0.882J[/tex]

                [tex]E=1.176-0.882=0.294J[/tex]

Thus, we can conclude that, the energy loss will be,0.294J.

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