A box contains four bags of sugar. The total mass of all four bags is 6 kg. What is the mass of each bag in grams?

Since the two triangles are congruent, we can square the triangle's side to find 't'.

Therefore, t equals 25.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Answer:

C. 170

Step-by-step explanation:

68/4=17

17 is 10% of the unknown number

17 times 10 is 170

Answer:

Step-by-step explanation:

68 is 40% of what number?

A.17

B.136

C.170

D.270

68 : 40 * 100 = 170

Answer:

Its Number of Seats

Step-by-step explanation:

Answer:674.475

Step-by-step explanation:

(690)(0.15)= 103.5

690-103.5= 586.5 (after first markdown)

(586.5)(0.15)= 87.975

586.5+87.975 (Final price after markup)

Answer:

The answer is going to be A

Step-by-step explanation:

Answer:

Because it is decimal

Step-by-step explanation:

Decimal do not have remainder

Hi can you translate into English then I would be happy to help

Answer: [tex]\frac{19}{14}[/tex] in improper form and [tex]1\frac{5}{14}[/tex] in mixed fraction form.

Step-by-step explanation: [tex]\frac{6}{7}[/tex] + [tex]\frac{1}{2}[/tex] = ? First you have to find the LCM (Least Common Multiple) of 7 and 2; also known as the LCD (Least Common Denominator). The LCM of 7 and 2 is 14 so you have to multiply both of the fractions by the number that equals 14, remember to multiply it for the numerator too. [tex]\frac{6}{7}[/tex] x [tex]\frac{2}{2}[/tex] = [tex]\frac{12}{14}[/tex] Then [tex]\frac{1}{2}[/tex] x [tex]\frac{7}{7}[/tex] = [tex]\frac{7}{14}[/tex] Now you add [tex]\frac{12}{14}[/tex] and [tex]\frac{7}{14}[/tex] together. You leave the denominator as 14 because you found the LCD of 7 and 2 already, so you add 12 and 7 together which gives you 19. The answer would be [tex]\frac{19}{14}[/tex] in improper fraction form and [tex]1\frac{5}{14}[/tex] in mixed fraction form.

The sum of the fraction 6/7 and 1/2 is 19/14

Given:

sum of 6/7 and 1/2

Sum means addition(+)

= 6/7 + 1/2

The least common denominator is 7 × 2 = 14

= 6/7 + 1/2

= (12+7) / 14

= 19/14

Therefore, the sum of 6/7 and 1/2 is 19/14

Learn more about fraction:

https://brainly.com/question/11562149

Answer:

-5

Step-by-step explanation:

We use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)

    = ( 7-2)/(5-6)

    = 5/-1

    = -5

Answer:

the answer is : 180° - (61° +61°) = 58°

7 x 27               189

              =    -------------------

9 x 1                     9

Equations are used to represent functions, and vice versa.

The equation of y as a function of x is [tex]y=\sqrt{6 - x^2[/tex]

The function is given as:

[tex]\sqrt{6-y^2}=x[/tex]

Square both sides

[tex]6-y^2=x^2[/tex]

Subtract 6 from both sides

[tex]-y^2=x^2 - 6[/tex]

Multiply both sides by -1

[tex]y^2=6 - x^2[/tex]

Take square root of both sides

[tex]y=\sqrt{6 - x^2[/tex]

Express as a function

[tex]f(x) = \sqrt{6- x^2[/tex]

Hence, the equation of y as a function of x is [tex]y=\sqrt{6 - x^2[/tex]

Read more about functions and equations at:

https://brainly.com/question/13336451

Answer:

y=-2x+4

Step-by-step explanation:

Since it is parallel, it has to have the same slope m=-2. Just use the equation y-y=m(x-x) to solve the equation of the line.

[tex]y-y_0=m(x-x_0)\\y-(-2)=-2(x-3)\\y+2=-2x+6\\y=-2x+4[/tex]

Answer:

$572

Step-by-step explanation:

Answer:

10 to 11 would be correct

Answer:

10 to 11

Step-by-step explanation:

Answer:

Equations 1 & 3 are correct.

Explanation:

Equation 2's actual answer is -8, and Equation 4's actual answer is positive 7.

Answer:

1 and 3 are correct

Step-by-step explanation:

Answer:

If I am wrong I appologize I haven't done this math in years

Step-by-step explanation:

60÷7= 8.57

so each mile takes 8.57 mins

24÷8.57= 2.8 miles

Answer:

8

Step-by-step explanation:

this is because a square has 4 and one side has a measurement of 2in

so you would and all the sides (2+2+2+2) which will give you an answer of 8

Answer:

x=8

Step-by-step explanation:

x+x+5=x+x+x-3

2x+5=3x-3

Subtract 2x from both sides.

5=x-3

Add 3 to both sides.

8=x

-hope it helps

It's probably 52 or 40.

Step-by-step explanation:

Need to find out total hours and total pay and simplify the answer.

Total Hours = 1+2+3+4+5+6 = 21

Total Pay = 25+40+55+70+85+100 = 375

Pay ÷ Hours = 375 ÷ 21 = 17.86

Not convinced with this answer tbh but it's what I got.

[tex]W(-2,-1) \to \\W \ ' \ (-4,4)\\\\X(0,2) \to \\X \ ' \ (0,4)\\\\Y(3,-1) \to \\Y \ ' \ (6,-2)\\\\V(-2,-1) \to \\V \ ' \ (-4,-2)\\\\[/tex]

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Explanation:

The scale factor is 2, which means we double each coordinate of each point. The general rule is [tex](x,y) \to (kx,ky)[/tex] with k = 2. So we can say the more specific dilation rule is [tex](x,y) \to (2x,2y)[/tex]

Something like W(-2,2) moves to W ' (-4, 4) after multiplying each coordinate by 2. Do the same for the other points as well.

The given preimage points

will dilate to the corresponding image points

as shown below. This causes the image to be larger compared to the preimage (since the scale factor is larger than 1). Any given point is twice as far from the origin as compared to before, which in turn means the distance between any two points is twice as much.

Answer:

Yes

Step-by-step explanation:

They are equal acute triangles, are congurent. Your welcom

Let's simplify step-by-step.

[tex]12a^2*b^4-36a^2*b+44abc=[/tex]

There are no like terms.

Answer:

[tex]12a^2*b^4-36a^2*b+44abc=[/tex]

Probabilities are used to determine the chances of events.

The given parameters:

[tex]n = 5[/tex] ---- the number of candy bars

[tex]p = 40\%[/tex] ---- the probability of selling a candy bar

(a) Name distributions

The distribution of X is represented as:

[tex]X \sim(r,p)[/tex]

Where:

[tex]r = 5[/tex]

[tex]p= \frac{5\times 40\%}{10}[/tex]

[tex]p= 0.2[/tex]

So, the name distribution of X is [tex]X \sim(r= 5,p = 0.2)[/tex]

(b) The probability that the last candy is sold at the 11th house

This means that:

[tex]n = 10[/tex] --- the number of previous houses

[tex]r = 4[/tex] --- the previous number of candies

[tex]p = 0.4[/tex] --- the given probability of selling a candy

The probability is calculated using:

[tex]P(x = n+1) = ^{n}C_r \times p^{r +1} \times (1 - p)^{n-r}[/tex]

This gives

[tex]P(x = 10+1) = ^{10}C_4 \times 0.4^{4 +1} \times (1 - 0.4)^{10-4}[/tex]

[tex]P(x = 11) = ^{10}C_4 \times 0.4^{5} \times (0.6)^6[/tex]

[tex]P(x = 11) = 210 \times 0.4^5 \times 0.6^6[/tex]

[tex]P(x = 11) = 0.1003290624[/tex]

Approximate

[tex]P(x = 11) = 0.1003[/tex]

Hence, the probability that the last candy is sold at the 11th house is 0.1003

(b) The probability he sells the candies on or before the 8th house

The probability is calculated using:

[tex]P(x \le 8) = P(5 \le x \le 8)[/tex]

This gives

[tex]P(x \le 8) = ^{10}C_5 \times 0.4^{6} \times (0.6)^5 + ^{10}C_6 \times 0.4^{7} \times (0.6)^4 + ^{10}C_7 \times 0.4^{8} \times (0.6)^3 +^{10}C_8 \times 0.4^{9} \times (0.6)^2[/tex]

[tex]P(x = 11) = 0.1737[/tex] ---- approximated

Hence, the probability he sells the candies on or before the 8th house is 0.1737

Read more about probabilities at:

https://brainly.com/question/251701

Problem 1

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Explanation:

The vertices are (-12,0) and (12,0). Both of which are on the same horizontal line. Because of this, we have a hyperbola that opens leftward and rightward. Such hyperbolas are of the form

[tex]\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1[/tex]

where (h,k) is the center and the a,b terms help set up the asymptotes.

The midpoint of the vertices (-12,0) and (12,0) is the point (0,0). This is the center. So we know that h = 0 and k = 0.

For left/right opening hyperbolas, the asymptotes can be described as the equations:

y = (b/a)x

y = (-b/a)x

Or we can condense them into [tex]y = \pm \frac{b}{a}x[/tex]. Compare this to the given equation [tex]y = \pm\frac{5}{12}x[/tex] to see that b = 5 and a = 12.

Therefore, we get the following:

[tex]\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\\\\\frac{(x-0)^2}{12^2}-\frac{(y-0)^2}{5^2}=1\\\\\frac{x^2}{144}-\frac{y^2}{25}=1[/tex]

That points us to choice D.

You chose the correct answer.

=============================================================

Problem 2

--------------

Explanation:

Divide both sides by 3600 so we can turn that "3600" into "1". Then our goal is to get that "1" to its own side like so:

[tex]25x^2-144y^2 + 3600 = 0\\\\\frac{25x^2-144y^2 + 3600}{3600} = \frac{0}{3600}\\\\\frac{25x^2}{3600}-\frac{144y^2}{3600} + \frac{3600}{3600} = 0\\\\\frac{x^2}{144}-\frac{y^2}{25} + 1 = 0\\\\\frac{x^2}{144}-\frac{y^2}{25} = -1\\\\-\frac{x^2}{144}+\frac{y^2}{25} = 1\\\\-\frac{x^2}{12^2}+\frac{y^2}{5^2} = 1\\\\[/tex]

We see that a = 12 and b = 5 like earlier, so we end up with the same asymptotes as before. The only difference is that this hyperbola opens upward/downward rather than left/right.

You made the correct choice in picking answer A. Both of your answers are correct. Nice work.

[tex]\huge \bf༆ Answer ༄[/tex]

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